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Sandra Miller and Stephanie Smith
Lamar High School
Arlington, TX
This problem is
designed to occur
during a Geometry
unit on circles.
A line tangent to a
circle forms a right
angle with a radius
drawn at the point
of tangency.
d
r

h
r

r – radius of the
planet/moon
h – height of the
observer (eyes)
d – distance to the
horizon
d
r

h
r

r – radius of the
planet/moon
h – height of the
observer (eyes)
d – distance to the
horizon

d=

r + h) − r 2
(
2

d = r 2 + 2rh + h2 − r 2

d = h ( 2r + h )
Object

Radius

Horizon

Earth

3959 mi.

3 mi.

Moon

1080 mi.

Mars

2106 mi.

Jupiter

43,441 mi.
Object

Radius

Horizon

Earth

3959 mi.

3 mi.

Moon

1080 mi.

1.6 mi.

Mars

2106 mi.

2.2 mi.

Jupiter

43,441 mi.

9.9 mi.
This problem set is geared toward a Pre-AP
Algebra I class or an Algebra II class.
By working through this packet, a student
will practice

Simplifying literal equations
Creating formulas
Unit conversions
Using formulas to solve problems
Sir Isaac Newton developed three equations
that we will use to develop some interesting
information about the solar system.

F = ma

When a force F acts on a body of mass m, it
produces in it an acceleration a equal to
the force divided by the mass.

v
a=
r

The centripetal acceleration a of any body
moving in a circular orbit is equal to the
square of its velocity v divided by the
radius r of the orbit.

Gm1m2
F=
r2

The grativational force F between two
objects is proportional to the product of
their two masses, divided by the distance
between them.

2
If we substitute the formula for centripetal
acceleration into the F = ma equation, we
have an equation for the orbital force:

 v 2  mv 2
F = m  =
r
 r 
The gravitational force that the object being
orbited exerts on its satellite is

GmM
F= 2
r
Objects that are in orbit stay in orbit
because the force required to keep them
there is equal to the gravitational force that
the object being orbited exerts on its
satellite.
If we set our two equations equal to each
other and solve for v, we end up with a
formula that will give us the orbital speed of
the satellite.
Simplify the equation and solve for v:

mv 2 GmM
= 2
r
r
Simplify the equation and solve for v:

mv 2 GmM
= 2
r
r
GmM
2
mv =
r
Gm
v =
r
GM
v=
r
2
Because the mass of the satellite m
cancelled out of the equation, if we know
the orbital velocity and the radius of the
orbit, we can find the mass of the object
being orbited.
Rewrite the velocity equation and solve for
M:

GM
v =
r
2
Rewrite the velocity equation and solve for
M:

GM
v =
r
2

v 2r = GM

v 2r
M=
G
Example: Use the Moon to calculate the
mass of the Earth.
Orbital radius: r = 3.84 × 10 8 m
Period: T = 27.3 days

circumference of orbit
Orbital velocity: v =
period of orbit
Example: Use the Moon to calculate the
mass of the Earth.

2πr
v=
T
=

2π ( 3.84 × 108 )

 24 hours   3600 seconds 
27.3 


1 hour

 1 day  

= 1023 m s
Example: Use the Moon to calculate the
mass of the Earth.

 G = 6.67 × 10 −11 N m2



kg2 


v 2r
M=
G
= 6.02 × 10

24

kg
To calculate escape velocity, we set the
equation for kinetic energy to the equation
for gravitational force and solve for v:
Kinetic energy > Force × distance

1
GmM
2
mv > 2 i r
2
r
2GM
2
v >
r
v>

2GM
r
Calculate Earth’s escape velocity in km/s.
Earth’s mass:
Earth’s radius:

6.02 × 1024 kg
6.38 × 106 m

v > 11.22 km s
Now that we’ve worked through the different
equations, we can calculate the mass and
escape velocity of Mars as well as the mass
of the Sun.
One of my favorite
sites for possible
astronomy-related
math problems has
been Space Math at
http://spacemath.gsfc.nasa.gov.
Unfortunately, because of cutbacks in
NASA’s education budget, it will not be
updated as frequently.
Invert the
problem
Ask for an
explanation:
oral or written

Examples or
counterexamples

Ask for
prediction

Break into
multiple parts

Original
(Standard)
Problem

Ask for
multiple
representation

Ask for
generalization

Automaticity
practice

Ask questions
that require
qualitative
reasoning

James Epperson, Ph.D.
The powerpoint and the worksheets will be
posted on my blog at
tothemathlimit.wordpress.com.

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Rich Mathematical Problems in Astronomy

  • 1. Sandra Miller and Stephanie Smith Lamar High School Arlington, TX
  • 2.
  • 3. This problem is designed to occur during a Geometry unit on circles. A line tangent to a circle forms a right angle with a radius drawn at the point of tangency.
  • 4. d r h r r – radius of the planet/moon h – height of the observer (eyes) d – distance to the horizon
  • 5. d r h r r – radius of the planet/moon h – height of the observer (eyes) d – distance to the horizon d= r + h) − r 2 ( 2 d = r 2 + 2rh + h2 − r 2 d = h ( 2r + h )
  • 6. Object Radius Horizon Earth 3959 mi. 3 mi. Moon 1080 mi. Mars 2106 mi. Jupiter 43,441 mi.
  • 7. Object Radius Horizon Earth 3959 mi. 3 mi. Moon 1080 mi. 1.6 mi. Mars 2106 mi. 2.2 mi. Jupiter 43,441 mi. 9.9 mi.
  • 8.
  • 9. This problem set is geared toward a Pre-AP Algebra I class or an Algebra II class. By working through this packet, a student will practice Simplifying literal equations Creating formulas Unit conversions Using formulas to solve problems
  • 10. Sir Isaac Newton developed three equations that we will use to develop some interesting information about the solar system. F = ma When a force F acts on a body of mass m, it produces in it an acceleration a equal to the force divided by the mass. v a= r The centripetal acceleration a of any body moving in a circular orbit is equal to the square of its velocity v divided by the radius r of the orbit. Gm1m2 F= r2 The grativational force F between two objects is proportional to the product of their two masses, divided by the distance between them. 2
  • 11. If we substitute the formula for centripetal acceleration into the F = ma equation, we have an equation for the orbital force:  v 2  mv 2 F = m  = r  r  The gravitational force that the object being orbited exerts on its satellite is GmM F= 2 r
  • 12. Objects that are in orbit stay in orbit because the force required to keep them there is equal to the gravitational force that the object being orbited exerts on its satellite. If we set our two equations equal to each other and solve for v, we end up with a formula that will give us the orbital speed of the satellite.
  • 13. Simplify the equation and solve for v: mv 2 GmM = 2 r r
  • 14. Simplify the equation and solve for v: mv 2 GmM = 2 r r GmM 2 mv = r Gm v = r GM v= r 2
  • 15. Because the mass of the satellite m cancelled out of the equation, if we know the orbital velocity and the radius of the orbit, we can find the mass of the object being orbited.
  • 16. Rewrite the velocity equation and solve for M: GM v = r 2
  • 17. Rewrite the velocity equation and solve for M: GM v = r 2 v 2r = GM v 2r M= G
  • 18. Example: Use the Moon to calculate the mass of the Earth. Orbital radius: r = 3.84 × 10 8 m Period: T = 27.3 days circumference of orbit Orbital velocity: v = period of orbit
  • 19. Example: Use the Moon to calculate the mass of the Earth. 2πr v= T = 2π ( 3.84 × 108 )  24 hours   3600 seconds  27.3    1 hour   1 day   = 1023 m s
  • 20. Example: Use the Moon to calculate the mass of the Earth.  G = 6.67 × 10 −11 N m2    kg2   v 2r M= G = 6.02 × 10 24 kg
  • 21. To calculate escape velocity, we set the equation for kinetic energy to the equation for gravitational force and solve for v: Kinetic energy > Force × distance 1 GmM 2 mv > 2 i r 2 r 2GM 2 v > r v> 2GM r
  • 22. Calculate Earth’s escape velocity in km/s. Earth’s mass: Earth’s radius: 6.02 × 1024 kg 6.38 × 106 m v > 11.22 km s
  • 23. Now that we’ve worked through the different equations, we can calculate the mass and escape velocity of Mars as well as the mass of the Sun.
  • 24. One of my favorite sites for possible astronomy-related math problems has been Space Math at http://spacemath.gsfc.nasa.gov. Unfortunately, because of cutbacks in NASA’s education budget, it will not be updated as frequently.
  • 25. Invert the problem Ask for an explanation: oral or written Examples or counterexamples Ask for prediction Break into multiple parts Original (Standard) Problem Ask for multiple representation Ask for generalization Automaticity practice Ask questions that require qualitative reasoning James Epperson, Ph.D.
  • 26. The powerpoint and the worksheets will be posted on my blog at tothemathlimit.wordpress.com.