Work, Power & Energy
Explaining the Causes of
Motion in a Different Way
Work
The product of force and the amount of
displacement along the line of action of
that force.
Units: Newton•meter (Joule)
ft . lbs (horsepower)
nt
displaceme
Force
Work 

Work = F x d
To calculate work done on an object, we
need:
The Force
The average magnitude of the force
The direction of the force
The Displacement
The magnitude of the change of position
The direction of the change of position
Calculate Work
During the ascent phase of a rep of the
bench press, the lifter exerts an
average vertical force of 1000 N
against a barbell while the barbell
moves 0.8 m upward
How much work did the lifter do to the
barbell?
Calculate Work
Table of Variables:
Force = +1000 N
Displacement = +0.8 m
Force is positive due to pushing upward
Displacement is positive due to moving
upward
Calculate Work
Table of Variables:
Force = +1000 N
Displacement = +0.8 m
Select the equation and solve:
   
J
Joule
Nm
Work
m
N
Work
nt
displaceme
Force
Work
800
800
800
8
.
0
1000









- & + Work
Positive work is performed when
the direction of the force and
the direction of motion are the
same
ascent phase of the bench press
Throwing a ball
push off (upward) phase of a jump
Calculate Work
During the descent phase of a rep of
the bench press, the lifter exerts an
average vertical force of 1000 N
against a barbell while the barbell
moves 0.8 m downward
Calculate Work
Table of Variables
Force = +1000 N
Displacement = -0.8 m
Force is positive due to pushing upward
Displacement is negative due to movement
downward
Calculate Work
Table of Variables
Force = +1000 N
Displacement = -0.8 m
Select the equation and solve:
   
J
Joule
Nm
Work
m
N
Work
nt
displaceme
Force
Work
800
800
800
8
.
0
1000












- & + Work
Positive work
Negative work is performed
when the direction of the force
and the direction of motion are
the opposite
descent phase of the bench press
catching
landing phase of a jump
Work performed climbing
stairs
 Work = Fd
 Force
 Subject weight
 From mass, ie 65 kg
 Displacement
 Height of each step
 Typical 8 inches (20cm)
 Work per step
 650N x 0.2 m = 130.0 Nm
 Multiply by the number of steps
Work on a stair stepper
Work = Fd
Force
Push on the step
????
Displacement
Step Height
8 inches
“Work” per step
???N x .203 m = ???Nm
Work on a cycle ergometer
Work = Fd
Force
belt friction on the flywheel
mass (eg 3 kg)
Displacement
revolution of the pedals
Monark: 6 m
“Work” per revolution
Work on a cycle ergometer
 Work = Fd
 Force
 belt friction on the flywheel
 mass (eg 3 kg)
 Displacement
 revolution of the pedals
 Monark: 6 m
 “Work” per revolution
 3kg x 6 m = 18 kgm
Similar principle for wheelchair
…and for handcycling
ergometer
Power
The rate of doing work
Work = Fd
Units: Fd/s = J/s = watt
velocity
Force
Power
t
Fd
Power
time
Work
Power




/
/
Calculate & compare power
During the ascent phase of a rep of the
bench press, two lifters each exert an
average vertical force of 1000 N
against a barbell while the barbell
moves 0.8 m upward
Lifter A: 0.50 seconds
Lifter B: 0.75 seconds
Calculate & compare power
Lifter A
Table of Variables
F = 1000 N
d = 0.8 m
t = 0.50 s
Lifter B’s time would
be .75 sec instead
of .5 sec
w
s
J
Power
s
m
N
Power
t
Fd
Power
1600
50
.
0
800
50
.
0
8
.
0
1000





Energy
 Energy (E) is defined as the capacity to do
work (scalar)
 Many forms
No more created, only converted
 chemical, sound, heat, nuclear, mechanical
 Kinetic Energy (KE):
 energy due to motion
 Potential Energy (PE):
 energy due to position or deformation
Kinetic Energy
Energy due to motion reflects
the mass
the velocity of the object
KE = 1/2 mv2
Calculate Kinetic Energy
How much KE in a 5
ounce baseball (145 g)
thrown at 80 miles/hr
(35.8 m/s)?
Calculate Kinetic Energy
Table of Variables
Mass = 145 g  0.145 kg
Velocity = 35.8 m/s
Calculate Kinetic Energy
Table of Variables
Mass = 145 g  0.145 kg
Velocity = 35.8 m/s
Select the equation and solve:
KE = ½ m v2
KE = ½ (0.145 kg)(35.8 m/s)2
KE = ½ (0.145 kg)(1281.54 m/s/s)
KE = ½ (185.8 kg m/s/s)
KE = 92.9 kg m/s/s, or 92.9 Nm, or 92.9J
Calculate Kinetic Energy
How much KE possessed by
a 68.1 kg female volleyball
player moving downward at
3.2 m/s after a block?
Calculate Kinetic Energy
Table of Variables
 68.18 kg of mass
 -3.2 m/s
Select the equation and solve:
KE = ½ m v2
 KE = ½ (68.18 kg)(-3.2 m/s)2
 KE = ½ (68.18 kg)(10.24 m/s/s)
 KE = ½ (698.16 kg m/s/s)
 KE = 349.08 Nm or J
Calculate Kinetic Energy
Compare KE possessed by:
 a 220 pound (100 kg) running back
moving forward at 4.0 m/s
 a 385 pound (175 kg) lineman moving
forward at 3.75 m/s
Calculate Kinetic Energy
Table of Variables
m = 100 Kg
v = 4.0 m/s
Select the equation
and solve:
KE = ½ m v2
KE = ½ (100 kg)(4.0
m/s)2
KE = 800 Nm or J
Table of Variables
m = 175 kg
v = 3.75 m/s
Select the equation
and solve:
KE = ½ m v2
KE = ½ (175)(3.75)2
KE = 1230 Nm or J
Potential Energy
Two forms of PE:
Gravitational PE:
energy due to an object’s position
relative to the earth
Strain PE:
due to the deformation of an
object
Gravitational PE
Affected by the object’s
 weight
mg
elevation (height) above reference point
 ground or some other surface
h
GPE = mgh
Calculate GPE
How much gravitational potential energy
in a 45 kg gymnast when she is 4m
above the mat of the trampoline?
Trampoline mat is 1.25 m
above the ground
Calculate GPE
GPE relative to mat
Table of Variables
m = 45 kg
g = 10 m/s/s
h = 4 m
PE = mgh
PE = 45kg * -9.81
m/s/s * 4 m
PE = 1765.8 J
GPE relative to ground
Table of Variables
m = 45 kg
g = 10m/s/s
h = 5.25 m
PE = mgh
PE = 45kg * -9.81
m/s/s * 5.25 m
PE = 2317.6 J
Conversion of KE to GPE and
GPE to KE and KE to GPE and …
Strain Energy
When a fiberglass vaulting pole
bends, strain energy is stored in
the bent pole
Bungee jumping
When a tendon/ligament/muscle is
stretched, strain energy is stored
in the elongated elastin fibers
.
Work - Energy Relationship
The work done by an external force
acting on an object causes a change in
the mechanical energy of the object
  )
(
2
1 2
i
f
i
f r
r
mg
v
v
m
Fd
PE
KE
Fd
Energy
Fd











Work, Energy Power rev.ppt

  • 1.
    Work, Power &Energy Explaining the Causes of Motion in a Different Way
  • 2.
    Work The product offorce and the amount of displacement along the line of action of that force. Units: Newton•meter (Joule) ft . lbs (horsepower) nt displaceme Force Work  
  • 3.
    Work = Fx d To calculate work done on an object, we need: The Force The average magnitude of the force The direction of the force The Displacement The magnitude of the change of position The direction of the change of position
  • 4.
    Calculate Work During theascent phase of a rep of the bench press, the lifter exerts an average vertical force of 1000 N against a barbell while the barbell moves 0.8 m upward How much work did the lifter do to the barbell?
  • 5.
    Calculate Work Table ofVariables: Force = +1000 N Displacement = +0.8 m Force is positive due to pushing upward Displacement is positive due to moving upward
  • 6.
    Calculate Work Table ofVariables: Force = +1000 N Displacement = +0.8 m Select the equation and solve:     J Joule Nm Work m N Work nt displaceme Force Work 800 800 800 8 . 0 1000         
  • 7.
    - & +Work Positive work is performed when the direction of the force and the direction of motion are the same ascent phase of the bench press Throwing a ball push off (upward) phase of a jump
  • 8.
    Calculate Work During thedescent phase of a rep of the bench press, the lifter exerts an average vertical force of 1000 N against a barbell while the barbell moves 0.8 m downward
  • 9.
    Calculate Work Table ofVariables Force = +1000 N Displacement = -0.8 m Force is positive due to pushing upward Displacement is negative due to movement downward
  • 10.
    Calculate Work Table ofVariables Force = +1000 N Displacement = -0.8 m Select the equation and solve:     J Joule Nm Work m N Work nt displaceme Force Work 800 800 800 8 . 0 1000            
  • 11.
    - & +Work Positive work Negative work is performed when the direction of the force and the direction of motion are the opposite descent phase of the bench press catching landing phase of a jump
  • 12.
    Work performed climbing stairs Work = Fd  Force  Subject weight  From mass, ie 65 kg  Displacement  Height of each step  Typical 8 inches (20cm)  Work per step  650N x 0.2 m = 130.0 Nm  Multiply by the number of steps
  • 13.
    Work on astair stepper Work = Fd Force Push on the step ???? Displacement Step Height 8 inches “Work” per step ???N x .203 m = ???Nm
  • 14.
    Work on acycle ergometer Work = Fd Force belt friction on the flywheel mass (eg 3 kg) Displacement revolution of the pedals Monark: 6 m “Work” per revolution
  • 15.
    Work on acycle ergometer  Work = Fd  Force  belt friction on the flywheel  mass (eg 3 kg)  Displacement  revolution of the pedals  Monark: 6 m  “Work” per revolution  3kg x 6 m = 18 kgm
  • 16.
  • 17.
  • 18.
    Power The rate ofdoing work Work = Fd Units: Fd/s = J/s = watt velocity Force Power t Fd Power time Work Power     / /
  • 19.
    Calculate & comparepower During the ascent phase of a rep of the bench press, two lifters each exert an average vertical force of 1000 N against a barbell while the barbell moves 0.8 m upward Lifter A: 0.50 seconds Lifter B: 0.75 seconds
  • 20.
    Calculate & comparepower Lifter A Table of Variables F = 1000 N d = 0.8 m t = 0.50 s Lifter B’s time would be .75 sec instead of .5 sec w s J Power s m N Power t Fd Power 1600 50 . 0 800 50 . 0 8 . 0 1000     
  • 22.
    Energy  Energy (E)is defined as the capacity to do work (scalar)  Many forms No more created, only converted  chemical, sound, heat, nuclear, mechanical  Kinetic Energy (KE):  energy due to motion  Potential Energy (PE):  energy due to position or deformation
  • 23.
    Kinetic Energy Energy dueto motion reflects the mass the velocity of the object KE = 1/2 mv2
  • 24.
    Calculate Kinetic Energy Howmuch KE in a 5 ounce baseball (145 g) thrown at 80 miles/hr (35.8 m/s)?
  • 25.
    Calculate Kinetic Energy Tableof Variables Mass = 145 g  0.145 kg Velocity = 35.8 m/s
  • 26.
    Calculate Kinetic Energy Tableof Variables Mass = 145 g  0.145 kg Velocity = 35.8 m/s Select the equation and solve: KE = ½ m v2 KE = ½ (0.145 kg)(35.8 m/s)2 KE = ½ (0.145 kg)(1281.54 m/s/s) KE = ½ (185.8 kg m/s/s) KE = 92.9 kg m/s/s, or 92.9 Nm, or 92.9J
  • 27.
    Calculate Kinetic Energy Howmuch KE possessed by a 68.1 kg female volleyball player moving downward at 3.2 m/s after a block?
  • 28.
    Calculate Kinetic Energy Tableof Variables  68.18 kg of mass  -3.2 m/s Select the equation and solve: KE = ½ m v2  KE = ½ (68.18 kg)(-3.2 m/s)2  KE = ½ (68.18 kg)(10.24 m/s/s)  KE = ½ (698.16 kg m/s/s)  KE = 349.08 Nm or J
  • 29.
    Calculate Kinetic Energy CompareKE possessed by:  a 220 pound (100 kg) running back moving forward at 4.0 m/s  a 385 pound (175 kg) lineman moving forward at 3.75 m/s
  • 30.
    Calculate Kinetic Energy Tableof Variables m = 100 Kg v = 4.0 m/s Select the equation and solve: KE = ½ m v2 KE = ½ (100 kg)(4.0 m/s)2 KE = 800 Nm or J Table of Variables m = 175 kg v = 3.75 m/s Select the equation and solve: KE = ½ m v2 KE = ½ (175)(3.75)2 KE = 1230 Nm or J
  • 31.
    Potential Energy Two formsof PE: Gravitational PE: energy due to an object’s position relative to the earth Strain PE: due to the deformation of an object
  • 32.
    Gravitational PE Affected bythe object’s  weight mg elevation (height) above reference point  ground or some other surface h GPE = mgh
  • 33.
    Calculate GPE How muchgravitational potential energy in a 45 kg gymnast when she is 4m above the mat of the trampoline? Trampoline mat is 1.25 m above the ground
  • 34.
    Calculate GPE GPE relativeto mat Table of Variables m = 45 kg g = 10 m/s/s h = 4 m PE = mgh PE = 45kg * -9.81 m/s/s * 4 m PE = 1765.8 J GPE relative to ground Table of Variables m = 45 kg g = 10m/s/s h = 5.25 m PE = mgh PE = 45kg * -9.81 m/s/s * 5.25 m PE = 2317.6 J
  • 35.
    Conversion of KEto GPE and GPE to KE and KE to GPE and …
  • 36.
    Strain Energy When afiberglass vaulting pole bends, strain energy is stored in the bent pole Bungee jumping When a tendon/ligament/muscle is stretched, strain energy is stored in the elongated elastin fibers .
  • 37.
    Work - EnergyRelationship The work done by an external force acting on an object causes a change in the mechanical energy of the object   ) ( 2 1 2 i f i f r r mg v v m Fd PE KE Fd Energy Fd          