Using the 8-bit 2\'s complement binary number system, perform the following addition and subtraction problems Clearly indicate how you checked for an overflow condition and the result of that check. Solution 2. 10100010 (16210) + 01111001 (12110) 100011011 (2710) In the above addition there is a carry of 1. As you have only 8 bits, 162 + 121 = 283 which requires a total of 9 bits cannot be stored here and an overflow occurs. 10100010 (16210) - 01111001 (-12110) Now converting 01111001 to 2\'s complement: 10000110 + 1 = 10000111. Now summation: 10100010 + 10000111 = 100101001 In the above subtraction, there is a carry of 1, which can be ignored. And after ignoring the carry bit, the value is: 00101001 = 4110..