What are some of the advantages in the use of AOA notation as oppose.pdf
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What are some of the advantages in the use of AOA notation as opposed to AON? Under what circumstances does it seem better to apply AON methodology in network development? Solution AOA means activity on arc. In network diagrams AOA notation uses arrow diagram where each activity is represented by an arrow joining 2 circles (nodes). The circles or the nodes represents the transition between activities, which are called events. AON means activity on node. Here activities are represented by circles and the arc represents the events. The advantage of using AOA as opposed to AON is that AOA is more suitable for analytical techniques. Path tracking in case of AOA is simplified by event numbering. Lastly key events are easy to identify. AON is better under the following circumstances:.
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Which asymmetric cryptosystem is used for digital signaturesA. DE.pdf
Which asymmetric cryptosystem is used for digital signatures?
A. DES
B. SHA1
C. Diffie-Hellman
D. ECC
Solution
D. Elliptic curve cryptosystems (ECC) is an asymmetric cryptosystem created in the 1980s to
create and store digital signatures in a small amount of memory. Answer A is incorrect because
DES is a symmetric algorithm. Answer B is incorrect because SHA1 is a hashing algorithm.
Answer C is incorrect because Diffie-Hellman is used for key exchange..
Which of these theories fit into the contextual world-viewQuestio.pdf
Which of these theories fit into the contextual world-view?
Question 13 options:
Stage theories, like Piaget\'s.
Learning theories, like Skinner\'s.
Universal theories, like Bowlby\'s.
Systems theories, like Bronfenbrenner\'s.
Save
Stage theories, like Piaget\'s.
Learning theories, like Skinner\'s.
Universal theories, like Bowlby\'s.
Systems theories, like Bronfenbrenner\'s.
Solution
ANS: D. Systems theories, like Bronfenbrenner\'s.
Explanation:
Developmental psychology is mainly influenced by three major world views. They are 1.
Organismic, 2. Mechanistic and 3. contextual world views.
Contextual world views:
Development is the result of reciprocal social interactions between an active person and their
social partners from in a series of nested contexts.
Systems theories, like Bronfenbrenner\'s theory fit into the contextual world-view.
Wrong theories:
A. Stage theories, like Piaget\'s. (Organismic)
B. Learning theories, like Skinner\'s. (Mechanistic)
C. Universal theories, like Bowlby\'s. (Maturational).
Which of the following distinguishes prophase of meiosis I from proph.pdf
Which of the following distinguishes prophase of meiosis I from prophase of mitosis?
homologous chromosomes pair up spindle forms nuclear membrane breaks down
chromosomes become visible
Solution
In meiosis there are two successive divion occure, meiosis I(which is reduction division) and
meiosis II (similar division). While meiosis II is similar to mitosis,Meiosis I is a eventfull cell
divion, divided into 4 phases....Prophase1, metaphase 1,Anaphase 1 and telophase 1.
Prophase 1 of MEIOSIS 1 divided into following subphases- LEPTONEMA, ZYGONEMA,
PACHYNEMA, DIPLOTENE and DIAKINESIS.
In zygotene or Zygonema homologous chromosome(paternally derrived and maternally derrived)
pair and form synapse in the process of synapsis..
What is meant by primary growth What is meant by secondary growth .pdf
What is meant by primary growth? What is meant by secondary growth? What are the three
primary meristems? What tissue(s develop(s) from each? How does the distribution of the
vascular bundles differ in monocots and dicots? Monocots: Dicots: What type of tissue
comprises the bundle cap of Hellanthus? What are some differences between the xylem and the
phloem?
Solution
1. Primary growth refers to the growth that occurs due to cell divisions at the tips of roots and
shoots , which cause them to elongate and forms primary tissue.
Secondary growth refers to the one that occurs due to cell division in cambium or lateral
meristem of the plant, that allows the plant to thicken..
What to the characteristic X-ray radiation What is the originSo.pdf
What to the characteristic X-ray radiation? What is the origin?
Solution
- Characteristics x- ray radiations are emitted from heavy elements when their electrons make
transitions between the lower atomic energy levels.
- the high energy electron can also cause an electron close to the neclues in a metal atom to be
knocked out from its place
ORIGIN
Discovery. German physicist Wilhelm Röntgen is usually credited as the discoverer of x rays in
1895, because he was the first to systematically study them, though he is not the first to have
observed their effects.
Rountgen called them x rays after the mathematical symbol X for unknown.
What other blood cell related problems are often seen in patients wi.pdf
What other blood cell related problems are often seen in patients with chronic leukemia?
Citereferencesplease
Solution
The term leukemia is referred to neoplasm of hematopoietic tissue. Unlike the solid tumors the
leukemic cells diffuse into bone marrow and lymphoid tissues and spill over into blood stream to
spread to various organs of the body. The leukemic cells are either mature or extremely
primitive. Rich amounts of white blood cell counts in leukemia reveals the spread of tumors to
peripheral blood. However, the proliferation of white blood cells is mostly confined to bone
marrow and no significant increase in number of white blood cells in the blood stream can be
observed.
Leukemia is classified depending on the type of the cell and maturity of proliferating cell. Any
type of hematopoietic cell may produce leukemia but most common types are granulocytic,
monocytic and lymphocytic. The leukemia developing from stem cells produce the leukocytes
containing specific granules such as neutrophils, eosinophils and basophils. This type of
leukemia is called granulocytic leukemia. Monocytic leukemia is developed from the precursor
cells of monocytes. Lymphocytic leukemia is produced by lymphoid precursor cells.
When the leukemic cells are most primitive forms the neoplasm is called acute leukemia. The
leukemia with mature cells is called chronic leukemia. Chronic granulocyte leukemia is caused
by circulating matured granulocytes and neutrophils along with few primitive cells. Chronic
lymphocytic leukemia is caused by circulating mature lymphocytes.
The clinical features of leukemia are either caused by impairment of function of bone marrow or
caused by infiltration of leukemic cells into viscera. The overgrowth of leukemic cells in bone
marrow crowds out the normal cells leading to anemia because of inadequate production of red
blood cells. Bleeding is caused by thrombocytopenia and infection resulting from insufficient
numbers of white blood cells to provide protection by immune defense mechanism against
pathogens.
Leukemic cells spreading to other tissues may invade into spleen, liver, lymph nodes and other
tissues. The chronic leukemia proceeds at a slow rate and can be controlled by treatment over
long periods of time. Therefore, the patient may survive for several years. In an acute leukemia
the disease is rapidly progressive and leukemic cells infiltrate bone marrow and viscera with
conspicuous appearance.
1.American Cancer Society. Cancer Facts and Figures 2016. Atlanta, Ga: American Cancer
Society; 2016.
2. Byrd JC, Brown JR, O\'Brien S, et al. Ibrutinib versus ofatumumab in previously treated
chronic lymphoid leukemia. N Engl J Med. 2014 Jul 17;371(3):213-23. Epub 2014 May 31.
3. Byrd JC, Furman RR, Coutre SE, et al. Targeting BTK with ibrutinib in relapsed chronic
lymphocytic leukemia. N Engl J Med. 2013 Jul 4;369(1):32-42. Epub 2013 Jun 19.
4. Byrd JC, Flynn JM. Chronic lymphocytic leukemia. In: Niederhuber JE,Armitage JO,
Doroshow .
what is inductive and deductive reasoningSolutionDeductive and.pdf
what is inductive and deductive reasoning
Solution
Deductive and Inductive Reasoning
Deductive and inductive are basically types of arguments and where argument generally supports
conclusion with premises.
Deductive reasoning is basically a type of argument which supports conclusion logically for
example arguments which are based on rules, facts, truth, laws and principles and are accepted
widely.
It is the process of reasoning which involves to draw conclusion based on the relationship of two
premises in which one assertion is broad(major premises and valid) and other is specific(minor
premises and invalid). As major premises are broad it is to be supported by values and laws.
Like for instance:
Reena is a woman
All women are mortal
Therefore it proves that reena is mortal.
It is a top to down approach.
Inductive Reasoning is basically a type of argument which supports conclusion on the basis of
judgment, pattern, trend, experience and observation. These arguments do not prove truth as
these conclusions are based on probable support. The argument which support successfully is a
strong argument whereas that fails to support is considered as weak. It is a bottom to up
approach..
What are the major evolutionary feats shared by all 3 phyla( Platyhe.pdf
What are the major evolutionary feats shared by all 3 phyla( Platyhelminthes, Nematoda, and
Annelida)? What are the implications of these evolutionary feats? What two additional
evolutionary feats are exhibited by Nemotoda? And 2 feats by Annelida?
Solution
Answer:
The major evolutionary feats shared by Platyhelminthes, Nematoda and Annelida are:
1. Level of Organization- Organ system level of organization
The organisms possesses distinct organ systems which marks the evolution of organ systems in
animals.
2. Symmetry - Bilateral
This is often a result of moving in one direction, thus having a “head” end.
3. Triploblastic
They share common body wall organization, consisting of 3 layers. Three germ layers are
evidence of slowly adapting layers of developmental control during embryogenesis as cells
specialized for greater efficiency.
Two additional evolutionary feats exhibited by Nematoda are:
1. Coelom- Pseudocoelomate
2. Digestive system -Complete
Two feats of Annelida are:
1. Segmentation - Presented
2. Circulatory system -Present.
Recommended
Which asymmetric cryptosystem is used for digital signaturesA. DE.pdf
Which asymmetric cryptosystem is used for digital signatures?
A. DES
B. SHA1
C. Diffie-Hellman
D. ECC
Solution
D. Elliptic curve cryptosystems (ECC) is an asymmetric cryptosystem created in the 1980s to
create and store digital signatures in a small amount of memory. Answer A is incorrect because
DES is a symmetric algorithm. Answer B is incorrect because SHA1 is a hashing algorithm.
Answer C is incorrect because Diffie-Hellman is used for key exchange..
Which of these theories fit into the contextual world-viewQuestio.pdf
Which of these theories fit into the contextual world-view?
Question 13 options:
Stage theories, like Piaget\'s.
Learning theories, like Skinner\'s.
Universal theories, like Bowlby\'s.
Systems theories, like Bronfenbrenner\'s.
Save
Stage theories, like Piaget\'s.
Learning theories, like Skinner\'s.
Universal theories, like Bowlby\'s.
Systems theories, like Bronfenbrenner\'s.
Solution
ANS: D. Systems theories, like Bronfenbrenner\'s.
Explanation:
Developmental psychology is mainly influenced by three major world views. They are 1.
Organismic, 2. Mechanistic and 3. contextual world views.
Contextual world views:
Development is the result of reciprocal social interactions between an active person and their
social partners from in a series of nested contexts.
Systems theories, like Bronfenbrenner\'s theory fit into the contextual world-view.
Wrong theories:
A. Stage theories, like Piaget\'s. (Organismic)
B. Learning theories, like Skinner\'s. (Mechanistic)
C. Universal theories, like Bowlby\'s. (Maturational).
Which of the following distinguishes prophase of meiosis I from proph.pdf
Which of the following distinguishes prophase of meiosis I from prophase of mitosis?
homologous chromosomes pair up spindle forms nuclear membrane breaks down
chromosomes become visible
Solution
In meiosis there are two successive divion occure, meiosis I(which is reduction division) and
meiosis II (similar division). While meiosis II is similar to mitosis,Meiosis I is a eventfull cell
divion, divided into 4 phases....Prophase1, metaphase 1,Anaphase 1 and telophase 1.
Prophase 1 of MEIOSIS 1 divided into following subphases- LEPTONEMA, ZYGONEMA,
PACHYNEMA, DIPLOTENE and DIAKINESIS.
In zygotene or Zygonema homologous chromosome(paternally derrived and maternally derrived)
pair and form synapse in the process of synapsis..
What is meant by primary growth What is meant by secondary growth .pdf
What is meant by primary growth? What is meant by secondary growth? What are the three
primary meristems? What tissue(s develop(s) from each? How does the distribution of the
vascular bundles differ in monocots and dicots? Monocots: Dicots: What type of tissue
comprises the bundle cap of Hellanthus? What are some differences between the xylem and the
phloem?
Solution
1. Primary growth refers to the growth that occurs due to cell divisions at the tips of roots and
shoots , which cause them to elongate and forms primary tissue.
Secondary growth refers to the one that occurs due to cell division in cambium or lateral
meristem of the plant, that allows the plant to thicken..
What to the characteristic X-ray radiation What is the originSo.pdf
What to the characteristic X-ray radiation? What is the origin?
Solution
- Characteristics x- ray radiations are emitted from heavy elements when their electrons make
transitions between the lower atomic energy levels.
- the high energy electron can also cause an electron close to the neclues in a metal atom to be
knocked out from its place
ORIGIN
Discovery. German physicist Wilhelm Röntgen is usually credited as the discoverer of x rays in
1895, because he was the first to systematically study them, though he is not the first to have
observed their effects.
Rountgen called them x rays after the mathematical symbol X for unknown.
What other blood cell related problems are often seen in patients wi.pdf
What other blood cell related problems are often seen in patients with chronic leukemia?
Citereferencesplease
Solution
The term leukemia is referred to neoplasm of hematopoietic tissue. Unlike the solid tumors the
leukemic cells diffuse into bone marrow and lymphoid tissues and spill over into blood stream to
spread to various organs of the body. The leukemic cells are either mature or extremely
primitive. Rich amounts of white blood cell counts in leukemia reveals the spread of tumors to
peripheral blood. However, the proliferation of white blood cells is mostly confined to bone
marrow and no significant increase in number of white blood cells in the blood stream can be
observed.
Leukemia is classified depending on the type of the cell and maturity of proliferating cell. Any
type of hematopoietic cell may produce leukemia but most common types are granulocytic,
monocytic and lymphocytic. The leukemia developing from stem cells produce the leukocytes
containing specific granules such as neutrophils, eosinophils and basophils. This type of
leukemia is called granulocytic leukemia. Monocytic leukemia is developed from the precursor
cells of monocytes. Lymphocytic leukemia is produced by lymphoid precursor cells.
When the leukemic cells are most primitive forms the neoplasm is called acute leukemia. The
leukemia with mature cells is called chronic leukemia. Chronic granulocyte leukemia is caused
by circulating matured granulocytes and neutrophils along with few primitive cells. Chronic
lymphocytic leukemia is caused by circulating mature lymphocytes.
The clinical features of leukemia are either caused by impairment of function of bone marrow or
caused by infiltration of leukemic cells into viscera. The overgrowth of leukemic cells in bone
marrow crowds out the normal cells leading to anemia because of inadequate production of red
blood cells. Bleeding is caused by thrombocytopenia and infection resulting from insufficient
numbers of white blood cells to provide protection by immune defense mechanism against
pathogens.
Leukemic cells spreading to other tissues may invade into spleen, liver, lymph nodes and other
tissues. The chronic leukemia proceeds at a slow rate and can be controlled by treatment over
long periods of time. Therefore, the patient may survive for several years. In an acute leukemia
the disease is rapidly progressive and leukemic cells infiltrate bone marrow and viscera with
conspicuous appearance.
1.American Cancer Society. Cancer Facts and Figures 2016. Atlanta, Ga: American Cancer
Society; 2016.
2. Byrd JC, Brown JR, O\'Brien S, et al. Ibrutinib versus ofatumumab in previously treated
chronic lymphoid leukemia. N Engl J Med. 2014 Jul 17;371(3):213-23. Epub 2014 May 31.
3. Byrd JC, Furman RR, Coutre SE, et al. Targeting BTK with ibrutinib in relapsed chronic
lymphocytic leukemia. N Engl J Med. 2013 Jul 4;369(1):32-42. Epub 2013 Jun 19.
4. Byrd JC, Flynn JM. Chronic lymphocytic leukemia. In: Niederhuber JE,Armitage JO,
Doroshow .
what is inductive and deductive reasoningSolutionDeductive and.pdf
what is inductive and deductive reasoning
Solution
Deductive and Inductive Reasoning
Deductive and inductive are basically types of arguments and where argument generally supports
conclusion with premises.
Deductive reasoning is basically a type of argument which supports conclusion logically for
example arguments which are based on rules, facts, truth, laws and principles and are accepted
widely.
It is the process of reasoning which involves to draw conclusion based on the relationship of two
premises in which one assertion is broad(major premises and valid) and other is specific(minor
premises and invalid). As major premises are broad it is to be supported by values and laws.
Like for instance:
Reena is a woman
All women are mortal
Therefore it proves that reena is mortal.
It is a top to down approach.
Inductive Reasoning is basically a type of argument which supports conclusion on the basis of
judgment, pattern, trend, experience and observation. These arguments do not prove truth as
these conclusions are based on probable support. The argument which support successfully is a
strong argument whereas that fails to support is considered as weak. It is a bottom to up
approach..
What are the major evolutionary feats shared by all 3 phyla( Platyhe.pdf
What are the major evolutionary feats shared by all 3 phyla( Platyhelminthes, Nematoda, and
Annelida)? What are the implications of these evolutionary feats? What two additional
evolutionary feats are exhibited by Nemotoda? And 2 feats by Annelida?
Solution
Answer:
The major evolutionary feats shared by Platyhelminthes, Nematoda and Annelida are:
1. Level of Organization- Organ system level of organization
The organisms possesses distinct organ systems which marks the evolution of organ systems in
animals.
2. Symmetry - Bilateral
This is often a result of moving in one direction, thus having a “head” end.
3. Triploblastic
They share common body wall organization, consisting of 3 layers. Three germ layers are
evidence of slowly adapting layers of developmental control during embryogenesis as cells
specialized for greater efficiency.
Two additional evolutionary feats exhibited by Nematoda are:
1. Coelom- Pseudocoelomate
2. Digestive system -Complete
Two feats of Annelida are:
1. Segmentation - Presented
2. Circulatory system -Present.
Verify the identity.StartFraction sine left parenthesis alpha plus.pdf
Verify the identity.
StartFraction sine left parenthesis alpha plus beta right parenthesis Over sine alpha cosine beta
EndFraction equals 1 plus cotangent alpha tangent beta
sin(+)
sincos
=1+cottan
Solution
sin(+)/sincos =1+cottan
sin( + ) = sin()cos() + cos()sin()
LHS ======> sin()cos()/sincos + cos()sin()/sincos = 1 + cot()*tan() = RHS.
Use C++class Node{public Node ( int = 0 ); constru.pdf
Use C++
class Node{
public:
Node ( int = 0 ); // constructor with default value for
// info field
int info; // data
Node * next; // pointer to next node in the list
};
and put the constructor in Node.cpp
// Constructor
Node::Node ( int data )
{
info = data;
next = nullptr;
}
Write the following using the Node class.
A function that copies a linked list pointed to by ptr and returns a pointer to the copied list.
Please note: the copied list should be independent of the original list; the original list can be
destroyed and the copy should still remain.
const Node * copy (Node * ptr);
Solution
Need to perform \'Deep copy\' here :
const Node * copy (Node * ptr)
{
//Create new list to hold copied items
Node* newNode = new Node;
//Return if empty list
if (ptr->next == 0)
{
return newNode;
}
while(ptr !=NULL)
{
newNode->info = ptr->info;
newNode->next = ptr->next;
ptr = ptr ->next;
}
return newNode;
}.
This is a lab for a java program that I am very unsure of, it has to.pdf
This is a lab for a java program that I am very unsure of, it has to do with Binary trees, and I am
very confused on how to work with them, if anyone can help I will be very grateful, thank you!!
You are to create a balanced binary tree which means that at each node n, the size of the left
subtree of n is within one of the size of the right subtree of n
Your program shall read in from user input a list of positive integers into an array (at most 100
elements). Your input stops when it reads a 0 (sentinel ).
Your program will then sort the elements in the array. You MUST write your own sort routine
You are then to create a balanced binary tree from this data.
You are then to print out your balanced tree using pre-order, in-order, and post-order routines
Requirements
1) Program must read integers from user input into an array
2) Program must sort integers with sort routine written by user
3) Program must implement a binary tree object using links (not arrays)
4) Program must implement at least methods PREORDER, INORDER, POSTORDER, ADD
(create a balanced binary search tree from the given array).
5) Output demonstrating input and output
Solution
import java.io.*;
import java.util.*;
class Nodetype
{
int info;
int ht;
Nodetype left;
Nodetype right;
Nodetype(int i)
{
info=i;
ht=0;
left=null;
right=null;
}
}
class Functions
{
Nodetype AVLroot;
void create()
{
int x,n,i;
AVLroot=null;
int[] a=new int[100];
String str;
int counter=0;
System.out.println(\"\ Enter numbers:\");
do
{
x=getNumber();
a[counter]=x;
counter++;
}while(x!=0);
int[] finalarr=new int[100];
finalarr=sort(a);
int tcntr=0;
while(finalarr[tcntr]!=0)
{
AVLroot=insert(AVLroot,finalarr[tcntr]);
tcntr++;
}
System.out.println(\"\ Preorder sequene:\");
preorder(AVLroot);
System.out.println(\"\ Inorder sequence:\");
inorder(AVLroot);
System.out.println(\"\ Postorder sequence:\");
postorder(AVLroot);
}
int[] sort(int[] arr)
{
int n = arr.length;
int temp = 0;
for(int i=0; i < n; i++){
for(int j=1; j < (n-i); j++){
if(arr[j-1] > arr[j]&&arr[j]!=0){
//swap elements
temp = arr[j-1];
arr[j-1] = arr[j];
arr[j] = temp;
}
}
}
return (arr);
}
int getNumber()
{
String str;
int ne=0;
InputStreamReader input=new InputStreamReader(System.in);
BufferedReader in=new BufferedReader(input);
try
{
str=in.readLine();
ne=Integer.parseInt(str);
}
catch(Exception e)
{
System.out.println(\"\ I/O error.\");
}
return ne;
}
Nodetype insert(Nodetype T,int x)
{
if(T==null)
{
Nodetype node=new Nodetype(x);
T=node;
}
else
if(x>T.info)
{
T.right=insert(T.right,x);
if(BF(T)==-2)
if(x>T.right.info)
T=RR(T);
else
T=RL(T);
}
else
if(xrh)
return(lh);
return(rh);
}
Nodetype rotateright(Nodetype x)
{
Nodetype y;
y=x.left;
x.left=y.right;
y.right=x;
x.ht=height(x);
y.ht=height(y);
return(y);
}
Nodetype rotateleft(Nodetype x)
{
Nodetype y;
y=x.right;
x.right=y.left;
y.left=x;
x.ht=height(x);
y.ht=height(y);
return(y);
}
Nodetype RR(Nodetype T)
{
T=rotateleft(T);
return(T);
}
Nodetype LL(Nodetype T)
{
T=rotateright(T);
return(T);
.
The concentration of carbon dioxide in the atmosphere today is about .pdf
The concentration of carbon dioxide in the atmosphere today is about Select one: a. 170 parts
per million. b. 300 parts per million. c. 400 parts per million d. 800 parts per million. How
would a shift in land use from forest to agriculture affect atmospheric carbon dioxide? Select
one: a. It would have no effect. b. It would result in a large release of CO_2 c. It would result
in a decrease in release of CO_2 d. Neither forests nor crops contribute significantly to
atmospheric carbon dioxide Charles Keeling chose to monitor atmospheric carbon dioxide levels
at Mauna Loa Observatory because Select one: a. uptake of carbon dioxide would be greatest in
warm tropical forests b. it was located far from industrial sources of pollution that might make
interpretation of the data more difficult c. the climate in Hawaii was very different from the
climate of Big Sur (California) where he did his previous work on carbon dioxide d. the relative
contribution of fossil fue
Solution
The concentration of carbondioxide in the atmosphere today is around 400 Parts per million
(ppm). The safe level of carbondioxide in atmosphere is around 350ppm. The shift in land use
from forest to agrivulture results in large release of carbondioxide in atmosphere. Also release of
other greenhouse gasses results in global warming. Its because of the relative contribution of
fossil fuel burning to the release of atmospheric carbondioxide was debated. Its one of the major
reason for the increase in global warminh..
Research and discuss two operating systems and how incident response.pdf
Research and discuss two operating systems and how incident response processes may differ in
properly shutting down the systems for transport to the laboratory.
Solution
Computer Incident Response and Computer Forensics Overview carried out in different
operating system. As follows below:
Introduction
When a compromise of security or an unauthorized/illegal action associated with a
computer is suspected, it is important that steps are taken to ensure the protection of the
data within the computer and/or storage media. The stored data is needed to determine
the level of security compromise and location of potential evidence concerning the
unauthorized or illegal act.
The initial response to a computer security incident may be more important than later
technical analysis of the computer system because of the actions taken by incident
response team members. Actions taken by the incident response team impact subsequent
laboratory examinations of the computer and/or media. Of most importance is that the
first responder act appropriately.
In the event of a suspected computer incident, care must be taken to preserve evidence in
its original state. While it may seem that simply viewing files on a system would not
result in alteration of the original media, opening a file changes it. From a legal sense, it
is no longer the original evidence and may be inadmissible in any subsequent legal or
administrative proceedings.
This paper will focus on the incident response and computer forensics on the personal or
desktop computers. The incident response and forensic procedures and techniques for
servers may additional knowledge and tools.
Incident Response
Every organization should have an incident response team. This team may consist of one
person in an organization or several persons. In the event of suspected computer crime or
violations of user policies, the team should be activated. The team should have written
procedures for incident response, including what conditions warrant calling in local
and/or federal law enforcement authorities. Violations of user policies may result in
administrative actions whereas suspected computer crimes may require that law
enforcement authorities be called in. The incident team needs to protect evidence for
either situation. For administrative actions, the procedures described in this paper may be
sufficient. However, for suspected computer crimes, the law enforcement officials may
instruct the incident team to wait for their arrival.
The activities/procedures for securing a suspected computer incident scene include
· Securing the scene
· Shutting down the computer
· Labeling the evidence
· Documenting the evidence
· Transporting the evidence
· Providing chain-of-custody documentation
The computer incident response team should keep in mind that what begins as a
collection of evidence for violation of administrative policy violations may escalate into
collection of evidence for more serious violations. The computer may hav.
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Proteins can be attached to a membrane in a variety of ways. How does the mode of attachment
relate to their function?
Solution
Membrane proteins are very important for different type of cellular functions like a transport
signalling pathways and cell adhesion etc…. proteins are interacting with membrane in different
types
Some proteins are associated with cytoplasmic face of the cell membrane; some proteins are
associated with extracellular face of the plasma membrane (peripheral proteins) and integral or
intrinsic proteins. Extrinsic proteins do not interact with the hydrophobic core of the
phospholipids bilayer.
Example porins are transmembrane proteins that play a major role in water transport
Prostaglandin H2 extracellular membrane bounded protein that is associated with surface of the
plasma membrane. Play major role in inflammation..
Problem 1-What is environmental engineering (20 pts) Below you wil.pdf
Problem 1-What is environmental engineering? (20 pts) Below you will see a list of four
different scenarios which to field of environmental engineering. For each one of ihena may
involve the area you need (1) Write out if th have defined it in our course e scenario involves
environmental engineering as wo for (1) by explaining what area of environmental engineering
the scenario fits into and why decide YES, the scenario does involve the field of specific an
environmental engineering, then describe something environmental engineer might do as part o
scenario. If you decide scendor of environmental engineering. you do not have to do anything t f
their job in thot e NQ, the scenario does not involve the field this step. northern Scenario 1:
Unsustainable deforestation in an old growth Canadian forest the Congo. Scenario 3: Assessment
of the level of exposure of indoor air pollutants in a school building for children that go to the
school. Scenario 4: Assisting a Native American tribe in legal arguments to justity to a state
court that their water rights are being violated. Scenario 2: Right handling of acid mine water
drainage for a gold mine in
Solution
1.
1.At 0.02% of its forested area, deforestation in Canada is among the world’s lowest, yet many
myths exist about the state of our forests. The reality is that Canada is a world leader in
sustainable forest management. Canadian forests are healthy, productive and thriving.
Deforestation is an important issue, since shrinking forest cover reduces biodiversity, affects soil
and water quality, impacts wildlife habitat and influences climate change. The Canadian
government carefully monitors and regularly publishes reports on deforestation. Our scientists
combine satellite and aerial images with information about regional development, forest
ecosystems, natural processes and local conditions to help monitor and manage the health of
Canadian forests.
Here are some key facts about Canada’s low levels of deforestation.
The annual deforestation rate in Canada in 2010 was less than 0.02% of our forests and the rate
has been declining for over 25 years. In 1990, 63,100 hectares were lost to deforestation and in
2014 this figure dropped to 34,200 hectares.
Today, Canada’s 348 million hectares of forest lands represent about 9% of the world’s forest
cover, but account for only 0.3% of global deforestation.
Deforestation only occurs when forests are permanently removed so the land can be used for
something else. Harvesting, forest fires and insect infestations do not constitute deforestation,
since the affected areas will grow back. According to laws, regulations and policies in place
across Canada, all areas harvested on public land must be reforested, either by replanting or
through natural regeneration. About 94% of Canada’s forests are on public land.
The conversion of forest to agricultural land is decreasing but it remains the largest contributor to
deforestation in Canada. The small contribution the.
NetWork Design Question2.) How does TCP prevent Congestion Dicuss.pdf
NetWork Design Question
2.) How does TCP prevent Congestion? Dicuss the information identifying congestion in the
network as well as the mechanism for reducing congestion?
Solution
Congestion is a problem that occurs on shared networks when multiple users contend for access
to the same resources (bandwidth, buffers, and queues).
Transmission Control Protocol (TCP) uses a network congestion-avoidance algorithm that
includes various aspects of an additive increase/multiplicative decrease (AIMD) scheme, with
other schemes such as slow-start to achieve congestion avoidance.
The TCP congestion-avoidance algorithm is the primary basis for congestion control in the
Internet.
Congestion typically occurs where multiple links feed into a single link, such as where internal
LANs are connected to WAN links. Congestion also occurs at routers in core networks where
nodes are subjected to more traffic than they are designed to handle.
TCP/IP networks such as the Internet are especially susceptible to congestion because of their
basic connection- less nature. There are no virtual circuits with guaranteed bandwidth. Packets
are injected by any host at any time, and those packets are variable in size, which make
predicting traffic patterns and providing guaranteed service impossible. While connectionless
networks have advantages, quality of service is not one of them.
Shared LANs such as Ethernet have their own congestion control mechanisms in the form of
access controls that prevent multiple nodes from transmitting at the same time.
Identifying:
Congestion is primarily reflected by a conventional user feeling-- slowness. This statement
reflects the change in the network effective flow, that is the time required to transmit an entire
data from one point to another. The effective flow doenot exist as such, it consists in reality of
three seperate indicators:
*Latency:the effective flow is inversely proportional to the latency.
*Jitter:it is latency variation over time, impacts by influencing the flow latency
*Loss Rate:the theoritical bandwidth is inversely proportional to the square root of the loss rate
These Congestion symtoms allow us to rely on objective indicators to characterize it.
Mechanism to reduce congestion:
The standard fare in TCP implementations today has four standard congestion control algorithms
that are now in common use. Their usefulness has passed the test of time.
The four algorithms, Slow Start, Congestion Avoidance, Fast Retransmit and Fast Recovery are
described below. (a) Slow Start
Slow Start, a requirement for TCP software implementations is a mechanism used by the sender
to control the transmission rate, otherwise known as sender-based flow control. This is
accomplished through the return rate of acknowledgements from the receiver. In other words, the
rate of acknowledgements returned by the receiver determine the rate at which the sender can
transmit data. When a TCP connection first begins, the Slow Start algorithm initializes a
.
Mosses and liverworts are early colonizers during ecological success.pdf
Mosses and liverworts are early colonizers during ecological succession and make the
environment more amenable for other species. How do these plants contribute to nitrogen levels
in the soil?
Solution
Answer:
Mosses and liverworts have been found to be the first organisms to colonize either a primary
succession or secondary succession. Their spores are carried by birds, insects or wind.
Studies indicate that mosses and liverworts make the soil more amenable to colonization by other
plants. This can be attributed to the fact that mosses and liverworts establish symbiotic
association with nitrogen fixing cyanobacteria, thus replenishing the soil with nitrogen..
Many programming languages, especially older ones, provide no langua.pdf
Many programming languages, especially older ones, provide no language support for
concurrency. C and C++ are examples of such languages. Is it essential that a language include
syntax for concurrency to be able to write concurrent programs in that language? If not, how is it
accomplished? What are the advantages and disadvantages of including support for concurrency
in a language?
Solution
Advantages:
1).Although the tasks are running and the user can relate with the applications.
2).It has the availability of services. means long running the tasks will not delay tiny running
ones.
3). complex programs make better use of many resources.
4).tasks are requiring certain pre conditions can hang and wait untill the pre conditions are seize
and then restart implementation properly.
Disadvantages:
1). a chance of corrupting consistent state of program by concurrent tasks.
2).Deadlock may occur.
3).It would be masters exponential number of interleavings due to different schedules..
Inferior nasal concha Lacrimal bone Mandible Maxilla Nasal bone .pdf
Inferior nasal concha Lacrimal bone Mandible Maxilla Nasal bone Palatine bone Vomer
bone Zygomatic bone Forms bridge of nose Only movable bone in the facial skeleton Contains
coronoid process Creates prominence of cheek inferior and lateral to the eye Contains sockets
of upper teeth Forms inferior portion of nasal septum Forms anterior portion of zygomatic arch
Scroll-shaped bone in nasal passage Forms anterior roof of mouth Contains mental foramen
Forms posterior roof of mouth Small bone in medial wall of orbit Forms a very small portion of
inferior orbit Contains large sinus inferior to orbit
Solution.
import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
I need this in python. Only python, please. Use list methods to add .pdf
I need this in python. Only python, please. Use list methods to add or remove elements from the
list. The tool accepts only integers or floating point values. Sort short_names in reverse
alphabetic order. Sample output from given program:
Solution
short_names=[\'Jan\',\'Sam\',\'Ann\',\'Joe\',\'Tod\']
short_names.sort(); #it will sort in ascending order
short_names.reverse(); #it will reverse the soretd list
print(short_names)
####OUTPUT#####
sh-4.3$ python
main.py
[\'Tod\', \'Sam\', \'Joe\', \'Jan\', \'Ann\']
####OUTPUT#####.
How many defective copies of a gene must someone inherit to express .pdf
How many defective copies of a gene must someone inherit to express a disease caused by a
dominant gene? How many defective copies of a gene must someone inherit to express a
recessive disorder? What is the expected phenotypic ratio of affected to unaffected individuals
for a dominant disorder?
Solution
In autosomal dominant inheritance even single copy of gene requires to get expressed
phenotypically in offspring
In autosomal recessive inheritance two copies of allele of the disease are require for an
individual to the susceptible to express phenotypically
There is 50% chances of offspring to get affected in a dominant disorder.
From Chapter 2 - Identify and describe the critical functions of com.pdf
From Chapter 2 - Identify and describe the critical functions of computer systems and how green
computing is implemented. Please answer both questions. You will have to start a new thread in
order to post.
Solution
Critical Functions of Computer System are
1. Inputting
2.Outputting
3.Mutiprocessing
4.Storing
5.Controlling
Inputting:
Input units link external environment with computer system. Data and instructions must be
entered before performing any competition. They can be entered through input devices like
Keyboard.
Output unit:
It provides information reasons of computation to the output of the world. It links the computer
with external world. A computer prepares results in binary code and the output unit converts
these results into human acceptable forms. It performs the following functions.
Storage unit:
Before processing, data & instructions entered to the computer must be stored inside computer
and results produced by the computer are to be stored before passed to the output unit. The
intermediate result produced by the computer must be stored for processing. functions of storage
unit are as follows:
ALU:
It is the place where actual execution of the instructions takes places during the processing
operations. All calculations & comparisons are done in the ALU. The data and instructions
stored in the primary storage are transfered as where they are required. Intermediate results are
also transfered back to ALU for final processing. After completion of processing, final results are
transfered to storage units from ALU.
Control unit:
ALU doesn`tt know what should done with data likewise, output device doesn`tt know when
result should be displayed. By selecting, interning and seeing the execution of the program the
Control Unit will maintain order and direct the operations of the entire system Control Unit
doesn’t perform any actual processing on data yet it is called as central nervous system of the
computer.
It manages and co-ordinates the entire system.
Green Computing is implemented in five steps:
Step1: Develop a sustainable green computing plan.
Step2: Recycle.
Step3: Make environmentally sound purchase decisions.
Step4: Reduce Paper Consumption.
Step5: Conserve Energy..
For this activity, hover over the various management viewpoints for h.pdf
For this activity, hover over the various management viewpoints for hints and descriptions and
place them in the correct chronological order on the sequential timeline below.
Solution
Historical perspective:
2. Behavioural viewpoint: it is the second viewpoint and it emphasizes on motivating the
employees and controlling human behaviour and emotions towards achievement of goals.
3. Quantitative viewpoint: It is the third viewpoint and it emphasizes on use and application of
quantitative methods for management decision making.
Contemporary perspective:.
Explain the goal of interim reporting and how the interim period is .pdf
Explain the goal of interim reporting and how the interim period is viewed relative to an annual
period.
Solution
ANSWER:
The primary goal of interim financial statements is to provide to users in due time the accounting
information which is required for the elaboration of operational or funding or investment
decision. Moreover can provide users the meaningful information about the directions on the
business development and on the seasonality of certain activities. This information could be
highlighted in the financial statements for the financial year. The meaningful, reliable and timely
interim financial reporting enhances the ability of creditors, investors, and others to understand a
firm\'s capacity to generate earnings and cash flows, its financial condition and liquidity
Interim reporting is the reporting of the financial results of any period which is lesser than a
fiscal year, thus interim periods are accounting time periods which are generally less than one
year in duration, such as a month, a quarter, or a semi-annual period..
Describe various scales of measurements. Provide two examples of .pdf
Describe various scales of measurements. Provide two examples of each scale.
Describe various scales of measurements. Provide two examples of each scale.
Solution
Nominal Level
Level of measurement which classifies data into mutually exclusive, all inclusive categories in
which no order or ranking can be imposed on the data.
Example: Gender, Race
Ordinal Level
Level of measurement which classifies data into categories that can be ranked. Differences
between the ranks do not exist.
Example: class Rank, socio economic status( low, medium,high)
Interval Level
Level of measurement which classifies data that can be ranked and differences are meaningful.
However, there is no meaningful zero, so ratios are meaningless.
Example: Temperature in Celsius, time
Ratio Level
Level of measurement which classifies data that can be ranked, differences are meaningful, and
there is a true zero. True ratios exist between the different units of measure.
Example: age, height.
Discrete random variables X(u) and F(u) both take values in {-1,0,+1}.pdf
Discrete random variables X(u) and F(u) both take values in {-1,0,+1}. The joint probability
mass function for X (u) and Y (u) is where K is a constant. Find and provide a label sketch of
the conditional probability mass functions: Given that X(u) = i, find the best estimate of Y(u)
under the Linear MMSE, MMSE, Maximum Likelihood, and Maximum A posteriori Probability
criteria. Fill in the table below to describe your answer: What is the residual mean-squared error
for the Linear MMSE estimator?
Solution.
All of these are steps in the lytic cycle of a temperate bacteriopha.pdf
All of these are steps in the lytic cycle of a temperate bacteriophage. Which happens second?
entry
release
attachment
assembly
Solution
Answer : entry is the second stage
The order is attachment, entry, assembly and release.
The lytic cycle involves the virus attaches itself to a specific host cell and enter into it, taking
control of the host DNA to produce viral DNA and the viral proteins that provide the structural
component of the bacteriophage, and then, when the cells has many new virus particles
assembled,digesting the host cell wall from within and releasing the new viruses..
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
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More from optokunal1
Verify the identity.StartFraction sine left parenthesis alpha plus.pdf
Verify the identity.
StartFraction sine left parenthesis alpha plus beta right parenthesis Over sine alpha cosine beta
EndFraction equals 1 plus cotangent alpha tangent beta
sin(+)
sincos
=1+cottan
Solution
sin(+)/sincos =1+cottan
sin( + ) = sin()cos() + cos()sin()
LHS ======> sin()cos()/sincos + cos()sin()/sincos = 1 + cot()*tan() = RHS.
Use C++class Node{public Node ( int = 0 ); constru.pdf
Use C++
class Node{
public:
Node ( int = 0 ); // constructor with default value for
// info field
int info; // data
Node * next; // pointer to next node in the list
};
and put the constructor in Node.cpp
// Constructor
Node::Node ( int data )
{
info = data;
next = nullptr;
}
Write the following using the Node class.
A function that copies a linked list pointed to by ptr and returns a pointer to the copied list.
Please note: the copied list should be independent of the original list; the original list can be
destroyed and the copy should still remain.
const Node * copy (Node * ptr);
Solution
Need to perform \'Deep copy\' here :
const Node * copy (Node * ptr)
{
//Create new list to hold copied items
Node* newNode = new Node;
//Return if empty list
if (ptr->next == 0)
{
return newNode;
}
while(ptr !=NULL)
{
newNode->info = ptr->info;
newNode->next = ptr->next;
ptr = ptr ->next;
}
return newNode;
}.
This is a lab for a java program that I am very unsure of, it has to.pdf
This is a lab for a java program that I am very unsure of, it has to do with Binary trees, and I am
very confused on how to work with them, if anyone can help I will be very grateful, thank you!!
You are to create a balanced binary tree which means that at each node n, the size of the left
subtree of n is within one of the size of the right subtree of n
Your program shall read in from user input a list of positive integers into an array (at most 100
elements). Your input stops when it reads a 0 (sentinel ).
Your program will then sort the elements in the array. You MUST write your own sort routine
You are then to create a balanced binary tree from this data.
You are then to print out your balanced tree using pre-order, in-order, and post-order routines
Requirements
1) Program must read integers from user input into an array
2) Program must sort integers with sort routine written by user
3) Program must implement a binary tree object using links (not arrays)
4) Program must implement at least methods PREORDER, INORDER, POSTORDER, ADD
(create a balanced binary search tree from the given array).
5) Output demonstrating input and output
Solution
import java.io.*;
import java.util.*;
class Nodetype
{
int info;
int ht;
Nodetype left;
Nodetype right;
Nodetype(int i)
{
info=i;
ht=0;
left=null;
right=null;
}
}
class Functions
{
Nodetype AVLroot;
void create()
{
int x,n,i;
AVLroot=null;
int[] a=new int[100];
String str;
int counter=0;
System.out.println(\"\ Enter numbers:\");
do
{
x=getNumber();
a[counter]=x;
counter++;
}while(x!=0);
int[] finalarr=new int[100];
finalarr=sort(a);
int tcntr=0;
while(finalarr[tcntr]!=0)
{
AVLroot=insert(AVLroot,finalarr[tcntr]);
tcntr++;
}
System.out.println(\"\ Preorder sequene:\");
preorder(AVLroot);
System.out.println(\"\ Inorder sequence:\");
inorder(AVLroot);
System.out.println(\"\ Postorder sequence:\");
postorder(AVLroot);
}
int[] sort(int[] arr)
{
int n = arr.length;
int temp = 0;
for(int i=0; i < n; i++){
for(int j=1; j < (n-i); j++){
if(arr[j-1] > arr[j]&&arr[j]!=0){
//swap elements
temp = arr[j-1];
arr[j-1] = arr[j];
arr[j] = temp;
}
}
}
return (arr);
}
int getNumber()
{
String str;
int ne=0;
InputStreamReader input=new InputStreamReader(System.in);
BufferedReader in=new BufferedReader(input);
try
{
str=in.readLine();
ne=Integer.parseInt(str);
}
catch(Exception e)
{
System.out.println(\"\ I/O error.\");
}
return ne;
}
Nodetype insert(Nodetype T,int x)
{
if(T==null)
{
Nodetype node=new Nodetype(x);
T=node;
}
else
if(x>T.info)
{
T.right=insert(T.right,x);
if(BF(T)==-2)
if(x>T.right.info)
T=RR(T);
else
T=RL(T);
}
else
if(xrh)
return(lh);
return(rh);
}
Nodetype rotateright(Nodetype x)
{
Nodetype y;
y=x.left;
x.left=y.right;
y.right=x;
x.ht=height(x);
y.ht=height(y);
return(y);
}
Nodetype rotateleft(Nodetype x)
{
Nodetype y;
y=x.right;
x.right=y.left;
y.left=x;
x.ht=height(x);
y.ht=height(y);
return(y);
}
Nodetype RR(Nodetype T)
{
T=rotateleft(T);
return(T);
}
Nodetype LL(Nodetype T)
{
T=rotateright(T);
return(T);
.
The concentration of carbon dioxide in the atmosphere today is about .pdf
The concentration of carbon dioxide in the atmosphere today is about Select one: a. 170 parts
per million. b. 300 parts per million. c. 400 parts per million d. 800 parts per million. How
would a shift in land use from forest to agriculture affect atmospheric carbon dioxide? Select
one: a. It would have no effect. b. It would result in a large release of CO_2 c. It would result
in a decrease in release of CO_2 d. Neither forests nor crops contribute significantly to
atmospheric carbon dioxide Charles Keeling chose to monitor atmospheric carbon dioxide levels
at Mauna Loa Observatory because Select one: a. uptake of carbon dioxide would be greatest in
warm tropical forests b. it was located far from industrial sources of pollution that might make
interpretation of the data more difficult c. the climate in Hawaii was very different from the
climate of Big Sur (California) where he did his previous work on carbon dioxide d. the relative
contribution of fossil fue
Solution
The concentration of carbondioxide in the atmosphere today is around 400 Parts per million
(ppm). The safe level of carbondioxide in atmosphere is around 350ppm. The shift in land use
from forest to agrivulture results in large release of carbondioxide in atmosphere. Also release of
other greenhouse gasses results in global warming. Its because of the relative contribution of
fossil fuel burning to the release of atmospheric carbondioxide was debated. Its one of the major
reason for the increase in global warminh..
Research and discuss two operating systems and how incident response.pdf
Research and discuss two operating systems and how incident response processes may differ in
properly shutting down the systems for transport to the laboratory.
Solution
Computer Incident Response and Computer Forensics Overview carried out in different
operating system. As follows below:
Introduction
When a compromise of security or an unauthorized/illegal action associated with a
computer is suspected, it is important that steps are taken to ensure the protection of the
data within the computer and/or storage media. The stored data is needed to determine
the level of security compromise and location of potential evidence concerning the
unauthorized or illegal act.
The initial response to a computer security incident may be more important than later
technical analysis of the computer system because of the actions taken by incident
response team members. Actions taken by the incident response team impact subsequent
laboratory examinations of the computer and/or media. Of most importance is that the
first responder act appropriately.
In the event of a suspected computer incident, care must be taken to preserve evidence in
its original state. While it may seem that simply viewing files on a system would not
result in alteration of the original media, opening a file changes it. From a legal sense, it
is no longer the original evidence and may be inadmissible in any subsequent legal or
administrative proceedings.
This paper will focus on the incident response and computer forensics on the personal or
desktop computers. The incident response and forensic procedures and techniques for
servers may additional knowledge and tools.
Incident Response
Every organization should have an incident response team. This team may consist of one
person in an organization or several persons. In the event of suspected computer crime or
violations of user policies, the team should be activated. The team should have written
procedures for incident response, including what conditions warrant calling in local
and/or federal law enforcement authorities. Violations of user policies may result in
administrative actions whereas suspected computer crimes may require that law
enforcement authorities be called in. The incident team needs to protect evidence for
either situation. For administrative actions, the procedures described in this paper may be
sufficient. However, for suspected computer crimes, the law enforcement officials may
instruct the incident team to wait for their arrival.
The activities/procedures for securing a suspected computer incident scene include
· Securing the scene
· Shutting down the computer
· Labeling the evidence
· Documenting the evidence
· Transporting the evidence
· Providing chain-of-custody documentation
The computer incident response team should keep in mind that what begins as a
collection of evidence for violation of administrative policy violations may escalate into
collection of evidence for more serious violations. The computer may hav.
Proteins can be attached to a membrane in a variety of ways. How doe.pdf
Proteins can be attached to a membrane in a variety of ways. How does the mode of attachment
relate to their function?
Solution
Membrane proteins are very important for different type of cellular functions like a transport
signalling pathways and cell adhesion etc…. proteins are interacting with membrane in different
types
Some proteins are associated with cytoplasmic face of the cell membrane; some proteins are
associated with extracellular face of the plasma membrane (peripheral proteins) and integral or
intrinsic proteins. Extrinsic proteins do not interact with the hydrophobic core of the
phospholipids bilayer.
Example porins are transmembrane proteins that play a major role in water transport
Prostaglandin H2 extracellular membrane bounded protein that is associated with surface of the
plasma membrane. Play major role in inflammation..
Problem 1-What is environmental engineering (20 pts) Below you wil.pdf
Problem 1-What is environmental engineering? (20 pts) Below you will see a list of four
different scenarios which to field of environmental engineering. For each one of ihena may
involve the area you need (1) Write out if th have defined it in our course e scenario involves
environmental engineering as wo for (1) by explaining what area of environmental engineering
the scenario fits into and why decide YES, the scenario does involve the field of specific an
environmental engineering, then describe something environmental engineer might do as part o
scenario. If you decide scendor of environmental engineering. you do not have to do anything t f
their job in thot e NQ, the scenario does not involve the field this step. northern Scenario 1:
Unsustainable deforestation in an old growth Canadian forest the Congo. Scenario 3: Assessment
of the level of exposure of indoor air pollutants in a school building for children that go to the
school. Scenario 4: Assisting a Native American tribe in legal arguments to justity to a state
court that their water rights are being violated. Scenario 2: Right handling of acid mine water
drainage for a gold mine in
Solution
1.
1.At 0.02% of its forested area, deforestation in Canada is among the world’s lowest, yet many
myths exist about the state of our forests. The reality is that Canada is a world leader in
sustainable forest management. Canadian forests are healthy, productive and thriving.
Deforestation is an important issue, since shrinking forest cover reduces biodiversity, affects soil
and water quality, impacts wildlife habitat and influences climate change. The Canadian
government carefully monitors and regularly publishes reports on deforestation. Our scientists
combine satellite and aerial images with information about regional development, forest
ecosystems, natural processes and local conditions to help monitor and manage the health of
Canadian forests.
Here are some key facts about Canada’s low levels of deforestation.
The annual deforestation rate in Canada in 2010 was less than 0.02% of our forests and the rate
has been declining for over 25 years. In 1990, 63,100 hectares were lost to deforestation and in
2014 this figure dropped to 34,200 hectares.
Today, Canada’s 348 million hectares of forest lands represent about 9% of the world’s forest
cover, but account for only 0.3% of global deforestation.
Deforestation only occurs when forests are permanently removed so the land can be used for
something else. Harvesting, forest fires and insect infestations do not constitute deforestation,
since the affected areas will grow back. According to laws, regulations and policies in place
across Canada, all areas harvested on public land must be reforested, either by replanting or
through natural regeneration. About 94% of Canada’s forests are on public land.
The conversion of forest to agricultural land is decreasing but it remains the largest contributor to
deforestation in Canada. The small contribution the.
NetWork Design Question2.) How does TCP prevent Congestion Dicuss.pdf
NetWork Design Question
2.) How does TCP prevent Congestion? Dicuss the information identifying congestion in the
network as well as the mechanism for reducing congestion?
Solution
Congestion is a problem that occurs on shared networks when multiple users contend for access
to the same resources (bandwidth, buffers, and queues).
Transmission Control Protocol (TCP) uses a network congestion-avoidance algorithm that
includes various aspects of an additive increase/multiplicative decrease (AIMD) scheme, with
other schemes such as slow-start to achieve congestion avoidance.
The TCP congestion-avoidance algorithm is the primary basis for congestion control in the
Internet.
Congestion typically occurs where multiple links feed into a single link, such as where internal
LANs are connected to WAN links. Congestion also occurs at routers in core networks where
nodes are subjected to more traffic than they are designed to handle.
TCP/IP networks such as the Internet are especially susceptible to congestion because of their
basic connection- less nature. There are no virtual circuits with guaranteed bandwidth. Packets
are injected by any host at any time, and those packets are variable in size, which make
predicting traffic patterns and providing guaranteed service impossible. While connectionless
networks have advantages, quality of service is not one of them.
Shared LANs such as Ethernet have their own congestion control mechanisms in the form of
access controls that prevent multiple nodes from transmitting at the same time.
Identifying:
Congestion is primarily reflected by a conventional user feeling-- slowness. This statement
reflects the change in the network effective flow, that is the time required to transmit an entire
data from one point to another. The effective flow doenot exist as such, it consists in reality of
three seperate indicators:
*Latency:the effective flow is inversely proportional to the latency.
*Jitter:it is latency variation over time, impacts by influencing the flow latency
*Loss Rate:the theoritical bandwidth is inversely proportional to the square root of the loss rate
These Congestion symtoms allow us to rely on objective indicators to characterize it.
Mechanism to reduce congestion:
The standard fare in TCP implementations today has four standard congestion control algorithms
that are now in common use. Their usefulness has passed the test of time.
The four algorithms, Slow Start, Congestion Avoidance, Fast Retransmit and Fast Recovery are
described below. (a) Slow Start
Slow Start, a requirement for TCP software implementations is a mechanism used by the sender
to control the transmission rate, otherwise known as sender-based flow control. This is
accomplished through the return rate of acknowledgements from the receiver. In other words, the
rate of acknowledgements returned by the receiver determine the rate at which the sender can
transmit data. When a TCP connection first begins, the Slow Start algorithm initializes a
.
Mosses and liverworts are early colonizers during ecological success.pdf
Mosses and liverworts are early colonizers during ecological succession and make the
environment more amenable for other species. How do these plants contribute to nitrogen levels
in the soil?
Solution
Answer:
Mosses and liverworts have been found to be the first organisms to colonize either a primary
succession or secondary succession. Their spores are carried by birds, insects or wind.
Studies indicate that mosses and liverworts make the soil more amenable to colonization by other
plants. This can be attributed to the fact that mosses and liverworts establish symbiotic
association with nitrogen fixing cyanobacteria, thus replenishing the soil with nitrogen..
Many programming languages, especially older ones, provide no langua.pdf
Many programming languages, especially older ones, provide no language support for
concurrency. C and C++ are examples of such languages. Is it essential that a language include
syntax for concurrency to be able to write concurrent programs in that language? If not, how is it
accomplished? What are the advantages and disadvantages of including support for concurrency
in a language?
Solution
Advantages:
1).Although the tasks are running and the user can relate with the applications.
2).It has the availability of services. means long running the tasks will not delay tiny running
ones.
3). complex programs make better use of many resources.
4).tasks are requiring certain pre conditions can hang and wait untill the pre conditions are seize
and then restart implementation properly.
Disadvantages:
1). a chance of corrupting consistent state of program by concurrent tasks.
2).Deadlock may occur.
3).It would be masters exponential number of interleavings due to different schedules..
Inferior nasal concha Lacrimal bone Mandible Maxilla Nasal bone .pdf
Inferior nasal concha Lacrimal bone Mandible Maxilla Nasal bone Palatine bone Vomer
bone Zygomatic bone Forms bridge of nose Only movable bone in the facial skeleton Contains
coronoid process Creates prominence of cheek inferior and lateral to the eye Contains sockets
of upper teeth Forms inferior portion of nasal septum Forms anterior portion of zygomatic arch
Scroll-shaped bone in nasal passage Forms anterior roof of mouth Contains mental foramen
Forms posterior roof of mouth Small bone in medial wall of orbit Forms a very small portion of
inferior orbit Contains large sinus inferior to orbit
Solution.
import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
I need this in python. Only python, please. Use list methods to add .pdf
I need this in python. Only python, please. Use list methods to add or remove elements from the
list. The tool accepts only integers or floating point values. Sort short_names in reverse
alphabetic order. Sample output from given program:
Solution
short_names=[\'Jan\',\'Sam\',\'Ann\',\'Joe\',\'Tod\']
short_names.sort(); #it will sort in ascending order
short_names.reverse(); #it will reverse the soretd list
print(short_names)
####OUTPUT#####
sh-4.3$ python
main.py
[\'Tod\', \'Sam\', \'Joe\', \'Jan\', \'Ann\']
####OUTPUT#####.
How many defective copies of a gene must someone inherit to express .pdf
How many defective copies of a gene must someone inherit to express a disease caused by a
dominant gene? How many defective copies of a gene must someone inherit to express a
recessive disorder? What is the expected phenotypic ratio of affected to unaffected individuals
for a dominant disorder?
Solution
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phenotypically in offspring
In autosomal recessive inheritance two copies of allele of the disease are require for an
individual to the susceptible to express phenotypically
There is 50% chances of offspring to get affected in a dominant disorder.
From Chapter 2 - Identify and describe the critical functions of com.pdf
From Chapter 2 - Identify and describe the critical functions of computer systems and how green
computing is implemented. Please answer both questions. You will have to start a new thread in
order to post.
Solution
Critical Functions of Computer System are
1. Inputting
2.Outputting
3.Mutiprocessing
4.Storing
5.Controlling
Inputting:
Input units link external environment with computer system. Data and instructions must be
entered before performing any competition. They can be entered through input devices like
Keyboard.
Output unit:
It provides information reasons of computation to the output of the world. It links the computer
with external world. A computer prepares results in binary code and the output unit converts
these results into human acceptable forms. It performs the following functions.
Storage unit:
Before processing, data & instructions entered to the computer must be stored inside computer
and results produced by the computer are to be stored before passed to the output unit. The
intermediate result produced by the computer must be stored for processing. functions of storage
unit are as follows:
ALU:
It is the place where actual execution of the instructions takes places during the processing
operations. All calculations & comparisons are done in the ALU. The data and instructions
stored in the primary storage are transfered as where they are required. Intermediate results are
also transfered back to ALU for final processing. After completion of processing, final results are
transfered to storage units from ALU.
Control unit:
ALU doesn`tt know what should done with data likewise, output device doesn`tt know when
result should be displayed. By selecting, interning and seeing the execution of the program the
Control Unit will maintain order and direct the operations of the entire system Control Unit
doesn’t perform any actual processing on data yet it is called as central nervous system of the
computer.
It manages and co-ordinates the entire system.
Green Computing is implemented in five steps:
Step1: Develop a sustainable green computing plan.
Step2: Recycle.
Step3: Make environmentally sound purchase decisions.
Step4: Reduce Paper Consumption.
Step5: Conserve Energy..
For this activity, hover over the various management viewpoints for h.pdf
For this activity, hover over the various management viewpoints for hints and descriptions and
place them in the correct chronological order on the sequential timeline below.
Solution
Historical perspective:
2. Behavioural viewpoint: it is the second viewpoint and it emphasizes on motivating the
employees and controlling human behaviour and emotions towards achievement of goals.
3. Quantitative viewpoint: It is the third viewpoint and it emphasizes on use and application of
quantitative methods for management decision making.
Contemporary perspective:.
Explain the goal of interim reporting and how the interim period is .pdf
Explain the goal of interim reporting and how the interim period is viewed relative to an annual
period.
Solution
ANSWER:
The primary goal of interim financial statements is to provide to users in due time the accounting
information which is required for the elaboration of operational or funding or investment
decision. Moreover can provide users the meaningful information about the directions on the
business development and on the seasonality of certain activities. This information could be
highlighted in the financial statements for the financial year. The meaningful, reliable and timely
interim financial reporting enhances the ability of creditors, investors, and others to understand a
firm\'s capacity to generate earnings and cash flows, its financial condition and liquidity
Interim reporting is the reporting of the financial results of any period which is lesser than a
fiscal year, thus interim periods are accounting time periods which are generally less than one
year in duration, such as a month, a quarter, or a semi-annual period..
Describe various scales of measurements. Provide two examples of .pdf
Describe various scales of measurements. Provide two examples of each scale.
Describe various scales of measurements. Provide two examples of each scale.
Solution
Nominal Level
Level of measurement which classifies data into mutually exclusive, all inclusive categories in
which no order or ranking can be imposed on the data.
Example: Gender, Race
Ordinal Level
Level of measurement which classifies data into categories that can be ranked. Differences
between the ranks do not exist.
Example: class Rank, socio economic status( low, medium,high)
Interval Level
Level of measurement which classifies data that can be ranked and differences are meaningful.
However, there is no meaningful zero, so ratios are meaningless.
Example: Temperature in Celsius, time
Ratio Level
Level of measurement which classifies data that can be ranked, differences are meaningful, and
there is a true zero. True ratios exist between the different units of measure.
Example: age, height.
Discrete random variables X(u) and F(u) both take values in {-1,0,+1}.pdf
Discrete random variables X(u) and F(u) both take values in {-1,0,+1}. The joint probability
mass function for X (u) and Y (u) is where K is a constant. Find and provide a label sketch of
the conditional probability mass functions: Given that X(u) = i, find the best estimate of Y(u)
under the Linear MMSE, MMSE, Maximum Likelihood, and Maximum A posteriori Probability
criteria. Fill in the table below to describe your answer: What is the residual mean-squared error
for the Linear MMSE estimator?
Solution.
All of these are steps in the lytic cycle of a temperate bacteriopha.pdf
All of these are steps in the lytic cycle of a temperate bacteriophage. Which happens second?
entry
release
attachment
assembly
Solution
Answer : entry is the second stage
The order is attachment, entry, assembly and release.
The lytic cycle involves the virus attaches itself to a specific host cell and enter into it, taking
control of the host DNA to produce viral DNA and the viral proteins that provide the structural
component of the bacteriophage, and then, when the cells has many new virus particles
assembled,digesting the host cell wall from within and releasing the new viruses..
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