NORMAL
DISTRIBUTION
INTRODUCTION
Most scientific and business data and natural
relationships, such as weight, height, etc., when
displayed using a histogramfrequency curve are
bell-shaped, andsymmetrical, known as NORMAL
DISTRIBUTION.
NORMAL DISTRIBUTION
Manythings closely follow a Normal
Distribution:
• heights of people
• size of things produced by machines
• errors in measurements
• blood pressure
• scores on a test
NORMALCURVE.
The graphical representation in statistics is
called NORMAL CURVE.
CHARACTERISTICS OF ANORMAL CURVE
✓Mathematical model represented by a
bell-shaped curve which is symmetric with
respect to the mean.
✓The normal curve does not intersect or touch
the horizontal axis.
CHARACTERISTICS OF ANORMAL CURVE
✓The mean, median and mode of the normal
distribution are equal.
✓The area under the normal curved is approximately
equal to 1 or 100%.
✓The standardized normal distribution has a mean
of 0 and standard deviation of 1.
Example: Mean and Std Deviation of the distribution
are 55 and 12 respectively
STANDARD SCORE- z-score
• It’ s a measure of how many
standard deviations below or above
the population mean a raw score is.
• z-scores are expressed in terms of
standard deviations from their
means.
• These z-scores have a distribution
with a mean of 0 and a standard
deviation of 1.
Standard Score Formula
z = (x - µ) / σ
• z = standard score
• x = given data
• µ = mean
• σ = standard deviation
Example:
Convert the following data to standard score
Given
score
z- score
13 -1.03
12 -1.28
18 + 0.26
20 +0.77
22 +1.28
z = (x - µ) / σ
• µ= 17 and σ= 3.9
z = (13 - 17) / 3.9 =
See how to get the value
Howto Find the Area under the Normal curve:
ComputingNormal Probabilities
There are several different situations that
can arise when asked to find normal
probabilities.
I. BETWEEN AZERO AND ANY NUMBER
Look at the area in the table.
II. BETWEEN TWO POSITIVES, OR BETWEEN TWO
NEGATIVES
▶Look at both area in the table and subtract the
smaller from larger
III. BETWEENA NEGATIVE AND A POSITIVE
• Look at both areas in the table and
add them together.
IV. LESS THAN A NEGATIVE, OR GREATER THAN A
POSITIVE
▶Look up the area in the table and subtract from
0.5.
V. GREATER THAN ANEGATIVE OR LESS THANA
POSITIVE
▶Look at the in the table and add 0.5.
Area Under Normal Curve
Using the table of Area under the Normal Curve,.
Determine the Area of the following:
1) Area to the right of Z=0.
2) Area to the left of Z=0.
3) Area from Z=0 to Z=1.25.
4) Area from Z=-1.5 to Z=0.
5) Area between Z=-1.5 to Z=1.5.
6) Area to the left of Z=1.35.
7) Area to the right of Z= 2.0.
8) Area to the right of Z= -3.0.
9) Area to the left of Z= -1.75.
10) Area between Z=-1.67 to Z=-2.0.
ANSWER
1. 0.5 or 50%
2. 0.5 or 50%
3. 0.3944 or 39.44 %
4. 0.4332 or 43.32%
5. 0.8664 or 86.64%
6. 0.9115 or 91.15%
7. 0.0228 or 2.28%
8. 0.9987 or 99.87%
9. 0.0401 or 4.01%
10. 0.0247 or 2. 47%
Application of the Normal Curve
Example 1. The scores of the grade 25 pupils
have a mean of 5.35 and standard deviation
of 0.45.
(a) What percentage of all these scores are
lower than 4?
(b) What percentage of these scores are
between 5 and 6?
Example 2
You take the entrance examination and
score 68. The mean score for the of the
exam is 54 and the standard deviation is 9.7.
(a) How well did you score on the test
compared to the average test taker?
Example 2
(b) If there were 500 students who took the
examination:
i. how many students score between 50
and 70
ii. how many students got below 45
Example 3
Let's consider the distribution of the tests for an
individual's intelligence quotient (IQ) are designed
to be normally distributed, with a mean of 100 and a
standard deviation of 15.
(a) If score 136 inthe tests for are "potential
genius", what percentage of individuals are
"potential geniuses"?
(b) If there were 800 students who took the IQ test,
how many of them are between 110 to 125?
ACTIVITY
1. Suppose that the volume of paint in the 1-gallon
paint cans produced by Acme Paint Company is
approximately normally distributed with a mean of 1.
04 gallons and a standard deviation of 0.023
gallons.
(a)What is the probability that a randomly selected
1-gallon can will actually contain at least 1 gallon of
paint?
(b)What volume can the Acme Paint Company say
that 95% of their cans exceed?
ACTIVITY
2.Suppose the amount of light (in lumens)
emitted by a particular brand of 40W light bulbs
is normally distributed with a mean of 450
lumens and a standard deviation of 20 lumens.
(a)What percentage of bulbs emit between 425
and 475 lumens?
(b)What percentage of bulbs emit greater than
430 lumens?

WEEK 9-10_NORMAL DISTRIBUTION_46913563.pdf

  • 1.
  • 2.
    INTRODUCTION Most scientific andbusiness data and natural relationships, such as weight, height, etc., when displayed using a histogramfrequency curve are bell-shaped, andsymmetrical, known as NORMAL DISTRIBUTION.
  • 3.
    NORMAL DISTRIBUTION Manythings closelyfollow a Normal Distribution: • heights of people • size of things produced by machines • errors in measurements • blood pressure • scores on a test
  • 4.
    NORMALCURVE. The graphical representationin statistics is called NORMAL CURVE.
  • 5.
    CHARACTERISTICS OF ANORMALCURVE ✓Mathematical model represented by a bell-shaped curve which is symmetric with respect to the mean. ✓The normal curve does not intersect or touch the horizontal axis.
  • 6.
    CHARACTERISTICS OF ANORMALCURVE ✓The mean, median and mode of the normal distribution are equal. ✓The area under the normal curved is approximately equal to 1 or 100%. ✓The standardized normal distribution has a mean of 0 and standard deviation of 1.
  • 7.
    Example: Mean andStd Deviation of the distribution are 55 and 12 respectively
  • 8.
    STANDARD SCORE- z-score •It’ s a measure of how many standard deviations below or above the population mean a raw score is. • z-scores are expressed in terms of standard deviations from their means. • These z-scores have a distribution with a mean of 0 and a standard deviation of 1.
  • 9.
    Standard Score Formula z= (x - µ) / σ • z = standard score • x = given data • µ = mean • σ = standard deviation
  • 10.
    Example: Convert the followingdata to standard score Given score z- score 13 -1.03 12 -1.28 18 + 0.26 20 +0.77 22 +1.28 z = (x - µ) / σ • µ= 17 and σ= 3.9 z = (13 - 17) / 3.9 =
  • 12.
    See how toget the value
  • 13.
    Howto Find theArea under the Normal curve: ComputingNormal Probabilities There are several different situations that can arise when asked to find normal probabilities. I. BETWEEN AZERO AND ANY NUMBER Look at the area in the table.
  • 14.
    II. BETWEEN TWOPOSITIVES, OR BETWEEN TWO NEGATIVES ▶Look at both area in the table and subtract the smaller from larger
  • 15.
    III. BETWEENA NEGATIVEAND A POSITIVE • Look at both areas in the table and add them together.
  • 16.
    IV. LESS THANA NEGATIVE, OR GREATER THAN A POSITIVE ▶Look up the area in the table and subtract from 0.5.
  • 17.
    V. GREATER THANANEGATIVE OR LESS THANA POSITIVE ▶Look at the in the table and add 0.5.
  • 18.
    Area Under NormalCurve Using the table of Area under the Normal Curve,. Determine the Area of the following: 1) Area to the right of Z=0. 2) Area to the left of Z=0. 3) Area from Z=0 to Z=1.25. 4) Area from Z=-1.5 to Z=0. 5) Area between Z=-1.5 to Z=1.5. 6) Area to the left of Z=1.35. 7) Area to the right of Z= 2.0. 8) Area to the right of Z= -3.0. 9) Area to the left of Z= -1.75. 10) Area between Z=-1.67 to Z=-2.0.
  • 19.
    ANSWER 1. 0.5 or50% 2. 0.5 or 50% 3. 0.3944 or 39.44 % 4. 0.4332 or 43.32% 5. 0.8664 or 86.64% 6. 0.9115 or 91.15% 7. 0.0228 or 2.28% 8. 0.9987 or 99.87% 9. 0.0401 or 4.01% 10. 0.0247 or 2. 47%
  • 20.
    Application of theNormal Curve Example 1. The scores of the grade 25 pupils have a mean of 5.35 and standard deviation of 0.45. (a) What percentage of all these scores are lower than 4? (b) What percentage of these scores are between 5 and 6?
  • 21.
    Example 2 You takethe entrance examination and score 68. The mean score for the of the exam is 54 and the standard deviation is 9.7. (a) How well did you score on the test compared to the average test taker?
  • 22.
    Example 2 (b) Ifthere were 500 students who took the examination: i. how many students score between 50 and 70 ii. how many students got below 45
  • 23.
    Example 3 Let's considerthe distribution of the tests for an individual's intelligence quotient (IQ) are designed to be normally distributed, with a mean of 100 and a standard deviation of 15. (a) If score 136 inthe tests for are "potential genius", what percentage of individuals are "potential geniuses"? (b) If there were 800 students who took the IQ test, how many of them are between 110 to 125?
  • 24.
    ACTIVITY 1. Suppose thatthe volume of paint in the 1-gallon paint cans produced by Acme Paint Company is approximately normally distributed with a mean of 1. 04 gallons and a standard deviation of 0.023 gallons. (a)What is the probability that a randomly selected 1-gallon can will actually contain at least 1 gallon of paint? (b)What volume can the Acme Paint Company say that 95% of their cans exceed?
  • 25.
    ACTIVITY 2.Suppose the amountof light (in lumens) emitted by a particular brand of 40W light bulbs is normally distributed with a mean of 450 lumens and a standard deviation of 20 lumens. (a)What percentage of bulbs emit between 425 and 475 lumens? (b)What percentage of bulbs emit greater than 430 lumens?