UPOSE Biology Entrance Test 2016 of the Q8 In animal reproduction the.pdf
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UPOSE Biology Entrance Test 2016 of the Q8 In animal reproduction the formation of gametes takes place in which following? A. Ovary B. Oviduct Uterus Prostrate gland Which of the following blood vessels carries deoxygenated blood away from the heart? A. Aorta B. Pulmonary vein C. Pulmonary artery D. Vena cava Q10. What will happen when plant cells are placed in pure water? A Sugar will leave the cells by diffusion B water will leave by osmosis C water will enter by active transport D water will enter by diffusion a11. What is the name given to a type of cell that lines the trachea (windpipe)? A. Ciliated epithelium B. Lipocyte Erythrocyte D. Neurone Solution Answers : Q29. The correct answer is B (Thick waxy cutucle) : Presence of thick waxy cuticle is an adaptation in plants found in xeric environments/dry places such as opuntia. This is an adaptaion to reduce transpiration/water loss. Q30. The correct answer is C ( Bacteria) : This explains the phenamenan of mutalism or symbiotic relationship.Mutualism is an obligatory, positive, interspecific interaction in which both the interacting partners are strongly benefited from each other. for example, Rhizobium bacteria lives in the root nodules of leguminous plants which fixes atmospheric nitrogen and inturn gets nourshment from the plants..
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right, the cells that will form the peripheral nervous system are represented by 11. The function
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regulation of mineral uptake.
Solution
Answer:
11). A. Prevent wate and minerals from entering the stele through the apoplast, forcing the fluid
to cross cells membrane.
Casparian strip A band of waterproof, corky tissue that is found on the side and walls of the
endodermis of roots. The strip prevents water from entering the pericycle except through the
cytoplasm of endodermal cells; this may be importantin producing root pressure. \"Casparian
strip.\"
12). D. Collenchyma, support
Collenchyma tissue strengthened by the thickening of cell walls, as in young shoots and it gives
mechanical support to plant body.
13). B. Mitochondria
Mitochondria found in both plants and animal. It helps in cellular respiration and release energy.
14). A. Plant 1 has less water.
The water potential increases as the purity of the water increases. If the water has less water
potential means less water and its purity is low. The highest water potential is zero..
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1) The document consists of exam questions from a biology exam covering topics such as respiration, cells, genetics and ecosystems.
2) The exam is multiple choice with 40 questions and candidates are given 45 minutes to complete it.
3) The exam paper contains instructions for candidates on how to fill in their answers and includes a warning that rough working should be done in the exam booklet.
Fill in the blanks. Word banks are given for each fill in and will b.pdf
Determine the number of Wangles. B = 15 degree C. = 65 degree, and a = 19 1 triangle 2
triangles no triangle
Solution
As per the rules of geometry,
The sum of two angles of a triangle is always greater than the side of the third angle
Given B=15
C=65
Hence A= 180-B-C= 100
according to geometry, A>=B+C which is not possible with given measurements
hence no triangle is formed.
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selective permeability affect diffusion. It is hypothesized that potassium permanganate will diffuse
further than methylene blue in agar due to its smaller molecular mass. Starch will remain in a
dialysis tube while iodine enters due to their size difference. A dialysis tube with higher internal
solute concentration will gain volume via osmosis, while one in a hyperosmotic solution will lose
volume.
Q questions 2014
This document contains 29 multiple choice questions from a 2014 Malaysian SPM exam. The questions cover topics in biology like plant structures, nerve pathways, animal digestion systems, genetics, and inherited diseases. Each question is accompanied by 4 possible answer choices labeled A, B, C, or D.
Bio2#9
The document discusses osmoregulation and excretion in animals. It describes how animals regulate water and salt balance in their bodies and remove nitrogenous waste. It covers key organs and systems involved, including kidneys, gills, and Malpighian tubules. It explains processes like filtration, reabsorption, and secretion that occur in nephrons and collecting ducts to produce urine. The two-process model of urine concentration is also summarized, involving a medullary osmotic gradient and the countercurrent mechanism in the loop of Henle.
3.1 movement in-and_out_of_cells-qp_igcse-cie-biology_
This document is a biology exam paper that tests students' understanding of movement in and out of cells through diffusion and osmosis. It contains 30 multiple choice questions about these topics, including questions about:
- The definition of active transport and how it differs from diffusion
- Experiments demonstrating diffusion and osmosis
- How gases like oxygen move in and out of cells in the lungs and leaves
- The effects of osmosis on plant and animal cells in different solutions
- How water is transported in plants
Students must select the best answer from the options provided to demonstrate their knowledge of the key concepts and processes.
AIPMTBiology 1994
This document contains an unsolved biology exam from 1994 containing 46 multiple choice questions testing knowledge of topics including ecology, physiology, evolution, and cell biology. The questions cover subjects such as the levels of DDT deposition in different organisms, the gas that contributes most to the greenhouse effect, the dominant second trophic level in a lake ecosystem, and the pacesetter of the heart.
SOALAN ANALISIS SPM 2014
SOALAN ULANGKAJI SPM 2014 :
1.BM
2.BI
3.MATH
4.SEJARAH
5.SAINS
6.ADD MATH
7.FIZIK
8.KIMIA
9.BIO
10.P.PERAKAUANAN
11.PERDAGANGAN
* 1.untuk dapatkan skema jawapan sila layari
http://e-learningsmktsj2.blogspot.com/
2.Cari nama folder ULANGKAJI SPM 2014 pada box MUAT TURUN BAHAN bahagian paling bawah post dan klik download.
High Yield surgery MCQ episode 3 (NEET PG, NEET SS, INI CET, FMGE)
Visit our telegram channel for daily MCQ
https://t.me/thinksurgery
This is part 3 of MCQ series, covering wide range of topics from surgery.
Many such questions are asked in NEET PG, NEET SS, INI CET and FMGE exams.
Questions are set from standard textbooks like Bailey and Love, and Sabiston textbook of surgery.
Do like the presentation and don’t forget to join our telegram channel for daily MCQ.
The city school 9 t r.s
This document contains a biology test with 9 multiple choice questions about plant cell transport processes. The questions cover topics like active transport of ions into plant cells, the process that moves sugar from leaf cells into phloem tissue, permeability of the plant cell wall and membrane, examples of diffusion in plants, water uptake by plant roots via osmosis, materials that diffusion can occur in, effects of a human red blood cell placed in a salt solution, and membrane transport methods that don't require protein channels or carriers.
Ib ch 1 question-answer
This document contains a biology exam with multiple choice questions testing knowledge of cell structure and function. It includes questions about:
- Striated muscle cells and exceptions to the cell theory
- How stem cells can help treat Stargardt's disease
- Identifying organelles such as mitochondria in electron micrographs
- Where 70S ribosomes are located and membrane protein functions
- Osmosis and the effects of solutions of different salt concentrations on cells
- Types of cellular movement such as facilitated diffusion and active transport
- Cell division processes like mitosis and cytokinesis
- Evidence for the endosymbiotic theory from mitochondrial DNA
- Key aspects of the cell theory including that cells come from pre-
Similar to UPOSE Biology Entrance Test 2016 of the Q8 In animal reproduction the.pdf (20)
based on this evidence Syconoid sponges were derived from leuconoid.pdf
based on this evidence Syconoid sponges were derived from leuconoid.pdf
B. You do an experiment in which you divide 8 cell stage urch.pdf
B. You do an experiment in which you divide 8 cell stage urch.pdf
Fill in the blanks. Word banks are given for each fill in and will b.pdf
Fill in the blanks. Word banks are given for each fill in and will b.pdf
4 chap 10 (kingdom animalia) f.sc 1st year biology helping notes
4 chap 10 (kingdom animalia) f.sc 1st year biology helping notes
3.1 movement in-and_out_of_cells-qp_igcse-cie-biology_
3.1 movement in-and_out_of_cells-qp_igcse-cie-biology_
High Yield surgery MCQ episode 3 (NEET PG, NEET SS, INI CET, FMGE)
High Yield surgery MCQ episode 3 (NEET PG, NEET SS, INI CET, FMGE)
More from fashionbags1
Why do people perceive Mr. Hyde as deformedA He limps.B His sou.pdf
Why do people perceive Mr. Hyde as deformed?
A He limps.
B His soul is deformed by evil.
C He is half blind.
D He suffers from brain damage.
Subject- Literature
-----------------------------------------------------------------
According to Dr. Jekyll, why is Mr. Hyde so much shorter and smaller?
A The evil side of his nature is not as well developed as the good.
B Evil is always less important that good.
C He is physically deformed.
D There is no particular reason; he is just built differently subject-- Literature
Solution
: 1)B. his soul is deformed by evil so he is considered as deformed
2) A. The evil side of his nature is not as well developed as his good side.
What functions are carried out by the human brain Solution .pdf
What functions are carried out by the human brain?
Solution
The brain consists of three major parts: the forebrain (cerebrum and diencephalon),
midbrain (tectum and tegmentum), and hindbrain (pons, cerebellum, medulla). Often the
midbrain, pons, and medulla are referred as the brainstem.
The cerebrum or cortex is the largest part of the human brain and is divided into four
sections or lobes- the frontal lobe, parietal lobe, occipital lobe, and temporal lobe. The functions
of each lobe are:
Frontal Lobe- voluntarymotor activity, speaking ability, thought processes, reasoning, and
problem solving
Parietal Lobe- process sensory information such as temperature, pain, taste and touch; movement
and orientation
The diencephalon contains the epithalamus, thalamus and hypothalamus. Epithalmus
secretes cerebrospinal fluid. Thalamus provides limited sensory awareness of pain, temperature,
touch and pressure. The hypothalamus has important functions such as regulating body
temperature, thirst, foodintake, sleeping rhythms, pituitary glands, emotional and behavioural
patterns.
The cerebellum controls body posture, maintains muscle tone, and coordinate voluntary
muscles. The pons which serves as a bridge between the midbrain and the medulla, controls the
facial and eye muscles. The medulla controls the reflexes for vomiting, swallowing, sneezing,
coughing and hiccupping.
The mid brain is a small constricted portion covered by cerebrum. The parts of tectum
are related to optical activity and auditory functions.
The brain stem is responsible for important life functions such as breathing, heartbeat,
and blood pressure..
Which of the following mediate the interaction of newly synthesized .pdf
Which of the following mediate the interaction of newly synthesized polypeptides with SecYEG
for transport to the periplasm?
A- Sec B
B- Signal recognition particle
C-Trigger factor
D-FtsY
Answer is NOT A
Solution
The answer is B AND D because
it is because of the signal recognition particle receptor which can be either SR or FtsY,the
ribosome secretory protein chain is usually transferred from SRP to the Sec-translocase (in other
words the periplasm)..
Which of the following is NOT true about protostomes They will beco.pdf
Which of the following is NOT true about protostomes? They will become mollusks, annelids,
and arthropods. They are types of advanced invertebrates. The blastopore during embryonic
development becomes the anus. They form true coelom. The mesoderm splits in order to form
the coelom. Which characteristic is shared by both cnidarians and flatworms? Dorsoventrally
flattened bodies. Flame cells. Radially symmetry A digestive system with a single opening.
Both a and D Which of the following features are unique to echinoderms? They are bilaterally
symmetrical as larvae, but undergo radial adults. They possess an endoskeleton of dermal plates
beneath the skin The coelom is transformed into a unique water- vascular system that uses
hydraulic power to operate many tiny feet. They exhibit protosomal growth pattern. Many have
miniature jaw like pincers on their body surface often on stalks and sometimes bearing poison
glands. What confines bryophytes to wet areas? They have no roots. They have no conducting
vessels. They have no waterproof coating. They have swimming sperm. A, B, and D only.
Solution
C. The blastopore during embryonic development becomes the anus in case of deuterostomes
and not in case of protostomes. D. Both cnidarians and flatworms have digestive system with a
single opening. Whereas, flatworms have dorsoventrally flat body and flame cells, and
cnidarians have radial symmetry. A, B, C and E are unique features of echinoderms. D.
Bryophytes are confined to wet areas because they have swimming sperms..
what is the food for mature seeds of monocotsA. Nutrient uptake f.pdf
what is the food for mature seeds of monocots?
A. Nutrient uptake from soil
B.cotyledon
C.endosperm
D.Placenta
Solution
Answer is option C. Endosperm.
In monocots, the single cotyledon is called a scutellum; it is connected directly to the embryo via
vascular tissue. Food reserves are stored in the large endosperm..
What are the ways to conceal theft and what are the principles of in.pdf
What are the ways to conceal theft and what are the principles of internal control?
Solution
How theft Is Concealed in the Accounting Records
The initial entry to record the transaction in the
accounting records must be made in 30 days of the
transaction.
Bank reconciliations are most often done at the end of
the month. In the process of doing a bank
reconciliation, funds disbursed by the organization that
were not booked would be revealed.
The initial entry in the accounting system is usually put
into a temporary spot (e.g., suspense account) and then
subsequently moved and placed in a final account that
will flow through to the financial statements.
Internal control is the process designed to ensure reliable financial reporting, effective and
efficient operations, and compliance with applicable laws and regulations. Safeguarding assets
against theft and unauthorized use, acquisition, or disposal is also part of internal control: The
main internal control principles include:
Establish ResponsibilitiesMaintain RecordsInsure Assets by Bonding Key EmployeesSegregate
of DutiesMandatory Employee RotationSplit Related Party ResponsibilityUse Technological
ControlsPerform Regular Independent Reviews.
Using MatLab Implement a bisection root finding method. Your progra.pdf
Using MatLab: Implement a bisection root finding method. Your program should accept two
endpoints, a tolerance limit and a function for input. It should then output the final
approximation and the number of iterations. Make sure that the program checks that the initial
interval is acceptable for this method.
Solution.
Think of a freshwater pond in Idaho. Name one organism that could li.pdf
Think of a freshwater pond in Idaho. Name one organism that could live in this pond in each of
the following classification groups
Domain Eukarya Kingdom Protista:
Domain Eukarya Kingdom Plantae:
Domain Eukarya Kingdom Animalia:
Domain Eukarya Kingdom Fungi:
Solution
Firstly, it is important to note that a pond ecosystem is a freshwater ecosystem. Thus all the
organisms living in it will be having a freshwater pond ecological-niche.
Since a pond is not deep, so the sunlight can easily penetrate the water and could reach to the
bottom of the pond and can support freshwater aquatic I.e. plant life. Pond ecosystem also
supports growth of fungi, animals, and protists.
Now in the given question it is asked to write about main eukarya kingdom protists, which mean
that these are those eukaryotes that lack multicellular stage or are not plantae, animals or fungi.
Example of it living in pond is amoeba and paramecium (they are animal like freshwater
protists), whereas chlorophyll and diatoms are plant like protists.
Example of domain eukaryotes kingdom plantae are: Bryophyta and mosses.
Example of eukaryotes kingdom animals: zooplanktons and insects.
Example of eukarya kingdom fungi: aquaphila and Jeranium.
The term stationary data means thata. there is an increasing l.pdf
The term \"stationary data\" means that
a. there is an increasing linear trend over time
b. the fitted line goes through the origin
c. the mean is constant
d. there is no change in the data
Solution
stationary means that the distribution does not change with time, which implies that mean is
constant.
The data itself is not constant!.
The social bacteria M. xanthus coordinate group attacks on other bac.pdf
The social bacteria M. xanthus coordinate group attacks on other bacteria, rapidly consuming
entire colonies of prey. Researchers may be interested in many different aspects of this behavior.
Recall Tinbergen\'s classification of questions about behavior (click here to go back to page 2
and review). Which of the following hypotheses suggests the potential ADAPTIVE VALUE of
such a coordinated attack?
1.M. xanthus use chemical signals that are exchanged between neighbors to coordinate their
attacks.
2. Coordinated attacks are unique among bacteria, having evolved in only M. xanthus.
3. M. xanthus that engage in coordinated attacks feed more efficiently and reproduce faster than
those that don\'t.
4. M. xanthus only engage in coordinated attacks if they have reached a certain, more mature,
developmental stage.
Solution
Answer : 3
M. xanthus that engage in coordinated attacks feed more efficiently and reproduce faster than
those that don\'t..
Step 1 trace the development of the male gamete Procedure 1 Time to .pdf
Step 1 trace the development of the male gamete Procedure 1 Time to Trace In this exercise, you
will trace the male and female gametes from their production in the gonads to the point at which
they meet in the uterine tube, where fertilization takes place. Step 1: Male Gamete Trace the
male gamete from its earliest stage--the spermatogonium in the seminiferous tubule--through the
stages of spermatogenesis to a mature sperm, and then through the male reproductive tract until it
exits the body and enters the uterine tube of the female reproductive tract. Trace the pathway
using Figure 16.14, and also fill in the space below. Start: spermatogonium FIGURE 16.14 Male
reproductive tract End: Uterine tube 16 Reproductive systems I UNIT 16 I 419
Solution
1: The germ cells of seminiferous tubules present near the capsule serve as spermatogonia which
divide and produce more cells by mitosis. Some of these new cells serve as primary
spermatocytes that undergo meiosis; meiosis I produces two secondary spermatocytes (n) which
is followed by meiosis II that produces four spermatids. The spermatids enter the epidydimis
where they are stored and capacitated. Vas deferens serves to transports mature sperm to the
urethra in preparation for ejaculation. Urethra serves to ejaculalte the semen during intercourse
(prostetic urethra--> membranous urethra-->penial urethra--> external urethral meatus)
2: During foetal development, few germinal cells in ovary differentiate and divide mitotically to
produce oogonia which in turn divide to produce diploid primary oocyte. In follicular prenatal
phase, the primary oocytes start first meiotic division but are transitionally suspended into
prophase stage of meiosis I. After puberty, primary oocyte resumes the division and completion
of first meiotic division produce one secondary oocyte and one polar body. The secondary
oocyte is released from ovary to fallopian tube where it fuses with sperm and completes the
meiosis II. If fertilization does not occur, the degeneration of corpus luteum cause menstruation
and the secondary oocyte is expelled out through vag alog with endometrium of uterus. (ovary-->
fallopian tube-->uterus--> vag)..
So this is Enterobacter sp. please tell ne the cell shape, cell arra.pdf
So this is Enterobacter sp. please tell ne the cell shape, cell arrangements, and the color. thank
you!
71, ..art.. .. *-. i
Solution
Answer:
Enterobacter is the genus of bacteria belongs to enteric bacteria (Enterobacteriaceae), are non-
spore forming, gram negative rods which are categorized as facultative anaerobes. Enterobacter
sp. are come in the category of non-fecal coliforms (colifoms but not present in feces). There are
several reported pathogenic Enterobacter sp. and some Enterobacter sp. are reported as non-
pathogenic.
Cell shape : Straight rod
Cell arrangements : Single
Color : They are gram negative, thus observed as pink colour cells (due to safranin dye) after
gram staining..
Phagocytosis pinocytosis receptor-mediated endocytosis secondary Cl.pdf
Phagocytosis pinocytosis receptor-mediated endocytosis secondary Clive transport Passive
membrane transport processes include movement of a substance down its concentration gradient
movement of water from an area of low concentration to an area of high concentration
consumption of ATP the use of transport proteins Peroxisomes are also called microbodies, and
contain acid hydrolases are able to detoxify substances by enzymatic action o function to digest
particles ingested by endocytosis sometimes function as secretary vesicles DNA replication can
also be called mitosis is spontaneous, not requiring enzyme action taken place during interphase
of the cell cycle occurs only in translationally active areas In the maintenance of the cell resting
membrane potential extracellular sodium levels are high cells are more permeable to Na+ than
K+ the steady state involves only passive processes in all cells the inside of the cell is positive
relative to its outside Which of the following does not serve as a signal for cell division?
repressor genes joining of cyclins and Cakes contact inhibition surface-to-volume ratio
Solution
38. (a)
39. (D) Phospholipids
40. (D) Mitosis always results in cell replication
41.(a) melanin is a pigment.
The oxygen revolution facilitated by cyanobacteria had an enormou.pdf
The \"oxygen revolution\" facilitated by cyanobacteria had an enormous impact on life in our
planet. As a result, the rising concentration of atmospheric oxygen wiped out the prokaryotic
organisms that flourished in the CO2 rich environment: none of these early prokaryotic
organisms has survived to present times. True False Kuru is caused by a neurotropic virus that
\"homes\" in the brain cells. This virus belongs to the same family of viruses that cause mad cow
disease, and it is one of the smallest life forms\" known to science. True False Lipid bilayers can
only be synthetized by biological organisms. This is supported by the rise of internal
compartmentalization seen in eukaryotic organisms. It is thought that the formation of internal
organelles in eukaryotic cells resulted from the invagination of the external cell membrane in
prokaryotic cells True False Abiogenesis is the hypothesis that life exists throughout the
universe, distributed by meteorites, planetoids and asteroids. The theory of abiogenesis proposes
that life in this planet arouse from extremophile bacteria that came from outer space trapped in
interstellar debris. True False The basic elements that are the building blocks of life in this planet
are only found in living organisms; hence, these are only of biological origin. This contradicts
the theory of abiogenesis. True False DNA is the only known source of genetic information/code
for biological organisms/systems in this planet. True False the Cretaceous mass extinction is
thought to have occurred as a result of a massive meteorite impact near the Yucatan peninsula.
The impact crater (recently located) together with the iridium deposits in the days of the planet,
supports this hypothesis. True False Reproduction, mutation, use of energy and evolution are
characteristics only of living things. True False
Solution
28)
The micro fossils discovered in the rocks more than 3.5 billion years old were the single celled
prokaryotic organisms resembling the modern bacteria. These must have evolved in absence of
oxygen. Over time, photosynthetic organisms (cyanobacteria) might have evolved increasing the
concentration of oxygen in the atmosphere. This has caused some organisms to extinct because
they could not tolerate the high oxygen levels and some organisms to develop more effective
metabolic pathways to metabolize the oxygen. The statement is true.
29)
Kuru is a neurodegenerative disease caused by abnormally folded protein agents called prions.
Mad cow disease or bovine spongiform encephalopathy or mad cow disease is also caused by a
misfolded protein agent called prion. The given statement is true.
30)
The prokaryotic cells evolved earlier were started to develop internal membranes some 2 billion
years ago, due to which the evolution of eukaryotic cells had took place. The eukaryotic
organelles like mitochondria and chloroplast resemble the prokaryotic cells. This has happened
due to establishment of symbiotic relationship bet.
In your own words how you would describe the function of the followi.pdf
In your own words how you would describe the function of the following organelles?
What are the function of the lysosome?
What are the function of the rough and smooth endoplasmic reticulum?
What are the function of the ribosomes?
What are the functions of the mitochondria?
What are the functions of the cell membrane?
Solution
Lysosome:
Rough Endoplasmic reticulum:
Smooth Endoplasmic reticulum:
Ribosome: these are very important organelles which are sites for protein synthesis i.e.
translation.
Mitochondria:.
Please explain how(4.17) If we leave out the low outlier, the cor.pdf
Please explain how(4.17) If we leave out the low outlier, the correlation for the remaining 14
points in Figure 4.7 is closest to
Please explain howA.0.9.B.-0.9.C.0.1. (4.17) If we leave out the low outlier, the correlation for
the remaining 14 points in Figure 4.7 is closest to Please explain how
Solution
Answer is (A)0.9.
On the Isle of Man off the coast of Ireland, a curious cat referred .pdf
On the Isle of Man off the coast of Ireland, a curious cat referred to as a manx cat was described
in 1845. It had long hind legs and a short tail. Further work showed that the manx characteristics
were the result of a dominant M allele at a single locus. An MM zygote would not survive, but
Mm genotypes produced the manx characteristics. Imagine a scenario where the M allele arises
by mutation on the Isle of Man. Explain how genetic drift could cause the M allele to reach a
relatively high frequency (freq(M) > 0.25), even though it has harmful effects on fitness.
Solution
Genetic drift is the force of evolution which causes separation of individuals of a species due to
geographical isolation. This causes these organisms to survive as a separate species and evolve at
their respective geographical locations.
According to the information, the dominant allele M is lethal to the organisms. Inspite of this
fact, the frequency of allele M is increasing on the geographical area separated due to genetic
drift. This suggests that the individuals on this geographical area might possess any kind of
adaptability soleley due to presence of this dominant M allele. Nevertheless, it remains highly
unlikely that the homozygous MM individuals will survive even on this island due to biological
failures. However, individuals with heterozygous Mm genotype must have biological benefits
against any stressor/stimulus at this new location. This benefit must be promoting these
individuals to survive better than any of the individuals with homozyogous genotype.
Thus, this particular case of fixation of higher allele frequency of geotype M in heterozygous
conditions deviates from the Hardy-Weinberg law, hence there are individuals with relatively
higher frequency of allele M..
John has created an incredibly successful wine operation in the Nort.pdf
John has created an incredibly successful wine operation in the Northeast. He has vineyard lands
along the Seneca and Cayuga wine trails in the Finger Lakes of New York. Many of his wineries
are considered some of the best on the East Coast, and one of them, “Jennifer T” was recently
named winery of the year by Wine Spectator magazine. In all, there are 5 different wineries
operations each in a different corporation. All 5 are in a separate S-Corporation with all the stock
owned by the parent Company Petosa Vineyards Inc, also an S-Corporation. John and his wife
Jennifer own 75% of the stock of the parent Company which means they own 75% of all of the
value of the entities. Jennifer and John are each other’s second marriage. John has three children
from his prior marriage and Jennifer has 2 children from her previous marriage. John and
Jennifer’s family have been an important part of the Company’s growth. John’s brother, Tom
became a partner in the business providing much needed capital when the wineries were in a
growth stage. Tom owns 20% of the remaining stock and he has 2 children who work at the
winery on weekends doing wine tasting, but have other jobs during the week. Jennifer’s sister
Karen owns the remaining 5% of the outstanding shares. Karen has 3 children, none of which are
involved in the wine operations. However, Karen has one son, Stephen, who has an engineering
degree from Georgia Tech and has been helpful in development of the winery’s bio-dynamic
farming operations. Stephen has expressed an interest in becoming a bigger part of the overall
operations as he enjoys the laid back lifestyle the winery offers. Jennifer has been the driving
force behind the winery’s commitment to bio-dynamic, organic farming. She has been in charge
of the vineyard operations and overall marketing. Jennifer’s two sons have also been very
involved in the winery operations. Albert received his degree from Syracuse University in
Economics and Entrepreneurship. After a few summers working as a landscaper, he learned that
he loved to work the land and has been the one to implement his mother’s organic farming
techniques at the various vineyards. Nino graduated from Syracuse University with a degree in
information studies. He has been in charge of the information systems for the wineries. He has
also been responsible for the social media and other electronic marketing methods that have
catapulted the growth in the company’s exports to other states and overseas markets. Only
Christopher, of John’s three children has been involved in the wineries. Chris, a graduate of SU’s
Whitman School of Management with a degree in accounting and the Syracuse College of Law,
has been the CFO of the Company and the lead wine maker following in his father’s footsteps. It
has been Chris’ adept touch and penchant for knowing just when to harvest the grapes that has
been crucial to the recent accolades received by various wine rating agencies. Jay and Allyson
are John’s othe.
In a survey conducted in November 2002 of 1400 international bus.pdf
In a survey conducted in November 2002 of 1400 international business travelers concerning in-
flight service over the past few years, the following information was obtained:
Comments on Quality of Service | Respondents
Has remained the same from 2 yrs ago | 630
Has diminished over that time frame | 406
Has improved over that time frame | 336
Wasn\'t sure | 28
If a person in the survey is chosen at random, what is the probability that he or she has rated in-
flight service as:
Remaining the same or improved over the time frame in question?
Remaining the same or diminished over the time frame in question?
In a survey conducted in November 2002 of 1400 international business travelers concerning in-
flight service over the past few years, the following information was obtained:
Comments on Quality of Service | Respondents
Has remained the same from 2 yrs ago | 630
Has diminished over that time frame | 406
Has improved over that time frame | 336
Wasn\'t sure | 28
If a person in the survey is chosen at random, what is the probability that he or she has rated in-
flight service as:
Remaining the same or improved over the time frame in question?
Remaining the same or diminished over the time frame in question?
In a survey conducted in November 2002 of 1400 international business travelers concerning in-
flight service over the past few years, the following information was obtained:
Comments on Quality of Service | Respondents
Has remained the same from 2 yrs ago | 630
Has diminished over that time frame | 406
Has improved over that time frame | 336
Wasn\'t sure | 28
If a person in the survey is chosen at random, what is the probability that he or she has rated in-
flight service as:
Remaining the same or improved over the time frame in question?
Remaining the same or diminished over the time frame in question?
Solution.
If a plant is test-crossed which of the following genes are linked.pdf
If a plant is test-crossed which of the following genes are linked?
A. Flower color and height
B. Flower color and flower placement
C. Flower placement and height
D. None of these genes appear to be linked phenotype Tall/purple/axial Tall/white/axial Short/ ur
Short/white/axial Short/white/terminal Short/purple/terminal Tall/white/terminal
Tall/purple/terminal Progeny number 3709 70 2034 2507 39 72 3507
Solution
The linked in a cross table is observable by parent genotypes.
The parental genotypes are always those who are in maximum numbers.
The parental are Tall/ purple / axial and Tall purple terminal are dominant [high number].
Short/ white/ terminal and short white axial are recessive parents [less number]
As we can see in both parents only axial and terminal are change, other two characters height and
flower color are not changing. Therefore, they are tightly arrange and called as linked.
The option A is correct..
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Think of a freshwater pond in Idaho. Name one organism that could li.pdf
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So this is Enterobacter sp. please tell ne the cell shape, cell arra.pdf
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Phagocytosis pinocytosis receptor-mediated endocytosis secondary Cl.pdf
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The oxygen revolution facilitated by cyanobacteria had an enormou.pdf
The oxygen revolution facilitated by cyanobacteria had an enormou.pdf
In your own words how you would describe the function of the followi.pdf
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Syllabus
Chapter-1
Introduction to objective, scope and outcome the subject
Chapter 2
Introduction: Scope and Specialization of Civil Engineering, Role of civil Engineer in Society, Impact of infrastructural development on economy of country.
Chapter 3
Surveying: Object Principles & Types of Surveying; Site Plans, Plans & Maps; Scales & Unit of different Measurements.
Linear Measurements: Instruments used. Linear Measurement by Tape, Ranging out Survey Lines and overcoming Obstructions; Measurements on sloping ground; Tape corrections, conventional symbols. Angular Measurements: Instruments used; Introduction to Compass Surveying, Bearings and Longitude & Latitude of a Line, Introduction to total station.
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Chapter 4
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Chapter 5
Transportation: Introduction to Transportation Engineering; Traffic and Road Safety: Types and Characteristics of Various Modes of Transportation; Various Road Traffic Signs, Causes of Accidents and Road Safety Measures.
Chapter 6
Environmental Engineering: Environmental Pollution, Environmental Acts and Regulations, Functional Concepts of Ecology, Basics of Species, Biodiversity, Ecosystem, Hydrological Cycle; Chemical Cycles: Carbon, Nitrogen & Phosphorus; Energy Flow in Ecosystems.
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2. Satheesh Gopi, Basic Civil Engineering, Pearson Publishers.
3. Ketki Rangwala Dalal, Essentials of Civil Engineering, Charotar Publishing House.
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