IT IS AN IMPORTANT TOPIC FOR ALL COMPETITIVE LEVEL EXAMINATIONS OR GOVT EXAMINATIONS. IT IS VERY HELPFUL FOR THOSE WHO ARE APPEARING FOR THOSE JOB EXAMINATIONS,
The document provides information on chain surveying and compass surveying. It defines surveying and its fundamental principles such as working from whole to part and locating new stations by at least two measurements. Chain surveying involves measuring linear distances with a chain and establishing a framework of triangles. It discusses the instruments used, types of chains, errors in chaining, and fieldwork procedures. Compass surveying determines directions using a compass and measures distances with a chain. It defines true and magnetic meridians/bearings and methods for recording whole circle and quadrantal bearings.
Distance Measurement & Chain Surveying
Contents
• Introduction About Surveying
.
• Primary Division Of Surveying • Classification Of Surveying • Distance Measurement And Chain Surveying • Principle Of Surveying • Types Of Tapes Based On The Materials Used • Erecting And Dropping A Perpendicular • Obstacle In Chain Survey • Types Of Errors • Corrections of Tape • Off –Sets • Ranging • Conclusion . • Homework And Next Lecture . • References.
-Definition of Surveying.
Types of Surveying
1. Plane Surveying
2. Geodetic Survey
3. Cadastral surveying
4. Aerial Surveying
5. Hydro graphic Surveying (Hydro-Survey)
6. Topographical Survey
7. Engineering Survey.
Primary division of Surveying
Reconnaissance.
• This is preliminary survey of the land to be surveyed. It may be either
1-Ground reconnaissance 2- Aerial reconnaissance survey.
Objectives of Reconnaissance
1. To ascertain the possibility of building or constructing route or track through the area.
Classification of Surveying:
1- Classification based on the instruments used:
A. Chain Surveying.
B. Compass Surveying.
C. Theodolite Surveying.
D. Tachometric Surveying .
E. Trigonometric Surveying.
F. Total station and GPS.
G. Photogrammetric and Aerial Surveying.
H. Plan Table .
2- According to the method used:
i. Traversing .
ii. Triangulation .
iii. Tacheometric.
iv. Trigonometric.
3- According to the Purpose of surveying:
i. Engineering survey.
ii. Military survey.
iii. Geological survey .
iv. Topographical survey
Chain and Tape Survey
-Length& Distance Measurements.
-Distance Measurement and Chain Surveying.
• In general there are two methods:
1- Direct methods of measuring lengths
2- Indirect methods of measuring distances.
There are two kinds of measurements used in plane surveying.
*Linear measurements
*Angular measurements
-Instruments used in Chain Surveying.
Types of tapes based on the materials used.
.......
.
.
.
.
.
.
.
.
.
.
Asst. Prof. Salar K.Hussein
Mr. Kamal Y.Abdullah
Asst.Lecturer. Dilveen H. Omar
Erbil Polytechnic University
Technical Engineering College
Civil Engineering Department
1. Contours are imaginary lines on a map that connect points of equal elevation. Contour maps show these lines, representing the topography of the land.
2. There are two main methods for creating contour maps - direct and indirect. The direct method involves precisely surveying points along contour lines in the field. The indirect method takes spot elevations across an area and interpolates the contour lines.
3. Common techniques for indirect contouring include dividing the area into squares and taking elevation readings at each corner, taking cross-sections of long strips, and using a tacheometer which can measure horizontal distances and elevations from a single station.
Kamavacara cittas are the 54 types of consciousness mostly experienced through the senses. They can be divided into four categories:
1. Akusala cittas (12 types of immoral consciousness) which are further divided into lobha-mula, dosa-mula, and moha-mula cittas based on their root causes of greed, hatred, and delusion.
2. Ahetuka cittas (18 rootless types of consciousness).
3. Kama-sobhana cittas (24 beautiful types of consciousness in the sense sphere) which can be further divided into maha-kusala, maha-vipaka
Hydraulics uses liquid pressure to transmit and multiply forces. A small force applied to a master piston is transmitted evenly through the liquid to exert pressure on a larger slave piston. This allows the larger slave piston to multiply the original force. Common hydraulic systems use this principle, such as car brakes which use a small brake pedal force to generate a larger braking force at each wheel through hydraulic fluid pressure. The key features of hydraulics are that pressure is transmitted evenly through the liquid and a small force can be used to create a much larger force via pistons of different sizes.
This document discusses contour mapping and surveying techniques. It contains:
1) Definitions of key terms like contour, contour line, contour map, and contour interval.
2) Descriptions of the direct and indirect methods for locating contours in the field. The direct method involves directly tracing and marking contour points, while the indirect method involves taking spot levels and interpolating the contours.
3) Characteristics used to identify topographic features like hills, depressions, ridges, and valleys from the pattern of contour lines on a map.
The document provides information on chain surveying and compass surveying. It defines surveying and its fundamental principles such as working from whole to part and locating new stations by at least two measurements. Chain surveying involves measuring linear distances with a chain and establishing a framework of triangles. It discusses the instruments used, types of chains, errors in chaining, and fieldwork procedures. Compass surveying determines directions using a compass and measures distances with a chain. It defines true and magnetic meridians/bearings and methods for recording whole circle and quadrantal bearings.
Distance Measurement & Chain Surveying
Contents
• Introduction About Surveying
.
• Primary Division Of Surveying • Classification Of Surveying • Distance Measurement And Chain Surveying • Principle Of Surveying • Types Of Tapes Based On The Materials Used • Erecting And Dropping A Perpendicular • Obstacle In Chain Survey • Types Of Errors • Corrections of Tape • Off –Sets • Ranging • Conclusion . • Homework And Next Lecture . • References.
-Definition of Surveying.
Types of Surveying
1. Plane Surveying
2. Geodetic Survey
3. Cadastral surveying
4. Aerial Surveying
5. Hydro graphic Surveying (Hydro-Survey)
6. Topographical Survey
7. Engineering Survey.
Primary division of Surveying
Reconnaissance.
• This is preliminary survey of the land to be surveyed. It may be either
1-Ground reconnaissance 2- Aerial reconnaissance survey.
Objectives of Reconnaissance
1. To ascertain the possibility of building or constructing route or track through the area.
Classification of Surveying:
1- Classification based on the instruments used:
A. Chain Surveying.
B. Compass Surveying.
C. Theodolite Surveying.
D. Tachometric Surveying .
E. Trigonometric Surveying.
F. Total station and GPS.
G. Photogrammetric and Aerial Surveying.
H. Plan Table .
2- According to the method used:
i. Traversing .
ii. Triangulation .
iii. Tacheometric.
iv. Trigonometric.
3- According to the Purpose of surveying:
i. Engineering survey.
ii. Military survey.
iii. Geological survey .
iv. Topographical survey
Chain and Tape Survey
-Length& Distance Measurements.
-Distance Measurement and Chain Surveying.
• In general there are two methods:
1- Direct methods of measuring lengths
2- Indirect methods of measuring distances.
There are two kinds of measurements used in plane surveying.
*Linear measurements
*Angular measurements
-Instruments used in Chain Surveying.
Types of tapes based on the materials used.
.......
.
.
.
.
.
.
.
.
.
.
Asst. Prof. Salar K.Hussein
Mr. Kamal Y.Abdullah
Asst.Lecturer. Dilveen H. Omar
Erbil Polytechnic University
Technical Engineering College
Civil Engineering Department
1. Contours are imaginary lines on a map that connect points of equal elevation. Contour maps show these lines, representing the topography of the land.
2. There are two main methods for creating contour maps - direct and indirect. The direct method involves precisely surveying points along contour lines in the field. The indirect method takes spot elevations across an area and interpolates the contour lines.
3. Common techniques for indirect contouring include dividing the area into squares and taking elevation readings at each corner, taking cross-sections of long strips, and using a tacheometer which can measure horizontal distances and elevations from a single station.
Kamavacara cittas are the 54 types of consciousness mostly experienced through the senses. They can be divided into four categories:
1. Akusala cittas (12 types of immoral consciousness) which are further divided into lobha-mula, dosa-mula, and moha-mula cittas based on their root causes of greed, hatred, and delusion.
2. Ahetuka cittas (18 rootless types of consciousness).
3. Kama-sobhana cittas (24 beautiful types of consciousness in the sense sphere) which can be further divided into maha-kusala, maha-vipaka
Hydraulics uses liquid pressure to transmit and multiply forces. A small force applied to a master piston is transmitted evenly through the liquid to exert pressure on a larger slave piston. This allows the larger slave piston to multiply the original force. Common hydraulic systems use this principle, such as car brakes which use a small brake pedal force to generate a larger braking force at each wheel through hydraulic fluid pressure. The key features of hydraulics are that pressure is transmitted evenly through the liquid and a small force can be used to create a much larger force via pistons of different sizes.
This document discusses contour mapping and surveying techniques. It contains:
1) Definitions of key terms like contour, contour line, contour map, and contour interval.
2) Descriptions of the direct and indirect methods for locating contours in the field. The direct method involves directly tracing and marking contour points, while the indirect method involves taking spot levels and interpolating the contours.
3) Characteristics used to identify topographic features like hills, depressions, ridges, and valleys from the pattern of contour lines on a map.
CT 1 NOTES FOR ACTUARIAL SCIENCE BY SOURAV SIR'S CLASSES 9836793076 SOURAV DAS
Money-weighted and time-weighted rates of return are two methods for measuring investment performance. The money-weighted rate considers cash flows, so it depends on an individual investor's activities. The time-weighted rate ignores cash flows and measures only market performance over a period. It is preferred for evaluating managers because it is not affected by deposits or withdrawals outside their control. The document provides examples of calculating each type of return for portfolios with cash flows over multiple periods.
GAME THEORY NOTES FOR ECONOMICS HONOURS FOR ALL UNIVERSITIES BY SOURAV SIR'S ...SOURAV DAS
This document provides an overview of game theory concepts including definitions of key terms like mixed strategy, Nash equilibrium, payoff, perfect information, player, rationality, strategic form, strategy, zero-sum game, cooperative games, non-cooperative games, representation of games as normal form, pure vs mixed strategies, two-person zero-sum games, examples of zero-sum games, and using linear programming to determine optimal strategies in a game.
The document discusses the results of a study on the impact of climate change on global wheat production. Researchers found that rising temperatures will significantly reduce wheat yields across different regions of the world by the end of the century. Under a high emissions scenario, the study projects a global average decrease in wheat production of 6% by 2050, and a 17% decrease by 2100, threatening global food security.
Justin Bieber is a Pisces singer from Canada. His last girlfriend was Selena Gomez. His original YouTube channel was called Justinbieber. His mother's name is Pattie and he has one sibling. His hamster was named Jackson and his manager is Scooter Braun.
The document outlines an agenda for a meeting that includes:
1) Introducing who the company is and who they are trying to help with their product
2) Demonstrating their product
3) Having a question and answer session
The document provides information about starting a business in Truckee, California, including the permit process, fees, and requirements for use permits and minor use permits, as well as an application for a temporary sign permit.
La leyenda cuenta el diálogo entre un niño por nacer y Dios. El niño expresa sus temores sobre vivir en la tierra pequeño e indefenso, pero Dios le asegura que ha escogido un ángel para cuidarlo y protegerlo, que le cantará, sonreirá y enseñará a orar y hablar para que sea feliz a pesar de la ausencia de Dios.
CALCUTTA UNIVERSITY (CU),
JADAVPURE UNIVERSITY(JU)
PRESIDENCY UNIVERSITY,
ST. XAVIER’S COLLEGE
(SEPARATE BATCHES)
SOLUTION OF MODEL QUESTION PAPERS ANSWERS,
10 YEARS AND ALL RELEVANT BOOK EXERCISES.
SPECIAL CLASSES FOR
COMPETITIVE LEVEL EXAMINATION FOR ENTRY IN M.SC.
COURSE AT JNU, ISI, DU, CU.
LIBRARY ACCESS. STUDY MATERIALS.
STUDENTS CAN ALSO HAVE
STATISTICS and MATHEMATICS ( general)
for
B.SC. LEVEL
This empathy map outlines the perspective of a working student who feels they have not enough time, experiences stress trying to balance work, life, and school, and feels alone without a support system. The working student tends to study alone or in ad hoc groups and worries that schools do not help address the challenges of being a working student. The problem statement identifies that working students need a way to connect with other working students to help manage their work and studies and expand their social and professional networks.
The manager summarizes the challenges they face with their recent graduate hiring and training program. There is a generational gap between the new graduates and managers, as the graduates have high expectations but lack experience, while managers find their work superficial. Retention rates are lower than hoped. The manager seeks to improve connections between graduates and managers and bridge their differences in needs and expectations.
I.Q. Enterprises manufactures and exports a diverse range of crowd and queue management products under the brand Q-Manager. The company pioneered these products in India over two decades and now has a global clientele. Q-Manager offers retractable belt posts, classic rope and chain posts, café barriers, and other products to help businesses manage customer flow and space. I.Q. Enterprises prides itself on providing customized solutions from manufacturing to delivery while maintaining high quality standards.
Benchmarking for Social Media: Get Social Brevard PresentationStephanie Byrd
Social Media Benchmarking on Facebook is a valuable tool. You can measure your internal engagement against your external competition or to an amazing standard like George Takei. Why is he worried...he has 4.3 million fans? Engagement to your audience always involves roamers and zombie fans. Presented at Get Social Brevard.
This document provides an introduction to Java, discussing its objectives, types of Java programs including applets and applications, the Java Virtual Machine, integrated development environments, the Java Development Kit and its tools, new features in Java 2, present Java technologies, and future trends.
A general introduction to the Turnitin Plagiarism Checker. The simple slideshow explains how to create a student account, submit an assignment paper, find the Originality Report and how to understand the report.
This document does not contain any substantive information to summarize in 3 sentences or less. It only repeats the date "Wednesday, August 7, 13" multiple times without providing any additional context or details.
Unit Nexus is a leading IT company based in India that provides software development and web design services. It has offices in multiple Indian cities and works with clients around the world. The company focuses on creating customized software and website solutions for clients using technologies like .NET, PHP, and Android/iPhone development. Unit Nexus aims to deliver high quality services on a low budget while maintaining transparency and customer satisfaction.
The person interviewed faces high stress at work and feels unrewarded for their work. They believe managing stress will be a lifelong process and suggest activities like meditation, exercise, and spending time with supportive people help alleviate stress.
Ix physics motion_and_rest_solved_numericalMoaizschah
This document contains multiple choice questions and solved numerical problems related to the topic of motion and rest from the ninth grade physics curriculum in India. It covers concepts like distance, displacement, velocity, uniform and non-uniform motion, acceleration, and graphs related to distance-time and velocity-time. Several word problems involve calculating speed, acceleration, time, or distance given certain variables like initial/final velocities or acceleration. The document aims to help students practice and understand concepts of motion through these sample questions.
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship PGPSE is for those who want to transform the world. It is different from MBA, BBA, CFA, CA,CS,ICWA and other traditional programmes. It is based on self certification and based on self learning and guidance by mentors. It is for those who want to be entrepreneurs and social changers. Let us work together. Our basic idea is that KNOWLEDGE IS FREE & AND SHARE IT WITH THE WORLD
CT 1 NOTES FOR ACTUARIAL SCIENCE BY SOURAV SIR'S CLASSES 9836793076 SOURAV DAS
Money-weighted and time-weighted rates of return are two methods for measuring investment performance. The money-weighted rate considers cash flows, so it depends on an individual investor's activities. The time-weighted rate ignores cash flows and measures only market performance over a period. It is preferred for evaluating managers because it is not affected by deposits or withdrawals outside their control. The document provides examples of calculating each type of return for portfolios with cash flows over multiple periods.
GAME THEORY NOTES FOR ECONOMICS HONOURS FOR ALL UNIVERSITIES BY SOURAV SIR'S ...SOURAV DAS
This document provides an overview of game theory concepts including definitions of key terms like mixed strategy, Nash equilibrium, payoff, perfect information, player, rationality, strategic form, strategy, zero-sum game, cooperative games, non-cooperative games, representation of games as normal form, pure vs mixed strategies, two-person zero-sum games, examples of zero-sum games, and using linear programming to determine optimal strategies in a game.
The document discusses the results of a study on the impact of climate change on global wheat production. Researchers found that rising temperatures will significantly reduce wheat yields across different regions of the world by the end of the century. Under a high emissions scenario, the study projects a global average decrease in wheat production of 6% by 2050, and a 17% decrease by 2100, threatening global food security.
Justin Bieber is a Pisces singer from Canada. His last girlfriend was Selena Gomez. His original YouTube channel was called Justinbieber. His mother's name is Pattie and he has one sibling. His hamster was named Jackson and his manager is Scooter Braun.
The document outlines an agenda for a meeting that includes:
1) Introducing who the company is and who they are trying to help with their product
2) Demonstrating their product
3) Having a question and answer session
The document provides information about starting a business in Truckee, California, including the permit process, fees, and requirements for use permits and minor use permits, as well as an application for a temporary sign permit.
La leyenda cuenta el diálogo entre un niño por nacer y Dios. El niño expresa sus temores sobre vivir en la tierra pequeño e indefenso, pero Dios le asegura que ha escogido un ángel para cuidarlo y protegerlo, que le cantará, sonreirá y enseñará a orar y hablar para que sea feliz a pesar de la ausencia de Dios.
CALCUTTA UNIVERSITY (CU),
JADAVPURE UNIVERSITY(JU)
PRESIDENCY UNIVERSITY,
ST. XAVIER’S COLLEGE
(SEPARATE BATCHES)
SOLUTION OF MODEL QUESTION PAPERS ANSWERS,
10 YEARS AND ALL RELEVANT BOOK EXERCISES.
SPECIAL CLASSES FOR
COMPETITIVE LEVEL EXAMINATION FOR ENTRY IN M.SC.
COURSE AT JNU, ISI, DU, CU.
LIBRARY ACCESS. STUDY MATERIALS.
STUDENTS CAN ALSO HAVE
STATISTICS and MATHEMATICS ( general)
for
B.SC. LEVEL
This empathy map outlines the perspective of a working student who feels they have not enough time, experiences stress trying to balance work, life, and school, and feels alone without a support system. The working student tends to study alone or in ad hoc groups and worries that schools do not help address the challenges of being a working student. The problem statement identifies that working students need a way to connect with other working students to help manage their work and studies and expand their social and professional networks.
The manager summarizes the challenges they face with their recent graduate hiring and training program. There is a generational gap between the new graduates and managers, as the graduates have high expectations but lack experience, while managers find their work superficial. Retention rates are lower than hoped. The manager seeks to improve connections between graduates and managers and bridge their differences in needs and expectations.
I.Q. Enterprises manufactures and exports a diverse range of crowd and queue management products under the brand Q-Manager. The company pioneered these products in India over two decades and now has a global clientele. Q-Manager offers retractable belt posts, classic rope and chain posts, café barriers, and other products to help businesses manage customer flow and space. I.Q. Enterprises prides itself on providing customized solutions from manufacturing to delivery while maintaining high quality standards.
Benchmarking for Social Media: Get Social Brevard PresentationStephanie Byrd
Social Media Benchmarking on Facebook is a valuable tool. You can measure your internal engagement against your external competition or to an amazing standard like George Takei. Why is he worried...he has 4.3 million fans? Engagement to your audience always involves roamers and zombie fans. Presented at Get Social Brevard.
This document provides an introduction to Java, discussing its objectives, types of Java programs including applets and applications, the Java Virtual Machine, integrated development environments, the Java Development Kit and its tools, new features in Java 2, present Java technologies, and future trends.
A general introduction to the Turnitin Plagiarism Checker. The simple slideshow explains how to create a student account, submit an assignment paper, find the Originality Report and how to understand the report.
This document does not contain any substantive information to summarize in 3 sentences or less. It only repeats the date "Wednesday, August 7, 13" multiple times without providing any additional context or details.
Unit Nexus is a leading IT company based in India that provides software development and web design services. It has offices in multiple Indian cities and works with clients around the world. The company focuses on creating customized software and website solutions for clients using technologies like .NET, PHP, and Android/iPhone development. Unit Nexus aims to deliver high quality services on a low budget while maintaining transparency and customer satisfaction.
The person interviewed faces high stress at work and feels unrewarded for their work. They believe managing stress will be a lifelong process and suggest activities like meditation, exercise, and spending time with supportive people help alleviate stress.
Ix physics motion_and_rest_solved_numericalMoaizschah
This document contains multiple choice questions and solved numerical problems related to the topic of motion and rest from the ninth grade physics curriculum in India. It covers concepts like distance, displacement, velocity, uniform and non-uniform motion, acceleration, and graphs related to distance-time and velocity-time. Several word problems involve calculating speed, acceleration, time, or distance given certain variables like initial/final velocities or acceleration. The document aims to help students practice and understand concepts of motion through these sample questions.
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship PGPSE is for those who want to transform the world. It is different from MBA, BBA, CFA, CA,CS,ICWA and other traditional programmes. It is based on self certification and based on self learning and guidance by mentors. It is for those who want to be entrepreneurs and social changers. Let us work together. Our basic idea is that KNOWLEDGE IS FREE & AND SHARE IT WITH THE WORLD
The document provides examples of speed and boat-related questions that are often asked in aptitude tests. It includes 6 questions with solutions related to the speed of boats traveling upstream or downstream in rivers at various speeds, or the speed of the river current. It also includes additional practice questions related to the speed of trains, walking rates, and geometric concepts like area and perimeter calculations.
Time & Distance is a broader topic in aptitude. Here the moving object could be train or person or boats etc.,
Students could find useful techniques to solve time & distance aptitude problems.
The document provides information and formulas related to speed, time, and distance problems involving trains. It includes conversions between km/hr and m/s, formulas for calculating time taken by trains of different lengths to pass objects, and examples of word problems involving trains passing stations, bridges, poles, and each other while moving in the same or opposite directions at various speeds.
This document provides information about time, distance, and speed including key concepts, units of measurement, conversion formulas between units, and formulas to calculate distance, time, and speed given two of the three variables. It includes examples of using the formulas to solve word problems involving trains passing poles and travel between cities. The document emphasizes that speed, time, and distance are important concepts in navigation, athletics, and transportation scheduling.
This document provides formulas and examples of problems related to train speed, time, and distance. It includes formulas to convert between km/hr and m/s, and formulas to calculate the time taken for trains of given lengths to pass each other or other objects when moving in the same or opposite directions at given speeds. It also provides the answers and explanations for 23 sample problems applying these formulas to calculate speeds, times, distances, or lengths based on the information given.
The document provides examples of time and distance word problems and their step-by-step solutions. It begins by introducing basic concepts of time, distance and speed, such as the relationship between speed, time and distance defined by the equation Speed = Distance/Time. It then works through 6 sample problems, providing the question, answer and detailed explanation of how to arrive at each answer using the fundamental speed, time and distance formulas and logical reasoning. The problems involve calculating speeds, distances traveled, times taken and relationships between multiple moving objects.
The document provides information and formulas related to time, distance, and speed. It defines speed as the ratio of distance to time. It provides the units used to measure distance, time, and speed depending on whether distance is measured in kilometers or meters. Several formulas are given for calculating speed, distance, and time taken in various scenarios involving objects traveling at different speeds. Sample problems with solutions are also provided to demonstrate the application of the formulas.
The document contains solutions to physics problems related to motion with constant acceleration. It includes calculations of acceleration, velocity, distance, displacement, average speed, and more using kinematic equations. Key details provided include initial and final velocities and accelerations, as well as time intervals. Formulas used include: acceleration=(final velocity - initial velocity)/time, distance/displacement=initial velocity x time + 1/2 x acceleration x time^2, and average speed=total distance/total time.
1. This document provides important formulas and examples related to time and distance problems. It includes formulas for speed, distance, and time as well as examples of speed, average speed, and time calculations for distances covered at different speeds.
2. Several solved examples demonstrate using the formulas and concepts to calculate speeds, times, distances, and average speeds for scenarios like traveling different distances at different speeds, catching up to another traveler, and missing a train by certain times depending on walking speed.
3. The document serves as a reference for the key formulas and concepts needed to solve time and distance word problems.
1. The document provides examples and formulas for calculating time, distance, and speed. It includes the formulas for calculating speed, time, and distance when two quantities are given.
2. Sample problems are given involving calculating speeds and distances traveled by people and vehicles using the time-distance formulas. Distances, speeds, and times taken to cover distances are calculated in the examples.
3. Thirteen example problems are shown with step-by-step solutions for calculating speeds, times, and distances from trains, cyclists, thieves, and more using the time-distance formulas.
The document provides examples of reasoning questions often asked in aptitude tests, with explanations and solutions. It includes 20 questions related to speed, distance, and time calculations involving trains, platforms, and people walking or running at different speeds. The purpose is to help students prepare for exams by practicing these types of reasoning questions.
The document provides examples of reasoning questions often asked in aptitude tests, with explanations and solutions. It includes 20 questions related to speed, distance, and time calculations involving trains, platforms, and people walking or running at different speeds. The purpose is to help students prepare for exams by practicing these types of reasoning questions.
The document discusses different types of motion and speed. It defines motion as a change in an object's position over time. There are three main types of speed discussed: regular speed which is constant, irregular speed which varies, and relative speed which depends on the observer. Equations for calculating speed, average speed, and acceleration are provided along with examples of using the equations to solve problems. Graphs are used to represent motion and speed visually.
The document provides information on the relationships between distance, time, and speed. It includes formulas for converting between kilometers per hour and meters per second, calculating average speed when distances are covered at different speeds, and calculating relative speeds of objects like trains moving in the same or opposite directions. It then provides a quiz with 10 multiple choice questions related to using these formulas and concepts to solve word problems involving time, distance, and speed.
1. The document provides teaching notes on speed, time, and distance concepts including definitions of key terms like speed, average speed, and relative speed.
2. It includes examples of speed, time, and distance word problems and step-by-step solutions showing calculations and conversions between units.
3. Sample problems cover topics like calculating time to meeting points, average speeds, relative speeds of objects traveling in the same or opposite directions, and speed of boats traveling upstream or downstream.
1. The document provides teaching notes on speed, time, and distance concepts including definitions of key terms like speed, average speed, and relative speed.
2. It includes examples of speed, time, and distance word problems and step-by-step solutions showing calculations and conversions between units.
3. Sample problems cover topics like calculating time to meeting points, average speeds, relative speeds of objects traveling in the same or opposite directions, and speed of boats traveling upstream or downstream.
This document discusses speed, time, and distance formulas. It explains that these formulas relate time, distance, and speed, and have practical applications for calculating travel times, distances, and speeds. The key formulas presented are:
Distance = Rate x Time
Rate = Distance / Time
Time = Distance / Rate
Steps for solving problems using these formulas are outlined, including translating the question into mathematical terms, putting values into consistent units, writing the appropriate equation, and solving it. Several example problems are worked through to demonstrate applying the formulas to calculate distances, rates, and times for scenarios involving traveling cars, trains, runners, and planes.
The document defines key terms related to linear motion such as scalar and vector quantities, linear and non-uniform motion, distance, displacement, speed, velocity, acceleration, and deceleration. It provides formulas for calculating these quantities and illustrates them with examples. It also describes how to apply the concepts of linear motion to solve related problems using the appropriate formulas and how to interpret velocity-time graphs to determine velocity, acceleration, and displacement.
Current Affairs Notes for December MonthSOURAV DAS
🌟 Stay updated with the latest Current Affairs for December Month! 📅 Dr. Sourav Sir's Classes presents comprehensive Current Affairs Notes curated by experts to keep you ahead in your preparation. 📝 Get insights into crucial events, developments, and news from around the globe in a student-friendly format.
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Competitive Mathematics Model Question Paper || Sourav Sir's ClassesSOURAV DAS
Competitive Mathematics
Competitive Maths Preparation
Competitive Mathematics Model Questions By Sourav Sir's Classes
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CAT (Common Admission Test) 2018 Slot 2 (Afternoon Session) Question Paper Wi...SOURAV DAS
CAT 2018 Slot 2 Question Paper With Solution
Common Admission Test
CAT 2018 Full Question Paper With Complete Answer Key & Solution
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CAT 2018 Slot 1 (Morning Session) Question Paper With Solution || Sourav Sir'...SOURAV DAS
The full form of CAT is the Common Admission Test. CAT is a computer-based examination of admission to a graduate management programme. The test includes three sections. QA (Quantitative Ability).
Contact Us for any query related to the exam.
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Chapter wise All Notes of First year Basic Civil Engineering.pptxDenish Jangid
Chapter wise All Notes of First year Basic Civil Engineering
Syllabus
Chapter-1
Introduction to objective, scope and outcome the subject
Chapter 2
Introduction: Scope and Specialization of Civil Engineering, Role of civil Engineer in Society, Impact of infrastructural development on economy of country.
Chapter 3
Surveying: Object Principles & Types of Surveying; Site Plans, Plans & Maps; Scales & Unit of different Measurements.
Linear Measurements: Instruments used. Linear Measurement by Tape, Ranging out Survey Lines and overcoming Obstructions; Measurements on sloping ground; Tape corrections, conventional symbols. Angular Measurements: Instruments used; Introduction to Compass Surveying, Bearings and Longitude & Latitude of a Line, Introduction to total station.
Levelling: Instrument used Object of levelling, Methods of levelling in brief, and Contour maps.
Chapter 4
Buildings: Selection of site for Buildings, Layout of Building Plan, Types of buildings, Plinth area, carpet area, floor space index, Introduction to building byelaws, concept of sun light & ventilation. Components of Buildings & their functions, Basic concept of R.C.C., Introduction to types of foundation
Chapter 5
Transportation: Introduction to Transportation Engineering; Traffic and Road Safety: Types and Characteristics of Various Modes of Transportation; Various Road Traffic Signs, Causes of Accidents and Road Safety Measures.
Chapter 6
Environmental Engineering: Environmental Pollution, Environmental Acts and Regulations, Functional Concepts of Ecology, Basics of Species, Biodiversity, Ecosystem, Hydrological Cycle; Chemical Cycles: Carbon, Nitrogen & Phosphorus; Energy Flow in Ecosystems.
Water Pollution: Water Quality standards, Introduction to Treatment & Disposal of Waste Water. Reuse and Saving of Water, Rain Water Harvesting. Solid Waste Management: Classification of Solid Waste, Collection, Transportation and Disposal of Solid. Recycling of Solid Waste: Energy Recovery, Sanitary Landfill, On-Site Sanitation. Air & Noise Pollution: Primary and Secondary air pollutants, Harmful effects of Air Pollution, Control of Air Pollution. . Noise Pollution Harmful Effects of noise pollution, control of noise pollution, Global warming & Climate Change, Ozone depletion, Greenhouse effect
Text Books:
1. Palancharmy, Basic Civil Engineering, McGraw Hill publishers.
2. Satheesh Gopi, Basic Civil Engineering, Pearson Publishers.
3. Ketki Rangwala Dalal, Essentials of Civil Engineering, Charotar Publishing House.
4. BCP, Surveying volume 1
How to Setup Warehouse & Location in Odoo 17 InventoryCeline George
In this slide, we'll explore how to set up warehouses and locations in Odoo 17 Inventory. This will help us manage our stock effectively, track inventory levels, and streamline warehouse operations.
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Philippine Edukasyong Pantahanan at Pangkabuhayan (EPP) CurriculumMJDuyan
(𝐓𝐋𝐄 𝟏𝟎𝟎) (𝐋𝐞𝐬𝐬𝐨𝐧 𝟏)-𝐏𝐫𝐞𝐥𝐢𝐦𝐬
𝐃𝐢𝐬𝐜𝐮𝐬𝐬 𝐭𝐡𝐞 𝐄𝐏𝐏 𝐂𝐮𝐫𝐫𝐢𝐜𝐮𝐥𝐮𝐦 𝐢𝐧 𝐭𝐡𝐞 𝐏𝐡𝐢𝐥𝐢𝐩𝐩𝐢𝐧𝐞𝐬:
- Understand the goals and objectives of the Edukasyong Pantahanan at Pangkabuhayan (EPP) curriculum, recognizing its importance in fostering practical life skills and values among students. Students will also be able to identify the key components and subjects covered, such as agriculture, home economics, industrial arts, and information and communication technology.
𝐄𝐱𝐩𝐥𝐚𝐢𝐧 𝐭𝐡𝐞 𝐍𝐚𝐭𝐮𝐫𝐞 𝐚𝐧𝐝 𝐒𝐜𝐨𝐩𝐞 𝐨𝐟 𝐚𝐧 𝐄𝐧𝐭𝐫𝐞𝐩𝐫𝐞𝐧𝐞𝐮𝐫:
-Define entrepreneurship, distinguishing it from general business activities by emphasizing its focus on innovation, risk-taking, and value creation. Students will describe the characteristics and traits of successful entrepreneurs, including their roles and responsibilities, and discuss the broader economic and social impacts of entrepreneurial activities on both local and global scales.
Leveraging Generative AI to Drive Nonprofit InnovationTechSoup
In this webinar, participants learned how to utilize Generative AI to streamline operations and elevate member engagement. Amazon Web Service experts provided a customer specific use cases and dived into low/no-code tools that are quick and easy to deploy through Amazon Web Service (AWS.)
Walmart Business+ and Spark Good for Nonprofits.pdfTechSoup
"Learn about all the ways Walmart supports nonprofit organizations.
You will hear from Liz Willett, the Head of Nonprofits, and hear about what Walmart is doing to help nonprofits, including Walmart Business and Spark Good. Walmart Business+ is a new offer for nonprofits that offers discounts and also streamlines nonprofits order and expense tracking, saving time and money.
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Special TechSoup offer for a free 180 days membership, and up to $150 in discounts on eligible orders.
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Answers about how you can do more with Walmart!"
Main Java[All of the Base Concepts}.docxadhitya5119
This is part 1 of my Java Learning Journey. This Contains Custom methods, classes, constructors, packages, multithreading , try- catch block, finally block and more.
it describes the bony anatomy including the femoral head , acetabulum, labrum . also discusses the capsule , ligaments . muscle that act on the hip joint and the range of motion are outlined. factors affecting hip joint stability and weight transmission through the joint are summarized.
This document provides an overview of wound healing, its functions, stages, mechanisms, factors affecting it, and complications.
A wound is a break in the integrity of the skin or tissues, which may be associated with disruption of the structure and function.
Healing is the body’s response to injury in an attempt to restore normal structure and functions.
Healing can occur in two ways: Regeneration and Repair
There are 4 phases of wound healing: hemostasis, inflammation, proliferation, and remodeling. This document also describes the mechanism of wound healing. Factors that affect healing include infection, uncontrolled diabetes, poor nutrition, age, anemia, the presence of foreign bodies, etc.
Complications of wound healing like infection, hyperpigmentation of scar, contractures, and keloid formation.
1. SOURAV SIR’S CLASSES 98367 93076
1
TIME, SPEED & DISTANCE
Important Formulae:
i) Speed=Distance/Time
ii) Time=Distance/speed
iii) Distance = speed*time
iv) 1kmhr=5/18ms
v) 1ms=18/5Kmhr
vi) If the ratio of the speed of A and B is a:b,then the ratio of the time taken by them to cover
the same distance is 1/a:1/b or b:a
vii) Suppose a man covers a distance at x kmph and an equal distance at y kmph,
then the AVERAGE SPEED during the whole journey is (2xy/x+y) kmph
Out of time, speed and distance we can compute any one of the quantities when we happen to
know the other two. For example, suppose we drive for 2 hours at 30 miles per hour, for a
total of 60 miles.
If we know the time and the speed, we can find the distance:
2 hour * 30 miles/hour=60 miles
If we know the time and the distance, we can find the speed:
60 miles2 hours=30miles/hour
Distance is directly proportional to Velocity when time is constant:
Example: A car travels at 30km/hr for the first 2 hrs& then 40km/hr for the next 2hrs. Find
the ratio of distance travelled
S1S2=V1V2=34
Example: Two cars leave simultaneously from points A & B (1.km apart) & they meet at a
point 40 km from A. What is VaVb?
Time is constant so V1V2=S1S2=4060=46
Example: A train meets with an accident and moves at (34)th its original speed. Due to this,
it is 20 min late. Find the original time for the journey beyond the point of accident?
BY
SOURAV DAS
2. SOURAV SIR’S CLASSES 98367 93076
2
Method1: Think about 2 diff. situations, 1st with accident and another w/o accident. As
distance in both the cases is constant
So V1V2=T2T1
=>V1[34*V1]=T1+20T1
=> 43=T1+20T1 =>T1=60
Method 2: Velocity decreases by 25% (34 of original speed => decrement by 14) so time
will increase by 33.3% (43 of original time => increment by 13)
now, 33.3%=20 min =>1.%=60 min
Relative Speed:
Case1: Two bodies are moving in opposite directions at speed V1 & V2 respectively. The
relative speed is defined as Vr=V1+V2
Case2: Two bodies are moving in same directions at speed V1 & V2 respectively. The
relative speed is defined as Vr=|V1–V2|
Train Problems:
The basic equation in train problem is the same Speed=DistanceTime
The following things need to be kept in mind while solving the train related problems.
When the train is crossing a moving object, the speed has to be taken as the relative
speed of the train with respect to the object.
The distance to be covered when crossing an object, whenever trains crosses an object
will be equal to: Length of the train + Length of the object
Boats & Streams:
Let U= Velocity of the boat in still water
V=Velocity of the stream.
While moving in upstream, distance covered, S=(U−V)T
In case of downstream, distance covered ,S=(U+V)T
Clock:
For clock problems consider the clock as a circular track of 60km.
Min. hand moves at the speed of 60km/hr (think min. hand as a point on the track) and hour
hand moves at 5km/hr and second hand at the speed of 36. km/hr.
Relative speed between HOUR hand and MINUTE hand = 55
3. SOURAV SIR’S CLASSES 98367 93076
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1. A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
A. 3.6 B. 7.2
C. 8.4 D. 10
Answer & Explanation
Answer: Option B
Explanation:
Speed =
600
m/sec.5 x 60
= 2 m/sec.
Converting m/sec to km/hr
= 2 x
18
km/hr
5
= 7.2 km/hr.
2. An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the
same distance in 1 hours, it must travel at a speed of:
A. 300 kmph B. 360 kmph
C. 600 kmph D. 720 kmph
Answer & Explanation
Answer: Option D
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
Required speed = 1200 x
3
km/hr
= 720 km/hr.
5
4. SOURAV SIR’S CLASSES 98367 93076
4
3. If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more.
The actual distance travelled by him is:
A. 50 km B. 56 km
C. 70 km D. 80 km
Answer: Option A
Explanation:
Let the actual distance travelled be x km.
Then,
x
=
x + 20
10 14
14x = 10x + 200
4x = 200
x = 50 km.
4. A train can travel 50% faster than a car. Both start from point A at the same time and
reach point B 75 kms away from A at the same time. On the way, however, the train lost
about 12.5 minutes while stopping at the stations. The speed of the car is:
A. 100 kmph B. 110 kmph
C. 120 kmph D. 130 kmph
Answer & Explanation
Answer: Option C
Explanation:
Let speed of the car be x kmph.
Then, speed of the train =
150
x =
3
x
kmph.100 2
75
-
75
=
125
x (3/2)x 10 x 60
75
-
50
=
5
x x 24
x = 25 x24 = 120 kmph.
5. SOURAV SIR’S CLASSES 98367 93076
5
5. Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45
kmph. For how many minutes does the bus stop per hour?
A. 9 B. 10
C. 12 D. 20
Answer & Explanation
Answer: Option B
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km =
9
x 60
min
= 10 min.
6. In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed
for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The
duration of the flight is:
A. 1 hour B. 2 hours
C. 3 hours D. 4 hours
Answer & Explanation
Answer: Option A
Explanation:
Let the duration of the flight be x hours.
Then,
600
-
600
= 200
x x + (1/2)
600
-
1200
= 200
x 2x + 1
x(2x + 1) = 3
2x2
+ x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
6. SOURAV SIR’S CLASSES 98367 93076
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7. A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21
km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
A. 220 km B. 224 km
C. 230 km D. 234 km
Answer & Explanation
Answer: Option B
Explanation:
(1/2)x
+
(1/2)x
= 10
21 24
x
+
x
= 20
21 24
15x = 168 x 20
x =
168 x 20
= 224 km.
15
8. The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4
hours, then the speed of the first train is:
A. 70 km/hr B. 75 km/hr
C. 84 km/hr D. 87.5 km/hr
Answer & Explanation
Answer: Option D
Explanation:
Let the speed of two trains be 7x and 8x km/hr.
Then, 8x =
400
= 100
4
x =
100
= 12.5
8
Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
7. SOURAV SIR’S CLASSES 98367 93076
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9. A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The
average speed for the first 320 km of the tour is:
A. 35.55 km/hr B. 36 km/hr
C. 71.11 km/hr D. 71 km/hr
Answer & Explanation
Answer: Option C
Explanation:
Total time taken =
160
+
160
hrs.
=
9
hrs.
64 80 2
Average speed = 320 x
2
km/hr
= 71.11 km/hr.
9
10.
A car travelling with of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the
actual speed of the car.
A. 17
6
km/hr
7
B. 25 km/hr
C. 30 km/hr D. 35 km/hr
Answer & Explanation
Answer: Option D
Explanation:
Time taken = 1 hr 40 min 48 sec = 1 hr 40
4
min = 1
51
hrs =
126
hrs.
5 75 75
Let the actual speed be x km/hr.
Then,
5
x x
126
= 42
7 75
x =
42 x 7 x 75
= 35 km/hr.
5 x 126
11. In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay
doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
8. SOURAV SIR’S CLASSES 98367 93076
8
A. 5 kmph B. 6 kmph
C. 6.25 kmph D. 7.5 kmph
Answer & Explanation
Answer: Option A
Explanation:
Let Abhay's speed be x km/hr.
Then,
30
-
30
= 3
x 2x
6x = 30
x = 5 km/hr.
12. Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels
at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must
he travel to reach A at 1 P.M.?
A. 8 kmph B. 11 kmph
C. 12 kmph D. 14 kmph
Answer & Explanation
Answer: Option C
Explanation:
Let the distance travelled by x km.
Then,
x
-
x
= 2
10 15
3x - 2x = 60
x = 60 km.
Time taken to travel 60 km at 10 km/hr =
60
hrs
= 6 hrs.
10
9. SOURAV SIR’S CLASSES 98367 93076
9
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
Required speed =
60
kmph.
= 12 kmph.
5
13. It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It
takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the
speed of the train to that of the cars is:
A. 2 : 3 B. 3 : 2
C. 3 : 4 D. 4 : 3
Answer & Explanation
Answer: Option C
Explanation:
Let the speed of the train be x km/hr and that of the car be y km/hr.
Then,
120
+
480
= 8
1
+
4
=
1
....(i)
x y x y 15
And,
200
+
400
=
25 1
+
2
=
1
....(ii)
x y 3 x y 24
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4.
14. A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr
and partly on bicycle @ 9 km/hr. The distance travelled on foot is:
A. 14 km B. 15 km
C. 16 km D. 17 km
Answer & Explanation
Answer: Option C
Explanation:
Let the distance travelled on foot be x km.
10. SOURAV SIR’S CLASSES 98367 93076
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Then, distance travelled on bicycle = (61 -x) km.
So,
x
+
(61 -x)
= 9
4 9
9x + 4(61 -x) = 9 x 36
5x = 80
x = 16 km.
15. A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would
have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40
minutes more. The distance (in km) is:
A. 35 B. 36
2
3
C. 37
1
2
D. 40
Answer & Explanation
Answer: Option D
Explanation:
Let distance = x km and usual rate = y kmph.
Then,
x
-
x
=
40
2y(y + 3) = 9x ....(i)
y y + 3 60
And,
x
-
x
=
40
y(y - 2) = 3x ....(ii)
y -2 y 60
On dividing (i) by (ii), we get: x = 40.
16. A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6
Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
A.) 3 1/5 Km B.) 2 1/5 Km
C.) 4 1/5 Km D.) 5 1/5 Km
11. SOURAV SIR’S CLASSES 98367 93076
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Show Answer
Answer: Option 'A'
Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 16/6
= 24/2 * 16/60
= 8 * 2/5
= 16/5 = 3 1/5 Km
17. A car takes 6 hours to cover a distance of 540 Km. how much should the speed in
Kmph be maintained to cover the same direction in 3/2th of the previous time?
A.) 6o Kmph B.) 62 Kmph
C.) 75 Kmph D.) 77 Kmph
Show Answer
Answer: Option 'A'
Time = 6
Distence = 540
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph
18. Avinash covers a distance of 8km in 50 minutes. If he covers 3km distance in 2/5th
of time then, What speed should he maintain to cover the remaining distance in the
remaining time?
A.) 13 Kmph B.) 14 Kmph
12. SOURAV SIR’S CLASSES 98367 93076
12
C.) 15 Kmph D.) 11 Kmph
Show Answer
Answer: Option 'C'
Total distance = 8 Km
Total time = 50 Km
Time taken to cover the distence of 3 Km = 50*2/5 = 20 min = 1/3 hours
Remaining distance = 8 - 3 = 5 Km
Required speed = 5/1/3 = 15 Kmph
19. A man covers a distance of 180 Km at 72 Kmph and next 190km at 88 Kmph. what
is his average speed For his whole journey of 370 Km?
A.) 79.2 Kmph B.) 79.3 Kmph
C.) 77.25 Kmph D.) 78.5 Kmph
Show Answer
Answer: Option 'A'
Formula = 2*F.S*S.P/F.S+S.P
= 2*72*88/88+72
=79.2 Kmph
20. An aeroplane covers a certain distance of 420 Kmph in 6 hours. to cover the same
distance in 4 2/3 hours, it Must travel at a speed of
A.) 580 Kmph B.) 550 Kmph
13. SOURAV SIR’S CLASSES 98367 93076
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C.) 540 Kmph D.) 530 Kmph
Show Answer
Answer: Option 'C'
Speed of aeroplane = 420 Kmph
Distance travelled in 6 hours
= 420 * 6 = 2520 Km
Speed of aeroplane to acver 2520 Km in 14/3
= 2520*3/14 = 540 Km
21. If a man walks 24 Km at 8 Kmph, he will be late by 25min. if he walks 12 Kmph,
how early the fixed time Will he reach?
A.) 30 minutes B.) 25 minutes
C.) 40 minutes D.) 35 minutes
Show Answer
Answer: Option 'D'
Time taken to cover 24 Km at the speed of 8 Kmph = 24/8 = 3 hours
Thus, right time was 2 hours 35 mintes
Now, time taken to cover 20 Km at the speed as 12 Kmph = 2 hours
Required time = 2 hours 35 minutes - 2 hours
= 35 minutes
14. SOURAV SIR’S CLASSES 98367 93076
14
Aptitude Questions for Time & Distance Problems
Aptitude Questions With .wers for Time & Distance Problems
22) A train covers a distance in 50 min ,if it runs at a speed
of 48kmph on an average.The speed at which the train must run
to reduce the time of journey to 40min will be.
Solution::
Time=50/60 hr=5/6hr
Speed=48mph
distance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph
23) Vikas can cover a distance in 1hr 24min by covering 2/3 of
the distance at 4 kmph and the rest at 5kmph.the total
distance is?
Solution::
Let total distance be S
total time=1hr24min
A to T :: speed=4kmph
diistance=2/3S
T to S :: speed=5km
distance=1-2/3S=1/3S
21/15 hr=2/3 S/4 + 1/3s /5
84=14/3S*3
S=84*3/14*3
= 6km
24) walking at ¾ of his usual speed ,a man is late by 2 ½ hr.
the usual time is.
Solution::
Usual speed = S
Usual time = T
Distance = D
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New Speed is ¾ S
New time is 4/3 T
4/3 T – T = 5/2
T=15/2 = 7 ½
25) A man covers a distance on scooter .had he moved 3kmph
faster he would have taken 40 min less. If he had moved
2kmph slower he would have taken 40min more.the distance is.
Solution::
Let distance = x m
Usual rate = y kmph
x/y – x/y+3 = 40/60 hr
2y(y+3) = 9x ————–1
x/y-2 – x/y = 40/60 hr y(y-2) = 3x —————–2
divide 1 & 2 equations
by solving we get x = 40
26) Excludingstoppages,the speed of the bus is 54kmph and
including stoppages,it is 45kmph.for how many min does the bus
stop per hr.
Solution::
Due to stoppages,it covers 9km less.
time taken to cover 9 km is [9/54 *60] min = 10min
27) Two boys starting from the same place walk at a rate of
5kmph and 5.5kmph respectively.wht time will they take to be
8.5km apart, if they walk in the same direction
Solution::
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The relative speed of the boys = 5.5kmph – 5kmph = 0.5 kmph
Distance between them is 8.5 km
Time= 8.5km / 0.5 kmph = 17 hrs
28) 2 trains starting at the same time from 2 stations 2.km
apart and going in opposite direction cross each other ata
distance of 110km from one of the stations.what is the ratio of
their speeds.
Solution::
In same time ,they cover 110km & 90 km respectively
so ratio of their speed =110:90 = 11:9
29) Two trains start from A & B and travel towards each other at
speed of 50kmph and 60kmph resp. At the time of the meeting the
second train has traveled 120km more than the first.the distance
between them.
Solution::
Let the distance traveled by the first train be x km
then distance covered by the second train is x + 120km
x/50 = x+120 / 60
x= 6.
so the distance between A & B is x + x + 120 = 1320 km
30) A thief steals a ca r at 2.30pm and drives it at 60kmph.the
theft is discovered at 3pm and the owner sets off in another car
at 75kmph when will he overtake the thief
Solution::
Let the thief is overtaken x hrs after 2.30pm
distance covered by the thief in x hrs = distance covered by
the owner in x-1/2 hr
60x = 75 ( x- ½)
x= 5/2 hr
thief is overtaken at 2.30 pm + 2 ½ hr = 5 pm
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31) In covering distance,the speed of A & B are in the ratio
of 3:4.A takes 30min more than B to reach the destion.The time
taken by A to reach the destinstion is.
Solution::
Ratio of speed = 3:4
Ratio of time = 4:3
let A takes 4x hrs,B takes 3x hrs
then 4x-3x = 30/60 hr
x = ½ hr
Time taken by A to reach the destination is 4x = 4 * ½ = 2 hr
32) In a one km race A gives B a start of 100m and in a one km race B gives a start of 80 m
to C. In a 1 km race who will win and by how much distance from the worst performer
between two losers?
Solution::
Ratio of speeds of A:B = 1000:900 = 100:90
Ratio of speeds of B:C = 1000:920 = 100:92
Therefore, when A moves 1000m , B moves 900 m and when B moves 900m, C moves
828m
Thus,
Since , C moves 8 % less than B in the same time . Thus, C is the worst performer and A will
win by him by 172 m
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PART 2
33. The speed of a car increases by 2 kms after every one hour. If the distance travelling in
the first one hour was 35 kms. what was the total distance travelled in 12 hours?
A) 456 kms B) 482 kms
C) 552 kms D) 556 kms
Explanation:
Total distance travelled in 12 hours =(35+37+39+.....upto 12 terms)
This is an A.P with first term, a=35, number of terms,
n= 12,d=2.
Required distance = 12/2[2 x 35+{12-1) x 2]
=6(70+23)
= 552 kms.
34. A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the
bridge (in metres) is
A) 600 B) 750
C) 1000 D) 1250
Answer &ExplanationAnswer: D) 1250
Explanation:
speed = (5x5/18)m/sec
= 25/18 m/sec.
Distance covered in 15 minutes = (25/18 x 15 x 60)m
= 1250 m.
35. A thief is noticed by a policeman from a distance of 200 m. The thief starts running and
the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km
per hour respectively. What is the distance between them after 6 minutes?
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A) 100 m B) 150 m
C) 190 m D) 200 m
Answer &ExplanationAnswer: A) 100 m
Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes = km = km = 100 m
Distance between the thief and policeman = (200 – 100) m = 100 m.
36. Two horses start trotting towards each other, one from A to B and another from B to A.
They cross each other after one hour and the first horse reaches B, 5/6 hour before the
second horse reaches A. If the distance between A and B is 50 km. what is the speed of the
slower horse?
A) 30 km/h B) 15 km/h
C) 25 km/h D) 20 km/h
Answer &ExplanationAnswer: D) 20 km/h
Explanation:
If the speed of the faster horse be and that of slower horse be then
and
Now, you can go through options.
The speed of slower horse is 20km/h
Since, 20+30=50
and
37. The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and
travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at
75 Km/hr. At what time do they meet?
A) 10 a.m B) 10.30 a.m
C) 11 a.m D) 11.30 a.m
Answer &ExplanationAnswer: C) 11 a.m
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Explanation:
Suppose they meet x hrs after 8 a.m
then,
[Distance moved by first in x hrs] + [Distance moved by second in (x-1) hrs] = 330.
Therefore, 60x + 75(x-1) = 330.
=> x=3.
So,they meet at (8+3) i.e, 11a.m.
38. A man takes 6 hours 15 minutes in walking a distance and riding back to the starting
place. He could walk both ways in 7 hours 45 minutes. The time taken by him to ride both
ways, is
A) 4 hours B) 4 hours 30 minutes
C) 4 hours 45 minutes D) 5 hours
Answer &ExplanationAnswer: C) 4 hours 45 minutes
Explanation:
Time taken in walking both ways = 7 hours 45 minutes --------(i)
Time taken in walking one way and riding back= 6 hours 15 minutes-------(ii)
By equation (ii)*2 -(i), we have
Time taken to man ride both ways, = 12 hours 30 minutes - 7 hours 45 minutes
39. A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The
average speed for the first 320 km of the tour is
A) 35.55 km/hr B) 36 km/hr
C) 71.11 km/hr D) 71 km/hr
Answer &ExplanationAnswer: C) 71.11 km/hr
Explanation:
Total time taken = (160/64 + 160/8)hrs
= 9/2 hrs.
Average speed = (320 x 2/9) km.hr
= 71.11 km/hr.
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40. A machine puts c caps on bottles in m minutes. How many hours will it take to put caps
on b bottles
A) 60bm/c B) bm/60c
C) bc/60m D) 60b/cm
Answer &ExplanationAnswer: B) bm/60c
Explanation:
Substitute sensible numbers and work out the problem. Then change the numbers back to
letters. For example if the machine puts 6 caps on bottles in 2 minutes, it will put 6 /2 caps on
per minute, or (6 /2) x 60 caps per hour. Putting letters back this is 60c/m.If you divide the
required number of caps (b) by the caps per hour you will get time taken in hours. This gives
bm/60c
41. The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4
hours, then the speed of the first train is ?
A) 83.5 km/hr B) 84.5 km/hr
C) 86.5 km/hr D) 87.5 km/hr
Answer &ExplanationAnswer: D) 87.5 km/hr
Explanation:
Let the speeds of two trains be 7X and 8X km/hr.
8x =
=> x= 12.5 km/hrX=4004=>X=12.5Km/hr
So speed of first train is 12.5*7 = 87.5 km/hr
42. The distance from town A to town B is five miles. C is six miles from B. Which of the
following could be the maximum distance from A to C?
A) 11 B) 8
C) 2 D) 4
Answer &ExplanationAnswer: A) 11
Explanation:
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Do not assume that AB and C are on a straight line. Make a diagram with A and B marked 5
miles apart. Draw a circle centered on B, with radius 6. C could be anywhere on this circle.
The minimum distance will be 1, and maximum 11
43. A boat sails 15 km of a river towards upstream in 5 hours. How long will it take to cover
the same distance downstream, if the speed of current is one-fourth the speed of the boat in
still water:
A) 1.8h B) 3h
C) 4h D) 5h
Answer &ExplanationAnswer: B) 3h
Explanation:
Upstream speed = B-S
Downstream speed = B+s
B-S = 15/5 = 3 km/h
Again B= 4S
Therefore B-S = 3= 3S
=> S = 1 and B= 4 km/h
Therefore B+S = 5km/h
Therefore, Time during downstream = 15/5 = 3h
44. A person crosses a 600 m long street in 5 minutes, What is his speed in km per hour?
A) 3.6 B) 7.2
C) 8.4 D) 10
Answer &ExplanationAnswer: B) 7.2
45. Two boys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively.
What time will they take to be 8.5km apart, if they walk in the same direction?
A) 15 hours B) 16 hours
C) 17 hours D) 18 hours
Answer &ExplanationAnswer: C) 17 hours
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Explanation:
In this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmph
Distance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrs
46. The distance of the college and home of Rajeev is 80km. One day he was late by 1 hour
than the normal time to leave for the college, so he increased his speed by 4km/h and thus he
reached to college at the normal time. What is the changed (or increased) speed of Rajeev?
A) 28 km/h B) 30 km/h
C) 40 km/h D) 20 km/h
Answer &ExplanationAnswer: D) 20 km/h
Explanation:
Let the normal speed be x km/h, then
x = 16 km/h
(x + 4) = 20 km/h
Therefore increased speed = 20 km/h
47. A train with 120 wagons crosses Arun who is going in the same direction, in 36 seconds.
It travels for half an hour from the time it starts overtaking the Arun ( he is riding on the
horse) before it starts overtaking the Sriram( who is also riding on his horse) coming from the
opposite direction in 24 seconds. In how much time (in seconds) after the train has crossed
the Sriram do the Arun meets to Sriram?
A) 3560 sec B) 3600 sec
C) 3576 sec D) can't be determined
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Answer &ExplanationAnswer: C) 3576 sec
Explanation:
Let the length of the train be L metres and speeds of the train Arun and Sriram be R, A and S
respectively, then
---------- (i)
and ---------(ii)
From eq.(i) and (ii)
3(R - A ) = 2 (R + K)
R = 3A + 2K
In 30 minutes (i.e 1800 seconds), the train covers 1800R (distance) but the Arun also covers
1800 A (distance) in the same time. Therefore distance between Arun and Sriram, when the
train has just crossed Sriram
= 1800 ( R - A) - 24 ( A + K)
Time required =
= (3600 - 24) = 3576 s
48. A train overtakes two girls who are walking in the opposite direction in which the train
is going at the rate of 3 km/h and 6km/h and passes them completely in 36 seconds and 30
seconds respectively. The length of the train is:
A) 120m B) 150m
C) 125m D) None of these
Answer &ExplanationAnswer: B) 150m
Explanation:
Let the length of the train e x meter, and let the speed of train be y km/h, then
and
From eq (1) and (2), we get
y = 12 km/h
x= 150 m
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49. If Deepesh had walked 20 km/h faster he woulh have saved 1 hour in the distance of
60km. what is the usual speed of Deepesh?
A) 100 B) 120
C) 150 D) None of these
Answer &ExplanationAnswer: A) 100
Explanation:
Let the original speed be x km/h, then
original speed = 100km/h
50. Shahrukh starts from Barabanki to Fatehpur , 1 hour after Ajay starts. Shahrukh meets
Kajol 1.5 hours after Shahrukh starts. If the speed of Shahrukh is at least 20km/h faster than
the speed of Kajol.
What is the minimum speed of Shahrukh to overtake Ajay, before he meets Kajol?
A) 30 B) 40
C) 60 D) None of these
Answer &ExplanationAnswer: D) None of these
Explanation:
Let t be the time after Kajol starts, when she meets Ajay, then
This should be less than 2.5 or (x+y)>120
Since y=
This (y>72) is greater than 67.5 km/h and hence Shahrukh will always overtake Ajay before
he meets Kajol.
51. A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average.
Find the speed at which the train must run to reduce the time of journey to 40 minutes.
A) 50 km/hr B) 60 km/hr
C) 65 km/hr D) 70 km/hr
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Answer &ExplanationAnswer: B) 60 km/hr
Explanation:
We are having time and speed given, so first we will calculate the distance. Then we can get
new speed for given time and distance.
Lets solve it.
Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km
New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph
52. A person goes to his office at 1/3rd of the speed at which he returns from his office. If the
average speed during the whole trip is 12 m /h .what is the speed of the person while he was
going to his office?
A) 10 B) 6
C) 8 D) can't be determined
Answer &ExplanationAnswer: C) 8
Explanation:
u = k , v= 3k
53. Akash leaves mumbai at 6 am and reaches Bangalore at 10 am . Prakash leaves
Bangalore at 8 am and reaches Mumbai at 11:30 am. At what time do they cross each other?
A) 10 am B) 8:32 am
C) 8:56 am D) 9:20 am
Answer &ExplanationAnswer: C) 8:56 am
Explanation:
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Time taken by Akash = 4 h
Time taken by Prakash = 3.5 h
For your convenience take the product of times taken by both as a distance.
Then the distance = 14km
Since, Akash covers half of the distance in 2 hours(i.e at 8 am)
Now, the rest half (i.e 7 km) will be coverd by both prakash and akash
Time taken by them = 7/7.5 = 56 min
Thus , they will cross each other at 8 : 56am.
54. A motor boat takes 12 hours to go downstream and it takes 24 hours to return the same
distance. what is the time taken by boat in still water?
A) 15 h B) 16 h
C) 8 h D) 20 h
Answer &ExplanationAnswer: B) 16 h
Explanation:
If t1 and t2 are the upstream and down stream times. Then time taken in still water is given
by
55. Arjun and Bhishma are running on a circular track of length 600m. Speed of Arjun is 30
m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same
direction. When will they meet again for the first time?
Answer
Sol :
Actually Arjun has to make a lead of 600 m, because when Arjun will be 600m ahead of
Bhishma, they will be together again as a person when completes the total length it starts
retracing he same path and thus Arjun and Bhishma can be together again.
Since , they make a difference of 10 m in 1 second. so, he will create 600m difference in 60
second.
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56. Den Bosch and Eastbourne are two famous cities 300 km apart. Maradona starts from
Den Bosch at 8:24 am . An hour later pele starts from Den Bosch. After travelling for 1 hour ,
Pele reaches Nottingham that Maradona had passed 40 minutes earlier. Nottingham falls on
the way from Den Bosch to Eastbourne. If pele and Maradona just reaches Eastbourne at the
same time, what are thespeeds of the Maradona and Pele Respectively?
A) 100 km/h , 125 km/h
B) 60 km/h , 80 km/h
C) 60 km/h , 75 km/h D) 75 km/h , 100 km/h
Answer &ExplanationAnswer: D) 75 km/h , 100 km/h
Explanation:
Let Pele x km in 1 hour. soMaradona takes (2h-40min)=1 h 20 min to cover x km. Let speed
of Maradona and Pele be M and P respectively than
x = and x= P x 1
Again
k= 25
M= 3k = 75 km/h
and P= 4k = 100 km/h
( Through options it is very easy to solve)
57. A man goes down stream with a boat to some destination and returns upstream to his
original place in 5 hours. If the speed of the boat in still water and the strean are 10km/hr and
14km/hr respectively, the distance of the destination from the string place is
A) 16 km B) 18 km
C) 21 km D) 25 km
Answer &ExplanationAnswer: C) 21 km
Explanation:
Let the distance covered be D km.
km
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58. A and B runs around a circular track. A beats B by one round or 10 minutes. In this race,
they had completed 4 rounds. If the race was only of one round, find the A's time over the
course:
A) 8 min B) 7.5 min
C) 12.5 min D) 12 min
Answer &ExplanationAnswer: B) 7.5 min
Explanation:
B runs around the track in 10 min.
i.e , Speed of B = 10 min per round
A beats B by 1 round
Time taken by A to complete 4 rounds
= Time taken by B to complete 3 rounds
= 30 min
A's speed = 30/4 min per round
= 7.5 min per round
Hence, if the race is only of one round A's time over the course = 7 min 30 sec
59. A Person X started at 3 hours earlier at 40km/h from a place P, then another person Y
followed him at 60km/h. Started his journey at 3 O'clock, afternoon. What is the diference in
time when X was30 km ahead of Y and when Y was 30 km ahead of X?
A) 2h B) 3h
C) 3.5h D) 4.25h
Answer &ExplanationAnswer: B) 3h
Explanation:
Time ( when X was 30 km ahead of Y) = (120-30)/20 =4.5h
Time ( when Y was 30 km ahead of X) = (120+30)/20 = 7.5 h
Thus, required difference in time = 3h
60. Two trains starting at the same time from two stations 200 km apart and going in opposite
directions cross each other at a distance of 110 km from one of the stations. What is the ratio
of their speeds?
A) 9 : 20 B) 11 : 9
C) 11 : 20 D) None of these
Answer &ExplanationAnswer: B) 11 : 9
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Explanation:
In the same time, they cover 110 km and 90 km respectively.
Ratio of their speeds = 110 : 90 = 11 : 9
61.In a race of 800m Kaushik gives Piyush a start of 200m and then loses the race by 20
seconds. What is the speed of Piyush and Kaushikrespectively ?If the ratio of respective
speeds be 3:2.
Answer
Let the speed of Kaushik be and speed of Piyush be and let the time taken by
Piyushbe t second then,
t = 20 s
Speed of Piyush =
and Speed of Kaushik =
62. In 12 hours how many times the two hands of clock will be just opposite to each other i.e,
they make a straight line having the difference of 180 degrees between them?
Answer
Sol : = 30 points
For the first time minute- hand and hour-hand will be seperated in
and for every next time they will take minutes more to occur as opposite to each other.
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( since in 60/55 hours they complete one round of clock's daili.e , 60npoints undergoing the
relative motion, we have total 12 hours)
Thus ,
only integral value is admissible.
Thus, total 10+1 =11 times both hands of a clock will be oppositeb to each other.
63. Uday travels half of his journey by train at the speed of 120 km/h and rest half by car at
80 Km/h.What is the average speed?
Answer
Let the total distance be 2D km, then
Total time = Time taken by train + Time taken by car =
Therefore, Average speed=
=
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64. A train of length 250 m crosses a bridge of length 150m in 20 seconds. What is the speed
of train?
Answer
Sol : (length of train+ length of bridge) = speed of train x Time
(250+150) = 20 x Speed
Speed = 400/20= 20 m/s =72 km/h
65. A man can row 9 km/h in still water. It takes him twice as long as to row down. Find the
rate of stream of the river ?
Answer
=
= where
B ---> speed of boat in still water
R---->speed of current
( Bycomponendo and dividendo)