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The ans is 3f. The lowest principal quantum number (n) for s-orbitals is 1, for p-
orbitals is 2, for d-orbitals is 3 and for f-orbitals is 4. Therefore, there can only exist these
orbitals: 1s (but not 1p, 1d, 1f); 2s, 2p (but not 2d, 2f); 3s, 3p, 3d (but not 3f); 4s, 4p, 4d, 4f; 5s,
5p ... and so on.
Solution
The ans is 3f. The lowest principal quantum number (n) for s-orbitals is 1, for p-
orbitals is 2, for d-orbitals is 3 and for f-orbitals is 4. Therefore, there can only exist these
orbitals: 1s (but not 1p, 1d, 1f); 2s, 2p (but not 2d, 2f); 3s, 3p, 3d (but not 3f); 4s, 4p, 4d, 4f; 5s,
5p ... and so on.

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  • 1. The ans is 3f. The lowest principal quantum number (n) for s-orbitals is 1, for p- orbitals is 2, for d-orbitals is 3 and for f-orbitals is 4. Therefore, there can only exist these orbitals: 1s (but not 1p, 1d, 1f); 2s, 2p (but not 2d, 2f); 3s, 3p, 3d (but not 3f); 4s, 4p, 4d, 4f; 5s, 5p ... and so on. Solution The ans is 3f. The lowest principal quantum number (n) for s-orbitals is 1, for p- orbitals is 2, for d-orbitals is 3 and for f-orbitals is 4. Therefore, there can only exist these orbitals: 1s (but not 1p, 1d, 1f); 2s, 2p (but not 2d, 2f); 3s, 3p, 3d (but not 3f); 4s, 4p, 4d, 4f; 5s, 5p ... and so on.