Please go through the slides. It is very interesting way to learn this chapter for 2020-21.If you like this PPT please put a thanks message in my number 9826371828.
Please go through the slides. It is very interesting way to learn this chapter for 2020-21.If you like this PPT please put a thanks message in my number 9826371828.
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
Model Attribute Check Company Auto PropertyCeline George
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
Francesca Gottschalk - How can education support child empowerment.pptxEduSkills OECD
Francesca Gottschalk from the OECD’s Centre for Educational Research and Innovation presents at the Ask an Expert Webinar: How can education support child empowerment?
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...Levi Shapiro
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
Instructions for Submissions thorugh G- Classroom.pptxJheel Barad
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
Instructions for Submissions thorugh G- Classroom.pptx
Tabla de fórmulas integrales.
1. Table of Basic Integrals
Basic Forms
(1) xn
dx =
1
n + 1
xn+1
, n = −1
(2)
1
x
dx = ln |x|
(3) udv = uv − vdu
(4)
1
ax + b
dx =
1
a
ln |ax + b|
Integrals of Rational Functions
(5)
1
(x + a)2
dx = −
1
x + a
(6) (x + a)n
dx =
(x + a)n+1
n + 1
, n = −1
(7) x(x + a)n
dx =
(x + a)n+1
((n + 1)x − a)
(n + 1)(n + 2)
(8)
1
1 + x2
dx = tan−1
x
(9)
1
a2 + x2
dx =
1
a
tan−1 x
a
1
2. (10)
x
a2 + x2
dx =
1
2
ln |a2
+ x2
|
(11)
x2
a2 + x2
dx = x − a tan−1 x
a
(12)
x3
a2 + x2
dx =
1
2
x2
−
1
2
a2
ln |a2
+ x2
|
(13)
1
ax2 + bx + c
dx =
2
√
4ac − b2
tan−1 2ax + b
√
4ac − b2
(14)
1
(x + a)(x + b)
dx =
1
b − a
ln
a + x
b + x
, a = b
(15)
x
(x + a)2
dx =
a
a + x
+ ln |a + x|
(16)
x
ax2 + bx + c
dx =
1
2a
ln |ax2
+bx+c|−
b
a
√
4ac − b2
tan−1 2ax + b
√
4ac − b2
Integrals with Roots
(17)
√
x − a dx =
2
3
(x − a)3/2
(18)
1
√
x ± a
dx = 2
√
x ± a
(19)
1
√
a − x
dx = −2
√
a − x
2
3. (20) x
√
x − a dx =
2a
3
(x − a)3/2
+ 2
5
(x − a)5/2
, or
2
3
x(x − a)3/2
− 4
15
(x − a)5/2
, or
2
15
(2a + 3x)(x − a)3/2
(21)
√
ax + b dx =
2b
3a
+
2x
3
√
ax + b
(22) (ax + b)3/2
dx =
2
5a
(ax + b)5/2
(23)
x
√
x ± a
dx =
2
3
(x 2a)
√
x ± a
(24)
x
a − x
dx = − x(a − x) − a tan−1 x(a − x)
x − a
(25)
x
a + x
dx = x(a + x) − a ln
√
x +
√
x + a
(26) x
√
ax + b dx =
2
15a2
(−2b2
+ abx + 3a2
x2
)
√
ax + b
(27)
x(ax + b) dx =
1
4a3/2
(2ax + b) ax(ax + b) − b2
ln a
√
x + a(ax + b)
(28)
x3(ax + b) dx =
b
12a
−
b2
8a2x
+
x
3
x3(ax + b)+
b3
8a5/2
ln a
√
x + a(ax + b)
(29)
√
x2 ± a2 dx =
1
2
x
√
x2 ± a2 ±
1
2
a2
ln x +
√
x2 ± a2
3
4. (30)
√
a2 − x2 dx =
1
2
x
√
a2 − x2 +
1
2
a2
tan−1 x
√
a2 − x2
(31) x
√
x2 ± a2 dx =
1
3
x2
± a2 3/2
(32)
1
√
x2 ± a2
dx = ln x +
√
x2 ± a2
(33)
1
√
a2 − x2
dx = sin−1 x
a
(34)
x
√
x2 ± a2
dx =
√
x2 ± a2
(35)
x
√
a2 − x2
dx = −
√
a2 − x2
(36)
x2
√
x2 ± a2
dx =
1
2
x
√
x2 ± a2
1
2
a2
ln x +
√
x2 ± a2
(37)
√
ax2 + bx + c dx =
b + 2ax
4a
√
ax2 + bx + c+
4ac − b2
8a3/2
ln 2ax + b + 2 a(ax2 + bx+c)
x
√
ax2 + bx + c dx =
1
48a5/2
2
√
a
√
ax2 + bx + c −3b2
+ 2abx + 8a(c + ax2
)
+3(b3
− 4abc) ln b + 2ax + 2
√
a
√
ax2 + bx + c
(38)
4
5. (39)
1
√
ax2 + bx + c
dx =
1
√
a
ln 2ax + b + 2 a(ax2 + bx + c)
(40)
x
√
ax2 + bx + c
dx =
1
a
√
ax2 + bx + c−
b
2a3/2
ln 2ax + b + 2 a(ax2 + bx + c)
(41)
dx
(a2 + x2)3/2
=
x
a2
√
a2 + x2
Integrals with Logarithms
(42) ln ax dx = x ln ax − x
(43) x ln x dx =
1
2
x2
ln x −
x2
4
(44) x2
ln x dx =
1
3
x3
ln x −
x3
9
(45) xn
ln x dx = xn+1 ln x
n + 1
−
1
(n + 1)2
, n = −1
(46)
ln ax
x
dx =
1
2
(ln ax)2
(47)
ln x
x2
dx = −
1
x
−
ln x
x
5
6. (48) ln(ax + b) dx = x +
b
a
ln(ax + b) − x, a = 0
(49) ln(x2
+ a2
) dx = x ln(x2
+ a2
) + 2a tan−1 x
a
− 2x
(50) ln(x2
− a2
) dx = x ln(x2
− a2
) + a ln
x + a
x − a
− 2x
(51)
ln ax2
+ bx + c dx =
1
a
√
4ac − b2 tan−1 2ax + b
√
4ac − b2
−2x+
b
2a
+ x ln ax2
+ bx + c
(52) x ln(ax + b) dx =
bx
2a
−
1
4
x2
+
1
2
x2
−
b2
a2
ln(ax + b)
(53) x ln a2
− b2
x2
dx = −
1
2
x2
+
1
2
x2
−
a2
b2
ln a2
− b2
x2
(54) (ln x)2
dx = 2x − 2x ln x + x(ln x)2
(55) (ln x)3
dx = −6x + x(ln x)3
− 3x(ln x)2
+ 6x ln x
(56) x(ln x)2
dx =
x2
4
+
1
2
x2
(ln x)2
−
1
2
x2
ln x
(57) x2
(ln x)2
dx =
2x3
27
+
1
3
x3
(ln x)2
−
2
9
x3
ln x
6
7. Integrals with Exponentials
(58) eax
dx =
1
a
eax
(59)
√
xeax
dx =
1
a
√
xeax
+
i
√
π
2a3/2
erf i
√
ax , where erf(x) =
2
√
π
x
0
e−t2
dt
(60) xex
dx = (x − 1)ex
(61) xeax
dx =
x
a
−
1
a2
eax
(62) x2
ex
dx = x2
− 2x + 2 ex
(63) x2
eax
dx =
x2
a
−
2x
a2
+
2
a3
eax
(64) x3
ex
dx = x3
− 3x2
+ 6x − 6 ex
(65) xn
eax
dx =
xn
eax
a
−
n
a
xn−1
eax
dx
(66) xn
eax
dx =
(−1)n
an+1
Γ[1 + n, −ax], where Γ(a, x) =
∞
x
ta−1
e−t
dt
(67) eax2
dx = −
i
√
π
2
√
a
erf ix
√
a
7
8. (68) e−ax2
dx =
√
π
2
√
a
erf x
√
a
(69) xe−ax2
dx = −
1
2a
e−ax2
(70) x2
e−ax2
dx =
1
4
π
a3
erf(x
√
a) −
x
2a
e−ax2
Integrals with Trigonometric Functions
(71) sin ax dx = −
1
a
cos ax
(72) sin2
ax dx =
x
2
−
sin 2ax
4a
(73) sin3
ax dx = −
3 cos ax
4a
+
cos 3ax
12a
(74) sinn
ax dx = −
1
a
cos ax 2F1
1
2
,
1 − n
2
,
3
2
, cos2
ax
(75) cos ax dx =
1
a
sin ax
(76) cos2
ax dx =
x
2
+
sin 2ax
4a
(77) cos3
axdx =
3 sin ax
4a
+
sin 3ax
12a
8
9. (78) cosp
axdx = −
1
a(1 + p)
cos1+p
ax × 2F1
1 + p
2
,
1
2
,
3 + p
2
, cos2
ax
(79) cos x sin x dx =
1
2
sin2
x + c1 = −
1
2
cos2
x + c2 = −
1
4
cos 2x + c3
(80) cos ax sin bx dx =
cos[(a − b)x]
2(a − b)
−
cos[(a + b)x]
2(a + b)
, a = b
(81) sin2
ax cos bx dx = −
sin[(2a − b)x]
4(2a − b)
+
sin bx
2b
−
sin[(2a + b)x]
4(2a + b)
(82) sin2
x cos x dx =
1
3
sin3
x
(83) cos2
ax sin bx dx =
cos[(2a − b)x]
4(2a − b)
−
cos bx
2b
−
cos[(2a + b)x]
4(2a + b)
(84) cos2
ax sin ax dx = −
1
3a
cos3
ax
(85)
sin2
ax cos2
bxdx =
x
4
−
sin 2ax
8a
−
sin[2(a − b)x]
16(a − b)
+
sin 2bx
8b
−
sin[2(a + b)x]
16(a + b)
(86) sin2
ax cos2
ax dx =
x
8
−
sin 4ax
32a
(87) tan ax dx = −
1
a
ln cos ax
9
10. (88) tan2
ax dx = −x +
1
a
tan ax
(89) tann
ax dx =
tann+1
ax
a(1 + n)
× 2F1
n + 1
2
, 1,
n + 3
2
, − tan2
ax
(90) tan3
axdx =
1
a
ln cos ax +
1
2a
sec2
ax
(91) sec x dx = ln | sec x + tan x| = 2 tanh−1
tan
x
2
(92) sec2
ax dx =
1
a
tan ax
(93) sec3
x dx =
1
2
sec x tan x +
1
2
ln | sec x + tan x|
(94) sec x tan x dx = sec x
(95) sec2
x tan x dx =
1
2
sec2
x
(96) secn
x tan x dx =
1
n
secn
x, n = 0
(97) csc x dx = ln tan
x
2
= ln | csc x − cot x| + C
10
11. (98) csc2
ax dx = −
1
a
cot ax
(99) csc3
x dx = −
1
2
cot x csc x +
1
2
ln | csc x − cot x|
(100) cscn
x cot x dx = −
1
n
cscn
x, n = 0
(101) sec x csc x dx = ln | tan x|
Products of Trigonometric Functions and Mono-
mials
(102) x cos x dx = cos x + x sin x
(103) x cos ax dx =
1
a2
cos ax +
x
a
sin ax
(104) x2
cos x dx = 2x cos x + x2
− 2 sin x
(105) x2
cos ax dx =
2x cos ax
a2
+
a2
x2
− 2
a3
sin ax
(106) xn
cos xdx = −
1
2
(i)n+1
[Γ(n + 1, −ix) + (−1)n
Γ(n + 1, ix)]
11
12. (107) xn
cos ax dx =
1
2
(ia)1−n
[(−1)n
Γ(n + 1, −iax) − Γ(n + 1, ixa)]
(108) x sin x dx = −x cos x + sin x
(109) x sin ax dx = −
x cos ax
a
+
sin ax
a2
(110) x2
sin x dx = 2 − x2
cos x + 2x sin x
(111) x2
sin ax dx =
2 − a2
x2
a3
cos ax +
2x sin ax
a2
(112) xn
sin x dx = −
1
2
(i)n
[Γ(n + 1, −ix) − (−1)n
Γ(n + 1, −ix)]
(113) x cos2
x dx =
x2
4
+
1
8
cos 2x +
1
4
x sin 2x
(114) x sin2
x dx =
x2
4
−
1
8
cos 2x −
1
4
x sin 2x
(115) x tan2
x dx = −
x2
2
+ ln cos x + x tan x
(116) x sec2
x dx = ln cos x + x tan x
12
13. Products of Trigonometric Functions and Ex-
ponentials
(117) ex
sin x dx =
1
2
ex
(sin x − cos x)
(118) ebx
sin ax dx =
1
a2 + b2
ebx
(b sin ax − a cos ax)
(119) ex
cos x dx =
1
2
ex
(sin x + cos x)
(120) ebx
cos ax dx =
1
a2 + b2
ebx
(a sin ax + b cos ax)
(121) xex
sin x dx =
1
2
ex
(cos x − x cos x + x sin x)
(122) xex
cos x dx =
1
2
ex
(x cos x − sin x + x sin x)
Integrals of Hyperbolic Functions
(123) cosh ax dx =
1
a
sinh ax
(124) eax
cosh bx dx =
eax
a2 − b2
[a cosh bx − b sinh bx] a = b
e2ax
4a
+
x
2
a = b
(125) sinh ax dx =
1
a
cosh ax
13
14. (126) eax
sinh bx dx =
eax
a2 − b2
[−b cosh bx + a sinh bx] a = b
e2ax
4a
−
x
2
a = b
(127) tanh axdx =
1
a
ln cosh ax
(128) eax
tanh bx dx =
e(a+2b)x
(a + 2b)
2F1 1 +
a
2b
, 1, 2 +
a
2b
, −e2bx
−
1
a
eax
2F1 1,
a
2b
, 1 +
a
2b
, −e2bx
a = b
eax
− 2 tan−1
[eax
]
a
a = b
(129) cos ax cosh bx dx =
1
a2 + b2
[a sin ax cosh bx + b cos ax sinh bx]
(130) cos ax sinh bx dx =
1
a2 + b2
[b cos ax cosh bx + a sin ax sinh bx]
(131) sin ax cosh bx dx =
1
a2 + b2
[−a cos ax cosh bx + b sin ax sinh bx]
(132) sin ax sinh bx dx =
1
a2 + b2
[b cosh bx sin ax − a cos ax sinh bx]
(133) sinh ax cosh axdx =
1
4a
[−2ax + sinh 2ax]
(134) sinh ax cosh bx dx =
1
b2 − a2
[b cosh bx sinh ax − a cosh ax sinh bx]
c 2014. From http://integral-table.com, last revised June 14, 2014. This mate-
rial is provided as is without warranty or representation about the accuracy, correctness or
suitability of this material for any purpose. This work is licensed under the Creative Com-
mons Attribution-Noncommercial-Share Alike 3.0 United States License. To view a copy
of this license, visit http://creativecommons.org/licenses/by-nc-sa/3.0/ or send
a letter to Creative Commons, 171 Second Street, Suite 300, San Francisco, California,
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