Statistika7
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1. The document provides information about a student named Julian Valerio Gultom in semester 2 including their student ID and interval class. 2. It calculates the mean (x̅), variance (S2), and standard deviation (S) of test score data for 7 students that were between 3-23 points. 3. It shows the calculations to find the (x-x̅)2 and f((x-x̅)2 values for each student's test score.
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Measures of Variability Part 2
The document provides data on ages and frequencies of individuals. It calculates the mean age as 41.0, the sum of deviations from the mean squared as 730, and the sample standard deviation as 2.38. It then shows the full calculations for finding the sample variance using the formula of summing the deviations from the mean squared multiplied by their respective frequencies and dividing by the total number of observations.
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The document provides data on ages and frequencies of individuals. It calculates the mean age as 41.0, the sum of deviations from the mean squared as 730, and the sample standard deviation as 2.38. It then shows the full calculations for finding the sample variance using the formula of summing the deviations from the mean squared multiplied by their respective frequencies and dividing by the total number of observations.
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The document contains a table with 15 observations of 4 variables (X1, X2, X3, X4) measured for each of 3 datasets (a total of 120 observations). The mean, standard deviation, and distribution of the data were calculated for each dataset. For all datasets, the data were found to be normally distributed. Datasets 2 and 3 were skewed slightly to the right. The standard deviations ranged from 0.01 to 0.18, indicating little variance among the observations within each dataset.
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Statistika7
- 1. Nama: Julian Valerio Gultom Nim: 19412005 Semester: II ( dua) TI Sore Interval Kela X f 2 X-X 2 X-Xf 3-5 6-8 9-11 12-14 15-17 18-20 21-23 4 5 10 13 16 19 22 2 3 4 6 10 12 3 75.8641 59.4441 7.3441 0.0841 10..8241 39.5641 86.3041 151.7282 178.3323 29.3764 0.5046 108.241 474.7692 258.9123 Σf = 40 ∑f(x-𝑥̅)2=1201.3594 Rumus mencari 𝒙̅ 𝑥̅ = 4 + 5 + 10 + 13 + 16 + 19 + 22 7 𝑥̅̅̅̅= 12.71 S2 = 1201.3594 40−1 = 30.8 S =√30.8 = 5.55
- 2. Penyelesaian 1. (x-𝑥̅)2 = ( 4 – 12.71)2 f(x-𝑥̅)2 = 2 ( 75.8641) = ( -8.71)2 = 151.7282 = 75.8641 2. (x-𝑥̅)2 = ( 5 – 12.71)2 f((x-𝑥̅)2 = 3 (59.4441) = ( -7.71)2 = 178.3323 = 59.4441 3. (x-𝑥̅)2 = ( 10 – 12.71)2 f(x-𝑥̅)2 = 4 (7.3441) = (--2.71)2 = 29.3764 = 7.3441 4. (x-𝑥̅)2 = ( 13 – 12.71)2 f(x-𝑥̅)2 = 6 (0.0841) = ( 0.29)2 = 0.5046 = 0.0841 5. (x-𝑥̅)2 = ( 16 – 12.71)2 f(x-𝑥̅)2 = 10 (10..8241) = (3.29)2 = 108.241 = 10..8241 6. (x-𝑥̅)2 = ( 19 – 12.71)2 f(x-𝑥̅)2 = 12 (39.5641) = (6.29)2 = 474.7692 = 39.5641 7. (x-𝑥̅)2 = ( 22 – 12.71)2 f(x-𝑥̅)2 = 3 (86.3041) = (9.29)2 = 258.9123 = 86.3041