The document summarizes the steps taken by four students to plot the trajectory of missiles launched from Earth and North Korea toward the moon using a scatter plot graph. They found the point of intersection between the trajectories and calculated that it would occur 232,405 kilometers from Earth, which is less than the distance from Earth to the moon's surface. They then calculated additional trajectory details like the average speed of the missiles.

1. By Keric, Tyler, Ethan, and Mike

2. Scatter Plot Graph

3. Prevention Plan 1) Plotted the points on a scatter plot graph and the found the best fit line for the US and North Korea. This showed that the best fit line equates to: Y=24388.1X-217474.4 Y=26176.4X-400085.1

4. 2) We then used our knowledge of the substitution method to solve for X 26176.4X-40085.1=24388.1X-21474.4 1788.3X=18610.7 -> X=10.41 3) Continuing our use of Substitution, we plugged in X and solved for Y, otherwise known as the distance of intersection from Earth. Y=24388.1 (10.41) – 21474.4 Y=232405.72

5. 4) Then we of course checked our coordinates in both solutions, this is the MOON we are talking about here! 232405.72 = 24388.1(10.41) -> 232405.72 = 253880.12 232405.72 = 26176.4(10.41) -> 232405.72 = 272496.32 5)We then took the radius of the moon times .27 because it’s 27% of the earth’s radius which in turn gave us the radius of the earth. 1737.4/.27 = 6434.81

6. 6) After finding the radius, we took (The distance from the center of Earth to the center of the moon) – (the moon’s radius) – (Earth’s radius) to get the distance from surface to surface. d= 384,476 – 1737.4 – 6434.81 d= 376303.79 Kilometers

7. 7) We checked that the distance from the Earth’s surface where they would intersect is less than the distance from Earth’s surface to the Moon’s surface. 232405.72 < 376303.79 8) Then took the number of hours in a day times the number of days to travel (on day 8) to get the number of hours travelled. 24(8) = 192

8. 9) Lastly, took the distance travelled (on day 8) divided by the number of hours travelled to get the average speed in Km/Hr for each of the missles. 173,057/192 = 901.34 Km/Hr 176,655/192 = 920.08 Km/Hr

9. Roles Keric – Power Point Mike – Graph and Power Point Tyler – Calculations and Process Ethan – Calculations and Process

10. End of Report