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Koya University
Faculty of Engineering
Chemical Engineering Department
3rd Stage (2021-2022)
Reactor Laboratory
Lab Report
Number of Experiment: 11
Experiment Name:
Impact of limiting Reactant Flow Rate on
Conversion in Plug Flow Reactor Test (21 o
C)
Experiment Date: 23/02/2022
Submitted on: 02/03/2021
Instructor: Mr. Ahmed Abdulkareem Ahmed
Group: A1
Prepared by:
Safeen Yaseen Jafar
Ahmed Mamand Aziz
Ibrahim Ali
Rokan Mohammad Omer
Rivan Dler Ali
Ramazan Shkur Kakl
1
1. Aim of Experiment
➢ Determine Conductivity.
➢ Find out conversion of Plug Flow Reactor (PFR) at 21 o
C with increasing
the limiting reactant flowrate.
2. Procedure
1. Prepare 1 L and 0.05 M of NaOH (solution). after it, we need to prepare second reactant
for reaction occur prepare 1 L and 0.05 M of CH3COOHC2H5 (solution) .
2. First of all, in the service units close all valve if open. After that put the bottles in specific
places in service unit. And be careful to that the pipes and valves are connected as well.
3. Turn on the switch control box (power supply).
4. In this experiment we don’t use water bath because it operates under room temperature (21
oC in this experiment).
5. Set the limited flow rate of the reagents before run the steps.
6. Switch on pumps of reactants.
7. Take the reactants from their containers to the Plug Flow Reactor (PFR).
8. Send both of reactants at same time by both reactant hose and reactants enter the reactor
by long tube (inside tube).
9. The reactants react together, and the tube flow as laminar through the Packaging and
then after a specific time give us a product.
10. Product will out from the top.
11. In this experiment we increase the flowrate of Limiting Reactant (NaOH)
12. To estimate the conductivity, we use the conductivity meter after output of the PFR.
Also, join end of the hose of product with the sensor then the value of conductivity can be
read on the display of the sensor.
13. At the end of the experiment, turn off the pumps.
14. Turn off the power of control interface box.
15. Reactants should be removed from both (1 and 2) reactant bottle container. Then, the
liquids must be kept for following test.
2
3. Tools and Apparatus
Figure 2: Service Unit - Back
Part
Figure 1: Service Unit - Front Part
1
2
4
3
5
6
7
Figure 3: Control Unit/Box
8
10
11
12
Figure 4: Plug Flow Reactor
13
9
14
3
Service Unit, control unit and its parts:
1. Water Bath: is the tank which contain water it used for control temperature of
reactants.
2. Water Bath temperature switch button and controllers.
3. Reactant Container 1: For storage reactant 1.
4. Reactant Container 2: For storage reactant 2.
5. Water Pump AB-1: it used for pumping water.
6. Pump AB-2: It used for pump the reactant 1.
7. Pump AB-3: It used for pump the reactant 2.
8. Pump AB-1 on/off button: It used for switch on or switch of pump AB-1.
9. Power Button: Used to turn on control unit.
10. Temperature Display: For displaying the temperatures
11. Temperature Sensor: for record or estimate temperature.
12. Volumetric Switch Button and Controller: For control the flowrate of reactant.
13. Sensor Selector: it used for select the temperature sensor that you want.
14. Temperature Controller: It can be used when we want to select specified
temperature or control temperature in water bath that we want.
Plug Flow reactor parts:
1. Tube: feeds (reactants) inter the reactor by two of hoses and flow through this
tube and react together.
2. Packaging: These Packaging are useful for increasing surface area to fast the
reaction or to make more collision number between reactants.
3. Temperature Sensor: it used for record temperature.
4
4. Calculation and Results
We obtained conductivity (λ) value from recording by conductivity meter in lab.
Concentration calculated by this equation:
CA
CAo
=
λ − λ∞
λo − λ∞
* Here we have four values for conductivity (λ)
Conversion calculated by this equation:
X =
CAo
− CA
CAo
CAo = 0.05 M
λo = 14.5 mS
λ∞ = 2.5 µS = 0.0025 mS
λ1 = 25 µS , λ2 = 26.4 µS , λ3 = 31.1 µS , λ4 = 31.5 µS
Let’s calculate X for (λ1 = 25 µS):
CA
0.05
=
0.025 − 0.0025
14.5 − 0.0025
CA
0.05
= 0.0015519
CA = 0.000077595 M
X =
0.05 − 0.000077595
0.05
X = 0.9984481
5
Let’s calculate X for (λ2 = 26.4 mS):
CA
0.05
=
0.0264 − 0.0025
14.5 − 0.0025
CA
0.05
= 0.00164856
CA = 0.000082428 M
X =
0.05 − 0.0495
0.05
→ 𝐗 = 𝟎. 𝟗𝟗𝟖𝟑𝟓𝟏𝟒
Let’s calculate X for (λ3 = 31.1 mS):
CA
0.05
=
0.0311 − 0.0025
14.5 − 0.0025
CA
0.05
= 0.0019727553
CA = 0.000098637 M
X =
0.05 − 0.0495
0.05
→ 𝐗 = 𝟎. 𝟗𝟗𝟖𝟎𝟐
Let’s calculate X for (λ4 = 31.5 mS):
CA
0.05
=
0.0315 − 0.0025
14.5 − 0.0025
CA
0.05
= 0.002000344
CA = 0.000100017 M
X =
0.05 − 0.0495
0.05
→ 𝐗 = 𝟎. 𝟗𝟗𝟕
6
5. Discussion
Discussion – Safeen Yaseen Ja’far
This Experiment about Plug Flow reactor or Plug flow reactor (PFR), from
the test we will learn that what is the impact of the increasing flowrate of the
reactant (Limiting Reactant) on the conversion (X). is after the starting procedure
we estimate conductivity (λ) and main aim of our experiment is that to finding out
the conversion (X) by using conductivity meter firstly and estimate value of
conductivity by this meter. this experiment is under room temperature of 21 o
C
(don’t use water bath) and we used NaOH and Ethyl Acetate (1L and 0.05 M). The
relationship between conductivity and flowrate is proportional but the relationship
between conductivity and conversion is vise versa, means when we increase flowrate
λ will increase then conversion will become less.
After the estimation of (λ) four times (during increasing flowrate) we need
to find the CA by an equation and then we can find X by equation of the conversion.
Discussion – Rivan Dler Ali
During this experiment we found conductivity, by conductivity meter then we
convert conductivity to conversion by this equation X=CA0-CA/CA0 at 20C. The
reaction is between NaOH with concentration of 0.05M and second reactant which
is CH3COOHC2H5 with same volume and concentration. First, we put the reactants
below the PFR since putting them above the reactor will cause them to fall quickly
and not have enough time to react due to gravity, and then we wait until they reach
the conductivity meter and start reading conductivity (λ) using the conductivity
meter. In this experiment we increased flow rate of limiting reactant which is NaOH
and we recorded the conductivity then convert it to concentration by this equation
Ca/Ca0= λ- λ∞/ λ0- λ∞ then determined conversion. We did that procedure four
7
times in a row while increasing flow rate of limiting reactant each time. Concluded
that each time we increased flow rate conversion decreases, because of reaction will
not complete perfectly.
Discussion – Ahmed Mamand Aziz
Throughout this experiment is about plug flow reactor (PFR), we were
determined the conductivity & conversion at 20 o
C, the solution of reactant was
between {Sodium hydroxide and Ethyl acetate} in the reactant input tube. Each
reactant prepared in 1 L contain of 0.05M. Read the value of conductivity-by-
conductivity meter four times by changing flowrate that is equal to λ1 = 25 µS, λ2
= 26.4 µS, λ3 = 31.1 µS, λ4 = 31.5 µS and these values are given λ∞=0.0025mS,
λo=14.5mS. Then we found conversion that is explained in calculation by the way
we have already have a value of λ∞=0.0025mS and λo=14.5 and we found the values
of λ in the experiment that is equal to λ1 = 25 µS , λ2 = 26.4 µS , λ3 = 31.1 µS , λ4
= 31.5 µS and also, we have the value of CAo =0.05, then we could find the value
of CA1 = 0.000077595 M and then by using the concentration low we found the X1
= 0.9984481 and same procedure for other changes, CA2 = 0.000082428 M and X2
=0.9983514, CA3 = 0.000098637 M and X3 = 0.99802, CA4 = 0.000100017 M and
X4 = 0.997.
According to these data when the flowrate will increase the value of
conductivity also increase, and when conductivity will increase by increasing the
flow rate the value of conversion will be decrease.
8
Discussion – Ramazan Shkur Kakl
While conducting the experiment we founded conductivity, then we got
conversion by switching the conductivity with following eq X=CA0-CA/CA0 at
20C. We start with 0.05M NaOH and then prepare the second reactant, which is also
0.05M CH3COOHC2H5. Then, from below, we pour the reactants into the Plug flow
reactor and wait until they reach the reactor's peak, at which point we take a first
reading of conductivity then we convert it to concentration by following equation
Ca/Ca0= λ- λ∞/ λ0- λ∞ at 20C then change it to conversion, result is 0.9984, then
we increased flow rate of limiting reactant NaOH 4 times the final result of
conversion is 0.997 we noticed that each time we increase flow rate conversion will
decrease.
Discussion – Ibrahim Ali
In this experiment we use plug Flow Reactor to our experiment and we want
to Determine Conductivity and Find out conversion of Plug Flow Reactor (PFR) at
21 C and in the plug Flow Reactor we have the catalyst inside the device this
catalyst increase cross section area and increase conversion but in this experiment
we increase the flow rate so the conversion is decrease because of increasing flow
rate and in this experiment we have two reactant we use 0.05 M NaOH and 0.05 M
of CH3COOHC2H5 to occur conversion and after a specific time we start to read
the conductivity-by-conductivity meter
Discussion – Rokan Mohammad
This experiment about plug flow reactor, estimate conductivity and aim of
our experiment is that to calculate the conversion (X). at different volume
flowrates, in this experiment at room temperature of 20 o
C, we used NaOH and
Ethyl Acetate 1L and 0.05 M. Then we recorded conductivity value by using
conductivity sensor, After, estimate of (λ) equal to λ1 = 25 µS, λ2 = 26.4 µS, λ3 =
9
31.1 µS, λ4 = 31.5 µS we find the CA and also find conversion (X). we have
already had a value of λ∞=0.0025mS and λo=14.5
Including the results, as the flowrate rises, the value of conductivity
increases as well, and when conductivity increases as the flow rate increases, the
value of conversion decreases.

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RD Lab - Exp-11 - G-A1.pdf

  • 1. Koya University Faculty of Engineering Chemical Engineering Department 3rd Stage (2021-2022) Reactor Laboratory Lab Report Number of Experiment: 11 Experiment Name: Impact of limiting Reactant Flow Rate on Conversion in Plug Flow Reactor Test (21 o C) Experiment Date: 23/02/2022 Submitted on: 02/03/2021 Instructor: Mr. Ahmed Abdulkareem Ahmed Group: A1 Prepared by: Safeen Yaseen Jafar Ahmed Mamand Aziz Ibrahim Ali Rokan Mohammad Omer Rivan Dler Ali Ramazan Shkur Kakl
  • 2. 1 1. Aim of Experiment ➢ Determine Conductivity. ➢ Find out conversion of Plug Flow Reactor (PFR) at 21 o C with increasing the limiting reactant flowrate. 2. Procedure 1. Prepare 1 L and 0.05 M of NaOH (solution). after it, we need to prepare second reactant for reaction occur prepare 1 L and 0.05 M of CH3COOHC2H5 (solution) . 2. First of all, in the service units close all valve if open. After that put the bottles in specific places in service unit. And be careful to that the pipes and valves are connected as well. 3. Turn on the switch control box (power supply). 4. In this experiment we don’t use water bath because it operates under room temperature (21 oC in this experiment). 5. Set the limited flow rate of the reagents before run the steps. 6. Switch on pumps of reactants. 7. Take the reactants from their containers to the Plug Flow Reactor (PFR). 8. Send both of reactants at same time by both reactant hose and reactants enter the reactor by long tube (inside tube). 9. The reactants react together, and the tube flow as laminar through the Packaging and then after a specific time give us a product. 10. Product will out from the top. 11. In this experiment we increase the flowrate of Limiting Reactant (NaOH) 12. To estimate the conductivity, we use the conductivity meter after output of the PFR. Also, join end of the hose of product with the sensor then the value of conductivity can be read on the display of the sensor. 13. At the end of the experiment, turn off the pumps. 14. Turn off the power of control interface box. 15. Reactants should be removed from both (1 and 2) reactant bottle container. Then, the liquids must be kept for following test.
  • 3. 2 3. Tools and Apparatus Figure 2: Service Unit - Back Part Figure 1: Service Unit - Front Part 1 2 4 3 5 6 7 Figure 3: Control Unit/Box 8 10 11 12 Figure 4: Plug Flow Reactor 13 9 14
  • 4. 3 Service Unit, control unit and its parts: 1. Water Bath: is the tank which contain water it used for control temperature of reactants. 2. Water Bath temperature switch button and controllers. 3. Reactant Container 1: For storage reactant 1. 4. Reactant Container 2: For storage reactant 2. 5. Water Pump AB-1: it used for pumping water. 6. Pump AB-2: It used for pump the reactant 1. 7. Pump AB-3: It used for pump the reactant 2. 8. Pump AB-1 on/off button: It used for switch on or switch of pump AB-1. 9. Power Button: Used to turn on control unit. 10. Temperature Display: For displaying the temperatures 11. Temperature Sensor: for record or estimate temperature. 12. Volumetric Switch Button and Controller: For control the flowrate of reactant. 13. Sensor Selector: it used for select the temperature sensor that you want. 14. Temperature Controller: It can be used when we want to select specified temperature or control temperature in water bath that we want. Plug Flow reactor parts: 1. Tube: feeds (reactants) inter the reactor by two of hoses and flow through this tube and react together. 2. Packaging: These Packaging are useful for increasing surface area to fast the reaction or to make more collision number between reactants. 3. Temperature Sensor: it used for record temperature.
  • 5. 4 4. Calculation and Results We obtained conductivity (λ) value from recording by conductivity meter in lab. Concentration calculated by this equation: CA CAo = λ − λ∞ λo − λ∞ * Here we have four values for conductivity (λ) Conversion calculated by this equation: X = CAo − CA CAo CAo = 0.05 M λo = 14.5 mS λ∞ = 2.5 µS = 0.0025 mS λ1 = 25 µS , λ2 = 26.4 µS , λ3 = 31.1 µS , λ4 = 31.5 µS Let’s calculate X for (λ1 = 25 µS): CA 0.05 = 0.025 − 0.0025 14.5 − 0.0025 CA 0.05 = 0.0015519 CA = 0.000077595 M X = 0.05 − 0.000077595 0.05 X = 0.9984481
  • 6. 5 Let’s calculate X for (λ2 = 26.4 mS): CA 0.05 = 0.0264 − 0.0025 14.5 − 0.0025 CA 0.05 = 0.00164856 CA = 0.000082428 M X = 0.05 − 0.0495 0.05 → 𝐗 = 𝟎. 𝟗𝟗𝟖𝟑𝟓𝟏𝟒 Let’s calculate X for (λ3 = 31.1 mS): CA 0.05 = 0.0311 − 0.0025 14.5 − 0.0025 CA 0.05 = 0.0019727553 CA = 0.000098637 M X = 0.05 − 0.0495 0.05 → 𝐗 = 𝟎. 𝟗𝟗𝟖𝟎𝟐 Let’s calculate X for (λ4 = 31.5 mS): CA 0.05 = 0.0315 − 0.0025 14.5 − 0.0025 CA 0.05 = 0.002000344 CA = 0.000100017 M X = 0.05 − 0.0495 0.05 → 𝐗 = 𝟎. 𝟗𝟗𝟕
  • 7. 6 5. Discussion Discussion – Safeen Yaseen Ja’far This Experiment about Plug Flow reactor or Plug flow reactor (PFR), from the test we will learn that what is the impact of the increasing flowrate of the reactant (Limiting Reactant) on the conversion (X). is after the starting procedure we estimate conductivity (λ) and main aim of our experiment is that to finding out the conversion (X) by using conductivity meter firstly and estimate value of conductivity by this meter. this experiment is under room temperature of 21 o C (don’t use water bath) and we used NaOH and Ethyl Acetate (1L and 0.05 M). The relationship between conductivity and flowrate is proportional but the relationship between conductivity and conversion is vise versa, means when we increase flowrate λ will increase then conversion will become less. After the estimation of (λ) four times (during increasing flowrate) we need to find the CA by an equation and then we can find X by equation of the conversion. Discussion – Rivan Dler Ali During this experiment we found conductivity, by conductivity meter then we convert conductivity to conversion by this equation X=CA0-CA/CA0 at 20C. The reaction is between NaOH with concentration of 0.05M and second reactant which is CH3COOHC2H5 with same volume and concentration. First, we put the reactants below the PFR since putting them above the reactor will cause them to fall quickly and not have enough time to react due to gravity, and then we wait until they reach the conductivity meter and start reading conductivity (λ) using the conductivity meter. In this experiment we increased flow rate of limiting reactant which is NaOH and we recorded the conductivity then convert it to concentration by this equation Ca/Ca0= λ- λ∞/ λ0- λ∞ then determined conversion. We did that procedure four
  • 8. 7 times in a row while increasing flow rate of limiting reactant each time. Concluded that each time we increased flow rate conversion decreases, because of reaction will not complete perfectly. Discussion – Ahmed Mamand Aziz Throughout this experiment is about plug flow reactor (PFR), we were determined the conductivity & conversion at 20 o C, the solution of reactant was between {Sodium hydroxide and Ethyl acetate} in the reactant input tube. Each reactant prepared in 1 L contain of 0.05M. Read the value of conductivity-by- conductivity meter four times by changing flowrate that is equal to λ1 = 25 µS, λ2 = 26.4 µS, λ3 = 31.1 µS, λ4 = 31.5 µS and these values are given λ∞=0.0025mS, λo=14.5mS. Then we found conversion that is explained in calculation by the way we have already have a value of λ∞=0.0025mS and λo=14.5 and we found the values of λ in the experiment that is equal to λ1 = 25 µS , λ2 = 26.4 µS , λ3 = 31.1 µS , λ4 = 31.5 µS and also, we have the value of CAo =0.05, then we could find the value of CA1 = 0.000077595 M and then by using the concentration low we found the X1 = 0.9984481 and same procedure for other changes, CA2 = 0.000082428 M and X2 =0.9983514, CA3 = 0.000098637 M and X3 = 0.99802, CA4 = 0.000100017 M and X4 = 0.997. According to these data when the flowrate will increase the value of conductivity also increase, and when conductivity will increase by increasing the flow rate the value of conversion will be decrease.
  • 9. 8 Discussion – Ramazan Shkur Kakl While conducting the experiment we founded conductivity, then we got conversion by switching the conductivity with following eq X=CA0-CA/CA0 at 20C. We start with 0.05M NaOH and then prepare the second reactant, which is also 0.05M CH3COOHC2H5. Then, from below, we pour the reactants into the Plug flow reactor and wait until they reach the reactor's peak, at which point we take a first reading of conductivity then we convert it to concentration by following equation Ca/Ca0= λ- λ∞/ λ0- λ∞ at 20C then change it to conversion, result is 0.9984, then we increased flow rate of limiting reactant NaOH 4 times the final result of conversion is 0.997 we noticed that each time we increase flow rate conversion will decrease. Discussion – Ibrahim Ali In this experiment we use plug Flow Reactor to our experiment and we want to Determine Conductivity and Find out conversion of Plug Flow Reactor (PFR) at 21 C and in the plug Flow Reactor we have the catalyst inside the device this catalyst increase cross section area and increase conversion but in this experiment we increase the flow rate so the conversion is decrease because of increasing flow rate and in this experiment we have two reactant we use 0.05 M NaOH and 0.05 M of CH3COOHC2H5 to occur conversion and after a specific time we start to read the conductivity-by-conductivity meter Discussion – Rokan Mohammad This experiment about plug flow reactor, estimate conductivity and aim of our experiment is that to calculate the conversion (X). at different volume flowrates, in this experiment at room temperature of 20 o C, we used NaOH and Ethyl Acetate 1L and 0.05 M. Then we recorded conductivity value by using conductivity sensor, After, estimate of (λ) equal to λ1 = 25 µS, λ2 = 26.4 µS, λ3 =
  • 10. 9 31.1 µS, λ4 = 31.5 µS we find the CA and also find conversion (X). we have already had a value of λ∞=0.0025mS and λo=14.5 Including the results, as the flowrate rises, the value of conductivity increases as well, and when conductivity increases as the flow rate increases, the value of conversion decreases.