Need help writing Conways Game of Life. These are the instructions.pdf
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Need help writing Conway\'s Game of Life. These are the instructions: The game of Life is intended to model life in a society of organisms. Consider a rectangular array of cells, each of which may contain an organism. If the array is considered to extend indefinitely in both directions, then each cell has eight neighbors, the eight cells surrounding it. Births and deaths occur according to the following rules: An organism is born in any empty cell having exactly three neighbors. An organism dies from isolation if it has fewer than two neighbors. An organism dies from overcrowding if it has more than three neighbors. All other organisms survive to the next generation. Write a program to play the game of Life and investigate the patterns produced by various initial configurations. Some configurations die off rather rapidly; others repeat after a certain number of generations; others change shape and size and may move across the array. NOTE: For representing each organism, use \"@\" characters. For an array of cells, use 30x30 two-dimensional array. Each generation should be displayed on the screen and should be paused. (You can use cin.get( ) library function to pause running your program.) 4. The source file should be called life.cpp 5. All assignments are expected to be INDIVIDUAL work. All work handed in must be original. Duplicate or very similar programs receive zero points. Input A set of initial cells will be given using the interactive way using a keyboard. The followings are the prompt for the input: Please Enter the number of initial cells: 4 The position of cell is 10 10 The position of cell is 10 11 The position of cell is 10 12 The position of cell is 11 11 How many generations do you want to display? 3 Output The program then display each generation of organisms at a time. The 1-generation @@@ @ Press any key to continue!! (This picture should be displayed on the new screen.) The 2-generation @ @@@ @@@ Press any key to continue!! The 3-generation @@@ @ @ @ Do you want to do it again?(Yes/No) N Solution Note: User given template is used. Answer: #include #include #include #include #include using namespace std; int orAry[30][30]; void initilaize() { for(int kk=0;kk<30;kk++) { for(int bb=0;bb<30;bb++) { orAry[kk][bb]=0; } } } void disply() { cout<=0 ) { cc++; } if( orAry[kk+1][aa-1]==1 && kk+1<30 && aa-1>=0) { cc++; } if( orAry[kk+1][aa]==1 && kk+1<30) { cc++; } if( orAry[kk][aa+1]==1 && aa+1<30) { cc++; } if( orAry[kk-1][aa-1]==1 && kk-1>=0 && aa-1>=0) { cc++; } if(orAry[kk+1][aa+1]==1 && kk+1<30 && aa+1<30) { cc++; } if(orAry[kk-1][aa]==1 && kk-1>=0) { cc++; } if( orAry[kk-1][aa+1]==1 && kk-1>=0 && aa+1<30) { cc++; } return cc; } void runLife() { int bCnt=0; int dCnt=0; for(int kk=0;kk<30;kk++) { for(int bb=0;bb<30;bb++) { if(orAry[kk][bb]==0) { bCnt=ChechNeighBourCount(kk,bb); if(bCnt==3) { orAry[kk][bb]=1; } } else if(orAry[kk][bb]==1) { dCnt=ChechNeighBourCount(kk,bb); if(dCnt>3) { orAry[kk][bb]=0; } if(dCnt<2) { orAry[kk][bb]=0.
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![(This picture should be displayed on the new screen.)
The 2-generation
@
@@@
@@@
Press any key to continue!!
The 3-generation
@@@
@ @
@
Do you want to do it again?(Yes/No) N
Solution
Note: User given template is used.
Answer:
#include
#include
#include
#include
#include
using namespace std;
int orAry[30][30];
void initilaize()
{
for(int kk=0;kk<30;kk++)
{
for(int bb=0;bb<30;bb++)
{
orAry[kk][bb]=0;
}
}
}
void disply()
{](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
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#include
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#include
int rows = 30;
coloums= 40;
static final int dead = 0
int alive =1;
int[] [] stateint main {.
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<img src="images/game-of-life-1.png"
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the transactions b) Prepare the Statement of Changes in Shareholder\'s Equity (HINTS: (a) Use
format similar to that shown in Illustration 14-10 on page 747 in the textbook; (b) you will need
a column for Preferred shares instead of Contributed Surplus)
Solution
Journal Entries
Date
Particulars
Debit
Credit
31-Jan
Cash
$66,500.00
Preferred Shares
$66,500.00
Preferred Shares being issued
2-Mar
Cash
$80,000.00
Treasury stock
$80,000.00
Common stocks being repurchased
28-Jun
No entry required, since stocks do not have any par value
15-Sep
Dividends - Preferred
$30,800.00
Dividends Payable - Preferred
$30,800.00
Preferred dividends at $4 per dividend being declared
30-Sep
Dividends Payable - Preferred
$30,800.00
Cash
$30,800.00
Preferred dividends declared being paid
31-Oct
Dividends - Common
$217,500.00
Dividends Payable - Common
$217,500.00
Common stock dividends being declared
15-Dec
Dividends Payable - Common
$217,500.00
Cash
$217,500.00
Common dividends declared being paid
Dividends payable – Preferred = (7,000 + 700) x $4 = $30,800
Dividends payable – Common = (150,000 – 5,000) x $0.50 = $217,500
Stocks repurchased at $16 = 5,000 x $16 = $80,000
Statement of Changes in Shareholders\' Equity
Year ended on December 31, 2017
Preferred Share Capital
Common Share Capital
Treasury Shares
Retained Earnings
Accumulated Other Comprehensive Income
Total Equity
Balance at January 1, 2017
$850,000
$2,250,000
$0
$1,750,000
$22,000
$4,872,000
Profit for the year
$0
$0
$0
$450,000
$0
$450,000
Other Comprehensive Income
$0
$0
$0
$0
$15,000
$15,000
Dividends - Preferred
$0
$0
$0
$30,800
$0
$30,800
Dividends - Common
$0
$0
$0
$217,500
$0
$217,500
Purchase of Own Shares
$0
$0
$80,000
($80,000)
$0
$0
Balance at December 31, 2017
$850,000
$2,250,000
$80,000
$2,368,300
$37,000
$5,585,300
Journal Entries
Date
Particulars
Debit
Credit
31-Jan
Cash
$66,500.00
Preferred Shares
$66,500.00
Preferred Shar.
Place the following formulas in their proper order A. ALE, residu.pdf
Place the following formulas in their proper order:
A. ALE, residual risk, SLE, ARO
B. ALE, ARO, SLE, residual risk
C. ARO, SLE, ALE, residual risk
D. SLE, ARO, ALE, residual risk
Solution
D. The quantitative assessment process involves the following steps: Estimate potential losses
(SLE), conduct a threat analysis (ARO), determine annual loss expectancy (ALE), and determine
the residual risk after a countermeasure has been applied..
please help i have 40 minsItem 1In the case below, the original .pdf
please help i have 40 mins
Item 1
In the case below, the original source material is given along with a sample of student work.
Determine the type of plagiarism by clicking the appropriate radio button.
Original Source Material
Student Version
There is a design methodology called rapid prototyping, which has been used successfully in
software engineering. Given similarities between software design and instructional design, we
argue that rapid prototyping is a viable method for instructional design, especially for computer-
based instruction.
References:
Tripp, S. D., & Bichelmeyer, B. A. (1990). Rapid prototyping: An alternative instructional
design strategy. Educational Technology Research and Development, 38(1), 31-44.
Tripp and Bichelmeyer (1990) suggested that rapid prototyping could be an advantageous
methodology for developing innovative computer-based instruction. They noted that this
approach has been used successfully in software engineering; hence, rapid prototyping could also
be a viable method for instructional design due to many parallels between software design and
instructional design.
References:
Tripp, S. D., & Bichelmeyer, B. A. (1990). Rapid prototyping: An alternative instructional
design strategy. Educational Technology Research and Development, 38(1), 31-44.
Which of the following is true for the Student Version above?
Word-for-Word plagiarism
Paraphrasing plagiarism
This is not plagiarism
Hints
Item 2
In the case below, the original source material is given along with a sample of student work.
Determine the type of plagiarism by clicking the appropriate radio button.
Original Source Material
Student Version
Learning is a complex set of processes that may vary according to the developmental level of the
learner, the nature of the task, and the context in which the learning is to occur. As already
indicated, no one theory can capture all the variables involved in learning.
References:
Gredler, M. E. (2001). Learning and instruction: Theory into practice (4th Ed.). Upper Saddle,
NJ: Prentice-Hall.
A learning theory, there, comprises a set of constructs linking observed changes in performance
with what is thought to bring about those changes.
References:
Driscoll, M. P. (2000). Psychology of learning for instruction (2nd Ed.). Needham Heights, MA:
Allyn & Bacon.
A learning theory is made up of a set of constructs linking observed changes in performance with
whatever is thought to bring about those changes. Therefore since learning is a complex set of
processes that may vary according to the developmental level of the learner, the nature of the
task, and the context in which the learning is to occur, it is apparent that no one theory can
capture all the variables involved in learning.
Which of the following is true for the Student Version above?
Word-for-Word plagiarism
Paraphrasing plagiarism
This is not plagiarism
Hints
Item 3
In the case below, the original source material is given along with a sample of student work.
Det.
Non-Euclidean GeometryWhat statement, if any, can be made about th.pdf
Non-Euclidean Geometry
What statement, if any, can be made about the summit and base in a quadrilateral whose
opposites sides lie on parallel lines?
Solution
If the opposite sides of a quadrilateral lie on parallel lines then the quadrilateral can satisfy the
possibility of being a parallelogram, rhombus, square , rectangle or trapezium because in all
these quadrilaterals have the property where opposite sides are parallel..
Java ProgrammingA Swing button can have more than one action liste.pdf
Java Programming
A Swing button can have more than one action listener.
is this True or False?
Solution
Answer: False
A Swing button can have only one action listener and one action event. these are ActionListener
and ActionEvent respectively.
We can handle that action by using beow method that is provided by ActionListner.
public void actionPerformed(ActionEvent e){
}.
JAVA Write a class called F.pdf
*****************JAVA********************** Write a class called Fraction, which can
be used to store an exact fraction. It must have: - A field to store the numerator - A
field to store the denominator - A toString method that returns a neatly formatted String
representing the fraction - An equals method that compares itself to another Fraction -
An add method that adds itself to another Fraction and returns a new Fraction - Appropriate
constructor and accessors as needed Write a program that asks the user to enter the numerators
and denominators of two fractions and create corresponding Fraction objects. Check for valid
input and a 0 denominator. Then output both Fractions (using your toString method implicitly),
whether they are equal, and their sum. Name your main class Hw6pr2 and your file
Hw6pr2.java. Submit all .java files
Solution
import java.util.*;
import java.io.*;
public class Fraction
{
static Scanner console = new Scanner(System.in);
public static void main(String[] args);
private int numerator;
private int denominator;
System.out.println(\"Enter the denominator\");
System.out.flush();
while(console.hasNext())
{
denominator = console.nextInt();
public String toString()
{
return (numerator + \" / \" + denominator);
}
public boolean equals(Fraction rightFr)
{
return(numerator * rightFr.denominator == denominator * rightFr.numerator);
}
public int compareTo(Fraction rightFr)
{
return(numerator * rightFr.denominator-denominator * rightFr.numerator);
}
public Fraction(int num, int deno) throws Exception
{
numerator = num;
if(deno == 0)
throw new Exception(\"denominator cannot be zero\");
else
denominator = deno;
}
public Fraction()
{
numerator = 0;
denominator = 1;
}
public void setFraction(int num, int deno) throws Exception
{
numerator = num;
if(deno == 0)
throw new Exception(\"denominator cannot be zero\");
else
denominator = deno;
}
public Fraction add(Fraction rightFr)
{
Fraction temp = new Fraction();
temp.numerator = numerator * rightFr.denominator + rightFr.numerator * denominator;
temp.denominator = denominator * rightFr.denominatior;
return temp;
}
public Fraction multiply(Fraction rightFr)
{
Fraction temp = new Fraction();
temp.numerator = numerator * rightFr.numerator;
temp.denominator = denominator * rightFr.denominator;
return temp;
}
public Fraction subtract(Fraction rightFr)
{
Fraction temp = new Fraction();
temp.numerator = numerator * rightFr. denominator-rightFr.numerator * denominator;
temp.denominator = denominator * rightFr.denominator;
retrun temp;
}
Fraction divide(Fraction rightFr) throws Exception
{
Fraction temp = new Fraction();
if(rightFr.numerator == 0)
throw new Exception(\"Cannot divide by zero\");
else{
temp.numerator = numerator * rightFr.denominator;
temp.denominator = rightFr.numerator *denominator;
return temp;
}
System.out.println(\" \");
System.out.println(\" \" +(numerator + denominator));
}
}.
In the adult, red bone marrow would normally be found in the sternu.pdf
In the adult, red bone marrow would normally be found in the: sternum diaphysis of the femur.
diaphysis of the humerus. medullary cavity of most long bones. choices A, B, and C.
Solution
in the adults normally the red bone marrow is found in the flat bones such as the sternum and
pelvic girdle femur and the humerus so the correct option is \"E\"..
I need help with these two questions 4.12 and 4.13 dealing with MATL.pdf
I need help with these two questions 4.12 and 4.13 dealing with MATLAB. Thank you in
advance.
Solution
clear all;
bigBal=2*10^5;
endBal=bigBal;
i=1;
payment=1199.11;
while endBal>0
A(i)=endBal*(1+0.5/100);
B(i)=payment;
C(i)=A(i)-B(i);
endBal=C(i);
i=i+1;
end
fileID = fopen(\'exp.txt\',\'w\');
x=1:1:(i-1);
M=[x; A; B; C];
fprintf(fileID,\'%4s %12s %12s %12s\ \',\'month\',\'Beg Balance\',\'payment\', \'end Balance\');
fprintf(fileID,\'%6.2f %12.2f %8.2f %6.2f\ \',M);
type exp.txt
if endBal<0
fprintf(\' Final balance amount to be refunded is: %f\', -endBal);
end
%out put
month Beg Balance payment end Balance
1.00 201000.00 1199.11 199800.89
2.00 200799.89 1199.11 199600.78
3.00 200598.79 1199.11 199399.68
4.00 200396.68 1199.11 199197.57
5.00 200193.55 1199.11 198994.44
6.00 199989.42 1199.11 198790.31
7.00 199784.26 1199.11 198585.15
8.00 199578.07 1199.11 198378.96
9.00 199370.86 1199.11 198171.75
10.00 199162.61 1199.11 197963.50
11.00 198953.32 1199.11 197754.21
12.00 198742.98 1199.11 197543.87
13.00 198531.59 1199.11 197332.48
14.00 198319.14 1199.11 197120.03
15.00 198105.63 1199.11 196906.52
16.00 197891.05 1199.11 196691.94
17.00 197675.40 1199.11 196476.29
18.00 197458.67 1199.11 196259.56
19.00 197240.86 1199.11 196041.75
20.00 197021.96 1199.11 195822.85
21.00 196801.96 1199.11 195602.85
22.00 196580.87 1199.11 195381.76
23.00 196358.67 1199.11 195159.56
24.00 196135.35 1199.11 194936.24
25.00 195910.92 1199.11 194711.81
26.00 195685.37 1199.11 194486.26
27.00 195458.70 1199.11 194259.59
28.00 195230.88 1199.11 194031.77
29.00 195001.93 1199.11 193802.82
30.00 194771.84 1199.11 193572.73
31.00 194540.59 1199.11 193341.48
32.00 194308.19 1199.11 193109.08
33.00 194074.62 1199.11 192875.51
34.00 193839.89 1199.11 192640.78
35.00 193603.98 1199.11 192404.87
36.00 193366.90 1199.11 192167.79
37.00 193128.63 1199.11 191929.52
38.00 192889.16 1199.11 191690.05
39.00 192648.50 1199.11 191449.39
40.00 192406.64 1199.11 191207.53
41.00 192163.57 1199.11 190964.46
42.00 191919.28 1199.11 190720.17
43.00 191673.77 1199.11 190474.66
44.00 191427.04 1199.11 190227.93
45.00 191179.07 1199.11 189979.96
46.00 190929.86 1199.11 189730.75
47.00 190679.40 1199.11 189480.29
48.00 190427.69 1199.11 189228.58
49.00 190174.72 1199.11 188975.61
50.00 189920.49 1199.11 188721.38
51.00 189664.99 1199.11 188465.88
52.00 189408.21 1199.11 188209.10
53.00 189150.14 1199.11 187951.03
54.00 188890.79 1199.11 187691.68
55.00 188630.14 1199.11 187431.03
56.00 188368.18 1199.11 187169.07
57.00 188104.92 1199.11 186905.81
58.00 187840.34 1199.11 186641.23
59.00 187574.43 1199.11 186375.32
60.00 187307.20 1199.11 186108.09
61.00 187038.63 1199.11 185839.52
62.00 186768.72 1199.11 185569.61
63.00 186497.46 1199.11 185298.35
64.00 186224.84 1199.11 185025.73
65.00 185950.86 1199.11 184751.75
66.00 185675.50 1199.11 184476.39
67.00 185398.78 1199.11 184199.67
68.00 185120.66 1199.11 183921.55
69.00 184841.16 1199.11 183642.05
70.00 184560.26 1199.11 183361.15
71.00 18427.
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Similar to Need help writing Conways Game of Life. These are the instructions.pdf
## Part B- Conway's Game of Life ### Introduction John Conway's Ga.pdf
## Part B: Conway's Game of Life
### Introduction
John Conway's Game of Life is a well known "game" with a very simple set of
rules that can simulate incredibly sophisticated behavior (as sophisticated, in
fact, as any computer program). Its setting -- which we'll refer to as the
game's "world" -- is a two-dimensional grid of cells, each one either living or
dead, and considered to be in contact with its eight neighbors (i.e.,
orthogonally or diagonally adjacent cells).
Given the state of each cell in the world at time $t_n$, we can compute the
state of each cell at time $t_{n+1}$ (i.e., one generation later) using the
following rules:
- **Birth rule**: a dead cell with exactly three living neighbors comes alive.
- **Survival rule**: a living cell with two to three neighbors remains alive.
- **Death rule**: a living cell with zero or one neighbors dies in isolation; a
living cell with four or more neighbors dies of overcrowding
The image below depicts a world before and after the rules are applied to a
group of cells.
<img src="images/game-of-life-1.png"
alt="Game of Life example"
style="display: block; margin: 0 auto; width:650px;"/>
Many living cell patterns have been discovered that result in
stable/non-changing shapes and repeatedly oscillating shapes, among other types
(see the [example patterns in the Game of Life Wikipedia
article](https://en.wikipedia.org/wiki/Conway%27s_Game_of_Life#Examples_of_patterns)
for some). An interesting fact about the Game of Life is that there is no
algorithm which can reliably predict whether or not a given pattern will appear
in the world given some starting state (this is related to the halting problem,
covered in CS 330).
Since each world state (after the initial state) is a pure function of the
preceding one, and the game world can be easily modeled using lists,
implementing the Game of Life makes for another fun list processing
exercise!
### Implementation in Haskell
We will represent the game world using the type: `((Int,Int), [[Bool]])`. I.e.,
as a tuple where the first element is a tuple of two integers $(w,h)$
representing the width and height of the world, and the second element is a list
of lists of Booleans representing the 2D grid, where each sublist of length
$w$ represents the cells in a row of the world, with $h$ sublists total.
A barren (i.e., containing only dead cells) world can be created with the
following function, which takes as input the width and height:
makeWorld :: (Int,Int) -> ((Int,Int), [[Bool]])
makeWorld dims@(w,h) = (dims, replicate h (replicate w False))
In "src/MP2b.hs" you will find declarations for functions you must complete to
implement the Game of Life. The first two functions compute the number of live
neighbors of a cell and the next world state:
liveNeighbors :: ((Int,Int), [[Bool]]) -- world
-> (Int,Int) -- cell
-> Int -- number of living neighbors
nextWorld :: ((Int,Int), [[Bool]]) -- world
-> ((Int,Int), [[Bool]]) -- next world (one generation later)
To animat.
Visual Programing basic lectures 7.pptx
Visual programming (VP) refers to a method of programming that uses a graphical interface to create and modify code, rather than typing out code manually. Unlike traditional text-based programming, visual programming uses visual elements to represent code. Some graphical elements you can use when creating programs with VP include:
Similar to Need help writing Conways Game of Life. These are the instructions.pdf (7)
## Part B- Conway's Game of Life ### Introduction John Conway's Ga.pdf
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What does it mean by mRNA coded for by the Operon What does it.pdf
What does it mean by mRNA coded for by the Operon?
What does it mean by mRNA coded for by the Operon?
Solution
operons are the functional unit of geonomic DNA containg a cluster of genes under the control of
a singale promoter, the genes are transcripted together into an mRNA strand and either translated
together in the cytoplasam,\'several genes must be co transcipted to define an operon, operons
are mainly exist in the prokaryotes and first operons are in eukarytes in 1990, one of main code
in the operons is mRNA is mainly trnaslate the messages.
Variability of a sample can he measured use the following statistic(s.pdf
Variability of a sample can he measured use the following statistic(s): Sample mean Standard
deviation Variance Both b and c are correct
Solution
Sample mean is a measure of central tendencym not variability.
However, standard deviation and variance are measures of variability.
Hence,
OPTION D: BOTH B AND C ARE CORRECT [ANSWER].
What are the advantages of using a compiled language over an interpr.pdf
What are the advantages of using a compiled language over an interpreted one? Under what
circumstances would you choose to use an interpreted language?
Solution
Advantages of compiled language over interpreted language:
- The general languges like c, c++, cobol etc., all these languages are compiled through a
compiler and converted source code into a binary file so this source code can be executed
number of times that means when the source code is compiled there is no need to translation of
this code whenever we tend to execute it only translate once and after that when at execution
time it only loads and execute.
- The programs which are under compiled language are more efficient when compared to
interpreted because it need not to be run each and every time.
- It can be very simply executed s that used more for the embeeded systems than interpreterd
language.
Usage of the interpreted languages:
- The language is platform independent so we can use this language on any type of platforms.
- It supports the object oriented programming where we can devolep secured applications with
efficient output.
- It supports language interoperability so we can use many programming languages..
Unbiased estimators Let theta be an estimator of a parameter theta..pdf
Unbiased estimators: Let theta be an estimator of a parameter theta. We say that theta is an
unbiased estimator of theta if E(theta) = theta Examples: Let X1, X2, ,Xn be an i.i.d. sample
from a population with mean mu and standard deviation sigma. Show that X and S^2 are
unbiased estimators of mu and sigma^2 respectively.
Solution.
Thomas Lewis said “the capacity to blunder slightly is the real marv.pdf
Thomas Lewis said “the capacity to blunder slightly is the real marvel of DNA. Without this
special attribute, we would still be anaerobic bacteria and there would be no music” Explain
what he means……
Solution
Blunder means a stupid or careless mistake. Mistakes are the very best to get anything useful
done. The mistakes of DNA are the real driving force for evolution through mutation. By this
simple creature becomes more complex. Mutations provide change. Different forms of life have
been evolved. Continual variation in genetic material provides the bases of all evolved forms of
life. Genetic variability, due to mutations in DNA, have many causes including errors during
normal replication, insults from chemicals or radiation, jumps or transpositions of genetic
materials, and other “spontaneous” changes. Our imperfection is God-given, built into our DNA,
a gift of grace and cause for hope.DNA has the built in capacity for mistakes or imperfections.
Today’s creation would not have happened. And we still remain today like the anaerobic bacteria
with very little oxygen oxygen. Anaerobic bacteria do not live or grow when oxygen is present.
The Great Oxygenation Event (GOE, also called the Oxygen Catastrophe, Oxygen Crisis,
Oxygen Holocaust, Oxygen Revolution, or Great Oxidation) was the biologically induced
appearance of dioxygen (O2) in Earth\'s atmosphere. The first autotrophy would have occurred
without oxygen. After the appearance of oxygen-producing photosynthesis, oxygen so produced
in water accumulated in the atmosphere and paved the way for to the arrival of aerobic
organisms. The earliest evolution must have taken place in anaerobic conditions, i.e. in the
absence of dioxygen. Oceanic cyanobacteria, which evolved into multicellular are believed to
have become the first microbes to produce oxygen by photosynthesis. These evolutionary
processes come out as the mutation or mistakes of DNA not by other means. Today’s life is the
only cause of it..
The strongest attractive forces between molecules of H_2O are ionic.pdf
The strongest attractive forces between molecules of H_2O are: ionic covalent hydrogen
bonding dipole-dipole attractions dispersion forces
Solution
Water molecules are held strong by hydrogen bond (electrostatic attraction). Due to this strong
bond only water is in liquid state.
Even though ionic and co valent bonds are stronger than hydrogen bond , in water two
hydrogen\'s are held together by strong hydrogen bond (electrostatic attraction between two polar
molecules)..
Q1. An individual who accepts the risks and opportunities entailed b.pdf
Q1. An individual who accepts the risks and opportunities entailed by creating and operating a
new business is a(n) ___________.
a. director
b. proprietor
c. entrepreneur
d. partner
e. officer
Q2. Prior to deregulation, the market for electricity in California would be best described as
a. perfect competition.
b. a monopoly.
c. an oligopoly.
d. oligopolistic competition.
e. monopolistic competition.
Q3. During which period did mass production reduce duplication of equipment and allow firms
to purchase raw materials at better prices?
a. Colonial Period
b. Industrial Revolution
c. Entrepreneurial Era
d. Production Era
e. Marketing Era
Q4. The Marketing Era saw the advance of the marketing concept. Which of the following does
NOT reflect the thinking behind the marketing concept?
a. The customer is the most important element.
b. A wide array of products should be offered.
c. Producers should find out what the customer wants.
d. Producers should decide what the customer needs.
e. Producers should provide what the customer wants.
Q5. In reality, most countries rely on some form of __________ economy.
a. operation
b. market
c. planned
d. mixed market
e. private
Q6. An industry in which one firm can most efficiently supply all the demand is _______.
a. an illegal monopoly
b. a natural oligopoly
c. a natural monopoly
d. a legal oligopoly
e. a controlled oligopoly
Q7. Of the following periods, which came first?
a. Entrepreneurial Era
b. Industrial Revolution
c. Global Era
d. Marketing Era
e. Production Era
Q8. Technological advances, improved communication, and more efficient transportation
networks contributed to the emergence of the
a. Global Era.
b. Industrial Revolution.
c. Entrepreneurial Era.
d. Production Era.
e. Marketing Era.
Q9. When identifying the factors of product, the term _____________ may also be used to refer
to labor.
a. management resources
b. entrepreneurs
c. human resources
d. production resources
e. contract resources
Q10. Which of the following eras was prompted by increased consumer demand after World
War II?
a. Global Era
b. Industrial Revolution
c. Entrepreneurial Era
d. Production Era
e. Marketing Era
Solution
As per the rule, I am required to answer first four questions only.
Entrepreneur is the person who arrange all the required resources, put them on the work, accepts
risks and opportunities and operates new business. He is the first promoter of the business and
gives life to his ideas and thoughts.
2. Option B is correct.
Prior to deregulation, the market for electricity in California was like a monopoly. There were
only one or two firms and they used to charge very high prices from their customers.
3.Option B is correct.
Mass production was started many years before industrial revolution. But it the industrial
revolution era wherein mass production reduced the duplication of equipment and allowed firms
to purchase raw materials in bulk and at cheaper rates.
4.Option B is correct.
Marketing concept considers consumer i.
Question 3 (24 markS) Westcock Shipbuilding Ltd. has a December 31 y.pdf
Question 3: (24 markS) Westcock Shipbuilding Ltd. has a December 31 year end. On January 1,
2017, the company had the following shareholder\'s equity accounts Preferred shares, $4 non-
cumulative, unlimited number authorized, 7,000 issued Common shares, unlimited number
authorized, 150,000 issued Retained earnings Accumulated Other Comprehensive Income
$850,000 2,250,000 1,750,000 22,000 Westcock Shipbuilding Ltd. had the following
transactions during 2017: Issued 700 preferred shares at $95 per share. Reacquired 5,000
common shares at $16 a share. Announced a 3-for-1 stock split of the common shares.
Immediately before the split, the share price was $13 a share. Declared the annual dividend on
preferred shares for the shareholders of record on Sep 30, payable on Oct 15 Declared a common
share dividend of $0.50 a share for all shareholders of record Nov 30. The dividend is payable on
Dec 15 Jan 31 Mar 2 Jun 28 Sep 15 Oct 31 The company reported a profit of $450,000 and other
comprehensive income of $15,000 for 2017. Required: a) Prepare journal entries to record all of
the transactions b) Prepare the Statement of Changes in Shareholder\'s Equity (HINTS: (a) Use
format similar to that shown in Illustration 14-10 on page 747 in the textbook; (b) you will need
a column for Preferred shares instead of Contributed Surplus)
Solution
Journal Entries
Date
Particulars
Debit
Credit
31-Jan
Cash
$66,500.00
Preferred Shares
$66,500.00
Preferred Shares being issued
2-Mar
Cash
$80,000.00
Treasury stock
$80,000.00
Common stocks being repurchased
28-Jun
No entry required, since stocks do not have any par value
15-Sep
Dividends - Preferred
$30,800.00
Dividends Payable - Preferred
$30,800.00
Preferred dividends at $4 per dividend being declared
30-Sep
Dividends Payable - Preferred
$30,800.00
Cash
$30,800.00
Preferred dividends declared being paid
31-Oct
Dividends - Common
$217,500.00
Dividends Payable - Common
$217,500.00
Common stock dividends being declared
15-Dec
Dividends Payable - Common
$217,500.00
Cash
$217,500.00
Common dividends declared being paid
Dividends payable – Preferred = (7,000 + 700) x $4 = $30,800
Dividends payable – Common = (150,000 – 5,000) x $0.50 = $217,500
Stocks repurchased at $16 = 5,000 x $16 = $80,000
Statement of Changes in Shareholders\' Equity
Year ended on December 31, 2017
Preferred Share Capital
Common Share Capital
Treasury Shares
Retained Earnings
Accumulated Other Comprehensive Income
Total Equity
Balance at January 1, 2017
$850,000
$2,250,000
$0
$1,750,000
$22,000
$4,872,000
Profit for the year
$0
$0
$0
$450,000
$0
$450,000
Other Comprehensive Income
$0
$0
$0
$0
$15,000
$15,000
Dividends - Preferred
$0
$0
$0
$30,800
$0
$30,800
Dividends - Common
$0
$0
$0
$217,500
$0
$217,500
Purchase of Own Shares
$0
$0
$80,000
($80,000)
$0
$0
Balance at December 31, 2017
$850,000
$2,250,000
$80,000
$2,368,300
$37,000
$5,585,300
Journal Entries
Date
Particulars
Debit
Credit
31-Jan
Cash
$66,500.00
Preferred Shares
$66,500.00
Preferred Shar.
Place the following formulas in their proper order A. ALE, residu.pdf
Place the following formulas in their proper order:
A. ALE, residual risk, SLE, ARO
B. ALE, ARO, SLE, residual risk
C. ARO, SLE, ALE, residual risk
D. SLE, ARO, ALE, residual risk
Solution
D. The quantitative assessment process involves the following steps: Estimate potential losses
(SLE), conduct a threat analysis (ARO), determine annual loss expectancy (ALE), and determine
the residual risk after a countermeasure has been applied..
please help i have 40 minsItem 1In the case below, the original .pdf
please help i have 40 mins
Item 1
In the case below, the original source material is given along with a sample of student work.
Determine the type of plagiarism by clicking the appropriate radio button.
Original Source Material
Student Version
There is a design methodology called rapid prototyping, which has been used successfully in
software engineering. Given similarities between software design and instructional design, we
argue that rapid prototyping is a viable method for instructional design, especially for computer-
based instruction.
References:
Tripp, S. D., & Bichelmeyer, B. A. (1990). Rapid prototyping: An alternative instructional
design strategy. Educational Technology Research and Development, 38(1), 31-44.
Tripp and Bichelmeyer (1990) suggested that rapid prototyping could be an advantageous
methodology for developing innovative computer-based instruction. They noted that this
approach has been used successfully in software engineering; hence, rapid prototyping could also
be a viable method for instructional design due to many parallels between software design and
instructional design.
References:
Tripp, S. D., & Bichelmeyer, B. A. (1990). Rapid prototyping: An alternative instructional
design strategy. Educational Technology Research and Development, 38(1), 31-44.
Which of the following is true for the Student Version above?
Word-for-Word plagiarism
Paraphrasing plagiarism
This is not plagiarism
Hints
Item 2
In the case below, the original source material is given along with a sample of student work.
Determine the type of plagiarism by clicking the appropriate radio button.
Original Source Material
Student Version
Learning is a complex set of processes that may vary according to the developmental level of the
learner, the nature of the task, and the context in which the learning is to occur. As already
indicated, no one theory can capture all the variables involved in learning.
References:
Gredler, M. E. (2001). Learning and instruction: Theory into practice (4th Ed.). Upper Saddle,
NJ: Prentice-Hall.
A learning theory, there, comprises a set of constructs linking observed changes in performance
with what is thought to bring about those changes.
References:
Driscoll, M. P. (2000). Psychology of learning for instruction (2nd Ed.). Needham Heights, MA:
Allyn & Bacon.
A learning theory is made up of a set of constructs linking observed changes in performance with
whatever is thought to bring about those changes. Therefore since learning is a complex set of
processes that may vary according to the developmental level of the learner, the nature of the
task, and the context in which the learning is to occur, it is apparent that no one theory can
capture all the variables involved in learning.
Which of the following is true for the Student Version above?
Word-for-Word plagiarism
Paraphrasing plagiarism
This is not plagiarism
Hints
Item 3
In the case below, the original source material is given along with a sample of student work.
Det.
Non-Euclidean GeometryWhat statement, if any, can be made about th.pdf
Non-Euclidean Geometry
What statement, if any, can be made about the summit and base in a quadrilateral whose
opposites sides lie on parallel lines?
Solution
If the opposite sides of a quadrilateral lie on parallel lines then the quadrilateral can satisfy the
possibility of being a parallelogram, rhombus, square , rectangle or trapezium because in all
these quadrilaterals have the property where opposite sides are parallel..
Java ProgrammingA Swing button can have more than one action liste.pdf
Java Programming
A Swing button can have more than one action listener.
is this True or False?
Solution
Answer: False
A Swing button can have only one action listener and one action event. these are ActionListener
and ActionEvent respectively.
We can handle that action by using beow method that is provided by ActionListner.
public void actionPerformed(ActionEvent e){
}.
JAVA Write a class called F.pdf
*****************JAVA********************** Write a class called Fraction, which can
be used to store an exact fraction. It must have: - A field to store the numerator - A
field to store the denominator - A toString method that returns a neatly formatted String
representing the fraction - An equals method that compares itself to another Fraction -
An add method that adds itself to another Fraction and returns a new Fraction - Appropriate
constructor and accessors as needed Write a program that asks the user to enter the numerators
and denominators of two fractions and create corresponding Fraction objects. Check for valid
input and a 0 denominator. Then output both Fractions (using your toString method implicitly),
whether they are equal, and their sum. Name your main class Hw6pr2 and your file
Hw6pr2.java. Submit all .java files
Solution
import java.util.*;
import java.io.*;
public class Fraction
{
static Scanner console = new Scanner(System.in);
public static void main(String[] args);
private int numerator;
private int denominator;
System.out.println(\"Enter the denominator\");
System.out.flush();
while(console.hasNext())
{
denominator = console.nextInt();
public String toString()
{
return (numerator + \" / \" + denominator);
}
public boolean equals(Fraction rightFr)
{
return(numerator * rightFr.denominator == denominator * rightFr.numerator);
}
public int compareTo(Fraction rightFr)
{
return(numerator * rightFr.denominator-denominator * rightFr.numerator);
}
public Fraction(int num, int deno) throws Exception
{
numerator = num;
if(deno == 0)
throw new Exception(\"denominator cannot be zero\");
else
denominator = deno;
}
public Fraction()
{
numerator = 0;
denominator = 1;
}
public void setFraction(int num, int deno) throws Exception
{
numerator = num;
if(deno == 0)
throw new Exception(\"denominator cannot be zero\");
else
denominator = deno;
}
public Fraction add(Fraction rightFr)
{
Fraction temp = new Fraction();
temp.numerator = numerator * rightFr.denominator + rightFr.numerator * denominator;
temp.denominator = denominator * rightFr.denominatior;
return temp;
}
public Fraction multiply(Fraction rightFr)
{
Fraction temp = new Fraction();
temp.numerator = numerator * rightFr.numerator;
temp.denominator = denominator * rightFr.denominator;
return temp;
}
public Fraction subtract(Fraction rightFr)
{
Fraction temp = new Fraction();
temp.numerator = numerator * rightFr. denominator-rightFr.numerator * denominator;
temp.denominator = denominator * rightFr.denominator;
retrun temp;
}
Fraction divide(Fraction rightFr) throws Exception
{
Fraction temp = new Fraction();
if(rightFr.numerator == 0)
throw new Exception(\"Cannot divide by zero\");
else{
temp.numerator = numerator * rightFr.denominator;
temp.denominator = rightFr.numerator *denominator;
return temp;
}
System.out.println(\" \");
System.out.println(\" \" +(numerator + denominator));
}
}.
In the adult, red bone marrow would normally be found in the sternu.pdf
In the adult, red bone marrow would normally be found in the: sternum diaphysis of the femur.
diaphysis of the humerus. medullary cavity of most long bones. choices A, B, and C.
Solution
in the adults normally the red bone marrow is found in the flat bones such as the sternum and
pelvic girdle femur and the humerus so the correct option is \"E\"..
I need help with these two questions 4.12 and 4.13 dealing with MATL.pdf
I need help with these two questions 4.12 and 4.13 dealing with MATLAB. Thank you in
advance.
Solution
clear all;
bigBal=2*10^5;
endBal=bigBal;
i=1;
payment=1199.11;
while endBal>0
A(i)=endBal*(1+0.5/100);
B(i)=payment;
C(i)=A(i)-B(i);
endBal=C(i);
i=i+1;
end
fileID = fopen(\'exp.txt\',\'w\');
x=1:1:(i-1);
M=[x; A; B; C];
fprintf(fileID,\'%4s %12s %12s %12s\ \',\'month\',\'Beg Balance\',\'payment\', \'end Balance\');
fprintf(fileID,\'%6.2f %12.2f %8.2f %6.2f\ \',M);
type exp.txt
if endBal<0
fprintf(\' Final balance amount to be refunded is: %f\', -endBal);
end
%out put
month Beg Balance payment end Balance
1.00 201000.00 1199.11 199800.89
2.00 200799.89 1199.11 199600.78
3.00 200598.79 1199.11 199399.68
4.00 200396.68 1199.11 199197.57
5.00 200193.55 1199.11 198994.44
6.00 199989.42 1199.11 198790.31
7.00 199784.26 1199.11 198585.15
8.00 199578.07 1199.11 198378.96
9.00 199370.86 1199.11 198171.75
10.00 199162.61 1199.11 197963.50
11.00 198953.32 1199.11 197754.21
12.00 198742.98 1199.11 197543.87
13.00 198531.59 1199.11 197332.48
14.00 198319.14 1199.11 197120.03
15.00 198105.63 1199.11 196906.52
16.00 197891.05 1199.11 196691.94
17.00 197675.40 1199.11 196476.29
18.00 197458.67 1199.11 196259.56
19.00 197240.86 1199.11 196041.75
20.00 197021.96 1199.11 195822.85
21.00 196801.96 1199.11 195602.85
22.00 196580.87 1199.11 195381.76
23.00 196358.67 1199.11 195159.56
24.00 196135.35 1199.11 194936.24
25.00 195910.92 1199.11 194711.81
26.00 195685.37 1199.11 194486.26
27.00 195458.70 1199.11 194259.59
28.00 195230.88 1199.11 194031.77
29.00 195001.93 1199.11 193802.82
30.00 194771.84 1199.11 193572.73
31.00 194540.59 1199.11 193341.48
32.00 194308.19 1199.11 193109.08
33.00 194074.62 1199.11 192875.51
34.00 193839.89 1199.11 192640.78
35.00 193603.98 1199.11 192404.87
36.00 193366.90 1199.11 192167.79
37.00 193128.63 1199.11 191929.52
38.00 192889.16 1199.11 191690.05
39.00 192648.50 1199.11 191449.39
40.00 192406.64 1199.11 191207.53
41.00 192163.57 1199.11 190964.46
42.00 191919.28 1199.11 190720.17
43.00 191673.77 1199.11 190474.66
44.00 191427.04 1199.11 190227.93
45.00 191179.07 1199.11 189979.96
46.00 190929.86 1199.11 189730.75
47.00 190679.40 1199.11 189480.29
48.00 190427.69 1199.11 189228.58
49.00 190174.72 1199.11 188975.61
50.00 189920.49 1199.11 188721.38
51.00 189664.99 1199.11 188465.88
52.00 189408.21 1199.11 188209.10
53.00 189150.14 1199.11 187951.03
54.00 188890.79 1199.11 187691.68
55.00 188630.14 1199.11 187431.03
56.00 188368.18 1199.11 187169.07
57.00 188104.92 1199.11 186905.81
58.00 187840.34 1199.11 186641.23
59.00 187574.43 1199.11 186375.32
60.00 187307.20 1199.11 186108.09
61.00 187038.63 1199.11 185839.52
62.00 186768.72 1199.11 185569.61
63.00 186497.46 1199.11 185298.35
64.00 186224.84 1199.11 185025.73
65.00 185950.86 1199.11 184751.75
66.00 185675.50 1199.11 184476.39
67.00 185398.78 1199.11 184199.67
68.00 185120.66 1199.11 183921.55
69.00 184841.16 1199.11 183642.05
70.00 184560.26 1199.11 183361.15
71.00 18427.
I dont understand the min and max Find the smallest positive value.pdf
I don\'t understand the min and max Find the smallest positive value of t for which f(t) = 5 sin (t
- pi/4). is the following. f(t) is zero. f(t)- attains a maximum. f(t) attains a minimum value.
Solution
we know that sine function attains maximum at pi/2 for first time and minimum at pifor first
time.
so, argument is x- pi/4
for maximunum x-pi/4 = pi/2
x = 3pi/4
for minimum, x-pi/4 = pi
x = 5pi/4
zero when x-pi/4 = 0
x = pi/4.
How can the activation of effector molecules within cells be restric.pdf
How can the activation of effector molecules within cells be restricted to subcellular localities?
Solution
The effector proteins can be transported to subcellular localities through specialised protein
secretion systems carried by bacteria which infect the host organism. These systems carry out
precise localization of the effector molecules into the host cell thereby enahancing their
effectiveness..
Explain how the skin of reptiles adaptive for terrestial existence. .pdf
Explain how the skin of reptiles adaptive for terrestial existence. (Is your skin also adaptive for a
terrestial existence?)
Solution
Reptiles posess many adaptations that permits them to live in dry conditions. One of the
important adaptation of reptiles is their skin.
Reptiles have dry, cornified skin without glands and with scales. The thick, scaly skin helps
conserve water inside their bodies and prevent water loss. This is an essential feature that helps
them survive not only on land, but in dry, desert areas as well. The skin functions as water proof
cover to conserve water inside, so they do not feel the need of water unlike other animals. This
important adaptation has helped reptiles to survive in terestrial habitats..
Distinguish the roles of the four economic actors in economicsSo.pdf
Distinguish the roles of the four economic actors in economics
Solution
Following are the four economic actors:
Consumer: Consumer buys the goods and service. He seeks to maximizes his utility. Consumer
is regarded as rational consumer.
Worker: Worker is most important human resource. worker provides the important service in the
form of labor.
Firm: firm seeks to maximizes its own profit. Like Microsoft tries to sell more software to earn
more profits.
Government. Govt aims to maximize the welfare of its citizens..
Explain the term liquidity and how it relates to the classified bala.pdf
Explain the term liquidity and how it relates to the classified balance sheet. Why is it important
to classify accounts in order of their liquidity?
Solution
Liquidity means the cash conversion/equivalent value of the asset.
The liquidity relates to the balance sheet towards the presentation of assets in order of their
liquidity in the assets column in the balance sheet and in the order of the amount of time the asset
would usually take to convert them into cash. Thus, in the defined cash is always presented first
and then followed by other assets like marketable securities, accounts receivable, inventory,
fixed assets and at the last the goodwill.
The importance of presentation of the balance sheet in order of the liquidity nature of the assets
is that the management and other user of the balance sheet would able to know how the firm is
performing in terms of liquidity and in case of emergency will the firm will able to convert its
assets into cash. It will provide confidence to the creditors towards the firm not going into
liquidation and their investment is safe.
=====================.
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Azure Interview Questions and Answers PDF By ScholarHat
Need help writing Conways Game of Life. These are the instructions.pdf
- 1. Need help writing Conway's Game of Life. These are the instructions: The game of Life is intended to model life in a society of organisms. Consider a rectangular array of cells, each of which may contain an organism. If the array is considered to extend indefinitely in both directions, then each cell has eight neighbors, the eight cells surrounding it. Births and deaths occur according to the following rules: An organism is born in any empty cell having exactly three neighbors. An organism dies from isolation if it has fewer than two neighbors. An organism dies from overcrowding if it has more than three neighbors. All other organisms survive to the next generation. Write a program to play the game of Life and investigate the patterns produced by various initial configurations. Some configurations die off rather rapidly; others repeat after a certain number of generations; others change shape and size and may move across the array. NOTE: For representing each organism, use "@" characters. For an array of cells, use 30x30 two-dimensional array. Each generation should be displayed on the screen and should be paused. (You can use cin.get( ) library function to pause running your program.) 4. The source file should be called life.cpp 5. All assignments are expected to be INDIVIDUAL work. All work handed in must be original. Duplicate or very similar programs receive zero points. Input A set of initial cells will be given using the interactive way using a keyboard. The followings are the prompt for the input: Please Enter the number of initial cells: 4 The position of cell is 10 10 The position of cell is 10 11 The position of cell is 10 12 The position of cell is 11 11 How many generations do you want to display? 3 Output The program then display each generation of organisms at a time. The 1-generation @@@ @ Press any key to continue!!
- 2. (This picture should be displayed on the new screen.) The 2-generation @ @@@ @@@ Press any key to continue!! The 3-generation @@@ @ @ @ Do you want to do it again?(Yes/No) N Solution Note: User given template is used. Answer: #include #include #include #include #include using namespace std; int orAry[30][30]; void initilaize() { for(int kk=0;kk<30;kk++) { for(int bb=0;bb<30;bb++) { orAry[kk][bb]=0; } } } void disply() {
- 3. cout<=0 ) { cc++; } if( orAry[kk+1][aa-1]==1 && kk+1<30 && aa-1>=0) { cc++; } if( orAry[kk+1][aa]==1 && kk+1<30) { cc++; } if( orAry[kk][aa+1]==1 && aa+1<30) { cc++; } if( orAry[kk-1][aa-1]==1 && kk-1>=0 && aa-1>=0) { cc++; } if(orAry[kk+1][aa+1]==1 && kk+1<30 && aa+1<30) { cc++; } if(orAry[kk-1][aa]==1 && kk-1>=0) { cc++; } if( orAry[kk-1][aa+1]==1 && kk-1>=0 && aa+1<30) { cc++; } return cc; } void runLife()
- 4. { int bCnt=0; int dCnt=0; for(int kk=0;kk<30;kk++) { for(int bb=0;bb<30;bb++) { if(orAry[kk][bb]==0) { bCnt=ChechNeighBourCount(kk,bb); if(bCnt==3) { orAry[kk][bb]=1; } } else if(orAry[kk][bb]==1) { dCnt=ChechNeighBourCount(kk,bb); if(dCnt>3) { orAry[kk][bb]=0; } if(dCnt<2) { orAry[kk][bb]=0; } } } } } int main() { int rr,cc;
- 5. int npos=0; int ngen=0; int xv,yv; char re; srand(time(NULL)); do { initilaize(); cout<<"Please Enter the number of initial cells:"; cin>>npos; for(int kk=0;kk>xv>>yv; if(orAry[xv][yv]==0) { orAry[xv][yv]=1; } } cout<<"How many generations do you want to display?"; cin>>ngen; for(int kk=0;kk>re; }while(re!='N'); return 0; } Sample Output: Please Enter the number of initial cells:4 The position of cell is 10 10 The position of cell is 10 11 The position of cell is 10 12 The position of cell is 11 11 How many generations do you want to display?3 1 - generation
- 6. @@@ @ Press any key to continue 2 - generation
- 7. @@ @ @ @ Press any key to continue 3 - generation
- 8. @@ @ @ @ Press any key to continue Do you want to do it again?(Yes/No) N Exit code: 0 (normal program termination)