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moles of NH3 = 34/17 = 2 moles of O2 = 40/32 = 1.25 Thus, L.R. = O2 So, 2.5 moles or 45 g H2O d. 45.0 Solution moles of NH3 = 34/17 = 2 moles of O2 = 40/32 = 1.25 Thus, L.R. = O2 So, 2.5 moles or 45 g H2O d. 45.0.

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moles of NH3 = 34/17 = 2 moles of O2 = 40/32 = 1.25 Thus, L.R. = O2 So, 2.5 moles or 45 g H2O d. 45.0 Solution moles of NH3 = 34/17 = 2 moles of O2 = 40/32 = 1.25 Thus, L.R. = O2 So, 2.5 moles or 45 g H2O d. 45.0

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moles of NH3 = 3417 = 2 moles of O2 = 4032 = 1..pdf

  • 1. moles of NH3 = 34/17 = 2 moles of O2 = 40/32 = 1.25 Thus, L.R. = O2 So, 2.5 moles or 45 g H2O d. 45.0 Solution moles of NH3 = 34/17 = 2 moles of O2 = 40/32 = 1.25 Thus, L.R. = O2 So, 2.5 moles or 45 g H2O d. 45.0