Vedic Maths has a lot of usage in today's world. It
makes maths very simple using some tricks and makes
maths fun.
Trick of Multiplying a
number by 11
 We all know the trick when multiplying by ten – add 0
to the end of the number, but did you know there is an
equally easy trick for multiplying a two digit number
by 11? This is it:
Take the original number and imagine a space between
the two digits (in this example we will use 52:
5_2
Now add the two numbers together and put them in the
middle:
5_(5+2)_2
That is it – you have the answer: 572.
Exceptions………..
 Please Note – If the numbers in the middle add up
to a 2 digit number, just insert the second number
and add 1 to the first:
 9_(9+9)_9
 (9+1)_8_9
 10_8_9
 1089 – It works every time.
Calculate reminder on dividing the
number by 27 and 37
Let me explain this rule by taking examples
consider number 34568276, we have to calculate
the reminder on diving this number by 27 and 37
respectively.
make triplets as written below starting from units
place
34.........568..........276
now sum of all triplets = 34+568+276 = 878
divide it by 27 we get reminder as 14
divide it by 37 we get reminder as 27
Examples………………..
Example.
Other examples for the clarification of the rule
let the number is 2387850765
triplets are 2...387...850...765
sum of the triplets = 2+387+850+765 = 2004
on revising the steps we get
2......004
sum = 6
divide it by 27 we get reminder as 6
divide it by 37 we get reminder as 6
Dividing any number by 9
To find the remainder of
a number after dividing
it by 9…
1) Write the first digit
itself then add the
next digit by the first
no. and then their
sum by the third digit
and so on…..
2) Note if asum exceeds
10 or is 10 then carry
forward 1 to the
preceeding digit
Multiplying 2 numbers close to
100
 This formula can be very
effectively applied in
multiplication of
numbers, which are
nearer to bases like 10,
100, 1000 i.e., to the
powers of 10 (eg: 96 x 98
or 102 x 104).
 It can also be used for
base numbers such as
50
Case I :
When both the numbers are lower
than the base.
 Conventional
Method
97 X 94
9 7
X 9 4
3 8 8
8 7 3 X
9 1 1 8
 Vedic Method
97 3
X 94 6
9 1 1 8
Case ( ii) : When both the
numbers are higher than the
base
 Conventional
Method
103 X 105
103
X 105
5 1 5
0 0 0 X
1 0 3 X X
1 0, 8 1 5
 Vedic Method
For Example103 X 105
103 3
X 105 5
1 0, 8 1 5
Case III: When one number is more
and the other is less than the base.
 Conventional Method
103 X 98
103
X 98
8 2 4
9 2 7 X
1 0, 0 9 4
 Vedic Method
103 +3
X 98 -2
1 0, 0 9 4
Square of any 2 digit number
Let me explain this trick by taking examples
67^2 = [6^2][7^2]+20*6*7 = 3649+840 = 4489
similarly
25^2 = [2^2][5^2]+20*2*5 = 425+200 = 625
Take one more example
97^2 = [9^2][7^2]+20*9*7 = 8149+1260 = 9409
Here [] is not an operation, it is only a separation
between initial 2 and last 2 digits
Example.
Here an extra case arises
Consider the following examples for that
91^2 = [9^2][1^2]+20*9*1 = 8101+180 = 8281
Multiplication of 2 two-digit numbers where the
first digit of both the numbers are same and the
last digit of the two numbers sum to 10 (You
cannot use this rule for other numbers)
 Let me explain this rule by taking examples
To calculate 56*54:
Multiply 5 by 5+1. So, 5*6 = 30. Write down 30.
Multiply together the last digits: 6*4 = 24. Write
down 24.
The product of 56 and 54 is thus 3024.
 Example.
Understand the rule by 1 more example
78*72 = [7*(7+1)][8*2] = 5616
Thank You
By Akashdeep Ramnaney

Maths tricks -1

  • 1.
    Vedic Maths hasa lot of usage in today's world. It makes maths very simple using some tricks and makes maths fun.
  • 2.
    Trick of Multiplyinga number by 11  We all know the trick when multiplying by ten – add 0 to the end of the number, but did you know there is an equally easy trick for multiplying a two digit number by 11? This is it: Take the original number and imagine a space between the two digits (in this example we will use 52: 5_2 Now add the two numbers together and put them in the middle: 5_(5+2)_2 That is it – you have the answer: 572.
  • 3.
    Exceptions………..  Please Note– If the numbers in the middle add up to a 2 digit number, just insert the second number and add 1 to the first:  9_(9+9)_9  (9+1)_8_9  10_8_9  1089 – It works every time.
  • 4.
    Calculate reminder ondividing the number by 27 and 37 Let me explain this rule by taking examples consider number 34568276, we have to calculate the reminder on diving this number by 27 and 37 respectively. make triplets as written below starting from units place 34.........568..........276 now sum of all triplets = 34+568+276 = 878 divide it by 27 we get reminder as 14 divide it by 37 we get reminder as 27
  • 5.
    Examples……………….. Example. Other examples forthe clarification of the rule let the number is 2387850765 triplets are 2...387...850...765 sum of the triplets = 2+387+850+765 = 2004 on revising the steps we get 2......004 sum = 6 divide it by 27 we get reminder as 6 divide it by 37 we get reminder as 6
  • 6.
    Dividing any numberby 9 To find the remainder of a number after dividing it by 9… 1) Write the first digit itself then add the next digit by the first no. and then their sum by the third digit and so on….. 2) Note if asum exceeds 10 or is 10 then carry forward 1 to the preceeding digit
  • 7.
    Multiplying 2 numbersclose to 100  This formula can be very effectively applied in multiplication of numbers, which are nearer to bases like 10, 100, 1000 i.e., to the powers of 10 (eg: 96 x 98 or 102 x 104).  It can also be used for base numbers such as 50
  • 8.
    Case I : Whenboth the numbers are lower than the base.  Conventional Method 97 X 94 9 7 X 9 4 3 8 8 8 7 3 X 9 1 1 8  Vedic Method 97 3 X 94 6 9 1 1 8
  • 9.
    Case ( ii): When both the numbers are higher than the base  Conventional Method 103 X 105 103 X 105 5 1 5 0 0 0 X 1 0 3 X X 1 0, 8 1 5  Vedic Method For Example103 X 105 103 3 X 105 5 1 0, 8 1 5
  • 10.
    Case III: Whenone number is more and the other is less than the base.  Conventional Method 103 X 98 103 X 98 8 2 4 9 2 7 X 1 0, 0 9 4  Vedic Method 103 +3 X 98 -2 1 0, 0 9 4
  • 11.
    Square of any2 digit number Let me explain this trick by taking examples 67^2 = [6^2][7^2]+20*6*7 = 3649+840 = 4489 similarly 25^2 = [2^2][5^2]+20*2*5 = 425+200 = 625 Take one more example 97^2 = [9^2][7^2]+20*9*7 = 8149+1260 = 9409 Here [] is not an operation, it is only a separation between initial 2 and last 2 digits Example. Here an extra case arises Consider the following examples for that 91^2 = [9^2][1^2]+20*9*1 = 8101+180 = 8281
  • 12.
    Multiplication of 2two-digit numbers where the first digit of both the numbers are same and the last digit of the two numbers sum to 10 (You cannot use this rule for other numbers)  Let me explain this rule by taking examples To calculate 56*54: Multiply 5 by 5+1. So, 5*6 = 30. Write down 30. Multiply together the last digits: 6*4 = 24. Write down 24. The product of 56 and 54 is thus 3024.  Example. Understand the rule by 1 more example 78*72 = [7*(7+1)][8*2] = 5616
  • 13.