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MATHEMATICS OF FINANCE 
Compound Interest & Compound Discount
Compound Interest 
P = Principal at the beginning of the first interest period. 
i = Interest rate per conversion period. 
P P(1+i) P(1+i)2 
P(1+i)3 P(1+i)4 
0 1 2 3 4 5 
Interest due = Pi 
Accumulated value = P + Pi 
= P(1+i) 
Interest due = (P(1+i))i 
Accumulated value = P(1+i) + 
(P(1+i))i 
= P(1+i)2 
Interest due = (P(1+i)2)i 
Accumulated value = P(1+i)2 + 
(P(1+i)2)i 
= P(1+i)3
Compound Interest 
S = P(1+i)n 
S = Accumulated value of P at the end of n interest periods. 
(1+i)n = Accumulation factor 
The accumulated value S of principal P at rate jm for t years is 
S = P(1+i)n = P(1+jm/m)mt = P[(1+jm/m)m]t
Compound Interest 
Find the compound interest on $1000 for 2 years at 12% 
compound semiannually. 
At the end of period Interest Accumulated value 
1 1000(0.12/2) = 60 1060 
2 1060(0.12/2) = 63.6 1123.6 
3 1123.6(0.12/2) = 67.416 1191.016 
4 1191.016(0.12/2) = 71.46096 1262.47696 
The compound interest is 1262.47696 – 1000 = 262.47696 
S = P[(1+jm/m)m]t = 1000[(1+0.12/2)2]2 = 1000[(1.06)2]2 
= 1000(1.06)4 = 1262.47696
Compound Interest 
Find the compound interest on $1000 for 2 years at 12% 
compound semiannually. 
S = P[(1+jm/m)m]t 
P = 1000, jm = j2 = 0.12, m = 2, t = 2 
= 1000[(1+0.12/2)2]2 = 1000[(1.06)2]2 
= 1000(1.06)4 = 1262.47696 
The compound interest is 1262.47696 – 1000 = 262.47696
Discounted value 
P = S(1+i)-n 
P = S[(1+jm/m)-m]t 
P = Discounted value of S (Present value of S) 
(1+i)-n , [(1+jm/m)-m]t = Discounted factor
Compound Interest 
Find the present value of $8000 due in 5 years at 7% 
compounded quaterly. 
P = S[(1+jm/m)-m]t 
S = 8000, jm = j4 = 0.07, m = 4, t = 5 
= 8000[(1+0.07/4)-4]5 = 8000[(1.0175)-4]5 
= 8000(1.0175)-20 = 5654.60

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คณิตศาสตร์การเงิน - Compound interest & Compound discount

  • 1. MATHEMATICS OF FINANCE Compound Interest & Compound Discount
  • 2. Compound Interest P = Principal at the beginning of the first interest period. i = Interest rate per conversion period. P P(1+i) P(1+i)2 P(1+i)3 P(1+i)4 0 1 2 3 4 5 Interest due = Pi Accumulated value = P + Pi = P(1+i) Interest due = (P(1+i))i Accumulated value = P(1+i) + (P(1+i))i = P(1+i)2 Interest due = (P(1+i)2)i Accumulated value = P(1+i)2 + (P(1+i)2)i = P(1+i)3
  • 3. Compound Interest S = P(1+i)n S = Accumulated value of P at the end of n interest periods. (1+i)n = Accumulation factor The accumulated value S of principal P at rate jm for t years is S = P(1+i)n = P(1+jm/m)mt = P[(1+jm/m)m]t
  • 4. Compound Interest Find the compound interest on $1000 for 2 years at 12% compound semiannually. At the end of period Interest Accumulated value 1 1000(0.12/2) = 60 1060 2 1060(0.12/2) = 63.6 1123.6 3 1123.6(0.12/2) = 67.416 1191.016 4 1191.016(0.12/2) = 71.46096 1262.47696 The compound interest is 1262.47696 – 1000 = 262.47696 S = P[(1+jm/m)m]t = 1000[(1+0.12/2)2]2 = 1000[(1.06)2]2 = 1000(1.06)4 = 1262.47696
  • 5. Compound Interest Find the compound interest on $1000 for 2 years at 12% compound semiannually. S = P[(1+jm/m)m]t P = 1000, jm = j2 = 0.12, m = 2, t = 2 = 1000[(1+0.12/2)2]2 = 1000[(1.06)2]2 = 1000(1.06)4 = 1262.47696 The compound interest is 1262.47696 – 1000 = 262.47696
  • 6. Discounted value P = S(1+i)-n P = S[(1+jm/m)-m]t P = Discounted value of S (Present value of S) (1+i)-n , [(1+jm/m)-m]t = Discounted factor
  • 7. Compound Interest Find the present value of $8000 due in 5 years at 7% compounded quaterly. P = S[(1+jm/m)-m]t S = 8000, jm = j4 = 0.07, m = 4, t = 5 = 8000[(1+0.07/4)-4]5 = 8000[(1.0175)-4]5 = 8000(1.0175)-20 = 5654.60