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ACCUMULATION OF MONEY 
DISCOUNTING PROBLEM 
NOMINAL AND EFFECTIVE RATES
ACCUMULATION OF MONEY 
 P = principal amount of the loan or 
investment 
 i = periodic interest rate 
 n = Time period (term) of the loan or 
investment 
 F = Maturity value of the loan or 
investment 
 I = Amount of interest paid or received
COMPUTATION OF PERIODIC 
RATE AND TIME 
•i = Given rate / given 
time 
•n = number of times per year 
this rate is compounded/ given 
year
FORMULA 
 F = P ( 1 + i )n 
 P = F 
( 1 + i )n 
 I = F - P
EXAMPLE PROBLEM 
 Determine the amount 
due at the end of 8.1/2 
years if 10,000 is 
invested 5% 
compounded monthly .
• GIVEN : 
• P = 10,000 
• R = 5% COMPOUNDED MONTHLY 
• i = 5% 
• 12 
• n = ( 12 x 8.1/2 YEARS ) 102
• F = P ( 1 + i )n 
• F = 10,000 ( 1 + 0.05 )102 
• 12 
• F = 10,000 ( 1.528240 ) 
• F = 15,282.40 
• I = F – P 
• I = 15,282.40 – 10,000 
• I = 5,282.40
EXERCISE PROBLEM 
• Accumulate P50,000 for 
5.3/4 years at 8% 
compounded quarterly . 
Determine the compound 
interest earned
SOLUTION 
• GIVEN : 
• P =50,000 
• R= 8% compounded quarterly 
• i = 8/4 is 2% 
• n = 4 ( 5.3/4 years ) is 23
• F = P ( 1 + i )n 
• SOLUTION: 
• F = 50,000 ( 1 + 0.02 )23 
• F = 50,000 ( 1.576899 ) 
• F = 78,844.95 
• I = F-P 
• I = 78,844.95 – 50,000 
• I = 28,844.95 INTEREST 
EARNED
DISCOUNTING PROBLEM 
•P = F ( 1 + i )-n 
•I = F - P
TAKE NOTE 
 In Accumulation formula , the 
exponent is POSITIVE n ( +n) 
In Discounting formula , the 
exponent is NEGATIVE n ( -n)
EXAMPLE 
• If money is worth 6% 
compounded semi-annually 
determine the present value 
of 5,000 due at the end of 5 
years.
• GIVEN: 
• F = 5,000 
• R = 6% compounded semi-annually 
• i = 3% 
• n = ( 5x2 ) = 10
DISCOUTING FORMULA 
•P = F ( 1 + i )-n 
• P = 5,000 ( 1 + 0.03 )-10 
• P = 5,000 ( 0.744093 ) 
• P = 3,720.47
ACCUMULATION FORMULA 
P = F 
( 1 + i )n 
 P = 5,000 
( 1+ 0.03 )10 
 P = 5,000 
1.343916 
 P = 3,720.47
EXERCISE PROBLEM 
• Discount P50,000 pesos for 
20 years at 5% 
compounded semi-annually 
. Determine 
present value and discount 
earned.
• GIVEN : 
• F = 50,000 
• R = 5% compounded semi-annually 
• i = 2.5% 
• n = ( 20 x 2 ) 40
•P = F ( 1 + i )-n 
• P = 50,000 ( 1 + 0.025 )-40 
• P = 50,000 ( 0.372430 ) 
• P = 18,621.50 
• I = F- P 
• I = 50,000 – 18,621.50 
• I = 31,378.50 DISCOUNT EARNED
NOMINAL AND EFFECTIVE 
RATES 
• j = nominal rate 
• m = number of times per year this 
rate is compounded 
• i = j/m 
• w = if compounded annually , is 
equivalent to given rate ( effective 
rate )
FORMULA 
•w = ( 1 + j )m – 1 
m 
•1 + w = ( 1+ j )m 
m
EXAMPLE PROBLEM 
•What rate converted 
quarterly yields the 
effective rate 6 % ?
•GIVEN: 
•w = 6% 
•m = 4 
•j = ?
• 1 + w = ( 1+ j )m j = 4 ( 1.01467385 – 1 ) 
m 
• 1 + 0.06 = ( 1 + j )4 j = 4 ( 0.01467385 ) 
4 
• √( 1.06 )1 = 1 + j j = 0.0586 or 5.86% 
4 
• ( 1.06 )1/4 = 1 + j 
4 
• ( 1.06 )1/4 - 1 = j 
4 
• 4[( 1.06 )1/4 – 1 ] = j
QUIZ 
• 1. How much will be the compounded interest of 
P1,000 pesos is invested for one year at 6% 
compounded monthly? 
• 2. Discount P32,000 for 16.1/2 years at 8% 
compounded monthly. How much is the 
discount? 
• 3. How much should you invest today to provide 
your only son a brand new car worth P 
1,000,000 as a graduation gift 5 years from now 
if money is worth 6% compounded semi-annually?

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Accumulation of Money

  • 1. ACCUMULATION OF MONEY DISCOUNTING PROBLEM NOMINAL AND EFFECTIVE RATES
  • 2.
  • 3. ACCUMULATION OF MONEY  P = principal amount of the loan or investment  i = periodic interest rate  n = Time period (term) of the loan or investment  F = Maturity value of the loan or investment  I = Amount of interest paid or received
  • 4. COMPUTATION OF PERIODIC RATE AND TIME •i = Given rate / given time •n = number of times per year this rate is compounded/ given year
  • 5. FORMULA  F = P ( 1 + i )n  P = F ( 1 + i )n  I = F - P
  • 6. EXAMPLE PROBLEM  Determine the amount due at the end of 8.1/2 years if 10,000 is invested 5% compounded monthly .
  • 7. • GIVEN : • P = 10,000 • R = 5% COMPOUNDED MONTHLY • i = 5% • 12 • n = ( 12 x 8.1/2 YEARS ) 102
  • 8. • F = P ( 1 + i )n • F = 10,000 ( 1 + 0.05 )102 • 12 • F = 10,000 ( 1.528240 ) • F = 15,282.40 • I = F – P • I = 15,282.40 – 10,000 • I = 5,282.40
  • 9. EXERCISE PROBLEM • Accumulate P50,000 for 5.3/4 years at 8% compounded quarterly . Determine the compound interest earned
  • 10. SOLUTION • GIVEN : • P =50,000 • R= 8% compounded quarterly • i = 8/4 is 2% • n = 4 ( 5.3/4 years ) is 23
  • 11. • F = P ( 1 + i )n • SOLUTION: • F = 50,000 ( 1 + 0.02 )23 • F = 50,000 ( 1.576899 ) • F = 78,844.95 • I = F-P • I = 78,844.95 – 50,000 • I = 28,844.95 INTEREST EARNED
  • 12. DISCOUNTING PROBLEM •P = F ( 1 + i )-n •I = F - P
  • 13. TAKE NOTE  In Accumulation formula , the exponent is POSITIVE n ( +n) In Discounting formula , the exponent is NEGATIVE n ( -n)
  • 14. EXAMPLE • If money is worth 6% compounded semi-annually determine the present value of 5,000 due at the end of 5 years.
  • 15. • GIVEN: • F = 5,000 • R = 6% compounded semi-annually • i = 3% • n = ( 5x2 ) = 10
  • 16. DISCOUTING FORMULA •P = F ( 1 + i )-n • P = 5,000 ( 1 + 0.03 )-10 • P = 5,000 ( 0.744093 ) • P = 3,720.47
  • 17. ACCUMULATION FORMULA P = F ( 1 + i )n  P = 5,000 ( 1+ 0.03 )10  P = 5,000 1.343916  P = 3,720.47
  • 18. EXERCISE PROBLEM • Discount P50,000 pesos for 20 years at 5% compounded semi-annually . Determine present value and discount earned.
  • 19. • GIVEN : • F = 50,000 • R = 5% compounded semi-annually • i = 2.5% • n = ( 20 x 2 ) 40
  • 20. •P = F ( 1 + i )-n • P = 50,000 ( 1 + 0.025 )-40 • P = 50,000 ( 0.372430 ) • P = 18,621.50 • I = F- P • I = 50,000 – 18,621.50 • I = 31,378.50 DISCOUNT EARNED
  • 21. NOMINAL AND EFFECTIVE RATES • j = nominal rate • m = number of times per year this rate is compounded • i = j/m • w = if compounded annually , is equivalent to given rate ( effective rate )
  • 22. FORMULA •w = ( 1 + j )m – 1 m •1 + w = ( 1+ j )m m
  • 23. EXAMPLE PROBLEM •What rate converted quarterly yields the effective rate 6 % ?
  • 24. •GIVEN: •w = 6% •m = 4 •j = ?
  • 25. • 1 + w = ( 1+ j )m j = 4 ( 1.01467385 – 1 ) m • 1 + 0.06 = ( 1 + j )4 j = 4 ( 0.01467385 ) 4 • √( 1.06 )1 = 1 + j j = 0.0586 or 5.86% 4 • ( 1.06 )1/4 = 1 + j 4 • ( 1.06 )1/4 - 1 = j 4 • 4[( 1.06 )1/4 – 1 ] = j
  • 26. QUIZ • 1. How much will be the compounded interest of P1,000 pesos is invested for one year at 6% compounded monthly? • 2. Discount P32,000 for 16.1/2 years at 8% compounded monthly. How much is the discount? • 3. How much should you invest today to provide your only son a brand new car worth P 1,000,000 as a graduation gift 5 years from now if money is worth 6% compounded semi-annually?