LHS = ( sin x - cos x )^2 = sin^2 x + cos^2 x -2 sinx cos x But sin^2 x + cos^2 x = 1 and 2 sin x cos x = sin 2 x So LHS = 1 - 2sin x cos x = 1 - sin 2x = RHS Hence pROved Solution LHS = ( sin x - cos x )^2 = sin^2 x + cos^2 x -2 sinx cos x But sin^2 x + cos^2 x = 1 and 2 sin x cos x = sin 2 x So LHS = 1 - 2sin x cos x = 1 - sin 2x = RHS Hence pROved.