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LHS = ( sin x - cos x )^2
= sin^2 x + cos^2 x -2 sinx cos x
But sin^2 x + cos^2 x = 1 and 2 sin x cos x = sin 2 x
So
LHS = 1 - 2sin x cos x
= 1 - sin 2x = RHS
Hence pROved
Solution
LHS = ( sin x - cos x )^2
= sin^2 x + cos^2 x -2 sinx cos x
But sin^2 x + cos^2 x = 1 and 2 sin x cos x = sin 2 x
So
LHS = 1 - 2sin x cos x
= 1 - sin 2x = RHS
Hence pROved

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LHS = ( sin x - cos x )^2= sin^2 x + cos^2 x -2 sinx cos xBut si.pdf

  • 1. LHS = ( sin x - cos x )^2 = sin^2 x + cos^2 x -2 sinx cos x But sin^2 x + cos^2 x = 1 and 2 sin x cos x = sin 2 x So LHS = 1 - 2sin x cos x = 1 - sin 2x = RHS Hence pROved Solution LHS = ( sin x - cos x )^2 = sin^2 x + cos^2 x -2 sinx cos x But sin^2 x + cos^2 x = 1 and 2 sin x cos x = sin 2 x So LHS = 1 - 2sin x cos x = 1 - sin 2x = RHS Hence pROved