H2Te H2SE H2S H2O .pdf

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This document ranks the acidity of hydrogen chalcogenides from most acidic to least acidic as follows: hydrogen telluride (H2Te) is more acidic than hydrogen selenide (H2Se), which is more acidic than hydrogen sulfide (H2S), which is more acidic than water (H2O).

H2Te < H2SE < H2S < H2O
Solution
H2Te < H2SE < H2S < H2O

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PV = n RT 15 x 0.068 x 1.01 = 0.75M x 0.0821 x .pdf

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HOkay. So. You\'ve got: Ruthenium(II)..this is your transition metal Ammonia..a common ligand (you\'ve just go to befamiliar with common ligands and their charges if they have them) Chloride..this is your cation now. from this information you must deduce: Ruthenium (R) has a charge of +2 which (because thequestion asks for a coordination compound) binds with ammonia (NH3) (remembering that ammonia is a common ligand who donates it\'selections to the metal..in other words it is a Lewisbase..). Ammonia ligands do not have any charge(like I said before, you just have to know that,there is a chart in your text book that will give you thisinformation). About the coordination number 6.. I\'ll get tothat in a second. Notating a complex ion we use brackets like this: [complexion]. Butremember, R has a +2 charge. so the complex ion is an cationiccomplexion like this: [complexion]+2. so thisis were chlorine comes in. chlorine is an anion meaning it has anegative charge, chlorine has a -1 charge. so in order to neutralout the +2 charge that R gives the [complexion] we need two of them(Cl2). so now we have everything to write this out in complex ionnotation. [R(NH3)6]Cl2 and now a word about the coordination number 6. you don\'t really know that there are 6 ligands present but it\'s agood assumption because 6 happens to be a very common coordinationfor ammonia ligands. don\'t worry about this too much, just know howto count coordination numbers when given the complex ion. Okay, NOW about naming this ridiculous thing. name the ligand first! and then name other ligands in alphabeticalorder! ammonia in the form of a ligand is called anammine...(you just have to memorize that table ofligand names which I\'m sure is in the book as well). 6 ammines = hexamine. that\'s prettystraight forward unless you need to also memorize numberprefixes. and then you name the metal it\'s boundtoo,Ruthenium(II). here is the tricky part. add ate to the end of themetal IF and only IF the charge on the complex ion (before itbecame neutral) was negative. (and in this case thepositive ion that would bind to the [complex ion notation] would gobefore it, like lets say it was potassium, then you would writeK[complex ion] and not [complex ion]K...oy...) but in thecase of our Ruthenium(II) we don\'t need to add ate, because thecharge was originally positive. so now we have hexamineruthenium(II) and now we add our little chloride... hexamineruthenium(II) chloride. (you don\'t have to say dichloride,it\'s deducible that there are two..clearly, because i explained howto figure it out up at the top, but hopefully my explanation wasclear too) (and in this same manner, if the [complex ion] wasnegative at first and we bound a positive potassium to it we\'d putthe name potassium before the complex ion like: potassiumwhateverwhatever(roman numeral).) Solution HOkay. So. You\'ve got: Ruthenium(II)..this is your transition metal Ammonia..a common ligand (you\'ve just go to befamiliar with common l.

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in.txt ( Suppose if we store the text file in D:Drive then the path of the file pointing to this file is D:\\\\in.txt ) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 3 38 39 40 41 42 43 44 45 46 45 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 ___________________________________________________________________ ReadFile.java import java.io.*; import java.util.*; public class ReadFile { public static void main(String[] args) { //Creating the Scanner class reference. Scanner scanner=null; try { //Creating Scanner object by passing the file Object as input scanner = new Scanner(new File(\"D:\\\\in.txt\")); } catch (FileNotFoundException e) { e.printStackTrace(); } //Creating the ArrayList Obkect ArrayList integers = new ArrayList(); while (scanner.hasNext()) { if (scanner.hasNextInt()) { //Adding each element in the file to the ArrayList. integers.add(scanner.nextInt()); } } //Create the Iterator Object. Iterator i=integers.iterator(); //Iterator over the ArrayList while(i.hasNext()) { //Displaying the contents in the ArrayList. System.out.println(i.next()); } } } ______________________________________________________________________ Output: Enter File Name :D:\\\\in.txt 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 3 38 39 40 41 42 43 44 45 46 4 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 _____________________________________________________________________ Solution in.txt ( Suppose if we store the text file in D:Drive then the path of the file pointing to this file is D:\\\\in.txt ) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 3 38 39 40 41 42 43 44 45 46 45 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 ___________________________________________________________________ ReadFile.java import java.io.*; import java.util.*; public class ReadFile { public static void main(String[] args) { //Creating the Scanner class reference. Scanner scanner=null; try { //Creating Scanner object by passing the file Object as input scanner = new Scanner(new File(\"D:\\\\in.txt\")); } catch (FileNotFoundException e) { e.printStackTrace(); } //Creating the ArrayList Obkect ArrayList integers = new ArrayList(); while (scanner.hasNext()) { if (scanner.hasNextInt()) { //Adding each element in the file to the ArrayList. integers.add(scanner.nextInt()); } } //Create the Iterator Object. Iterator i=integers.iterator(); //Iterator over the ArrayList while(i.hasNext()) { //Displaying the contents in the ArrayList. System.out.println(i.next()); } } } _____________________.

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The matrix, the dominant component in the landscape, is the most extensive and connected landscape type, and it plays the dominant role in landscape functioning. A landscape is composed typically of several types of landscape elements (usually patches). Of these, the matrix is the most extensive and most connected landscape element type, and therefore plays the dominant role in the functioning of the landscape .The characteristics of matrix structure are the density of the patches (porosity), boundary shape, networks, and heterogeneity . For example, in a large contiguous area of mature forest embedded with numerous small disturbance patches (e.g., timber harvest patches), the mature forest constitutes the matrix element type because it is greatest in areal extent, is mostly connected, and exerts a dominant influence on the area flora and fauna and ecological processes. Effect of matrix on metapopulation: The core conceptual framework of metapopulation theory (Levins 1969) is that with-in-patch dynamics are influenced not only by local extinction but also by colonization from elsewhere in the landscape. When the landscape becomes more fragmented, colonization rates are reduced. Then, within-patch species richness will decline and extinction risk at the scale of the entire metapopulation will increase. Matrix affects its communities by the following ways. (1) altering dispersal and colonization rates, which may be reduced or enhanced, depending on the characteristics of each species (2) providing alternative habitat to existing species (for some species matrix habitat may be of lower quality than the original habitat, while for others it may be of higher quality) (3) as a source of novel invading species for fragments, as the matrix may provide habitat for new species. Holt a researcher studied \"Potential effects of the matrix on communities in patchy environments \". He predicted that species that were abundant in the common habitat (matrix) had potential to become more common members of local communities in the sparser habitat (fragments) than species that did not inhabit the common habitat. This spillover effect had potential to be important in determining which species make up local communities. Solution The matrix, the dominant component in the landscape, is the most extensive and connected landscape type, and it plays the dominant role in landscape functioning. A landscape is composed typically of several types of landscape elements (usually patches). Of these, the matrix is the most extensive and most connected landscape element type, and therefore plays the dominant role in the functioning of the landscape .The characteristics of matrix structure are the density of the patches (porosity), boundary shape, networks, and heterogeneity . For example, in a large contiguous area of mature forest embedded with numerous small disturbance patches (e.g., timber harvest patches), the mature forest constitutes the matrix element type because it i.

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The non-disjunctioning had occur in her mother. Turner\'s syndrome is caused by incomplete inheritance of or missing X chromosome, which generally affects females. The poor growth and development of sexual organs can be seen early. Haemophilia is an X-lined recessive disease. Females inherit one X-chromosome from the father and another from the mother. The inheritance of haemophilia from the father ensures the inheritance of X-chromosomes from the father. So, the nondisjunction occurred in females during meiosis-I. The daughter received one X-chromosome from the father and no chromosomes from the mother, resulting in 45, X karyotype (Turner\'s syndrome) and haemophilia. Solution The non-disjunctioning had occur in her mother. Turner\'s syndrome is caused by incomplete inheritance of or missing X chromosome, which generally affects females. The poor growth and development of sexual organs can be seen early. Haemophilia is an X-lined recessive disease. Females inherit one X-chromosome from the father and another from the mother. The inheritance of haemophilia from the father ensures the inheritance of X-chromosomes from the father. So, the nondisjunction occurred in females during meiosis-I. The daughter received one X-chromosome from the father and no chromosomes from the mother, resulting in 45, X karyotype (Turner\'s syndrome) and haemophilia..

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Team 1 should start with Rohnda because of her no loss in fight 1 and Cat for 2 fight Team 2 should start with Holly because of her no loss in fight 1 and Miesha for 2 fight And team 2 has advantage over team 1 Solution Team 1 should start with Rohnda because of her no loss in fight 1 and Cat for 2 fight Team 2 should start with Holly because of her no loss in fight 1 and Miesha for 2 fight And team 2 has advantage over team 1.

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Rods are responsible for dim light vision and cones are responsible for color vision. Cones are of three types( three wavelengths) Red , green and blue. A severe color deficiency or color blind is present when one or more of the cones light sensitive pigments is really wrong Solution Rods are responsible for dim light vision and cones are responsible for color vision. Cones are of three types( three wavelengths) Red , green and blue. A severe color deficiency or color blind is present when one or more of the cones light sensitive pigments is really wrong.

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Navigation Design:Because of navigation component present in the interface we are able to navigate through the system.How this navigation component does this navigation means it takes the input as comand from the user and perform corresponding action and review the information. Navigation component enable users know about their success or failture of their actions by messages.The main goal of any system is providing user ease of access.That ease of access is given by this navigation component. A good navigation component does the things as the way user expecting actions from the system. Basic principles of Navigation Design: 1)Prevent mistakes:Designing navigation controls is to prevent from the user making mistakes.This mistake costs of time as well as frustation.Making continuous mistakes by user discard the system. 2)Simplify recovery from mistakes:The system have Undo button that do the mistakes override simply. 3)Use Consistent Grammar Order: Input Design:It is all about designing screens so that user can enter information.We can say this in different manner also that is providing forms so that can write or enter information. Principles of input design: 1)Capture data at the source:capturing data in an electronic format. 2)Online versus Batch Processing:Online means enter the data individually while tranction is going on Batch Processing:Collecting or gathering data over some time and enter the data into the system. 3)Minimize keystrokes:Whatever the system we design It is not allowed user to enter information via keyboard Because it costs time and also money.So,minimize this by providing drop down or involving database calculation. Output Design:Outputs are the reprots that system produces on the screen or paper or in web. 1. Manage information load:Output motive is not about providing all the information.So,we have to mangage the information so that it is intended about that particular task or input. 2.Minimize Bias: Solution Navigation Design:Because of navigation component present in the interface we are able to navigate through the system.How this navigation component does this navigation means it takes the input as comand from the user and perform corresponding action and review the information. Navigation component enable users know about their success or failture of their actions by messages.The main goal of any system is providing user ease of access.That ease of access is given by this navigation component. A good navigation component does the things as the way user expecting actions from the system. Basic principles of Navigation Design: 1)Prevent mistakes:Designing navigation controls is to prevent from the user making mistakes.This mistake costs of time as well as frustation.Making continuous mistakes by user discard the system. 2)Simplify recovery from mistakes:The system have Undo button that do the mistakes override simply. 3)Use Consistent Grammar Order: Input Design:It is all about designing screens so that user can ent.

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//FuelGauge class class FuelGauge { private int fuel; public static int max_capacity = 15; public FuelGauge() { fuel = 0; } // parameterized constructor public FuelGauge(int oil) { if (oil <= max_capacity) { fuel = oil; } else { fuel = max_capacity; } } // return amount of fuel public int getfuel() { return fuel; } // add fuel till max capacity is reached public void addfuel() { if (fuel < max_capacity) { fuel++; } else { System.out.println(\"Maximum capacity reached, Burn some fuel\ \"); } } // burn the fuel public void burnFuel() { if (fuel > 0) { fuel--; } else { System.out.println(\"No fuel left, Add some fuel\ \"); } } } //Odometer class class Odometer { // maximum mileage public int max_mileage = 999999; // miles per gallon public int fuel_economy = 22; private int startmileage; private int mileage; // FuelGauge object private FuelGauge fuelgauge; public Odometer(int mlg, FuelGauge fg) { startmileage = mlg; mileage = mlg; fuelgauge = fg; } public int getMileage() { return mileage; } public void addMileage() { if (mileage < max_mileage) { mileage++; } else { mileage = 0; } int d = startmileage - mileage; if (d % fuel_economy == 0) { fuelgauge.burnFuel(); } } } // Driver class public class Driver { public static void main(String[] args) { FuelGauge fuel = new FuelGauge(); Odometer odometer = new Odometer(0, fuel); for (int i = 0; i < FuelGauge.max_capacity; i++) { fuel.addfuel(); } // while there is fuel left while (fuel.getfuel() > 0) { odometer.addMileage(); System.out.println(\"Mileage: \" + odometer.getMileage()); // amount of fuel left System.out.println(\"Fuel left: \" + fuel.getfuel() + \" Gallons\ \"); } } } /* output: Mileage: 1 Fuel left: 15 Gallons Mileage: 2 Fuel left: 15 Gallons Mileage: 3 Fuel left: 15 Gallons Mileage: 4 Fuel left: 15 Gallons Mileage: 5 Fuel left: 15 Gallons Mileage: 6 Fuel left: 15 Gallons Mileage: 7 Fuel left: 15 Gallons Mileage: 8 Fuel left: 15 Gallons Mileage: 9 Fuel left: 15 Gallons Mileage: 10 Fuel left: 15 Gallons Mileage: 11 Fuel left: 15 Gallons Mileage: 12 Fuel left: 15 Gallons Mileage: 13 Fuel left: 15 Gallons Mileage: 14 Fuel left: 15 Gallons Mileage: 15 Fuel left: 15 Gallons Mileage: 16 Fuel left: 15 Gallons Mileage: 17 Fuel left: 15 Gallons Mileage: 18 Fuel left: 15 Gallons Mileage: 19 Fuel left: 15 Gallons Mileage: 20 Fuel left: 15 Gallons Mileage: 21 Fuel left: 15 Gallons Mileage: 22 Fuel left: 14 Gallons Mileage: 23 Fuel left: 14 Gallons Mileage: 24 Fuel left: 14 Gallons Mileage: 25 Fuel left: 14 Gallons Mileage: 26 Fuel left: 14 Gallons Mileage: 27 Fuel left: 14 Gallons Mileage: 28 Fuel left: 14 Gallons Mileage: 29 Fuel left: 14 Gallons Mileage: 30 Fuel left: 14 Gallons Mileage: 31 Fuel left: 14 Gallons Mileage: 32 Fuel left: 14 Gallons Mileage: 33 Fuel left: 14 Gallons Mileage: 34 Fuel left: 14 Gallons Mileage: 35 Fuel left: 14 Gallons Mileage: 36 Fuel left: 14 Gallons Mileage: 37 Fuel left: 14 Gallons Mileage: 38 Fuel left: 14 Gallons Mileage: 39 Fuel left: 14 Gallons Mileage: 40 Fuel lef.

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