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[object Object],[object Object],[object Object],[object Object]
The combined gas law Uses three gas variables to describe a gas sample at two different times. If a variable does not change (is constant) it can be removed from the equation. P 1 V 1   P 2 V 2 T 1   T 2   =
Boyle’s Law: Pressure and Volume ,[object Object],[object Object],[object Object],P 1 V 1   P 2 V 2 T 1   T 2   = P 1 V 1   P 2 V 2 =
[object Object],[object Object]
INDIRECTLY PROPORTIONAL  aka  INVERSELY PROPORTIONAL
Boyle Problem V 1  = 30.0L All math examples should be in your notes L measures Volume(V)
Boyle Problem V 1  = 30.0L  V 2  = ? P 1  = 103 kPa  P 2  = 25.0 kPa kPa measures Pressure(P)
Boyle Problem V 1  = 30.0L  V 2  = ? P 1  = 103 kPa  P 2  = 25.0 kPa These two values go together because they describe the gas at the same moment.
Boyle Problem V 1  = 30.0L  V 2   = ? P 1  = 103 kPa This is the unknown
Boyle Problem V 1  = 30.0L  V 2   = ? P 1  = 103 kPa   P 2  = 25.0 kPa This is a pressure value
Boyle Problem V 1  = 30.0L  V 2  = ? P 1  = 103 kPa  P 2  = 25.0 kPa These two values go together because they describe the gas at the same moment.
Boyle Problem Temp is constant and I need an equation that relates pressure and volume. P 1 V 1  = P 2 V 2 V 1  = 30.0L  V 2  = ? P 1  = 103 kPa  P 2  = 25.0 kPa P 1 V 1  = P 2 V 2 T 1   T 2
Boyle Problem P 1 V 1  = P 2 V 2 103 kPa x 30L =  25.0 kPa x V 2 ___________  ___________ 25.0 kPa  25.0kPa = 124 L P  ,V   GOOD! V 1  = 30.0L  V 2  = ? P 1  = 103 kPa  P 2  = 25.0 kPa
for Sample Problem 14.1
[object Object],[object Object],[object Object],[object Object],P 1 V 1   P 2 V 2 T 1   T 2   = V 1   V 2 T 1   T 2   =
[object Object],[object Object]
DIRECTLY PROPORTIONAL
14.2 T 1  = 24  C  T 2  = 58  C V 1  = 4.00L  V 2  =  ? T  must  be in Kelvins!! + 273 = 297K  + 273 = 331K  V 2  = 4L    297K x 331K = 4.46 L T   V   GOOD! 4.00L  V 2 297 K  331 K =
for Sample Problem 14.2
[object Object],[object Object],[object Object],[object Object],P 1 V 1   P 2 V 2 T 1   T 2   = P 1   P 2 T 1   T 2   =
[object Object],[object Object]
14.3
 
 
 
for Sample Problem 14.3
[object Object]
 
 
 
 
for Sample Problem 14.4
[object Object],[object Object],[object Object],[object Object],[object Object]
14.2 Section Quiz. ,[object Object],[object Object],[object Object],[object Object],[object Object]

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Gas laws variables and equations

  • 1.
  • 2. The combined gas law Uses three gas variables to describe a gas sample at two different times. If a variable does not change (is constant) it can be removed from the equation. P 1 V 1 P 2 V 2 T 1 T 2 =
  • 3.
  • 4.
  • 5. INDIRECTLY PROPORTIONAL aka INVERSELY PROPORTIONAL
  • 6. Boyle Problem V 1 = 30.0L All math examples should be in your notes L measures Volume(V)
  • 7. Boyle Problem V 1 = 30.0L V 2 = ? P 1 = 103 kPa P 2 = 25.0 kPa kPa measures Pressure(P)
  • 8. Boyle Problem V 1 = 30.0L V 2 = ? P 1 = 103 kPa P 2 = 25.0 kPa These two values go together because they describe the gas at the same moment.
  • 9. Boyle Problem V 1 = 30.0L V 2 = ? P 1 = 103 kPa This is the unknown
  • 10. Boyle Problem V 1 = 30.0L V 2 = ? P 1 = 103 kPa P 2 = 25.0 kPa This is a pressure value
  • 11. Boyle Problem V 1 = 30.0L V 2 = ? P 1 = 103 kPa P 2 = 25.0 kPa These two values go together because they describe the gas at the same moment.
  • 12. Boyle Problem Temp is constant and I need an equation that relates pressure and volume. P 1 V 1 = P 2 V 2 V 1 = 30.0L V 2 = ? P 1 = 103 kPa P 2 = 25.0 kPa P 1 V 1 = P 2 V 2 T 1 T 2
  • 13. Boyle Problem P 1 V 1 = P 2 V 2 103 kPa x 30L = 25.0 kPa x V 2 ___________ ___________ 25.0 kPa 25.0kPa = 124 L P  ,V  GOOD! V 1 = 30.0L V 2 = ? P 1 = 103 kPa P 2 = 25.0 kPa
  • 15.
  • 16.
  • 18. 14.2 T 1 = 24  C T 2 = 58  C V 1 = 4.00L V 2 = ? T must be in Kelvins!! + 273 = 297K + 273 = 331K V 2 = 4L  297K x 331K = 4.46 L T  V  GOOD! 4.00L V 2 297 K 331 K =
  • 20.
  • 21.
  • 22. 14.3
  • 23.  
  • 24.  
  • 25.  
  • 27.
  • 28.  
  • 29.  
  • 30.  
  • 31.  
  • 33.
  • 34.

Editor's Notes

  1. The pressure of a gas changes as the volume changes. INTERPRETING GRAPHS a. Observing When the volume is 2.0 L, what is the pressure? b. Predicting What would the pressure be if the volume were increased to 3.0 L? c. Drawing Conclusions Based on the shape of the graph, describe the general pressure-volume relationship.
  2. This graph shows how the volume changes as the temperature of a gas changes. INTERPRETING GRAPHS a. Observing What is the unit of temperature? b. Drawing Conclusions What happens to the volume as the temperature rises? c. Predicting If the temperature of a gas were 0 K, what would the volume of the gas be?