This document discusses the load carrying capacity and design of reinforced concrete beams. It provides information on:
1. The loads carried by different types of beams supporting one-way or two-way slabs. Equations are given for calculating equivalent uniform distributed loads.
2. Slab load per unit area calculations for different floor types, including dead loads from self-weight, finishes, and live loads.
3. The process for designing singly reinforced concrete beams using the strength method, including selecting dimensions and reinforcement ratios to satisfy strength and serviceability limits.
4. Details on reinforcement schedules, bar types, hook lengths, and calculating rebar quantities.
Sheryar Bismil
Student of Mirpur University of Science & Technology(MUST).
Student of Final Year Civil Engineering Department Main campus Mirpur.
Here we Gonna to learn about the basic to depth wise study of Plan Reinforced Concrete-i.
From basis terminology to wide information about the analysis and design of Concrete member like column,Beam,Slab,etc.
Sheryar Bismil
Student of Mirpur University of Science & Technology(MUST).
Student of Final Year Civil Engineering Department Main campus Mirpur.
Here we Gonna to learn about the basic to depth wise study of Plan Reinforced Concrete-i.
From basis terminology to wide information about the analysis and design of Concrete member like column,Beam,Slab,etc.
Sheryar Bismil
Student of Mirpur University of Science & Technology(MUST).
Student of Final Year Civil Engineering Department Main campus Mirpur.
Here we Gonna to learn about the basic to depth wise study of Plan Reinforced Concrete-i.
From basis terminology to wide information about the analysis and design of Concrete member like column,Beam,Slab,etc.
Sheryar Bismil
Student of Mirpur University of Science & Technology(MUST).
Student of Final Year Civil Engineering Department Main campus Mirpur.
Here we Gonna to learn about the basic to depth wise study of Plan Reinforced Concrete-i.
From basis terminology to wide information about the analysis and design of Concrete member like column,Beam,Slab,etc.
Sheryar Bismil
Student of Mirpur University of Science & Technology(MUST).
Student of Final Year Civil Engineering Department Main campus Mirpur.
Here we Gonna to learn about the basic to depth wise study of Plan Reinforced Concrete-i.
From basis terminology to wide information about the analysis and design of Concrete member like column,Beam,Slab,etc.
Sheryar Bismil
Student of Mirpur University of Science & Technology(MUST).
Student of Final Year Civil Engineering Department Main campus Mirpur.
Here we Gonna to learn about the basic to depth wise study of Plan Reinforced Concrete-i.
From basis terminology to wide information about the analysis and design of Concrete member like column,Beam,Slab,etc.
This Presentation deals with the Design of a Cantilever Retaining Wall with no surcharge.
Please notify any errors you may find in the ppt.
thankyou for your time.
This ppt is more useful for Civil Engineering students.
I have prepared this ppt during my college days as a part of semester evaluation . Hope this will help to current civil students for their ppt presentations and in many more activities as a part of their semester assessments.
I have prepared this ppt as per the syllabus concerned in the particular topic of the subject, so one can directly use it just by editing their names.
This Presentation deals with the Design of a Cantilever Retaining Wall with no surcharge.
Please notify any errors you may find in the ppt.
thankyou for your time.
This ppt is more useful for Civil Engineering students.
I have prepared this ppt during my college days as a part of semester evaluation . Hope this will help to current civil students for their ppt presentations and in many more activities as a part of their semester assessments.
I have prepared this ppt as per the syllabus concerned in the particular topic of the subject, so one can directly use it just by editing their names.
information on types of beams, different methods to calculate beam stress, design for shear, analysis for SRB flexure, design for flexure, Design procedure for doubly reinforced beam,
Reinforced concrete Course Assignments, 2023.
Educational material for the RCS course. Design examples for reinforced concrete structures regarding beams and mast columns.
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Industrial Training at Shahjalal Fertilizer Company Limited (SFCL)MdTanvirMahtab2
This presentation is about the working procedure of Shahjalal Fertilizer Company Limited (SFCL). A Govt. owned Company of Bangladesh Chemical Industries Corporation under Ministry of Industries.
Hierarchical Digital Twin of a Naval Power SystemKerry Sado
A hierarchical digital twin of a Naval DC power system has been developed and experimentally verified. Similar to other state-of-the-art digital twins, this technology creates a digital replica of the physical system executed in real-time or faster, which can modify hardware controls. However, its advantage stems from distributing computational efforts by utilizing a hierarchical structure composed of lower-level digital twin blocks and a higher-level system digital twin. Each digital twin block is associated with a physical subsystem of the hardware and communicates with a singular system digital twin, which creates a system-level response. By extracting information from each level of the hierarchy, power system controls of the hardware were reconfigured autonomously. This hierarchical digital twin development offers several advantages over other digital twins, particularly in the field of naval power systems. The hierarchical structure allows for greater computational efficiency and scalability while the ability to autonomously reconfigure hardware controls offers increased flexibility and responsiveness. The hierarchical decomposition and models utilized were well aligned with the physical twin, as indicated by the maximum deviations between the developed digital twin hierarchy and the hardware.
Student information management system project report ii.pdfKamal Acharya
Our project explains about the student management. This project mainly explains the various actions related to student details. This project shows some ease in adding, editing and deleting the student details. It also provides a less time consuming process for viewing, adding, editing and deleting the marks of the students.
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Buying new cosmetic products is difficult. It can even be scary for those who have sensitive skin and are prone to skin trouble. The information needed to alleviate this problem is on the back of each product, but it's thought to interpret those ingredient lists unless you have a background in chemistry.
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CFD analysis is incredibly effective at solving mysteries and improving the performance of complex systems!
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It is always satisfying when we can help solve complex challenges like this. Do your systems also need a check-up or optimization? Give us a call!
Work done in cooperation with James Malloy and David Moelling from Tetra Engineering.
More examples of our work https://www.r-r-consult.dk/en/cases-en/
2. Plain & Reinforced Concrete-1
Load Carried by the Beam
Beam Supporting One-way Slab
lx
lx
Exterior Beam
Interior Beam
Width of slab supported by interior beam = lx
Width of slab supported by exterior beam = lx/2 + Cantilever width
ly
(ly/lx > 2)
3. Plain & Reinforced Concrete-1
Load Carrie by the Beam
Beam Supporting Two-way Slab (ly/lx≤ 2)
lx
lx
ly ly
Exterior Long Beam
Interior Long Beam
Exterior Short Beam
Interior Short Beam
45o
4. Plain & Reinforced Concrete-1
Load Carrie by the Beam
Beam Supporting Two-way Slab (ly/lx≤ 2) contd…
45olx/2
lx/2
o
45cos
2/xl
2
o
45cos
2/x
lArea of Square
Shorter Beams
For simplification this
triangular load on both
the sides is to be replaced
by equivalent UDL,
which gives same Mmax as
for the actual triangular
load.
2
2
xl
5. Plain & Reinforced Concrete-1
Load Carried by the Beam
Beam Supporting Two-way Slab (ly/lx≤ 2) contd…
45o45o
Equivalent Rectangular
Area
2
2
x
3
2
2
x
3
4
l
l
Factor of 4/3 convert this VDL into UDL.
Equivalent width supported
by interior short beam
lx
x
x
3
2
l
l 2
x
3
2
l
Equivalent width supported
by exterior short beam
3
xl
Cantilever
x
3
2
l
6. Plain & Reinforced Concrete-1
Load Carried by the Beam
Beam Supporting Two-way Slab (ly/lx≤ 2)contd…
lx
lx
ly
Exterior Long Beam
2
2
x
xy
2
x
l
ll
l
Supported Area
lx/2 lx/2ly - lx
4
x
2
x
2
yx 22
llll
4
x
2
yx 2
lll
2
x
yx
2
1 2
l
ll
7. Plain & Reinforced Concrete-1
Load Carried by the Beam
Beam Supporting Two-way Slab (ly/lx≤ 2)contd…
Exterior Long Beam
2
R1
3
R1
F
2
y
x
R
l
l
where
Factor F converts
trapezoidal load into
equivalent UDL for
maximum B.M. at center
of simply supported
beam.For Square panel
R = 1 and F = 4/3
8. Plain & Reinforced Concrete-1
Load Carried by the Beam
Beam Supporting Two-way Slab (ly/lx≤ 2)contd…
Exterior Long Beam
Equivalent width
lx/2 lx/2ly - lx
Equivalent width
Length...Span
F)Supported..Area(
ly
y
1
2R1
3R1
2
x
yx
2
1 22
l
l
ll
2R1
3R1
2
x
1
2
x 2
lyll
3R1
2
x 2l
+ Cantilever (if present)
11. Plain & Reinforced Concrete-1
Wall Load on the Lintel
Equivalent UDL on lintel if
height of slab above lintel
is greater than 0.866L 0.866L
60o 60o
L
Ltw11.0UDL kN/m
tw = wall thickness in “mm”
L = Opening size in “m”
If the height of slab above lintel is less than 0.866L
Total Wall Load + Load from slab in case of load bearing wall
UDL = (Equivalent width of slab supported) x (Slab load per unit area)
= m x kN/m2 = kN/m
12. Plain & Reinforced Concrete-1
Slab Load per Unit Area
Top Roof
Slab Thickness = 125 mm
Earth Filling = 100 mm
Brick Tiles = 38 mm
Dead Load
2
m/kg3002400
1000
125
Self wt. of R.C. slab
Earth Filling
2
m/kg1801800
1000
100
Brick Tiles
2
m/kg741930
1000
38
554 kg/m2Total Dead Load, Wd =
13. Plain & Reinforced Concrete-1
Slab Load per Unit Area (contd…)
Top Roof
Live Load
WL = 200 kg/m2
Ldu W6.1W2.1W
Total Factored Load, Wu
1000
81.9
2006.15542.1Wu
2
u m/kN66.9W
14. Plain & Reinforced Concrete-1
Slab Load per Unit Area (contd…)
Intermediate Floor
Slab Thickness = 150 mm
Screed (brick ballast + 25% sand) = 75 mm
P.C.C. = 40 mm
Terrazzo Floor = 20 mm
Dead Load
2
m/kg3602400
1000
150
Self wt. of R.C. slab
Screed 2
m/kg1351800
1000
75
Terrazzo + P.C.C 2
m/kg1382300
1000
)4020(
633 kg/m2
Total Dead Load, Wd =
15. Plain & Reinforced Concrete-1
Slab Load per Unit Area (contd…)
Intermediate Floor
Live Load
Occupancy Live Load = 250 kg/m2
Moveable Partition Load = 150 kg/m2
WL = 250 + 150 = 400 kg/m2
Ldu W6.1W2.1W
Total Factored Load, Wu
1000
81.9
4006.16332.1Wu
2
u m/kN73.13W
16. Plain & Reinforced Concrete-1
Slab Load per Unit Area (contd…)
Self Weight of Beam
Service Self Wight of Beam = b x h x 1m x 2400
2
L11.112400m1
18
L
12
L
Kg/m
Factored Self Wight of Beam
22
L131.0
1000
81.9
2.1L11.11 kN/m
Self weight of beam is required to be calculated in at the stage of
analysis, when the beam sizes are not yet decided, so approximate
self weight is computed using above formula.
17. Plain & Reinforced Concrete-1
Bar Bending Schedule
Serial #
Bar
Designation
Number
of Bars
Length
of one
Bar
Dia
of
bar
Weight of Steel Required
Shape of
Bar
#10 #13 #15 #19 #25
1 M-1 #25
2 S-1 #10
3 H-1 #15
Σ
Total weight of steel = 1.05Σ , 5% increase, for wastage during cutting
and bending
18. Plain & Reinforced Concrete-1
Bar Bending Schedule (contd…)
Bent-up Bar
h45o
h
h2
Additional Length = 0.414 h
Total Length = L + 0.414 h
L
19. Plain & Reinforced Concrete-1
Bar Bending Schedule (contd…)
90o-Standard Hooks (ACI)
db
R = 4db
for bar up-to #25
R = 5db
for bar #29 & #36
R = 12db
L
Total Length = L + 18db For R 4db
20. Plain & Reinforced Concrete-1
Bar Bending Schedule (contd…)
180o-Standard Hooks (ACI)
db
L
Total Length = L + 20db
4db
Same as 90o hook
21. Plain & Reinforced Concrete-1
Bar Bending Schedule (contd…)
Example: Prepare bar bending schedule for the given beam. Clear
cover = 40 mm
2-#20 +1-#15
4000
570 2-#20
2-#10
228
#10 @ 180 c/c
Longitudinal Section
1-# 15
22. Plain & Reinforced Concrete-1
Bar Bending Schedule (contd…)
Example: Prepare bar bending schedule for the given beam. Clear
cover = 40 mm
#10 @ 180 c/c
228
375
2-#10
1-# 15
2-#20
(M-2)
(M-1)
(S-1)
(H-1)
Cross Section
23. Plain & Reinforced Concrete-1
Bar Bending Schedule (contd…)
Example:
M-1
M-1 = 4000 + 2 x 228 – 2 x 40 + 2 x (18 x 20)
= 5096
M-2h = 375 – 2 x 40 – 2 x 10 – 2 (15/2) = 260
h
M-2 = 4000 + 2 x 228 – 2 x 40 + (0.414 x 260) x 2
= 5091
H-1
H-1 = 4000 + 2 x 228 – 2 x 40
= 4376
24. Plain & Reinforced Concrete-1
Bar Bending Schedule (contd…)
Example: Prepare bar bending schedule for the given beam. Clear
cover = 40 mm
Number of Bars = 4000 / 180 +1 = 24 Round-up
Shear stirrups
a
a = 375 – 2 x 40 – 10 = 285 mm
bb = 228– 2 x 40 – 10 =138 mm
Total length of S-1 = 2 (138 + 285 + 18 x 10) = 1206 mm
25. Plain & Reinforced Concrete-1
Bar Bending Schedule
Serial #
Bar
Designation
Number
of Bars
Length
of one
Bar
(m)
Dia
of
bar
Weight of Steel
Bars
Shape of Bar
#10 #15 #20
1 M-1 2 5.096 20 24
2 M-2 1 4.591 15 7.2
3 H-1 2 4.376 10 6.9
4 S-1 24 1.206 10 22.7
1.05 Σ 31.1 7.6 25.2
Total Weight = 64 kg
4376
4376
4376
285138
26. Plain & Reinforced Concrete-1
Design of Singly Reinforced Beam by Strength
Method (for flexure only)
Data:
Load, Span (SFD, BMD)
fc’, fy, Es
Architectural depth, if any
Required:
Dimensions, b & h
Area of steel
Detailing (bar bending schedule)
27. Plain & Reinforced Concrete-1
Design of Singly Reinforced Beam by Strength Method (contd…)
Procedure:
1. Select reasonable steel ratio between ρmin and ρmax.
Then find b, h and As.
2. Select reasonable values of b, h and then
calculate ρ and As.
28. Plain & Reinforced Concrete-1
Design of Singly Reinforced Beam by Strength Method (contd…)
2. Using Trial Dimensions
I. Calculate loads acting on the beam.
II. Calculate total factored loads and plot SFD and
BMD. Determine Vumax and Mumax.
III. Select suitable value of beam width ‘b’. Usually
between L/20 to L/15. preferably a multiple of
75mm or 114 mm.
IV. Calculate dmin.
b'f205.0
M
d
c
u
min
hmin = dmin + 60 mm for single layer of steel
hmin = dmin + 75mm for double layer of steel
Round to
upper 75 mm
29. Plain & Reinforced Concrete-1
Design of Singly Reinforced Beam by Strength Method (contd…)
V. Decide the final depth.
minhh For strength
minhh For deflection
ahh Architectural depth
12
hh
Preferably “h” should be multiple of 75mm.
Recalculate “d” for the new value of “h”
30. Plain & Reinforced Concrete-1
Design of Singly Reinforced Beam by Strength Method (contd…)
VI. Calculate “ρ” and “As”.
fc'
2.614R
11wρ
Four methods
y
c
f
'f
0.85w 2
u
bd
M
R
Design Table
Design curves
Using trial Method
a)
b)
c)
d)
31. Plain & Reinforced Concrete-1
Design of Singly Reinforced Beam by Strength Method (contd…)
VII. Check As ≥ As min.
As min = ρmin bd (ρmin = 1.4/fy to fc’ ≤ 30 MPa)
VIII. Carry out detailing
IX. Prepare detailed sketches/drawings.
X. Prepare bar bending schedule.
32. Plain & Reinforced Concrete-1
Design of Singly Reinforced Beam by Strength Method (contd…)
1. Using Steel Ratio
I. Step I and II are same as in previous method.
III. Calculate ρmax and ρmin & select some suitable “ρ”.
IV. Calculate bd2 from the formula of moment
V. Select such values of “b” and “d” that “bd2” value
is satisfied.
VI. Calculate As.
VII. Remaining steps are same as of previous method.
'1.7f
ρf
1fρbd0.9MΦM
c
y
y
2
nbu