Law of Acceleration.pptx
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This document defines key terms and concepts related to Newton's Second Law of Motion, including force, mass, weight, and acceleration. It states Newton's Second Law - that the acceleration of an object is directly proportional to the net force acting on it, and inversely proportional to its mass. Several example problems are worked through to demonstrate how to use the law to calculate force, mass, or acceleration given values for the other two quantities.
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Law of Acceleration.pptx
- 1. Law of Acceleration Prepared by: Jeve F. Gonzales Isaac Newton
- 2. Objectives: define and identify the units for acceleration, mass, and force State the Law of Acceleration Solve problems on law of acceleration
- 3. Getting started First, you need to define and know the units of mass, force and acceleration: Force is a push or a pull The unit that used to measure Force is Newton (N) Gravity is the force of attraction that exists between two objects that have mass The force of gravity depends on the mass of the object and the distance between them.
- 4. The force of the gravity causes all objects near Earth’s surface to fall with an acceleration of 9.8 m/s². Your weight on Earth is the gravitational force between you and Earth.
- 5. How are weight and mass different? Weight is a force and is measured in newtons Mass is the amount of matter in an object and does not depend on location - it is measured in kg Weight will vary in location but mass will remain constant. F = W = mg
- 6. Acceleration Is a change in velocity Speeding up - positive acceleration Slowing down - negative acceleration - deceleration Changing direction Unbalanced forces cause objects to accelerate
- 10. But there is a twist Acceleration is inversely related to the mass of the object
- 12. a ∝ F a ∝ 1/𝑚 a = F/m
- 13. 1.
- 14. Given: m = 1 000 kg a = 0.05 m/s² F = ? Solution: F= ma F = 1 000 kg x 0.05 m/s² F= 50 kg.m/s² or 50 N
- 15. Problem Number 2 A golf ball has a mass of approximately 0.046 kg. How much force must be applied by the tee so that the ball will move from rest to 8.25 m/s in 10.0 seconds?
- 16. Given: m = 0.046 kg F = ? t = 10 sec. Vi = 0 Vf = 8.25 m/s Solving for acceleration, a = vf-vi t a = 8.25 m/s – 0 10 sec F = ma F = 0.046 kg x 0.825 m/s² a = 0.825 m/s² F = 0.038 N
- 17. Problem no. 3 Suppose a bus weighs 1,200N and slows down in a distance of 55m from 50m/s. How much force is exerted to the brakes?
- 18. Given: w = 1,200 N F =? d = 55 m Vf = 0 Vi = 50 m/s Solution: a = vf²-Vi² 2d a =(0)² – (50 m/s)² 2 (55 m ) a = - 2 500 m²/s² 110 m m = w/g m = 1, 200 kg.m/s² -9.8 m/s² F = ma F = (- 122.45 kg) ( - 22.73 m/s²) a = - 22.73 m/s² m = - 122.45 kg F = 2, 783.29 N
- 19. Supply the following with the correct answer: Net Force (N) Mass (kg) Acceleration ( m/s²) 10 2 5 20 2 10 20 5 10 5 1 10
- 20. Net Force N) Mass (kg) Acceleration ( m/s²) 10 2 5 20 2 10 20 4 5 10 5 2 10 1 10 If mass remains constant, doubling the acceleration, doubles the force. If force remains constant, doubling the mass, halves the acceleration.
- 21. Thank you!