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JUEC 初中 (2016 Past Year)
1.
18 8 ? 𝑎𝑟𝑒𝑎 𝑜𝑓 ∆𝐴𝐵𝐶
= 𝑎𝑟𝑒𝑎 𝑜𝑓 𝐶𝐷𝐸𝐹 1 2 × 𝐵𝐶 × ℎ = 1 2 × 𝐸𝐹 + 𝐶𝐷 × ℎ 𝐵𝐶 = 𝐸𝐹 + 𝐶𝐷 𝐶𝐷 = 𝐵𝐶 − 𝐸𝐹 𝐶𝐷 = 18 − 8 = 10 𝑐𝑚
2.
? 𝑎𝑛𝑔𝑙𝑒 𝑜𝑓 𝐴𝑂𝐵
= 360° 𝑛 = 360° 8 = 45° 𝑥 = 3(45°) = 135° 1 2 3 𝑛 = 8 𝑥 = 𝑂𝐵 → 𝑂𝐸
3.
∆𝐷𝐴𝐵 ≡ ∆𝐸𝐵𝐶 120° 120° 120° 60° 120° 60° 120° 2𝑎 3𝑎
= 60° 𝑎 = 20°
4.
r ↓ 20% new
radius, 𝑟1 = 0.8r original radius = r original area, A = π𝑟2 𝑛𝑒𝑤 𝑎𝑟𝑒𝑎, 𝐴1 = π 0.8𝑟 2 ↓ ∆A% = 𝐴 − 𝐴1 𝐴 × 100% = 1 − 𝐴1 𝐴 × 100% = 1 − 𝜋 0.8𝑟 2 𝜋𝑟2 × 100% = 36%
5.
𝑥 𝑥 = 𝑏
6.
34° 180° −
134° 2𝑥 = 34 + 180 − 134 − 15 2𝑥 + 15 = 34 + (180 − 134) 𝑥 = 65 2 = 32.5 °
7.
𝑂 = (0,
0) 𝐴 = (2𝑝, 𝑝) 𝐵 = (2𝑝 + 1, 𝑝 − 3) 𝑂𝐴 = 𝑂𝐵 2𝑝 2 + 𝑝 2 = 2𝑝 + 1 2 + 𝑝 − 3 2 = 1 + 4𝑝 + 9 − 6𝑝 4𝑝2 + 𝑝2 = 4𝑝2 + 1 + 4𝑝 + 𝑝2 + 9 − 6𝑝 2𝑝 = 10 𝑝 = 5
8.
𝑎𝑟𝑒𝑎 𝑜𝑓 𝑄𝑅𝑆𝑇
= 30 ∆𝑃𝑄𝑇~∆𝑃𝑅𝑆 1 2 𝑈𝑋 𝑄𝑇 + 𝑅𝑆 = 30 𝑈 𝑈𝑋 = 4 𝑐𝑚 1 2 𝑈𝑋 6 + 9 = 30 P T Q P S R 6 U 9 X 𝑄𝑇 𝑅𝑆 = 𝑃𝑈 𝑃𝑋 6 9 = 𝑃𝑈 𝑃𝑈 + 𝑈𝑋 𝑃𝑈 = 8 𝑐𝑚 𝑃𝑋 = 𝑃𝑈 + 𝑈𝑋 = 8 + 4 = 12 𝑐𝑚
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