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>> IN THE NAME OF GOD << 
Pushover analysis of simply support steel section beam based on 
plastic hinge concept in MATLAB and SAP2000 
The MATLAB Program is Verified by SAP2000  v.15.1.0  and Experimental Model 
This MATLAB program is written by Salar Delavar Ghashghaei ‐ Date of Publication: July/22/2016 
E‐mail: salar.d.ghashghaei@gmail.com
Figure(1) Two elements beam 
Figure(2) Verification data are gutten from Shun‐ichi Nakamura paper (Bending and shear strengths of partially 
encased composite I‐girders‐G Shun‐ichi Nakamura _2003) doi:10.1016/S0143‐974X(03)00104‐4 
Figure(3) Simply support beam model in SAP2000 
Define Parameters:
P4=0; % [kN]
P5=1; % [kN]
P6=0; % [kN.mm]
L = 1800; % [mm]
a1=1500;
b1=L-a1;
a2=300;
b2=L-a2;
U5max=20;% ultimate displacement[mm] [dof(5)]
%% Section Properties
tf1=12;% [mm] I section thickness on Top flange
bf1=200;% [mm] I section width on Top flange
tw=6;% [mm] I section thickness of Web
hw=876;% [mm] Height of web
tf2=12;% [mm] I section thickness on Bottom flange
bf2=200;% [mm] I section width on Bottom flange
fy =372.3;% [N/mm^2] Yield strength of steel section
Es =2e5;% [N/mm^2] Modulus of elasticity of steel section
fu=511.4;% Ultimate steel stress
ey=fy/Es;% Yield steel strain
esh=0.02;% Strain at steel strain-hardening
esu=0.14;% Ultimate steel strain
Esh=(fu-fy)/(esu-esh);
h=ptf1+ptf2+tf1+tf2+hw;% [mm] Height of Section
Ie=((tw*hw^3)/12)+2*(((bf1*tf1^3)/12)+(bf1*tf1)*(0.5*h-0.5*tf1-
ptf1)^2)+2*(((pbf1*ptf1^3)/12)+(pbf1*ptf1)*(0.5*h-0.5*ptf1)^2);
A=2*tf1*bf1+tw*hw;
E = 200; % [kN/mm^2]
Ny= 0.3; % Poisson's ratio
EI = E*Ie; % [kN.mm^2]
EA = E*A; % [kN]
As = 5400;% [mm^2]
G = E/(2*(1+Ny)); % Shear modulus
fi = (12*EI)/(G*As*L^2);% Timoshenko beam coefficient
m = 3500; % number of calculation
itermax = 5000;% maximum number of iterations
tolerance = 1e-12; % specified tolerance for convergence
lanX=1;lanY=0;
% Element stiffness coefficient
A=((4+fi)*EI/L)*(1/(1+fi));B=(6*EI/L^2)*(1/(1+fi));C=((2fi)*EI/L)*(1/(1+fi));
D=(12*EI/L^3)*(1/(1+fi));G=(EA/L);
Plastic Hinge Properties: 
Lp=0.1*L; % Plastic hinge length
Cur=[0;0.0041;0.3111]*10^-3; % [1/mm] Curvature
M=[0;1.0610;1.6405]*10^6; % [kN.mm] Moment
t=Cur*Lp; % [rad] Rotation
MATLAB Analysis Report:
(+)It is converged in 2 iterations for increment 1 
(+)It is converged in 2 iterations for increment 2 
(+)It is converged in 2 iterations for increment 3 
(+)It is converged in 2 iterations for increment 4 
(+)It is converged in 2 iterations for increment 5 
(+)It is converged in 2 iterations for increment 6 
(+)It is converged in 2 iterations for increment 7 
(+)It is converged in 2 iterations for increment 8 
(+)It is converged in 2 iterations for increment 9 
(+)It is converged in 2 iterations for increment 10 
. 
. 
. 
(+)It is converged in 2 iterations for increment 701 
(+)It is converged in 2 iterations for increment 702 
(+)It is converged in 2 iterations for increment 703 
(+)It is converged in 2 iterations for increment 704 
(+)It is converged in 2 iterations for increment 705 
(+)It is converged in 2 iterations for increment 706 
(+)It is converged in 2 iterations for increment 707 
(+)It is converged in 2 iterations for increment 708 
(‐)For increment 709 trail iteration reached to Ultimate 5000 
    ## The solution for this step is not converged ## 
(‐)For increment 710 trail iteration reached to Ultimate 5000 
    ## The solution for this step is not converged ## 
(‐)For increment 711 trail iteration reached to Ultimate 5000 
    ## The solution for this step is not converged ## 
(+)It is converged in 2801 iterations for increment 712 
(+)It is converged in 256 iterations for increment 713 
(+)It is converged in 252 iterations for increment 714 
(+)It is converged in 248 iterations for increment 715 
 
Displacement at middle [dof(5)] reched to ultimate displacement 
 
============== Internal Force ================ 
+ =============== Nonlinear ================ + 
     (f3)             (f6)          (f7)          (f10)      
‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐ 
  1.0e+006 * 
 
   ‐0.0000    0.0015   ‐0.0015    0.0000 
   ‐0.0000    0.0030   ‐0.0030    0.0000 
   ‐0.0000    0.0045   ‐0.0045    0.0000 
   ‐0.0000    0.0060   ‐0.0060   ‐0.0000 
    0.0000    0.0075   ‐0.0075   ‐0.0000 
    0.0000    0.0090   ‐0.0090   ‐0.0000 
    0.0000    0.0105   ‐0.0105   ‐0.0000 
   ‐0.0000    0.0120   ‐0.0120   ‐0.0000 
   ‐0.0000    0.0135   ‐0.0135    0.0000 
   ‐0.0000    0.0150   ‐0.0150    0.0000 
   ‐0.0000    0.0165   ‐0.0165    0.0000 
    0.0000    0.0180   ‐0.0180   ‐0.0000 
    0.0000    0.0195   ‐0.0195    0.0000 
    0.0000    0.0210   ‐0.0210    0.0000 
. 
. 
. 
 
   ‐0.0000    1.0560   ‐1.0560   ‐0.0000 
   ‐0.0000    1.0575   ‐1.0575    0.0000 
   ‐0.0000    1.0590   ‐1.0590   ‐0.0000 
   ‐0.0000    1.0605   ‐1.0605    0.0000 
    0.0000    1.0620   ‐1.0620   ‐0.0000 
   ‐0.0000    1.0635   ‐1.0635    0.0000 
   ‐0.0000    1.0650   ‐1.0650    0.0000 
    0.0000    1.0665   ‐1.0665    0.0000 
    0.0000    1.0680   ‐1.0680   ‐0.0000 
   ‐0.0000    1.0695   ‐1.0695    0.0000 
     0.0000    1.0710   ‐1.0710   0.0000 
   ‐0.0000    1.0725   ‐1.0725    0.0000 
 
+ ================ Linear ================== + 
     (f3)            (f6)          (f7)          (f10)      
‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐ 
  1.0e+006 * 
 
   ‐0.0000    0.0015   ‐0.0015    0.0000 
   ‐0.0000    0.0030   ‐0.0030    0.0000 
   ‐0.0000    0.0045   ‐0.0045    0.0000 
   ‐0.0000    0.0060   ‐0.0060    0.0000 
    0.0000    0.0075   ‐0.0075   ‐0.0000 
   ‐0.0000    0.0090   ‐0.0090    0.0000 
   ‐0.0000    0.0105   ‐0.0105    0.0000 
   ‐0.0000    0.0120   ‐0.0120    0.0000 
    0.0000    0.0135   ‐0.0135   ‐0.0000 
    0.0000    0.0150   ‐0.0150   ‐0.0000 
    0.0000    0.0165   ‐0.0165   ‐0.0000 
   ‐0.0000    0.0180   ‐0.0180    0.0000 
    0.0000    0.0195   ‐0.0195   ‐0.0000 
   ‐0.0000    0.0210   ‐0.0210    0.0000 
    0.0000    0.0225   ‐0.0225    0.0000 
   ‐0.0000    0.0240   ‐0.0240    0.0000 
. 
. 
. 
   ‐0.0000    1.0545   ‐1.0545    0.0000 
    0.0000    1.0560   ‐1.0560   ‐0.0000 
    0.0000    1.0575   ‐1.0575    0.0000 
    0.0000    1.0590   ‐1.0590   ‐0.0000 
   ‐0.0000    1.0605   ‐1.0605    0.0000 
    0.0000    1.0620   ‐1.0620    0.0000 
    0.0000    1.0635   ‐1.0635   ‐0.0000 
   ‐0.0000    1.0650   ‐1.0650    0.0000 
    0.0000    1.0665   ‐1.0665    0.0000 
    0.0000    1.0680   ‐1.0680   ‐0.0000 
   ‐0.0000    1.0695   ‐1.0695    0.0000 
   ‐0.0000    1.0710   ‐1.0710    0.0000 
    0.0000    1.0725   ‐1.0725   ‐0.0000 
============================================== 
SAP2000 Analysis Report: 
B E G I N A N A L Y S I S 2016/07/21 19:37:53
RUNNING ANALYSIS WITHIN THE GUI PROCESS
USING THE ADVANCED SOLVER (PROVIDES LIMITED INSTABILITY INFORMATION)
NUMBER OF JOINTS = 3
WITH RESTRAINTS = 2
NUMBER OF FRAME/CABLE/TENDON ELEMENTS = 2
NUMBER OF LOAD PATTERNS = 1
NUMBER OF ACCELERATION LOADS = 6
NUMBER OF LOAD CASES = 2
N O N L I N E A R S T A T I C A N A L Y S I S 19:37:53
CASE: 1
STARTING FROM ZERO (UNSTRESSED) INITIAL CONDITIONS
LOAD CONTROL TYPE = FORCE
NUMBER OF STAGES = 0
TYPE OF GEOMETRIC NONLINEARITY = NONE
INCLUDE ELASTIC MATERIAL NONLINEARITY = YES
INCLUDE INELASTIC MATERIAL NONLINEARITY = YES
METHOD TO USE WHEN HINGES DROP LOAD = UNLOAD ENTIRE STRUCTURE
SAVE POSITIVE INCREMENTS ONLY = YES
RELATIVE FORCE CONVERGENCE TOLERANCE = 0.000100
RELATIVE EVENT TOLERANCE = 0.010000
E L E M E N T F O R M A T I O N 19:37:53
Saved Null Total Iteration Relative Curr Step Curr Sum Max Sum
Steps Steps Steps this Step Unbalance Size of Steps of Steps
( 100 50 200 10/40 1.000000 0.100000 1.000000 1.000000)
1 0 1 Conv 1 2.17E-15 0.100000 0.100000 0.100000
2 0 2 Conv 1 4.34E-15 0.100000 0.200000 0.200000
3 0 3 Conv 1 8.67E-15 0.100000 0.300000 0.300000
4 0 4 Conv 1 8.67E-15 0.100000 0.400000 0.400000
5 0 5 Conv 1 8.68E-15 0.100000 0.500000 0.500000
6 0 6 Conv 1 2.03E-16 0.100000 0.600000 0.600000
7 0 7 Conv 1 2.37E-16 0.100000 0.700000 0.700000
8 0 8 Conv 1 2.71E-16 0.100000 0.800000 0.800000
9 0 9 Conv 1 3.05E-16 0.100000 0.900000 0.900000
10 0 10 Conv 1 3.39E-16 0.100000 1.000000 1.000000
TIME FOR INITIALIZING ANALYSIS = 0.21
TIME FOR CONTROLLING ANALYSIS = 0.02
TIME FOR UPDATING LOADS AND STATE = 0.08
TIME FOR FORMING STIFFNESS MATRIX = 0.05
TIME FOR SOLVING STIFFNESS MATRIX = 0.51
TIME FOR CALCULATING DISPLACEMENTS = 0.06
TIME FOR DETERMINING EVENTS = 0.00
TIME FOR SAVING RESULTS = 0.12
----------
TOTAL TIME FOR THIS ANALYSIS = 1.05
N O N L I N E A R S T A T I C A N A L Y S I S 19:37:54
CASE: PUSH
CONTINUING FROM THE END OF CASE: 1
LOAD CONTROL TYPE = DISPLACEMENT
NUMBER OF STAGES = 0
TYPE OF GEOMETRIC NONLINEARITY = NONE
INCLUDE ELASTIC MATERIAL NONLINEARITY = YES
INCLUDE INELASTIC MATERIAL NONLINEARITY = YES
METHOD TO USE WHEN HINGES DROP LOAD = UNLOAD ENTIRE STRUCTURE
SAVE POSITIVE INCREMENTS ONLY = NO
RELATIVE FORCE CONVERGENCE TOLERANCE = 0.000100
RELATIVE EVENT TOLERANCE = 0.010000
Saved Null Total Iteration Relative Curr Step Curr Sum Max Sum
Steps Steps Steps this Step Unbalance Size of Steps of Steps
( 30 50 200 10/10 1.000000 0.050000 1.000000 1.000000)
1 0 1 Conv 1 6.01E-12 0.050000 0.050000 0.050000
2 0 2 Conv 1 8.02E-12 0.050000 0.100000 0.100000
3 0 3 Conv 1 8.02E-12 0.050000 0.150000 0.150000
4 0 4 Conv 1 8.02E-12 0.050000 0.200000 0.200000
5 0 5 Conv 1 1.60E-11 0.050000 0.250000 0.250000
6 0 6 Conv 1 1.60E-11 0.050000 0.300000 0.300000
7 0 7 Conv 1 1.60E-11 0.050000 0.350000 0.350000
8 0 8 Conv 1 1.60E-11 0.050000 0.400000 0.400000
9 0 9 Conv 1 5.64E-13 0.050000 0.450000 0.450000
10 0 10 Conv 1 6.26E-13 0.050000 0.500000 0.500000
11 0 11 Conv 1 6.43E-13 0.013630 0.513630 0.513630
11 0 12 1 1.560729 0.050000 0.513630 0.513630
12 0 12 Conv 2 0.133201 0.050000 0.563630 0.563630
12 0 13 1 1.693929 0.050000 0.563630 0.563630
13 0 13 Conv 2 0.144569 0.050000 0.613630 0.613630
13 0 14 1 1.705297 0.050000 0.613630 0.613630
14 0 14 Conv 2 0.145539 0.050000 0.663630 0.663630
14 0 15 1 1.706267 0.050000 0.663630 0.663630
15 0 15 Conv 2 0.145622 0.050000 0.713630 0.713630
15 0 16 1 1.706350 0.050000 0.713630 0.713630
16 0 16 Conv 2 0.145629 0.050000 0.763630 0.763630
16 0 17 1 1.706357 0.050000 0.763630 0.763630
17 0 17 Conv 2 0.145629 0.050000 0.813630 0.813630
17 0 18 1 1.706358 0.050000 0.813630 0.813630
18 0 18 Conv 2 0.145629 0.050000 0.863630 0.863630
18 0 19 1 1.706358 0.050000 0.863630 0.863630
19 0 19 Conv 2 0.145629 0.050000 0.913630 0.913630
19 0 20 1 1.706358 0.050000 0.913630 0.913630
20 0 20 Conv 2 0.145629 0.050000 0.963630 0.963630
20 0 21 1 1.280907 0.036370 0.963630 0.963630
21 0 21 Conv 2 0.109319 0.036370 1.000000 1.000000
TIME FOR INITIALIZING ANALYSIS = 0.02
TIME FOR CONTROLLING ANALYSIS = 0.04
TIME FOR UPDATING LOADS AND STATE = 0.03
TIME FOR FORMING STIFFNESS MATRIX = 0.18
TIME FOR SOLVING STIFFNESS MATRIX = 0.76
TIME FOR CALCULATING DISPLACEMENTS = 0.17
TIME FOR DETERMINING EVENTS = 0.00
TIME FOR SAVING RESULTS = 0.16
----------
TOTAL TIME FOR THIS ANALYSIS = 1.36
A N A L Y S I S C O M P L E T E 2016/07/21 19:37:56
Plot : 
 
Figure(4) Steel section in SAP2000 
Figure(5) Plastic hinge (M3) in SAP2000 
Figure(6) Define Load Patterns in SAP2000 
Figure(7) Define Load Cases in SAP2000 
Figure(8) Load cases data in SAP2000 
 
Figure(9) Load application control for nonlinear static analysis in SAP2000 
Figure(10) Pushover analysis result in SAP2000 
Figure(11) Moment diagram in SAP2000 
Figure(12) Moment‐Curvature diagram in MATLAB 
Figure(13) Moment‐Rotation diagram during the analysis in MATLAB 
Figure(14)  Last step loading diagram of Shear and Moment during the analysis in MATLAB 
Figure(15) Last step loading deflection shape in MATLAB 
Figure(16) Base shear‐Displacement diagram in SAP2000 ,MATLAB and Experiment 

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