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Data Structures & Algorithms
Resource Person:
Muhammad Abrar
Sorting
 Sorting methods can be divided into two types based
upon the complexity of their algorithms.
 One type of sorting algorithms includes
 Bubble Sort
 Insertion Sort
 Selection Sort
 Other type consists is
 Merge Sort
 Choice of a method depends upon the type and size of
data to be sorted.
Truth in CS Act (proof is ur job)
 NOBODY EVER USES BUBBLE SORT
 NOBODY
 NOT EVER
 BECAUSE IT IS EXTREMELY
INEFFICIENT
LB
Insertion sort
 The insertion sort works just like its name
suggests –
 it inserts each item into its proper place in the
final list.
 The simplest implementation of this requires
two list structures –
 the source list and the list into which sorted items are
inserted.
Insertion sort
 The insertion sort is a good middle-of-the-road choice for
sorting lists of a few thousand items or less.
 Insertion sort is over twice as fast as the bubble sort and
 almost 40% faster than the selection sort. The insertion
sort shouldn't be used for sorting lists larger than a
couple thousand items or repetitive sorting of lists larger
than a couple hundred items.
Insertion sort
 Suppose an array A with n elements
A[1], A[2],……..A[N] in memory.
 The insertion sort algorithm scan A form
A[1] to A[N], inserting each elements
A[K] into its proper position in the
previously sorted sub array A[1],
A[2]……….A[K-1] that is,
Insertion sort
 Pass1: A[1] by itself is trivially sorted.
 Pass 2: A[2] in inserted either before or after A[1] so
that A[1], A[2] is sorted.
 Pass 3: A[3] is inserted into its proper position in A[1],
A[2], so that all the three elements will be sorted.
 Pass 4. A[4] is inserted into its proper place so that…..
 Pass N. A[N] is inserted into its proper place so that
A[1], A[2], …………A[N] is sorted.
Insertion Sort cont…..
• The insertion sort algorithm sorts the list by moving
each element to its proper place
Figure 6: Array list to be sorted
Figure 7: Sorted and unsorted portions of the array list
Insertion Sort Algorithm (Cont’d)
Figure 8: Move list[4] into list[2]
Figure 9: Copy list[4] into temp
Insertion Sort Algorithm (Cont’d)
Figure 10: Array list before copying list[3] into list[4], then
list[2] into list[3]
Figure 11: Array list after copying list[3] into list[4], and then
list[2] into list[3]
Insertion Sort Algorithm (Cont’d)
Figure 12: Array list after copying temp into list[2]
12
INSERTION SORT
 The basic idea of Insertion Sort for
the items A (1 : n) is as follows:
 A (1) is already sorted
 for j2 to n do
 place A(j) in its correct position in the
sorted set A(1 : j-1)
 repeat.
Insertion sort algorithm
 INSERTION ( A, N).
this algorithm sorts the array A with N elements.
1. Set A[0]:= -infinity.
2. Repeat step 3 to 5 for K=: 2 to N
3. Set temp:= A[K] and PTR:= K-1
4. Repeat while TEMP < A[PTR]
a. Set A[PTR+1]:= A[PTR] [moves elements forward]
b. Set PTR:= PTR-1
[end of loop]
5. Set A[PTR + 1]:=TEMP. [insert elements in proper
position]
[end of step 2 loop]
6. exit
14
INSERTION SORT (Contd..)
Procedure Insertion sort (A, n)
A(0)  -infinity // create a smallest //
// value to exit while loop //
for j2 to n do // A(1 : j-1) is sorted //
Item A(j) ;
ij-1
while item < A (i) do // 0<=i<j //
A (i+1)A(i) ; ii-1
Repeat
A (i+1)item
Repeat
End Insertion sort
15
INSERTION SORT (Contd..)
Example: Sort A = ( 15, 10, 5, 6, 8 )
1, 2, 3, 4, 5
n = 5 A(0) = - 
15 is already sorted
Now j2 itemA(2) = 10
10 is to be inserted in (15)
ij-1 = 1 item = 10 < A(i) = 15
so A(i+1 = 2)A(i) i1-1=0
Now item>A(1) = -  so while loop is exited
and A(0+1)=A(1)item
16
INSERTION SORT (Contd..)
So, the current sorted list is (10, 15)
Now j3 itemA(j) =5
5 is to be inserted in (10 15)
i2, item=5<A(1)=15 so
A(i+1)=A(3)A(i)=15, i2-1=1
item=5<A(i)=10 so A(2)10
i0, item = 5 >A(0) = - 
so A(1)5
Similarly 6 is inserted at 2nd place and 8 at 3rd
place
So, final sorted list is (5, 6, 8, 10, 15)
Algorithm: INSERTIONSORT
Input: An array A[1..n] of n elements.
Output: A[1..n] sorted in nondecreasing
order.
1. for i  2 to n
2. x  A[i]
3. j  i - 1
4. while (j >0) and (A[j] > x)
5. A[j + 1]  A[j]
6. j  j - 1
7. end while
8. A[j + 1]  x
9. end for
Example sort : 34 8 64 51 32 21
An Example: Insertion Sort
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
30 10 40 20
1 2 3 4
i =  j =  key = 
A[j] =  A[j+1] = 
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
30 10 40 20
1 2 3 4
i = 2 j = 1 key = 10
A[j] = 30 A[j+1] = 10
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
30 30 40 20
1 2 3 4
i = 2 j = 1 key = 10
A[j] = 30 A[j+1] = 30
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
30 30 40 20
1 2 3 4
i = 2 j = 1 key = 10
A[j] = 30 A[j+1] = 30
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
30 30 40 20
1 2 3 4
i = 2 j = 0 key = 10
A[j] =  A[j+1] = 30
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
30 30 40 20
1 2 3 4
i = 2 j = 0 key = 10
A[j] =  A[j+1] = 30
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 2 j = 0 key = 10
A[j] =  A[j+1] = 10
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 3 j = 0 key = 10
A[j] =  A[j+1] = 10
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 3 j = 0 key = 40
A[j] =  A[j+1] = 10
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 3 j = 0 key = 40
A[j] =  A[j+1] = 10
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 3 j = 2 key = 40
A[j] = 30 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 3 j = 2 key = 40
A[j] = 30 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 3 j = 2 key = 40
A[j] = 30 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 4 j = 2 key = 40
A[j] = 30 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 4 j = 2 key = 20
A[j] = 30 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 4 j = 2 key = 20
A[j] = 30 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 4 j = 3 key = 20
A[j] = 40 A[j+1] = 20
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 20
1 2 3 4
i = 4 j = 3 key = 20
A[j] = 40 A[j+1] = 20
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 40
1 2 3 4
i = 4 j = 3 key = 20
A[j] = 40 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 40
1 2 3 4
i = 4 j = 3 key = 20
A[j] = 40 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 40
1 2 3 4
i = 4 j = 3 key = 20
A[j] = 40 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 40
1 2 3 4
i = 4 j = 2 key = 20
A[j] = 30 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 40 40
1 2 3 4
i = 4 j = 2 key = 20
A[j] = 30 A[j+1] = 40
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 30 40
1 2 3 4
i = 4 j = 2 key = 20
A[j] = 30 A[j+1] = 30
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 30 40
1 2 3 4
i = 4 j = 2 key = 20
A[j] = 30 A[j+1] = 30
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 30 40
1 2 3 4
i = 4 j = 1 key = 20
A[j] = 10 A[j+1] = 30
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 30 30 40
1 2 3 4
i = 4 j = 1 key = 20
A[j] = 10 A[j+1] = 30
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 20 30 40
1 2 3 4
i = 4 j = 1 key = 20
A[j] = 10 A[j+1] = 20
InsertionSort(A, n) {
for i = 2 to n {
key = A[i]
j = i - 1;
while (j > 0) and (A[j] > key) {
A[j+1] = A[j]
j = j - 1
}
A[j+1] = key
}
}
10 20 30 40
1 2 3 4
i = 4 j = 1 key = 20
A[j] = 10 A[j+1] = 20
Done!
comparison
 Take an array of 1000 items,
compare both the bubble sort and
insertion sort,
 How many comparison will be made each
sorting algorithm
 How many swaps will be made each
sorting algorithm.
 Write a general formula for comparison
and swaps for both the algorithm.

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insertion sort.ppt

  • 1. Data Structures & Algorithms Resource Person: Muhammad Abrar
  • 2. Sorting  Sorting methods can be divided into two types based upon the complexity of their algorithms.  One type of sorting algorithms includes  Bubble Sort  Insertion Sort  Selection Sort  Other type consists is  Merge Sort  Choice of a method depends upon the type and size of data to be sorted.
  • 3. Truth in CS Act (proof is ur job)  NOBODY EVER USES BUBBLE SORT  NOBODY  NOT EVER  BECAUSE IT IS EXTREMELY INEFFICIENT LB
  • 4. Insertion sort  The insertion sort works just like its name suggests –  it inserts each item into its proper place in the final list.  The simplest implementation of this requires two list structures –  the source list and the list into which sorted items are inserted.
  • 5. Insertion sort  The insertion sort is a good middle-of-the-road choice for sorting lists of a few thousand items or less.  Insertion sort is over twice as fast as the bubble sort and  almost 40% faster than the selection sort. The insertion sort shouldn't be used for sorting lists larger than a couple thousand items or repetitive sorting of lists larger than a couple hundred items.
  • 6. Insertion sort  Suppose an array A with n elements A[1], A[2],……..A[N] in memory.  The insertion sort algorithm scan A form A[1] to A[N], inserting each elements A[K] into its proper position in the previously sorted sub array A[1], A[2]……….A[K-1] that is,
  • 7. Insertion sort  Pass1: A[1] by itself is trivially sorted.  Pass 2: A[2] in inserted either before or after A[1] so that A[1], A[2] is sorted.  Pass 3: A[3] is inserted into its proper position in A[1], A[2], so that all the three elements will be sorted.  Pass 4. A[4] is inserted into its proper place so that…..  Pass N. A[N] is inserted into its proper place so that A[1], A[2], …………A[N] is sorted.
  • 8. Insertion Sort cont….. • The insertion sort algorithm sorts the list by moving each element to its proper place Figure 6: Array list to be sorted Figure 7: Sorted and unsorted portions of the array list
  • 9. Insertion Sort Algorithm (Cont’d) Figure 8: Move list[4] into list[2] Figure 9: Copy list[4] into temp
  • 10. Insertion Sort Algorithm (Cont’d) Figure 10: Array list before copying list[3] into list[4], then list[2] into list[3] Figure 11: Array list after copying list[3] into list[4], and then list[2] into list[3]
  • 11. Insertion Sort Algorithm (Cont’d) Figure 12: Array list after copying temp into list[2]
  • 12. 12 INSERTION SORT  The basic idea of Insertion Sort for the items A (1 : n) is as follows:  A (1) is already sorted  for j2 to n do  place A(j) in its correct position in the sorted set A(1 : j-1)  repeat.
  • 13. Insertion sort algorithm  INSERTION ( A, N). this algorithm sorts the array A with N elements. 1. Set A[0]:= -infinity. 2. Repeat step 3 to 5 for K=: 2 to N 3. Set temp:= A[K] and PTR:= K-1 4. Repeat while TEMP < A[PTR] a. Set A[PTR+1]:= A[PTR] [moves elements forward] b. Set PTR:= PTR-1 [end of loop] 5. Set A[PTR + 1]:=TEMP. [insert elements in proper position] [end of step 2 loop] 6. exit
  • 14. 14 INSERTION SORT (Contd..) Procedure Insertion sort (A, n) A(0)  -infinity // create a smallest // // value to exit while loop // for j2 to n do // A(1 : j-1) is sorted // Item A(j) ; ij-1 while item < A (i) do // 0<=i<j // A (i+1)A(i) ; ii-1 Repeat A (i+1)item Repeat End Insertion sort
  • 15. 15 INSERTION SORT (Contd..) Example: Sort A = ( 15, 10, 5, 6, 8 ) 1, 2, 3, 4, 5 n = 5 A(0) = -  15 is already sorted Now j2 itemA(2) = 10 10 is to be inserted in (15) ij-1 = 1 item = 10 < A(i) = 15 so A(i+1 = 2)A(i) i1-1=0 Now item>A(1) = -  so while loop is exited and A(0+1)=A(1)item
  • 16. 16 INSERTION SORT (Contd..) So, the current sorted list is (10, 15) Now j3 itemA(j) =5 5 is to be inserted in (10 15) i2, item=5<A(1)=15 so A(i+1)=A(3)A(i)=15, i2-1=1 item=5<A(i)=10 so A(2)10 i0, item = 5 >A(0) = -  so A(1)5 Similarly 6 is inserted at 2nd place and 8 at 3rd place So, final sorted list is (5, 6, 8, 10, 15)
  • 17. Algorithm: INSERTIONSORT Input: An array A[1..n] of n elements. Output: A[1..n] sorted in nondecreasing order. 1. for i  2 to n 2. x  A[i] 3. j  i - 1 4. while (j >0) and (A[j] > x) 5. A[j + 1]  A[j] 6. j  j - 1 7. end while 8. A[j + 1]  x 9. end for Example sort : 34 8 64 51 32 21
  • 18. An Example: Insertion Sort InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 30 10 40 20 1 2 3 4 i =  j =  key =  A[j] =  A[j+1] = 
  • 19. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 30 10 40 20 1 2 3 4 i = 2 j = 1 key = 10 A[j] = 30 A[j+1] = 10
  • 20. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 30 30 40 20 1 2 3 4 i = 2 j = 1 key = 10 A[j] = 30 A[j+1] = 30
  • 21. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 30 30 40 20 1 2 3 4 i = 2 j = 1 key = 10 A[j] = 30 A[j+1] = 30
  • 22. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 30 30 40 20 1 2 3 4 i = 2 j = 0 key = 10 A[j] =  A[j+1] = 30
  • 23. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 30 30 40 20 1 2 3 4 i = 2 j = 0 key = 10 A[j] =  A[j+1] = 30
  • 24. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 2 j = 0 key = 10 A[j] =  A[j+1] = 10
  • 25. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 3 j = 0 key = 10 A[j] =  A[j+1] = 10
  • 26. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 3 j = 0 key = 40 A[j] =  A[j+1] = 10
  • 27. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 3 j = 0 key = 40 A[j] =  A[j+1] = 10
  • 28. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 3 j = 2 key = 40 A[j] = 30 A[j+1] = 40
  • 29. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 3 j = 2 key = 40 A[j] = 30 A[j+1] = 40
  • 30. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 3 j = 2 key = 40 A[j] = 30 A[j+1] = 40
  • 31. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 4 j = 2 key = 40 A[j] = 30 A[j+1] = 40
  • 32. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 4 j = 2 key = 20 A[j] = 30 A[j+1] = 40
  • 33. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 4 j = 2 key = 20 A[j] = 30 A[j+1] = 40
  • 34. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 4 j = 3 key = 20 A[j] = 40 A[j+1] = 20
  • 35. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 20 1 2 3 4 i = 4 j = 3 key = 20 A[j] = 40 A[j+1] = 20
  • 36. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 40 1 2 3 4 i = 4 j = 3 key = 20 A[j] = 40 A[j+1] = 40
  • 37. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 40 1 2 3 4 i = 4 j = 3 key = 20 A[j] = 40 A[j+1] = 40
  • 38. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 40 1 2 3 4 i = 4 j = 3 key = 20 A[j] = 40 A[j+1] = 40
  • 39. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 40 1 2 3 4 i = 4 j = 2 key = 20 A[j] = 30 A[j+1] = 40
  • 40. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 40 40 1 2 3 4 i = 4 j = 2 key = 20 A[j] = 30 A[j+1] = 40
  • 41. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 30 40 1 2 3 4 i = 4 j = 2 key = 20 A[j] = 30 A[j+1] = 30
  • 42. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 30 40 1 2 3 4 i = 4 j = 2 key = 20 A[j] = 30 A[j+1] = 30
  • 43. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 30 40 1 2 3 4 i = 4 j = 1 key = 20 A[j] = 10 A[j+1] = 30
  • 44. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 30 30 40 1 2 3 4 i = 4 j = 1 key = 20 A[j] = 10 A[j+1] = 30
  • 45. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 20 30 40 1 2 3 4 i = 4 j = 1 key = 20 A[j] = 10 A[j+1] = 20
  • 46. InsertionSort(A, n) { for i = 2 to n { key = A[i] j = i - 1; while (j > 0) and (A[j] > key) { A[j+1] = A[j] j = j - 1 } A[j+1] = key } } 10 20 30 40 1 2 3 4 i = 4 j = 1 key = 20 A[j] = 10 A[j+1] = 20 Done!
  • 47. comparison  Take an array of 1000 items, compare both the bubble sort and insertion sort,  How many comparison will be made each sorting algorithm  How many swaps will be made each sorting algorithm.  Write a general formula for comparison and swaps for both the algorithm.