Ignore what I have written because Im pretty sure its wrong. Thank.pdf
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Ignore what I have written because I\'m pretty sure its wrong. Thanks! Deliver the assignment to my office, 4502 French Hal! West or Scan your assignment and send it as an email attachment. Write the complex number, z = a + bi, in polar form, z = r (cos theta + i sin theta), with argument theta between 0 and 2 pi. -3i 3 - Squareroot 3i -1 + i II. Find the product, z_1z_2, and the quotient, z_1/z_2. Express your answer in polar form. z_1 = 3(cos 15 degree + i sin 15 degree) z_2 = 6(cos 20 degree + i sin 20 degree) z_1z_2: ____ z_1/z_2: ____ z_1 = 21 (cso pi/5 + i sin pi/5) z_2 = 7(cos 2 pi/3 + i sin 2 pi/3) z_1z_2: ____ z_1/z_2: ____ Solution I) 1) -3i r=[02+(-3)2]=3 =tan-1(-3/0) =3/2 polar form is 3(cos(3/2)+i sin(3/2)) 2) 3-3i r=[32+(-3)2]=12=23 =tan-1(-3/3) =11/6 polar form is 23(cos(11/6)+i sin(11/6)) 3) -1+i r=[(-1)2+12]=2 =tan-1(1/-1) =3/4 polar form is 2(cos(3/4)+i sin(3/4)) =========================================================== II) 1) z1=3(cos15o+isin15o), z2=6(cos20o+isin20o) z1z2=3(cos15o+isin15o)*6(cos20o+isin20o) z1z2=3*6(cos(15+20)o+isin(15+20)o) z1z2=18(cos(35)o+isin(35)o) z1/z2=3(cos15o+isin15o)/[6(cos20o+isin20o)] z1/z2=(3/6)(cos(15-20)o+isin(15-20)o) z1/z2=(1/2)(cos(-5)o+isin(-5)o) z1/z2=(1/2)(cos(355)o+isin(355)o) 2) z1=21(cos(/5)+isin(/5)), z2=7(cos(2/3)+isin(2/3)) z1z2=21(cos(/5)+isin(/5))*7(cos(2/3)+isin(2/3)) z1z2=21*7(cos((/5)+(2/3))+isin((/5)+(2/3))) z1z2=147(cos(13/15)+isin(13/15)) z1/z2=21(cos(/5)+isin(/5))/7(cos(2/3)+isin(2/3)) z1/z2=3(cos((/5)-(2/3))+isin((/5)-(2/3))) z1/z2=3(cos(-7/15)+isin(-7/15)) z1/z2=3(cos(23/15)+isin(23/15)).
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![Ignore what I have written because I'm pretty sure its wrong. Thanks! Deliver the assignment to
my office, 4502 French Hal! West or Scan your assignment and send it as an email attachment.
Write the complex number, z = a + bi, in polar form, z = r (cos theta + i sin theta), with argument
theta between 0 and 2 pi. -3i 3 - Squareroot 3i -1 + i II. Find the product, z_1z_2, and the
quotient, z_1/z_2. Express your answer in polar form. z_1 = 3(cos 15 degree + i sin 15 degree)
z_2 = 6(cos 20 degree + i sin 20 degree) z_1z_2: ____ z_1/z_2: ____ z_1 = 21 (cso pi/5 + i sin
pi/5) z_2 = 7(cos 2 pi/3 + i sin 2 pi/3) z_1z_2: ____ z_1/z_2: ____
Solution
I)
1)
-3i
r=[02+(-3)2]=3
=tan-1(-3/0) =3/2
polar form is 3(cos(3/2)+i sin(3/2))
2)
3-3i
r=[32+(-3)2]=12=23
=tan-1(-3/3) =11/6
polar form is 23(cos(11/6)+i sin(11/6))
3)
-1+i
r=[(-1)2+12]=2
=tan-1(1/-1) =3/4
polar form is 2(cos(3/4)+i sin(3/4))
===========================================================
II)
1)
z1=3(cos15o+isin15o), z2=6(cos20o+isin20o)
z1z2=3(cos15o+isin15o)*6(cos20o+isin20o)
z1z2=3*6(cos(15+20)o+isin(15+20)o)
z1z2=18(cos(35)o+isin(35)o)
z1/z2=3(cos15o+isin15o)/[6(cos20o+isin20o)]
z1/z2=(3/6)(cos(15-20)o+isin(15-20)o)](https://image.slidesharecdn.com/ignorewhatihavewrittenbecauseimprettysureitswrong-230903213329-44a6d8a3/85/Ignore-what-I-have-written-because-Im-pretty-sure-its-wrong-Thank-pdf-1-320.jpg)
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Once we are done with the identification, we acquire physical and digital data.After this we
isolate ,secure and preserve these data.We do this because ,it is required for furthur
investigation.We also see to it that these events take place in proper order,one after other like a
chain of events happening one after another.
Collection:
In this phase,we extract the preserved data and if required we perform duplicate copies of these
data.Bacause for analysis and examination each piece of data is important.So proper collection is
required.
Examination:
Identification and locating the potential evidence from the collected data is known as
Examination phase. Examination phase has to be done in a very careful way.The task of
determining the significant evidences and drawing conclusions based on the evidences found is
done in Analysis phase.
Presentation:
Our findings from the examination and analysis phase,which is done prior to this step is
presented.The results obtained are presented.
The most challenging step as a whole is a examination and analysis phase because the whole
outcome of the study depends on that.If this step is not done carefully,then investigation may
produce false outcomes.Since this is a matter of forensic science,usually people\'s life will be
involved here. So false result may result in punishment to good person.So forensic examination
decides the life of the person ,whether he is a good person or a person who deserve punishment
due to his wrong deeds..
ArticleHinduism and Caste Systemby Jayaram VHinduism is a univ.pdf
Article
Hinduism and Caste System
by Jayaram V
Hinduism is a universal religion. Its primary emphasis is on universal brotherhood. It views the
world as one family. It believes that man is divine in nature and realization of that supreme truth
as the primary aim of all human activity. It is therefore unfortunate that for a very long time this
religion of great antiquity has been in the clutches a few privileged castes. It would be a great
service to the cause of Hinduism if the present day Vedic teachers identify bright children from
the lower castes and start teaching them the Vedas and the Upanishads and allow them to serve
God in the temples of India. The strength of Christianity stems from dedicated missionaries who
come from all sections of society. The weakness of Hinduism and of Hindu society is a caste
system, which divides people into divergent and bickering groups and keeps them apart. Perhaps
there is no other nation in the world that is as openly and shamelessly as racial as India. To be
born in an upper caste is a matter of pride whether the family to which a person belongs deserves
it or not. A number of Indians who visit foreign countries often complain about being treated
differently on account of their skin color or accent. They overlook the fact that a vast number of
people in their own country exhibit a far greater obsession with an accent, skin color, and caste.
Indian film stars put on white makeup, on the screen, and off the screen, even if they are black,
to look acceptable and desirable. The country\'s democracy is not a true democracy, but
autocracy, where people vote and leaders are elected to cast lines. The Indian political parties
thrive and succeed by appealing to this base emotion of people. There are countless scholars who
justify Hindu caste system quoting chapter and verse from the scriptures, ignoring the fact that
they were convenient interpolations or authored by bigoted scholars in an otherwise sacred lore
to justify a cruel and unjust system using the very authority of God. Caste System has been the
bane of Hindu society for centuries. In terms of impact, it did much greater damage for a much
longer period to a great many people than the slave system of the western world or the witch-
hunting practices of medieval Europe. The Hindu caste system was a clever invention of the later
Vedic society, justified by a few lawmakers. The upper castes found it convenient to retain and
perpetuate their social and religious distinction and political and economic advantage. With the
exception of Saivism and a few ascetic traditions, most of the ancient sects of Hinduism were
caste biased. The idea of staying away from unclean people is understandable in a society that
was obsessed with the concept of physical and mental purity. There is nothing unusual with
people who are selective in choosing their friends and relationships. It is normal behavior to stay
away from people who are found to be socially deviant, untrustw.
Can someone solveexplain this I thought I was understanding this, .pdf
Can someone solve/explain this? I thought I was understanding this, but I think I\'ve confused
myself.
A. Find the length of the curve and the area under the curve where x=0, x=2pi, y=0, y=sin2x+2.
B. What if y=sin10x +2? What is the pattern about the length and/or area? (Sketch the graph)
Solution
A. here the function sin(2x) 2 always lies above x-axis(y=0). So we can directly
integrate from x=0 to x=2pi. integral of sin(2x) in the given range is 0. So the area under the
curve is 2*(2pi-0)= 4*pi.
C The ame compound componda with F Souls . E Difluut eoupou ds with.pdf
C The ame compound componda with F Souls . E | Difluut eoupou ds with different foumulas |-
F None of the above The same c compomds th ifeen fommlas Nome of the abore Pape 4 of 6
Ch4 Tet-Sieoebamisty (100 pts) C Thesame compouna CI H CI CH C Theszme compouni ith
different formms Nome of the aboce Ca Pape 5 of 6
Solution
A. Enantiomers since non superimposible mirror images to each other
B. Enantiomers
C. Same compound
D. Same compound, Cis 1,2-dimethyl cyclohexane
E. Diastereomers, since nonsuperimpisible non mirror images to each other
F. Diastereomers
G. Enantiomers
H. Same compound.
Background Sometimes the standard C libraries (stdio.h, stdlib.h, e.pdf
Background: Sometimes the standard C libraries (stdio.h, stdlib.h, etc) are not extensive enough
to handle every programming need. If you find yourself rewriting or reusing functions you’ve
written earlier like those used to calculate statistical parameters (mean, variance etc), copying the
code again and again is inefficient. If you could write the code once, troubleshoot it so it works,
and have it compiled in its own object file, you could then link these object files to your source
code object file and not have to rewrite all the functions. ------------------------------------------------
--------------------------------------------------------------------------------------- Page 2 Part I – [100
points] Description Your task is to create a personal library to implement a statistic package on
any given data (assume that the data is always of type float). To do this you must create: 1. a
header file (stats.h) with 5 function prototypes: § maximum() § minimum() § mean() – equation:
= = 1 0 [ ] 1 N i x i N x § variance() – equation: 2 1 0 2 ( [ ] ) 1 1 x i x N N i = = § histogram()
2. five (5) implementation files with each of functions listed above – min.c, max.c, mean.c,
variance.c, and histogram.c You will then write C code (main.c) that asks the user for the data
file he/she wishes to compute the statistics for and displays the results to the user. YOU WILL
NOT WRITE ANY STATISTICS FUNCTIONS IN main.c – you will simply call the functions
prototyped in stats.h and coded in min.c, max.c, mean.c, variance.c, and histogram.c!!!
Procedure: (Refer to textbook pg 669-677) 1. Create the header file stats.h: a. Start with a block
comment summarizing the purpose of the header file b. # define any constant that you need for
the header file (NOT YOUR CODE) c. Individual function prototypes (with introductory
comments stating purpose of each function) d. Save e. Below is the template for stats.h #ifndef
STATS_H #define STATS_H float minimum(…); // NOTE: You need to complete the
prototypes float maximum(…); float mean(…); float variance(…); void histogram(…); #endif //
STATS_H_INCLUDED EGR 107 Page 3 2. Create 5 implementation files (min.c, max.c,
mean.c, variance.c, histogram.c) a. Start with a block comment summarizing the purpose of each
implementation file b. #include the necessary standard C libraries for each function c. #include
“stats.h” – the angular brackets (< >) are used for standard C libraries found in the system
directory, the quotation marks (“ ”) indicate a custom library found in the SAME directory as
your code. d. #define – any constants for that particular implementation file e. Each file will
contain one function as you would normally write it. i.
The first four files will calculate maximum, minimum, mean, and variance and return one value
each time (so they can be regular call-by-value functions) ii. Your histogram function will count
the number of occurrences of data within a certain range; each range is commonly referred to as
a.
a. Modify the C program ex.9 so that it simulates the Unix pipe comm.pdf
a. Modify the C program ex.9 so that it simulates the Unix pipe command:
ls | grep .c | tail -4
b.. Implement following programs to exhibit UNIX Process Control:
A program where parent process sorts array elements in descending order and prints them out
and child process sorts array elements in ascending order and prints them out.
A program where parent process counts number of vowels in the given sentence and child
process will count number of words in the same sentence. The above programs should use
system calls like fork, exec and wait.
ex.9:
/*
simulates unix pipe
ls | grep .c
*/
#include
#include
#include
#define RD 0
#define WT 1
int main()
{
int fd[2];
pipe(fd);
switch(fork()) { // parent forks
case -1:
perror(\"Fork error\");
break;
case 0: // child does the ls
close(fileno(stdout)); // no need for stdout here
dup(fd[WT]); // duplicate the descriptor for writing
close(fd[WT]);
close(fd[RD]);
execlp(\"ls\", \"ls\", NULL);
break;
default: // parent does the grep
close(fileno(stdin)); // no need for stdin here
dup(fd[RD]); // duplicate the descriptor for reading
close(fd[WT]);
close(fd[RD]);
execlp(\"grep\", \"grep\", \".c\", NULL);
break;
}
return 0;
}
Solution
#include
#include
#include
#define RD 0
#define WT 1
int main()
{
int fd1[2];
int fd2[2];
pipe(fd1);
switch(fork()) {
case -1:
perror(\"Fork error\");
break;
case 0: // child does the ls
close(fileno(stdout));
dup(fd[WT]);
close(fd1[WT]);
close(fd1[RD]);
execlp(\"ls\", \"ls\", NULL);
break;
default:
pipe(fd2);
switch(fork()) {
case -1:
perror(\"Fork error\");
break;
case 0:
close(fileno(stdin));
dup(fd1[RD]);
dup(fd2[RD];
close(fd1[WT]);
close(fd1[RD]);
close(fd2[WT]);
close(fd2[RD]);
execlp(\"grep\", \"grep\", \".c\", NULL);
break;
default:
dup(fd2[RD]);
close(fd2[WT]);
close(fd2[RD]);
execlp(\"tail\", \"tail\", \"-4\", NULL);
break;
}
return 0;
}.
A severe B12 deficiency can cause megaloblastic anemia but in severe .pdf
A severe B12 deficiency can cause megaloblastic anemia but in severe cases you will see ___
____ ____ depression, dementia, memory loss fatigue, dementia, memory loss depression,
dementia, poor sleep depression, fatigue, loss of concentration.
Solution
The answer is b- fatigue, dementia and memory loss
the b12 deficiency causes memory loss and fatigue primarily.
When you are admitted to the hospital for surgery, you are very ofte.pdf
When you are admitted to the hospital for surgery, you are very often administered intravenously
a physiological saline solution (a solution of NaCl in water). Calculate the concentration of this
solution knowing that the solution has to be isotonic with blood and knowing that the average
osmotic pressure of blood is 7.7 atm at 25 oC.
Solution
Pi (osmotic pressure) = iMRT
molarity M = Pi/iRT = 7.7 / 2x[0.082 x (273.15 +25)] = 0.16 M
i = Hoff factor = 2 since NaCl dissociates as Na+ and Cl-..
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Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
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Ignore what I have written because Im pretty sure its wrong. Thank.pdf
- 1. Ignore what I have written because I'm pretty sure its wrong. Thanks! Deliver the assignment to my office, 4502 French Hal! West or Scan your assignment and send it as an email attachment. Write the complex number, z = a + bi, in polar form, z = r (cos theta + i sin theta), with argument theta between 0 and 2 pi. -3i 3 - Squareroot 3i -1 + i II. Find the product, z_1z_2, and the quotient, z_1/z_2. Express your answer in polar form. z_1 = 3(cos 15 degree + i sin 15 degree) z_2 = 6(cos 20 degree + i sin 20 degree) z_1z_2: ____ z_1/z_2: ____ z_1 = 21 (cso pi/5 + i sin pi/5) z_2 = 7(cos 2 pi/3 + i sin 2 pi/3) z_1z_2: ____ z_1/z_2: ____ Solution I) 1) -3i r=[02+(-3)2]=3 =tan-1(-3/0) =3/2 polar form is 3(cos(3/2)+i sin(3/2)) 2) 3-3i r=[32+(-3)2]=12=23 =tan-1(-3/3) =11/6 polar form is 23(cos(11/6)+i sin(11/6)) 3) -1+i r=[(-1)2+12]=2 =tan-1(1/-1) =3/4 polar form is 2(cos(3/4)+i sin(3/4)) =========================================================== II) 1) z1=3(cos15o+isin15o), z2=6(cos20o+isin20o) z1z2=3(cos15o+isin15o)*6(cos20o+isin20o) z1z2=3*6(cos(15+20)o+isin(15+20)o) z1z2=18(cos(35)o+isin(35)o) z1/z2=3(cos15o+isin15o)/[6(cos20o+isin20o)] z1/z2=(3/6)(cos(15-20)o+isin(15-20)o)