Problem-Solving
R U P C ?
Read it! … what’s it about?
Underline it! … find the clues
Picture it! … add? subtract? multiply? divide?
… use a number line to help
Calculate it! … work it out !
How to become a
PROBLEM-CRACKER
in 4 Easy Steps!
The Area of a Rectangle …
means … the amount of surface inside
and measured by … the number of squares inside
(eg: square centimetres, square metres, square feet, square yards)
- Or LENGTH X WIDTH
= 10 X 6 = 60
The area is 60 square metres
- Or ROWS X COLUMNS
6 rows of 10 squares = 60
The area is 60 square metres
COUNT THE SQUARES
1, 2, 3, … 59, 60
The area is 60 square metres
10 m
6 m
Area Example 1
Easy! Just count the 12 squares
Area = 12 squares centimetres
METHOD 1: COUNT THE SQUARES
USEFUL METHOD WHEN …
- You can see the squares
AND
-there’s not too many to count!
What is the area of this
rectangle? …
HOW MANY SQUARES?
Too many squares to count!
Is there an easier way?
You can see there are 6 rows with 10
in each row
= 60 squares
METHOD 2: AREA = ROWS X COLUMNS
USEFUL METHOD WHEN …
- You can see the squares
BUT
-there’s too many to count!
Area Example 2
Area Example 3
What is the area of this
rectangle? …
HOW MANY SQUARES?
No squares to count
BUT
7cm means 7 squares fit in each row
5 cm means 5 squares fit in each column
2
Number of squares = length x width
= 7 x 5 = 35 square centimetres
METHOD 3: AREA = LENGTH X WIDTH
USEFUL METHOD WHEN …
- You can’t see the squares
AND
It’s very fast
7 cm
5 cm
9 cm
3 cm
AREA =
LENGTH X WIDTH
AREA = COUNT
THE SQUARES
AREA =
ROWS X COLUMNS
Area: Test Yourself 1
Which
method
best suits
each
problem?
AREA =
LENGTH X WIDTH
Area: Test Yourself 1
9 cm
3 cm
= 9 x 3
= 27 cm²
= 4 x 2
= 8 cm²
= 11 x 5
= 55 cm²
AREA =
LENGTH X WIDTH
Area Test Yourself 2
AND
which way
works for
ALL 3?
8 cm
5 cm
= 7 x 5
= 35 cm²
= 8 x 5
= 40 cm²
= 3 x 4
= 12 cm²
Area– General Rule for all
Rectangles
General Rule:
The area of a rectangle = Length x Width
Or if you like shorthand …
A = L x W
The Perimeter of a Rectangle …
means - the distance around the outside
and is measured by - the sum of the lengths of the 4 sides
(eg: millimetres, centimetres, metres, kilometres, feet, yards)
2 LENGTHS + 2 WIDTHS
= 2 X 10 + 2 X 6
= 20 + 12 = 32m
ADD 1 LENGTH + 1 WIDTH
THEN DOUBLE IT
10 + 6 = 16m
2 X 16 = 32m
ADD 4 LENGTHS IN ORDER
10 + 6 + 10 + 6 = 32 m
10m
6m
10m
6m
Perimeter
Units of perimeter:
Any units of length
METRIC UNITS
Millimetres mm
Centimetres cm
Kilometres km
IMPERIAL UNITS
Miles
Yards
Feet
Inches
STEP 1
Read it !
STEP 2
Underline it !
… and …
LOOK FOR
KEY
NUMBERS!
The history
classroom is 10m
long and 4m wide.
How much carpet
is needed for the
floor?WORD CLUE! area
KEY NUMBER!
KEY NUMBER!
… and
WORD
CLUES –
area or
perimeter?
AREA CLUES
surface
cover
coverage
amount of carpet
how much carpet
Some word clues
to watch out for…
PERIMETER CLUES
edge
edging
outside distance
outside length
perimeter fencing
total outside length
external length
STEP 1 Read it !
STEP 2 Underline It !
STEP 3 Picture It! !
The history
classroom is 10m
long and 4m wide.
How much carpet
is needed for the
floor?WORD CLUE! area
KEY NUMBER!
KEY NUMBER!
10m
4m
This means
AREA
Example 1
STEP 1 Read it !
STEP 2 Underline It !
STEP 3 Picture It! !
STEP 4 Calculate It !
Area of a rectangle = length x width
= 10 x 40
= 40
An area of 40m ² carpet is needed.
10m
4m
The history
classroom is 10m
long and 4m wide.
How much carpet
is needed for the
floor?
STEP 1
Read it !
STEP 2
Underline it !
… and …
LOOK FOR
KEY
NUMBERS!
The history
classroom is 10m
long and 4m wide.
How much
edging strip is
needed
for the classroom
floor?
WORD CLUE!
perimeter
KEY NUMBER!
KEY NUMBER!
AREA CLUES
surface
cover
coverage
amount of carpet
how much carpet
PERIMETER CLUES
edge
edging
outside distance
outside length
perimeter fencing
total outside length
external length
… and
WORD
CLUES –
area or
perimeter?
STEP 1 Read it !
STEP 2 Underline It !
STEP 3 Picture It! !
Example 2
10m
4m
10m
4m
The history
classroom is 10m
long and 4m wide.
How much
edging strip is
needed
to go around the
classroom floor?
This means
PERIMETER
10m
4m
10m
4m
Remember – there’s lots of
ways to do this!
For example:
10 + 4 + 10 + 4 = 28
OR
10 + 4 = 14
2 X 14 = 28
OR
10 X 2 = 20 and 4 X 2 = 8
20 + 8 = 28
The history room floor
is 12m by 6m.
The project corner is a
1m by 3m rectangle.
The rest is tiled.
How much of the
floor surface is tiled?
WORD CLUE! area
KEY NUMBER!
KEY NUMBERS!
 Total Area = 6 + 9 = 15m²
 The tiled area is 15m ²
1m
6m
3m
3m
Example 4
STEP 1 Read it !
STEP 2 Underline It !
STEP 3 Picture It! !
2 Steps so far …
CLICK for Step 3!
EDGING MEANS PERIMETER
But the shape you’re interested in is not
a rectangle!
One way is to start at the top
left-hand corner and write down each
length around the perimeter.
Then ADD.
The history room floor
is 12m by 6m.
The carpeted area in
the corner is a
1m by 3m rectangle.
The rest is tiled and
surrounded by
wooden edging.
What length of
edging is needed?
 Work out the length of each side and add!
 18m of edging is needed
STEP 1
?
STEP 2
?
STEP 3
?
STEP 4
?
Underline It ! Picture It! ! Calculate It !Read it !
6m
1.5m
2m
4m
Problem 1
The history classroom is 9m long and
5m wide.
How carpet is needed to cover the floor?
Problem 2
The history classroom is 9m
long and 5m wide.
How edging tape is needed for
the carpet perimeter?
A length of 28m edging strip is
needed
STEP 1
?
STEP 2
?
STEP 3
?
STEP 4
?
Underline It ! Picture It! ! Calculate It !Read it !
Problem 3
The history classroom floor is
a 12m and 6m rectangle.
The resource corner is 2m x
2m square. How much floor
space is still free?
Problem 4
The history classroom floor is a
12m by 6m rectangle.
The resource corner is 2m x 2m
square. A tiled border marks the
perimeter of the remaining floor.
How long is the border?
An area of 68m² carpet is needed
Problem 6
What length of skirting board
is needed this classroom?
(Remember to allow for the door!)
KEY
Door
(0.5m wide)
15m
7m
6m
11m
43.5m of skirting board is needed.
Problem 7
How much floor space is there
in this classroom?
KEY
Door
(1/2 m wide)
10m
7m
5.5m
8m
The floor area is 59m²

Hinterland Area/ perimeter

  • 1.
  • 2.
    R U PC ? Read it! … what’s it about? Underline it! … find the clues Picture it! … add? subtract? multiply? divide? … use a number line to help Calculate it! … work it out ! How to become a PROBLEM-CRACKER in 4 Easy Steps!
  • 3.
    The Area ofa Rectangle … means … the amount of surface inside and measured by … the number of squares inside (eg: square centimetres, square metres, square feet, square yards) - Or LENGTH X WIDTH = 10 X 6 = 60 The area is 60 square metres - Or ROWS X COLUMNS 6 rows of 10 squares = 60 The area is 60 square metres COUNT THE SQUARES 1, 2, 3, … 59, 60 The area is 60 square metres 10 m 6 m
  • 4.
    Area Example 1 Easy!Just count the 12 squares Area = 12 squares centimetres METHOD 1: COUNT THE SQUARES USEFUL METHOD WHEN … - You can see the squares AND -there’s not too many to count!
  • 5.
    What is thearea of this rectangle? … HOW MANY SQUARES? Too many squares to count! Is there an easier way? You can see there are 6 rows with 10 in each row = 60 squares METHOD 2: AREA = ROWS X COLUMNS USEFUL METHOD WHEN … - You can see the squares BUT -there’s too many to count! Area Example 2
  • 6.
    Area Example 3 Whatis the area of this rectangle? … HOW MANY SQUARES? No squares to count BUT 7cm means 7 squares fit in each row 5 cm means 5 squares fit in each column 2 Number of squares = length x width = 7 x 5 = 35 square centimetres METHOD 3: AREA = LENGTH X WIDTH USEFUL METHOD WHEN … - You can’t see the squares AND It’s very fast 7 cm 5 cm
  • 7.
    9 cm 3 cm AREA= LENGTH X WIDTH AREA = COUNT THE SQUARES AREA = ROWS X COLUMNS Area: Test Yourself 1 Which method best suits each problem?
  • 8.
    AREA = LENGTH XWIDTH Area: Test Yourself 1 9 cm 3 cm = 9 x 3 = 27 cm² = 4 x 2 = 8 cm² = 11 x 5 = 55 cm²
  • 9.
    AREA = LENGTH XWIDTH Area Test Yourself 2 AND which way works for ALL 3? 8 cm 5 cm = 7 x 5 = 35 cm² = 8 x 5 = 40 cm² = 3 x 4 = 12 cm²
  • 10.
    Area– General Rulefor all Rectangles General Rule: The area of a rectangle = Length x Width Or if you like shorthand … A = L x W
  • 11.
    The Perimeter ofa Rectangle … means - the distance around the outside and is measured by - the sum of the lengths of the 4 sides (eg: millimetres, centimetres, metres, kilometres, feet, yards) 2 LENGTHS + 2 WIDTHS = 2 X 10 + 2 X 6 = 20 + 12 = 32m ADD 1 LENGTH + 1 WIDTH THEN DOUBLE IT 10 + 6 = 16m 2 X 16 = 32m ADD 4 LENGTHS IN ORDER 10 + 6 + 10 + 6 = 32 m 10m 6m 10m 6m
  • 12.
    Perimeter Units of perimeter: Anyunits of length METRIC UNITS Millimetres mm Centimetres cm Kilometres km IMPERIAL UNITS Miles Yards Feet Inches
  • 13.
    STEP 1 Read it! STEP 2 Underline it ! … and … LOOK FOR KEY NUMBERS! The history classroom is 10m long and 4m wide. How much carpet is needed for the floor?WORD CLUE! area KEY NUMBER! KEY NUMBER! … and WORD CLUES – area or perimeter?
  • 14.
    AREA CLUES surface cover coverage amount ofcarpet how much carpet Some word clues to watch out for… PERIMETER CLUES edge edging outside distance outside length perimeter fencing total outside length external length
  • 15.
    STEP 1 Readit ! STEP 2 Underline It ! STEP 3 Picture It! ! The history classroom is 10m long and 4m wide. How much carpet is needed for the floor?WORD CLUE! area KEY NUMBER! KEY NUMBER! 10m 4m This means AREA
  • 16.
    Example 1 STEP 1Read it ! STEP 2 Underline It ! STEP 3 Picture It! ! STEP 4 Calculate It ! Area of a rectangle = length x width = 10 x 40 = 40 An area of 40m ² carpet is needed. 10m 4m The history classroom is 10m long and 4m wide. How much carpet is needed for the floor?
  • 17.
    STEP 1 Read it! STEP 2 Underline it ! … and … LOOK FOR KEY NUMBERS! The history classroom is 10m long and 4m wide. How much edging strip is needed for the classroom floor? WORD CLUE! perimeter KEY NUMBER! KEY NUMBER! AREA CLUES surface cover coverage amount of carpet how much carpet PERIMETER CLUES edge edging outside distance outside length perimeter fencing total outside length external length … and WORD CLUES – area or perimeter?
  • 18.
    STEP 1 Readit ! STEP 2 Underline It ! STEP 3 Picture It! ! Example 2 10m 4m 10m 4m The history classroom is 10m long and 4m wide. How much edging strip is needed to go around the classroom floor? This means PERIMETER
  • 19.
    10m 4m 10m 4m Remember – there’slots of ways to do this! For example: 10 + 4 + 10 + 4 = 28 OR 10 + 4 = 14 2 X 14 = 28 OR 10 X 2 = 20 and 4 X 2 = 8 20 + 8 = 28
  • 20.
    The history roomfloor is 12m by 6m. The project corner is a 1m by 3m rectangle. The rest is tiled. How much of the floor surface is tiled? WORD CLUE! area KEY NUMBER! KEY NUMBERS!
  • 21.
     Total Area= 6 + 9 = 15m²  The tiled area is 15m ²
  • 22.
    1m 6m 3m 3m Example 4 STEP 1Read it ! STEP 2 Underline It ! STEP 3 Picture It! ! 2 Steps so far … CLICK for Step 3! EDGING MEANS PERIMETER But the shape you’re interested in is not a rectangle! One way is to start at the top left-hand corner and write down each length around the perimeter. Then ADD.
  • 23.
    The history roomfloor is 12m by 6m. The carpeted area in the corner is a 1m by 3m rectangle. The rest is tiled and surrounded by wooden edging. What length of edging is needed?
  • 24.
     Work outthe length of each side and add!  18m of edging is needed
  • 25.
    STEP 1 ? STEP 2 ? STEP3 ? STEP 4 ? Underline It ! Picture It! ! Calculate It !Read it ! 6m 1.5m 2m 4m Problem 1 The history classroom is 9m long and 5m wide. How carpet is needed to cover the floor?
  • 26.
    Problem 2 The historyclassroom is 9m long and 5m wide. How edging tape is needed for the carpet perimeter?
  • 27.
    A length of28m edging strip is needed
  • 28.
    STEP 1 ? STEP 2 ? STEP3 ? STEP 4 ? Underline It ! Picture It! ! Calculate It !Read it ! Problem 3 The history classroom floor is a 12m and 6m rectangle. The resource corner is 2m x 2m square. How much floor space is still free?
  • 29.
    Problem 4 The historyclassroom floor is a 12m by 6m rectangle. The resource corner is 2m x 2m square. A tiled border marks the perimeter of the remaining floor. How long is the border?
  • 30.
    An area of68m² carpet is needed
  • 31.
    Problem 6 What lengthof skirting board is needed this classroom? (Remember to allow for the door!) KEY Door (0.5m wide) 15m 7m 6m 11m
  • 32.
    43.5m of skirtingboard is needed.
  • 33.
    Problem 7 How muchfloor space is there in this classroom? KEY Door (1/2 m wide) 10m 7m 5.5m 8m
  • 34.