Genetics Exercise
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Anna has ptosis, which is caused by a dominant gene P. Her father also had ptosis and was homozygous dominant for the gene, while her mother has normal eyes. Anna's genotype is Pp, her father's is PP, and her mother's is pp. If Anna marries a man with normal eyes (genotype pp), there is a 50% chance their child will have ptosis. Albinism is recessive, so for the families described: the first family's parents were Pp and Pp or pp and the albino child was pp, and the second family's parents were Pp and pp and all children were Pp.
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![Anna Sweetstory has a problem. Her eyes are half-closed all the time. Her teachers think she sleeps during class and her friends think she is always bored. Anna’s condition is called ptosis, which is caused by a single dominant gene, P. The opposite normal condition, open eyes, is caused by the recessive allele, p. Anna’s father had ptosis, and his parents were both found to be homozygous dominant with respect to this gene. Anna’s mother has normal eyes. ,[object Object]](https://image.slidesharecdn.com/lec7genetics-090811204648-phpapp01/85/Genetics-Exercise-1-320.jpg)
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have? Draw Punnett squares. 2. artan\'s syndrome is caused by an autosomal dominant altele.
What are chances of having a child that will develop syndrome if one of the parents has
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Answer:
1)
John has O blood group, so genotype is \"IOIO\"
Mother blood group---?
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Child genotype can be either IAIA or IAIO
Based in chidren blood group, if we cross father blood group with A, then..
1) IOIO X IAIA
2) IOIO X IAIO
From the above , we can say that mother blood is A, and genotype can be IAIA
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was so limited that even when he was three years old his mother still found herself trying to guess
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became upset when his mother had to go out and leave him with a friend or relative. In fact, he
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3) The X0 system where males are X0 and the sperm determines sex - containing either an X or no sex chromosome.
Sex-limited traits are expressed by only one sex, sex-influenced traits are expressed differently between sexes, and sex-linked traits are found on sex chromosomes and behave differently between sexes with non-homologous chromosomes. Hemophilia is an
Lec14 Pedigree Analysis Exercise
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1. Eye color is determined by multiple alleles at a single gene locus. There are multiple versions (alleles) of the eye color gene - blue, green, and brown.
2. Polygenic inheritance is when multiple genes contribute to a single trait. For traits determined by polygenic inheritance, there are many possible combinations of alleles across several gene loci that result in a range of phenotypes.
3. Both multiple allele inheritance and polygenic inheritance can contribute to natural variation in human eye color. Multiple alleles at a single gene locus explain some of the variation, but many genes likely have small effects, making polygenic inheritance important as well.
Bio3 0910 Lec6 Mendel
The document discusses early theories of heredity prior to Gregor Mendel's work, including the spermist view that sperm contained a miniature human, the ovist view that the egg contained the future human, and the pangenesis theory that traits were carried in the blood. It also describes the blending theory of inheritance. The key findings of Mendel's work that are highlighted include his discovery of the laws of segregation and independent assortment through dihybrid crosses, showing that traits are inherited independently from each parent and segregate during gamete formation.
Bio3 0910 Lec6 Genetics Starter
Genetics is the study of heredity and how traits are passed from parents to children through genes. Children inherit genes from both parents that determine traits like physical characteristics, talents, and genetic disorders. Genes are found on chromosomes and are passed through a process called Mendelian inheritance. In Harry Potter, some observable genetic traits of characters that are described include hair color, eye color, freckles, and height. Genetic concepts can help explain traits seen in the Weasley and Potter families by using Punnett squares to determine possible genotypes that result in the observed phenotypes.
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Based on the reasoning provided, the possible DNA template sequence that would code for the polypeptide Phe-Pro-Lys is TTT-CCA-AAA.
P S H S U P C A T Review Bio ( Part 1)
The document discusses various biology topics including cell organelles, osmosis, photosynthesis, respiration, the immune system, reproduction and development in animals, evolution, and ecology. It provides information on the structures and functions of organelles like the mitochondria and nucleus. It explains concepts such as osmosis, diffusion, active transport and homeostasis. Key processes like cellular respiration and photosynthesis are defined. Immune system cells and their roles are outlined. Stages of animal development from fertilization to gastrulation are named. Principles of evolution, reproduction and ecology are touched on.
Bio3 0910 Lec4 Meiosis
Meiosis involves two rounds of cell division. In meiosis I, homologous chromosomes pair up and crossover occurs between aligned genes. The homologous chromosomes then separate, with each daughter cell receiving one of the two homologous chromosomes. Meiosis II then follows, where the sister chromatids separate and move to opposite poles, resulting in four haploid daughter cells each with half the number of chromosomes as the original cell.
Bio3 0910 Lec2 Controls Cd Ks
The document discusses checkpoints in the cell cycle that control progression from one phase to the next. It describes the G1, G2, and M phase checkpoints, noting that the G1 checkpoint determines whether cells continue cycling or enter quiescence, the G2 checkpoint is driven by maturation promoting factor allowing passage to mitosis, and the M phase checkpoint ensures proper chromosome attachment before anaphase. External signals and cyclins/cyclin-dependent kinases regulate progression through the checkpoints.
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Genetics Exercise
- 2. What are the genotypes of both her parents?