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International Journal Of Mathematics And Statistics Invention (IJMSI)
E-ISSN: 2321 – 4767 P-ISSN: 2321 - 4759
www.Ijmsi.org || Volume 3 Issue 2 || February. 2015 || PP-35-38
www.ijmsi.org 35 | P a g e
Exact value of pi π = (17- 8√3)
Mr. Laxman S. Gogawale
Fulora co-operative society, Dhankawadi, Pune-411043 (India)
Abstract: In this paper, I show that exact area of circle = (π r2
) = 17 - 8√3) r2
. I found that the exact value of
pi is = (17- 8√3).My findings are based on geometrical constructions, formula and proofs.
I. INTRODUCTION
Is it possible or impossible?
100% exact value of pi, 100% exact area of circle, area of circle = area of square
Yes, it is Possible!
We know that, where C /D = A/R2
= approximate value of pi = 3.1415926535897…which is endless value.
C = circumference of circle, D = diameter of circle, A = area of circle, R = radius of circle,
If we calculate C / D we cannot measure end point of circumference. So it will give approximate results.
I started research to find exact area of circle using A /R2
method.
There are different proofs to find the old value of pi but no one get 100% exact answer.
Like using number series, Trigonometry, Dividing circle into infinite parts, as practically we can’t measure
endpoint etc. In order to find 100% exact area of circle I found the new method.
I have made number of proofs but here I am giving simple proof out of it.
Reason why I am 100% sure about my research is that I estimated pi value by number of different
algebraic methods. Why should we discuss pi is transcendental or algebraic? This is not important. But we are
more concentrated on calculating 100% exact answer which is most important.
New methods are also discovered .i.e. algebraic table method. By all the methods the answer remains same.
Basic Figure
Modified figure (1 & 2)
Exact value of pi π = (17- 8√3)
www.ijmsi.org 36 | P a g e
Fig. 1
fig. 2
From fig. 1 & 2
Note: let a, b, c & d each part shows area
Area of square = (12a + 12b + 12c + 4d) = (16a + 16b) = 4r2
(12a + 12b + 12c + 4d) – (16a + 16b) = 0
= (- 4a - 4b + 12c + 4d) = 0
i.e. (4a + 4b = 12c + 4d) (a + b) = (3c+d) equation no. 1
From fig. no. 2
16a = [2r × 2(√3/2) r] = (2√3) r2
a = (2√3) r2
/16 = (0.125√3) r2
16b = [2r – 2(√3/2) r] × 2r = (4 - 2√3) r2
b = (4 - 2√3) r2
/ 16 = (0.25 – 0.125√3) r2
Problems faced during the research of pi that:
How to estimate the exact values of part c & part d?
I found number of equations for calculating area of square = 4r2
.Few of them is mentioned in the following
table. On the basis of these equations I estimated the exact area of circle in following manner.
Area of inscribed dodecagon (12a + 12b) = 3r2
area of square = (12a + 12b + 12c + 4d) = 4r2
= area of circle – 12c = area of circle + 4d
I have geometric proofs for all of the following equations
S. r. no. Equations of area of square = 4r2
Equations total = … 4r2
1 12a + 12b + 12c + 4d =4r2
12a + 12b + 12c + 4d = 4r2
2 64b + 12c + 8d =4r2
12a + 76b + 24c + 12d = 2(4r2
)
3 4a + 100b – 18c = 4r2
16a + 176b + 6c + 12d = 3(4r2
)
4 -8a + 120b + 8d = 4r2
8a + 296b + 6c + 20d = 4(4r2
)
5 32a – 96b + 24c =4r2
40a + 200b + 30c + 20d = 5(4r2
)
6 20a – 12b + 6c = 4r2
60a + 188b + 36c + 20d = 6(4r2
)
7 96b – 6c + 4d = 4r2
60a + 284b + 30c + 24d = 7(4r2
)
Exact value of pi π = (17- 8√3)
www.ijmsi.org 37 | P a g e
8 48a – 208b + 48c = 4r2
108a + 76b + 78c + 24d = 8(4r2
)
9 24a – 40b + 12c = 4r2
132a + 36b + 90c + 24d = 9(4r2
)
10 128b – 24c = 4r2
132a + 164b + 66c + 24d = 10(4r2
)
11 -20a + 172b + 12d = 4r2
112a + 336b + 66c + 36d = 11(4r2
)
12 12a + 44b – 6c = 4r2
124a + 380b + 60c + 36d = 12(4r2
)
13 28a – 68b + 18c = 4r2
152a + 312b + 78c + 36d = 13(4r2
)
14 8a + 72b – 12c = 4r2
160a + 384b + 66c + 36d = 14(4r2
)
15 4a + 68b + 4d = 4r2
164a + 452b + 66c + 40d = 15(4r2
)
16 60a – 292b + 66c = 4r2
224a + 160b + 132c + 40d = 16(4r2
)
17 104a – 600b + 132c = 4r2
328a – 440b + 264c + 40d = 17(4r2
)
18 18a + 2b + 3c = 4r2
346a – 438b + 267c + 40d = 18(4r2
)
19 36a – 124b + 30c = 4r2
382a – 562b + 297c + 40d = 19(4r2
)
20 48c + 16d = 4r2
382a – 562b + 345c + 56d = 20(4r2
)
Total area of 20 square = 382a – 562b + 345c +56d = 20(4r2
)
In the following proof I used area of inscribed dodecagon.
How I am getting the values of c & d for that see the following examples
Area of square = (12a + 12b + 12c + 4d) main equation
(Area of 15 square – area of 10 square) = (164a + 452b + 66c + 40d) – 10(12a + 12b + 12c + 4d)
= area of 5 square = (164a + 452b + 66c + 40d) – (120a + 120b + 120c + 40d)
= 44a + 332b – 54c
= 44a + 332b + area of 4.5 inscribed dodecagon – area of 4.5 circle
= 44a + 332b + 4.5(3r2
) – area of 4.5 circle
Area of 5 square + area of 4.5 circle = 44a + 332b + 4.5(3r2
)
Area of 4.5 circle = 44(0.125√3) r2
+ 332(0.25 – 0.125√3) r2
+ 13.5r2
- area of 5 square
= (5.5√3) r2
+ (83 – 41.5√3) r2
+ 13.5r2
– 5(4r2
)
= (96.5 – 36√3) r2
– 20r2
= (76.5 – 36√3) r2
Area of circle = (76.5 – 36√3) r2
/4.5
= (17- 8√3) r2
One more example
(Area of 12 square – area of 9 square) = (124a + 380b + 60c + 36d) - 9(12a + 12b + 12c + 4d)
= area of 3 square = (124a + 380b + 60c + 36d) – (108a + 108b + 108c + 36d)
= (16a + 272b – 48c)
= 16a + 272b + area of 4 inscribed dodecagon – area of 4 circle
= 16a + 272b + 4(3r2
) – area of 4 circle
Area of 3 square + area of 4 circle = 16a + 272b + 4(3r2
)
Area of 4 circle = 16(0.125√3) r2
+ 272(0.25 – 0.125√3) r2
+ 12r2
- area of 3 square
= (2√3) r2
- (68 - 34√3) r2
+ 12r2
– 3(4r2
)
= (80 – 32√3) r2
– 12r2
= (68 – 32√3) r2
Area of circle = (68 – 32√3) r2
/4
= (17- 8√3) r2
Found the value of 3c & d
Area of square = 4r2
Area of circle = (17 - 8√3) r2
(Area of square – area of circle) = 4d)
= 4r2
– (17 - 8√3) r2
= (8√3 – 13) r2
d = (2√3 – 3.25) r2
Exact value of pi π = (17- 8√3)
www.ijmsi.org 38 | P a g e
Area of square = 16a+16b = 4r2
(a + b) = (3c+d) = (4r2
/16) = o.25r2
(a + b) – d = 3c
= [0.25 – (2√3 – 3.25)] r2
= 3c = (3.5 -2√3) r2
a = (0.125√3) r2
b = (0.25 – 0.125√3) r2
3c = (3.5 - 2√3) r2
d = (2√3 – 3.25) r2
By using value of (a, b, c & d) in the above equations we get same answer = 4r2
& total …4r2
I have prepared all examples of this type but answer remains same.
Conclusions:-
Exact area of circle = (17 - 8√3) r2
Exact value of pi π = (17 - 8√3)
REFERENCES
Exact area of equilateral triangle formula = (√3 ÷ 4) × side2
Basic Algebra & Geometry concept, History of pi (π) from internet
Complete thesis of my research titled as ‘‘Exact value of pi ’’ is being published in following journals:
IOSR(international journal of scientific research) journal of mathematics in May-June 2012.
IJERA(international journal of Engineering research and applications) in July-August 2013.
Soft copy of my thesis is now also available on internet and one can get it by making search with following key
words:
“Laxman Gogawale.
“Pi value Gogawale.

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Exact value of pi π = (17- 8√3)

  • 1. International Journal Of Mathematics And Statistics Invention (IJMSI) E-ISSN: 2321 – 4767 P-ISSN: 2321 - 4759 www.Ijmsi.org || Volume 3 Issue 2 || February. 2015 || PP-35-38 www.ijmsi.org 35 | P a g e Exact value of pi π = (17- 8√3) Mr. Laxman S. Gogawale Fulora co-operative society, Dhankawadi, Pune-411043 (India) Abstract: In this paper, I show that exact area of circle = (π r2 ) = 17 - 8√3) r2 . I found that the exact value of pi is = (17- 8√3).My findings are based on geometrical constructions, formula and proofs. I. INTRODUCTION Is it possible or impossible? 100% exact value of pi, 100% exact area of circle, area of circle = area of square Yes, it is Possible! We know that, where C /D = A/R2 = approximate value of pi = 3.1415926535897…which is endless value. C = circumference of circle, D = diameter of circle, A = area of circle, R = radius of circle, If we calculate C / D we cannot measure end point of circumference. So it will give approximate results. I started research to find exact area of circle using A /R2 method. There are different proofs to find the old value of pi but no one get 100% exact answer. Like using number series, Trigonometry, Dividing circle into infinite parts, as practically we can’t measure endpoint etc. In order to find 100% exact area of circle I found the new method. I have made number of proofs but here I am giving simple proof out of it. Reason why I am 100% sure about my research is that I estimated pi value by number of different algebraic methods. Why should we discuss pi is transcendental or algebraic? This is not important. But we are more concentrated on calculating 100% exact answer which is most important. New methods are also discovered .i.e. algebraic table method. By all the methods the answer remains same. Basic Figure Modified figure (1 & 2)
  • 2. Exact value of pi π = (17- 8√3) www.ijmsi.org 36 | P a g e Fig. 1 fig. 2 From fig. 1 & 2 Note: let a, b, c & d each part shows area Area of square = (12a + 12b + 12c + 4d) = (16a + 16b) = 4r2 (12a + 12b + 12c + 4d) – (16a + 16b) = 0 = (- 4a - 4b + 12c + 4d) = 0 i.e. (4a + 4b = 12c + 4d) (a + b) = (3c+d) equation no. 1 From fig. no. 2 16a = [2r × 2(√3/2) r] = (2√3) r2 a = (2√3) r2 /16 = (0.125√3) r2 16b = [2r – 2(√3/2) r] × 2r = (4 - 2√3) r2 b = (4 - 2√3) r2 / 16 = (0.25 – 0.125√3) r2 Problems faced during the research of pi that: How to estimate the exact values of part c & part d? I found number of equations for calculating area of square = 4r2 .Few of them is mentioned in the following table. On the basis of these equations I estimated the exact area of circle in following manner. Area of inscribed dodecagon (12a + 12b) = 3r2 area of square = (12a + 12b + 12c + 4d) = 4r2 = area of circle – 12c = area of circle + 4d I have geometric proofs for all of the following equations S. r. no. Equations of area of square = 4r2 Equations total = … 4r2 1 12a + 12b + 12c + 4d =4r2 12a + 12b + 12c + 4d = 4r2 2 64b + 12c + 8d =4r2 12a + 76b + 24c + 12d = 2(4r2 ) 3 4a + 100b – 18c = 4r2 16a + 176b + 6c + 12d = 3(4r2 ) 4 -8a + 120b + 8d = 4r2 8a + 296b + 6c + 20d = 4(4r2 ) 5 32a – 96b + 24c =4r2 40a + 200b + 30c + 20d = 5(4r2 ) 6 20a – 12b + 6c = 4r2 60a + 188b + 36c + 20d = 6(4r2 ) 7 96b – 6c + 4d = 4r2 60a + 284b + 30c + 24d = 7(4r2 )
  • 3. Exact value of pi π = (17- 8√3) www.ijmsi.org 37 | P a g e 8 48a – 208b + 48c = 4r2 108a + 76b + 78c + 24d = 8(4r2 ) 9 24a – 40b + 12c = 4r2 132a + 36b + 90c + 24d = 9(4r2 ) 10 128b – 24c = 4r2 132a + 164b + 66c + 24d = 10(4r2 ) 11 -20a + 172b + 12d = 4r2 112a + 336b + 66c + 36d = 11(4r2 ) 12 12a + 44b – 6c = 4r2 124a + 380b + 60c + 36d = 12(4r2 ) 13 28a – 68b + 18c = 4r2 152a + 312b + 78c + 36d = 13(4r2 ) 14 8a + 72b – 12c = 4r2 160a + 384b + 66c + 36d = 14(4r2 ) 15 4a + 68b + 4d = 4r2 164a + 452b + 66c + 40d = 15(4r2 ) 16 60a – 292b + 66c = 4r2 224a + 160b + 132c + 40d = 16(4r2 ) 17 104a – 600b + 132c = 4r2 328a – 440b + 264c + 40d = 17(4r2 ) 18 18a + 2b + 3c = 4r2 346a – 438b + 267c + 40d = 18(4r2 ) 19 36a – 124b + 30c = 4r2 382a – 562b + 297c + 40d = 19(4r2 ) 20 48c + 16d = 4r2 382a – 562b + 345c + 56d = 20(4r2 ) Total area of 20 square = 382a – 562b + 345c +56d = 20(4r2 ) In the following proof I used area of inscribed dodecagon. How I am getting the values of c & d for that see the following examples Area of square = (12a + 12b + 12c + 4d) main equation (Area of 15 square – area of 10 square) = (164a + 452b + 66c + 40d) – 10(12a + 12b + 12c + 4d) = area of 5 square = (164a + 452b + 66c + 40d) – (120a + 120b + 120c + 40d) = 44a + 332b – 54c = 44a + 332b + area of 4.5 inscribed dodecagon – area of 4.5 circle = 44a + 332b + 4.5(3r2 ) – area of 4.5 circle Area of 5 square + area of 4.5 circle = 44a + 332b + 4.5(3r2 ) Area of 4.5 circle = 44(0.125√3) r2 + 332(0.25 – 0.125√3) r2 + 13.5r2 - area of 5 square = (5.5√3) r2 + (83 – 41.5√3) r2 + 13.5r2 – 5(4r2 ) = (96.5 – 36√3) r2 – 20r2 = (76.5 – 36√3) r2 Area of circle = (76.5 – 36√3) r2 /4.5 = (17- 8√3) r2 One more example (Area of 12 square – area of 9 square) = (124a + 380b + 60c + 36d) - 9(12a + 12b + 12c + 4d) = area of 3 square = (124a + 380b + 60c + 36d) – (108a + 108b + 108c + 36d) = (16a + 272b – 48c) = 16a + 272b + area of 4 inscribed dodecagon – area of 4 circle = 16a + 272b + 4(3r2 ) – area of 4 circle Area of 3 square + area of 4 circle = 16a + 272b + 4(3r2 ) Area of 4 circle = 16(0.125√3) r2 + 272(0.25 – 0.125√3) r2 + 12r2 - area of 3 square = (2√3) r2 - (68 - 34√3) r2 + 12r2 – 3(4r2 ) = (80 – 32√3) r2 – 12r2 = (68 – 32√3) r2 Area of circle = (68 – 32√3) r2 /4 = (17- 8√3) r2 Found the value of 3c & d Area of square = 4r2 Area of circle = (17 - 8√3) r2 (Area of square – area of circle) = 4d) = 4r2 – (17 - 8√3) r2 = (8√3 – 13) r2 d = (2√3 – 3.25) r2
  • 4. Exact value of pi π = (17- 8√3) www.ijmsi.org 38 | P a g e Area of square = 16a+16b = 4r2 (a + b) = (3c+d) = (4r2 /16) = o.25r2 (a + b) – d = 3c = [0.25 – (2√3 – 3.25)] r2 = 3c = (3.5 -2√3) r2 a = (0.125√3) r2 b = (0.25 – 0.125√3) r2 3c = (3.5 - 2√3) r2 d = (2√3 – 3.25) r2 By using value of (a, b, c & d) in the above equations we get same answer = 4r2 & total …4r2 I have prepared all examples of this type but answer remains same. Conclusions:- Exact area of circle = (17 - 8√3) r2 Exact value of pi π = (17 - 8√3) REFERENCES Exact area of equilateral triangle formula = (√3 ÷ 4) × side2 Basic Algebra & Geometry concept, History of pi (π) from internet Complete thesis of my research titled as ‘‘Exact value of pi ’’ is being published in following journals: IOSR(international journal of scientific research) journal of mathematics in May-June 2012. IJERA(international journal of Engineering research and applications) in July-August 2013. Soft copy of my thesis is now also available on internet and one can get it by making search with following key words: “Laxman Gogawale. “Pi value Gogawale.