Fluorescein has a OH group and a COOH group. If a.pdf

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Fluorescein has a OH group and a COOH group. If a solvent containing NaOH is added it can deprotonate those group creating a more soluble salt. ex. O-Na+ and COO-Na+ These salts are soluble. Solution Fluorescein has a OH group and a COOH group. If a solvent containing NaOH is added it can deprotonate those group creating a more soluble salt. ex. O-Na+ and COO-Na+ These salts are soluble..

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Halfway titration: Half of the base is neutralised with HCl and becomes water plus its conjugate acid. This weak base, plus its conjugate acid forms a buffer solution with equimolar of both species. They obey the formula where pH = pKa +log(base/acid). Since they are equimolar, base/acid =1 and log 1 = 0 pH = pKa Ka = Kw/Kb = 2.27 x 10^-11 pH = - log(2.27 x 10^-11) = 10.6 (A) Solution Halfway titration: Half of the base is neutralised with HCl and becomes water plus its conjugate acid. This weak base, plus its conjugate acid forms a buffer solution with equimolar of both species. They obey the formula where pH = pKa +log(base/acid). Since they are equimolar, base/acid =1 and log 1 = 0 pH = pKa Ka = Kw/Kb = 2.27 x 10^-11 pH = - log(2.27 x 10^-11) = 10.6 (A).

Halfway titration Half of the base is neutralise.pdf

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The HTML canvas element is used to draw graphics on a web page.T.pdf

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Solution 3 Capital = Total Assets – Current Liabilities = $159,000 - $48,000 = $111,000 Income before interest and after taxes = EBIT x (1- Tax rate) = 26000 x (1-.4167) = $15,165.80 Return on capital(2008) = Income before interest and after taxes/ Capital = $15,165.80 / $111,000 = 13.66% Return on capital (2005) = (10000 x (1-.4444)/ (93000 -21000) = 5555.55/72000 = 7.71% Improvement = 13.66%-7.71% = 5.94%.

Solution 3Capital = Total Assets – Current Liabilities .pdf

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Q1: ROM The boot loader basically put Hex code into already there ROM inside controller, whenever microcontroller been powered up code from ROM get up into RAM and get executed and hence job got performed. Q2: INCA command is executed only 1 tine Solution Q1: ROM The boot loader basically put Hex code into already there ROM inside controller, whenever microcontroller been powered up code from ROM get up into RAM and get executed and hence job got performed. Q2: INCA command is executed only 1 tine.

Q1ROMThe boot loader basically put Hex code into already there .pdf

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Raising the temperature changes the solubility of a substance in water. Solubility increases with increasing temperature. The rate of solution in water also increases. Crushing or grinding the solid does not change the solubility but increases rate of solution. Adding more of the solid also does not change the solubility of that substance but increases rate of solution Agitating the solid/solvent mixture does not change the solubility of that substance but increases rate of solution Solution Raising the temperature changes the solubility of a substance in water. Solubility increases with increasing temperature. The rate of solution in water also increases. Crushing or grinding the solid does not change the solubility but increases rate of solution. Adding more of the solid also does not change the solubility of that substance but increases rate of solution Agitating the solid/solvent mixture does not change the solubility of that substance but increases rate of solution.

Raising the temperature changes the solubility of a substance in wat.pdf

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MAN pages. These pages describes commands functions and there proper execution. Pages are arranged in the 9 sections : Section 1 : Covers the commands that is normally provided by the user in the terminal. Section 2 to 5 : Programmers interface to the UNIX system is documented. Section 6: Covers the amusements and games included in UNIX system. Section 7 : Covers the device drivers of the system. Section 8: Covers the commands use by administrator to manage the system. Section 9 : UNIX kernels functions, which programmers uses while writing device drivers. Solution MAN pages. These pages describes commands functions and there proper execution. Pages are arranged in the 9 sections : Section 1 : Covers the commands that is normally provided by the user in the terminal. Section 2 to 5 : Programmers interface to the UNIX system is documented. Section 6: Covers the amusements and games included in UNIX system. Section 7 : Covers the device drivers of the system. Section 8: Covers the commands use by administrator to manage the system. Section 9 : UNIX kernels functions, which programmers uses while writing device drivers..

MAN pages.These pages describes commands functions and there prope.pdf

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If a person has inability to present antigens to Tc cells (cytotoxic T cells), then there will be deficiency of molecules like granzyme, perforin and granulysin. These molecules are required to kill abnormal cells or cells infected with viruses. If a person has inability to present antigens to Th1 cells, then there will be deficiency of molecules like tumour necrosis factor (TNF)-beta, interferon-gamma and interleukin (IL)-2. These molecules help in phagocytosis of foreign bodies (like bacteria and protozoa) and promote cell mediated immunity. If a person has inability to present antigens to Th2 cells, then there will be deficiency of molecules like IL-4, IL-5, IL-10, and IL-13. These molecules aid in eosinophil activation and induce antibody production against extracellular parasites. As is clear from above, the critical role of these molecules shows that a person with these T Cell deficiencies can not survive properly in normal environment and will be prone to recurrent infections or illnesses. However, if the person is treated with antiobiotics and other therapeutic regimes then chances of survival will increase depending on the severity of T Cell deficiency. Solution If a person has inability to present antigens to Tc cells (cytotoxic T cells), then there will be deficiency of molecules like granzyme, perforin and granulysin. These molecules are required to kill abnormal cells or cells infected with viruses. If a person has inability to present antigens to Th1 cells, then there will be deficiency of molecules like tumour necrosis factor (TNF)-beta, interferon-gamma and interleukin (IL)-2. These molecules help in phagocytosis of foreign bodies (like bacteria and protozoa) and promote cell mediated immunity. If a person has inability to present antigens to Th2 cells, then there will be deficiency of molecules like IL-4, IL-5, IL-10, and IL-13. These molecules aid in eosinophil activation and induce antibody production against extracellular parasites. As is clear from above, the critical role of these molecules shows that a person with these T Cell deficiencies can not survive properly in normal environment and will be prone to recurrent infections or illnesses. However, if the person is treated with antiobiotics and other therapeutic regimes then chances of survival will increase depending on the severity of T Cell deficiency..

If a person has inability to present antigens to Tc cells (cytotoxic.pdf

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i didnt get your question its unclear do you mean conjunctive .pdf

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Here is the code with comments for the question. Sample output is also attached for differnet inputs. If it helped, please dont forget to rate the answer.Thank you very much. import java.io.File; import java.io.FileNotFoundException; import java.util.ArrayList; import java.util.HashMap; import java.util.Scanner; //Class to read an input file an then process the first line as a b c m n // f is a relation on set from 1...a to 1...b // g is a relation on set 1...b to 1..c // m rows of relation f mappings // n rows of relation g mappings // outputs if f is a function, g is funcion, f is onto and g is one-one. Also if f and g are functions, then print gof() mappings public class Functions { //function to load number of rows specified from the file where the domain is 1....domainSize and codomain is 1, 2, .... codomainsize // returns a boolean array of size 3. value in 0 th index says where the the relation is a function or not. return[0] = true means the relation is a function, not a function if its false //return[1] indicates wheter the relation is one-one . so return[1] is true means the function is one one, if false not one-one //return[2] indicates wheter the relation is onto. os return[2] is true means the loaded function is onto otherwise not onto if false private static boolean[] analyzeRelation(Scanner scanner,int domainSize,int codomainSize,int rows,HashMapdomain,HashMap> codomain) throws Exception { boolean function=true,onto=true,oneone=true; boolean analysis[]=new boolean[3]; //stores the return values , isfunction? ,isoneone? isonto? //since a singel element in co-domain can be mapped to multiple elements in domain, we maintain an arraylist to tell which elements in domain it is mapped to .If the number of elements is 1 for //each elemeent in codomain, then its one-one for(int i=1;i<=codomainSize;i++) codomain.put(i, new ArrayList()); //initialize the arraylist for each of the co-domain elements int count=0; String l,line,nums[]; int idx1,idx2; int x,y; while(scanner.hasNext() && count1) //if the co-domain element is mapped to more than 1, its not oneoone, save the findings oneone=false; count++; } for(int i=1;i<=domainSize;i++) //now check that every element in the domain has a value in the map, otherwise its not a function { if(domain.get(i)==null) //an element in domain is not mapped. so not function function=false; } //now check the codomain elements, if every element is mapped , then its onto, other its not for(int i=1;i<=codomainSize;i++) { if(codomain.get(i).size()<1) //some element in codomain is not mapped to any element in domain, so its not onto onto=false; } ///store the results of your findints // 0th index isfunction? // 1st index isOneone? //2ind index isonto? analysis[0]=function; analysis[1]=oneone; analysis[2]=onto; return analysis; } public static void main(String[] args) { int a,b,c,m,n; HashMap fdomain=new HashMap(); HashMap> fcodomain=new HashMap>(); HashMap gdomain=new HashMap(); HashMap> gcodomain=new HashMap>(.

Here is the code with comments for the question. Sample output is al.pdf

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Embedded system: It is a computer system with a dedicated function within a larger mechanical or electrical system, often with real-time computing constraints. It is embedded as part of a complete device often including hardware and mechanical parts.They can control many devices in common use today. Solution Embedded system: It is a computer system with a dedicated function within a larger mechanical or electrical system, often with real-time computing constraints. It is embedded as part of a complete device often including hardware and mechanical parts.They can control many devices in common use today..

Embedded systemIt is a computer system with a dedicated function .pdf

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Factors.java import java.io.*; import java.util.Scanner; class Factors { public static void main(String args[]) { int a,i; Scanner in = new Scanner(System.in); System.out.println(\"Enter an integer\"); a = in.nextInt(); System.out.println(\"You entered integer \"+a); System.out.print(\"\ \"); System.out.print(\"The factors are : \"); for(i=1;i<=a/2;i++) { if(a%i==0) System.out.print(i+\",\"); } System.out.print(a); } } Output: Enter an integer 44 You entered integer 44 The factors are : 1,2,4,11,22,44 Solution Factors.java import java.io.*; import java.util.Scanner; class Factors { public static void main(String args[]) { int a,i; Scanner in = new Scanner(System.in); System.out.println(\"Enter an integer\"); a = in.nextInt(); System.out.println(\"You entered integer \"+a); System.out.print(\"\ \"); System.out.print(\"The factors are : \"); for(i=1;i<=a/2;i++) { if(a%i==0) System.out.print(i+\",\"); } System.out.print(a); } } Output: Enter an integer 44 You entered integer 44 The factors are : 1,2,4,11,22,44.

Factors.javaimport java.io.; import java.util.Scanner; class .pdf

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date of recordSolutiondate of record.pdf

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Dividend recieved deduction causes a temporary difference between ta.pdf

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d)y = (x+7.1)^2 x-4This is how you should represent the Fortra.pdf

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Answer 7. Danielle will produce eggs with allele i as her blood group is O i.e. no antigen is present in her blood. Michael can produce sperm with either A or B allele as his blood group is AB allele i.e. both A and B alleles are present. Ia Ib Ii Ia Ii Ib Ii The possible blood groups of the offspring is Ia Ii (A type) and Ib Ii (B type) As Michael can contribute either A or B allele, offspring will definitely have A or B allele. Hence, offspring with O allele (i.e. without A or B allele) is not possible. Ia Ib Ii Ia Ii Ib Ii Solution Answer 7. Danielle will produce eggs with allele i as her blood group is O i.e. no antigen is present in her blood. Michael can produce sperm with either A or B allele as his blood group is AB allele i.e. both A and B alleles are present. Ia Ib Ii Ia Ii Ib Ii The possible blood groups of the offspring is Ia Ii (A type) and Ib Ii (B type) As Michael can contribute either A or B allele, offspring will definitely have A or B allele. Hence, offspring with O allele (i.e. without A or B allele) is not possible. Ia Ib Ii Ia Ii Ib Ii.

Answer 7. Danielle will produce eggs with allele i as her blood grou.pdf

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Answersb. multipath (when two or more signals arrive at the recev.pdf

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A population is a group of individuals that belong to the same species and confined to a geographic area where they potentially interbreed. The genetic information carried by individuals of a population is known as gene pool. At a geographical location, the population may get well adapted to the environment and are highly homozygous with favorable alleles at high frequency. But the evidences available reveal that the populations exhibit high degree of heterzygosity. The diversity of the population may not be detected phenotypically because genetic diversity is often concealed. The genetic variation can be detected by artificial selection by which the phenotypic characteristics are affected. The variations at the genetic levels are mostly estimated by comparing the nucleotide sequences of the individuals. The amount of genetic variation can be determined by detectable variation at the protein level and at the nucleotide level. Sometimes the nucleotide substitutions result in the silent variations in the gene. Mutation is a sudden heritable change that can occur naturally or it can be induced. The gene shuffling causes inheritable variations during the production of gametes, by the process of crossing over during sexual reproduction. Thus sexual reproduction can produce different phenotypes with various combinations of genes and does not alter the allele frequencies of particular alleles responsible for specific traits. The amount of genetic variation can be determined by detectable variation at the protein level and at the nucleotide level. Sometimes the nucleotide substitutions result in the silent variations in the gene. Studies on various organisms and on different genes resulted in the enormous nucleotide diversity. The extensive genetic variability in most populations exhibited at the DNA level. Almost all genes exhibit the diversity from individual to individual. Especially the alleles represent the variations that are widely distributed among the individuals of the population. Genetic diversity in small populations is reduced because of genetic drift, high degree of inbreeding and reduction in gene flow. These effects are exhibited adversely on a species survival. For example, inbreeding in a population causes the loss of heterzygosity and promotes homozygosity. The recessive alleles received by offspring may be rare and lethal and affect the survival of the offspring. Thus, the low level of genetic diversity in a species extends harmful effects on the survival of the species and populations cannot get rid of \"bad or lethal genes\" due to homozygosity. Solution A population is a group of individuals that belong to the same species and confined to a geographic area where they potentially interbreed. The genetic information carried by individuals of a population is known as gene pool. At a geographical location, the population may get well adapted to the environment and are highly homozygous with favorable alleles at high frequency. But .

A population is a group of individuals that belong to the same speci.pdf

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2. Write the equilibrium constant expression forSolution2. Wr.pdf

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1.ploidy refers to the number of complete sets of chromosomes in an organism. Humans have 2 sets of chromosomes and are classified as diploid Organisms with only one set of chromosomes are classified as haploid 2. homozygotes are Individuals who have copies of the same allele at paired genetic loci. 3. The phenotype of an organism is what can be observed; this is the physical manifestation of the organism’s genotype 4. The term locus refers to the specific location of a gene or gene sequence along the chromosome 5. The spindle microtubules attach to a chromosome at a constricted region on a chromosome known as the centromere,The set of proteins at this location that provide the point of attachment for the spindle microtubules is called the kinetochore 6. The chiasma is the point of contact between paired (homologous) chromosomes at which crossing over takes place, during the first metaphase of meiosis. Another term for crossing over is recombination 7. Each gene in the species can have two, three, four, or even more alleles in any given population. But a diploid individual could only have two per gene at most. 8. The centrosome is the structure from which the spindle apparatus develops; in animal cells, it contains the centrioles. 9. The two identical chromosomes that result from DNA replication are referred to as sister chromatids.They are held together by proteins at a region of the chromosome called the centromere. 10. cohesin is the molecule that holds the two sister chromatids of a chromosome together. Its breakdown at the centromeres enables the chromatids to separate in anaphase of mitosis and anaphase II of meiosis 11. At the beginning of nuclear division in animal cells, the centrioles position themselves at opposite ends of the cell forming cell poles. Long protein fibers called microtubules extend from the centrioles in all possible directions. This results in the formation of the spindle apparatus 12.cytokinesis refers to the physical process of cell division that divides the cytoplasm of a parent cell into two daughter cells. Solution 1.ploidy refers to the number of complete sets of chromosomes in an organism. Humans have 2 sets of chromosomes and are classified as diploid Organisms with only one set of chromosomes are classified as haploid 2. homozygotes are Individuals who have copies of the same allele at paired genetic loci. 3. The phenotype of an organism is what can be observed; this is the physical manifestation of the organism’s genotype 4. The term locus refers to the specific location of a gene or gene sequence along the chromosome 5. The spindle microtubules attach to a chromosome at a constricted region on a chromosome known as the centromere,The set of proteins at this location that provide the point of attachment for the spindle microtubules is called the kinetochore 6. The chiasma is the point of contact between paired (homologous) chromosomes at which crossing over takes place, during the first metaphase of meios.

1.ploidy refers to the number of complete sets of chromosomes in an .pdf

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