The document discusses an epicyclic gear train, detailing its function and the relationships between its components. It calculates the number of teeth required on the planet gear using given parameters such as rotation speeds and teeth counts. The final result indicates that the planet gear should have 20 teeth to maintain the necessary configuration and operation of the system.

1. EPICYCLIC GEAR
TRAIN
VAIBHAV SANJAY PATIL
170101092035
Roll No. : - 14
Div. : - A

2. EPICYCLIC GEAR TRAIN
In epicyclic gear train ,the axis of at least one of the gears moves relative to the frame.
A gear train having a relative motion of axes is called a planetary or an epicyclic gear train.

3. The annulus ‘A’ in an epicyclic gear train rotates at 300rpm about
the axis of fixed sun gear which has 80 teeth. A 3 arm spider is
driven at 180rpm. Determine the number of teeth required on
planet ‘P’
Given : -
ts = 80
N6 = 180rpm
NA = 300
NS = 0
rs + 2 rp = ra

4. Ds + 2 Dp = Da
Since module is same it follows that,
ts + 2 tp = tA …………….(1)
Steps Operation Arm C Gear S Gear P Gear A
1. Fix the arm C and give
1 rotation to S
0 +1 -(tS/tP) -(tS/tP) x (tP/tA) - (tS/tA)
2. Multiply ‘m’ 0 m -m x (tS/tP) -m x (tS/tA)
3. Add n to all elements n n n n
4. Total motion n m + n -m x (tS/tP) + n -m x (tS/tA) + n

5. Since NC = 180rpm
therefore, n = 180
NS = 0
m + n = 0
∴ m = -180
∴ -m x (tS/tA) + n = 300
-(-180) x (80/tA) + 180 = 300
tA = 120
Put this value in equation (1)
∴ 80 + 2tP = 120
tP = 20

6. Thank You…