dh = Tds + vdPdifferentiating with respect to temp. that is dh d.pdf

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dh = Tds + vdP differentiating with respect to temp. that is dh / dT dh / dT = ds + (vdP / dT) using PV= nRT P= nRT/V dp/dT = nR/V so collective term (vdP / dT) = nR dU = T dS - p dV from above dS = (dU+pdV) / T putting these values in dh / dT = ds + (vdP / dT) dh / dT =[ (dU+pdV) / T ] + nR now dU= Cv dT and pdV = nRdT so (dU+pdV) = Cv dT + nRdT and (dU+pdV) / T = [Cv dT + nRdT ] / T now using Cv = Cp - R we will get (dU+pdV) / T = [(Cp - R)dT + nRdT ] / T so dh / dT =[ (dU+pdV) / T ] + nR = {[(Cp - R)dT + nRdT ] / T } + nR Solution dh = Tds + vdP differentiating with respect to temp. that is dh / dT dh / dT = ds + (vdP / dT) using PV= nRT P= nRT/V dp/dT = nR/V so collective term (vdP / dT) = nR dU = T dS - p dV from above dS = (dU+pdV) / T putting these values in dh / dT = ds + (vdP / dT) dh / dT =[ (dU+pdV) / T ] + nR now dU= Cv dT and pdV = nRdT so (dU+pdV) = Cv dT + nRdT and (dU+pdV) / T = [Cv dT + nRdT ] / T now using Cv = Cp - R we will get (dU+pdV) / T = [(Cp - R)dT + nRdT ] / T so dh / dT =[ (dU+pdV) / T ] + nR = {[(Cp - R)dT + nRdT ] / T } + nR.

dh = Tds + vdP
differentiating with respect to temp. that is dh / dT
dh / dT = ds + (vdP / dT)
using PV= nRT
P= nRT/V
dp/dT = nR/V
so collective term (vdP / dT) = nR
dU = T dS - p dV
from above dS = (dU+pdV) / T
putting these values in dh / dT = ds + (vdP / dT)
dh / dT =[ (dU+pdV) / T ] + nR
now dU= Cv dT and pdV = nRdT
so (dU+pdV) = Cv dT + nRdT
and (dU+pdV) / T = [Cv dT + nRdT ] / T
now using Cv = Cp - R we will get
(dU+pdV) / T = [(Cp - R)dT + nRdT ] / T
so dh / dT =[ (dU+pdV) / T ] + nR = {[(Cp - R)dT + nRdT ] / T } + nR
Solution
dh = Tds + vdP
differentiating with respect to temp. that is dh / dT
dh / dT = ds + (vdP / dT)
using PV= nRT
P= nRT/V
dp/dT = nR/V
so collective term (vdP / dT) = nR
dU = T dS - p dV
from above dS = (dU+pdV) / T
putting these values in dh / dT = ds + (vdP / dT)
dh / dT =[ (dU+pdV) / T ] + nR
now dU= Cv dT and pdV = nRdT
so (dU+pdV) = Cv dT + nRdT
and (dU+pdV) / T = [Cv dT + nRdT ] / T
now using Cv = Cp - R we will get

(dU+pdV) / T = [(Cp - R)dT + nRdT ] / T
so dh / dT =[ (dU+pdV) / T ] + nR = {[(Cp - R)dT + nRdT ] / T } + nR

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Tests of Controls in an Audit of Internal Control. The objective of .pdf

Tests of Controls in an Audit of Internal Control. The objective of .pdf

Tests of Controls in an Audit of Internal Control. The objective of .pdf

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Software Quality Assurance is important because Quality in the softw.pdf

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Oxygen rich blood leaves the lungs. It travels via the pulmonary vein to the heart. It travels through the aorta to the iliac artery. It then travels through the femoral artery to lower leg capillaries. It leaves the lower leg capillaries through the femoral vein It travels through the iliac vein to the inferior vena cava to the heart Carbon di oxide rich blood reaches the lungs through the pulmonary artery. Solution Oxygen rich blood leaves the lungs. It travels via the pulmonary vein to the heart. It travels through the aorta to the iliac artery. It then travels through the femoral artery to lower leg capillaries. It leaves the lower leg capillaries through the femoral vein It travels through the iliac vein to the inferior vena cava to the heart Carbon di oxide rich blood reaches the lungs through the pulmonary artery..

Oxygen rich blood leaves the lungs. It travels via the pulmonary vei.pdf

Oxygen rich blood leaves the lungs. It travels via the pulmonary vei.pdf

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Normal Concept : For colour vision, our normal human eyes have 3 cones and photoreceptors. L cone - sensitive to long wavelength of yellowish green light M cone - middle wavelength of green light s cone - short wavelength to bluish violet light Protonapia - complete absence of red cone photoreceptors.He felt difficulty in identifying the red colour Deuteranopia - complete absence of green cone photoreceptors.He felt difficulty in identifying green colour Red green colour discrimination is called red- green dichromat vision blindness.He can able to see yellow circles sometimes in place of red or green colour, it shows the unstable working colour vision receptors. If one colour dominates the vision, the other will be absent,for instance, if red hue is dominant, it strikes the receptors of green colour and vice versa. Red green dichromat friend will have reduction view in the normally appearing red - green colour.The hues, he perceives was not like normal, it looks fade olive in colour.This is due to specific absence of photoreceptors. If he able to perceive colours, either one of the phoreceptors work in exitatory state and the other in inhibitory state.This is called opponent colour theory. Of all that, he might have some degeneration or improper formation issues with myelin sheath(covering the axon of a neuron) which is responsible for colour determination. Solution Normal Concept : For colour vision, our normal human eyes have 3 cones and photoreceptors. L cone - sensitive to long wavelength of yellowish green light M cone - middle wavelength of green light s cone - short wavelength to bluish violet light Protonapia - complete absence of red cone photoreceptors.He felt difficulty in identifying the red colour Deuteranopia - complete absence of green cone photoreceptors.He felt difficulty in identifying green colour Red green colour discrimination is called red- green dichromat vision blindness.He can able to see yellow circles sometimes in place of red or green colour, it shows the unstable working colour vision receptors. If one colour dominates the vision, the other will be absent,for instance, if red hue is dominant, it strikes the receptors of green colour and vice versa. Red green dichromat friend will have reduction view in the normally appearing red - green colour.The hues, he perceives was not like normal, it looks fade olive in colour.This is due to specific absence of photoreceptors. If he able to perceive colours, either one of the phoreceptors work in exitatory state and the other in inhibitory state.This is called opponent colour theory. Of all that, he might have some degeneration or improper formation issues with myelin sheath(covering the axon of a neuron) which is responsible for colour determination..

Normal Concept For colour vision, our normal human eyes have 3 con.pdf

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LinkedListOperations.java:- class Node { public int item; public Node next; public Node(int val) { item = val; } public void displayNode() { System.out.println(\"[\" + item + \"] \"); } } class LinkedList { private Node first; public LinkedList() { first = null; } public boolean isEmpty() { return (first==null); } public void insert(int val)//inserts at beginning of list { Node newNode = new Node(val); newNode.next = first; first = newNode; } public Node delete()//deletes at beginning of list { Node temp = first; first = first.next; return temp; } public void display() { System.out.println(\"List items from first to last :\"); Node current = first; while(current != null) { current.displayNode(); current = current.next; } System.out.println(\"\"); } public Node search(int val) { Node current = first; while(current.item != val) { if(current.next == null) return null; else current = current.next; } return current; } public Node delete(int val) { Node current = first; Node previous = first; while(current.item != val) { if(current.next == null) return null; else { previous = current; current = current.next; } } if(current == first) first = first.next; else previous.next = current.next; return current; } } class LinkedListOperations { public static void main(String[] args) { LinkedList object = new LinkedList(); object.insert(10); object.insert(20); object.insert(30); object.display(); while( !object.isEmpty() ) { Node member = object.delete(); System.out.print(\"Deleted \"); member.displayNode(); System.out.println(\"\"); } object.display(); object.insert(40); object.insert(50); object.insert(60); object.display(); Node objecttosearch = object.search(50); if( objecttosearch != null) System.out.println(\"Found Node : \" + objecttosearch.item); else System.out.println(\"Cannot locate the node\"); Node objecttodelete = object.delete(50); if( objecttodelete != null ) System.out.println(\"Deleted node : \" + objecttodelete.item); else System.out.println(\"Cannot delete the node\"); object.display(); } } Solution LinkedListOperations.java:- class Node { public int item; public Node next; public Node(int val) { item = val; } public void displayNode() { System.out.println(\"[\" + item + \"] \"); } } class LinkedList { private Node first; public LinkedList() { first = null; } public boolean isEmpty() { return (first==null); } public void insert(int val)//inserts at beginning of list { Node newNode = new Node(val); newNode.next = first; first = newNode; } public Node delete()//deletes at beginning of list { Node temp = first; first = first.next; return temp; } public void display() { System.out.println(\"List items from first to last :\"); Node current = first; while(current != null) { current.displayNode(); current = current.next; } System.out.println(\"\"); } public Node search(int val) { Node current = first; while(current.item != val) { if(current.next == null) return null; else current = current.next; } return current; } public Node delete(int val) { N.

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In Keynesian economic theory, a factor that quantifies the change in total income as compared to the injection of capital deposits or investments which originally fueled the growth. It is usually used as a measurement of the effects of government spending on income, and it can be calculated as one divided by the marginal propensity to save. Average propensity to consume, or APC, is the ratio of total consumption to total disposable income, whereas marginal propensity to consume, or MPC, is the ratio of change in consumption to the change in disposable income. Y= C + S That is, disposable income (income after tax) = Consumption + Savings Think of Bob the Builder who earns a gross income of $1000 per week. After tax (which he legally has no choice but to pay) he brings in $850 dollars. His DISPOSABLE Income is $850. He then has two very simple choices- to save it all (i.e. place it in a financial institution such as a credit union, bank, super fund) or to spend it (consume as economists would say). Realistically, he will probably save a fraction and spend a fraction. The fraction of his disposable income (Y) in which he decides to save (S) is his APS- Average Propensity to Save Therefore- Amount Saved/Disposable Income or S/Y. Very simple maths. Similarly, the amount of disposable income that he uses on consumption (spends) is his Average Propensity to Consume- Consumption/Disposable Income or C/Y. The APC and APS are expressed as fractions of Disposable Income- for example 0.3 and 0.7. As he only has two choices, whether to save or spend, the APC and APS must always sum to give 1. They vary with individuals, particularly with those of different disposable incomes. Surprisingly, the wealthy has a higher APS and a lower APC compared to the poor. This is because APS/APC are proportional things; poor people will spend a larger amount of their income on bills and just general living expenses leaving little to no room for saving. As you get wealthy, your consumption will rise however you can afford to live comfortably plus have a lot more money left over for savings, hence their APS is higher. Extending this, economists have come up with the Marginal Propensity (Tendency) to Save/Consume. This looks at the tendency to save/spend each extra dollar of income that is earned. MPC is the proportion of the next dollar in which someone earns that is spent, and similarly MPS is the proportion that is saved. Eg- I give you one dollar, you spend 80 cents and keep 20 cents, your MPC is 0.8 and your MPS is 0.2. As you can see- MPC + MPS also add to 1. As pointed out above, this concept must be clearly understood, as it is the fundamental of Keynes demand theory and the multiplier which you look at to explain economic growth in year 12. As for the difference between savings and investment. Savings are placed away in a financial institution, the incentive to do so is that they earn interest and hence ‘grow’. If you look at the circular flow of income model (if yo.

In Keynesian economic theory, a factor that quantifies the change in.pdf

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import java.util.LinkedList; import java.util.Random; import java.util.Scanner; /** * author * */ public class LinkedListTest { /** * param args */ public static void main(String[] args) { int M, N, Lower, Upper; Scanner scanner = null; try { LinkedList list1 = new LinkedList(); LinkedList list2 = new LinkedList(); LinkedList list3 = new LinkedList(); Random random = new Random(); scanner = new Scanner(System.in); System.out.print(\"Enter the Lower and Upper bounds:\"); Lower = scanner.nextInt(); Upper = scanner.nextInt(); System.out.print(\"Enter the N value to Insert list1:\"); N = scanner.nextInt(); System.out.print(\"Enter the M value to Insert list2:\"); M = scanner.nextInt(); for (int i = 1; i <= N; i++) { list1.add(random.nextInt((Upper - Lower) + 1) + Lower); } for (int i = 1; i <= M; i++) { list2.add(random.nextInt((Upper - Lower) + 1) + Lower); } System.out.println(\"list1: \" + list1); System.out.println(\"list2: \" + list2); System.out.println(\"Minimum elelment in list1 :\" + getMin(list1)); System.out.println(\"Minimum elelment in list2 :\" + getMin(list2)); System.out .println(\"Count Divisibles by 3 and 5 elelment in list1 :\" + countDivisibles(list1)); System.out .println(\"Count Divisibles by 3 and 5 elelment in list2 :\" + countDivisibles(list2)); System.out.println(\"Common Elements From list1 and list2:\" + getCommonList(list1, list2)); } catch (Exception e) { // TODO: handle exception } } /** * param list * return */ public static int getMin(LinkedList list) { int min = list.get(0); for (Integer integer : list) { if (min > integer) { min = integer; } } return min; } /** * param list * return */ public static int countDivisibles(LinkedList list) { int count = 0; for (Integer integer : list) { if (integer % 3 == 0 && integer % 5 == 0) { count++; } } return count; } /** * param list1 * param list2 * return */ public static LinkedList getCommonList(LinkedList list1, LinkedList list2) { LinkedList list = new LinkedList(); LinkedList listCommon = new LinkedList(); list = (list1.size() > list2.size()) ? list1 : list2; for (int i = 0; i < list.size(); i++) { Integer number = list.get(i); if (list2.contains(number) && list1.contains(number)) { listCommon.add(number); } } return listCommon; } } OUTPUT: Enter the Lower and Upper bounds:1 10 Enter the N value to Insert list1:10 Enter the M value to Insert list2:20 list1: [1, 4, 4, 6, 9, 4, 9, 5, 8, 5] list2: [5, 10, 10, 2, 1, 10, 8, 8, 8, 2, 6, 10, 6, 2, 5, 9, 6, 9, 6, 2] Minimum elelment in list1 :1 Minimum elelment in list2 :1 Count Divisibles by 3 and 5 elelment in list1 :0 Count Divisibles by 3 and 5 elelment in list2 :0 Common Elements From list1 and list2:[5, 1, 8, 8, 8, 6, 6, 5, 9, 6, 9, 6] Solution import java.util.LinkedList; import java.util.Random; import java.util.Scanner; /** * author * */ public class LinkedListTest { /** * param args */ public static void main(String[] args) { int M, N, Lower, Upper; Scanner scanner = null; try { LinkedList list1 = new LinkedList(); L.

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Hi, Please find the answers as follows: Part A: Expected Return = .1*-10 + .2*0 + .4*10 + .2*20 + .1*30 = 10% Part B: Variance = .1*(-10 - 10)^2 + .2*(0 - 10)^2 + .4*(10 - 10)^2 + .2*(20 - 10)^2 + .1*(30 -10)^2 = 120 Standard Deviation = (120)^1/2 = 10.95% Part C: Coeffcient of Variation = Standard Deviation/Expected Return = 10.95/10 = 1.095 Part D: Stand Alone Risk is measured by th Standard Deviation or Coefficient of variation (CV) of returns. Part E: Stand Alone Risk reflects the uncertainty about the cash flows. It is relevant when the the undiversified risk of an individual asset is required to be measured. Thanks. Solution Hi, Please find the answers as follows: Part A: Expected Return = .1*-10 + .2*0 + .4*10 + .2*20 + .1*30 = 10% Part B: Variance = .1*(-10 - 10)^2 + .2*(0 - 10)^2 + .4*(10 - 10)^2 + .2*(20 - 10)^2 + .1*(30 -10)^2 = 120 Standard Deviation = (120)^1/2 = 10.95% Part C: Coeffcient of Variation = Standard Deviation/Expected Return = 10.95/10 = 1.095 Part D: Stand Alone Risk is measured by th Standard Deviation or Coefficient of variation (CV) of returns. Part E: Stand Alone Risk reflects the uncertainty about the cash flows. It is relevant when the the undiversified risk of an individual asset is required to be measured. Thanks..

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1. dh = Tds + vdP differentiating with respect to temp. that is dh / dT dh / dT = ds + (vdP / dT) using PV= nRT P= nRT/V dp/dT = nR/V so collective term (vdP / dT) = nR dU = T dS - p dV from above dS = (dU+pdV) / T putting these values in dh / dT = ds + (vdP / dT) dh / dT =[ (dU+pdV) / T ] + nR now dU= Cv dT and pdV = nRdT so (dU+pdV) = Cv dT + nRdT and (dU+pdV) / T = [Cv dT + nRdT ] / T now using Cv = Cp - R we will get (dU+pdV) / T = [(Cp - R)dT + nRdT ] / T so dh / dT =[ (dU+pdV) / T ] + nR = {[(Cp - R)dT + nRdT ] / T } + nR Solution dh = Tds + vdP differentiating with respect to temp. that is dh / dT dh / dT = ds + (vdP / dT) using PV= nRT P= nRT/V dp/dT = nR/V so collective term (vdP / dT) = nR dU = T dS - p dV from above dS = (dU+pdV) / T putting these values in dh / dT = ds + (vdP / dT) dh / dT =[ (dU+pdV) / T ] + nR now dU= Cv dT and pdV = nRdT so (dU+pdV) = Cv dT + nRdT and (dU+pdV) / T = [Cv dT + nRdT ] / T now using Cv = Cp - R we will get

2. (dU+pdV) / T = [(Cp - R)dT + nRdT ] / T so dh / dT =[ (dU+pdV) / T ] + nR = {[(Cp - R)dT + nRdT ] / T } + nR