Create a document with a form that registers all non-profit organiza.pdf
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Create a document with a form that registers all non-profit organizations in the area, the number of members they have, and the type of organization. After the user enters data in all the fields and presses the button, your program will create a single text le that saves information for each organization on a separate line. The name of the data file is np.txt. This data file should be created in the same directory as your running program, without hard-coding the file path to ensure portability. In the data file please include the Organization name, Membership, and Type, separated by commas. Membership should only accept numbers, Type should only accept the following strings: Educational, Animal Rescue, Religious, Food Service, and misspellings should not be allowed. The first line of the output will be the headers. You can make up all the names and numbers while you are testing your programs. Sample Output written to a file will look as following: Organization, Membership, Type Meals on Trucks, 123, Food Service The Church of Purple Cross, 34, Religious Kitties and Puppies, 1234, Animal Rescue Solution import java.io.BufferedWriter; import java.io.FileWriter; import java.io.IOException; import java.util.Scanner; public class WriteToFile { private static final String FILENAME = \"np.txt.\"; private static Scanner s; static int mem; static String org, type; static int getMem() { System.out.println(\"Enter Membership Number: \"); return s.nextInt(); } public static void main(String[] args) { try (BufferedWriter bw = new BufferedWriter(new FileWriter(FILENAME))) { boolean isMore = true; s = new Scanner(System.in); String content = \"Organization, Membership, Type\"; bw.write(content); while (isMore) { System.out.println(\"Enter Organization Name: \"); org = s.nextLine(); try { System.out.println(\"Enter Membership Number: \"); mem = s.nextInt(); } catch (Exception e) { System.out.println(\"Membership Should only be of Number Type\"); mem = getMem(); } boolean end = false; do { System.out.println(\"Enter Type Of Organization: \"); type = s.next(); switch (type) { case \"Educational\": break; case \"Animal Rescue\": break; case \"Religious\": break; case \"Food Service\": break; default: { System.out.println( \"Type Name Should be Only Educational, Animal Rescue ,Religious ,Food Service\"); end = true; } } } while (end); String f=org+\",\"+mem+\",\"+type; bw.newLine(); bw.append(f); System.out.println(\"Enter More Enteries?(y/n) :\"); if(s.next().equals(\"n\")) isMore=false; } } catch (IOException e) { e.printStackTrace(); } } }.
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![Create a document with a form that registers all non-profit organizations in the area, the number
of members they have, and the type of organization. After the user enters data in all the fields
and presses the button, your program will create a single text le that saves information for each
organization on a separate line. The name of the data file is np.txt. This data file should be
created in the same directory as your running program, without hard-coding the file path to
ensure portability.
In the data file please include the Organization name, Membership, and Type, separated by
commas. Membership should only accept numbers, Type should only accept the following
strings: Educational, Animal Rescue, Religious, Food Service, and misspellings should not be
allowed. The first line of the output will be the headers. You can make up all the names and
numbers while you are testing your programs.
Sample Output written to a file will look as following:
Organization, Membership, Type
Meals on Trucks, 123, Food Service
The Church of Purple Cross, 34, Religious
Kitties and Puppies, 1234, Animal Rescue
Solution
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.IOException;
import java.util.Scanner;
public class WriteToFile {
private static final String FILENAME = "np.txt.";
private static Scanner s;
static int mem;
static String org, type;
static int getMem() {
System.out.println("Enter Membership Number: ");
return s.nextInt();
}
public static void main(String[] args) {
try (BufferedWriter bw = new BufferedWriter(new FileWriter(FILENAME))) {
boolean isMore = true;](https://image.slidesharecdn.com/createadocumentwithaformthatregistersallnon-profitorganiza-230710065734-bbca1be8/85/Create-a-document-with-a-form-that-registers-all-non-profit-organiza-pdf-1-320.jpg)
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Write a java program that allows the user to input the name of a file that contains positive integers (one integer per line) The number of integers in the file The program should find all odd and even numbers and write the odd numbers to a file \"odd.txt\" and write the even numbers to another file \"even.txt\"
Solution
package expertques;
import java.io.File;
import java.io.PrintWriter;
import java.util.Scanner;
public class evenoddwithfile {
public static void main(String[] args) throws Exception {
File in;//file input
File even = new File(\"f://even.txt\");//creates file even
File odd = new File(\"f://odd.txt\");//creates file odd
Scanner s = new Scanner(System.in);//reads input from console or user
System.out.println(\"Enter the file name with path: \");
in = new File(s.nextLine());
System.out.println(\"Enter the number of integers n the file: \");
int n = s.nextInt();
if (in.exists()) {//checks if input file exist or not
Scanner ins = new Scanner(in);//reads input file
PrintWriter pe = new PrintWriter(even);//write to even file
PrintWriter po = new PrintWriter(odd);//writes to odd file
for (int i = 0; i < n; i++) {//loop till the numbers exists
int x = ins.nextInt();//reads from input file
if (x % 2 == 0) {//checks for even or odd
pe.println(x);//if even writes in even file
} else {
po.println(x);//if odd writes in odd file
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}
pe.close();//closes even file very important else nothing will be written in the file
po.close();//closes odd file very important else nothing will be written in the file
System.out.println(\"File successfully written with odds and evens\");
} else {
System.out.println(\"Error file not found at specified path\");//if file not exist
}
}
}
output
run:
Enter the file name with path:
f://integers.txt
Enter the number of integers n the file:
8
File successfully written with odds and evens
BUILD SUCCESSFUL (total time: 6 seconds)
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import java.io.PrintWriter;
import java.util.Scanner;
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PrintWriter po = new PrintWriter(odd);//writes to odd file
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int x = ins.nextInt();//reads from input file
if (x % 2 == 0) {//checks for even or odd
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} else {
po.println(x);//if odd writes in odd file
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pe.close();//closes even file very important else nothing will be written in the file
po.close();//closes odd file very important else nothing will be written in the file
System.out.println(\"File successfully written with odds and evens\");
} else {
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output
run:
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Enter the number of integers n the file:
8
File successfully written with odds and evens
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There are many different tools available to forensic investigato.docx
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Scanner scnr = new Scanner(System.in);
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String fileName = scnr.next();
Reader reader = new Reader();
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Need help with this java code. fill in lines where needed. Also, not.pdf
Need help with this java code. fill in lines where needed. Also, not sure how to make the text
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Create a package named \"reading_with_exceptions\". Write a class named:
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void process(String inputFilename)
Your program will encounter errors, and we want you to gracefully handle them in such a way
that you print out informative information and continue executing.
Your process routine will try to open a file with the name of inputFilename for input. If there is
any problem (i.e. the file doesn\'t exist), then you should catch the exception, give an appropriate
error and then return. Otherwise, your program reads the file for instructions.
Your process routine will read the first line of the file looking for an outputFilename String
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Your process method will copy the integers read from inputFilename and write them to your
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output file.
If you encounter bad input, your program should not die with an exception. For example:
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If any of the other numbers are bad, print a complaint message and skip over the data
If you don\'t have enough input numbers, complain but do not abort
After you have processed inputFilename, I would like your program to then close the output file
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We would expect the output of your program to be (Note that after 23 numbers we stop printing
numbers):
The main program will access the command line to obtain the list of filenames to call your
process routine with.
For those of you who benefit from a Template, your program might look like:
To prove that your program works, I want you to run your program with the following command
line parameters:
file1.txt non-existent-file file2.txt file3.txt
Where non-existent-file does not exist.
file1.txt contains:
file2.txt contains:
file3.txt contains:
Solution
// Reading_With_Exceptions.java
import java.io.File; // required imports for the code
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
import java.util.Scanner;
public class Reading_With_Exceptions
{ // class that runs the code
// 1.) Create a Scanner from the inputFilename. Catch exceptions from errors.
// 2.) Read the first String from the file and use it to create a PrintStream
// catching appropriate exceptions
// 3.) Using hasNextInt and nextInt, carefully re.
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Solution
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Willaims Kane
Johnson Mitchel
Sachin Tendulkar
Vinod kamblie
Sanjay Manjrekar
Ravi sastri
Ricky Pointing
Clarke Michael
_____________________
code:
#include
#include
#include
#include
using namespace std;
int main()
{
//Declaring variables
string fname,lname;
string uname;
int index=0;
//defines an input stream for the data file
ifstream dataIn;
//Defines an output stream for the data file
ofstream dataOut;
//Opening the input file
dataIn.open(\"D:\\\\people.txt\");
//creating and Opening the output file
dataOut.open(\"D:\\\\usernames.txt\");
//This loop continues to execute until the end of the file
while (!dataIn.eof( ))
{
//reading the firstname and lastname from people.txt file
dataIn>>fname>>lname;
//Concatinating the firstname first letter with the lastname
uname=lname+fname.at(index);
//Storing the user name in the txt file
dataOut<.
PAGE 1Input output for a file tutorialStreams and File IOI.docx
PAGE
1Input output for a file tutorialStreams and File I/O
In this tutorial we study the following concepts:
Text File I/O
Techniques for a file: Class File
Binary File I/O
File Objects and File Name
Note: For question 4 of the midterm you only need to look at the sections 2.2 and 2.3. I do not think you need java class: StringTokenizer. But I just added a small section about it to the end of this tutorial.
So far we learned keyboard/screen I/O. It is time to learn File I/O.
1 An Overview of stream and file I/O
A stream is an object that either outputs data or inputs data. The Java System.out is a stream object that outputs data on the screen.
As our program gets bigger and bigger we may need to enter a lot of data every time we run our program. We also may have a lot of data as the output of the program. It is not practical to enter a sizable input from the keyboard. Therefore, we save the data in a file and let our program to input from this file. Similarly, it is not practical to look at a sizable output. Moreover, we may need to save the output for further study. Therefore, we let our program to output to a file.
We have two kinds of I/O files: Text files and binary files. A text file is readable and understandable by human, but a binary file is not. The size of a text file is bigger than the size of a binary file. We can write arrays without using a loop into a binary file. We can also write objects to a binary file.
2 Text-File I/O
In this section we learn how to input from a text file and how to output to a text file. We first look at output instructions for a text file.
2.1 Text-File Output with PrintWriter class.
To be able to write to a file we need the Java class PrintWriter. This class is in JDK java.io, therefore we need to import it . Another class that we need is : FileOutputStream. This class also is in java.io. A file output stream is an output stream for writing data to a File.
Example 1. The following program to write an integer, a floating point number, a Boolean value and a string into a text file.
import java. io. PrintWriter;
import java. io. FileNotFoundException;
publicclass Main {
publicstaticvoid main( String[] args) {
PrintWriter out = null;
try {
out = new PrintWriter("out.txt");
} catch( FileNotFoundException e) {
System. out. println("Error: opening the file out.txt");
System. exit( 0);
}
out.println(-12);
out.println(25.5);
out.println(true);
out.println("John Doe.");
//Note that we also can write:
out.println(-12+"\n"+ 25.5 + "\n" + true + "\n" + "John Doe.");
out.close();
} }
The content of the file out.txt would be:
-12
25.5
true
John Doe.
-12
25.5
true
John Doe.
Description:
First we need to declare a variable that refers to and object of class PrintWriter. This class has several constructors. One of them needs the name of the output file on the hard drive (or other storages): out = new PrintWriter("out.txt")
This instruction co.
Write a program in java that asks a user for a file name and prints .pdf
Write a program in java that asks a user for a file name and prints the number of characters,
words (separated by whitespace), and lines in that file. Then, it replaces each line of the file with
its reverse. For example, if the file contains the following lines (Test1.txt):
This is a test
Hi there
Output on the console:
Number of characters: 22
Number of words: 6
Number of lines: 2
Data written to the file (Test1.txt):
tset a si sihT
ereth iH
Solution
ReadFileCount.java
import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintStream;
import java.util.Scanner;
public class ReadFileCount {
public static void main(String[] args) throws FileNotFoundException {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter file name: \");
String fileName = scan.next();
StringBuffer finalsb = new StringBuffer();
File file = new File(fileName);
if(file.exists()){
int numberOfLines = 0;
int numberOfCharacters = 0;
int numberOfWords = 0;
Scanner scan1 = new Scanner(file);;
while(scan1.hasNextLine()){
StringBuffer sb = new StringBuffer();
String s = scan1.nextLine();
sb.append(s);
numberOfLines++;
numberOfCharacters = numberOfCharacters + s.length();
String words[] = s.split(\" \");
numberOfWords = numberOfWords + words.length;
finalsb.append(sb.reverse());
finalsb.append(\"\ \");
}
System.out.println(\"Number of characters: \"+numberOfCharacters);
System.out.println(\"Number of words: \"+numberOfWords);
System.out.println(\"Number of lines : \"+numberOfLines);
PrintStream ps =new PrintStream(file);
ps.print(finalsb.toString());
ps.flush();
ps.close();
System.out.println(\"Data written to the file \"+fileName);
}
else{
System.out.println(\"File does not exist\");
}
}
}
Output:
Enter file name:
D:\\\\Test1.txt
Number of characters: 0
Number of words: 0
Number of lines : 0
Data written to the file D:\\\\Test1.txt
Test1.txt
tset a si sihT
ereht iH.
Chapter 10.1
The document discusses different types of files and the File class in Java. It explains that all files are collections of bytes to the computer, which are interpreted as text, numbers, images, etc. by software. Files can be categorized as text files containing ASCII characters or binary files containing other data types. The File class represents files and directories, and allows checking if a file exists, getting its length and name, and determining if it can be read or written. Methods like list() are used to get all files in a directory.
Apache tika
Apache Tika is a library that is used for document type detection and content extraction from various file formats.
Eventlog
The document discusses event logs in Windows, which record system and application events. It explains that event logs include the application log, system log, security log, and other custom logs. The event log centralizes logging for applications and the operating system. It notes that the event log can be used to audit activity and comply with regulations by monitoring events in real-time, performing audits and analysis, and archiving logs. The document also provides examples of events recorded in each log type and discusses how to programmatically work with event logs using the EventLog class in C#.
File Handling In C++(OOPs))
This document provides an overview of file handling in C++. It discusses the need for data files and the two main types: text files and binary files. Text files store readable character data separated by newline characters, while binary files store data in the same format as memory. The key classes for file input/output in C++ are ifstream, ofstream, and fstream. Functions like open(), read(), write(), get(), put(), and close() are used to work with files. Files can be opened in different modes like append, read, or write and it is important to check if they open successfully.
Copyright © 2018 Pearson Education, Inc. C H A P T E R 6.docx
Copyright © 2018 Pearson Education, Inc.
C H A P T E R 6
Files and Exceptions
Copyright © 2018 Pearson Education, Inc.
TopicsIntroduction to File Input and OutputUsing Loops to Process FilesProcessing RecordsExceptions
Copyright © 2018 Pearson Education, Inc.
Introduction to File Input and OutputFor program to retain data between the times it is run, you must save the data
Data is saved to a file, typically on computer disk
Saved data can be retrieved and used at a later time“Writing data to”: saving data on a fileOutput file: a file that data is written to
Copyright © 2018 Pearson Education, Inc.
Copyright © 2018 Pearson Education, Inc.
Introduction to File Input and Output (cont’d.)“Reading data from”: process of retrieving data from a fileInput file: a file from which data is readThree steps when a program uses a file
Open the file
Process the file
Close the file
Copyright © 2018 Pearson Education, Inc.
Copyright © 2018 Pearson Education, Inc.
Types of Files and File Access MethodsIn general, two types of files
Text file: contains data that has been encoded as text
Binary file: contains data that has not been converted to textTwo ways to access data stored in file
Sequential access: file read sequentially from beginning to end, can’t skip ahead
Direct access: can jump directly to any piece of data in the file
Copyright © 2018 Pearson Education, Inc.
Filenames and File ObjectsFilename extensions: short sequences of characters that appear at the end of a filename preceded by a period
Extension indicates type of data stored in the fileFile object: object associated with a specific file
Provides a way for a program to work with the file: file object referenced by a variable
Copyright © 2018 Pearson Education, Inc.
Filenames and File Objects (cont’d.)
Copyright © 2018 Pearson Education, Inc.
Opening a Fileopen function: used to open a file
Creates a file object and associates it with a file on the disk
General format:
file_object = open(filename, mode)Mode: string specifying how the file will be opened
Example: reading only ('r'), writing ('w'), and appending ('a')
Copyright © 2018 Pearson Education, Inc.
Specifying the Location of a FileIf open function receives a filename that does not contain a path, assumes that file is in same directory as programIf program is running and file is created, it is created in the same directory as the program
Can specify alternative path and file name in the open function argument
Prefix the path string literal with the letter r
Copyright © 2018 Pearson Education, Inc.
Writing Data to a FileMethod: a function that belongs to an object
Performs operations using that objectFile object’s write method used to write data to the file
Format: file_variable.write(string)File should be closed using file object close method
Format: file_variable.close()
Copyright © 2018 Pearson Education, Inc.
Reading Data From a Fileread method: file object method tha.
Create a text file named lnfo.txt. Enter the following informatio.pdf
The document describes a Java program that takes user input of a name, address, and phone number and writes it line by line to a text file. The program runs in a continuous loop prompting for input until the user enters "Exit" for the name, at which point it closes the file and exits the program.
File Handling in Java.pdf
This document discusses file handling in Java. It begins by explaining that a file stores related information together and describes standard input, output, and error streams in Java which represent System.in, System.out, and System.err. It then discusses input and output streams in Java, describing how to create them and common methods. It also covers the Java File class and common file operations like creating, reading from, writing to, and deleting files.
Assignment #4 will be the construction of 2 new classes and a driver program/...
This document describes an assignment to create two new classes - BirthInfo and Pet - and a driver class Assignment4. The BirthInfo class stores information about a pet's birth including date, month, year and place. The Pet class represents a pet with attributes for name, type, and birth information. The Assignment4 driver class displays a menu and allows the user to add a pet by entering its details, display the pet information, or quit the program. It provides test case input and expected output files to test the program.
File Handling In C++
The document outlines file handling in C++, including the need for data files, types of files (text and binary), basic file operations for each type, and the components used in C++ for file handling like header files, classes, and functions. It discusses opening, reading, writing, and closing files, as well as file pointers and random vs sequential access.
Below are the transactions and adjustments that occurred during the .pdf
Below are the transactions and adjustments that occurred during the first year of operations at
Kissick Co
a. Issued 190,000 shares of $5-par-value common stock for $950,000 in cash.
b. Borrowed $500,000 from Oglesby National Bank and signed a 10% note due in three years.
c. Incurred and paid $380,000 in salaries for the year.
d. Purchased $730,000 of merchandise inventory on account during the year.
e. Sold inventory costing $590,000 for a total of $910,000, all on credit.
f. Paid rent of $220,000 on the sales facilities during the first 11 months of the year.
g. Purchased $180,000 of store equipment, paying $55,000 in cash and agreeing to pay the
difference within 90 days.
h. Paid the entire $125,000 owed for store equipment and $620,000 of the amount due to
suppliers for credit purchases previously recorded.
i. Incurred and paid utilities expense of $35,000 during the year.
j. Collected $825,000 in cash from customers during the year for credit sales previously
recorded.
k. At year-end, accrued $50,000 of interest on the note due to Oglesby National Bank.
l. At year-end, accrued $20,000 of past-due December rent on the sales facilities. Required a.
Prepare an income statement (ignoring income taxes) for Kissick Co.\'s first year of operations
and a balance sheet as of the end of the year. account affected by the transactions.) KISSICK CO
Income Statement
Solution
Answers
ASSETS
LIABILITIES
STOCKHOLDER EQUITY
INCOME STATEMENT (Retained earnings)
Transaction
Cash
Accounts receivables
Merchandise Inventory
Equipment
Notes Payable
Accounts Payable
Common Stock
Net Income
Revenue
Expenses
a
$ 950,000.00
$ 950,000.00
$ -
b
$ 500,000.00
$ 500,000.00
$ -
c
$ (380,000.00)
$ (380,000.00)
$ 380,000.00
d
$ 730,000.00
$ 730,000.00
$ -
e
$ 910,000.00
$ 910,000.00
$ 910,000.00
$ (590,000.00)
$ (590,000.00)
$ 590,000.00
f
$ (220,000.00)
$ (220,000.00)
$ 220,000.00
g
$ (55,000.00)
$ 55,000.00
$ -
$ 125,000.00
$ 125,000.00
$ -
h
$ (745,000.00)
$ (745,000.00)
$ -
i
$ (41,000.00)
$ (41,000.00)
$ 41,000.00
j
$ 825,000.00
$ (825,000.00)
$ -
k
$ 50,000.00
$ (50,000.00)
$ 50,000.00
l
$ 20,000.00
$ (20,000.00)
$ 20,000.00
Total
$ 834,000.00
$ 85,000.00
$ 140,000.00
$ 180,000.00
$ 550,000.00
$ 130,000.00
$ 950,000.00
$ (391,000.00)
$ 910,000.00
$ 1,301,000.00
Transaction no.
e
Sales Revenues
$ 910,000.00
e
Cost of Goods Sold
$ 590,000.00
Gross Profits
$ 320,000.00
Operating Expenses:
c
Salaries expense
$ 380,000.00
f + l
Rent Expenses
$ 240,000.00
i
Utilities expense
$ 41,000.00
Total operating expenses
$ 661,000.00
Operating Income
$ (341,000.00)
Other revenues & expenses
j
Interest expense
$ 50,000.00
Net Income (Loss)
$ (391,000.00)
ASSETS
Current Assets:
Cash
$ 834,000.00
Accounts receivables
$ 85,000.00
Merchandise Inventory
$ 140,000.00
Total current assets
$ 1,059,000.00
Equipment
$ 180,000.00
Total Assets
$ 1,239,000.00
LIABILITIES
Accounts Payable
$ 110,000.00
Interest Payable
$ 50,000.00
Rent (Expense) Payable
$ 20,000.00
Total current Liabilities
$ 180,0.
Help Please. Results not given Explain how your results for the pe.pdf
Help Please. Results not given Explain how your results for the percent of water in the hydrate
and the formula of the hydrate would be changed if water from the air were absorbed by the hot
dry sample as it cools. Be specific and justifty your answer.
Solution
For example take calcium sulphate anhydrous form which is black in color upon cooling changes
to blue which is calcium sulphate penta hydrate . The percent of water content increases and also
5 H2O is added in the empirical formula..
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There are many different tools available to forensic investigato.docx
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Assignment:
What other analysis tools are available (our book gives several examples) for organizations to use, who are the developers of those tools (organization/individual/open source), and what is the use of each tool you are reporting?
Find three different tools used/available. Answer the above questions with a minimum of 1 full page (more pages are certainly acceptable). Set your paragraphs to 1.5 spacing, 0 points before and after. Use Arial or Times New Roman font, size 12 point. You only need to include your name at the top of the document, the rest is content.
...
Change the code in Writer.java only to get it working. Must contain .pdf
Change the code in Writer.java only to get it working. Must contain methods: logReverse() ,
logMax(), logDuplicates(),
This lab is going to focus on File Output, which you will find is somewhat similar to console
output.
FileMain.java
import java.io.IOException;
import java.util.ArrayList;
import java.util.Scanner;
public class FileMain {
public static void main(String[] args) throws IOException{
Scanner scnr = new Scanner(System.in);
System.out.print("Please enter the name of the file you would like to read: ");
String fileName = scnr.next();
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents(fileName);
System.out.println("Please enter a name for your new file: ");
String newFileName = scnr.next();
Writer fileOut = new Writer(newFileName);
fileOut.logReverse(fileContents);
fileOut.logMax(fileContents);
fileOut.logDuplicates(fileContents);
fileOut.closeWriter();
scnr.close();
}
}
Filetester.java
import java.io.IOException;
import java.util.ArrayList;
public class FileTester {
public static boolean testLogReverse(ArrayList contents) throws IOException {
Writer writer = new Writer("logReverseTest.txt");
writer.logReverse(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Reversed file contents: ");
expected.add("58");
expected.add("12");
expected.add("19");
expected.add("42");
expected.add("12");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logReverseTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogMax(ArrayList contents) throws IOException {
Writer writer = new Writer("logMaxTest.txt");
writer.logMax(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("The largest number in the file is: 58");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logMaxTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogDuplicates(ArrayList contents) throws IOException {
Writer writer = new Writer("logDuplicatesTest.txt");
writer.logDuplicates(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Duplicates found: true");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logDuplicatesTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static void main(String[] args) throws IOException {
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents("nums.txt");
System.out.println("logReverse test passed? " + testLogReverse(fileContents));
System.out.println("logMax test passed? " + testLogMax(fileContents));
System.out.println("logDuplicates test passed? " + testLogDuplicates(fileContents));
}
}
Reader.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Sca.
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Austin Powell - Digital Forensic Case Study.pdf
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Need help with this java code. fill in lines where needed. Also, not.pdf
Need help with this java code. fill in lines where needed. Also, not sure how to make the text
files and load them into program. Thanks!!
Create a package named \"reading_with_exceptions\". Write a class named:
Reading_With_Exceptions with the following method:
void process(String inputFilename)
Your program will encounter errors, and we want you to gracefully handle them in such a way
that you print out informative information and continue executing.
Your process routine will try to open a file with the name of inputFilename for input. If there is
any problem (i.e. the file doesn\'t exist), then you should catch the exception, give an appropriate
error and then return. Otherwise, your program reads the file for instructions.
Your process routine will read the first line of the file looking for an outputFilename String
followed by an integer. i.e.:
outputFilename number_to_read
Your program will want to write output to a file having the name outputFilename. Your program
will try to read from \"inputFilename\" the number of integers found in \"number_to_read\".
Your process method will copy the integers read from inputFilename and write them to your
output file(i.e. outputFilename). There should contain 10 numbers per line of output in your
output file.
If you encounter bad input, your program should not die with an exception. For example:
If the count of the numbers to be read is bad or < 0 you will print out a complaint message and
then read as many integers as you find.
If any of the other numbers are bad, print a complaint message and skip over the data
If you don\'t have enough input numbers, complain but do not abort
After you have processed inputFilename, I would like your program to then close the output file
and tell the user that the file is created. Then Open up the output file and copy it to the Screen.
For example, if inputFilename contained:
We would expect the output of your program to be (Note that after 23 numbers we stop printing
numbers):
The main program will access the command line to obtain the list of filenames to call your
process routine with.
For those of you who benefit from a Template, your program might look like:
To prove that your program works, I want you to run your program with the following command
line parameters:
file1.txt non-existent-file file2.txt file3.txt
Where non-existent-file does not exist.
file1.txt contains:
file2.txt contains:
file3.txt contains:
Solution
// Reading_With_Exceptions.java
import java.io.File; // required imports for the code
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
import java.util.Scanner;
public class Reading_With_Exceptions
{ // class that runs the code
// 1.) Create a Scanner from the inputFilename. Catch exceptions from errors.
// 2.) Read the first String from the file and use it to create a PrintStream
// catching appropriate exceptions
// 3.) Using hasNextInt and nextInt, carefully re.
Write a C++ program that reads in a list of first and last names fro.pdf
Write a C++ program that reads in a list of first and last names from an input data file named
people.txt. The program should create a user name for each person consisting of the last name
and the first initial of the first name. The program should print the first name, the last name, and
the created user name for each person to the output data file usernames.txt. The program must
use an end-of-file (EOF) loop.
Solution
people.txt (Save this file under D Drive .Then the path of the file pointing to it is D:\\\\people.txt)
Willaims Kane
Johnson Mitchel
Sachin Tendulkar
Vinod kamblie
Sanjay Manjrekar
Ravi sastri
Ricky Pointing
Clarke Michael
_____________________
code:
#include
#include
#include
#include
using namespace std;
int main()
{
//Declaring variables
string fname,lname;
string uname;
int index=0;
//defines an input stream for the data file
ifstream dataIn;
//Defines an output stream for the data file
ofstream dataOut;
//Opening the input file
dataIn.open(\"D:\\\\people.txt\");
//creating and Opening the output file
dataOut.open(\"D:\\\\usernames.txt\");
//This loop continues to execute until the end of the file
while (!dataIn.eof( ))
{
//reading the firstname and lastname from people.txt file
dataIn>>fname>>lname;
//Concatinating the firstname first letter with the lastname
uname=lname+fname.at(index);
//Storing the user name in the txt file
dataOut<.
PAGE 1Input output for a file tutorialStreams and File IOI.docx
PAGE
1Input output for a file tutorialStreams and File I/O
In this tutorial we study the following concepts:
Text File I/O
Techniques for a file: Class File
Binary File I/O
File Objects and File Name
Note: For question 4 of the midterm you only need to look at the sections 2.2 and 2.3. I do not think you need java class: StringTokenizer. But I just added a small section about it to the end of this tutorial.
So far we learned keyboard/screen I/O. It is time to learn File I/O.
1 An Overview of stream and file I/O
A stream is an object that either outputs data or inputs data. The Java System.out is a stream object that outputs data on the screen.
As our program gets bigger and bigger we may need to enter a lot of data every time we run our program. We also may have a lot of data as the output of the program. It is not practical to enter a sizable input from the keyboard. Therefore, we save the data in a file and let our program to input from this file. Similarly, it is not practical to look at a sizable output. Moreover, we may need to save the output for further study. Therefore, we let our program to output to a file.
We have two kinds of I/O files: Text files and binary files. A text file is readable and understandable by human, but a binary file is not. The size of a text file is bigger than the size of a binary file. We can write arrays without using a loop into a binary file. We can also write objects to a binary file.
2 Text-File I/O
In this section we learn how to input from a text file and how to output to a text file. We first look at output instructions for a text file.
2.1 Text-File Output with PrintWriter class.
To be able to write to a file we need the Java class PrintWriter. This class is in JDK java.io, therefore we need to import it . Another class that we need is : FileOutputStream. This class also is in java.io. A file output stream is an output stream for writing data to a File.
Example 1. The following program to write an integer, a floating point number, a Boolean value and a string into a text file.
import java. io. PrintWriter;
import java. io. FileNotFoundException;
publicclass Main {
publicstaticvoid main( String[] args) {
PrintWriter out = null;
try {
out = new PrintWriter("out.txt");
} catch( FileNotFoundException e) {
System. out. println("Error: opening the file out.txt");
System. exit( 0);
}
out.println(-12);
out.println(25.5);
out.println(true);
out.println("John Doe.");
//Note that we also can write:
out.println(-12+"\n"+ 25.5 + "\n" + true + "\n" + "John Doe.");
out.close();
} }
The content of the file out.txt would be:
-12
25.5
true
John Doe.
-12
25.5
true
John Doe.
Description:
First we need to declare a variable that refers to and object of class PrintWriter. This class has several constructors. One of them needs the name of the output file on the hard drive (or other storages): out = new PrintWriter("out.txt")
This instruction co.
Write a program in java that asks a user for a file name and prints .pdf
Write a program in java that asks a user for a file name and prints the number of characters,
words (separated by whitespace), and lines in that file. Then, it replaces each line of the file with
its reverse. For example, if the file contains the following lines (Test1.txt):
This is a test
Hi there
Output on the console:
Number of characters: 22
Number of words: 6
Number of lines: 2
Data written to the file (Test1.txt):
tset a si sihT
ereth iH
Solution
ReadFileCount.java
import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintStream;
import java.util.Scanner;
public class ReadFileCount {
public static void main(String[] args) throws FileNotFoundException {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter file name: \");
String fileName = scan.next();
StringBuffer finalsb = new StringBuffer();
File file = new File(fileName);
if(file.exists()){
int numberOfLines = 0;
int numberOfCharacters = 0;
int numberOfWords = 0;
Scanner scan1 = new Scanner(file);;
while(scan1.hasNextLine()){
StringBuffer sb = new StringBuffer();
String s = scan1.nextLine();
sb.append(s);
numberOfLines++;
numberOfCharacters = numberOfCharacters + s.length();
String words[] = s.split(\" \");
numberOfWords = numberOfWords + words.length;
finalsb.append(sb.reverse());
finalsb.append(\"\ \");
}
System.out.println(\"Number of characters: \"+numberOfCharacters);
System.out.println(\"Number of words: \"+numberOfWords);
System.out.println(\"Number of lines : \"+numberOfLines);
PrintStream ps =new PrintStream(file);
ps.print(finalsb.toString());
ps.flush();
ps.close();
System.out.println(\"Data written to the file \"+fileName);
}
else{
System.out.println(\"File does not exist\");
}
}
}
Output:
Enter file name:
D:\\\\Test1.txt
Number of characters: 0
Number of words: 0
Number of lines : 0
Data written to the file D:\\\\Test1.txt
Test1.txt
tset a si sihT
ereht iH.
Chapter 10.1
The document discusses different types of files and the File class in Java. It explains that all files are collections of bytes to the computer, which are interpreted as text, numbers, images, etc. by software. Files can be categorized as text files containing ASCII characters or binary files containing other data types. The File class represents files and directories, and allows checking if a file exists, getting its length and name, and determining if it can be read or written. Methods like list() are used to get all files in a directory.
Apache tika
Apache Tika is a library that is used for document type detection and content extraction from various file formats.
Eventlog
The document discusses event logs in Windows, which record system and application events. It explains that event logs include the application log, system log, security log, and other custom logs. The event log centralizes logging for applications and the operating system. It notes that the event log can be used to audit activity and comply with regulations by monitoring events in real-time, performing audits and analysis, and archiving logs. The document also provides examples of events recorded in each log type and discusses how to programmatically work with event logs using the EventLog class in C#.
File Handling In C++(OOPs))
This document provides an overview of file handling in C++. It discusses the need for data files and the two main types: text files and binary files. Text files store readable character data separated by newline characters, while binary files store data in the same format as memory. The key classes for file input/output in C++ are ifstream, ofstream, and fstream. Functions like open(), read(), write(), get(), put(), and close() are used to work with files. Files can be opened in different modes like append, read, or write and it is important to check if they open successfully.
Copyright © 2018 Pearson Education, Inc. C H A P T E R 6.docx
Copyright © 2018 Pearson Education, Inc.
C H A P T E R 6
Files and Exceptions
Copyright © 2018 Pearson Education, Inc.
TopicsIntroduction to File Input and OutputUsing Loops to Process FilesProcessing RecordsExceptions
Copyright © 2018 Pearson Education, Inc.
Introduction to File Input and OutputFor program to retain data between the times it is run, you must save the data
Data is saved to a file, typically on computer disk
Saved data can be retrieved and used at a later time“Writing data to”: saving data on a fileOutput file: a file that data is written to
Copyright © 2018 Pearson Education, Inc.
Copyright © 2018 Pearson Education, Inc.
Introduction to File Input and Output (cont’d.)“Reading data from”: process of retrieving data from a fileInput file: a file from which data is readThree steps when a program uses a file
Open the file
Process the file
Close the file
Copyright © 2018 Pearson Education, Inc.
Copyright © 2018 Pearson Education, Inc.
Types of Files and File Access MethodsIn general, two types of files
Text file: contains data that has been encoded as text
Binary file: contains data that has not been converted to textTwo ways to access data stored in file
Sequential access: file read sequentially from beginning to end, can’t skip ahead
Direct access: can jump directly to any piece of data in the file
Copyright © 2018 Pearson Education, Inc.
Filenames and File ObjectsFilename extensions: short sequences of characters that appear at the end of a filename preceded by a period
Extension indicates type of data stored in the fileFile object: object associated with a specific file
Provides a way for a program to work with the file: file object referenced by a variable
Copyright © 2018 Pearson Education, Inc.
Filenames and File Objects (cont’d.)
Copyright © 2018 Pearson Education, Inc.
Opening a Fileopen function: used to open a file
Creates a file object and associates it with a file on the disk
General format:
file_object = open(filename, mode)Mode: string specifying how the file will be opened
Example: reading only ('r'), writing ('w'), and appending ('a')
Copyright © 2018 Pearson Education, Inc.
Specifying the Location of a FileIf open function receives a filename that does not contain a path, assumes that file is in same directory as programIf program is running and file is created, it is created in the same directory as the program
Can specify alternative path and file name in the open function argument
Prefix the path string literal with the letter r
Copyright © 2018 Pearson Education, Inc.
Writing Data to a FileMethod: a function that belongs to an object
Performs operations using that objectFile object’s write method used to write data to the file
Format: file_variable.write(string)File should be closed using file object close method
Format: file_variable.close()
Copyright © 2018 Pearson Education, Inc.
Reading Data From a Fileread method: file object method tha.
Create a text file named lnfo.txt. Enter the following informatio.pdf
The document describes a Java program that takes user input of a name, address, and phone number and writes it line by line to a text file. The program runs in a continuous loop prompting for input until the user enters "Exit" for the name, at which point it closes the file and exits the program.
File Handling in Java.pdf
This document discusses file handling in Java. It begins by explaining that a file stores related information together and describes standard input, output, and error streams in Java which represent System.in, System.out, and System.err. It then discusses input and output streams in Java, describing how to create them and common methods. It also covers the Java File class and common file operations like creating, reading from, writing to, and deleting files.
Assignment #4 will be the construction of 2 new classes and a driver program/...
This document describes an assignment to create two new classes - BirthInfo and Pet - and a driver class Assignment4. The BirthInfo class stores information about a pet's birth including date, month, year and place. The Pet class represents a pet with attributes for name, type, and birth information. The Assignment4 driver class displays a menu and allows the user to add a pet by entering its details, display the pet information, or quit the program. It provides test case input and expected output files to test the program.
File Handling In C++
The document outlines file handling in C++, including the need for data files, types of files (text and binary), basic file operations for each type, and the components used in C++ for file handling like header files, classes, and functions. It discusses opening, reading, writing, and closing files, as well as file pointers and random vs sequential access.
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There are many different tools available to forensic investigato.docx
Change the code in Writer.java only to get it working. Must contain .pdf
Change the code in Writer.java only to get it working. Must contain .pdf
D2L Site Admin Tools Discussion at Brightspace South Carolina Connection
D2L Site Admin Tools Discussion at Brightspace South Carolina Connection
Need help with this java code. fill in lines where needed. Also, not.pdf
Need help with this java code. fill in lines where needed. Also, not.pdf
Write a C++ program that reads in a list of first and last names fro.pdf
Write a C++ program that reads in a list of first and last names fro.pdf
PAGE 1Input output for a file tutorialStreams and File IOI.docx
PAGE 1Input output for a file tutorialStreams and File IOI.docx
Write a program in java that asks a user for a file name and prints .pdf
Write a program in java that asks a user for a file name and prints .pdf
Copyright © 2018 Pearson Education, Inc. C H A P T E R 6.docx
Copyright © 2018 Pearson Education, Inc. C H A P T E R 6.docx
Create a text file named lnfo.txt. Enter the following informatio.pdf
Create a text file named lnfo.txt. Enter the following informatio.pdf
Assignment #4 will be the construction of 2 new classes and a driver program/...
Assignment #4 will be the construction of 2 new classes and a driver program/...
More from rohit219406
Below are the transactions and adjustments that occurred during the .pdf
Below are the transactions and adjustments that occurred during the first year of operations at
Kissick Co
a. Issued 190,000 shares of $5-par-value common stock for $950,000 in cash.
b. Borrowed $500,000 from Oglesby National Bank and signed a 10% note due in three years.
c. Incurred and paid $380,000 in salaries for the year.
d. Purchased $730,000 of merchandise inventory on account during the year.
e. Sold inventory costing $590,000 for a total of $910,000, all on credit.
f. Paid rent of $220,000 on the sales facilities during the first 11 months of the year.
g. Purchased $180,000 of store equipment, paying $55,000 in cash and agreeing to pay the
difference within 90 days.
h. Paid the entire $125,000 owed for store equipment and $620,000 of the amount due to
suppliers for credit purchases previously recorded.
i. Incurred and paid utilities expense of $35,000 during the year.
j. Collected $825,000 in cash from customers during the year for credit sales previously
recorded.
k. At year-end, accrued $50,000 of interest on the note due to Oglesby National Bank.
l. At year-end, accrued $20,000 of past-due December rent on the sales facilities. Required a.
Prepare an income statement (ignoring income taxes) for Kissick Co.\'s first year of operations
and a balance sheet as of the end of the year. account affected by the transactions.) KISSICK CO
Income Statement
Solution
Answers
ASSETS
LIABILITIES
STOCKHOLDER EQUITY
INCOME STATEMENT (Retained earnings)
Transaction
Cash
Accounts receivables
Merchandise Inventory
Equipment
Notes Payable
Accounts Payable
Common Stock
Net Income
Revenue
Expenses
a
$ 950,000.00
$ 950,000.00
$ -
b
$ 500,000.00
$ 500,000.00
$ -
c
$ (380,000.00)
$ (380,000.00)
$ 380,000.00
d
$ 730,000.00
$ 730,000.00
$ -
e
$ 910,000.00
$ 910,000.00
$ 910,000.00
$ (590,000.00)
$ (590,000.00)
$ 590,000.00
f
$ (220,000.00)
$ (220,000.00)
$ 220,000.00
g
$ (55,000.00)
$ 55,000.00
$ -
$ 125,000.00
$ 125,000.00
$ -
h
$ (745,000.00)
$ (745,000.00)
$ -
i
$ (41,000.00)
$ (41,000.00)
$ 41,000.00
j
$ 825,000.00
$ (825,000.00)
$ -
k
$ 50,000.00
$ (50,000.00)
$ 50,000.00
l
$ 20,000.00
$ (20,000.00)
$ 20,000.00
Total
$ 834,000.00
$ 85,000.00
$ 140,000.00
$ 180,000.00
$ 550,000.00
$ 130,000.00
$ 950,000.00
$ (391,000.00)
$ 910,000.00
$ 1,301,000.00
Transaction no.
e
Sales Revenues
$ 910,000.00
e
Cost of Goods Sold
$ 590,000.00
Gross Profits
$ 320,000.00
Operating Expenses:
c
Salaries expense
$ 380,000.00
f + l
Rent Expenses
$ 240,000.00
i
Utilities expense
$ 41,000.00
Total operating expenses
$ 661,000.00
Operating Income
$ (341,000.00)
Other revenues & expenses
j
Interest expense
$ 50,000.00
Net Income (Loss)
$ (391,000.00)
ASSETS
Current Assets:
Cash
$ 834,000.00
Accounts receivables
$ 85,000.00
Merchandise Inventory
$ 140,000.00
Total current assets
$ 1,059,000.00
Equipment
$ 180,000.00
Total Assets
$ 1,239,000.00
LIABILITIES
Accounts Payable
$ 110,000.00
Interest Payable
$ 50,000.00
Rent (Expense) Payable
$ 20,000.00
Total current Liabilities
$ 180,0.
Help Please. Results not given Explain how your results for the pe.pdf
Help Please. Results not given Explain how your results for the percent of water in the hydrate
and the formula of the hydrate would be changed if water from the air were absorbed by the hot
dry sample as it cools. Be specific and justifty your answer.
Solution
For example take calcium sulphate anhydrous form which is black in color upon cooling changes
to blue which is calcium sulphate penta hydrate . The percent of water content increases and also
5 H2O is added in the empirical formula..
As a software developer you have been delegated with the assignment .pdf
As a software developer you have been delegated with the assignment of developing a software
“Library Management System” for an educational institute to manage their books. Elaborate the
different tasks you will undertake at each step of the software development lifecycle to develop
an efficient software
Solution
There are basically three phases in developing this LIbrary Management System .They are:
1)Project Initiation
2)Project execution
3)Release and usage (deploying)
1) PROJECT INITIATION : This is the Starting pahse of the project.Here the requirements are
gathered and the scope and cost of executing the project are known.This is known for deciding
whether the project should be developed or not.
2)PROJECT EXECUTION
In this phase the development or execution of the project takes place. Here we will try to build
up the project.
In this we have three sub-phases they are:
A. system analysis
• Initial study: The details about the project are known.
• Information gathering:The components or tools required to build up the project are
gathered.EX:Programming languages.
B. System design
• Design standard
• High level design & design tools
• Database design
• Logical design
• Construction
3. System implementation
• Integration & testing : Here all the individual build up phases are combined and are developed
into a totally functional system and are thouroughly tested.
• Post implementation :This is generally the BEta testing or USer Acceptence testing phase,This
is done after the entire project is implemented.
3)PROJECT DEPLOYMENT
In this phase the project is ready for work.It is deployed and is used.
After all these phases MAINTENANCE phase takes place.In MAINTENANCE phase any faults
which are found in the system will be solved..
What scientist is credited with proposing the equivalency of mass and.pdf
What scientist is credited with proposing the equivalency of mass and energy? What is the
famous equation that he proposed?
Solution
Here ,
the scientist proposing the equivalency of mass and energy was Albert Einstein.
the equation proposed by him was.
E = m * c^2
where E is energy
m is mass
c is the speed of light.
Why do countries with high GNI and GDP are attractive for foreign in.pdf
Why do countries with high GNI and GDP are attractive for foreign investment?
Solution
Let us first understand what is a GNI and GDP
The gross national income (GNI) is the total domestic and foreign output claimed by residents of
a country, consisting of gross domestic product (GDP) plus factor incomes earned by foreign
residents, minus income earned in the domestic economy by nonresidents
Gross Domestic Product (GDP) is the broadest quantitative measure of a nation\'s total economic
activity. More specifically, GDP represents the monetary value of all goods and services
produced within a nation\'s geographic borders over a specified period of time.
The gross domestic product (GDP) is one of the primary indicators used to gauge the health of a
country\'s economy. It represents the total dollar value of all goods and services produced over a
specific time period; you can think of it as the size of the economy. Usually, GDP is expressed as
a comparison to the previous quarter or year. For example, if the year-to-year GDP is up 3%, this
is thought to mean that the economy has grown by 3% over the last year.
Measuring GDP is complicated (which is why we leave it to the economists), but at its most
basic, the calculation can be done in one of two ways: either by adding up what everyone earned
in a year (income approach), or by adding up what everyone spent (expenditure method).
Logically, both measures should arrive at roughly the same total.
Both the factors reflects the following ; and are most important in attracting foreign investments
In other words ,it determine the health of the any given economy ,and therefore is an important
yardstick to assess and measure and invest.
Which of the following is NOT true about the ESCBA.It acts as an.pdf
Which of the following is NOT true about the? ESCB?
A.It acts as an independent monetary authority.
B.It is an abbreviation for the European System of Central Banks.
C.Any one country can exert veto power over monetary policy.
D.It includes European Central Bank
Solution
A) It acts as an independent monetary authority. This is not true for ESCB as it consists of ECB
and 28 state national central banks. So the ESCB is not a monetary authority and also many EU
states having national banks have not joined euro..
What is 4 -4 + infinity - infinity As x approaches 3 from th.pdf
What is 4 -4 + infinity - infinity As x approaches 3 from the right (i.e. 3) the values are just
bigger that 3. So the denominator is positive and approaching 0. Hence the limit is going to +
infinity. Had the denominator been (3 - x) then the answer would have been - infinity.
Solution
c) +infinity if x approaches from 3+ then it will always be less than 3 ,suppose
x=3.00001 then the difference = 3-3.00001 = -.00001 hence when denominator is 3-x it will
always tend to (-infinity).
Use what you have learned so far to bring variety in your writing. U.pdf
Use what you have learned so far to bring variety in your writing. Use the following lines or your
own sheet of paper to write six sentences that practice each basic sentence pattern. When you
have finished, label each part of the sentence (S, V, LV, N, Adj, Adv, DO, IO).
1. ________________________________________________________________
2. ________________________________________________________________
3. ________________________________________________________________
4. ________________________________________________________________
5. ________________________________________________________________
6. ________________________________________________________________
Solution
The sentences you have encountered so far have been independent clauses. As you look more
closely at your past writing assignments, you may notice that some of your sentences are not
complete. A sentence that is missing a subject or a verb is called a fragment. A fragment may
include a description or may express part of an idea, but it does not express a complete thought.
Fragment: Children helping in the kitchen.
Complete sentence: Children helping in the kitchen often make a mess.
You can easily fix a fragment by adding the missing subject or verb. In the example, the sentence
was missing a verb. Adding often make a mess creates an S-V-N sentence structure. Figure 3.1
illustrates how you can edit a fragment to become a complete sentence.
Editing Fragments That Are Missing a Subject or a Verb
Fragment: Told her about the broken vase.
Complete sentence: I told her about the broken vase.
Complete sentence: The store down on Main Street sells music.
Common Sentence Errors
Fragments often occur because of some common errors, such as starting a sentence with a
preposition, a dependent word, an infinitive, or a gerund. If you use the six basic sentence
patterns when you write, you should be able to avoid these errors and thus avoid writing
fragments.
When you see a preposition, check to see that it is part of a sentence containing a subject and a
verb. If it is not connected to a complete sentence, it is a fragment, and you will need to fix this
type of fragment by combining it with another sentence. You can add the prepositional phrase to
the end of the sentence. If you add it to the beginning of the other sentence, insert a comma after
the prepositional phrase. Look at the examples. Figure 3.2 illustrates how you can edit a
fragment that begins with a preposition.
Example A:
[Incorrect: After walking over two miles. John remembered his wallet. Correct: After walking
over two miles, John remembered his wallet. Correct: John remembered his wallet after walking
over two miles.]
Example B:
[Incorrect: The dog growled at the vacuum cleaner. When it was switched on. Correct: When the
vacuum cleaner was switched on, the dog growled. Correct: The dog growled at the vacuum
cleaner when it was switched on.]
Clauses that start with a dependent word—such as since, because, without.
Use C programmingMake sure everything works only uploadSol.pdf
Use C programming
Make sure everything works only upload
Solution
C program
#include
int isPrime(int number);// function prototype
int main()
{
int No,i;// variable decleration
printf(\"Input a number greater than 2: \");// asking user to enter a number
scanf(\"%d\",&No);// scaning the number form user
if(No <= 2)// checking no is lessthan or equ to 2
{ // if yes print message
printf(\"No prime number is smaller than %d.\ \",No);
return 0;// and stop computation
}
// else print the prime numbers
printf(\"Prime numbers smaller than %d:\",No);
for (i = 2;i.
Thoroughly describe the molecular underpinnings of ONE and only one.pdf
Thoroughly describe the molecular underpinnings of ONE and only one of these processes.
Transcription initiation and elongation
Solution
Transcription is the biochemical process involves transferring of information from DNA to
RNA, assisted with RNA polymerase. The RNA produced in this process will be converted to
protein in the process of translation. RNA polymerase read the DNA template and synthesize
with help of other important proteins to carried out the process. The process of transcription
comprises of series of events leading to Initiation, elongation, and termination. In the initiation
process, RNA polymerase with other adapter proteins binds to the upstream of DNA in the
initiation point.
RNA polymerase complexed with unwound DNA which bind to the promoter sequence, and
results in the initiation of the process. Promoter region contains an initiation site where process
begins. RNA polymerase synthesize new strand RNA, which is complementary to the DNA
strand.
In elongation phase, DNA polymerase lengthened the RNA, used as a DNA triplet code in the
template strand. polymerse read the template until the signal is percieved. RNA polymerase
functions by adding nucleotids to 3\' end of the strand and synthesized in 5\' to 3\' direction..
The Blackbeard Company Ltd provided the following information in reg.pdf
The Blackbeard Company Ltd provided the following information in regard to its operations for
the year ended 30 June 2014:
Cash Book Summary
Opening balance
$20,000
Accounts Payable
$40,000
Accounts receivable
100,000
Bills Payable (suppliers)
20,000
Bills Receivable (suppliers)
20,000
Interest paid
60,000
Debenture Issue
400,000
Operating expenses
180,000
Dividends received
20,000
Salaries & wages
200,000
Interest received
40,000
Current tax payable
80,000
Motor vehicles
60,000
Plant & machinery
100,000
Share capital
200,000
Dividend paid
120,000
Balance c/d
60,000
860,000
860,000
Balance b/d
60,000
Required:
(a) Net cash used in operating activities; (b) Net cash used in investing activities; (c) Net cash
from financing activities;
(d) Net increase/(decrease) in cash and cash equivalents.
Please use the following format
Statement of Cash Flows for Blackbeard Company
For the Financial Year Ended 30 June 2014
( i ) Cash flows from Operating Activities
Inflows/
Inflows/
(Outflows)
(Outflows)
Net cash used in operating activities
( ii ) Cash flows from Investing Activities
Net cash used in Investing Activities
( iii ) Cash flows from Financing Activities
Cash Book Summary
Opening balance
$20,000
Accounts Payable
$40,000
Accounts receivable
100,000
Bills Payable (suppliers)
20,000
Bills Receivable (suppliers)
20,000
Interest paid
60,000
Debenture Issue
400,000
Operating expenses
180,000
Dividends received
20,000
Salaries & wages
200,000
Interest received
40,000
Current tax payable
80,000
Motor vehicles
60,000
Plant & machinery
100,000
Share capital
200,000
Dividend paid
120,000
Balance c/d
60,000
860,000
860,000
Balance b/d
60,000
Solution
Statement of Cash flows for Blackbeard Company For the Financial Year Ended 30
June 2014 (i) Cash flow from Operating Activities Inflows/(outflows)
Inflows/(outflows) Accounts Receivable $ 1,00,000 Bills Receivable (suppliers)
$ 20,000 Accounts Payable $ -40,000 Bills Payable(suppliers) $ -
20,000 Operating expense $ -1,80,000 Salaries and wages $ -2,00,000
Current Tax Payable $ -80,000 Dividend received $ 20,000 Interest
received $ 40,000 Net Cash used in Operating Activties $ -3,40,000
(ii) Cash flow from Investing Activities Sales of Motor Vehicle
$ 60,000 Purchase of Plant and Machinery $ -1,00,000 Net Cash
from Investing Actiivties $ -40,000 (iii) Cash flow from Financing activities
Debenture issue $ 4,00,000 Share capital $ 2,00,000 Interest
paid $ -60,000 Dividend paid $ -1,20,000 Net Cash from
financing actiivties $ 4,20,000 Net Increase /(decrease) in cash and cash
equivalent $ 40,000 Cash at the Beginning of the period $ 20,000 Cash at the
end of the period $ 60,000.
Thank you 1. What is responsible for anteriorposterior axis formati.pdf
Thank you 1. What is responsible for anterior:posterior axis formation in the chicken? How is
dorsal ventral patterning accomplished? 2. What is the role of the Posterior Marginal zone in
early chicken development? 3. What is the primitive streak and why is it important in chicken
development? 4. What is the function of Henson\'s Node? To what is it analogous in amphibian
development?
Solution
1.The primitive streak defines the axes of the embryo. It extends from posterior to anterior;
migrating cells enter through its dorsal side and move to its ventral side; and it separates the left
portion of the embryo from the right. Those elements close to the streak will be the medial
(central) structures, while those farther from it will be the distal (lateral) structures
2.Primitive streak is induced by the posterior marginal zone (PMZ) of Koller\'s sickle, which can
also induce Hensen\'s node. If cell movement in the PMZ is blocked, primitive streak does not
form.Thus, the PMZ acts as an organizer.Cells in marginal zones of the embryo, like the PMZ,
are key to development and cell fate determination in chick embryos.
3.The primitive streak is a structure that forms in the blastula during the early stages of avian,
reptilian and mammalian embryonic development. It forms on the dorsal (back) face of the
developing embryo, toward the caudal or posterior end.The presence of the primitive streak will
establish bilateral symmetry, determine the site of gastrulation and initiate germ layer formation.
To form the streak, reptiles, birds and mammals arrange mesenchymal cells along the
prospective midline, establishing the second embryonic axis, as well as the place where cells will
ingress and migrate during the process of gastrulation and germ layer formation.The primitive
streak extends through this midline and creates the left–right and cranial–caudal body axes,and
marks the beginning of gastrulation.This process involves the ingression of mesoderm
progenitors and their migration to their ultimate position,where they will differentiate into the
mesoderm germ layer that, together with endoderm and ectoderm germ layers, will give rise to
all the tissues of the adult organism.
4.
The primitive knot (or primitive node) is the organizer for gastrulation in the vertebrate embryo.
Diversity
In birds, it is known as \"Hensen\'s node\", and is named after its discoverer Victor Hensen.
In amphibians, it is known as \"Spemann\'s organizer\", and is named after Hans Spemann
In chick development, the primitive knot starts as a regional knot of cells that forms on the
blastodisc immediately anterior to where the outer layer of cells will begin to migrate inwards -
an area known as the primitive streak, which is involved with Koller\'s sickle. Posterior to the
node is the primitive pit, where the cells of the epiblast (the upper layer of embryonic cells)
initially begin to invaginate. This invagination expands posteriorly into the primitive groove as
the cells layers c.
Take the basic Hardy-Weinberg Equilibrium equation, where there are a.pdf
Take the basic Hardy-Weinberg Equilibrium equation, where there are alleles A and B. If the
frequency of the two alleles are represented by p and q, then the expected genotypic frequencies
are p2 2pq q2. Please review your comfort with calculating observed and expected allele and
genotype frequencies. Try adding subscripts to the equation for relative fitness (use w) to predict
change in allele frequency due to selection. Both inbreeding and genetic drift can cause problems
for rare species with declining population size due to reducing genetic diversity. Please contrast
(say how they are different these two forces in terms of number of alleles at a locus (some loci
have more than two alleles) and in terms of average heterozygosity at a locus. In most organisms
most mating is local. If populations of an organism are scattered across a landscape, with gaps
between population, how will that affect inbreeding and expected Hardy Weinberg equilibrium?
Solution
Both inbreeding and genetic drift can cause problems for rare species with declining population
size due to reducing genetic diversity. Please contrast (say how they are different) these two
forces in terms of number of alleles at a locus (some loci have more than two alleles) and in
terms of average heterozygosity at a locus. In most organisms most mating is local. If
populations of an organism are scattered across a landscape, with gaps between population, how
will that affect inbreeding and expected Hardy-Weinberg equilibrium? If migration among
populations increases how will it affect inbreeding and expected hardy-Weinberg equilibrium?
P^2 = homozygous dominant
2pq =heterozygotes
Q^2= homozygous recessive
According to hardy Weinberg
P^2 +2pq + Q^2 =1
p = p2 + ½ (2pq) = p2 + pq
q = q2 + ½ (2pq) = q2 + pq
p + q = 1
(p + q)2 = 1
p2 + 2pq + q2 = 1 (the Hardy-Weinberg Principle)
Inbreeding can be referred as the mating between closely related organisms.
Inbreeding favors homozygosity, and increase q^2 (recessive homozygotes) and decreases
dominant phenotypes
It will increases the chances of offspring being affected by recessive or lethal traits.
Genetic bottlenecks and founder effects occurs in the population
Leads to
Hence population will be deviated from hardy-Weinberg equilibrium.
Systems analysis project 10 can you answer the 4 questions at the t.pdf
Systems analysis project 10: can you answer the 4 questions at the task section, thank you.
Personal Trainer, Inc. owns and operates fitness centers in a dozen Midwestern cities. The
centers have done well, and the company is planning an international expansion by opening a
new “supercenter” in the Toronto area. Personal Trainer’s president, Cassia Umi, hired an IT
consultant, Susan Park, to help develop an information system for the new facility. During the
project, Susan will work closely with Gray Lewis, who will manage the new operation.
Background
Susan and Gray finished their work on user interface, input, and output design. They developed
a user-centered design that would be flexible and easy to learn. Now Susan turned her attention
to the architecture for the new system. Susan wanted to consider their own organization and
culture, enterprise resource planning, total cost of ownership, scalability, Web integration, legacy
systems, processing methods, security issues, and corporate portal. She also needed to select a
network plan, or topology, that would dictate the physical cabling and network connections, or
consider a wireless network. When all these tasks were completed, she would submit a system
design specification for approval.
Tasks:
1. What would be the advantages of selecting an Internet-based architecture for the Personal
Trainer’s system?
2. If Personal Trainer wants to increase its Internet marketing efforts, what advice could you
offer? Perform research to find out more about the topic of Web-based marketing before you
answer Gray.
3. What software and hardware infrastructure will be necessary to ensure Personal Trainer can
process point of sale transactions?
4. Prepare an outline for a system design specification and describe the contents of each section
Solution
1)
The Internet has had a colossal effect on system architecture modeling. The Internet has turn out
to be more than a communication channel — numerous IT onlookers see it as a in a far-reaching
way distinctive environment for system development. In a customary client/server system, the
client handles the user interface and the server (or servers in a multi-level framework) handles
the information and application rationale. As it were, a piece of the framework keeps running on
the customer, part on the server.
Interestingly, in an Internet-based architecture, notwithstanding information and application
rationale, the whole user interface is given by the Web server as HTML coded documents that
are deciphered and showed by the client\'s browser. Moving the obligation regarding the
interface from the client to the server improves the procedure of information transmission and
results in lower hardware’s expenses and complexities. The pattern toward Internet-based e-
business is reshaping the IT scene as additional firms utilize the Web to manufacture proficient,
solid, and practical arrangements. At the point when arranging new systems, experts can utilize
accessible.
Step 1. Read critically and analyze the following scenarioGeraldi.pdf
Step 1. Read critically and analyze the following scenario:
Geraldine Barney Garrett, the granddaughter of Wilford Barney took over the reins of the R&D
department of Biotech Health and Life Products (Biotech) in 1965. She had trained at the hands
of her grandmother Wilford’s mother, Maria. Geraldine was a strong manager and developed the
Research and Development (R&D) lab from the advanced kitchen of her grandmother to the
scientific lab of her peers. Geraldine’s management philosophy evolved over the years but she
had several basic ideas that kept her grounded. Geraldine knew she had to answer to the family
in every decision she made. Her grandmother stressed this point and she eventually came to
agree. Therefore, decisions were made by her. She also realized that her employees had good
ideas and talent but they did not bear the responsibility she did. So, although she consulted with
the employees often, she never gave them the power to make important decisions.
Geraldine was charismatic in a motherly way and employees saw her as someone to learn from
but career growth was unlikely so in five or six years employees moved on to another company.
The unambitious stayed on and eventually Geraldine collected a small group of people she
trusted and who became her team. Now, several of the team members are retiring like Geraldine
leaving few left to the company.
When it comes to leading the entire R&D Division, Geraldine is very controlled in defining
goals, setting tasks, and is outstanding at dividing the work among the employees, organizing the
product materials and coordinating and communicating activities between the different
departments. Decisions that Geraldine makes are always dependent on the circumstances and
context of the decision. You often hear her instructing the young employees stating, “Always ask
yourself, which method will work best here? Remember, you are always looking to find the
simplest and most cost-effective solution.” When it comes to developing new products and
innovating, Geraldine is much more open to other people’s input and ideas relying heavily on her
team of experienced but older people. Still, the final decision remains in her hands.
Geraldine could see the need for changes in the lab, the most important of which was retaining
younger employees. Since she was retiring at the end of the year, Geraldine knew the new
department head would have to deal with the problem. Her immediate concern was who the new
department head should be. Her own granddaughter, Melanie Malone, was now working in the
company and she knew Melanie was expecting the job.
Melanie was qualified for the job. She was a Phi Beta Kappa graduate of the University of
Maryland College Park with a double major in Botany and Food Science. She minored in
Business Management. She had worked in the plant in Chicago every summer since High School
and had reproduced and revised all her grandmother’s and great-great grandmother’s recipes.
Starting full-time .
Question 3 2 pts In response to the Great Recession, the Federal Rese.pdf
Question 3 2 pts In response to the Great Recession, the Federal Reserve engaged in quantitative
easing. As a consequence, the monetary base rose by nearly 400%, causing some to worry about
inflation. However, during this time the money supply rose by only 110%. What explains this? A
money multiplier greater than 1. A money multiplier equal to 1. A money multiplier smaller than
1. A negative money multiplier.
Solution
Money multiplier = Money supply / monetary base = 110 / 400 = 0.275
A money multiplier smaller than 1.
Prove that the T_i -property is a topological property for i = 0S.pdf
Prove that the T_i -property is a topological property for i = 0
Solution
Hausdorff spaces do not have in general the homotopy type of any finite space. Recall that a
topological space
X satisfies the T1- separation axiom if for any two distinct points x, y X there exist open sets U
and V such that
x U, y V , y / U, x / V . This is equivalent to saying that the points are closed in X. All
Hausdorff spaces are
T1, but the converse is false.
Q4.14. Which of the following species is most likely to exhibit pate.pdf
Q4.14. Which of the following species is most likely to exhibit paternal care?
The polygynous topi antelope, one of nine species of lekking mammals.
Atlantic cod, a broadcast spawner for which fertilization by satellite males is common.
The monogamous great spotted woodpecker, a species whose males have high paternity
certainty.
Bonobos, a polygynandrous primate with internal fertilization and very low paternity certainty.
Solution
Ans c the monogamous great spotted wood pecker , a species whose males have high paternity
certainty.
They belong to family picidae and live in forests or woodland habitats..
Prepare a classified balance sheet. Do not show the components that .pdf
Prepare a classified balance sheet. Do not show the components that add up to your answer in
requirement 1 but rather show only the line “Cash and Cash Equivalents.” (Amounts to be
deducted should be indicated by a minus sign.)Gatti Corporation reported the following balances
at June 30.
Solution
1. Cash and cash equivalents = Cash + Cash equivalents + Petty cash + Restricted cash
= 15 + 20 + 25 + 20
= $80
2. Gatti Corporation
Balance Sheet
June 30Assets$Liabilities$Current assetsCurrent liabilitiesCash and cash equivalents80Notes
payable20Account receivable95Accounts payable105Total current assets175Unearned
revenue45Property, plant and equipmentTotal current liabilities170Equipment350Long term
liabilitiesLess: Accumulated depreciation-45Notes payable110Property, plant and equipment,
net305Total long term liabilities110Total liabilities280Stockholders EquityCommon
stock150Retained earnings50Total stockholders equity200Total assets480Total liabilities and
stockholders equity480.
Microscopes and telescopes both consist of two converging lenses cont.pdf
Microscopes and telescopes both consist of two converging lenses contained in a tube. What is
the difference in set-up of the two lenses between a microscope and a telescope? The rearview
mirror on a truck warns the user that objects may be closer than they appear. What kind of mirror
is being used, and why was that type selected? Why does a clear stream always appear to be
shallower than it actually is? Discuss the type of aberration involved in each of the following
situations. (i) The edges of the image appear reddish. (ii) The image cannot be clearly focused.
A baby fish has his eyesight tested and is found to be myopic. His father wants to make a set of
glasses to correct for this problem. Since fish live under water, the father fish will make the
glasses out of a very thin clear plastic bag which is filled with air (n = 1.000). What type of lens
does the fish need to make? What shape should the lens be? What is the wavelength of yellow
light?
Solution
In refracting telescopes, there are typically two convex lenses. One lens acts as the objective
lens: this lens gathers light from faraway objects and forms a real, inverted image of the object at
its focal point. A second lens, called the eyepiece, is positioned such that the image formed by
the objective lens is at its focal point. When an observer looks through the eyepiece with a
relaxed eye, they are able to see an object of the image, formed at infinity. Microscopes are used
to look at magnified images of small objects. A simple microscope (a “magnifying glass”)
consists of a single convex lens. The lens is held close to the object so that the object is between
the lens and its focal point. When viewed from the other side of the lens, a magnified, virtual,
upright image is seen. The compound microscope is the most common type of microscope used
in laboratories. With these microscopes, an objective lens is used to create an inverted, real
image of the object. Using the eyepiece, the image is magnified. In this sense, its operating
principles are similar to that of a refracting telescope. The rear view mirror is a convex mirror
which forms a virtual and erect image of the object which is smaller in length than the object.
Because the image formed is smaller in length, it appears to be farther away and hence, the
warning written on it. This is because of the phenomenon of refraction of light as it crosses the
medium of water(refractive index greater than that of air). As the light ray travels from
water(denser medium) to air(rarer medium), the light ray bends away from the normal and the
image of the bottom of the stream seems to be raised and hence, the stream appears to be
shallower. a) In optics, chromatic aberration (CA, also called chromatic distortion, and
spherochromatism) is an effect resulting from dispersion in which there is a failure of a lens to
focus all colors to the same convergence point. It occurs because lenses have different refractive
indices for differentwavelength.
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