Unit 3 : Coordinate Geometry
Chapter 7 : Coordinate Geometry
1. Fundamentals
2. Distance Formula
3. Section Formula
4. Mid – Point Formula
Topics
1. Fundamentals
1
2
3
4
5
6
1 2 3 4 5 6
-1
-2
-3
-4
-5
-6
Y
X
X’
Y’
-1
-2
-3
-4
-5
-6
𝟏𝒔𝒕 Quadrant
X – axis
Y – axis
𝟐𝒏𝒅
Quadrant
𝟒𝒕𝒉
Quadrant
𝟑𝒓𝒅
Quadrant
Origin
1. Fundamentals
X
0
Y
(𝒙𝟏 ,
𝒚𝟏)
P
𝒚𝟏
𝒙𝟏
(𝒙𝟏 ,
𝟎)
(𝟎 , 𝒚𝟏)
(𝟎 , 𝟎)
Origin
Distance of a point from the x-axis is
y-coordinate or ordinate
Distance of a point from the y-axis is
x-coordinate or abscissa
2. Distance Formula
𝑷 (𝒙𝟏 , 𝒚𝟏)
𝑸 (𝒙𝟐 , 𝒚𝟐)
0
𝑫 (𝟎 , 𝒚𝟐)
𝑪 (𝟎 , 𝒚𝟏)
𝑨 (𝒙𝟏 , 𝟎) 𝑩 (𝒙𝟐 , 𝟎)
Y-axis
X-axis
(𝒙𝟐 – 𝒙𝟏)
(𝒚𝟐 – 𝒚𝟏)
𝑷𝑸 = (𝒙𝟐 – 𝒙𝟏)
𝟐
+ (
𝒚𝟐 – 𝒚𝟏)
𝟐
3. Section Formula
𝒎 𝒏
𝑷(𝒙 , 𝒚) 𝑩(𝒙𝟐 , 𝒚𝟐)
𝑨(𝒙𝟏 , 𝒚𝟏)
𝑷 (𝒙 , 𝒚) =
𝒎𝒙𝟐 +
𝒏𝒙𝟏
𝒎 + 𝒏
,
𝒎𝒚𝟐 +
𝒏𝒚𝟏
𝒎 + 𝒏
𝑷 (𝒙 , 𝒚) =
𝒎𝒙𝟐 +
𝒏𝒙𝟏
𝒎 + 𝒏
,
𝒎𝒚𝟐 +
𝒏𝒚𝟏
𝒎 + 𝒏
4. Mid – Point Formula
𝑨
(𝒙𝟏, 𝒚𝟏)
𝑷
(𝒙, 𝒚)
𝑩
(𝒙𝟐, 𝒚𝟐)
𝑷 (𝒙 , 𝒚) =
𝒙𝟏 + 𝒙𝟐
2
,
𝒚𝟏 + 𝒚𝟐
2
Question 1
Find the ratio in which y-axis divides the line segment joining the
points A(5, –6) and B(–1, –4). Also find the coordinates of the
point of division.
Question 2
Find the value of k, if the point A(0, 3) is equidistant from P(3, k)
and Q(k, 4).
Question 3
Find the perimeter of the triangle formed by the points (0, 0),
(2, 0) and (0, 2).
Question 4
Find the point on the x-axis which is equidistant from (2, –5) and
(–2, 9).
Question 5
Find the points of trisection of the line segment joining the points
A(-4, 3) and B(2, -1).
Question 6
If the point C(–1, 2) divides internally the line segment joining
A(2, 5) and B(x, y) in the ratio 3 : 4, find the coordinates of B.
Question 7
In what ratio is the line segment joining the points (-1, 3) and
(4, -7) divided by the point (2, -3)?
Question 8
Let P and Q be the points of trisection of the line segment joining
the points A(2, – 2) and B(–7, 4) such that P is nearer to A. Find
the coordinates of P and Q.
Question 9
Determine if the points (1, 5), (2, 3) and (– 2, – 11) are collinear.
Question 10
Find the area of a rhombus if its vertices are (3, 0), (4, 5), (– 1, 4)
and (– 2, – 1) taken in order.
[Hint : Area of a rhombus =
𝟏
𝟐
× (product of its diagonals)]
Question 11
Find the coordinates of point A, where AB is the diameter of a
circle whose center is (2, – 3) and point B is (1, 4).
Question 12
The points (𝒂, 𝒂), (−𝒂, −𝒂) and (− 𝟑𝒂, 𝟑𝒂) are the vertices of
a/an ……… triangle.
Question 13
The x-coordinate of a point P is twice its y-coordinate. If P
is equidistant from Q(2, -5) and R(-3, 6), find the coordinates
of P.
Question 14
If two vertices of an equilateral triangle be (𝟎, 𝟎), 𝟑, 𝟑 , find
the third vertex.
Question 15
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crash course unit 3 grade 10.pdf without any adds

  • 1.
    Unit 3 :Coordinate Geometry Chapter 7 : Coordinate Geometry
  • 6.
    1. Fundamentals 2. DistanceFormula 3. Section Formula 4. Mid – Point Formula Topics
  • 7.
    1. Fundamentals 1 2 3 4 5 6 1 23 4 5 6 -1 -2 -3 -4 -5 -6 Y X X’ Y’ -1 -2 -3 -4 -5 -6 𝟏𝒔𝒕 Quadrant X – axis Y – axis 𝟐𝒏𝒅 Quadrant 𝟒𝒕𝒉 Quadrant 𝟑𝒓𝒅 Quadrant Origin
  • 8.
    1. Fundamentals X 0 Y (𝒙𝟏 , 𝒚𝟏) P 𝒚𝟏 𝒙𝟏 (𝒙𝟏, 𝟎) (𝟎 , 𝒚𝟏) (𝟎 , 𝟎) Origin Distance of a point from the x-axis is y-coordinate or ordinate Distance of a point from the y-axis is x-coordinate or abscissa
  • 9.
    2. Distance Formula 𝑷(𝒙𝟏 , 𝒚𝟏) 𝑸 (𝒙𝟐 , 𝒚𝟐) 0 𝑫 (𝟎 , 𝒚𝟐) 𝑪 (𝟎 , 𝒚𝟏) 𝑨 (𝒙𝟏 , 𝟎) 𝑩 (𝒙𝟐 , 𝟎) Y-axis X-axis (𝒙𝟐 – 𝒙𝟏) (𝒚𝟐 – 𝒚𝟏) 𝑷𝑸 = (𝒙𝟐 – 𝒙𝟏) 𝟐 + ( 𝒚𝟐 – 𝒚𝟏) 𝟐
  • 10.
    3. Section Formula 𝒎𝒏 𝑷(𝒙 , 𝒚) 𝑩(𝒙𝟐 , 𝒚𝟐) 𝑨(𝒙𝟏 , 𝒚𝟏) 𝑷 (𝒙 , 𝒚) = 𝒎𝒙𝟐 + 𝒏𝒙𝟏 𝒎 + 𝒏 , 𝒎𝒚𝟐 + 𝒏𝒚𝟏 𝒎 + 𝒏 𝑷 (𝒙 , 𝒚) = 𝒎𝒙𝟐 + 𝒏𝒙𝟏 𝒎 + 𝒏 , 𝒎𝒚𝟐 + 𝒏𝒚𝟏 𝒎 + 𝒏
  • 11.
    4. Mid –Point Formula 𝑨 (𝒙𝟏, 𝒚𝟏) 𝑷 (𝒙, 𝒚) 𝑩 (𝒙𝟐, 𝒚𝟐) 𝑷 (𝒙 , 𝒚) = 𝒙𝟏 + 𝒙𝟐 2 , 𝒚𝟏 + 𝒚𝟐 2
  • 13.
  • 14.
    Find the ratioin which y-axis divides the line segment joining the points A(5, –6) and B(–1, –4). Also find the coordinates of the point of division. Question 2
  • 15.
    Find the valueof k, if the point A(0, 3) is equidistant from P(3, k) and Q(k, 4). Question 3
  • 16.
    Find the perimeterof the triangle formed by the points (0, 0), (2, 0) and (0, 2). Question 4
  • 17.
    Find the pointon the x-axis which is equidistant from (2, –5) and (–2, 9). Question 5
  • 18.
    Find the pointsof trisection of the line segment joining the points A(-4, 3) and B(2, -1). Question 6
  • 19.
    If the pointC(–1, 2) divides internally the line segment joining A(2, 5) and B(x, y) in the ratio 3 : 4, find the coordinates of B. Question 7
  • 20.
    In what ratiois the line segment joining the points (-1, 3) and (4, -7) divided by the point (2, -3)? Question 8
  • 21.
    Let P andQ be the points of trisection of the line segment joining the points A(2, – 2) and B(–7, 4) such that P is nearer to A. Find the coordinates of P and Q. Question 9
  • 22.
    Determine if thepoints (1, 5), (2, 3) and (– 2, – 11) are collinear. Question 10
  • 23.
    Find the areaof a rhombus if its vertices are (3, 0), (4, 5), (– 1, 4) and (– 2, – 1) taken in order. [Hint : Area of a rhombus = 𝟏 𝟐 × (product of its diagonals)] Question 11
  • 24.
    Find the coordinatesof point A, where AB is the diameter of a circle whose center is (2, – 3) and point B is (1, 4). Question 12
  • 25.
    The points (𝒂,𝒂), (−𝒂, −𝒂) and (− 𝟑𝒂, 𝟑𝒂) are the vertices of a/an ……… triangle. Question 13
  • 26.
    The x-coordinate ofa point P is twice its y-coordinate. If P is equidistant from Q(2, -5) and R(-3, 6), find the coordinates of P. Question 14
  • 27.
    If two verticesof an equilateral triangle be (𝟎, 𝟎), 𝟑, 𝟑 , find the third vertex. Question 15
  • 28.
    Take the testfor FREE Registration link in description! Exam Dates: 21st Jan - 22nd Jan 28th Jan - 29th Jan 4th Feb - 5th Feb
  • 29.
    Stand A Chance toWin Big Get Scholarships* worth 100 Crore And exciting Cash Awards* *T&C Apply Get A 15-Page Personalised Academic Report ● Overall Analysis ● Skillset Analysis ● Behavioural Analysis ● Subject Analysis ● Capability Analysis ● Career Inclinations
  • 30.