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By Logan Danielson
Titrations
Titrations are done to determine the unknown
  concentrations of unknown acids.

It is based of off determining how much known acid or
  base is needed to reach the equivalence point of the
  unknown liquid and at what pH the equivalence point
  exists.

The equivalence point is the middle point of the fastest
  changing pH area. Usually a color indicator is used to help
  find the equivalence point as well as a pH indicator.
Solubility Equilibria
Adding an ionic solid to water
   It will be in equilibrium so long as some solid exists in
     solution



Mg(OH)2(s)<-> Mg2+(aq) + 2 OH-(aq)


   Ksp= [Mg2+][OH-]2
        This is the solubility product constant for the above equation
          Note, the solid is not part of the equation
Predicting precipitation
For Mg(OH)2(s)<-> Mg2+(aq) + 2 OH-(aq)


   If Q= [Mg2+][OH-]2 < Ksp then the there will be no
    precipitate.
   If Q > Ksp then the there will be a precipitate.


   Note, if Q was < Ksp then only Mg2+(aq) or OH-(aq) would need
     to be added to cause precipitation.
Thermodynamics
Is the flow of energy

1st law of thermodynamics
   The total energy of the universe is constant, energy can not
      be created nor destroyed
             If you decrease the energy in the system, then you increase the
              energy of the surrounding
             If you increase the energy in the system, then you decrease the
              energy of the surrounding

 U = internal energy = all potential energy + all kinetic energy

 dU universe = dU system + dU surroundings
    dU system = - dU surroundings
Thermodynamics 2: heat and work
dU system = Heat (q) + Work (w)
   q= Heat = energy flow from the change in temperature
   w= Work = energy flow from movement against a force


Closed system- do not allow matter in or out of the system

q<0 – heat flows out of the system
q>0 – heat flows into the system

w<0 – the system does work on the surrounding
w>0 – the surrounding does work on the system
Thermodynamics 3: enthalpy
The most common work in chemical systems
 w= -P dV
       Work= - Pressure * change in Volume

  dU system = q – P * dV

  dH (enthalpy) = dU + d(PV)
    dH = dU + P*dH @ constant P
    Plugging in “dU system = q – P * dV” you get:
    dH = q - P*dH + P*dH = q @ constant P
    dH = q @ constant P
2nd law of thermodynamics
All spontaneous processes increase the entropy of the
 universe
  dS (entropy) > 0 for spontaneous processes


Entropy is a measure of the dispersive-ness of energy
  A larger value of entropy is a more dispersed energy
Guessing thermodynamics
C6H12O6(s) -> 2 C2H3OH(s) + 2 CO2(g)
   dH>0 because we are breaking more bonds then we are forming
   dS>0 because there are more moles on the right


H2O(s) -> H2O(l)
   dS>0 because liquid is more dispersible than solid
H2O(l) -> H2O(g)
   dS>0 because gas is more dispersible than liquid
Entropy guessing rules
Increase Entropy
  Breaking bonds without making new ones
  Change to a favored phase
  More moles on the product side
Entropy
dS universe = (dS system + dS surroundings) > 0
dS surroundings = -q / T

dS system - q / T > 0
    At constant P, q=dH so:
       dS             - dH / T > 0
              system



For phase changes:
 dS system - dH / T is approximately 0, so:
         dS system = dH / T
Calculating entropy
aA + bB -> cC + dD
  dS reaction = c*SCo + d*SDo – a*SAo – b*S Bo


  SAo is the standard entropy of A
Gibbs free energy
 G = free energy

 dG = dH – TdS @ constant P and T

 dG < 0 for a spontaneous process

 Reactions that are dG>0 won’t happen, but their reverse reaction will
 Reactions that are dG=0 will have nothing happen because the system is at
  equilibrium

 The free energy and the equilibrium constant are related:
    dGo= - RT ln K
         dGo is the dG at standard temperature and pressure
         R is the gas law constant, R=8.314 J/(K*mol)
         T is the temperature
         ln K is the natural logarithm of the equilibrium constant
Gibbs free energy
dG = dH – T*dS @ constant P and T


dHo               dSo                      dGo


>0, endothermic   >0, increase in energy   (+)-T(+), more negative at higher temperatures


<0, exothermic    <0, decrease in energy   (-)-T(-), more negative at lower temperatures


>0, endothermic   <0, decrease in energy   (+)-T(-), always positive, never spontaneous


<0, exothermic    >0, increase in energy   (-)-T(+), always negative, always spontaneous



At low T: dG is approximately= dH
At high T: dG is approximately= – T*dS

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Chemistry chapter 20

  • 2. Titrations Titrations are done to determine the unknown concentrations of unknown acids. It is based of off determining how much known acid or base is needed to reach the equivalence point of the unknown liquid and at what pH the equivalence point exists. The equivalence point is the middle point of the fastest changing pH area. Usually a color indicator is used to help find the equivalence point as well as a pH indicator.
  • 3. Solubility Equilibria Adding an ionic solid to water It will be in equilibrium so long as some solid exists in solution Mg(OH)2(s)<-> Mg2+(aq) + 2 OH-(aq) Ksp= [Mg2+][OH-]2  This is the solubility product constant for the above equation  Note, the solid is not part of the equation
  • 4. Predicting precipitation For Mg(OH)2(s)<-> Mg2+(aq) + 2 OH-(aq) If Q= [Mg2+][OH-]2 < Ksp then the there will be no precipitate. If Q > Ksp then the there will be a precipitate. Note, if Q was < Ksp then only Mg2+(aq) or OH-(aq) would need to be added to cause precipitation.
  • 5. Thermodynamics Is the flow of energy 1st law of thermodynamics  The total energy of the universe is constant, energy can not be created nor destroyed  If you decrease the energy in the system, then you increase the energy of the surrounding  If you increase the energy in the system, then you decrease the energy of the surrounding  U = internal energy = all potential energy + all kinetic energy  dU universe = dU system + dU surroundings  dU system = - dU surroundings
  • 6. Thermodynamics 2: heat and work dU system = Heat (q) + Work (w)  q= Heat = energy flow from the change in temperature  w= Work = energy flow from movement against a force Closed system- do not allow matter in or out of the system q<0 – heat flows out of the system q>0 – heat flows into the system w<0 – the system does work on the surrounding w>0 – the surrounding does work on the system
  • 7. Thermodynamics 3: enthalpy The most common work in chemical systems w= -P dV  Work= - Pressure * change in Volume dU system = q – P * dV dH (enthalpy) = dU + d(PV) dH = dU + P*dH @ constant P Plugging in “dU system = q – P * dV” you get: dH = q - P*dH + P*dH = q @ constant P dH = q @ constant P
  • 8. 2nd law of thermodynamics All spontaneous processes increase the entropy of the universe dS (entropy) > 0 for spontaneous processes Entropy is a measure of the dispersive-ness of energy A larger value of entropy is a more dispersed energy
  • 9. Guessing thermodynamics C6H12O6(s) -> 2 C2H3OH(s) + 2 CO2(g) dH>0 because we are breaking more bonds then we are forming dS>0 because there are more moles on the right H2O(s) -> H2O(l) dS>0 because liquid is more dispersible than solid H2O(l) -> H2O(g) dS>0 because gas is more dispersible than liquid
  • 10. Entropy guessing rules Increase Entropy Breaking bonds without making new ones Change to a favored phase More moles on the product side
  • 11. Entropy dS universe = (dS system + dS surroundings) > 0 dS surroundings = -q / T dS system - q / T > 0 At constant P, q=dH so:  dS - dH / T > 0 system For phase changes: dS system - dH / T is approximately 0, so:  dS system = dH / T
  • 12. Calculating entropy aA + bB -> cC + dD dS reaction = c*SCo + d*SDo – a*SAo – b*S Bo SAo is the standard entropy of A
  • 13. Gibbs free energy  G = free energy  dG = dH – TdS @ constant P and T  dG < 0 for a spontaneous process  Reactions that are dG>0 won’t happen, but their reverse reaction will  Reactions that are dG=0 will have nothing happen because the system is at equilibrium  The free energy and the equilibrium constant are related:  dGo= - RT ln K  dGo is the dG at standard temperature and pressure  R is the gas law constant, R=8.314 J/(K*mol)  T is the temperature  ln K is the natural logarithm of the equilibrium constant
  • 14. Gibbs free energy dG = dH – T*dS @ constant P and T dHo dSo dGo >0, endothermic >0, increase in energy (+)-T(+), more negative at higher temperatures <0, exothermic <0, decrease in energy (-)-T(-), more negative at lower temperatures >0, endothermic <0, decrease in energy (+)-T(-), always positive, never spontaneous <0, exothermic >0, increase in energy (-)-T(+), always negative, always spontaneous At low T: dG is approximately= dH At high T: dG is approximately= – T*dS