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Chapter 7
1
CHAPTER 7 DRILLS
D7.1
(a) V |P (1,2,3) =
4(2)(3)
(1)2
+1 = 12 V
As, ρv = −∇2
V, so we first calculate ∇2
V :
∇V = −8
yzx
(x2
+1)2
+
4z
x2
+1 +
4y
x2
+1
⇒ ∇2
V = 32 yzx2
(x2
+1)3 −8 yz
(x2
+1)2
⇒ ∇2
V |P (1,2,3) = 12;
so, ρv = −∇2
V = −o(12) = −106.25pC
m3
(b) V
|
P (3, π
3
,2) =
−
22.5 V
As, ρv = −∇2
V, so we first calculate ∇2
V :
∇2
V = 20 cos (2φ) −20 cos(2 φ)
⇒ ∇2
V |P (3, π
3
,2) = 0;
so, ρv = −∇2
V = −o(0) = 0 pC
m3
Solved by Zaeem Ahm ad Vara ich
Com piled by www.EngineersTeam.tk
(c) V |P (0.5,45o
,60o
) = 4 V
As, ρv = −∇2
V, so we first calculate ∇2
V :
∇2
V = 4 cos(φ)
r4 −2 cos(φ)
r4
(sin(θ))2
⇒ ∇2
V |P (0.5,45o
,60o
) = 0;
so, ρv = −∇2
V = −o(0) = 0 pC
m3
D7.2
Apply the formulae & concepts to find the answers!
www.engineersteam.tk
Compiled by www.EngineersTeam.tk
2
D7.3
(a) The solution to Laplace’s equation 1
ρ
∂
∂ρ

ρ ∂
∂ρ

= 0 is:
V = A ln ρ + B
Putting the given values of V & ρ and solving the simultaneous equations, we get:
A = −73.9 & B = 101.28
so, V = −73.9 ln ρ + 101.28
1 1
Compiled by www.EngineersTeam.tk
Link
3 of 4
Now, E = −∇V = ρ
(73.9) aρ = √
10
(73.9) aρ = 23.36aφ
(
∵
ρ =
√
3
2
+ 1
2
)
so, |E| = 23.36 V
m
(b) The solution to Laplace’s equation 1
ρ2
∂2
V
∂φ2 = 0 is:
V = Aφ + B
Putting the given values of V & φ and solving the simultaneous equations, we get:
A = −85.9 & B = 64.9
so, V = −85.9φ + 64.9
Now, E = −∇V = 1
ρ
(85.9) aφ = 1√
10
(85.9) aφ = 27.16 aφ
(∵ ρ = √32 + 12)
so, |E| = 27.16 V
m
D7.4 & D7.5
Not included in the course!
www.engineersteam.tk
Compiled by www.EngineersTeam.tk
3
D7.6
The solution to this problem depends on how you proceed in each iteration and on your initial estimate.
The dotted lines show how the initial estimate was found.
(a) 20.8 V
(b) 44.47 V
(c) 89.8 V
Compiled by www.EngineersTeam.tk
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Chapter 7 drill

  • 1. Upload Log In Sign Up Search books, presentations, business, academics Explore Documents School WorkHealth & MedicineBrochures/CatalogsMagazines/NewspapersHow-To Guides/ManualsRecipes/MenusBooks - FictionBooks - Non- fictionGovernment Docs+ all categories RecentFeatured People AuthorsStudentsResearchersPublishersGovernment & NonprofitsBusinessesMusiciansArtists & DesignersTeachers+ all categories Most FollowedPopular × Language: English Chapter 7
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  • 3. 1 CHAPTER 7 DRILLS D7.1 (a) V |P (1,2,3) = 4(2)(3) (1)2 +1 = 12 V As, ρv = −∇2 V, so we first calculate ∇2 V : ∇V = −8 yzx (x2 +1)2 + 4z x2 +1 + 4y x2 +1 ⇒ ∇2 V = 32 yzx2 (x2 +1)3 −8 yz (x2 +1)2 ⇒ ∇2 V |P (1,2,3) = 12; so, ρv = −∇2 V = −o(12) = −106.25pC m3 (b) V | P (3, π 3 ,2) = − 22.5 V As, ρv = −∇2 V, so we first calculate ∇2 V : ∇2 V = 20 cos (2φ) −20 cos(2 φ) ⇒ ∇2 V |P (3, π 3 ,2) = 0; so, ρv = −∇2 V = −o(0) = 0 pC m3 Solved by Zaeem Ahm ad Vara ich Com piled by www.EngineersTeam.tk
  • 4. (c) V |P (0.5,45o ,60o ) = 4 V As, ρv = −∇2 V, so we first calculate ∇2 V : ∇2 V = 4 cos(φ) r4 −2 cos(φ) r4 (sin(θ))2 ⇒ ∇2 V |P (0.5,45o ,60o ) = 0; so, ρv = −∇2 V = −o(0) = 0 pC m3 D7.2 Apply the formulae & concepts to find the answers! www.engineersteam.tk Compiled by www.EngineersTeam.tk 2 D7.3 (a) The solution to Laplace’s equation 1 ρ ∂ ∂ρ  ρ ∂ ∂ρ  = 0 is: V = A ln ρ + B Putting the given values of V & ρ and solving the simultaneous equations, we get: A = −73.9 & B = 101.28 so, V = −73.9 ln ρ + 101.28 1 1 Compiled by www.EngineersTeam.tk
  • 5. Link 3 of 4 Now, E = −∇V = ρ (73.9) aρ = √ 10 (73.9) aρ = 23.36aφ ( ∵ ρ = √ 3 2 + 1 2 ) so, |E| = 23.36 V m (b) The solution to Laplace’s equation 1 ρ2 ∂2 V ∂φ2 = 0 is: V = Aφ + B Putting the given values of V & φ and solving the simultaneous equations, we get: A = −85.9 & B = 64.9 so, V = −85.9φ + 64.9 Now, E = −∇V = 1 ρ (85.9) aφ = 1√ 10 (85.9) aφ = 27.16 aφ (∵ ρ = √32 + 12) so, |E| = 27.16 V m D7.4 & D7.5 Not included in the course! www.engineersteam.tk Compiled by www.EngineersTeam.tk
  • 6. 3 D7.6 The solution to this problem depends on how you proceed in each iteration and on your initial estimate. The dotted lines show how the initial estimate was found. (a) 20.8 V (b) 44.47 V (c) 89.8 V Compiled by www.EngineersTeam.tk Search This Document Search Search History: Searching... Result 00 of 00 00 results for result for p.
  • 7. Www.engineersTeam.tk-chapter 7-Engineering Electromagnetics by William Hyatt 7th-Edition-DRILL PROBLEMS SOLUTION- Www.engineersTeam.tk Add To Collection 86 Reads 0 Readcasts 0 Embed Views This is a private document. Published by www.engineersteam.tk Compiled by www.EngineersTeam.tk
  • 8. EngineersTeam Follow Search This Document Search TIP Press Ctrl-F⌘F to search anywhere in the document. Info and Rating Category: Uncategorized. Rating: Not available for private documents Upload Date: 01/08/2013 Copyright: Traditional Copyright: All rights reserved Tags: This document has no tags. Read online for free. Flag document for inapproriate content More From This User
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