At the end of Meiosis I for this organism, what is the policy number .pdf

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At the end of Meiosis I for this organism, what is the policy number (n, 2n, 3n, 4n)? Solution Answer: n (haploid) Considering that the organism is diploid (2n) and undergoes meiosis to form the gametes, one diploid cell undergoes division to reduce the chromosome number to half. So, at the end of meiosis 1, the two cells so produced are haploid (n) with a DNA content of 2C..

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Each of the following is a function of membranes except sites for specific biochemical functions regulation of transport. cell - cell communication. information storage. defining cell and organelle boundaries. Solution Biological membranes serve as defining boundaries of the cells and membrane bound cell organelles. They also serve in transport of selected substaces through them and thereby maintain the cell\'s interior. They serve as site for complex reactions and are central to cell cell communication. However, storage of information is the function of nucelus which houses the genetic material. Correct answer is D..

Each of the following is a function of membranes except sites for spe.pdf

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Develop a detailed Compliance budget for fiscal year 2015-16 for a 100-bed skilled nursing facility with 50 employees and a program budget amount of $200,000. Solution A detailed copliance is done by looking into some things. in which that hopital company can adobe or not. 1.) see that, the department has large amount of funded beds that are not used. 2.) hospital should see for operation the level staff should be needed to operate hospital facilities. 3.) the budgeting methodology used by the department creates incentives for it to operate effeciently. and etc., still many things have to be taken under control..

Develop a detailed Compliance budget for fiscal year 2015-16 for a 1.pdf

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Devlin Inc produces snack foods such as bagel chips. The company had .pdf

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Choose the one that the correct sequence (going from Mart to finish) for the lymphatic system duct, capillary, vessel, trunk, duct, vessel. capillary vessel, trunk capillary, duct capillary, vowel, trunk, duct There is congestion in the flow when the lymph enters the lymphatic node to increase the component by the lymphocytes True False John is considers a high-risk individual as his immune system has many delicacies Thus of he was to be infected by a serious disease, one would go about using which type of immunity? passive, nature scoured passive, scoured nature Active, artificially acquired Solution Please find the answers below and explanations in parentheses: Answer 36: Choice 4 (A small capillary collects the lymph from the interstitial tissue bed. A number of these small capillaries combine to form a small vessel. A few vessels combine to drain all the lymph fluid into a large trunk which transports the lymph across the body) Answer 37: True (The lymph fluid is comprised of large amounts of lymphocytes which help in fighting the infections. The lymphocytes are primarily concentrated at the lymph nodes. When the lymph arrives at these lymph nodes, the lymphocytes accumulate to analyse the lymphatic fluid for any infeciton of pathogens. This creates a temporary resistance to flow and causes slight congestion of fluid across the lymphatic vessels which is cleared by some time) Answer 38: Choice D (Since John is at risk of immune response and low on immunity, it clearly suggests that he his immune response depends upon artificially acquired boost due to immunization and thus result in active immune response against multiple infections. Had he not had been pre-immunized, the primary source of immunity might had been his natural defence against infections.).

Choose the one that the correct sequence (going from Mart to finish) .pdf

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Connecting the Concepts: Structural Adaptations in Land Plants What structural adaptations enable plants to live on land? Part A Drag the terms to their correct locations in this concept map. Solution a. Vascular system b. mosses- laks vascular system xylem and phloem. c. lignin- natural polymer and not made of carbohydrates. d. Ferns- have vascular tissues to transpot food and water. e. phloem- distributes sugar and nutrients prepared in the shoot. f. xylem- distributes water and minerals taken up by roots. g. water and minerals.

Connecting the Concepts Structural Adaptations in Land Plants What .pdf

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Business statistics 1.How is the trend eliminated in the ratio-to-moving average procedure? 2. Why take the seasonality out of a time series? 3. Does a index of 103 indicate above or below average? 4. What is autocorrealtion? 5. Be able to read and interpret a short time series using an index. 6. What is done with seasonal indexes? 7. Be able to read and interpret a short time series using an index. 8. Hypothesis tests for nominal and ordinal merasurement are? 9. Chi-square test? 10. Sum of differences in expected and observed frequencies Solution 1)It is harder to see a trend in a noisy time series thats why it is eliminated in the ratio-to-moving average procedure. 2)Unlike the trend and cyclical components, seasonal components, theoretically, happen with similar magnitude during the same time period each year. The seasonal components of a series are sometimes considered to be uninteresting and to hinder the interpretation of a series. Removing the seasonal component directs focus on other components 4)Autocorrelation is the correlation between the elements of a series and others from the same series separated from them by a given interval. 6)A seasonal index is used when forecasting products with seasonal demand patterns. 9)A chi-squared test, also referred to as.

Business statistics1.How is the trend eliminated in the ratio-to-m.pdf

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Assignment: Write a multithreaded Java program that uses either semaphores or Java synchronization to control access to a one-lane bridge. One thread should simulate eastbound vehicles and another thread should simulate westbound vehicles. The vehicles do not have a reverse gear, so the bridge would become deadlocked if both an eastbound vehicle and a westbound vehicle were allowed to drive onto the bridge at the same time. Therefore, mutual exclusion must be enforced. Your solution should avoid both deadlock and starvation (e.g. the bridge being monopolized by westbound vehicles while the eastbound vehicles never get to cross). Vehicles traveling in either direction should wait (sleep) for some amount of time, then attempt to cross. Once a vehicle is on the bridge, it should sleep for some amount of time to simulate how long it takes to drive across the bridge. Output a message when each vehicle drives onto the bridge and another message when that vehicle has completed the crossing. Simulate several vehicles traveling in each direction. Solution public class baboon{ public static boolean eastLock = false; public static boolean westLock = false; public static int onBranch = 0; public static void main(String [] args) { BaboonEast bEast = new BaboonEast(); BaboonWest bWest = new BaboonWest(); for (int i=1; i<=10; i++) { new Thread(bEast, \"E: \"+i).start(); new Thread(bWest, \"W: \"+i).start(); //bEast.start(); }//for }//main }//class class BaboonEast extends Thread { public void run() { while (baboon.westLock == true) { System.out.println(Thread.currentThread().getName() + \" waiting\"); try { sleep(50); } catch (InterruptedException ex) {} }//while //baboon.eastLock = true; //stops west baboons entering baboon.onBranch ++; baboon.westLock = true; baboon.eastLock = true; System.out.println(\"Baboon \" + Thread.currentThread().getName() + \" is entering\"); try { sleep(100); } catch (InterruptedException ex) {} baboon.onBranch --; System.out.println (\"Baboon \" + Thread.currentThread().getName() + \" has crossed\"); if (baboon.onBranch <= 0) { baboon.eastLock = false; baboon.westLock = false; } //System.out.println(baboon.onBranch); }//run }//class class BaboonWest extends Thread { public void run() { while (baboon.eastLock == true) { System.out.println(Thread.currentThread().getName() + \" waiting\"); try { sleep(50); } catch (InterruptedException ex) {} }//while baboon.westLock = true; //stops east baboons entering baboon.onBranch ++; System.out.println(\"Baboon \" + Thread.currentThread().getName() + \" is entering\"); baboon.westLock = true; baboon.eastLock = true; try { sleep(100); } catch (InterruptedException ex) {} baboon.onBranch --; System.out.println (\"Baboon \" + Thread.currentThread().getName() + \" has crossed\"); if (baboon.onBranch <= 0) { baboon.westLock = false; baboon.eastLock = false; } //System.out.println(baboon.onBranch); }//run }//class.

Assignment Write a multithreaded Java program that uses either semap.pdf

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African and white abolitionist often did not get along whySoluti.pdf

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What unique properties of the genome do forensic scientists use to generate a DNA footprint and this footprint enough to identify a specific (one) suspect? Solution only one tenth of a single percent of DNA differs from one person to another, forensic scientist use these variable regions to generate a DNA profile of an individual using samples from blood , hair ,etc. scientist find markers in a DNA sample by designing a small pieces of DNA(probes) that will bind to a complementary DNA sequence in the sample.A series of probes bound to a DNA sample creates a distinctive pattern for individual.scientist compare these DNA profile to determine whether the suspect\'s sample matches the evidence sample.if they don\'t match the person don\'t contribute to the crime scene.If it match it means the suspect may have contributes to the evidence sample. There are variable number of tendom repeats which are used to identify the suspects, which vary in each person. RFLP(restriction fragment length polymorphism ) is a technique used in this concern as it analyze variable length of DNA fragments that results from digesting a DNA sample with a special kind of enzyme. various other techniques are also there as- PCR,STAR analysis.

What unique properties of the genome do forensic scientists use to g.pdf

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what are the five major activities of an operating system in regard to file management? Solution Operating systems perform the vital function of being the bridge between a computer\'s hardware and software. They provide an environment where software can be written without the need to cater to the specifics of the underlying hardware, which was necessary in the earlier days of computing. There are several widely-used operating systems which differ from each other in many respects. However, they each perform a number of similar functions including executing basic instructions, either compiled or interpreted; and also managing processes, memory, input and output, storage, network operations, and file and folder/directory operations. There are five major file management functions that an operating system controls. CREATING AND DELETING FILES : File creation and deletion are fundamental to computer operations. In the former, data can\'t be stored in an efficient manner unless arranged in some form of file structure. In the latter, permanent storage would quickly fill up if files were not deleted and the space occupied by them reallocated to new files. CREATING AND DELETING DIRECTORIES: As a corollary to the need to store data in files, files themselves need to be arranged in directories or folders in order to allow their efficient storage and retrieval. This is particularly so in the case of personal computers where the user needs to navigate to one or more specific files to access them. Without some form of compartmentalization, this would prove an onerous if not impossible task. Much like file deletion, unnecessary directories or folders need to be removed in order to keep the system uncluttered. FILE MANIPULATION INSTRUCTIONS: Since operating systems allow application software to perform file manipulation using symbolic instructions, the operating system itself needs to have a machine-level instruction set in order to interface with the hardware directly. The application\'s symbolic instructions need to be translated into the machine-level instructions either by an interpreter or by compiling the application code. The operating system contains provisions to manage this machine-level file manipulation. BACKING UP FILES : Files represent a considerable investment in time, intellectual effort and often money as well, thus their loss can have a severe impact. Computer\'s permanent storage devices generally contain a number of mechanical devices which can fail, and the storage media itself may degrade. A function of operating systems is to obviate the risk of data loss by backing files up on additional secure and stable media in a redundant system. MAPPING TO PERMANENT STORAGE : Operating systems need to be able to map files and folders to their physical location on permanent storage in order to be able to store and retrieve them. This will be recorded in some form of disk directory which varies according to the file system or systems that the opera.

what are the five major activities of an operating system in regard .pdf

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What are the key components of a typical centralized all-air HVAC system? Write the component name and their corresponding function/role. Based on the heat transfer media, HVAC systems can be classified into how many systems? Which system is the most popular system and why? Solution HVAC stands for Heating, Ventilating and Air Conditioning. The key components and their functions are as follows: 1. Thermostat. - to keep the home at a desired temperature. When the ambient temperature becomes too cold or too hot, the thermostat will trigger the heat exchanger or the evaporator coil- condensing unit combo to begin circulating warmed or cooled air as needed. 2. Furnace. - to heat a supply of air which is to be distributed to various rooms of the building via the HVAC. This heating process is accomplished using one of four possible heat sources -- combustion (burning natural gas, oil, coal, or propane), electric resistance, heat pump, or solar energy collected on site. 3. Heat exchanger. - switches on when the furnace is activated by thermostat to produce warmer temperatures in winter. The heat exchanger pulls in cool air, heats it, and circulates the resulting heated air via your ducts and out through the vents. 4. Evaporator coil. - it acts to cool the air when the thermostat is set to lower temperatures in summer. which is then circulated through the ductwork. 5. Condensing unit. - When the refrigerant has been cooled to a liquid by heat exchange with the exterior air, the condensing unit pumps the liquid to the evaporator coil to be evaporated into a gas once more. 6. Refrigerant lines. The refrigerant lines carry a refrigerant substance to the condensing unit vaporized in the form of a gas, and return it to the evaporator coil in liquid form. 7. Ductwork. - system of ducts that transports air warmed or cooled by the system to the various areas of the building. 8. Vents. - transfer the heated or cooled air from the duct system into the individual rooms of the building..

What are the key components of a typical centralized all-air HVAC sys.pdf

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What are lymphoid nodules and where are they located? What functions are served by these? (1 paragraph) Solution These are small localised ovoid or kidney shaped organs containing collection of lymphoid tissue. They are generally located in the loose connective tissue under wet epithelial membranes eg-digestive system, respiratory system etc. They are located in the walls of alimentary canal (tonsils, appendix and caecum, Peyer\'s patches), genitourinary passages, respiratory tract and also in other parts of the body. Peyer\'s patches are permanently localized lymphoid tissue in the sub mucosa of ileum. To defend nasal and oral cavities in the body lymphatic nodules are grouped together forming tonsils which are of three pairs viz. Palatine, Lingual and Pharyngeal. They help in the proper functioning of the immune system. They act as a filter for foreign particles and cancer cells. They guard the body and respond to entry of infectious organisms and toxins. Lymphoid nodules are the sites of proliferation/activation of lymphocytes (B cells). It occurs in the germinal centre..

What are lymphoid nodules and where are they located What functions.pdf

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Useful addition rules for mutually exclusive events: Rule 1: Given N mutually exclusive events {A1,A2, ... ,AN} then P(A1) + P(A2) + ... + P(AN) = 1.0 Rule 2: P(A particular mutually exclusive event) = 1 - P(all the others) This rule is very useful! For example: Suppose I toss a coin 10 times (or 10 coins once) and ask what is the probability of getting at least one head in 10 tosses. We could do this in two ways one is to sum probabilities P(1 at least head in 10) + P(2 heads in 10) + P(10 heads in 10) or we can simply go: P(1 at least head in 10 tosses) = 1 - P(no heads in 10 tosses) = 1 - 1/(2^10) Application to genetics: Activity 6 For maternal and paternal chromosomes in the human gamete example, what is the probability of a gamete having at least one maternal chromosome? Activity 7 Many types of color blindness are what are called X linked, that is determined by genes on the X chromosome. Suppose a woman is carrying one X chromosome with the gene for a particular type of color blindness; her other X chromosome does not have this gene. If she is married to a man who does not have this gene on his X chromosome. You may remember that color blindness is X linked recessive. A. What is the probability that her first child will carry the X chromosome with the gene associated with color blindness? B. Suppose amniocentesis reveals that the child is male. What is the probability that the child is color blind. Hint: this involves conditional probability Solution answer 6) P(at least one maternal) = 1 - P(no maternal ) maternal and paternal one chromosone similar and 1 chromosome different then the probability of no maternal = 1/2 hence the probability of atleast one = 1-1/2 = 1/2.

Useful addition rules for mutually exclusive eventsRule 1 Given .pdf

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There are three possible fates for immature B cells with IgM that recognizes self-antigens... Under what circumstances would a self-reactive cell become anergic? Solution Self reactive cell activated when cell is encountered by their specific antigen and cell undergoing rewiring of cellular processes. In response of antigen reactive cell become non responsive (anergic) This helpful in certain condition where requirement to reduce immunity of patient like organ transfer or any other..

There are three possible fates for immature B cells with IgM that re.pdf

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This if for a C# assignment. Please explain a scenario/use case for each of the following design patterns. Does not have to be long but it can not be one online please help! A) Adapter B) Briidge C) Composite D) Decorator E) Facade F) Flyweight G) Proxy Solution A)Adapter:It is mainly preloved to change the interfcae of a class into other interface that clients anticipates. B)Briidge:It is deliberated to to remain the interface with client programm constraint when permiting to modify the real type of class utilized.then the interface can be modified and the class being individually. C)Composite:It is a group of objects any of the class is a composite or simply a primary object.it allows the users individual and composition of objects much consisitently. D)Decorator:it is a class which that encircles a class ,appends a fresh abilities for a class and proceeds the unmodified methods to the classes being. E)Facade:It assembles a complex object heirarchy ,offers a fresh ,easier interface to acess the data.it senses a gaint-level interface which acquires a sub system uncomplicated utilization. F)Fly weight:it offers a procedure to restrict the prolification of little ,same class instances mobiling a few of the class data exterior the class and progressing at the time of different execution methods.it utilizes the splitting to enhance the more number of objects effectively. G)Proxy:It offers a proxy (or) easy place-holder class for much composite class which was high cost to instance..

This if for a C# assignment.Please explain a scenariouse case for.pdf

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The Hubble law shows the relationship between the mass of a galaxy and its distance. Solution The distant galaxies we see in all directions are moving away from the Earth, as evidenced by their red shifts. Hubble\'s law describes this expansion. The fact that we see other galaxies moving away from us doesnotimply that we are the center of the universe!Allgalaxies will see other galaxies moving away from them in an expanding universe unless the other galaxies are part of the same gravitationally bound group or cluster of galaxies. A rising loaf of raisin bread is a good visual model: each raisin will see all other raisins moving away from it as the loaf expands. The fact that the universe is expanding then raises the question \"Will it always expand?\" Since the action of gravity works against the expansion, then if the density were large enough, the expansion would stop and the universe would collapse in a \"big crunch\". This is called a closed universe. If the density were small enough, the expansion would continue forever (an open universe). At a certain precise critical density, the universe would asymtotically approach zero expansion rate, but never collapse. Remarkably, all evidence indicates that the universe is very close to that critical density. Discussions about the expansion of the universe often refer to adensity parameter which is the density divided by the critical density, such that = 1 represents the critical density condition. Hubble\'s Law Hubble\'s law is a statement of a direct correlation between the distance to a galaxy and its recessional velocity as determined by the red shift. It can be stated as v = H0r, v= recessional velocity, H0=Hubble constant, r=distance. Hubble Parameter The proportionality between recession velocity and distance in the Hubble Law is called the Hubble constant, or more appropriately the Hubble parameter since it does depend upon time. In recent years the value of the Hubble parameter has been considerably refined, and the current value given by the WMAP mission is 71 km/s per megaparsec. The recession velocities of distant galaxies are known from the red shift, but the distances are much more uncertain. Distance measurement to nearby galaxies uses Cepheid variables as the main standard candle, but more distant galaxies must be examined to determine the Hubble constant since the direct Cepheid distances are all within the range of the gravitational pull of the local cluster. Use of the Hubble Space Telescope has permitted the detection of Cepheid variables in the Virgo cluster which have contributed to refinement of the distance scale. The Particle Data Group documents quote a \"best modern value\" of the Hubble constant as 72 km/s per megaparsec (+/- 10%). This value comes from the use of type Ia supernovae (which give relative distances to about 5%) along with data from Cepheid variables gathered by the Hubble Space Telescope. The value from the WMAP survey is 71 km/s per megaparsec..

The Hubble law shows the relationship between the mass of a galaxy a.pdf

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The difference between the saturated dissolved oxygen concentration .pdf

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1) What does globalization mean? 2) Is globalization a good thing or a bad thing? Why? 3) Are we experiencing global integration or disintegration? 4) Why is it important to widen our global view? 5) What examples of globalization can you identify in your life? 1) What does globalization mean? 2) Is globalization a good thing or a bad thing? Why? 3) Are we experiencing global integration or disintegration? 4) Why is it important to widen our global view? 5) What examples of globalization can you identify in your life? 1) What does globalization mean? 2) Is globalization a good thing or a bad thing? Why? 3) Are we experiencing global integration or disintegration? 4) Why is it important to widen our global view? 5) What examples of globalization can you identify in your life? Solution 1) globalisation means acceptance of different cultures across the world. People exchange ideas. Share cultural knowledge, etc due to globalisation 2) globalisation is a good thing. It helps in exchange of ideas from different sections of the society. T brings humanity and brotherhood among people of different cultures 3)there is global integration due to globalisation which is good 4) it is important to widen our global view because it helps us to reach people of different cultures. It makes a person perspective large towards the society. 5) The examples of globalisation includes trade among different countries. It also includes social help for the under priveledge.

1) What does globalization mean2) Is globalization a good thi.pdf

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SNR calculation for conventional AM small noise case? Prove that signal and noise components are no longer additive in an envelope detector? In SoS development process, explain why it is important that system selection and architecture design should be concurrent activities and why there should be close links between them. Let C be a closed path that lies on the unit circle in the p-plane and that is traversed in the clockwise direction in order to evaluate W (p). Determine the net number of times the plot of W (p) encircles the origin in a clockwise direction for W (p) = (1 -1/2 p^-1)/(1 -1/4p^-1) Solution Q3: The SoS development process play an important role in large and complex entities in the application domain and organization essential requirements for development strategies using System selection and Architecture Design. Architecture design is same as System selection. An entire architecture design is SoS development stage which depends upon various parameters using interface and integration development process exists in application system..

SNR calculation for conventional AM small noise case Prove that sign.pdf

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Question 6 Of the following, which one is not a component of the project change control system? Solution Question 6: schedule change control system is not a component of project change control system as it involves reviewing, approving, carrying out and controlling changes to the project\'s deliverables. Change Control is applicable after the first version of a deliverable has been completed and agreed..

Question 6 Of the following, which one is not a component of the proj.pdf

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