Assume the letter D is represented by the number 3. Perform an RSA e.pdf

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Assume the letter D is represented by the number 3. Perform an RSA encoding of the message \"3\" using 7 for the public exponent, and n = pq = 1113 = 143 for the public modulus. Solution Given as n= p*q= 11*13=143 exponent (e)=7 and message (D)=3 Compute (n) = (p - 1) * (q - 1) =10 * 12 = 120 Compute a value for d such that (d * e) % (n) = 1. I have selected One solution for d as 103 i.e [(103 * 7) % 120 = 1] Public key is (e, n) => (7, 143) Private key is (d, n) => (103, 143) The encryption of message 3 is c = D^e % n = 3^7 % 143 =42.

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Use C programming Make sure everything works only upload Solution C program #include int isPrime(int number);// function prototype int main() { int No,i;// variable decleration printf(\"Input a number greater than 2: \");// asking user to enter a number scanf(\"%d\",&No);// scaning the number form user if(No <= 2)// checking no is lessthan or equ to 2 { // if yes print message printf(\"No prime number is smaller than %d.\ \",No); return 0;// and stop computation } // else print the prime numbers printf(\"Prime numbers smaller than %d:\",No); for (i = 2;i.

Use C programmingMake sure everything works only uploadSol.pdf

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Thoroughly describe the molecular underpinnings of ONE and only one of these processes. Transcription initiation and elongation Solution Transcription is the biochemical process involves transferring of information from DNA to RNA, assisted with RNA polymerase. The RNA produced in this process will be converted to protein in the process of translation. RNA polymerase read the DNA template and synthesize with help of other important proteins to carried out the process. The process of transcription comprises of series of events leading to Initiation, elongation, and termination. In the initiation process, RNA polymerase with other adapter proteins binds to the upstream of DNA in the initiation point. RNA polymerase complexed with unwound DNA which bind to the promoter sequence, and results in the initiation of the process. Promoter region contains an initiation site where process begins. RNA polymerase synthesize new strand RNA, which is complementary to the DNA strand. In elongation phase, DNA polymerase lengthened the RNA, used as a DNA triplet code in the template strand. polymerse read the template until the signal is percieved. RNA polymerase functions by adding nucleotids to 3\' end of the strand and synthesized in 5\' to 3\' direction..

Thoroughly describe the molecular underpinnings of ONE and only one.pdf

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The Blackbeard Company Ltd provided the following information in regard to its operations for the year ended 30 June 2014: Cash Book Summary Opening balance $20,000 Accounts Payable $40,000 Accounts receivable 100,000 Bills Payable (suppliers) 20,000 Bills Receivable (suppliers) 20,000 Interest paid 60,000 Debenture Issue 400,000 Operating expenses 180,000 Dividends received 20,000 Salaries & wages 200,000 Interest received 40,000 Current tax payable 80,000 Motor vehicles 60,000 Plant & machinery 100,000 Share capital 200,000 Dividend paid 120,000 Balance c/d 60,000 860,000 860,000 Balance b/d 60,000 Required: (a) Net cash used in operating activities; (b) Net cash used in investing activities; (c) Net cash from financing activities; (d) Net increase/(decrease) in cash and cash equivalents. Please use the following format Statement of Cash Flows for Blackbeard Company For the Financial Year Ended 30 June 2014 ( i ) Cash flows from Operating Activities Inflows/ Inflows/ (Outflows) (Outflows) Net cash used in operating activities ( ii ) Cash flows from Investing Activities Net cash used in Investing Activities ( iii ) Cash flows from Financing Activities Cash Book Summary Opening balance $20,000 Accounts Payable $40,000 Accounts receivable 100,000 Bills Payable (suppliers) 20,000 Bills Receivable (suppliers) 20,000 Interest paid 60,000 Debenture Issue 400,000 Operating expenses 180,000 Dividends received 20,000 Salaries & wages 200,000 Interest received 40,000 Current tax payable 80,000 Motor vehicles 60,000 Plant & machinery 100,000 Share capital 200,000 Dividend paid 120,000 Balance c/d 60,000 860,000 860,000 Balance b/d 60,000 Solution Statement of Cash flows for Blackbeard Company For the Financial Year Ended 30 June 2014 (i) Cash flow from Operating Activities Inflows/(outflows) Inflows/(outflows) Accounts Receivable $ 1,00,000 Bills Receivable (suppliers) $ 20,000 Accounts Payable $ -40,000 Bills Payable(suppliers) $ - 20,000 Operating expense $ -1,80,000 Salaries and wages $ -2,00,000 Current Tax Payable $ -80,000 Dividend received $ 20,000 Interest received $ 40,000 Net Cash used in Operating Activties $ -3,40,000 (ii) Cash flow from Investing Activities Sales of Motor Vehicle $ 60,000 Purchase of Plant and Machinery $ -1,00,000 Net Cash from Investing Actiivties $ -40,000 (iii) Cash flow from Financing activities Debenture issue $ 4,00,000 Share capital $ 2,00,000 Interest paid $ -60,000 Dividend paid $ -1,20,000 Net Cash from financing actiivties $ 4,20,000 Net Increase /(decrease) in cash and cash equivalent $ 40,000 Cash at the Beginning of the period $ 20,000 Cash at the end of the period $ 60,000.

The Blackbeard Company Ltd provided the following information in reg.pdf

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Thank you 1. What is responsible for anterior:posterior axis formation in the chicken? How is dorsal ventral patterning accomplished? 2. What is the role of the Posterior Marginal zone in early chicken development? 3. What is the primitive streak and why is it important in chicken development? 4. What is the function of Henson\'s Node? To what is it analogous in amphibian development? Solution 1.The primitive streak defines the axes of the embryo. It extends from posterior to anterior; migrating cells enter through its dorsal side and move to its ventral side; and it separates the left portion of the embryo from the right. Those elements close to the streak will be the medial (central) structures, while those farther from it will be the distal (lateral) structures 2.Primitive streak is induced by the posterior marginal zone (PMZ) of Koller\'s sickle, which can also induce Hensen\'s node. If cell movement in the PMZ is blocked, primitive streak does not form.Thus, the PMZ acts as an organizer.Cells in marginal zones of the embryo, like the PMZ, are key to development and cell fate determination in chick embryos. 3.The primitive streak is a structure that forms in the blastula during the early stages of avian, reptilian and mammalian embryonic development. It forms on the dorsal (back) face of the developing embryo, toward the caudal or posterior end.The presence of the primitive streak will establish bilateral symmetry, determine the site of gastrulation and initiate germ layer formation. To form the streak, reptiles, birds and mammals arrange mesenchymal cells along the prospective midline, establishing the second embryonic axis, as well as the place where cells will ingress and migrate during the process of gastrulation and germ layer formation.The primitive streak extends through this midline and creates the left–right and cranial–caudal body axes,and marks the beginning of gastrulation.This process involves the ingression of mesoderm progenitors and their migration to their ultimate position,where they will differentiate into the mesoderm germ layer that, together with endoderm and ectoderm germ layers, will give rise to all the tissues of the adult organism. 4. The primitive knot (or primitive node) is the organizer for gastrulation in the vertebrate embryo. Diversity In birds, it is known as \"Hensen\'s node\", and is named after its discoverer Victor Hensen. In amphibians, it is known as \"Spemann\'s organizer\", and is named after Hans Spemann In chick development, the primitive knot starts as a regional knot of cells that forms on the blastodisc immediately anterior to where the outer layer of cells will begin to migrate inwards - an area known as the primitive streak, which is involved with Koller\'s sickle. Posterior to the node is the primitive pit, where the cells of the epiblast (the upper layer of embryonic cells) initially begin to invaginate. This invagination expands posteriorly into the primitive groove as the cells layers c.

Thank you 1. What is responsible for anteriorposterior axis formati.pdf

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Take the basic Hardy-Weinberg Equilibrium equation, where there are alleles A and B. If the frequency of the two alleles are represented by p and q, then the expected genotypic frequencies are p2 2pq q2. Please review your comfort with calculating observed and expected allele and genotype frequencies. Try adding subscripts to the equation for relative fitness (use w) to predict change in allele frequency due to selection. Both inbreeding and genetic drift can cause problems for rare species with declining population size due to reducing genetic diversity. Please contrast (say how they are different these two forces in terms of number of alleles at a locus (some loci have more than two alleles) and in terms of average heterozygosity at a locus. In most organisms most mating is local. If populations of an organism are scattered across a landscape, with gaps between population, how will that affect inbreeding and expected Hardy Weinberg equilibrium? Solution Both inbreeding and genetic drift can cause problems for rare species with declining population size due to reducing genetic diversity. Please contrast (say how they are different) these two forces in terms of number of alleles at a locus (some loci have more than two alleles) and in terms of average heterozygosity at a locus. In most organisms most mating is local. If populations of an organism are scattered across a landscape, with gaps between population, how will that affect inbreeding and expected Hardy-Weinberg equilibrium? If migration among populations increases how will it affect inbreeding and expected hardy-Weinberg equilibrium? P^2 = homozygous dominant 2pq =heterozygotes Q^2= homozygous recessive According to hardy Weinberg P^2 +2pq + Q^2 =1 p = p2 + ½ (2pq) = p2 + pq q = q2 + Â½ (2pq) = q2 + pq p + q = 1 (p + q)2 = 1 p2 + 2pq + q2 = 1 (the Hardy-Weinberg Principle) Inbreeding can be referred as the mating between closely related organisms. Inbreeding favors homozygosity, and increase q^2 (recessive homozygotes) and decreases dominant phenotypes It will increases the chances of offspring being affected by recessive or lethal traits. Genetic bottlenecks and founder effects occurs in the population Leads to Hence population will be deviated from hardy-Weinberg equilibrium.

Take the basic Hardy-Weinberg Equilibrium equation, where there are a.pdf

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Systems analysis project 10: can you answer the 4 questions at the task section, thank you. Personal Trainer, Inc. owns and operates fitness centers in a dozen Midwestern cities. The centers have done well, and the company is planning an international expansion by opening a new “supercenter” in the Toronto area. Personal Trainer’s president, Cassia Umi, hired an IT consultant, Susan Park, to help develop an information system for the new facility. During the project, Susan will work closely with Gray Lewis, who will manage the new operation. Background Susan and Gray finished their work on user interface, input, and output design. They developed a user-centered design that would be flexible and easy to learn. Now Susan turned her attention to the architecture for the new system. Susan wanted to consider their own organization and culture, enterprise resource planning, total cost of ownership, scalability, Web integration, legacy systems, processing methods, security issues, and corporate portal. She also needed to select a network plan, or topology, that would dictate the physical cabling and network connections, or consider a wireless network. When all these tasks were completed, she would submit a system design specification for approval. Tasks: 1. What would be the advantages of selecting an Internet-based architecture for the Personal Trainer’s system? 2. If Personal Trainer wants to increase its Internet marketing efforts, what advice could you offer? Perform research to find out more about the topic of Web-based marketing before you answer Gray. 3. What software and hardware infrastructure will be necessary to ensure Personal Trainer can process point of sale transactions? 4. Prepare an outline for a system design specification and describe the contents of each section Solution 1) The Internet has had a colossal effect on system architecture modeling. The Internet has turn out to be more than a communication channel — numerous IT onlookers see it as a in a far-reaching way distinctive environment for system development. In a customary client/server system, the client handles the user interface and the server (or servers in a multi-level framework) handles the information and application rationale. As it were, a piece of the framework keeps running on the customer, part on the server. Interestingly, in an Internet-based architecture, notwithstanding information and application rationale, the whole user interface is given by the Web server as HTML coded documents that are deciphered and showed by the client\'s browser. Moving the obligation regarding the interface from the client to the server improves the procedure of information transmission and results in lower hardware’s expenses and complexities. The pattern toward Internet-based e- business is reshaping the IT scene as additional firms utilize the Web to manufacture proficient, solid, and practical arrangements. At the point when arranging new systems, experts can utilize accessible.

Systems analysis project 10 can you answer the 4 questions at the t.pdf

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Step 1. Read critically and analyze the following scenario: Geraldine Barney Garrett, the granddaughter of Wilford Barney took over the reins of the R&D department of Biotech Health and Life Products (Biotech) in 1965. She had trained at the hands of her grandmother Wilford’s mother, Maria. Geraldine was a strong manager and developed the Research and Development (R&D) lab from the advanced kitchen of her grandmother to the scientific lab of her peers. Geraldine’s management philosophy evolved over the years but she had several basic ideas that kept her grounded. Geraldine knew she had to answer to the family in every decision she made. Her grandmother stressed this point and she eventually came to agree. Therefore, decisions were made by her. She also realized that her employees had good ideas and talent but they did not bear the responsibility she did. So, although she consulted with the employees often, she never gave them the power to make important decisions. Geraldine was charismatic in a motherly way and employees saw her as someone to learn from but career growth was unlikely so in five or six years employees moved on to another company. The unambitious stayed on and eventually Geraldine collected a small group of people she trusted and who became her team. Now, several of the team members are retiring like Geraldine leaving few left to the company. When it comes to leading the entire R&D Division, Geraldine is very controlled in defining goals, setting tasks, and is outstanding at dividing the work among the employees, organizing the product materials and coordinating and communicating activities between the different departments. Decisions that Geraldine makes are always dependent on the circumstances and context of the decision. You often hear her instructing the young employees stating, “Always ask yourself, which method will work best here? Remember, you are always looking to find the simplest and most cost-effective solution.” When it comes to developing new products and innovating, Geraldine is much more open to other people’s input and ideas relying heavily on her team of experienced but older people. Still, the final decision remains in her hands. Geraldine could see the need for changes in the lab, the most important of which was retaining younger employees. Since she was retiring at the end of the year, Geraldine knew the new department head would have to deal with the problem. Her immediate concern was who the new department head should be. Her own granddaughter, Melanie Malone, was now working in the company and she knew Melanie was expecting the job. Melanie was qualified for the job. She was a Phi Beta Kappa graduate of the University of Maryland College Park with a double major in Botany and Food Science. She minored in Business Management. She had worked in the plant in Chicago every summer since High School and had reproduced and revised all her grandmother’s and great-great grandmother’s recipes. Starting full-time .

Step 1. Read critically and analyze the following scenarioGeraldi.pdf

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Question 3 2 pts In response to the Great Recession, the Federal Reserve engaged in quantitative easing. As a consequence, the monetary base rose by nearly 400%, causing some to worry about inflation. However, during this time the money supply rose by only 110%. What explains this? A money multiplier greater than 1. A money multiplier equal to 1. A money multiplier smaller than 1. A negative money multiplier. Solution Money multiplier = Money supply / monetary base = 110 / 400 = 0.275 A money multiplier smaller than 1.

Question 3 2 pts In response to the Great Recession, the Federal Rese.pdf

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Prove that the T_i -property is a topological property for i = 0 Solution Hausdorff spaces do not have in general the homotopy type of any finite space. Recall that a topological space X satisfies the T1- separation axiom if for any two distinct points x, y X there exist open sets U and V such that x U, y V , y / U, x / V . This is equivalent to saying that the points are closed in X. All Hausdorff spaces are T1, but the converse is false.

Prove that the T_i -property is a topological property for i = 0S.pdf

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Q4.14. Which of the following species is most likely to exhibit paternal care? The polygynous topi antelope, one of nine species of lekking mammals. Atlantic cod, a broadcast spawner for which fertilization by satellite males is common. The monogamous great spotted woodpecker, a species whose males have high paternity certainty. Bonobos, a polygynandrous primate with internal fertilization and very low paternity certainty. Solution Ans c the monogamous great spotted wood pecker , a species whose males have high paternity certainty. They belong to family picidae and live in forests or woodland habitats..

Q4.14. Which of the following species is most likely to exhibit pate.pdf

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Prepare a classified balance sheet. Do not show the components that add up to your answer in requirement 1 but rather show only the line “Cash and Cash Equivalents.” (Amounts to be deducted should be indicated by a minus sign.)Gatti Corporation reported the following balances at June 30. Solution 1. Cash and cash equivalents = Cash + Cash equivalents + Petty cash + Restricted cash = 15 + 20 + 25 + 20 = $80 2. Gatti Corporation Balance Sheet June 30Assets$Liabilities$Current assetsCurrent liabilitiesCash and cash equivalents80Notes payable20Account receivable95Accounts payable105Total current assets175Unearned revenue45Property, plant and equipmentTotal current liabilities170Equipment350Long term liabilitiesLess: Accumulated depreciation-45Notes payable110Property, plant and equipment, net305Total long term liabilities110Total liabilities280Stockholders EquityCommon stock150Retained earnings50Total stockholders equity200Total assets480Total liabilities and stockholders equity480.

Prepare a classified balance sheet. Do not show the components that .pdf

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Microscopes and telescopes both consist of two converging lenses contained in a tube. What is the difference in set-up of the two lenses between a microscope and a telescope? The rearview mirror on a truck warns the user that objects may be closer than they appear. What kind of mirror is being used, and why was that type selected? Why does a clear stream always appear to be shallower than it actually is? Discuss the type of aberration involved in each of the following situations. (i) The edges of the image appear reddish. (ii) The image cannot be clearly focused. A baby fish has his eyesight tested and is found to be myopic. His father wants to make a set of glasses to correct for this problem. Since fish live under water, the father fish will make the glasses out of a very thin clear plastic bag which is filled with air (n = 1.000). What type of lens does the fish need to make? What shape should the lens be? What is the wavelength of yellow light? Solution In refracting telescopes, there are typically two convex lenses. One lens acts as the objective lens: this lens gathers light from faraway objects and forms a real, inverted image of the object at its focal point. A second lens, called the eyepiece, is positioned such that the image formed by the objective lens is at its focal point. When an observer looks through the eyepiece with a relaxed eye, they are able to see an object of the image, formed at infinity. Microscopes are used to look at magnified images of small objects. A simple microscope (a “magnifying glass”) consists of a single convex lens. The lens is held close to the object so that the object is between the lens and its focal point. When viewed from the other side of the lens, a magnified, virtual, upright image is seen. The compound microscope is the most common type of microscope used in laboratories. With these microscopes, an objective lens is used to create an inverted, real image of the object. Using the eyepiece, the image is magnified. In this sense, its operating principles are similar to that of a refracting telescope. The rear view mirror is a convex mirror which forms a virtual and erect image of the object which is smaller in length than the object. Because the image formed is smaller in length, it appears to be farther away and hence, the warning written on it. This is because of the phenomenon of refraction of light as it crosses the medium of water(refractive index greater than that of air). As the light ray travels from water(denser medium) to air(rarer medium), the light ray bends away from the normal and the image of the bottom of the stream seems to be raised and hence, the stream appears to be shallower. a) In optics, chromatic aberration (CA, also called chromatic distortion, and spherochromatism) is an effect resulting from dispersion in which there is a failure of a lens to focus all colors to the same convergence point. It occurs because lenses have different refractive indices for differentwavelength.

Microscopes and telescopes both consist of two converging lenses cont.pdf

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Know the function of the following cytokines and create a table: IL-1, IL-2, IL-4, IL-5, IL-6, IL- 7, IL-10, IL-12, IL-13, IFN-alpha, IFN-beta, IFN-gamma, TGF-alpha, and TGF-beta (the table should include: the cell that synthesizes each cytokine, the function of each cytokine, the target cell for each cytokine, and the action of each cytokines; need to be listed in table format). Solution Answer of Question Cytokines Source Action on function IL1 including monocytes, macrophages, dendritic cells, NK cells,and non-immune system cells such as epithelial and endothelial cells, fibroblasts, adipocytes, astrocytes, and some smooth muscle cells. diff erent cell types, including T cells, B cells, monocytes, eosinophils and dendritic cells, as well as fi broblasts, liver cells, vascular endothelial cells, and some cells of the nervous system. eff ects of IL-1 include induction of local infl ammation and systemic eff ects such as fever, the acute phase response, and stimulation of neutrophil production IL-2 Activated T cells. T and B cells; activates NK cells Stimulates proliferation and diff erentiation of T and B cells; activates NK cells. IL-4 T cells (particularly those of the TH2 subset),mast cells, basophils, and bone marrow stromal cells. T CELL,B CELL Promote nave T cell diff erentiation to TH2 cells. Stimulates the growth and differentiation of B cells. Induces class switching to IgE. Promotes allergic responses. IL-5 T cells (particularly those of the TH2 subset), mast cells, eosinophils. B cell,esinophils Induces eosinophil formation and diff erentiation. Stimulates B cell growthand differentiation. IL-6 Some T cells and B cells, several nonlymphoid cells, including macrophages, bone marrow stromal cells, fi broblasts, endothelial and muscle cells, adipocytes, and astrocytes. Bcell, T cell Regulates B- and T-cell functions; in vivo eff ects on hematopoiesis. Inducesinfl ammation and the acute phase response. IL-7 Bone marrow and thymic stromal cells, intestinal epithelial cells T CELL, B cell Growth factor for T- and B-cell progenitors. IL-10 I Activated subsets of CD4_ and CD8_T cells, macrophages, and dendritic cells. T CELL ,B CELL ,MAST CELL Enhances proliferation of B cells, thymocytes, and mast cells; in cooperation with TGF-_, stimulates IgA synthesis and secretion by human B cells. Anti-infl ammatory; antagonizes generation of the TH1 subset of helper T cells. IL-12 Macrophages, B cells, and dendritic cells. T CELL ,NK CELL Important factor in inducing diff erentiation of TH1 subset of helper T cells; induces IFN-_ production by T cells and NK cells and enhances NK and cytotoxic T cell activity IL-13 Activated T cells (particularly those of the TH2 subset), mast cells, and NK cells T cell Role in TH2 responses; up-regulates synthesis of IgE and suppresses infl amatory responses. Involved in pathology of asthma and some allergic conditions INF alpha Cells activated by viral and other microbial components: macrophages, dendritic cells.

Know the function of the following cytokines and create a table IL-.pdf

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IPv6 was developed to correct the limitation inherent in IPv4. What are the areas that IPv5 improved on? Solution Firstly there is no version 5 for Internet protocol. IPV6 is definitely developed to overcome the limitations of IPV4. Most important limitation is address depletion problem. IPv4 provided 32 bit addressing which means that there will be 232 different and unique addresses that can be granted to the users of the internet, which is been classified into classes A,B,C,D and E out of which A,B,C are granted based on the requirement from large scale to small scale. The classful addressing was the main cause of the address depletion.To overcome that classless addressing was intoduced,NAT was introduced which could not rectify the problem completely. Therefore IPV6 was developed to satify the requirements of growing internet population. IPV6 has 128 bit addressing which can assign 2128 unique addresses which is far bigger than IPV4. Apart from this IPV6 has simple header when compared to IPV4, with IPV6 the routing is more effective and it also provides authentication which is part of security, which is another main drawback in IPV4(it is unreliable)..

IPv6 was developed to correct the limitation inherent in IPv4. What .pdf

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Japadog is the pioneer of street vending in Vancouver. They are unique to Vancouver(they tried to branch outin New York but apparently failed) and they sell “Japanese-style” hot-dogsin the streets. They have a stand that serves a stretch of West Cordova. There’s only one licence, so they do not decide how many stands to open. One stand. On any given day Japadog expects that up to 100 visitors may want to buy their hot-dogs. They think that the Hotelling spatial model is a good framework to make theirbusiness decision, and here are their estimates: the dog’s reservation price is $9, a customer’s cost of traveling along West Cordova is $6/km, there are no fixed costs, the stretch of West Cordova they serve is 1 km long, and they have a stand right in the middle ofthatstretch. The cost of making the hotdogsis flat $6 per dog. 1. What is the profit- maximizing price ($ per hot-dog)? 2. How many hot-dogs(per day) would Japadog sell? 3. What profit will Japadog expect to make ($ per day) Solution First-rate proof of Mayor Sam Sullivan\'s political vulnerability seem at all of the wannabes lining up for the 2008 mayoral contest. Two-time mayoral candidate Jim inexperienced, NDP MLA Gregor Robertson, and councillors Raymond Louie and David Cadman have not dominated themselves out of the race, which means that they may be in most cases all involved in walking. Then there are the chronic rumours that NPA councillor Peter Ladner additionally needs Sullivan\'s job. Former NPA mayors Gordon Campbell and Philip Owen under no circumstances found themselves in Sullivan\'s situation a 12 months earlier than they sought reelection, nevertheless it\'s most of the time nonetheless too early to put in writing off the little bugger\'s political career. Sullivan has been underestimated many times earlier thanâunder that boyish veneer beats the heart of a political cobra. First-rate double dipping The premier\'s former deputy minister, Ken Dobell, is a shoo-in. What are you able to say a few man who contracts himself out as a provincial lobbyist (or \"content material guide\", as he put it) for the town of Vancouver on housing issues whilst he has a desk in the premier\'s office as Gordon Campbell\'s unique adviser? Dobell, a former Vancouver metropolis supervisor, managed to duck controversy for a long time, regardless of taking part in a position in a couple of critical public-policy errors. While he was CEO of TransLink, he was the actual father of the Canada Line rapid-transit undertaking, which has compelled neighborhood firms into bankruptcy and which might eventually do the same to TransLink. He has additionally been the preferable\'s point man on the ever-extra-costly expansion of the Vancouver convention and Exhibition Centre. It started out at $495 million but has when you consider that crossed the $800-million threshold (which is an overrun that is $fifty five million greater than the $250-million rapid-ferry overshoot that was once seized upon via the B..

Japadog is the pioneer of street vending in Vancouver. They are uniq.pdf

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In each of the following situations, identify one or more ways that cultural differences may be leading to miscommunication. 1. Alan is a U.S. sales representative in South America. He makes appointments and is careful to be on time. But the person he’s calling on is frequently late. To save time, Alan tries to get right to business. But his hosts want to talk about sightseeing and his family. Even worse, his appointments are interrupted constantly, not only by business phone calls but also by long conversations with other people and even the customers’ children who come into the office. Alan’s first progress report is very negative. He hasn’t yet made a sale. Perhaps South America just isn’t the right place to sell his company’s products. 2. To help her company establish a presence in Asia, Susan wants to hire a local interpreter who can advise her on business customs. Kana Tomari has superb qualifications on paper. But when Susan tries to probe about her experience, Kana just says, “I will do my best. I will try very hard.” She never gives details about any of the previous positions she’s held. Susan begins to wonder if the re?sume? is inflated. 3. Stan wants to negotiate a joint venture with an Asian company. He asks Tung-Sen Lee if the people have enough discretionary income to afford his product. Mr. Lee is silent for a time, and then says, “Your product is good. People in the West must like it.” Stan smiles, pleased that Mr. Lee recognizes the quality of his product, and he gives Mr. Lee a contract to sign. Weeks later, Stan still hasn’t heard anything. If Asians are going to be so non-responsive, he wonders if he really should try to do business with them. 4. Elspeth is very proud of her participatory management style. On assignment in India, she is careful not to give orders but to ask for suggestions. But people rarely suggest anything. Even a formal suggestion system doesn’t work. And to make matters worse, she doesn’t sense the respect and camaraderie of the plant she managed in the United States. Perhaps, she decides gloomily, people in India just aren’t ready for a woman boss. Solution Answer for 1) The difference of culture in between Alan and his hosts is that his hosts want to talk about sightseeing and his family which are matter related to some thing personal but Alan want to go to the business straightly.Along with it Alan is not getting any thing that he expects like punctuality from his customers but that what he is not getting which leaded to miscommunication. Answer for 2) Here,Kana Tomari as she looked great on the paper she really may bcapable.Here, while in work one person may not reach the expectation of other person and that what Kana Tomari wants to say but when it comes to the view of Susan she want to see confidence in Kana Tomari that her need will be definitely served that lead to miscommunication. Answer for 3) HereMr.lee just wanted to say that his prodect won\'t be succeed in Asian country and hence, he d.

In each of the following situations, identify one or more ways that .pdf

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I need to implment a function that can reverse a single linked list. Not just print it, but actually change the order of the list. THIS MUST BE DONE USING RECURSION EX: a, b, c, d -> d, c, b, a You have access to the start of the list. Code must be in C++ Solution #include using namespace std; struct node { char data; struct node* next; }; void reverse(struct node* head) { if (head == NULL) //base case return; reverse(head->next); //calling function recursively cout<data<<\",\"; } //add data to the front of the linked list void add(struct node** head_ref, char data) { //create new node struct node* newnode=new node(); //adding data newnode->data = data; //adding node to the front newnode->next = (*head_ref); //making new node head (*head_ref) = newnode; } int main() { // create linked list a, b, c, d struct node* head = NULL; add(&head, \'d\'); add(&head, \'c\'); add(&head, \'b\'); add(&head, \'a\'); reverse(head); return 0; } //OUTPUT*********** d,c,b,a, //OUTPUT*********** //This code has been tested on g++ compiler,Please ask in case of any doubt,Thanks..

I need to implment a function that can reverse a single linked list..pdf

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Data Structures in C++ I am really new to C++, so links are really hard topic for me. It would be nice if you can provide explanations of what doubly linked lists are and of some of you steps... Thank you In this assignment, you will implement a doubly-linked list class, together with some list operations. To make things easier, you’ll implement a list of int, rather than a template class. Solution A variable helps us to identify the data. For ex: int a = 5; Here 5 is identified through variable a. Now, if we have collection of integers, we need some representation to identify them. We call it array. For ex: int arr[5] This array is nothing but a Data Structure. So, a Data Structure is a way to group the data. There are many Data Structures available like Arrays, Linked List, Doubly-Linked list, Stack, Queue, etc. Doubly-Linked list are the ones where you can traverse from the current node both in left and right directions. Why so many different types of Data Structures are required ? Answer is very simple, grouping of data, storage of data and accessing the data is different. For example, in case of Arrays we store all the data in contiguous locations. What if we are not able to store the data in contiguous locations because we have huge data. Answer is go for Linked List/Doubly-Linked list. Here we can store the data anywhere and link the data through pointers. I will try to provide comments for the code you have given. May be this can help you. #pragma once /* dlist.h Doubly-linked lists of ints */ #include class dlist { public: dlist() { } // Here we are creating a NODE, it has a integer value and two pointers. // One pointer is to move to next node and other to go back to previous node. struct node { int value; node* next; node* prev; }; // To return head pointer, i.e. start of the Doubly-Linked list. node* head() const { return _head; } // To return Tail pointer, i.e. end of the Doubly-Linked list. node* tail() const { return _tail; } // **** Implement ALL the following methods **** // Returns the node at a particular index (0 is the head). node* at(int index){ int cnt = 0; struct node* tmp = head(); while(tmp!=NULL) { if (cnt+1 == index) return tmp; tmp = tmp->next; } } // Insert a new value, after an existing one void insert(node *previous, int value){ // check if the given previous is NULL if (previous == NULL) { printf(\"the given previous node cannot be NULL\"); return; } // allocate new node struct node* new_node =(struct node*) malloc(sizeof(struct node)); // put in the data new_node->data = new_data; // Make next of new node as next of previous new_node->next = previous->next; // Make the next of previous as new_node previous->next = new_node; // Make previous as previous of new_node new_node->prev = previous; // Change previous of new_node\'s next node if (new_node->next != NULL) new_node->next->prev = new_node; } // Delete the given node void del(node* which){ struct node* head_ref = head(); /* base case */ if(*head_ref == NUL.

Data Structures in C++I am really new to C++, so links are really .pdf

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How to secure information systems? Solution Answer: Information security: Information security, sometimes shortened to InfoSec, is the practice of halting unauthorized access, use, revelation, disordering, modification, investigation, recording or destruction of information. It is a general term that can be used regardless of the form the data may take (e.g. electronic, physical). Since the advent of the internet and increased expansion of computer based technology in today\'s corporations, information security breaches have increased at an alarming rate. While businesses take a more cautious approach to how they handle IT security threats, these are becoming increasingly complex and sophisticated. Denial-of-service attacks, software tampering (e.g. Trojan horses and computer viruses) and social engineering techniques (e.g. phishing) are some examples becoming prevalent. While we often times hear of the more widely publicized embezzlement, money laundering, burglary and bribery statistics, data has shown that companies have seen greater losses from losses attributed to information security breaches. One of the most effective ways to prevent criminals from accessing and compromising confidential company information is to implement an effective information security plan and properly train firm employees accessing the system. Additionally, companies should implement a dynamic and independent third party auditor to frequently test the adequacy of their security system. Lastly, key responsibilities within the information security chain should be segregated and rotated frequently. If companies follow these three basic tenets, they will be one step closer to the effective security of their information. Threats to Information Systems: Information security threats come in many different forms. Some of the most common threats today are software attacks, theft of intellectual property, identity theft, theft of equipment or information, sabotage, and information infiltration Some of the most prevalent types of data infiltration include input manipulation, program manipulation, data input manipulation, data stealing, and outright sabotage. The most frequent type associated with this form of fraud is manipulation of the data. The reason for this most common is because the criminal requires the less amount of skill. Most people have experienced software attacks of some sort. Viruses, worms, phishing attacks, and Trojan horses are a few common examples of software attacks. Governments, military, corporations, financial institutions, hospitals and private businesses amass a great deal of confidential information about their employees, customers, products, research and financial status. Most of this information is now collected, processed and stored on electronic computers and transmitted across networks to other computers. Implementing a Information Security System: With so many different ways and so much potential for breaches to information security systems.

How to secure information systemsSolutionAnswerInformation.pdf

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Explain the factors necessary to raising productivity. (Brief answers please) Explain the factors necessary to raising productivity. (Brief answers please) (Brief answers please) Solution Many factors which can affect productivity , positively and negatively. Factors necessary to raising productivity are : 1. increase in capital investments in production , 2. Increase in capital investments in technology, 3. Capital investment in facilities, 4. Economies of scale, 5. Knowledge and skill resulting from training and experience, 6. Work methods - positive changes in working methods, 7. quality of products- high quality products, 8. Quality of management- cooperative management, 9. Legislative and regulatory environment, 10. Geographical factors also effect productivity, 11. technological changes-innovative methods, 12. Social environment..

Explain the factors necessary to raising productivity. (Brief a.pdf

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