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Assignment #1
Subject:
Applied Statistics
Topic:
Spss Work
Submitted by:
Menal Hasan
Question
There are two interventions that are described below. Put your data into spss and
then describe the result?
Answer
The above data I have put to the spss and got the following result related to the
data. That is describing below.
Name N Minimum Maximum Mean Std. Deviation
Intervention 1 10 60 100 80.00 10.842
Intervention 2 10 70 90 80.00 5.375
Intervention#1
In the intervention 1 the variability is high because the values are widely dispersed
with each other.
Intervention#2
In the intervention 2 the variability is low because the values are tightly cluster
with each other.
Some of the other results related to the data are following.
Intervention#1 60 70 75 78 80 80 82 85 90 100
Intervention#2 70 75 78 79 80 80 81 82 85 90
Intervention 1:
Valid 10
Missing 0
Std. Deviation 10.842
Skewness .000
Std. Error of Skewness .687
Data Frequency Percent Valid Percent Cumulative Percent
60 1 10.0 10.0 10.0
70 1 10.0 10.0 20.0
75 1 10.0 10.0 30.0
78 1 10.0 10.0 40.0
80 2 20.0 20.0 60.0
82 1 10.0 10.0 70.0
85 1 10.0 10.0 80.0
90 1 10.0 10.0 90.0
100 1 10.0 10.0 100.0
Total 10 100.0 100.0
Explanation:
In this table it is clearly shows that the value are widely dispersed with each other
so the variability is high and the data in which the variability is high is more
successfulthan other.
Intervention 2 :
Valid 10
Missing
0
Std. Deviation
5.375
Skewness
.000
Std. Error of Skewness
.687
Data Frequency Percent Valid Percent Cumulative Percent
70 1 10.0 10.0 10.0
75 1 10.0 10.0 20.0
78 1 10.0 10.0 30.0
79 1 10.0 10.0 40.0
80 2 20.0 20.0 60.0
81 1 10.0 10.0 70.0
82 1 10.0 10.0 80.0
85 1 10.0 10.0 90.0
90 1 10.0 10.0 100.0
Total
10 100.0 100.0
Explanation:
This is also clearly shows that the value are tightly cluster with each other so the
variability is low and the data in which the variability is low is not more
successful.
Variability:
By putting the data into the variability.
 The range.
 The standard deviation.
 The variance.
The following result will appeared.
Data N Range Mean Std.
Deviation
Variance Skewness Kurtosis
Statistic Statistic Statistic Statistic Statistic Statistic Std. Error Statistic Std. Error
Intervention 1 10 40 80.00 10.842 117.556 .000 .687 1.051 1.334
Intervention 2 10 20 80.00 5.375 28.889 .000 .687 1.227 1.334
Data Intervention 1 Intervention 2
Valid 10 10
Missing 0 0
Std. Deviation 10.842 5.375
Variance
117.556 28.889
Skewness
.000 .000
Std. Error of Skewness
.687 .687
Kurtosis
1.051 1.227
Std. Error of Kurtosis
1.334 1.334
Range
40 20
If we can put data into spss the above result will appear that clearly shows
that the inventor 1 is successfulthen 2 because of the widely dispersed of the
data.

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Assignment on APSS

  • 2. Question There are two interventions that are described below. Put your data into spss and then describe the result? Answer The above data I have put to the spss and got the following result related to the data. That is describing below. Name N Minimum Maximum Mean Std. Deviation Intervention 1 10 60 100 80.00 10.842 Intervention 2 10 70 90 80.00 5.375 Intervention#1 In the intervention 1 the variability is high because the values are widely dispersed with each other. Intervention#2 In the intervention 2 the variability is low because the values are tightly cluster with each other. Some of the other results related to the data are following. Intervention#1 60 70 75 78 80 80 82 85 90 100 Intervention#2 70 75 78 79 80 80 81 82 85 90
  • 3. Intervention 1: Valid 10 Missing 0 Std. Deviation 10.842 Skewness .000 Std. Error of Skewness .687 Data Frequency Percent Valid Percent Cumulative Percent 60 1 10.0 10.0 10.0 70 1 10.0 10.0 20.0 75 1 10.0 10.0 30.0 78 1 10.0 10.0 40.0 80 2 20.0 20.0 60.0 82 1 10.0 10.0 70.0 85 1 10.0 10.0 80.0 90 1 10.0 10.0 90.0 100 1 10.0 10.0 100.0 Total 10 100.0 100.0 Explanation:
  • 4. In this table it is clearly shows that the value are widely dispersed with each other so the variability is high and the data in which the variability is high is more successfulthan other. Intervention 2 : Valid 10 Missing 0 Std. Deviation 5.375 Skewness .000 Std. Error of Skewness .687 Data Frequency Percent Valid Percent Cumulative Percent 70 1 10.0 10.0 10.0 75 1 10.0 10.0 20.0 78 1 10.0 10.0 30.0 79 1 10.0 10.0 40.0 80 2 20.0 20.0 60.0 81 1 10.0 10.0 70.0 82 1 10.0 10.0 80.0 85 1 10.0 10.0 90.0 90 1 10.0 10.0 100.0 Total 10 100.0 100.0
  • 5. Explanation: This is also clearly shows that the value are tightly cluster with each other so the variability is low and the data in which the variability is low is not more successful. Variability: By putting the data into the variability.  The range.  The standard deviation.  The variance. The following result will appeared. Data N Range Mean Std. Deviation Variance Skewness Kurtosis Statistic Statistic Statistic Statistic Statistic Statistic Std. Error Statistic Std. Error Intervention 1 10 40 80.00 10.842 117.556 .000 .687 1.051 1.334 Intervention 2 10 20 80.00 5.375 28.889 .000 .687 1.227 1.334 Data Intervention 1 Intervention 2
  • 6. Valid 10 10 Missing 0 0 Std. Deviation 10.842 5.375 Variance 117.556 28.889 Skewness .000 .000 Std. Error of Skewness .687 .687 Kurtosis 1.051 1.227 Std. Error of Kurtosis 1.334 1.334 Range 40 20 If we can put data into spss the above result will appear that clearly shows that the inventor 1 is successfulthen 2 because of the widely dispersed of the data.