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This learning object aims to explore the relationship between position plots and time plots. I initially struggled to comprehend the distinction between the two plots. However, I was able to reach an understanding after some research and practice. Hopefully my learning objective can help other students gain a better understanding of this topic as well!
This learning object aims to explore the relationship between position plots and time plots. I initially struggled to comprehend the distinction between the two plots. However, I was able to reach an understanding after some research and practice. Hopefully my learning objective can help other students gain a better understanding of this topic as well!
Honest Reviews of Tim Han LMA Course Program.pptxtimhan337
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http://sandymillin.wordpress.com/iateflwebinar2024
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Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
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The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
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Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
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Home assignment II on Spectroscopy 2024 Answers.pdf
Aplicaciones de edo ii johelbys campos
1. Programa Nacional De Formación En Sistema De Calidad Y Ambiente
Matemática aplicada.
Autor:
Johelbys Campos C.I: 24.156.988
Grupo: A
Barquisimeto, 2021
2. Una masa de 40 kg alarga un resorte 9.8 cm. Al inicio, la masa se libera desde un punto que
está 40 cm arriba de la posición de equilibrio con una velocidad descendente de 4 m/s.
a) ¿Cuáles son la amplitud, la frecuencia angular y el periodo del movimiento?
b) ¿Cuántos ciclos (completos) habrá completado la masa al final de 3s?
c) ¿En qué momento la masa pasa por la posición de equilibrio con dirección hacia
abajo por sexta vez?
d) ¿Cuál es la velocidad y la aceleración en ese instante?
e) ¿En qué instantes la masa alcanza sus desplazamientos extremos en cualquier lado
de la posición de equilibrio?
f) ¿Cuál es la posición, velocidad y aceleración en los tiempos t= 5, 10, 15, 20 y 25s?
g) ¿En qué instantes la masa está a 0.40 m abajo de la posición de equilibrio?
Solución:
De acuerdo a la ley de Hooke la constante del resorte es:
𝐾 =
𝑓
∆𝐼
=
40(9.8)𝑁
0.098𝑚
= 4000 𝑁/𝑚
Entonces la ecuación diferencial que describe la posición x(t) es:
40𝑥´´(𝑡) + 4000𝑥(𝑡) = 0
La ecuación característica viene dada por:
40𝑟2
+ 4000 = 0 𝑟2
+ 100 = 0
Por lo que 𝑟1 = −10𝑖 𝑟2 = 10𝑖
La solución general de la ecuación diferencial es:
𝑥(𝑡) = 𝐶1 cos 10𝑡 + 𝐶2 𝑠𝑒𝑛 10𝑡
Derivando la posición obtenemos la velocidad:
𝑥´(𝑡) = 𝑉(𝑡) = −10 𝐶1 𝑠𝑒𝑛 10𝑡 + 10 𝐶2 𝑐𝑜𝑠 10𝑡
Usando las condiciones iniciales tenemos 𝑥(0) = −0.4 ; 𝑥´(0) = 4
𝐶1 = −0.4 10 𝐶2 = 4 𝐶2 = 0.4
La solución del PVI será:
𝑥(𝑡) = −0.4 cos 10t + 0.4 𝑠𝑒𝑛 10𝑡
Expresando esta función como 𝑥(𝑡) = 𝐴𝑠𝑒𝑛(10𝑡 + ∅) tenemos que:
−0.4 cos 10𝑡 + 0.4 𝑠𝑒𝑛 10𝑡 = 𝐴𝑠𝑒𝑛 (10𝑡 + ∅) = 𝐴𝑠𝑒𝑛 10𝑡 cos ∅ + 𝑠𝑒𝑛 ∅ cos 10𝑡
= (𝐴𝑠𝑒𝑛 ∅) cos 10𝑡 + (𝐴𝑐𝑜𝑠 ∅)𝑠𝑒𝑛 10𝑡
Entonces 𝐴𝑠𝑒𝑛 ∅ = −0.4 𝐴𝑐𝑜𝑠 ∅ = 0.4
De donde 𝐴 = √(−0.4)2 + (0.4)2 = 0.4√2 𝑡𝑔∅ = −1
Como ∅ > 0 entonces ∅ = 𝑎𝑟𝑐𝑡𝑔(−1) =
−𝜋
4
por lo tanto la posición en cualquier instante
es:
3. 𝑥(𝑡) = (0.4)√2 𝑠𝑒𝑛 (10𝑡
−𝜋
4
)
Así obtenemos la velocidad y la aceleración
𝑉(𝑡) = 4√2 cos (10𝑡
−𝜋
4
) 𝑎(𝑡) = −40√2 sen (10𝑡
−𝜋
4
)
Donde la posición x(t) está dada en metros (m) la velocidad V(T) en m/s y la aceleración a(t)
en m/𝑠2
a) La amplitud es 𝐴 = 0.4√2𝑚 = 0.5657𝑚 𝑤 = 10 𝑟𝑎𝑑/𝑠 𝑇 =
𝜋
5
𝑠𝑒𝑔 = 0.6283 𝑠𝑒𝑔
b) El número de ciclos completos en 3 seg es 4 ya que
3
𝑇
= 4.77
c) La posición de equilibrio se alcanza en los tiempos donde 10𝑡 −
𝜋
4
= 𝑛𝜋 es decir:
𝑡 =
𝑛𝜋
10
+
𝜋
40
𝑐𝑜𝑛 𝑛 = 0,1,2, …
Ahora la masa se mueve hacia abajo cuando la velocidad es positiva, esto se logra cuando n
es par, es decir, la masa pasa por primera vez hacia abajo cuando n=0; por segunda vez
cuando n=2 y por sexta vez cuando n=10. Este último tiempo es:
𝑡 =
4𝑡𝜋
40
= 3.22 𝑠𝑒𝑔
d) En ese momento la velocidad y la aceleración son 𝑉 = 4√2
𝑚
𝑠
= 5.6569 𝑚/𝑠
𝑎 = 0 𝑚/𝑠2
e) La masa alcanza sus desplazamientos extremos cuando la velocidad se anula, esto es:
10𝑡 −
𝜋
4
=
𝜋
2
+ 𝑛𝜋 es decir 𝑡 =
1
10
(
3𝜋
4
+ 𝑛𝜋) 𝑐𝑜𝑛 𝑛 = 0,1,2, …
f)
t X(t) V(t) a(t)
5 -0.4909 2.8104 49.0936
10 -0.5475 1.4238 54.7474
15 -0.5657 -0.0625 56.5651
20 -05442 -1.5444 54.4194
25 -0.4846 -2.9182 48.4607
g) La masa está a 0,40m abajo de la posición de equilibrio cuando
𝑥(𝑡) = 0.4√2 𝑠𝑒𝑛 (10𝑡 −
𝜋
4
) = 0.4
es decir, cuando:
10𝑡 −
𝜋
4
= 𝑎𝑟𝑐𝑠𝑒𝑛 (
1
√2
) Por lo que tenemos dos opciones:
10𝑡 −
𝜋
4
=
𝜋
4
+ 2𝑛𝜋 𝑑𝑜𝑛𝑑𝑒 𝑡
𝜋
10
(2𝑛 +
1
2
) 𝑛 = 0,1,2, …
10𝑡 −
𝜋
4
=
3𝜋
4
+ 2𝑛𝜋 𝑑𝑜𝑛𝑑𝑒 𝑡 =
(2𝑛 + 1)𝜋
10
𝑛 = 0,1,2, …