A generalized transducing phage is used to infect wildtype prototroph.pdf
•
0 likes•4 views
A generalized transducing phage is used to infect wildtype prototrophic E. coli, and the lysate is used to transduce an abcderecipient. The recipient cells are plated on minimal medium supplied with the indicated compounds. The results are shown in the following table. (Note that aindicates a requirement for compound A, etc.) What can you conclude about the order of these genes? Three of the genes are closely linked and have the order bdc, while genes a and e are not closely linked to any other genes. The gene order of four of the genes is cead, but the placement of b is unknown. Genes b,c and d are linked, but their order cannot be determined. Genes a and e are not closely linked to any of the other genes. Genes a,c,d and e are closely linked, but their order cannot be determined with certainty, while gene b is not closely linked to this group..
Report
Share
Report
Share
Download to read offline
Recommended
a. From the DNA fragmentation analysis, it is clear that the polydac.pdf
a. From the DNA fragmentation analysis, it is clear that the polydactyly came from the parents X
chromosome as the affected sons have same band pattern as father has one band that found in
sons and mother has two bands that appeared in affected sons.
The father genotype is XbY, where Xb is affected with polydactyly.
The mother genotype is XbX, one X is unaffected, as daughters are not affected by the disease.
First son has XY genotype, Second son has XbY genotype, First daughter has XbX genotype,
third son has XbY genotype, second daughter has XbX genotype, fourth son has XbY genotype
and fifth son has XY genotype.
b. Yes. For example, AABbccDd genotype might contribute +1.3 units to genetic liability while
aabbCcdd might contribute -2.3 units to genetic liability. Due to unmeasure genetic liability, any
arbitrary unit can be set. It can be 0 which denote the mean liability and positive numbers denote
risk and negative denote protection i.e., lower probablity of developing the disease. Polydactyly
mutation was mapped to chromosome 2p. A single point mutation is maintained to carry the
mutation. A study showed that five-generation Indian family of 37 individuals have 15 affected
persons of polydactyly and genome wide mapping and haplotype analysis observed in this study
indicated highly informative polymorphic markers on part of pedigree showed linkage between
the phenotype and markers on the chromosome.
c. The first daughter is likely to be carrier of this mutation as analyzed from the restriction
fragments of the gene.
Recombination between marker and disease can never be completely ruled out, even for very
tightly linked markers, but the error rate can be greatly reduced by using two marker loci situated
on opposite sides of the disease locus. This type of flanking or bridging markers help to produce
a marker-marker recombination and at least false prediction can be avoided.
Solution
a. From the DNA fragmentation analysis, it is clear that the polydactyly came from the parents X
chromosome as the affected sons have same band pattern as father has one band that found in
sons and mother has two bands that appeared in affected sons.
The father genotype is XbY, where Xb is affected with polydactyly.
The mother genotype is XbX, one X is unaffected, as daughters are not affected by the disease.
First son has XY genotype, Second son has XbY genotype, First daughter has XbX genotype,
third son has XbY genotype, second daughter has XbX genotype, fourth son has XbY genotype
and fifth son has XY genotype.
b. Yes. For example, AABbccDd genotype might contribute +1.3 units to genetic liability while
aabbCcdd might contribute -2.3 units to genetic liability. Due to unmeasure genetic liability, any
arbitrary unit can be set. It can be 0 which denote the mean liability and positive numbers denote
risk and negative denote protection i.e., lower probablity of developing the disease. Polydactyly
mutation was mapped to chromosome 2p. A single point mutation is.
An STR on chromosome 5 is immediately adjacent to a gene involved in a.pdf
An STR on chromosome 5 is immediately adjacent to a gene involved in a dominant metabolism
disorder (one one copy of the mutation is required for the disease). Thus, in a family with a
known mutation in the disorder-causing gene, inheritance of the STR can be used to diagnose the
disorder. There are four different alleles of the STR (Q, B, S, and L), each with different
numbers of GATCTCG repeats. The S allele has 2 repeats, the B allele has 7 repeats, the Q allele
has 10 repeats, and the L allele has 5 repeats. Part 1 Lane 1 of the gel shown below indicates the
locations of PCR products corresponding to all four STR alleles when run together in one lane.
DNA was loaded into the wells at the top of the gel. Move the letter of each allele to its correct
position at the left of Lane 1 to indicate where each allele runs on the gel. Andre and Maria are
the parents in this family; all others shown on the gel are children. Daughter Juliana is born with
the metabolism disorder, but daughter Camila does not have the disorder. Who else in the family
has the disorder? Gabricl. Maria Andre Part 3 Why does Gabriel have only one band on the gel?
He inherited the same allele from each parent. The DNA must have run incorrectly. He inherited
an allele from only one parent. Part 4 The family adopts a boy and names him Bruno. He is
tested and confirmed not to have the metabolism disorder that runs in this family. However, he
does share, by chance, an STR allele with Andre but NOT Maria. Given this information, which
of the following genotypes could be Brouno's genotype? B, B B, 5 Q. B B.
Answer part a)According to the gene map of the wild type and the m.pdf
Answer part a)
According to the gene map of the wild type and the mutant gene, it can be seen that the mutant
lacks a site for restriction digestion. This shows that in wild type, the restriction enzyme can
digest the DNA at any three sites and thus atleast two bands will appear after amplification. On
the contrary, the deletion of middle sequence of restriction site will lead to formation of a single
band in mutant gene. The smaller band will represnt the mutant and the larger band will
represent the normal/wild type allele. Thus, according to this information, it can be deciphered
that the mother is a heterozygous in nature and carries a mutant allele for Tay-Sachs disease
while the father does not. Thus, the lower band will be a representative of mutant or \"t\" and the
upper band will be a representative of normal \"T\" allele.
Answer part b)
Since the mother is a carrier, there are 50% chances that the mother will transmit the mutant
allele to her offspring. Thus, the couple can bear a normal heterozygous carrier female offspring
or an affected male offspring. According to the information in the image, the genotype bands of
father and offspring match which clearly suggest that the offspring is an unaffected heterozygous
carrier female.
Answer part c)
There are always 50% changes for a male to be affected by the disease. Rest 50% males will be
normal both geotypically and phenotypically. Also, all the females will be phenotypically normal
but 50% of them would be heterozygous carriers.
Genotypes: XtX : XtY : XX : XY :: 1:1:1:1
Phenotypes: Affected : normal : carriers :: 1: 2: 1XYXtXtXXtYXXXXY
Solution
Answer part a)
According to the gene map of the wild type and the mutant gene, it can be seen that the mutant
lacks a site for restriction digestion. This shows that in wild type, the restriction enzyme can
digest the DNA at any three sites and thus atleast two bands will appear after amplification. On
the contrary, the deletion of middle sequence of restriction site will lead to formation of a single
band in mutant gene. The smaller band will represnt the mutant and the larger band will
represent the normal/wild type allele. Thus, according to this information, it can be deciphered
that the mother is a heterozygous in nature and carries a mutant allele for Tay-Sachs disease
while the father does not. Thus, the lower band will be a representative of mutant or \"t\" and the
upper band will be a representative of normal \"T\" allele.
Answer part b)
Since the mother is a carrier, there are 50% chances that the mother will transmit the mutant
allele to her offspring. Thus, the couple can bear a normal heterozygous carrier female offspring
or an affected male offspring. According to the information in the image, the genotype bands of
father and offspring match which clearly suggest that the offspring is an unaffected heterozygous
carrier female.
Answer part c)
There are always 50% changes for a male to be affected by the disease. Rest 50% males w.
Recommended
a. From the DNA fragmentation analysis, it is clear that the polydac.pdf
a. From the DNA fragmentation analysis, it is clear that the polydactyly came from the parents X
chromosome as the affected sons have same band pattern as father has one band that found in
sons and mother has two bands that appeared in affected sons.
The father genotype is XbY, where Xb is affected with polydactyly.
The mother genotype is XbX, one X is unaffected, as daughters are not affected by the disease.
First son has XY genotype, Second son has XbY genotype, First daughter has XbX genotype,
third son has XbY genotype, second daughter has XbX genotype, fourth son has XbY genotype
and fifth son has XY genotype.
b. Yes. For example, AABbccDd genotype might contribute +1.3 units to genetic liability while
aabbCcdd might contribute -2.3 units to genetic liability. Due to unmeasure genetic liability, any
arbitrary unit can be set. It can be 0 which denote the mean liability and positive numbers denote
risk and negative denote protection i.e., lower probablity of developing the disease. Polydactyly
mutation was mapped to chromosome 2p. A single point mutation is maintained to carry the
mutation. A study showed that five-generation Indian family of 37 individuals have 15 affected
persons of polydactyly and genome wide mapping and haplotype analysis observed in this study
indicated highly informative polymorphic markers on part of pedigree showed linkage between
the phenotype and markers on the chromosome.
c. The first daughter is likely to be carrier of this mutation as analyzed from the restriction
fragments of the gene.
Recombination between marker and disease can never be completely ruled out, even for very
tightly linked markers, but the error rate can be greatly reduced by using two marker loci situated
on opposite sides of the disease locus. This type of flanking or bridging markers help to produce
a marker-marker recombination and at least false prediction can be avoided.
Solution
a. From the DNA fragmentation analysis, it is clear that the polydactyly came from the parents X
chromosome as the affected sons have same band pattern as father has one band that found in
sons and mother has two bands that appeared in affected sons.
The father genotype is XbY, where Xb is affected with polydactyly.
The mother genotype is XbX, one X is unaffected, as daughters are not affected by the disease.
First son has XY genotype, Second son has XbY genotype, First daughter has XbX genotype,
third son has XbY genotype, second daughter has XbX genotype, fourth son has XbY genotype
and fifth son has XY genotype.
b. Yes. For example, AABbccDd genotype might contribute +1.3 units to genetic liability while
aabbCcdd might contribute -2.3 units to genetic liability. Due to unmeasure genetic liability, any
arbitrary unit can be set. It can be 0 which denote the mean liability and positive numbers denote
risk and negative denote protection i.e., lower probablity of developing the disease. Polydactyly
mutation was mapped to chromosome 2p. A single point mutation is.
An STR on chromosome 5 is immediately adjacent to a gene involved in a.pdf
An STR on chromosome 5 is immediately adjacent to a gene involved in a dominant metabolism
disorder (one one copy of the mutation is required for the disease). Thus, in a family with a
known mutation in the disorder-causing gene, inheritance of the STR can be used to diagnose the
disorder. There are four different alleles of the STR (Q, B, S, and L), each with different
numbers of GATCTCG repeats. The S allele has 2 repeats, the B allele has 7 repeats, the Q allele
has 10 repeats, and the L allele has 5 repeats. Part 1 Lane 1 of the gel shown below indicates the
locations of PCR products corresponding to all four STR alleles when run together in one lane.
DNA was loaded into the wells at the top of the gel. Move the letter of each allele to its correct
position at the left of Lane 1 to indicate where each allele runs on the gel. Andre and Maria are
the parents in this family; all others shown on the gel are children. Daughter Juliana is born with
the metabolism disorder, but daughter Camila does not have the disorder. Who else in the family
has the disorder? Gabricl. Maria Andre Part 3 Why does Gabriel have only one band on the gel?
He inherited the same allele from each parent. The DNA must have run incorrectly. He inherited
an allele from only one parent. Part 4 The family adopts a boy and names him Bruno. He is
tested and confirmed not to have the metabolism disorder that runs in this family. However, he
does share, by chance, an STR allele with Andre but NOT Maria. Given this information, which
of the following genotypes could be Brouno's genotype? B, B B, 5 Q. B B.
Answer part a)According to the gene map of the wild type and the m.pdf
Answer part a)
According to the gene map of the wild type and the mutant gene, it can be seen that the mutant
lacks a site for restriction digestion. This shows that in wild type, the restriction enzyme can
digest the DNA at any three sites and thus atleast two bands will appear after amplification. On
the contrary, the deletion of middle sequence of restriction site will lead to formation of a single
band in mutant gene. The smaller band will represnt the mutant and the larger band will
represent the normal/wild type allele. Thus, according to this information, it can be deciphered
that the mother is a heterozygous in nature and carries a mutant allele for Tay-Sachs disease
while the father does not. Thus, the lower band will be a representative of mutant or \"t\" and the
upper band will be a representative of normal \"T\" allele.
Answer part b)
Since the mother is a carrier, there are 50% chances that the mother will transmit the mutant
allele to her offspring. Thus, the couple can bear a normal heterozygous carrier female offspring
or an affected male offspring. According to the information in the image, the genotype bands of
father and offspring match which clearly suggest that the offspring is an unaffected heterozygous
carrier female.
Answer part c)
There are always 50% changes for a male to be affected by the disease. Rest 50% males will be
normal both geotypically and phenotypically. Also, all the females will be phenotypically normal
but 50% of them would be heterozygous carriers.
Genotypes: XtX : XtY : XX : XY :: 1:1:1:1
Phenotypes: Affected : normal : carriers :: 1: 2: 1XYXtXtXXtYXXXXY
Solution
Answer part a)
According to the gene map of the wild type and the mutant gene, it can be seen that the mutant
lacks a site for restriction digestion. This shows that in wild type, the restriction enzyme can
digest the DNA at any three sites and thus atleast two bands will appear after amplification. On
the contrary, the deletion of middle sequence of restriction site will lead to formation of a single
band in mutant gene. The smaller band will represnt the mutant and the larger band will
represent the normal/wild type allele. Thus, according to this information, it can be deciphered
that the mother is a heterozygous in nature and carries a mutant allele for Tay-Sachs disease
while the father does not. Thus, the lower band will be a representative of mutant or \"t\" and the
upper band will be a representative of normal \"T\" allele.
Answer part b)
Since the mother is a carrier, there are 50% chances that the mother will transmit the mutant
allele to her offspring. Thus, the couple can bear a normal heterozygous carrier female offspring
or an affected male offspring. According to the information in the image, the genotype bands of
father and offspring match which clearly suggest that the offspring is an unaffected heterozygous
carrier female.
Answer part c)
There are always 50% changes for a male to be affected by the disease. Rest 50% males w.
Final horizontal gene transfer
Ppt is made vailable for public for scientifc use.
gene transfer in bacteria its concept and its mechanism explained by using practical examples in a simple language. data is significant for competitive examinations
Bacteriophage T2 normally infects the different E. coli strains. B an.pdf
Bacteriophage T2 normally infects the different E. coli strains. B and C. However, certain
mutations, designated r, block growth on strain B. Ten r mutations were mapped by two-point
recombination frequencies to a small region of the T2 chromosome, shown below. When the ten
r mutants were tested for complementation by mixed-infection of strain B, certain pairs could kill
the B host (+), while other pairs failed to grow completely (-), Assuming the mutations a, b, and
c are known to lie in the genes A, B. and C. use the complementation data in the table below to
mark gene boundaries on the genetic map. Do the data reveal the presence of a fourth gene in
this region? If so, please show it\'s location on the map.
Solution
Crosses between strains which produce wild type progenies, suggest that these genes are present
in different gene. On the basis of this we would determine the following boundaries:
agdj are present in one gene because crosses between these gene are producing mutant
progenies; representing cis effect. The other genes are bh, efi and kc. Therefore, there are four
different genes.
Agdj, bh, efi and kc..
Which is NOT true about alleles- Ans A- Alleles differ from each other.docx
Which is NOT true about alleles? Ans A. Alleles differ from each other by one or only a few bases B. New alleles are formed by mutation C. Facial characteristics and certain behaviors are in part determined by alleles D. Alleles are generally found on different chromosomes What does sporadic cause of a disease mean? (choose the best answer) Ans A. We don't understand its origin B. There is probably a genetic mutation that occurred in the patient even though there is no family history C. The disease was caused by non-genetic processes D. It is a disease that only occurs in plant seeds Which of the following statements is NOT correct Ans A. Every cell in the human body contains DNA B. Genetics should be viewed as a probability C. Non-coding RNA transcribed from DNA have important roles in regulating the expression of genes D. Each of us carries 15-20 lethal mutations 6. What percent of genes in Humans encode proteins? Ans A. 22 , 000 1 2% of the DNA B. 22 , 000 10 20% of the DNA C. 11 , 000 1 2% of the DNA D. 11 , 000 10 20% of the DNA 7. A gene family is a group of genes that share important characteristics. In many cases, genes in a family share a similar sequence of DNA building blocks (nucleotides). The largest gene family encodes for: A. Longevity genes Ans B. Immunoglobulins C. Blood types (Rh, A,B, and O) D. Intelligence genes 8. Bacteria may be used to synthesize certain drugs and food additives because: Ans A. they are identical to human cells. B. scientists can transform them into human cells. C. their genetic codes are similar to humans.
.
Please give an explaination fir those quesions! 2 3 4 5 1- Aman with r.docx
Please give an explaination fir those quesions!
2
3
4
5
1. Aman with red.geen colour blindness is marned to a girl with normal colwir vision. What is the probaliliny that his childron will be coluur blind? 2. A boy has Dachenne muscular dyatrophy. His malemal uncle had died of museular dystrophy at the age of 21 years. What is the prohatility that this chilfs sibs will be affected? Assignments \#3 rocosive or S -kinked dominant and X -linked recesive inheritance. (Nole that a potigrte may be coempable with muve thas ane type of inheritance.) Assignnents \#4 Examine the pedieree frum a funily with a ernetic disease and anvv the questiens below: a. Does this pedigree isdicate autosonal deuninant, teoessive of set-link type of inheritance? Give reasons for your choice. b. Assuaning that B and b are the normal and mataut alleies respectively what would be the enenotypes of the individuals :II.1, 11 2 and III .3? c. Individual II. 3 requested genctic counselling. What is the probubility that her child woald be affected. Fxplain why. Assignments \#5 Susan's grandfather was deaf, and passed down a hercditary form of deafhess within Susan's family as shown in Figure. A. Is this mutation most likely to be dominant of recessive?? B. Is it carried on an autosome of a sex cluomosome? Why? C. A complete SNP analysis has been done for all of the 11 grandchildren (4 affected, and 7 unaffected) In comparing these 11 SNP result, how long a haplotype block would you expect to find around the critical \#ene? How might you deleet it? Assignments \#1 Distinguish between the following genetic terms: A. Gene and allele. B. Homozygous and heterozygous. C. Genotype and phenotype. D. Dominant and recessive. 1. A man with red-green colour blindness is married to a girl with normal colour vision. What is the probability that his children will be colour blind? 2. A boy has Duchenne muscular dystrophy. His maternal uncle had died of muscular dystrophy at the age of 21 years. What is the probability that this child's sibs will be affected? Explain, giving reasons, whether the following pedigrees are compatible with autosomal dominant, autosomal recessive or X -linked dominant and X -linked recessive inheritance. (Note that a pedigree may be compatible with more than one type of inheritance.) a. b. c. a. b. c. Assignments \#4 Examine the pedigree from a family with a genetic disease and ansv the questions below: a. Does this pedigree indicate autosomal dominant, recessive or sex-link type of inheritance? Give reasons for your choice. b. Assuming that B and b are the normal and mutant alleles respectively what would be the genotypes of the individuals: II.I, II.2 and III.3 ? c. Individual II. 3 requested genetic counselling. What is the probability that her child would be affected. Explain why. Susan's grandfather was deaf, and passed down a hereditary form of deafness within Susan's family as shown in Figure. A. Is this mutation most likely to be dominant or recessive? B. I.
1- Recessive traits are less common than dominant traits because ) B-.docx
1- Recessive traits are less common than dominant traits because )
B- person would need to inherit the recessive allele from both parents . A the dominant alleles must not have existed in the person's family history . dominant
. D ) only fathers are able to pass on recessive genes to their children , and mothers ' genes are typically
C ) recessive genes are more sensitive to the crossing over process
2- Imagine that Dr. Walsh measures the heritability of anger in pairs of siblings who are being reared together . She finds a correlation of .15 between pairs of adopted siblings who are biologically unrelated , a correlation of .63 for fraternal twins , and a correlation of .92 for identical twins . These results suggest that D ) relative to the influence of genetics , the environment contributes relatively little to variability in anger . C ) both the environment and genetics contribute substantially to the variability in anger . A ) compared to the impact of the environment , genetics contributes relatively little to variability in anger . B ) the shared environment contributes greatly to the variability in anger only among identical twins .
3- Genotype is to phenotype as An
A) male is to female.
D) dominant is to recessive .
C ) hidden is to observable .
B ) nature is to nurture .
4- If Roger is an XYY male, he is likely to A) be taller than average. B ) be infertile . C) experience motor skill problems. D) have all of the above characteristics. Answers: A) be taller than average
B- person would need to inherit the recessive allele from both parents . A the dominant alleles must not have existed in the person's family history . dominant
. D ) only fathers are able to pass on recessive genes to their children , and mothers ' genes are typically
C ) recessive genes are more sensitive to the crossing over process
2- Imagine that Dr. Walsh measures the heritability of anger in pairs of siblings who are being reared together . She finds a correlation of .15 between pairs of adopted siblings who are biologically unrelated , a correlation of .63 for fraternal twins , and a correlation of .92 for identical twins . These results suggest that D ) relative to the influence of genetics , the environment contributes relatively little to variability in anger . C ) both the environment and genetics contribute substantially to the variability in anger . A ) compared to the impact of the environment , genetics contributes relatively little to variability in anger . B ) the shared environment contributes greatly to the variability in anger only among identical twins .
3- Genotype is to phenotype as An
A) male is to female.
D) dominant is to recessive .
C ) hidden is to observable .
B ) nature is to nurture .
4- If Roger is an XYY male, he is likely to A) be taller than average. B ) be infertile . C) experience motor skill problems. D) have all of the above characteristics. Answers: A) be taller than average
.
GENE MAPPING
GENE MAPPING WITH A NOTE ON THE BAND SUB BAND AND ARMS OF CHROMOSOMES AND GPS MAPPING OF CHROMOSOMES
Please answer all questionsDefine1. Wild type –2. Epistasis –.pdf
Please answer all questions
Define
1. Wild type –
2. Epistasis –
Fill in the Blank
3. Two genes may interact effecting one trait and resulting in novel phenotypes with an F2
phenotypic ________________ ratio.
4. Under ________________ conditions, conditionally lethal mutants will die.
True or False
5. Penetrance is the degree or intensity with which a particular genotype is expressed in a
phenotype.
6. Continuous traits are usually controlled by multiple genes and may be influenced by the
environment.
Short Answer
7. Describe the inheritance pattern(s) of blood types.
8. When studying a newly discovered flowering plant in Costa Rica, you collect data on its petal
color in an effort to determine how this trait may be inherited. You find that 852 flowers are red,
331 are white and 389 are yellow. What are the possible inheritance patterns, and how could you
definitely conclude which of these possibilities is the true mode of inheritance?
Solution
Wild type- wild type phenotype refers to characteristics that occurs naturally in a breeding
population.
Epistasis - it refers to a phenomena when one gene’s expression is dependent on the presence of
another gene(s), called the modifier gene.
9:16
Let\'s take an example of comb varieties in chicken
We have two pure breeds : wyandotte whose phenotype is a rose comb and brahmas having the
phenotype of a pea comb, when crossed with each other, they create a completely new phenotype
of a walnut comb. Let\'s look at the ratio:
Parental cross: rose comb x pea comb
F1 : all walnut combs
F2 : 9 walnut : 3 rose: 3peas : 1 single
Hence the ratio is 9:16
Under the restrictive or nonpermissive condition conditions, conditionally lethal mutants will
die.
Conditionally lethal mutants are those which have an allele that will make the survival of the
species difficult only in a specific condition.
True. for example if a mutation in a gene gives the species a particular characterisitc which has
97%penetrance, only 97% of those with the mutation will develop that characteristic and 3 %
will not.
True. multiple genes affect continuous traits. For such complex gene interactions, the traits are
influenced by environmental factors too. For example, height and skin color.
There are four basic blood types which are A, B, AB and O and together with the Rh factor,
these can be +ve or -ve.
A and B are dominant, while O is recessive.
Blood type
A
B
O
A
A
AB
A
B
AB
B
B
O
A
B
O
For Rh factor, Rh (+)ve is dominant.
So if the any one or both parents have Rh (+)ve factor, the progeny will be Rh(+)ve.
If both parents are Rh(-)ve, the progeny will be Rh (-)ve
Father
Mother
D
D
d
Dd
Dd
d
Dd
Dd
100% Rh (+)ve children
Father
Mother
D
d
d
Dd
dd
d
Dd
dd
50% Rh(+)ve children
Red: 852
White: 331
Yellow:389
According to the given data, red is dominant and white is recessive and yellow is a result of
incomplete dominance of both white and red phenotype.
It can\'t be codominance, because codominance involves both phenotypes being expressed in
di.
Please also provide an explanation for the chosen answer Q2.pdf
Please also provide an explanation for the chosen answer.
Q24.3. Within a group of mutants (genetically related organisms with slightly different genotypes)
with the same overt phenotype, DN/ sequencing studies mapping the location of the mutations
determined that mutations in different organisms were on different chromosomes. This indicates
that A. the same gene governs all the steps in a particular biological pathway. B. different genes
can govern different individual steps in the same biological pathway. C. different genes govern the
same step in a particular biological pathway. D. all biological pathways are governed by different
genes. E. genes do not govern steps in biological pathways. Question Q24.4. A bit of practice
reading and interpreting networks. Q24.4 In the network below we see the functional relationships
network of transcription factors, the genes encoding them, environmental factors and the genes
responsible for a complex bacterial phenotype called heterocyst formation ( hgl, hep, and nif).
Which interpretation of the figure is most reasonable? A. Calcium negatively regulates CcbP. B.
The expression of gene pats leads to an increase in the expression of hgl. C. Nitrogen limitation
"turns-on" hgl expression. D. The NtcA transcription factor can act both negatively and positively.
E. C & D.
A few days ago. a recall notice was issued foe frozen strawberries so.pdf
A few days ago. a recall notice was issued foe frozen strawberries sold in the Portland area
because several cases of hepatitis A in Wastlngton were linked to these products. Presumably,
the strawberries were elther irrigated or otherwise contaminated with water containing human
feces that harbored hepatitis A virus, This is an example of which trpe of microblal sourced for
foodborne illneis? A food animal - infection or colonltation during its lifetime None of the other
four anwers are correct Contamination by human or animal feces during growing. harvesting,
washing, tramport, or storme Contamination by human microbioda or pathogens durine handling
\& preparation Contamination by naturaliy occurring envirormental organisms from soil or other
sources.
A female is heterozygous for an X-linked recessive trait. Which of th.pdf
A female is heterozygous for an X-linked recessive trait. Which of the following statements is
true? She may or may not be affected because some of her cells express one allele of the
causative gene, while other cells express the other allele. She is unaffected because all of her
cells express the common allele of the causative gene. She is affected because all of her cells
express the disease allele of the causative gene. She is unaffected because all of her cells express
both alleles of the causative gene..
More Related Content
Similar to A generalized transducing phage is used to infect wildtype prototroph.pdf
Final horizontal gene transfer
Ppt is made vailable for public for scientifc use.
gene transfer in bacteria its concept and its mechanism explained by using practical examples in a simple language. data is significant for competitive examinations
Bacteriophage T2 normally infects the different E. coli strains. B an.pdf
Bacteriophage T2 normally infects the different E. coli strains. B and C. However, certain
mutations, designated r, block growth on strain B. Ten r mutations were mapped by two-point
recombination frequencies to a small region of the T2 chromosome, shown below. When the ten
r mutants were tested for complementation by mixed-infection of strain B, certain pairs could kill
the B host (+), while other pairs failed to grow completely (-), Assuming the mutations a, b, and
c are known to lie in the genes A, B. and C. use the complementation data in the table below to
mark gene boundaries on the genetic map. Do the data reveal the presence of a fourth gene in
this region? If so, please show it\'s location on the map.
Solution
Crosses between strains which produce wild type progenies, suggest that these genes are present
in different gene. On the basis of this we would determine the following boundaries:
agdj are present in one gene because crosses between these gene are producing mutant
progenies; representing cis effect. The other genes are bh, efi and kc. Therefore, there are four
different genes.
Agdj, bh, efi and kc..
Which is NOT true about alleles- Ans A- Alleles differ from each other.docx
Which is NOT true about alleles? Ans A. Alleles differ from each other by one or only a few bases B. New alleles are formed by mutation C. Facial characteristics and certain behaviors are in part determined by alleles D. Alleles are generally found on different chromosomes What does sporadic cause of a disease mean? (choose the best answer) Ans A. We don't understand its origin B. There is probably a genetic mutation that occurred in the patient even though there is no family history C. The disease was caused by non-genetic processes D. It is a disease that only occurs in plant seeds Which of the following statements is NOT correct Ans A. Every cell in the human body contains DNA B. Genetics should be viewed as a probability C. Non-coding RNA transcribed from DNA have important roles in regulating the expression of genes D. Each of us carries 15-20 lethal mutations 6. What percent of genes in Humans encode proteins? Ans A. 22 , 000 1 2% of the DNA B. 22 , 000 10 20% of the DNA C. 11 , 000 1 2% of the DNA D. 11 , 000 10 20% of the DNA 7. A gene family is a group of genes that share important characteristics. In many cases, genes in a family share a similar sequence of DNA building blocks (nucleotides). The largest gene family encodes for: A. Longevity genes Ans B. Immunoglobulins C. Blood types (Rh, A,B, and O) D. Intelligence genes 8. Bacteria may be used to synthesize certain drugs and food additives because: Ans A. they are identical to human cells. B. scientists can transform them into human cells. C. their genetic codes are similar to humans.
.
Please give an explaination fir those quesions! 2 3 4 5 1- Aman with r.docx
Please give an explaination fir those quesions!
2
3
4
5
1. Aman with red.geen colour blindness is marned to a girl with normal colwir vision. What is the probaliliny that his childron will be coluur blind? 2. A boy has Dachenne muscular dyatrophy. His malemal uncle had died of museular dystrophy at the age of 21 years. What is the prohatility that this chilfs sibs will be affected? Assignments \#3 rocosive or S -kinked dominant and X -linked recesive inheritance. (Nole that a potigrte may be coempable with muve thas ane type of inheritance.) Assignnents \#4 Examine the pedieree frum a funily with a ernetic disease and anvv the questiens below: a. Does this pedigree isdicate autosonal deuninant, teoessive of set-link type of inheritance? Give reasons for your choice. b. Assuaning that B and b are the normal and mataut alleies respectively what would be the enenotypes of the individuals :II.1, 11 2 and III .3? c. Individual II. 3 requested genctic counselling. What is the probubility that her child woald be affected. Fxplain why. Assignments \#5 Susan's grandfather was deaf, and passed down a hercditary form of deafhess within Susan's family as shown in Figure. A. Is this mutation most likely to be dominant of recessive?? B. Is it carried on an autosome of a sex cluomosome? Why? C. A complete SNP analysis has been done for all of the 11 grandchildren (4 affected, and 7 unaffected) In comparing these 11 SNP result, how long a haplotype block would you expect to find around the critical \#ene? How might you deleet it? Assignments \#1 Distinguish between the following genetic terms: A. Gene and allele. B. Homozygous and heterozygous. C. Genotype and phenotype. D. Dominant and recessive. 1. A man with red-green colour blindness is married to a girl with normal colour vision. What is the probability that his children will be colour blind? 2. A boy has Duchenne muscular dystrophy. His maternal uncle had died of muscular dystrophy at the age of 21 years. What is the probability that this child's sibs will be affected? Explain, giving reasons, whether the following pedigrees are compatible with autosomal dominant, autosomal recessive or X -linked dominant and X -linked recessive inheritance. (Note that a pedigree may be compatible with more than one type of inheritance.) a. b. c. a. b. c. Assignments \#4 Examine the pedigree from a family with a genetic disease and ansv the questions below: a. Does this pedigree indicate autosomal dominant, recessive or sex-link type of inheritance? Give reasons for your choice. b. Assuming that B and b are the normal and mutant alleles respectively what would be the genotypes of the individuals: II.I, II.2 and III.3 ? c. Individual II. 3 requested genetic counselling. What is the probability that her child would be affected. Explain why. Susan's grandfather was deaf, and passed down a hereditary form of deafness within Susan's family as shown in Figure. A. Is this mutation most likely to be dominant or recessive? B. I.
1- Recessive traits are less common than dominant traits because ) B-.docx
1- Recessive traits are less common than dominant traits because )
B- person would need to inherit the recessive allele from both parents . A the dominant alleles must not have existed in the person's family history . dominant
. D ) only fathers are able to pass on recessive genes to their children , and mothers ' genes are typically
C ) recessive genes are more sensitive to the crossing over process
2- Imagine that Dr. Walsh measures the heritability of anger in pairs of siblings who are being reared together . She finds a correlation of .15 between pairs of adopted siblings who are biologically unrelated , a correlation of .63 for fraternal twins , and a correlation of .92 for identical twins . These results suggest that D ) relative to the influence of genetics , the environment contributes relatively little to variability in anger . C ) both the environment and genetics contribute substantially to the variability in anger . A ) compared to the impact of the environment , genetics contributes relatively little to variability in anger . B ) the shared environment contributes greatly to the variability in anger only among identical twins .
3- Genotype is to phenotype as An
A) male is to female.
D) dominant is to recessive .
C ) hidden is to observable .
B ) nature is to nurture .
4- If Roger is an XYY male, he is likely to A) be taller than average. B ) be infertile . C) experience motor skill problems. D) have all of the above characteristics. Answers: A) be taller than average
B- person would need to inherit the recessive allele from both parents . A the dominant alleles must not have existed in the person's family history . dominant
. D ) only fathers are able to pass on recessive genes to their children , and mothers ' genes are typically
C ) recessive genes are more sensitive to the crossing over process
2- Imagine that Dr. Walsh measures the heritability of anger in pairs of siblings who are being reared together . She finds a correlation of .15 between pairs of adopted siblings who are biologically unrelated , a correlation of .63 for fraternal twins , and a correlation of .92 for identical twins . These results suggest that D ) relative to the influence of genetics , the environment contributes relatively little to variability in anger . C ) both the environment and genetics contribute substantially to the variability in anger . A ) compared to the impact of the environment , genetics contributes relatively little to variability in anger . B ) the shared environment contributes greatly to the variability in anger only among identical twins .
3- Genotype is to phenotype as An
A) male is to female.
D) dominant is to recessive .
C ) hidden is to observable .
B ) nature is to nurture .
4- If Roger is an XYY male, he is likely to A) be taller than average. B ) be infertile . C) experience motor skill problems. D) have all of the above characteristics. Answers: A) be taller than average
.
GENE MAPPING
GENE MAPPING WITH A NOTE ON THE BAND SUB BAND AND ARMS OF CHROMOSOMES AND GPS MAPPING OF CHROMOSOMES
Please answer all questionsDefine1. Wild type –2. Epistasis –.pdf
Please answer all questions
Define
1. Wild type –
2. Epistasis –
Fill in the Blank
3. Two genes may interact effecting one trait and resulting in novel phenotypes with an F2
phenotypic ________________ ratio.
4. Under ________________ conditions, conditionally lethal mutants will die.
True or False
5. Penetrance is the degree or intensity with which a particular genotype is expressed in a
phenotype.
6. Continuous traits are usually controlled by multiple genes and may be influenced by the
environment.
Short Answer
7. Describe the inheritance pattern(s) of blood types.
8. When studying a newly discovered flowering plant in Costa Rica, you collect data on its petal
color in an effort to determine how this trait may be inherited. You find that 852 flowers are red,
331 are white and 389 are yellow. What are the possible inheritance patterns, and how could you
definitely conclude which of these possibilities is the true mode of inheritance?
Solution
Wild type- wild type phenotype refers to characteristics that occurs naturally in a breeding
population.
Epistasis - it refers to a phenomena when one gene’s expression is dependent on the presence of
another gene(s), called the modifier gene.
9:16
Let\'s take an example of comb varieties in chicken
We have two pure breeds : wyandotte whose phenotype is a rose comb and brahmas having the
phenotype of a pea comb, when crossed with each other, they create a completely new phenotype
of a walnut comb. Let\'s look at the ratio:
Parental cross: rose comb x pea comb
F1 : all walnut combs
F2 : 9 walnut : 3 rose: 3peas : 1 single
Hence the ratio is 9:16
Under the restrictive or nonpermissive condition conditions, conditionally lethal mutants will
die.
Conditionally lethal mutants are those which have an allele that will make the survival of the
species difficult only in a specific condition.
True. for example if a mutation in a gene gives the species a particular characterisitc which has
97%penetrance, only 97% of those with the mutation will develop that characteristic and 3 %
will not.
True. multiple genes affect continuous traits. For such complex gene interactions, the traits are
influenced by environmental factors too. For example, height and skin color.
There are four basic blood types which are A, B, AB and O and together with the Rh factor,
these can be +ve or -ve.
A and B are dominant, while O is recessive.
Blood type
A
B
O
A
A
AB
A
B
AB
B
B
O
A
B
O
For Rh factor, Rh (+)ve is dominant.
So if the any one or both parents have Rh (+)ve factor, the progeny will be Rh(+)ve.
If both parents are Rh(-)ve, the progeny will be Rh (-)ve
Father
Mother
D
D
d
Dd
Dd
d
Dd
Dd
100% Rh (+)ve children
Father
Mother
D
d
d
Dd
dd
d
Dd
dd
50% Rh(+)ve children
Red: 852
White: 331
Yellow:389
According to the given data, red is dominant and white is recessive and yellow is a result of
incomplete dominance of both white and red phenotype.
It can\'t be codominance, because codominance involves both phenotypes being expressed in
di.
Please also provide an explanation for the chosen answer Q2.pdf
Please also provide an explanation for the chosen answer.
Q24.3. Within a group of mutants (genetically related organisms with slightly different genotypes)
with the same overt phenotype, DN/ sequencing studies mapping the location of the mutations
determined that mutations in different organisms were on different chromosomes. This indicates
that A. the same gene governs all the steps in a particular biological pathway. B. different genes
can govern different individual steps in the same biological pathway. C. different genes govern the
same step in a particular biological pathway. D. all biological pathways are governed by different
genes. E. genes do not govern steps in biological pathways. Question Q24.4. A bit of practice
reading and interpreting networks. Q24.4 In the network below we see the functional relationships
network of transcription factors, the genes encoding them, environmental factors and the genes
responsible for a complex bacterial phenotype called heterocyst formation ( hgl, hep, and nif).
Which interpretation of the figure is most reasonable? A. Calcium negatively regulates CcbP. B.
The expression of gene pats leads to an increase in the expression of hgl. C. Nitrogen limitation
"turns-on" hgl expression. D. The NtcA transcription factor can act both negatively and positively.
E. C & D.
Similar to A generalized transducing phage is used to infect wildtype prototroph.pdf (20)
Bacteriophage T2 normally infects the different E. coli strains. B an.pdf
Bacteriophage T2 normally infects the different E. coli strains. B an.pdf
Which is NOT true about alleles- Ans A- Alleles differ from each other.docx
Which is NOT true about alleles- Ans A- Alleles differ from each other.docx
Please give an explaination fir those quesions! 2 3 4 5 1- Aman with r.docx
Please give an explaination fir those quesions! 2 3 4 5 1- Aman with r.docx
1- Recessive traits are less common than dominant traits because ) B-.docx
1- Recessive traits are less common than dominant traits because ) B-.docx
Please answer all questionsDefine1. Wild type –2. Epistasis –.pdf
Please answer all questionsDefine1. Wild type –2. Epistasis –.pdf
Please also provide an explanation for the chosen answer Q2.pdf
Please also provide an explanation for the chosen answer Q2.pdf
More from ambajialuminium
A few days ago. a recall notice was issued foe frozen strawberries so.pdf
A few days ago. a recall notice was issued foe frozen strawberries sold in the Portland area
because several cases of hepatitis A in Wastlngton were linked to these products. Presumably,
the strawberries were elther irrigated or otherwise contaminated with water containing human
feces that harbored hepatitis A virus, This is an example of which trpe of microblal sourced for
foodborne illneis? A food animal - infection or colonltation during its lifetime None of the other
four anwers are correct Contamination by human or animal feces during growing. harvesting,
washing, tramport, or storme Contamination by human microbioda or pathogens durine handling
\& preparation Contamination by naturaliy occurring envirormental organisms from soil or other
sources.
A female is heterozygous for an X-linked recessive trait. Which of th.pdf
A female is heterozygous for an X-linked recessive trait. Which of the following statements is
true? She may or may not be affected because some of her cells express one allele of the
causative gene, while other cells express the other allele. She is unaffected because all of her
cells express the common allele of the causative gene. She is affected because all of her cells
express the disease allele of the causative gene. She is unaffected because all of her cells express
both alleles of the causative gene..
A farmer cut trees on his property and completed the table of tree he.pdf
A farmer cut trees on his property and completed the table of tree heights. If she knows the
SD=5.6, find each 2-decimal number for a 94% interval The alpha value The value for Z/2 The
small number in the confidence interval The large number in the confidence interval The margin
of error.
A eukaryotic pathogen that causes diarrhea is Multiple Choice Vibri.pdf
A eukaryotic pathogen that causes diarrhea is Multiple Choice Vibrio cholera All of the above
Giardia lamblia Trypanosoma species
A simple stain Multiple Choice can color the background surrounding the cells. all of the above.
require the use of a stain that contains a chromophore and an auxochrome. can color the cells
directly..
A definition of a career, as per Greenhaus and Kossek, is all the job.pdf
A definition of a career, as per Greenhaus and Kossek, is all the jobs held over a period of time a
pattern or sequence of work experiences that evolve over time... life course a sequence of paid
positions, including internships, held in different organizations the sum of all paid, unpaid and
volunteer work experiences
The value an employee brings to an organization is based on the importance of the employee to
long-term sustainability of the firm how much the employee contributes to revenue generation
the extent to which the employee's work matters for the firm to achieve social goals All of the
rest
Research on organizational careers has included all the following EXCEPT All of the rest have
been studied Employee development (includes skills training) Performance evaluation
(assessment of workplace contributions) Employee retention (why employees stay or leave)
According to theory, Vocational Identity is different for women and men has significant impact
on job performance is based on the job that an individual did refers to the kinds of work an
individual likes and dislikes
Holland identified six types of vocational personalities. These were Rational, Intuitive, Artistic,
Social, Business, Conformist Realistic, Financial, Community oriented, Artistic, Social,
Conventional Realistic, Investigative, Artistic, Social, Enterprising, Conventional Retail,
Financial, Investigative, Social, Business, Conventional
Which one of these is Gottfredson's idea about career choice by individuals? Individuals follow
careers that family and friends have followed Individuals do various jobs and a career is a
process of developing a self-concept Individuals choose jobs they feel they have the ability and
competence to do Individuals make career decisions based on what they understand about each
career
According to Rodrigues et al., an individual's career orientation, which reflects their preferences,
is influenced by all the following ExCEPT social background commitment to organizational jobs
the individual's disposition (inherent qualities) labor market conditions (kinds of jobs available)
Aspects related to job performance such as skills and knowledge is referred to as Human capital
Intellectual capital Social capital Psychological capital.
A data set follows a normal distribution. The mean of the data set is.pdf
A data set follows a normal distribution. The mean of the data set is 72 and the standard
deviation of the data set is 1. Find a z-score for a data value of 73 from the set. Round your
answer to two decimal places..
A counselor requested to have every Tuesday and Wednesday off of work.pdf
A counselor requested to have every Tuesday and Wednesday off of work so he can attend
church. KCL requires its counselors to work four afternoons during the work week (M-F) and
every-other Saturday. KCL is closed on Sundays. The site manager says that the location would
need to increase another counselor's hours or hire an additional part-time counselor to
accommodate the request. Is KCL legally obligated to accommodate the counselor's request?
Explain your answer..
A contribution format income statement of Chihuahua Company reported .pdf
A contribution format income statement of Chihuahua Company reported the following data for
the year: If the contribution margin ratio is 40%, how much is the variable cost per unit? (Do not
round intermediate calculations. Round the final answer to the nearest two decimal places)..
A corporation must appoint a president, chief executive officer.pdf
A corporation must appoint a president, chief executive officer (CEO), chief operating oticer (B)
fire 12 qualified candidates. officer (CFO). It must also appoint a planning committee with four
difterent merticers can also serve on the committee. Complete parts (a) through (c) below. a.
How many different ways can the officers be appointed? There are different ways to appoint the
officers. b. How many different ways can the committee be appointed? There are different ways
to appoint the committee. c. What is the probability of randomly selecting the committee
members and getting the four youngest of the qualified candidates? P(getting the four youngest
of the qualified candidates) = (Type an integer or a simplified fraction.).
A continuous random variable x is uniformly distributed over the inte.pdf
A continuous random variable x is uniformly distributed over the interval between 2 and 7 . The
density function of this uniform probability distribution is given in the figure below: What is the
probability that x will take on values above 7 ? 0 0.6 0.2 None of the above.
A condensation reaction joins 2 smaller molecules to make more comple.pdf
A condensation reaction joins 2 smaller molecules to make more complex molecule while
femoving water split larger molecule into 2 simpler molecules through addition of water both a
and b none of the above.
A local face mask manufacturer that puts local artists and local spor.pdf
A local face mask manufacturer that puts local artists and local sports team and tourist images
on face masks that they sell through local stores has done well, but its biggest problem has been
profitability due to high transportation, manufacturing costs, and supply chain costs. As part of
its business model generation, it would be best served by being More fact-driven Usage-fee
based More cost-driven Less revenue-driven.
A low regression R2 means that (Note ESS Explained Sum of Squares..pdf
A low regression R2 means that: (Note: ESS: Explained Sum of Squares. TSS: Total Sum of
Squares. SSR : Sum of Squared Residuals) A. the regression is bad. B. the Sum of Squared
Residuals (SSR) is low relative to the total variation in Y. C. tells you what the other factors
influencing the dependent variable are. D. there are other important factors that influence the
dependent variable..
A computer selects a number X from 5 to 13 randomly and uniformly. Ro.pdf
A computer selects a number X from 5 to 13 randomly and uniformly. Round all answers to 4
decimal places where possible. a. What is the distribution of X?X Ui b. Suppose that the
computer randomly picks 38 such numbers. What is the distribution of x for this selection of
numbers. xN(, c. What is the probability that the average of 38 numbers will be less than 8.4 ?.
A linear fragramming computer pac.pdf
A linear fragramming computer package is needed. inchude televisidn, radio, and online.
Audience estimates, costs, and maximum media usage limitations are as thown. the total number
of advertisements authorized. (a) If the promotional budget is limited to $27,400, how mamy
commereial messgges should be run on each medium to maximize total a0dience contact?
Television
the race mumber of advertisements authorised. (a). If the protnotional budget is limked to
327,400 , how many commercial messages should be fun on each medium to maximiae tokal
audence contact? televisise Factie Online What is the allocotion of the buspet among the three
media, and what is the tocal audience recched? Television Budget Hasio Budget Oniat budget
Focal Audience B) By how moch would aublence contact increase if an extra 1100 were
allocated o the prometional budget? (Round your anawer to the Rearest whele number).
A large File F is transformed from host A to host B. There are N La.pdf
A large File F is transformed from host A to host B. There are N Layer 3 devices between them.
Assuming the links are uncongested. if the size of each segment was S and the size of the header
was h and the transmission rate for each link is R. write the equation (formula) of the total delay
assuming that the propagation delay for each link is P& assuming each Layer 3 device uses
store-and-forward packet switching NOTE: briefly verify your answers (showing the results only
is not acceptable).
A key reason that there are various acceptable deprecia.pdf
A key reason that there are various acceptable depreciation methods is different assets have
different expected usage patterns. some methods are too complicated to calculate. to make it
easier to calculate corporate income taxes, to account for assets with indefinite lives. eTextbook
and Media Assistance Us.
A label heading with the teid Inwentory Tracke, The boef a bourd to.pdf
A label heading with the teid "Inwentory Tracke", The boef a bourd to the top of the sereen and
remains centred, tegardless of screen width Labelfreutfield aairs to be used for data entry by the
woer, There is bepe pat of controh for each field inpat. The fabels contain the String captions
The ADO button. This button has the hot-key "A" and ir used to elear the inout fieliss so. that the
user can easily type inputs for a ncw lnvestory abject The SAVE button. This button has the hot-
key "S" and in wased to stoe the curnent inpe: values as an Imventory object to the inventorytist.
The inguts entened by the wier ar validated before the ioventory object is added to the
intentorybist any errors are displayed in Alert dialog bowes. The ORDens button. This buaton
har the hot -hey " 0 " and, when rliched, will direldy a liar. of Inventory objects from the
lewventorylist that need to be re-ordered fqch crepp). The list of items is displayod in the
TextAeca below the input area. The EXIT button. This button is used lo exit the prografs upon
confirmition frum the usef. The input fields and butons are laid out in the 7inprat Acea", in a
Geidsene conesiner (instead of AnchoePane, details later). The Messages LabeL. This labef is at
the bottom of the Lie, at is used for? - It displays a message "No items to list. Add some," In red
when the aser cliok the CRDER button while the inventoryList is empty. - It disolans a messape
"No items to re-order, when the user dicki okctas and there
must contain a niearinglut titfe in the tothe bar out and displared exactly as shown in the screen s.
The UI's Functionality Use event handlers to add control functionaldiss as followp. When AD0
Button is cinciecioe tot i Al text figlds emplico of atd text. Dependingon how you deal with the
mensare label, wou might ako need 1 "error" from the message label at this point arid empty its
text. When SAVE Button is clicked or Hot keyts is used. Construct a new Inventory object and
use the mutator methods to ass inputs to each lield Handie any error display an Alert dualog bor
for the field that has the error show one error message at a time-Showing several error dialogs at
once is cumbersome for the user. Alert dialogs appear with irtuentory error medsac sinput is
invalid. If no exceptions occur: Add the new inventory itent to the lfwentorylist. When QRDers
Button is clicked or Hot hey 0 is used:
Diplay only thote ecem from the inveriorylite that need re destrice battom messine tabel. ordered
by diding those inventory objects to the fexshuma on a saparate lise the bottom message label
Exit button Lter says Yes, ext the program. if the sier sen no, de nothing. Tipt and Hints property
of thin beon to ceecter", thesadd a Labet.
the fow procedure for al othir buthom poperten tabl and set at Prefieigie 10200.
A hypothetical compound has the chemical formula C55H72O5�N4. The.pdf
A hypothetical compound has the chemical formula C55H72O5N4. The number of atoms in this
molecule is . The number of elements in this molecule is and their names are and All names must
be spelled correctly in lower case.
Hydrophobic interactions are important (check all that are correct) To stabilize ribosomes To
exclude water from bonds in tertiary structure To stabilite enzyme structure For DNA replication.
A high school principal wanted to know how the teachers at her school.pdf
A high school principal wanted to know how the teachers at her school felt about early dismissal
for Homecoming. She put the names of the 114 faculty in a hat and randomly selected 30 of the
names. She gave questionnaires to those 30 people asking whether they agreed or disagreed with
the following statement: "Valuable learning time should not be sacrificed for extracurricular
social activities." The questionnaires were filled out anonymously. Her conclusion was that 80%
of the faculty were opposed to early dismissal for Homecoming. What is the biggest flaw in the
study? Confounding variables The setting may discourage honest responses The wording of the
question Selection bias Participation bias.
More from ambajialuminium (20)
A few days ago. a recall notice was issued foe frozen strawberries so.pdf
A few days ago. a recall notice was issued foe frozen strawberries so.pdf
A female is heterozygous for an X-linked recessive trait. Which of th.pdf
A female is heterozygous for an X-linked recessive trait. Which of th.pdf
A farmer cut trees on his property and completed the table of tree he.pdf
A farmer cut trees on his property and completed the table of tree he.pdf
A eukaryotic pathogen that causes diarrhea is Multiple Choice Vibri.pdf
A eukaryotic pathogen that causes diarrhea is Multiple Choice Vibri.pdf
A definition of a career, as per Greenhaus and Kossek, is all the job.pdf
A definition of a career, as per Greenhaus and Kossek, is all the job.pdf
A data set follows a normal distribution. The mean of the data set is.pdf
A data set follows a normal distribution. The mean of the data set is.pdf
A counselor requested to have every Tuesday and Wednesday off of work.pdf
A counselor requested to have every Tuesday and Wednesday off of work.pdf
A contribution format income statement of Chihuahua Company reported .pdf
A contribution format income statement of Chihuahua Company reported .pdf
A corporation must appoint a president, chief executive officer.pdf
A corporation must appoint a president, chief executive officer.pdf
A continuous random variable x is uniformly distributed over the inte.pdf
A continuous random variable x is uniformly distributed over the inte.pdf
A condensation reaction joins 2 smaller molecules to make more comple.pdf
A condensation reaction joins 2 smaller molecules to make more comple.pdf
A local face mask manufacturer that puts local artists and local spor.pdf
A local face mask manufacturer that puts local artists and local spor.pdf
A low regression R2 means that (Note ESS Explained Sum of Squares..pdf
A low regression R2 means that (Note ESS Explained Sum of Squares..pdf
A computer selects a number X from 5 to 13 randomly and uniformly. Ro.pdf
A computer selects a number X from 5 to 13 randomly and uniformly. Ro.pdf
A large File F is transformed from host A to host B. There are N La.pdf
A large File F is transformed from host A to host B. There are N La.pdf
A key reason that there are various acceptable deprecia.pdf
A key reason that there are various acceptable deprecia.pdf
A label heading with the teid Inwentory Tracke, The boef a bourd to.pdf
A label heading with the teid Inwentory Tracke, The boef a bourd to.pdf
A hypothetical compound has the chemical formula C55H72O5�N4. The.pdf
A hypothetical compound has the chemical formula C55H72O5�N4. The.pdf
A high school principal wanted to know how the teachers at her school.pdf
A high school principal wanted to know how the teachers at her school.pdf
Recently uploaded
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is prepared for master's students (MIFB & MIBS) UUM. May it be useful to all.Polish students' mobility in the Czech Republic
Polish students mobility to the Czech Republic within eTwinning project "Medieval adventures with Marco Polo"
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
Synthetic Fiber Construction in lab .pptx
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
A Strategic Approach: GenAI in Education
Artificial Intelligence (AI) technologies such as Generative AI, Image Generators and Large Language Models have had a dramatic impact on teaching, learning and assessment over the past 18 months. The most immediate threat AI posed was to Academic Integrity with Higher Education Institutes (HEIs) focusing their efforts on combating the use of GenAI in assessment. Guidelines were developed for staff and students, policies put in place too. Innovative educators have forged paths in the use of Generative AI for teaching, learning and assessments leading to pockets of transformation springing up across HEIs, often with little or no top-down guidance, support or direction.
This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdf
In this webinar you will learn how your organization can access TechSoup's wide variety of product discount and donation programs. From hardware to software, we'll give you a tour of the tools available to help your nonprofit with productivity, collaboration, financial management, donor tracking, security, and more.
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
Class 11 CBSE Business Studies Project ( AIDS TO TRADE - INSURANCE)
Francesca Gottschalk - How can education support child empowerment.pptx
Francesca Gottschalk from the OECD’s Centre for Educational Research and Innovation presents at the Ask an Expert Webinar: How can education support child empowerment?
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Supporting (UKRI) OA monographs at Salford.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
1.4 modern child centered education - mahatma gandhi-2.pptx
Child centred education is an educational approach that priorities the interest, needs and abilities of the child in the learning process.
The French Revolution Class 9 Study Material pdf free download
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
The Roman Empire A Historical Colossus.pdf
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
Recently uploaded (20)
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptx
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
Digital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and Research
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdf
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdf
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
Francesca Gottschalk - How can education support child empowerment.pptx
Francesca Gottschalk - How can education support child empowerment.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
The French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free download
A generalized transducing phage is used to infect wildtype prototroph.pdf
- 1. A generalized transducing phage is used to infect wildtype prototrophic E. coli, and the lysate is used to transduce an abcderecipient. The recipient cells are plated on minimal medium supplied with the indicated compounds. The results are shown in the following table. (Note that aindicates a requirement for compound A, etc.) What can you conclude about the order of these genes? Three of the genes are closely linked and have the order bdc, while genes a and e are not closely linked to any other genes. The gene order of four of the genes is cead, but the placement of b is unknown. Genes b,c and d are linked, but their order cannot be determined. Genes a and e are not closely linked to any of the other genes. Genes a,c,d and e are closely linked, but their order cannot be determined with certainty, while gene b is not closely linked to this group.