3. Transportation technology (15 points) a. Explain both generally and with specific examples
how changes in transportation technology have affected the development of urban areas. b.
Indicate two ways in which governmental policy has influenced the shape of urbanization in the
U.S. c. Do you believe that new telecommunication and other forms of technology will make
distance an unimportant factor in economic development and, thus, make cities unimportant
economic factors? Support your answer.
Solution
Transportation enbles activity of connecting people, businesses and resources.Transportation
improvement is necessary for the economicdevelopment and transportation policies help to
support the economic objectives.it helps to improve economic efficieny. Economic efficiency
refers to the ratio total benifit to cost. Increase economic efficieny, increase productivity which
leads to economic development.
The ultimate goal of transportation is accessabilty, access the people and the company abilities
including raw material, labor, worksites, proffessional services, distrbutors etc. Increased
accessibilty means reduction in time,money, risk require recouces reaches in less time so the
productivity of a company increases.
cost saving in an organisation---Economic efficiency more output per unit of input---productivity
more goods and services produced in less cost---Ecoonomis development.
Example- if in a company a manager has to submit an assignment cost company say 10 crores
and he has to submit it with in 2 days then the manager priority is to travel by Air not by train
etc. because the loss of the company is veyr high then the cost of transportation. In transportation
priortization is imortant point to improve productivity hence economic development.
Urbanisation means the population shifted rural to urban areas and how the economy adopt the
change.Recent development of commiucation technology in US, such as broadband services ,
package express delivery services, cheap telecommunication, courier services , easy ways to
transprotation, highways development promotes people to work in the different ares of the
country.
But now days the USA government initiating suburbanisation..
Making cities more competitive the economic case for public transportTristan Wiggill
A presentation by Adv Alma Nel (Director: Legal and Policy Research: Gauteng Provincial Government) at the Transport Forum Month of Transport Celebrations 1 October 2015 hosted by University of Johannesburg. The theme for the event was: "Trends in Policy Development for Transport" and the topic for the presentation was: "Making cities more competitive The Economic Case for Public Transport."
More like this on www.transportworldafrica.co.za
Making cities more competitive the economic case for public transportTristan Wiggill
A presentation by Adv Alma Nel (Director: Legal and Policy Research: Gauteng Provincial Government) at the Transport Forum Month of Transport Celebrations 1 October 2015 hosted by University of Johannesburg. The theme for the event was: "Trends in Policy Development for Transport" and the topic for the presentation was: "Making cities more competitive The Economic Case for Public Transport."
More like this on www.transportworldafrica.co.za
Transit-oriented development (TOD): Integrating rail and commercial developme...Atkins
Atkins' technical director Jason Hutchings explores the ways in which cities across the world can gain maximum benefit from their investment in transport, commercial and civic projects through transit oriented development (TOD). TOD facilitates and encourages the use of public transport and provides alternative revenue streams for transport providers and operators, reducing their reliance on state funding for capital investment and operation/maintenance costs. It means transit systems are more popular, accessible and better connected for the commuting population, and commercial property development can be integrated and benefit from such a holistic approach to critical city centre locations. But TOD is not without its challenges. Atkins illustrates the issues and solutions across a range of international projects.
This presentation was first delivered in May 2013 at the 3rd Annual Modern Railways Conference, Singapore.
Future of transport An initial perspective - Professor Glenn Lyons, UWE, Br...Future Agenda
An initial perspective on the future of transport by Professor Glenn Lyons, Professor of Transport and Society at UWE Bristol. This is the starting point for the global future agenda discussions taking place through 2015 as part of the the futureagenda2.0 programme. www.futureagenda.org
The recent focus on how to internalize the external costs of commuting have open a frontier of researches in estimating the private cost of commuting, however, there is still the dearth of knowledge on what constitute social cost of transportation in developing countries. This study estimates the private costs of commuting in Metropolitan Lagos. Data were collected on the socio-economic characteristics of commuting households (income, wages, modal choice,
Summary of input gained from the first rounds of committee meetings and public meetings (July-September 2012) for the 2040 Regional Transportation Plan.
4) Converting data into indices is... a) used only by governments.pdfInfo489948
4) Converting data into indices is...
a) used only by governments
b) a way to show the change in the data over time
c) a way to show the data in percentage form
d) misleading if theres a sudden change in the datas trend
5) The table below reports the earnings per share of common stock for Home Dumpo Inc. for
recent years.
Solution
I have fitted a parabolic curve for the given data and found good correlation.
4) A wastewater treatment operator has been fined because the.pdfInfo489948
4) A wastewater treatment operator has been fined because the DO at a point 1 km downstream
is below the 4.5 mg/L regulation. Assuming the plant can produce a wastewater effluent with a
BODu of 10mg/L, what is the lowest DO in the wastewater? DO in wastewater must remain
above 4.5 mg/L year round. QR = 50 m3/s Qw = 15 m3/s Tw Summer 25°C R Summer 18°C
kaonaar= 0.15 d-1 (assume KBOD is the same for the river and effluent) H =1 m (assume no
change due to wastewater flow) V = 0.04 m/s (assume no change due to wastewater flow) DOR
= 6 mg/L BODww=10mg/L BODa = 5 mg/L n = 0.3 DOs @ 20. = 9.2 mg/L Downstream
Distance = 1km
Solution
wastewater
(given)
Stream Given
Mixture of WW and River
flow (m3/s)
15
50
Qmixture=50 + 15 = 65
65
Dissolved oxygen, mg/L
9.2
6
DOmixture=(9.2* 15 + 6*50)/(50 + 15)
= 6.738 mg/L
6.738
Temperature, °C
25
18
Temperature Mixture = (25 x15 + 18 x 50)/(65
19.615
BOD5 at 20°C, mg/L
10
5
BOD mixture = (10 x 15 + 5 x 50)/65
6.153
Oxygen consumption rate (K1 at
°C) (1/day)
0.15
0.15
(0.15 x 15 + 0.15 x 50)/65
0.15
Oxygen reaeration rate (K2 at °C)
(1/day)
0.83
0.7
Mixture = (.83 x15 + 0.7 x 50)/65
0.73
L = L0e-k1t
So, K1s=
K2 = 3.9 x v1/2 x [ (1.025) T-20]1/2/H3/2
K2R = 3.9 x (0.04) 1/2 x [ (1.025) 18-20]1/2/H3/2 = 0.7
K2s = 3.9 x (0.04) 1/2 x [ (1.025) 25 -20]1/2/H3/2= 0.83
Ultimate BOD= Yultimate=L0 = (5-day BOD in mixture water)/[1-exp(-K1mixture*5)]
=(6.153 mg/L)/ [1-exp(-0.15*5)] = 11.66 mg/L
For 20°C stream water temperature, equilibrium concentration of oxygen =9.17 mg/L
D0 = 9.17 mg/L-6.738 mg/L = 2.432 mg/L
Initial deficit = 2.432 mg/L
D (t=2 days) = [K1*L0]*[exp (-K1*t)-exp (-K2*t)]/ (K2-K1) + D0 exp (-K2*t)
= (0.15 x 11.66) *[exp (-0.15*13.649)-exp (-0.73*13.649)]/ (0.73- 0.15) + 2.432 exp (-
0.73*13.649)
= 0.388 mg/L
DO (2day) = 9.17- 0.388 = 8.782 mg/L
Time for critical DO deficit
(tc)= 1/ (K2-K1)*ln [(K2/K1)*(1-D0 *(K2-K1)/ (K1L0))]
= 1/ (0.73-0.15)*ln [(0.73/0.15)*(1-2.432 *(0.73-0.15)/ (0.73* 11.66 ))]
= 2.41 days
Critical DO deficit (Dc)= (K1/K2)*L0 exp (-K1*tc)
= ( 0.15/0.73) x 11.66 exp( - 0.15 x 2.41)= 1.669 mg/L
DOcritical= 9.17- 1.669 = 7.501 mg/L
wastewater
(given)
Stream Given
Mixture of WW and River
flow (m3/s)
15
50
Qmixture=50 + 15 = 65
65
Dissolved oxygen, mg/L
9.2
6
DOmixture=(9.2* 15 + 6*50)/(50 + 15)
= 6.738 mg/L
6.738
Temperature, °C
25
18
Temperature Mixture = (25 x15 + 18 x 50)/(65
19.615
BOD5 at 20°C, mg/L
10
5
BOD mixture = (10 x 15 + 5 x 50)/65
6.153
Oxygen consumption rate (K1 at
°C) (1/day)
0.15
0.15
(0.15 x 15 + 0.15 x 50)/65
0.15
Oxygen reaeration rate (K2 at °C)
(1/day)
0.83
0.7
Mixture = (.83 x15 + 0.7 x 50)/65
0.73.
More Related Content
Similar to 3. Transportation technology (15 points) a. Explain both generally an.pdf
Transit-oriented development (TOD): Integrating rail and commercial developme...Atkins
Atkins' technical director Jason Hutchings explores the ways in which cities across the world can gain maximum benefit from their investment in transport, commercial and civic projects through transit oriented development (TOD). TOD facilitates and encourages the use of public transport and provides alternative revenue streams for transport providers and operators, reducing their reliance on state funding for capital investment and operation/maintenance costs. It means transit systems are more popular, accessible and better connected for the commuting population, and commercial property development can be integrated and benefit from such a holistic approach to critical city centre locations. But TOD is not without its challenges. Atkins illustrates the issues and solutions across a range of international projects.
This presentation was first delivered in May 2013 at the 3rd Annual Modern Railways Conference, Singapore.
Future of transport An initial perspective - Professor Glenn Lyons, UWE, Br...Future Agenda
An initial perspective on the future of transport by Professor Glenn Lyons, Professor of Transport and Society at UWE Bristol. This is the starting point for the global future agenda discussions taking place through 2015 as part of the the futureagenda2.0 programme. www.futureagenda.org
The recent focus on how to internalize the external costs of commuting have open a frontier of researches in estimating the private cost of commuting, however, there is still the dearth of knowledge on what constitute social cost of transportation in developing countries. This study estimates the private costs of commuting in Metropolitan Lagos. Data were collected on the socio-economic characteristics of commuting households (income, wages, modal choice,
Summary of input gained from the first rounds of committee meetings and public meetings (July-September 2012) for the 2040 Regional Transportation Plan.
4) Converting data into indices is... a) used only by governments.pdfInfo489948
4) Converting data into indices is...
a) used only by governments
b) a way to show the change in the data over time
c) a way to show the data in percentage form
d) misleading if theres a sudden change in the datas trend
5) The table below reports the earnings per share of common stock for Home Dumpo Inc. for
recent years.
Solution
I have fitted a parabolic curve for the given data and found good correlation.
4) A wastewater treatment operator has been fined because the.pdfInfo489948
4) A wastewater treatment operator has been fined because the DO at a point 1 km downstream
is below the 4.5 mg/L regulation. Assuming the plant can produce a wastewater effluent with a
BODu of 10mg/L, what is the lowest DO in the wastewater? DO in wastewater must remain
above 4.5 mg/L year round. QR = 50 m3/s Qw = 15 m3/s Tw Summer 25°C R Summer 18°C
kaonaar= 0.15 d-1 (assume KBOD is the same for the river and effluent) H =1 m (assume no
change due to wastewater flow) V = 0.04 m/s (assume no change due to wastewater flow) DOR
= 6 mg/L BODww=10mg/L BODa = 5 mg/L n = 0.3 DOs @ 20. = 9.2 mg/L Downstream
Distance = 1km
Solution
wastewater
(given)
Stream Given
Mixture of WW and River
flow (m3/s)
15
50
Qmixture=50 + 15 = 65
65
Dissolved oxygen, mg/L
9.2
6
DOmixture=(9.2* 15 + 6*50)/(50 + 15)
= 6.738 mg/L
6.738
Temperature, °C
25
18
Temperature Mixture = (25 x15 + 18 x 50)/(65
19.615
BOD5 at 20°C, mg/L
10
5
BOD mixture = (10 x 15 + 5 x 50)/65
6.153
Oxygen consumption rate (K1 at
°C) (1/day)
0.15
0.15
(0.15 x 15 + 0.15 x 50)/65
0.15
Oxygen reaeration rate (K2 at °C)
(1/day)
0.83
0.7
Mixture = (.83 x15 + 0.7 x 50)/65
0.73
L = L0e-k1t
So, K1s=
K2 = 3.9 x v1/2 x [ (1.025) T-20]1/2/H3/2
K2R = 3.9 x (0.04) 1/2 x [ (1.025) 18-20]1/2/H3/2 = 0.7
K2s = 3.9 x (0.04) 1/2 x [ (1.025) 25 -20]1/2/H3/2= 0.83
Ultimate BOD= Yultimate=L0 = (5-day BOD in mixture water)/[1-exp(-K1mixture*5)]
=(6.153 mg/L)/ [1-exp(-0.15*5)] = 11.66 mg/L
For 20°C stream water temperature, equilibrium concentration of oxygen =9.17 mg/L
D0 = 9.17 mg/L-6.738 mg/L = 2.432 mg/L
Initial deficit = 2.432 mg/L
D (t=2 days) = [K1*L0]*[exp (-K1*t)-exp (-K2*t)]/ (K2-K1) + D0 exp (-K2*t)
= (0.15 x 11.66) *[exp (-0.15*13.649)-exp (-0.73*13.649)]/ (0.73- 0.15) + 2.432 exp (-
0.73*13.649)
= 0.388 mg/L
DO (2day) = 9.17- 0.388 = 8.782 mg/L
Time for critical DO deficit
(tc)= 1/ (K2-K1)*ln [(K2/K1)*(1-D0 *(K2-K1)/ (K1L0))]
= 1/ (0.73-0.15)*ln [(0.73/0.15)*(1-2.432 *(0.73-0.15)/ (0.73* 11.66 ))]
= 2.41 days
Critical DO deficit (Dc)= (K1/K2)*L0 exp (-K1*tc)
= ( 0.15/0.73) x 11.66 exp( - 0.15 x 2.41)= 1.669 mg/L
DOcritical= 9.17- 1.669 = 7.501 mg/L
wastewater
(given)
Stream Given
Mixture of WW and River
flow (m3/s)
15
50
Qmixture=50 + 15 = 65
65
Dissolved oxygen, mg/L
9.2
6
DOmixture=(9.2* 15 + 6*50)/(50 + 15)
= 6.738 mg/L
6.738
Temperature, °C
25
18
Temperature Mixture = (25 x15 + 18 x 50)/(65
19.615
BOD5 at 20°C, mg/L
10
5
BOD mixture = (10 x 15 + 5 x 50)/65
6.153
Oxygen consumption rate (K1 at
°C) (1/day)
0.15
0.15
(0.15 x 15 + 0.15 x 50)/65
0.15
Oxygen reaeration rate (K2 at °C)
(1/day)
0.83
0.7
Mixture = (.83 x15 + 0.7 x 50)/65
0.73.
4.63
4.15
4.76
4.70
4.65
4.52
4.70
5.06
4.42
4.51
4.24
4.52
Listed below is the rate of return for one year (reported in percent) for a sample of 12 mutual
funds that are classified as taxable money market funds.
Solution
Critical t value is (DF=11) 1.796
Sample mean is 4.5717
Sample standard deviation is 0.2405
t= (4.5717- 4.5)/.2405/12= 1.033
Do not reject the null hypothesis (that the mean rate of return is 4.5)..
4. Let TL, t 2 be a colloclion of arbitrary vcclors in R. Is span(T.pdfInfo489948
4. Let TL, t 2 be a colloclion of arbitrary vcclors in R\". Is span(TL, i2,...,im) aveclor subspace
of RA? Explain why or why not.
Solution
i dont know why the font size is too small cant even read it properly repost the
question with proper font size thanks.
4. Image and Kernel of homomorphism. Let f R S be a ring homomo.pdfInfo489948
4. Image and Kernel of homomorphism. Let f: R ? > S be a ring homomorphism. Prove that ker
(f) is an ideal of R.
Solution
Consider ker(f) as a subring of R
Let y belong to ker(f) and x belong to R.
Then f(xy)=f(x)f(y)=f(x)0=0
Thus, f(xy)=0 that is xy belongs to ker(f)
Hence, ker(f) is an ideal of R.
4. Find all values of z that satisfy the equation sin z = -5. Express.pdfInfo489948
4. Find all values of z that satisfy the equation sin z = -5. Express each in the form a + bi. Or,
explain why no such z exists.
Solution
If we try solving this we will get
sine inverse of (-5) =z
But as we know that sine inverse functionby definition takes the values [-1,1] Hence no such z is
defined for the above equation..
4. A steel channel made of 1040 HR is welded to a thick steel wall wi.pdfInfo489948
4. A steel channel made of 1040 HR is welded to a thick steel wall with fillet welds around the
outside of the channel only. Select the least expensive fillet that will provide a FOS of 3 for the
static load shown.
Solution
The cheapest way of welding is fillet joint which is most commonly used in welding processs.it
is mainly used for the welding of steels..
4. A f-unction f D right arrow R is a Lipschitz function if there is.pdfInfo489948
4. A f-unction f: D right arrow R is a Lipschitz function if there is a C > = 0 such that |f(x) f(y)|
Solution
a) Suppose f is Lipschitz on [a,b] and let e > 0. Set d = e/M. If P = {[xi, yi]} is any partition of
[a,b] with ||P|| < d, then ? |f(xi) - f(yi) ? ? M|xi - yi| = M||P|| < M(e/M) = e. Thus f is absolutely
continuous on [a,b].
b) If f is not Lipschitz, then are sequences {x_n} and {y_n} in [a,b] such that |f(x_n) - f(y_n)| >
n|x_n - y_n| for all n ? 1. Thus |f(x_n) - f(y_n)|/|x_n - y_n| > n for all n ? 1. Hence lim sup |f(x_n)
- f(y_n)|/|x_n - y_n| = ? and lim inf |f(x_n) - f(y_n)|/|x_n - y_n| = ?. This the one sided derivatives
of f are not bounded..
3. Use the compound interest formulas A F 1+ and A Pe to find the acc.pdfInfo489948
3. Use the compound interest formulas A F 1+ and A Pe to find the accumulated value of an
investment of S12,850 for 8 years at an interest rate of 6 iftie money is... a. Compounded
Quarterly b. compounded Continuously
Solution
A=P[1+(R/N)]^(NT) P=12850 $ T=8 YRS R=6.5%=0.065 a).
3. Use the compound interest formulas A=P(1+rn)^m and A= Pe^rt to fi.pdfInfo489948
3. Use the compound interest formulas A=P(1+r/n)^m and A= Pe^rt to find the accumulated
value of an investment of $12,850 for 8 years at an interest rate of 6.5% if the money is a.
Compounded Quarterly b. Compounded Continuously
Solution
A=P[1+(R/N)]^(NT) P=12850 $ T=8 YRS R=6.5%=0.065 a).
3. The number N of bacteria present in a culture at time t, in ho.pdfInfo489948
3. The number N of bacteria present in a culture at time t, in hours, obeys the law exponential
growth N(t) = 500e^0.02t a) How many bacteria are there at t = 0 hours? b) When will the
number of bacteria triple?
Solution
put t=0
N(0)= 500e0= 500
bacteria triple
N(t) = 500*3 = 1500
1500=500e0.02t
3=e0.02t
ln3=0.02t
t = ln3*50
=50ln3.
3. Suppose for f(z) holomorphic C there are constants a, b, e 0 Pr.pdfInfo489948
3. Suppose for f(z) holomorphic C there are constants a, b, e > 0: Prove that f is a polynomial of
degree n less than equal to c .
Solution
A holomorphic function is a complex-valued function of one or more complex variables that is
complex differentiable in a neighborhood of every point in its domain.
Hence f(z) is holomorphic means
f\'(z) exists for all z
2x= z+z bar and 2iy = z-z bar
f(z,zbar) = =?m?0,n?0amnzmz.
3. Joe is considering pursuing an MBA degree. He has applied to t.pdfInfo489948
3. Joe is considering pursuing an MBA degree. He has applied to two different universities. The
acceptance rate for applicants with similar qualifications is 25% for University A and 40% for
University B.
What is the probability that Joe will not be accepted at either university? (Points : 4)
0.75
0.45
0.90
0.65
0.60
Solution
Given P(A)=0.25, P(B)=0.4 So the probability is P(A\' and B\') = P(A\')*P(B\')
=[1-P(A)]*[1-P(B)] =(1-0.25)*(1-0.4) =0.45 Answer:0.45.
3. Let On be the set of odd permutations in Sn. Is On a subgroup .pdfInfo489948
3. Let On be the set of odd permutations in Sn. Is On a subgroup?
Solution
No, On is not a subgroup..
to see that the odd permutations don\'t form a subgroup of Sn is a bit easier to resolve.
Recall that any subgroup of Sn has the same identity element as the identity element in Sn. But
since the identity element in Sn is not an odd permutation (a result we saw in class), it follows
that
the collection of odd permutations cannot be a subgroup of Sn. (One could also argue that the
odd
elements aren\'t closed under the group operation.).
3. (4 points) Consider the function (in the domain {z i Solut.pdfInfo489948
3. (4 points) Consider the function (in the domain {|z ? i|
Solution
Consider f(z)
It got a denominator of 1+(z-i)2
Equate to 0 the denominator to get singular points
(z-i)2 =-1
Take square root
z-i =i, -i
z=2i or 0
As |z-i|<1 we can expand f(z) by binomial series
f(z) = 1-(z-i)2+(z-i)4+...+(-1)n(z-i)2n+...
As odd powers are 0 we have
derivative of f^m(z) =0 for m = odd
For n even f\"m(z) = (-1)n(2n)(2n-1)....(1)(x2n-2n)
= (-1)n(2n)!
Proved..
3. Find currents (values and directions) in all resistors of the circ.pdfInfo489948
3. Find currents (values and directions) in all resistors of the circuit given below. Find total
electric power developing in this circuit Neglect internal resistances of the batteries.
Solution
As all the Voltage sources are DC (Batteries) there by the capacitor acts as short circuit .
I1 = Current through R1 =E1-E2)/R1 = (6-3)/5 = 3/5 Amps (direction from E1 to E2)
I2= Current Throuh R3 = E2/R3 = 3/4 Amps (direction from Top to bottom)
I3 = Current Through R2 = E3-E2)/R2 = (5-3)/5 = 2/5 Amps (direction from E3 to E2)
Power delivered = (I1*E1) + (E3*I3) =(3/5)*6 + (2/5)*5 = 28/5 Watts.
3. Assume that the DS register contains 0100 and register SI contains.pdfInfo489948
3. Assume that the DS register contains 0100 and register SI contains 0020. What is the result of
following instruction LES DI, [SI] Where the content of memory Location is as follows:
Solution
the command LES DI , [SI] does the following:
it takes the pointer of SI , i.e the address of the memory location SI and breaks it into lower bits
and upper bits.
then the lower bits are stored in DI and the upper bits are stored in ES.
so address of SI is 1027 .
lower bit is 27 and upper bit is 10.
27 will be stored in DI . and 10 will be saved in ES.
now DI is the lower bit of the register DS.
as it is said initially DS 0100 so, initially DI is 00.
which is changed to 27.
now DS is 0127..
2a Briefly describe the 1st law of thermodynamics. You can use either.pdfInfo489948
2a Briefly describe the 1st law of thermodynamics. You can use either plain language or
equations with short explanation. Figures can also be used if necessary. (2b) Please demonstrate
that the unit of the specific kinetic energy 1/2 v^2 (where V is velocity with unit s /m) is Joule /
kg.
Solution.
3 (a) calculate thy potential at point P located a distance z above .pdfInfo489948
3 (a) calculate thy potential at point P located a distance z above the center of a charged disk of
radius a and surface charge density p, Coulombs per square meter. Please show all work An
integral that you may need is The elemental area in cylindrical coordinates is dA = (b) Calculate
the electric field at P. Use back of page if necessary
Solution
function [Ef] = Loop_Ef() %(Main M-File function)
clc, clear all, close all
u.N1 = 1e21; %This is the number of states
u.NA = 1e15; %This is the number of acceptors
u.ND = 0; %This is the number of donors
u.Z1 = 281.73e19; %This term in front of the square root of the energy (this contains mass of
electron)
u.Z2 = 757.989e19; %This is the mass of hole
u.Eg = 1.12/2; %This is the energy gap
u.a = 0.0259;
%u.rat_a = 2 %scaling factor that modifies the steepness of the oxide exponential density of
states
u.es = 11.9 * 8.854187817e-14; %permittivity measured C / cm * V
u.qe = 1.602e-19; %This is the value of charge
u.psi_0_range = linspace(-0.4, 1, 160)\'; %This defines the range of Psi_0
u.display = true; %psi is in Volts Not ev?
%%
%ratN_range = 1e-2; ratS_range = [ 0.5: 0.2: 2];
ratN_range = 1; ratS_range = 1; %This doesn’t matter for Parabolic DOS
for iN = 1 : length(ratN_range)
for iS = 1 : length(ratS_range)
u.ratN = ratN_range(iN);
u.ratS = ratS_range(iS);
u.N2 = u.ratN * u.N1;
try
% Ef_(iN,iS) = Calculate_Ef(u); %Here its calculating the f_function
Ef_(iN,iS) = -0.356324 %REMOVE-TESTING
u.Ef_ = Ef_(iN,iS); %Here Ef equals
u.Q = Calculate_El(u);%Here is calculating the charge
DiffQ(u);
catch
Ef_(iN,iS) = NaN; %If there is nothing then NaN
end
end
end
clf,
plot(u.psi_0_range, u.Q) %Its plotting the graph
u.Ef_all = Ef_;
save \'u.mat\' %It saves all the data in u.file
save \'Ef_.dat\' Ef_ -ascii %Exports the data of Ef as ascii
keyboard %This command gives the control to the user
end
%================================================
function [Ef_] = Calculate_Ef(u)
clc
time = cputime;
%rescale volumes for numerical stability
u.Nscale = u.N1 ^ 2;
Nscale = u.Nscale;
u.N1 = u.N1 / Nscale;
u.N2 = u.N2 / Nscale;
u.Z1 = u.Z1 / Nscale;
u.Z2 = u.Z2 / Nscale;
%get rid of the u.\'\'
N1 = u.N1; N2 = u.N2;
Z1 = u.Z1; Z2 = u.Z2;
Eg = u.Eg;
a = u.a;
NA = u.NA/Nscale; ND = u.ND/Nscale;
P_1 = @(E) Z1.*sqrt(-Eg-E); %This is the parabolic function(Valance band)
P_2 = @(E) Z2.*sqrt(E-Eg); %This is the parabolic function (Conduction band)
Fn = @(E,Ef) 1 ./ ( exp((E-Ef)/a) ); %This is the Fermi-dirac for electrons
Fp = @(E,Ef) 1 ./ ( exp((Ef-E)/a) ); %This is the Fermi-dirac for holes
dp = @(E,Ef) P_1(E) .* Fp(E,Ef); %the integrands
dn = @(E,Ef) P_2(E) .* Fn(E,Ef);
p = @(Ef) Nscale * (IntegrateInf_p( @(E) dp(E,Ef), u ) + ND); %define our functions p & n
(Ef)
n = @(Ef) Nscale * (IntegrateInf_n( @(E) dn(E,Ef), u ) + NA);
%%we need to make sure that multiplication/division with Nscale is consistent all the way
through to DiffQ
Ef_ = Solve_Ef(-0.5, p, n); %Ef* is obtained here
fprintf(\'The value Ef*= %f, gives equal val.
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
A review of the growth of the Israel Genealogy Research Association Database Collection for the last 12 months. Our collection is now passed the 3 million mark and still growing. See which archives have contributed the most. See the different types of records we have, and which years have had records added. You can also see what we have for the future.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
A workshop hosted by the South African Journal of Science aimed at postgraduate students and early career researchers with little or no experience in writing and publishing journal articles.
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...Levi Shapiro
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
2024.06.01 Introducing a competency framework for languag learning materials ...
3. Transportation technology (15 points) a. Explain both generally an.pdf
1. 3. Transportation technology (15 points) a. Explain both generally and with specific examples
how changes in transportation technology have affected the development of urban areas. b.
Indicate two ways in which governmental policy has influenced the shape of urbanization in the
U.S. c. Do you believe that new telecommunication and other forms of technology will make
distance an unimportant factor in economic development and, thus, make cities unimportant
economic factors? Support your answer.
Solution
Transportation enbles activity of connecting people, businesses and resources.Transportation
improvement is necessary for the economicdevelopment and transportation policies help to
support the economic objectives.it helps to improve economic efficieny. Economic efficiency
refers to the ratio total benifit to cost. Increase economic efficieny, increase productivity which
leads to economic development.
The ultimate goal of transportation is accessabilty, access the people and the company abilities
including raw material, labor, worksites, proffessional services, distrbutors etc. Increased
accessibilty means reduction in time,money, risk require recouces reaches in less time so the
productivity of a company increases.
cost saving in an organisation---Economic efficiency more output per unit of input---productivity
more goods and services produced in less cost---Ecoonomis development.
Example- if in a company a manager has to submit an assignment cost company say 10 crores
and he has to submit it with in 2 days then the manager priority is to travel by Air not by train
etc. because the loss of the company is veyr high then the cost of transportation. In transportation
priortization is imortant point to improve productivity hence economic development.
Urbanisation means the population shifted rural to urban areas and how the economy adopt the
change.Recent development of commiucation technology in US, such as broadband services ,
package express delivery services, cheap telecommunication, courier services , easy ways to
transprotation, highways development promotes people to work in the different ares of the
country.
But now days the USA government initiating suburbanisation.
