4. Image and Kernel of homomorphism. Let f R S be a ring homomo.pdf
•
0 likes•4 views
4. Image and Kernel of homomorphism. Let f: R ? > S be a ring homomorphism. Prove that ker (f) is an ideal of R. Solution Consider ker(f) as a subring of R Let y belong to ker(f) and x belong to R. Then f(xy)=f(x)f(y)=f(x)0=0 Thus, f(xy)=0 that is xy belongs to ker(f) Hence, ker(f) is an ideal of R.
Report
Share
Report
Share
Download to read offline
Recommended
4) Converting data into indices is... a) used only by governments.pdf
4) Converting data into indices is...
a) used only by governments
b) a way to show the change in the data over time
c) a way to show the data in percentage form
d) misleading if theres a sudden change in the datas trend
5) The table below reports the earnings per share of common stock for Home Dumpo Inc. for
recent years.
Solution
I have fitted a parabolic curve for the given data and found good correlation.
4) A wastewater treatment operator has been fined because the.pdf
4) A wastewater treatment operator has been fined because the DO at a point 1 km downstream
is below the 4.5 mg/L regulation. Assuming the plant can produce a wastewater effluent with a
BODu of 10mg/L, what is the lowest DO in the wastewater? DO in wastewater must remain
above 4.5 mg/L year round. QR = 50 m3/s Qw = 15 m3/s Tw Summer 25°C R Summer 18°C
kaonaar= 0.15 d-1 (assume KBOD is the same for the river and effluent) H =1 m (assume no
change due to wastewater flow) V = 0.04 m/s (assume no change due to wastewater flow) DOR
= 6 mg/L BODww=10mg/L BODa = 5 mg/L n = 0.3 DOs @ 20. = 9.2 mg/L Downstream
Distance = 1km
Solution
wastewater
(given)
Stream Given
Mixture of WW and River
flow (m3/s)
15
50
Qmixture=50 + 15 = 65
65
Dissolved oxygen, mg/L
9.2
6
DOmixture=(9.2* 15 + 6*50)/(50 + 15)
= 6.738 mg/L
6.738
Temperature, °C
25
18
Temperature Mixture = (25 x15 + 18 x 50)/(65
19.615
BOD5 at 20°C, mg/L
10
5
BOD mixture = (10 x 15 + 5 x 50)/65
6.153
Oxygen consumption rate (K1 at
°C) (1/day)
0.15
0.15
(0.15 x 15 + 0.15 x 50)/65
0.15
Oxygen reaeration rate (K2 at °C)
(1/day)
0.83
0.7
Mixture = (.83 x15 + 0.7 x 50)/65
0.73
L = L0e-k1t
So, K1s=
K2 = 3.9 x v1/2 x [ (1.025) T-20]1/2/H3/2
K2R = 3.9 x (0.04) 1/2 x [ (1.025) 18-20]1/2/H3/2 = 0.7
K2s = 3.9 x (0.04) 1/2 x [ (1.025) 25 -20]1/2/H3/2= 0.83
Ultimate BOD= Yultimate=L0 = (5-day BOD in mixture water)/[1-exp(-K1mixture*5)]
=(6.153 mg/L)/ [1-exp(-0.15*5)] = 11.66 mg/L
For 20°C stream water temperature, equilibrium concentration of oxygen =9.17 mg/L
D0 = 9.17 mg/L-6.738 mg/L = 2.432 mg/L
Initial deficit = 2.432 mg/L
D (t=2 days) = [K1*L0]*[exp (-K1*t)-exp (-K2*t)]/ (K2-K1) + D0 exp (-K2*t)
= (0.15 x 11.66) *[exp (-0.15*13.649)-exp (-0.73*13.649)]/ (0.73- 0.15) + 2.432 exp (-
0.73*13.649)
= 0.388 mg/L
DO (2day) = 9.17- 0.388 = 8.782 mg/L
Time for critical DO deficit
(tc)= 1/ (K2-K1)*ln [(K2/K1)*(1-D0 *(K2-K1)/ (K1L0))]
= 1/ (0.73-0.15)*ln [(0.73/0.15)*(1-2.432 *(0.73-0.15)/ (0.73* 11.66 ))]
= 2.41 days
Critical DO deficit (Dc)= (K1/K2)*L0 exp (-K1*tc)
= ( 0.15/0.73) x 11.66 exp( - 0.15 x 2.41)= 1.669 mg/L
DOcritical= 9.17- 1.669 = 7.501 mg/L
wastewater
(given)
Stream Given
Mixture of WW and River
flow (m3/s)
15
50
Qmixture=50 + 15 = 65
65
Dissolved oxygen, mg/L
9.2
6
DOmixture=(9.2* 15 + 6*50)/(50 + 15)
= 6.738 mg/L
6.738
Temperature, °C
25
18
Temperature Mixture = (25 x15 + 18 x 50)/(65
19.615
BOD5 at 20°C, mg/L
10
5
BOD mixture = (10 x 15 + 5 x 50)/65
6.153
Oxygen consumption rate (K1 at
°C) (1/day)
0.15
0.15
(0.15 x 15 + 0.15 x 50)/65
0.15
Oxygen reaeration rate (K2 at °C)
(1/day)
0.83
0.7
Mixture = (.83 x15 + 0.7 x 50)/65
0.73.
4.634.154.764.704.654.524.705.064.424.514.2.pdf
4.63
4.15
4.76
4.70
4.65
4.52
4.70
5.06
4.42
4.51
4.24
4.52
Listed below is the rate of return for one year (reported in percent) for a sample of 12 mutual
funds that are classified as taxable money market funds.
Solution
Critical t value is (DF=11) 1.796
Sample mean is 4.5717
Sample standard deviation is 0.2405
t= (4.5717- 4.5)/.2405/12= 1.033
Do not reject the null hypothesis (that the mean rate of return is 4.5)..
4. Let TL, t 2 be a colloclion of arbitrary vcclors in R. Is span(T.pdf
4. Let TL, t 2 be a colloclion of arbitrary vcclors in R\". Is span(TL, i2,...,im) aveclor subspace
of RA? Explain why or why not.
Solution
i dont know why the font size is too small cant even read it properly repost the
question with proper font size thanks.
4. Find all values of z that satisfy the equation sin z = -5. Express.pdf
4. Find all values of z that satisfy the equation sin z = -5. Express each in the form a + bi. Or,
explain why no such z exists.
Solution
If we try solving this we will get
sine inverse of (-5) =z
But as we know that sine inverse functionby definition takes the values [-1,1] Hence no such z is
defined for the above equation..
4. A steel channel made of 1040 HR is welded to a thick steel wall wi.pdf
4. A steel channel made of 1040 HR is welded to a thick steel wall with fillet welds around the
outside of the channel only. Select the least expensive fillet that will provide a FOS of 3 for the
static load shown.
Solution
The cheapest way of welding is fillet joint which is most commonly used in welding processs.it
is mainly used for the welding of steels..
4. A f-unction f D right arrow R is a Lipschitz function if there is.pdf
4. A f-unction f: D right arrow R is a Lipschitz function if there is a C > = 0 such that |f(x) f(y)|
Solution
a) Suppose f is Lipschitz on [a,b] and let e > 0. Set d = e/M. If P = {[xi, yi]} is any partition of
[a,b] with ||P|| < d, then ? |f(xi) - f(yi) ? ? M|xi - yi| = M||P|| < M(e/M) = e. Thus f is absolutely
continuous on [a,b].
b) If f is not Lipschitz, then are sequences {x_n} and {y_n} in [a,b] such that |f(x_n) - f(y_n)| >
n|x_n - y_n| for all n ? 1. Thus |f(x_n) - f(y_n)|/|x_n - y_n| > n for all n ? 1. Hence lim sup |f(x_n)
- f(y_n)|/|x_n - y_n| = ? and lim inf |f(x_n) - f(y_n)|/|x_n - y_n| = ?. This the one sided derivatives
of f are not bounded..
3. Use the compound interest formulas A F 1+ and A Pe to find the acc.pdf
3. Use the compound interest formulas A F 1+ and A Pe to find the accumulated value of an
investment of S12,850 for 8 years at an interest rate of 6 iftie money is... a. Compounded
Quarterly b. compounded Continuously
Solution
A=P[1+(R/N)]^(NT) P=12850 $ T=8 YRS R=6.5%=0.065 a).
Recommended
4) Converting data into indices is... a) used only by governments.pdf
4) Converting data into indices is...
a) used only by governments
b) a way to show the change in the data over time
c) a way to show the data in percentage form
d) misleading if theres a sudden change in the datas trend
5) The table below reports the earnings per share of common stock for Home Dumpo Inc. for
recent years.
Solution
I have fitted a parabolic curve for the given data and found good correlation.
4) A wastewater treatment operator has been fined because the.pdf
4) A wastewater treatment operator has been fined because the DO at a point 1 km downstream
is below the 4.5 mg/L regulation. Assuming the plant can produce a wastewater effluent with a
BODu of 10mg/L, what is the lowest DO in the wastewater? DO in wastewater must remain
above 4.5 mg/L year round. QR = 50 m3/s Qw = 15 m3/s Tw Summer 25°C R Summer 18°C
kaonaar= 0.15 d-1 (assume KBOD is the same for the river and effluent) H =1 m (assume no
change due to wastewater flow) V = 0.04 m/s (assume no change due to wastewater flow) DOR
= 6 mg/L BODww=10mg/L BODa = 5 mg/L n = 0.3 DOs @ 20. = 9.2 mg/L Downstream
Distance = 1km
Solution
wastewater
(given)
Stream Given
Mixture of WW and River
flow (m3/s)
15
50
Qmixture=50 + 15 = 65
65
Dissolved oxygen, mg/L
9.2
6
DOmixture=(9.2* 15 + 6*50)/(50 + 15)
= 6.738 mg/L
6.738
Temperature, °C
25
18
Temperature Mixture = (25 x15 + 18 x 50)/(65
19.615
BOD5 at 20°C, mg/L
10
5
BOD mixture = (10 x 15 + 5 x 50)/65
6.153
Oxygen consumption rate (K1 at
°C) (1/day)
0.15
0.15
(0.15 x 15 + 0.15 x 50)/65
0.15
Oxygen reaeration rate (K2 at °C)
(1/day)
0.83
0.7
Mixture = (.83 x15 + 0.7 x 50)/65
0.73
L = L0e-k1t
So, K1s=
K2 = 3.9 x v1/2 x [ (1.025) T-20]1/2/H3/2
K2R = 3.9 x (0.04) 1/2 x [ (1.025) 18-20]1/2/H3/2 = 0.7
K2s = 3.9 x (0.04) 1/2 x [ (1.025) 25 -20]1/2/H3/2= 0.83
Ultimate BOD= Yultimate=L0 = (5-day BOD in mixture water)/[1-exp(-K1mixture*5)]
=(6.153 mg/L)/ [1-exp(-0.15*5)] = 11.66 mg/L
For 20°C stream water temperature, equilibrium concentration of oxygen =9.17 mg/L
D0 = 9.17 mg/L-6.738 mg/L = 2.432 mg/L
Initial deficit = 2.432 mg/L
D (t=2 days) = [K1*L0]*[exp (-K1*t)-exp (-K2*t)]/ (K2-K1) + D0 exp (-K2*t)
= (0.15 x 11.66) *[exp (-0.15*13.649)-exp (-0.73*13.649)]/ (0.73- 0.15) + 2.432 exp (-
0.73*13.649)
= 0.388 mg/L
DO (2day) = 9.17- 0.388 = 8.782 mg/L
Time for critical DO deficit
(tc)= 1/ (K2-K1)*ln [(K2/K1)*(1-D0 *(K2-K1)/ (K1L0))]
= 1/ (0.73-0.15)*ln [(0.73/0.15)*(1-2.432 *(0.73-0.15)/ (0.73* 11.66 ))]
= 2.41 days
Critical DO deficit (Dc)= (K1/K2)*L0 exp (-K1*tc)
= ( 0.15/0.73) x 11.66 exp( - 0.15 x 2.41)= 1.669 mg/L
DOcritical= 9.17- 1.669 = 7.501 mg/L
wastewater
(given)
Stream Given
Mixture of WW and River
flow (m3/s)
15
50
Qmixture=50 + 15 = 65
65
Dissolved oxygen, mg/L
9.2
6
DOmixture=(9.2* 15 + 6*50)/(50 + 15)
= 6.738 mg/L
6.738
Temperature, °C
25
18
Temperature Mixture = (25 x15 + 18 x 50)/(65
19.615
BOD5 at 20°C, mg/L
10
5
BOD mixture = (10 x 15 + 5 x 50)/65
6.153
Oxygen consumption rate (K1 at
°C) (1/day)
0.15
0.15
(0.15 x 15 + 0.15 x 50)/65
0.15
Oxygen reaeration rate (K2 at °C)
(1/day)
0.83
0.7
Mixture = (.83 x15 + 0.7 x 50)/65
0.73.
4.634.154.764.704.654.524.705.064.424.514.2.pdf
4.63
4.15
4.76
4.70
4.65
4.52
4.70
5.06
4.42
4.51
4.24
4.52
Listed below is the rate of return for one year (reported in percent) for a sample of 12 mutual
funds that are classified as taxable money market funds.
Solution
Critical t value is (DF=11) 1.796
Sample mean is 4.5717
Sample standard deviation is 0.2405
t= (4.5717- 4.5)/.2405/12= 1.033
Do not reject the null hypothesis (that the mean rate of return is 4.5)..
4. Let TL, t 2 be a colloclion of arbitrary vcclors in R. Is span(T.pdf
4. Let TL, t 2 be a colloclion of arbitrary vcclors in R\". Is span(TL, i2,...,im) aveclor subspace
of RA? Explain why or why not.
Solution
i dont know why the font size is too small cant even read it properly repost the
question with proper font size thanks.
4. Find all values of z that satisfy the equation sin z = -5. Express.pdf
4. Find all values of z that satisfy the equation sin z = -5. Express each in the form a + bi. Or,
explain why no such z exists.
Solution
If we try solving this we will get
sine inverse of (-5) =z
But as we know that sine inverse functionby definition takes the values [-1,1] Hence no such z is
defined for the above equation..
4. A steel channel made of 1040 HR is welded to a thick steel wall wi.pdf
4. A steel channel made of 1040 HR is welded to a thick steel wall with fillet welds around the
outside of the channel only. Select the least expensive fillet that will provide a FOS of 3 for the
static load shown.
Solution
The cheapest way of welding is fillet joint which is most commonly used in welding processs.it
is mainly used for the welding of steels..
4. A f-unction f D right arrow R is a Lipschitz function if there is.pdf
4. A f-unction f: D right arrow R is a Lipschitz function if there is a C > = 0 such that |f(x) f(y)|
Solution
a) Suppose f is Lipschitz on [a,b] and let e > 0. Set d = e/M. If P = {[xi, yi]} is any partition of
[a,b] with ||P|| < d, then ? |f(xi) - f(yi) ? ? M|xi - yi| = M||P|| < M(e/M) = e. Thus f is absolutely
continuous on [a,b].
b) If f is not Lipschitz, then are sequences {x_n} and {y_n} in [a,b] such that |f(x_n) - f(y_n)| >
n|x_n - y_n| for all n ? 1. Thus |f(x_n) - f(y_n)|/|x_n - y_n| > n for all n ? 1. Hence lim sup |f(x_n)
- f(y_n)|/|x_n - y_n| = ? and lim inf |f(x_n) - f(y_n)|/|x_n - y_n| = ?. This the one sided derivatives
of f are not bounded..
3. Use the compound interest formulas A F 1+ and A Pe to find the acc.pdf
3. Use the compound interest formulas A F 1+ and A Pe to find the accumulated value of an
investment of S12,850 for 8 years at an interest rate of 6 iftie money is... a. Compounded
Quarterly b. compounded Continuously
Solution
A=P[1+(R/N)]^(NT) P=12850 $ T=8 YRS R=6.5%=0.065 a).
3. Transportation technology (15 points) a. Explain both generally an.pdf
3. Transportation technology (15 points) a. Explain both generally and with specific examples
how changes in transportation technology have affected the development of urban areas. b.
Indicate two ways in which governmental policy has influenced the shape of urbanization in the
U.S. c. Do you believe that new telecommunication and other forms of technology will make
distance an unimportant factor in economic development and, thus, make cities unimportant
economic factors? Support your answer.
Solution
Transportation enbles activity of connecting people, businesses and resources.Transportation
improvement is necessary for the economicdevelopment and transportation policies help to
support the economic objectives.it helps to improve economic efficieny. Economic efficiency
refers to the ratio total benifit to cost. Increase economic efficieny, increase productivity which
leads to economic development.
The ultimate goal of transportation is accessabilty, access the people and the company abilities
including raw material, labor, worksites, proffessional services, distrbutors etc. Increased
accessibilty means reduction in time,money, risk require recouces reaches in less time so the
productivity of a company increases.
cost saving in an organisation---Economic efficiency more output per unit of input---productivity
more goods and services produced in less cost---Ecoonomis development.
Example- if in a company a manager has to submit an assignment cost company say 10 crores
and he has to submit it with in 2 days then the manager priority is to travel by Air not by train
etc. because the loss of the company is veyr high then the cost of transportation. In transportation
priortization is imortant point to improve productivity hence economic development.
Urbanisation means the population shifted rural to urban areas and how the economy adopt the
change.Recent development of commiucation technology in US, such as broadband services ,
package express delivery services, cheap telecommunication, courier services , easy ways to
transprotation, highways development promotes people to work in the different ares of the
country.
But now days the USA government initiating suburbanisation..
3. Use the compound interest formulas A=P(1+rn)^m and A= Pe^rt to fi.pdf
3. Use the compound interest formulas A=P(1+r/n)^m and A= Pe^rt to find the accumulated
value of an investment of $12,850 for 8 years at an interest rate of 6.5% if the money is a.
Compounded Quarterly b. Compounded Continuously
Solution
A=P[1+(R/N)]^(NT) P=12850 $ T=8 YRS R=6.5%=0.065 a).
3. The number N of bacteria present in a culture at time t, in ho.pdf
3. The number N of bacteria present in a culture at time t, in hours, obeys the law exponential
growth N(t) = 500e^0.02t a) How many bacteria are there at t = 0 hours? b) When will the
number of bacteria triple?
Solution
put t=0
N(0)= 500e0= 500
bacteria triple
N(t) = 500*3 = 1500
1500=500e0.02t
3=e0.02t
ln3=0.02t
t = ln3*50
=50ln3.
3. Suppose for f(z) holomorphic C there are constants a, b, e 0 Pr.pdf
3. Suppose for f(z) holomorphic C there are constants a, b, e > 0: Prove that f is a polynomial of
degree n less than equal to c .
Solution
A holomorphic function is a complex-valued function of one or more complex variables that is
complex differentiable in a neighborhood of every point in its domain.
Hence f(z) is holomorphic means
f\'(z) exists for all z
2x= z+z bar and 2iy = z-z bar
f(z,zbar) = =?m?0,n?0amnzmz.
3. Joe is considering pursuing an MBA degree. He has applied to t.pdf
3. Joe is considering pursuing an MBA degree. He has applied to two different universities. The
acceptance rate for applicants with similar qualifications is 25% for University A and 40% for
University B.
What is the probability that Joe will not be accepted at either university? (Points : 4)
0.75
0.45
0.90
0.65
0.60
Solution
Given P(A)=0.25, P(B)=0.4 So the probability is P(A\' and B\') = P(A\')*P(B\')
=[1-P(A)]*[1-P(B)] =(1-0.25)*(1-0.4) =0.45 Answer:0.45.
3. Let On be the set of odd permutations in Sn. Is On a subgroup .pdf
3. Let On be the set of odd permutations in Sn. Is On a subgroup?
Solution
No, On is not a subgroup..
to see that the odd permutations don\'t form a subgroup of Sn is a bit easier to resolve.
Recall that any subgroup of Sn has the same identity element as the identity element in Sn. But
since the identity element in Sn is not an odd permutation (a result we saw in class), it follows
that
the collection of odd permutations cannot be a subgroup of Sn. (One could also argue that the
odd
elements aren\'t closed under the group operation.).
3. (4 points) Consider the function (in the domain {z i Solut.pdf
3. (4 points) Consider the function (in the domain {|z ? i|
Solution
Consider f(z)
It got a denominator of 1+(z-i)2
Equate to 0 the denominator to get singular points
(z-i)2 =-1
Take square root
z-i =i, -i
z=2i or 0
As |z-i|<1 we can expand f(z) by binomial series
f(z) = 1-(z-i)2+(z-i)4+...+(-1)n(z-i)2n+...
As odd powers are 0 we have
derivative of f^m(z) =0 for m = odd
For n even f\"m(z) = (-1)n(2n)(2n-1)....(1)(x2n-2n)
= (-1)n(2n)!
Proved..
3. Find currents (values and directions) in all resistors of the circ.pdf
3. Find currents (values and directions) in all resistors of the circuit given below. Find total
electric power developing in this circuit Neglect internal resistances of the batteries.
Solution
As all the Voltage sources are DC (Batteries) there by the capacitor acts as short circuit .
I1 = Current through R1 =E1-E2)/R1 = (6-3)/5 = 3/5 Amps (direction from E1 to E2)
I2= Current Throuh R3 = E2/R3 = 3/4 Amps (direction from Top to bottom)
I3 = Current Through R2 = E3-E2)/R2 = (5-3)/5 = 2/5 Amps (direction from E3 to E2)
Power delivered = (I1*E1) + (E3*I3) =(3/5)*6 + (2/5)*5 = 28/5 Watts.
3. Assume that the DS register contains 0100 and register SI contains.pdf
3. Assume that the DS register contains 0100 and register SI contains 0020. What is the result of
following instruction LES DI, [SI] Where the content of memory Location is as follows:
Solution
the command LES DI , [SI] does the following:
it takes the pointer of SI , i.e the address of the memory location SI and breaks it into lower bits
and upper bits.
then the lower bits are stored in DI and the upper bits are stored in ES.
so address of SI is 1027 .
lower bit is 27 and upper bit is 10.
27 will be stored in DI . and 10 will be saved in ES.
now DI is the lower bit of the register DS.
as it is said initially DS 0100 so, initially DI is 00.
which is changed to 27.
now DS is 0127..
2a Briefly describe the 1st law of thermodynamics. You can use either.pdf
2a Briefly describe the 1st law of thermodynamics. You can use either plain language or
equations with short explanation. Figures can also be used if necessary. (2b) Please demonstrate
that the unit of the specific kinetic energy 1/2 v^2 (where V is velocity with unit s /m) is Joule /
kg.
Solution.
3 (a) calculate thy potential at point P located a distance z above .pdf
3 (a) calculate thy potential at point P located a distance z above the center of a charged disk of
radius a and surface charge density p, Coulombs per square meter. Please show all work An
integral that you may need is The elemental area in cylindrical coordinates is dA = (b) Calculate
the electric field at P. Use back of page if necessary
Solution
function [Ef] = Loop_Ef() %(Main M-File function)
clc, clear all, close all
u.N1 = 1e21; %This is the number of states
u.NA = 1e15; %This is the number of acceptors
u.ND = 0; %This is the number of donors
u.Z1 = 281.73e19; %This term in front of the square root of the energy (this contains mass of
electron)
u.Z2 = 757.989e19; %This is the mass of hole
u.Eg = 1.12/2; %This is the energy gap
u.a = 0.0259;
%u.rat_a = 2 %scaling factor that modifies the steepness of the oxide exponential density of
states
u.es = 11.9 * 8.854187817e-14; %permittivity measured C / cm * V
u.qe = 1.602e-19; %This is the value of charge
u.psi_0_range = linspace(-0.4, 1, 160)\'; %This defines the range of Psi_0
u.display = true; %psi is in Volts Not ev?
%%
%ratN_range = 1e-2; ratS_range = [ 0.5: 0.2: 2];
ratN_range = 1; ratS_range = 1; %This doesn’t matter for Parabolic DOS
for iN = 1 : length(ratN_range)
for iS = 1 : length(ratS_range)
u.ratN = ratN_range(iN);
u.ratS = ratS_range(iS);
u.N2 = u.ratN * u.N1;
try
% Ef_(iN,iS) = Calculate_Ef(u); %Here its calculating the f_function
Ef_(iN,iS) = -0.356324 %REMOVE-TESTING
u.Ef_ = Ef_(iN,iS); %Here Ef equals
u.Q = Calculate_El(u);%Here is calculating the charge
DiffQ(u);
catch
Ef_(iN,iS) = NaN; %If there is nothing then NaN
end
end
end
clf,
plot(u.psi_0_range, u.Q) %Its plotting the graph
u.Ef_all = Ef_;
save \'u.mat\' %It saves all the data in u.file
save \'Ef_.dat\' Ef_ -ascii %Exports the data of Ef as ascii
keyboard %This command gives the control to the user
end
%================================================
function [Ef_] = Calculate_Ef(u)
clc
time = cputime;
%rescale volumes for numerical stability
u.Nscale = u.N1 ^ 2;
Nscale = u.Nscale;
u.N1 = u.N1 / Nscale;
u.N2 = u.N2 / Nscale;
u.Z1 = u.Z1 / Nscale;
u.Z2 = u.Z2 / Nscale;
%get rid of the u.\'\'
N1 = u.N1; N2 = u.N2;
Z1 = u.Z1; Z2 = u.Z2;
Eg = u.Eg;
a = u.a;
NA = u.NA/Nscale; ND = u.ND/Nscale;
P_1 = @(E) Z1.*sqrt(-Eg-E); %This is the parabolic function(Valance band)
P_2 = @(E) Z2.*sqrt(E-Eg); %This is the parabolic function (Conduction band)
Fn = @(E,Ef) 1 ./ ( exp((E-Ef)/a) ); %This is the Fermi-dirac for electrons
Fp = @(E,Ef) 1 ./ ( exp((Ef-E)/a) ); %This is the Fermi-dirac for holes
dp = @(E,Ef) P_1(E) .* Fp(E,Ef); %the integrands
dn = @(E,Ef) P_2(E) .* Fn(E,Ef);
p = @(Ef) Nscale * (IntegrateInf_p( @(E) dp(E,Ef), u ) + ND); %define our functions p & n
(Ef)
n = @(Ef) Nscale * (IntegrateInf_n( @(E) dn(E,Ef), u ) + NA);
%%we need to make sure that multiplication/division with Nscale is consistent all the way
through to DiffQ
Ef_ = Solve_Ef(-0.5, p, n); %Ef* is obtained here
fprintf(\'The value Ef*= %f, gives equal val.
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama UniversityAkanksha trivedi rama nursing college kanpur.
Natural birth techniques are various type such as/ water birth , alexender method, hypnosis, bradley method, lamaze method etcAzure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
Unit 2- Research Aptitude (UGC NET Paper I).pdf
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar KanvariaChapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
Biological Screening of Herbal Drugs in detailed.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Operation Blue Star - Saka Neela Tara
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
More Related Content
More from Info489948
3. Transportation technology (15 points) a. Explain both generally an.pdf
3. Transportation technology (15 points) a. Explain both generally and with specific examples
how changes in transportation technology have affected the development of urban areas. b.
Indicate two ways in which governmental policy has influenced the shape of urbanization in the
U.S. c. Do you believe that new telecommunication and other forms of technology will make
distance an unimportant factor in economic development and, thus, make cities unimportant
economic factors? Support your answer.
Solution
Transportation enbles activity of connecting people, businesses and resources.Transportation
improvement is necessary for the economicdevelopment and transportation policies help to
support the economic objectives.it helps to improve economic efficieny. Economic efficiency
refers to the ratio total benifit to cost. Increase economic efficieny, increase productivity which
leads to economic development.
The ultimate goal of transportation is accessabilty, access the people and the company abilities
including raw material, labor, worksites, proffessional services, distrbutors etc. Increased
accessibilty means reduction in time,money, risk require recouces reaches in less time so the
productivity of a company increases.
cost saving in an organisation---Economic efficiency more output per unit of input---productivity
more goods and services produced in less cost---Ecoonomis development.
Example- if in a company a manager has to submit an assignment cost company say 10 crores
and he has to submit it with in 2 days then the manager priority is to travel by Air not by train
etc. because the loss of the company is veyr high then the cost of transportation. In transportation
priortization is imortant point to improve productivity hence economic development.
Urbanisation means the population shifted rural to urban areas and how the economy adopt the
change.Recent development of commiucation technology in US, such as broadband services ,
package express delivery services, cheap telecommunication, courier services , easy ways to
transprotation, highways development promotes people to work in the different ares of the
country.
But now days the USA government initiating suburbanisation..
3. Use the compound interest formulas A=P(1+rn)^m and A= Pe^rt to fi.pdf
3. Use the compound interest formulas A=P(1+r/n)^m and A= Pe^rt to find the accumulated
value of an investment of $12,850 for 8 years at an interest rate of 6.5% if the money is a.
Compounded Quarterly b. Compounded Continuously
Solution
A=P[1+(R/N)]^(NT) P=12850 $ T=8 YRS R=6.5%=0.065 a).
3. The number N of bacteria present in a culture at time t, in ho.pdf
3. The number N of bacteria present in a culture at time t, in hours, obeys the law exponential
growth N(t) = 500e^0.02t a) How many bacteria are there at t = 0 hours? b) When will the
number of bacteria triple?
Solution
put t=0
N(0)= 500e0= 500
bacteria triple
N(t) = 500*3 = 1500
1500=500e0.02t
3=e0.02t
ln3=0.02t
t = ln3*50
=50ln3.
3. Suppose for f(z) holomorphic C there are constants a, b, e 0 Pr.pdf
3. Suppose for f(z) holomorphic C there are constants a, b, e > 0: Prove that f is a polynomial of
degree n less than equal to c .
Solution
A holomorphic function is a complex-valued function of one or more complex variables that is
complex differentiable in a neighborhood of every point in its domain.
Hence f(z) is holomorphic means
f\'(z) exists for all z
2x= z+z bar and 2iy = z-z bar
f(z,zbar) = =?m?0,n?0amnzmz.
3. Joe is considering pursuing an MBA degree. He has applied to t.pdf
3. Joe is considering pursuing an MBA degree. He has applied to two different universities. The
acceptance rate for applicants with similar qualifications is 25% for University A and 40% for
University B.
What is the probability that Joe will not be accepted at either university? (Points : 4)
0.75
0.45
0.90
0.65
0.60
Solution
Given P(A)=0.25, P(B)=0.4 So the probability is P(A\' and B\') = P(A\')*P(B\')
=[1-P(A)]*[1-P(B)] =(1-0.25)*(1-0.4) =0.45 Answer:0.45.
3. Let On be the set of odd permutations in Sn. Is On a subgroup .pdf
3. Let On be the set of odd permutations in Sn. Is On a subgroup?
Solution
No, On is not a subgroup..
to see that the odd permutations don\'t form a subgroup of Sn is a bit easier to resolve.
Recall that any subgroup of Sn has the same identity element as the identity element in Sn. But
since the identity element in Sn is not an odd permutation (a result we saw in class), it follows
that
the collection of odd permutations cannot be a subgroup of Sn. (One could also argue that the
odd
elements aren\'t closed under the group operation.).
3. (4 points) Consider the function (in the domain {z i Solut.pdf
3. (4 points) Consider the function (in the domain {|z ? i|
Solution
Consider f(z)
It got a denominator of 1+(z-i)2
Equate to 0 the denominator to get singular points
(z-i)2 =-1
Take square root
z-i =i, -i
z=2i or 0
As |z-i|<1 we can expand f(z) by binomial series
f(z) = 1-(z-i)2+(z-i)4+...+(-1)n(z-i)2n+...
As odd powers are 0 we have
derivative of f^m(z) =0 for m = odd
For n even f\"m(z) = (-1)n(2n)(2n-1)....(1)(x2n-2n)
= (-1)n(2n)!
Proved..
3. Find currents (values and directions) in all resistors of the circ.pdf
3. Find currents (values and directions) in all resistors of the circuit given below. Find total
electric power developing in this circuit Neglect internal resistances of the batteries.
Solution
As all the Voltage sources are DC (Batteries) there by the capacitor acts as short circuit .
I1 = Current through R1 =E1-E2)/R1 = (6-3)/5 = 3/5 Amps (direction from E1 to E2)
I2= Current Throuh R3 = E2/R3 = 3/4 Amps (direction from Top to bottom)
I3 = Current Through R2 = E3-E2)/R2 = (5-3)/5 = 2/5 Amps (direction from E3 to E2)
Power delivered = (I1*E1) + (E3*I3) =(3/5)*6 + (2/5)*5 = 28/5 Watts.
3. Assume that the DS register contains 0100 and register SI contains.pdf
3. Assume that the DS register contains 0100 and register SI contains 0020. What is the result of
following instruction LES DI, [SI] Where the content of memory Location is as follows:
Solution
the command LES DI , [SI] does the following:
it takes the pointer of SI , i.e the address of the memory location SI and breaks it into lower bits
and upper bits.
then the lower bits are stored in DI and the upper bits are stored in ES.
so address of SI is 1027 .
lower bit is 27 and upper bit is 10.
27 will be stored in DI . and 10 will be saved in ES.
now DI is the lower bit of the register DS.
as it is said initially DS 0100 so, initially DI is 00.
which is changed to 27.
now DS is 0127..
2a Briefly describe the 1st law of thermodynamics. You can use either.pdf
2a Briefly describe the 1st law of thermodynamics. You can use either plain language or
equations with short explanation. Figures can also be used if necessary. (2b) Please demonstrate
that the unit of the specific kinetic energy 1/2 v^2 (where V is velocity with unit s /m) is Joule /
kg.
Solution.
3 (a) calculate thy potential at point P located a distance z above .pdf
3 (a) calculate thy potential at point P located a distance z above the center of a charged disk of
radius a and surface charge density p, Coulombs per square meter. Please show all work An
integral that you may need is The elemental area in cylindrical coordinates is dA = (b) Calculate
the electric field at P. Use back of page if necessary
Solution
function [Ef] = Loop_Ef() %(Main M-File function)
clc, clear all, close all
u.N1 = 1e21; %This is the number of states
u.NA = 1e15; %This is the number of acceptors
u.ND = 0; %This is the number of donors
u.Z1 = 281.73e19; %This term in front of the square root of the energy (this contains mass of
electron)
u.Z2 = 757.989e19; %This is the mass of hole
u.Eg = 1.12/2; %This is the energy gap
u.a = 0.0259;
%u.rat_a = 2 %scaling factor that modifies the steepness of the oxide exponential density of
states
u.es = 11.9 * 8.854187817e-14; %permittivity measured C / cm * V
u.qe = 1.602e-19; %This is the value of charge
u.psi_0_range = linspace(-0.4, 1, 160)\'; %This defines the range of Psi_0
u.display = true; %psi is in Volts Not ev?
%%
%ratN_range = 1e-2; ratS_range = [ 0.5: 0.2: 2];
ratN_range = 1; ratS_range = 1; %This doesn’t matter for Parabolic DOS
for iN = 1 : length(ratN_range)
for iS = 1 : length(ratS_range)
u.ratN = ratN_range(iN);
u.ratS = ratS_range(iS);
u.N2 = u.ratN * u.N1;
try
% Ef_(iN,iS) = Calculate_Ef(u); %Here its calculating the f_function
Ef_(iN,iS) = -0.356324 %REMOVE-TESTING
u.Ef_ = Ef_(iN,iS); %Here Ef equals
u.Q = Calculate_El(u);%Here is calculating the charge
DiffQ(u);
catch
Ef_(iN,iS) = NaN; %If there is nothing then NaN
end
end
end
clf,
plot(u.psi_0_range, u.Q) %Its plotting the graph
u.Ef_all = Ef_;
save \'u.mat\' %It saves all the data in u.file
save \'Ef_.dat\' Ef_ -ascii %Exports the data of Ef as ascii
keyboard %This command gives the control to the user
end
%================================================
function [Ef_] = Calculate_Ef(u)
clc
time = cputime;
%rescale volumes for numerical stability
u.Nscale = u.N1 ^ 2;
Nscale = u.Nscale;
u.N1 = u.N1 / Nscale;
u.N2 = u.N2 / Nscale;
u.Z1 = u.Z1 / Nscale;
u.Z2 = u.Z2 / Nscale;
%get rid of the u.\'\'
N1 = u.N1; N2 = u.N2;
Z1 = u.Z1; Z2 = u.Z2;
Eg = u.Eg;
a = u.a;
NA = u.NA/Nscale; ND = u.ND/Nscale;
P_1 = @(E) Z1.*sqrt(-Eg-E); %This is the parabolic function(Valance band)
P_2 = @(E) Z2.*sqrt(E-Eg); %This is the parabolic function (Conduction band)
Fn = @(E,Ef) 1 ./ ( exp((E-Ef)/a) ); %This is the Fermi-dirac for electrons
Fp = @(E,Ef) 1 ./ ( exp((Ef-E)/a) ); %This is the Fermi-dirac for holes
dp = @(E,Ef) P_1(E) .* Fp(E,Ef); %the integrands
dn = @(E,Ef) P_2(E) .* Fn(E,Ef);
p = @(Ef) Nscale * (IntegrateInf_p( @(E) dp(E,Ef), u ) + ND); %define our functions p & n
(Ef)
n = @(Ef) Nscale * (IntegrateInf_n( @(E) dn(E,Ef), u ) + NA);
%%we need to make sure that multiplication/division with Nscale is consistent all the way
through to DiffQ
Ef_ = Solve_Ef(-0.5, p, n); %Ef* is obtained here
fprintf(\'The value Ef*= %f, gives equal val.
More from Info489948 (11)
3. Transportation technology (15 points) a. Explain both generally an.pdf
3. Transportation technology (15 points) a. Explain both generally an.pdf
3. Use the compound interest formulas A=P(1+rn)^m and A= Pe^rt to fi.pdf
3. Use the compound interest formulas A=P(1+rn)^m and A= Pe^rt to fi.pdf
3. The number N of bacteria present in a culture at time t, in ho.pdf
3. The number N of bacteria present in a culture at time t, in ho.pdf
3. Suppose for f(z) holomorphic C there are constants a, b, e 0 Pr.pdf
3. Suppose for f(z) holomorphic C there are constants a, b, e 0 Pr.pdf
3. Joe is considering pursuing an MBA degree. He has applied to t.pdf
3. Joe is considering pursuing an MBA degree. He has applied to t.pdf
3. Let On be the set of odd permutations in Sn. Is On a subgroup .pdf
3. Let On be the set of odd permutations in Sn. Is On a subgroup .pdf
3. (4 points) Consider the function (in the domain {z i Solut.pdf
3. (4 points) Consider the function (in the domain {z i Solut.pdf
3. Find currents (values and directions) in all resistors of the circ.pdf
3. Find currents (values and directions) in all resistors of the circ.pdf
3. Assume that the DS register contains 0100 and register SI contains.pdf
3. Assume that the DS register contains 0100 and register SI contains.pdf
2a Briefly describe the 1st law of thermodynamics. You can use either.pdf
2a Briefly describe the 1st law of thermodynamics. You can use either.pdf
3 (a) calculate thy potential at point P located a distance z above .pdf
3 (a) calculate thy potential at point P located a distance z above .pdf
Recently uploaded
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama UniversityAkanksha trivedi rama nursing college kanpur.
Natural birth techniques are various type such as/ water birth , alexender method, hypnosis, bradley method, lamaze method etcAzure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
Unit 2- Research Aptitude (UGC NET Paper I).pdf
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar KanvariaChapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
Biological Screening of Herbal Drugs in detailed.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Operation Blue Star - Saka Neela Tara
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
South African Journal of Science: Writing with integrity workshop (2024)
South African Journal of Science: Writing with integrity workshop (2024)Academy of Science of South Africa
A workshop hosted by the South African Journal of Science aimed at postgraduate students and early career researchers with little or no experience in writing and publishing journal articles.1.4 modern child centered education - mahatma gandhi-2.pptx
Child centred education is an educational approach that priorities the interest, needs and abilities of the child in the learning process.
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
CACJapan - GROUP Presentation 1- Wk 4.pdf
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
The Diamonds of 2023-2024 in the IGRA collection
A review of the growth of the Israel Genealogy Research Association Database Collection for the last 12 months. Our collection is now passed the 3 million mark and still growing. See which archives have contributed the most. See the different types of records we have, and which years have had records added. You can also see what we have for the future.
Recently uploaded (20)
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
Multithreading_in_C++ - std::thread, race condition
Multithreading_in_C++ - std::thread, race condition
South African Journal of Science: Writing with integrity workshop (2024)
South African Journal of Science: Writing with integrity workshop (2024)
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI fund...
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
4. Image and Kernel of homomorphism. Let f R S be a ring homomo.pdf
- 1. 4. Image and Kernel of homomorphism. Let f: R ? > S be a ring homomorphism. Prove that ker (f) is an ideal of R. Solution Consider ker(f) as a subring of R Let y belong to ker(f) and x belong to R. Then f(xy)=f(x)f(y)=f(x)0=0 Thus, f(xy)=0 that is xy belongs to ker(f) Hence, ker(f) is an ideal of R