285 - Askhseis HM Teyxos 2
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Παρουσίαση με ασκήσεις Φυσική Γ Προσανατολισμού από το Κεφάλαιο Η/Μ τεύχος 2 σελ.223 για μάθημα Φυσικής Γ΄ Λυκείου ΓΕΛ Νυδριού Λευκάδος Γουρζής Στάθης - Φυσικός
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285 - Askhseis HM Teyxos 2
- 1. Γουρζής Στάθης – Φυσικός ΓΕΛ Νυδριού Λευκάδος ΥΣΕΦΕ 2020 - 2021 Ασκήσεις στον Η/Μ – Τεύχος 2 Προβλήματα σελ. 223
- 5. V = I .R
- 6. V = I .R
- 7. => V = I .R
- 8. => V = I .R
- 9. => V = I .R
- 10. => V = I .R
- 11. => V = I .R
- 12. => V = I .R
- 13. => V = I .R =>
- 14. => V = I .R =>
- 18. =>
- 19. =>
- 20. => =
- 21. => =
- 22. => =
- 23. => => =
- 24. => => =
- 25. => => = A = π .r2
- 26. => => = A = π .r2
- 27. => => = A = π .r2 =>
- 28. => => = A = π .r2 =>
- 31. R = ρ l / S
- 32. R = ρ l / S
- 33. R = ρ l / S =>
- 34. R = ρ l / S =>
- 35. R = ρ l / S => l = N 2πr
- 36. R = ρ l / S => l = N 2πr
- 37. R = ρ l / S => l = N 2πr =>
- 38. R = ρ l / S => l = N 2πr =>
- 39. R = ρ l / S => l = N 2πr => =>
- 40. R = ρ l / S => l = N 2πr => =>
- 41. R = ρ l / S => l = N 2πr => => =>
- 42. R = ρ l / S => l = N 2πr => => => =>
- 43. R = ρ l / S => l = N 2πr => => ΔQ = (2.10-5).(10-1. 10-4). (8.10-2)/ 1,6 .10-6 => =>
- 44. R = ρ l / S => l = N 2πr => => ΔQ = (2.10-5).(10-1. 10-4). (8.10-2)/ 1,6 .10-6 => => => =>
- 45. R = ρ l / S => l = N 2πr => => ΔQ = (2.10-5).(10-1. 10-4). (8.10-2)/ 1,6 .10-6 => => => => ΔQ = (16).10-12/1,6 .10-6
- 46. R = ρ l / S => l = N 2πr => => ΔQ = (2.10-5).(10-1. 10-4). (8.10-2)/ 1,6 .10-6 => => => => => => ΔQ = (16).10-12/1,6 .10-6
- 47. R = ρ l / S => l = N 2πr => => ΔQ = (2.10-5).(10-1. 10-4). (8.10-2)/ 1,6 .10-6 => => => => => => ΔQ = (16).10-12/1,6 .10-6 ΔQ = (10).10-6=> ΔQ = 10-5 C
- 54. =>
- 55. =>
- 56. => R = 2 x R*
- 57. => R = 2 x R*
- 58. => R = 2 x R* =>
- 59. => R = 2 x R* =>
- 60. => R = 2 x R* => x = υt
- 61. => R = 2 x R* => x = υt
- 62. => R = 2 x R* => x = υt =>
- 63. => R = 2 x R* => x = υt =>
- 64. => R = 2 x R* => x = υt => =>
- 65. => R = 2 x R* => x = υt => =>
- 66. => R = 2 x R* => x = υt => => =>
- 69. =>
- 70. => I = (5.10-2).(10.10-2)/ 2.(10-2/10-2)t =>
- 71. => I = (5.10-2).(10.10-2)/ 2.(10-2/10-2)t => => I = (50).10-4)/ 2.t =>
- 72. => I = (5.10-2).(10.10-2)/ 2.(10-2/10-2)t => => I = (50).10-4)/ 2.t => => I = (25.10-4) / t => I = (2,5.10-3)/t
- 74. I = (2,5.10-3)/t =>
- 75. I = (2,5.10-3)/t => I = (2,5.10-3)/2 =>
- 76. I = (2,5.10-3)/t => I = (2,5.10-3)/2 => I = 1,25.10-3 A
- 85. =>
- 86. =>
- 87. =>
- 88. => =>
- 89. => => =>
- 90. => => => =>
- 94. =>
- 95. =>
- 96. =>
- 97. =>
- 98. =>
- 99. => =>
- 100. => =>
- 101. => =>
- 102. => =>
- 103. => =>
- 104. => => =>
- 105. => => =>
- 106. => => =>
- 107. => => =>
- 108. => => => =>
- 109. => => => =>
- 112. =>
- 113. =>
- 114. => => υορ= 1. (1.10-1+5.10-1)/(2.10-1)2.12 =>
- 115. => => υορ= 1. (1.10-1+5.10-1)/(2.10-1)2.12 => => υορ= (6.10-1)/(4.10-2)=>
- 116. => => υορ= 1. (1.10-1+5.10-1)/(2.10-1)2.12 => => υορ= (6.10-1)/(4.10-2)=> => υορ= 6/4.10 => υορ= 1,5.10 m /s
- 121. =>
- 122. => Εεπ= (2.10-1) .1.15 => Εεπ= 3 V
- 123. => Εεπ= (2.10-1) .1.15 => Εεπ= 3 V
- 124. => Εεπ= (2.10-1) .1.15 => Εεπ= 3 V =>
- 125. => Εεπ= (2.10-1) .1.15 => Εεπ= 3 V => I = (2.10-1) .1.15/ 6. 10-1=>
- 126. => Εεπ= (2.10-1) .1.15 => Εεπ= 3 V => I = (2.10-1) .1.15/ 6. 10-1=> => I = 30/6 A => I = 5 A
- 127. => Εεπ= (2.10-1) .1.15 => Εεπ= 3 V => I = (2.10-1) .1.15/ 6. 10-1=> => I = 30/6 A => I = 5 A
- 130. =>
- 131. =>
- 132. => => FL = (2.10-1)2 .12.(7,5)/ 6. 10-1=>
- 133. => => FL = (2.10-1)2 .12.(7,5)/ 6. 10-1=> => FL = (4.10-2) (7,5)/ 6. 10-1=>
- 134. => => FL = (2.10-1)2 .12.(7,5)/ 6. 10-1=> => FL = (4.10-2) (7,5)/ 6. 10-1=> => FL = (30.10-2)/ 6. 10-1=>
- 135. => => FL = (2.10-1)2 .12.(7,5)/ 6. 10-1=> => FL = (4.10-2) (7,5)/ 6. 10-1=> => FL = (30.10-2)/ 6. 10-1=> => FL = 5. 10-1 => FL = 0,5 N
- 139. =>
- 140. =>
- 141. =>
- 142. =>
- 143. => =>
- 144. => =>
- 145. => =>
- 158. =>
- 159. =>
- 160. => =>
- 161. => =>
- 162. => =>
- 163. =>
- 172. =>
- 173. =>