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284 - Newton's 2nd Low in 2D
The document discusses Newton's second law in a two-dimensional context, demonstrating calculations related to forces and acceleration. It includes specific numerical examples, revealing values such as acceleration (α = 5.4 m/s²) and displacement (s = 43.2 m). The overall focus is on illustrating the application of Newton's laws through calculations.
284 - Newton's 2nd Low in 2D
- 1. Γουρζής Στάθης –Φυσικός ΓΕΛ Νυδριού Λευκάδος Ο 2ος νόμος του Newton Στις δύο διαστάσεις – Παράδειγμα
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- 54. => => => => Τ= ¼ ( 10 . 10 – 80. ½ ) =>
- 55. => => => => Τ= ¼ ( 10 . 10 – 80. ½ ) => =>Τ = ¼ ( 100 – 40 ) =>
- 56. => => => => Τ= ¼ ( 10 . 10 – 80. ½ ) => =>Τ = ¼ ( 100 – 40 ) => =>Τ = ¼ 60 =>
- 57. => => => => Τ= ¼ ( 10 . 10 – 80. ½ ) => =>Τ = ¼ ( 100 – 40 ) => =>Τ = ¼ 60 => Τ = 15 Ν
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- 68. => => => => α= ( 80 . (31/2/2) – 15 ) / 10 =>
- 69. => => => => α= ( 80 . (31/2/2) – 15 ) / 10 => => α = ( 138,5/2 – 15)/10 =>
- 70. => => => => α= ( 80 . (31/2/2) – 15 ) / 10 => => α = ( 138,5/2 – 15)/10 => => α = (69,25 – 15)/10 =>
- 71. => => => => α= ( 80 . (31/2/2) – 15 ) / 10 => => α = ( 138,5/2 – 15)/10 => => α = (69,25 – 15)/10 => => α = 54,25.10 =>
- 72. => => => => α= ( 80 . (31/2/2) – 15 ) / 10 => => α = ( 138,5/2 – 15)/10 => => α = (69,25 – 15)/10 => => α = 54,25.10 => α = 5,4 m/s2
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- 77. s = ½. 5,4 . 42 => =>
- 78. s = ½. 5,4 . 42 => => s = ½ . 5,4 . 16 => =>
- 79. s = ½. 5,4 . 42 => => s = ½ . 5,4 . 16 => => s = 8 . 5,4 => =>
- 80. s = ½. 5,4 . 42 => => s = ½ . 5,4 . 16 => => s = 8 . 5,4 => s = 43,2 m =>