The document discusses the C programming language and provides examples of C code. It introduces C programming concepts like data types, variables, input/output functions, operators, conditional statements, loops, functions, arrays and strings. It then provides examples of C code to calculate addition, percentages, student averages, and project budgets to demonstrate applying these concepts.

2. (cos)
(Windows)

4. 1.
. .
1972
BCLP
B
( Bell
Laboratoories)

5. . . 1972
The C
Programming Language

6. . . 1988
ANSI

7. 2.

8. 1. (Source
Program)
.c work.c

9. .c

10. 2.
(Compile)
(Build)
A

11. 3. ( Link)
printf ()
exe

13. # include < header file
> 1
Main ( )
{
Statements ;
2
}

14. 1 (Header
File)
main ( ) .h

15. # include < header_name>
header_name
printf
#include <stdio.h>
# include <stdio.h>

16. stdio.h include
#include <stdio.h>

17. stdio.h .o include

18. 2. (Main
Function)
{ }
main ( )

20. 3.
(
)
1.

21. 2.
3.
(;)

22. 4. 1 1
1
5.

24. (identifier)
(Address )

25. 2

26. 1.
3
char a [20] :

27. 2.
:
Const data_type var = data ;
data_type
Var
Data

28. 3
:
1 var_type var_name[,….];
2 var_type var_name = data ;
var_type
var name
data (
)

29. 3
(input )
(Process)
(Qutput )

30. 1 : printf ( )
:
1 Printf (“ string_format” ,
data_list ) ;
2 Printf (“string_format” ) ;
string_format
(text ) %d
n
Data_list

31. format code
%c
char
%d
int 10
%s
string

32. :
Scanf ( “ string_format” , &
address_list ) ;
string_format
%d
Address_list
&(Ampersand)

33. 3. : expression
:
Var = expression ;
var
Expression

34. 1. ;
x A
y
Printf ( “data x=” ) ; scanf ( “%d ,&x )
;
Printf ( “data y=” ) ; scanf ( “%d ,&y )

35. 2.
r = 2 + 3 * 2 ; 8
s = (2 + 3 ) * 2;
10
t = 2 + 3 * 2-1 ;
7

36. 3.
Printf ( “r = x + y * 2 = %d
n” , r ) ;
Printf ( “r = (x + y X* 2 = %d
n” , s ) ;
Printf ( “r = x + y * 2-1 = %d
n” , t ) ;

37. 8 (char )
5.1 putchar ( )
1
Putchar ( char_argument) ;
putchar_argument

39. 1. ‘A’
char word1 „1‟
word2 char
word1=‟A‟ , word2=‟1‟
2.
1
putchar(word1);

40. 5.2 getchar ( )
1
Enter
1
getchar ( ) ;
2
char_var = getchar ( ) ;

42. 1.
printf ( “Key 1 Character = “ ) ;
word = getchar ( );
1 a
Enter

43. 2 .
word a (
word)
printf ( “You key Character is =
%cn”, word ) ;

44. 5.3 getch ( )
1
Enter
1
getch( ) ;
2
char_var = getch 1( ) ;

45. 1.
printf ( “Key 1 Character = “ ) ;
word = getch ( );
1 a
Enter

46. 2.
word a (
word )
printf ( “You key Character is =
%cn”, word ) ;

47. 5.4 getche( )
1
Enter
1
getche ( );
2
char_var = getche ( );
char_var

48. 1.
printf ( “Key 1 Character = “ ) ;
word = getche ( );
1 a
Enter

49. 2.
word
a ( word )
printf ( “You key Character is =
%cn”, word ) ;

51. (String)
char [n]
6.1. puts( )
6.2. gets( )

52. 6.1. puts( )
1
puts ( string_argument ) ;
string_argument

53. 1.
word
Char word [15] = “*Example
* “ ;
2.
puts
Puts ( word ) ;

54. 6.2 gets ( )
Enter
1
gets ( );
2
string_var =gets ( ) ;
string_var

56. 1.
Enter
gets (word) ;
2.
printf ( “You name is = %sn”,

57. 1.

58. 1.
#include <stdio.h>
2. (remark) /*
calculate// cal1.c*/

59. 3.
int
n1,n2,result;( 3 n1,n2
result )
4.
printf(“*calculate
Add*nn*);n

60. 5.
printf (“key number 1 =”) ;
scanf(“%d”,&n1); key
number 1 =(
)
6.
result= n1+n2; ( n1
n2
result)

61. 7. _
printf (“n**Result =%dn”
,result);
(
** Result = result
%d
)

62. 2.

63. 1.
1.1 )
const char line[20] =
“**************”;
const int n3 =2;
1.2)

64. 2.
printf("*Calculate Value * nn");
printf(line);
printf("n key number 8 = ");
scanf("%d" , &n8);
printf(" key number ; = ");

65. result = n8 + n; * nA;
5.
printf("n %d + %d * %d = %d
n" , n8, n;, nA, result);

66. 3.
1.
printf (“n key syudent name :”)

67. 2.
result = (score * 100) /250 ;
3.
printf(“n * percentage = %f
n” , result) ;

68. 4.
1.
char name[30];
int code, sum,num;
float avg;

69. 2.
printf(“ code =>”); scanf(“%d”,
&code);
printf(“ name =>”); scanf(“%s”,
&name);
printf(“ summit =>”); scanf(“%d”,
&sum);
printf(“ number =>”); scanf(“%d”,

70. 3.
avg = sum/num;
4.
printf(“* average = % .2f n” , avg);

71. 1.
char name[40];
float budget, maint, pub,
remain ;

72. 2.
printf(“project name = ”);
scanf(“%s” , name);
printf(“budget = ”) ;
scanf(“%f” , &budget) ;
3.
maint = budget * 20/100 ;
pub = (budget - maint) * </8BB ;

73. 4.
printf(“n ** maintenance = %.2f
n” , maint);
printf(“n ** public utility = %.2f
n” , pub);
printf(“n ** remain = %.2f n” ,
remain);

74. 6/2
1.
4
2.
6
3.
7
4. 12
5.