Assignment 2 Cloud SolutionsCloud-based computing allows busine.docx

Assignment 2: Cloud
Solution
s
Cloud-based computing allows businesses to store and access
large amounts of data over the Internet rather than on in-house
computer hard drives. There are several cloud-based data
solutions currently available in the marketplace.
Using the Argosy University online library resources and the
Internet, research the latest cloud-based data solutions in the
marketplace today. Select at least 2 scholarly sources for use in
this assignment.
Assume you are evaluating vendors providing cloud-based
solutions for your current organization or a hypothetical
organization. Complete the following:
· Identify three potential vendors.
· Compare and contrast the three different vendors. Be sure to
consider the services, data solutions, and security features they
provide.
· Based on your analysis, provide a recommendation about
which provider or solution you think would work best.
· Provide a justification explaining why it would be the best

product for your selected business to use (using your current
organization or a hypothetical organization). Support your
recommendation with up-to-date knowledge of business
practices and technology use. Be sure to provide a little
background about the organization to help justify your
recommendation.
Utilize at least 2 scholarly sources in support of your assertions.
WEB SITES ONLY
Make sure you write in a clear, concise, and organized manner;
demonstrate ethical scholarship in appropriate and accurate
representation and attribution of sources; display accurate
spelling, grammar, and punctuation.
Write a 3–4-page report in Word format. Apply APA standards
to citation of sources. By Wednesday, November 5, 2014,
Assignment Components
Proficient
Max Points
Compared and contrasted the services, data solutions, and
security features provided by the vendors.
An accurate comparative analysis of each vendor is provided
including services, data solutions, and security features.
32
Provide a recommendation about which provider or solution you
think would work best.

Recommendation is based on accurate vendor information and it
explains which provider would work best in the specific
situation.
16
Provide justification about why you feel it would be the best
product for a business to use.
Justification is supported using up-to-date knowledge of
business practices and technology use.
32
Academic Writing
Write in a clear, concise, and organized manner; demonstrate
ethical scholarship in appropriate and accurate representation
and attribution of sources (i.e., APA); and display accurate
spelling, grammar, and punctuation. Use of scholarly sources
aligns with specified assignment requirements.
Wrote in a clear, concise, and organized manner; demonstrated
ethical scholarship in appropriate and accurate representation
and attribution of sources; and displayed accurate spelling,
grammar, and punctuation. Use of scholarly sources aligns with
specified assignment requirements.
20
Total

100
1
Collisions in One Dimension
Conservation of Linear Momentum and (Sometimes) Energy
Introduction and theory:
Collisions are an important way of studying how objects
interact. Conservation laws
have been developed that allow one to say quite a bit about
what is happening without
knowing the exact details of the interaction during a collision.
In this lab we are going to

show that momentum is always conserved when there is no net
external force acting on
the system and that energy is only sometimes conserved in
various kinds of collisions.
These principles are important in studying automobile
collisions, planetary motion, and
the collisions of subatomic particles.
Momentum is the product of mass and velocity so it has units of
kg m/sec.
p = m*v (1)
It is a vector quantity with its direction the same as the
velocity. We do not have a
special name for the unit of momentum but we do commonly use
the letter p to represent

the momentum vector. Conservation of momentum is derived in
your textbook using
Newton’s third law and also deals with the quantity called
Momentum is conserved
whenever the interacting objects are only interacting with each
other (or at least in the
coordinate direction which we are considering). If pi is the
initial momentum of the
system before the collision and pf is the final momentum of the
system after the collision
then:
Δp = (pf – pi) = 0 , (2)
where pi = p1i + p2i and pf = p1f + p2f in case of the

collision of two carts.
Another important conservation law is the conservation of
energy. Energy is a scalar
quantity and not a vector. A scalar quantity just has a
magnitude and no direction.
Energy is conserved depending on whether the forces between
the objects are
conservative. Examples of conservative forces are gravity,
electric, and magnetic forces.
There are other forces at the level of nuclear physics that are
also conservative. The most
important non-conservative force we will deal with is friction.
Friction is a non-
conservative force because energy is converted into heat by
friction. Another example of
a non-conservative force will occur when we have two bodies

that collide and stick
together. This will be a special case of friction where the
energy will be converted into
heat in the process of sticking together.
In this experiment we will be dealing with collisions in one
dimension. The motion of
the bodies involved is constrained by a horizontal track. This
means that the velocity and
momentum vectors can be only in one of two directions, +x or –
x where x represents the
2
coordinate of the track. Since we will be dealing with two
bodies, the conservation of

expressed for two bodies as
Thus, in order to show the conservation of momentum, we must
know the masses of the
two bodies and their vector velocities before and after the
collision. To see if energy is
conserved we must evaluate the kinetic energy before and after
the collision. There is no
change in gravitational potential energy in this case because the
motion takes place on a
level surface.
We can express conservation of energy with the following
equation:
(4) .

2
1
2
1
2
1
2
1 2
22
2
11
?
2
22

2
A question mark is placed over the equal sign because energy
will not always be
conserved.
A collision in which the total kinetic energy before the collision
(KEi) is the same as the
total kinetic energy after the collision (KEf) is said to be
elastic.
ΔKE = (KEf – KEi) = 0 (5)
It is also useful to formulate these fundamental relations such as
law of conservation of

momentum (3) and law of conservation of energy (4) in terms of
velocities. Thus we have
(for elastic collisions)
(v2f – v1f)/(vi2 – vi1) = -1 (6)
Or in other words “the relative velocities after/before are equal
but opposite”. This is
true for any mass values. A somewhat more restrictive case is
for vi2 = 0 (stationary
“target” m2). Then it can be shown that:
v1f = (m1 – m2) vi1/(m1+m2) (7a)
v2f = (2m1) vi1/(m1+m2) (7b)
Note that the ratio r = v1/v2 is constant here where vi2=0.

If the total kinetic energy after the collision is different from
the total kinetic energy
before the collision, then the collision is said to be inelastic.
The fundamental relations for KE and p are now modified and
the velocity relations (Eq.
6, 7) do not apply. Momentum conservation holds, but simple
energy conservation does
not (if we ignore work done in sticking Velcro).
(3) . 22112211 ffii mmmm
3
A collision where the colliding objects stick together after the

collision is said to be
perfectly inelastic. In this type of collision the kinetic energy
loss is maximum, but not
necessarily 100%. Text reference: Young and Freedman §§8.3-
4.
Procedure:
The two photogates will record the position of carts as a
function of time. It is done by
using picket fences of known band spacing. Make sure that the
photogate light beam
is level with the 1 cm spaced bans. The recording has to be
started and stopped
manually. The magnitude of the cart velocity (= speed, no
direction indicated) is equal to
the slope of the linear fit to the position data.

The experimental setup is depicted below:
Open the pre-set experiment file: Labs/phy122/spring
2011/collisions 1D.
Check that the photogates on the left side of track are connected
to Channel 1.

Beware: the software does not know which cart is passing
through a given gate, or
which direction it is going. Keep careful notes of these items in
your notebook, for
example with small diagrams.
In Excel prepare two data tables: data table 1: Calibration; data
table 2: Collisions. You
will use it to record the measurements.
Data table 1: Calibration; prepare 6 rows: (slow left; slow right;
moderate left;
moderate right; fast left; fast right) and 2 columns: velocity
photogate 1 & velocity
photogate 2.
Data table 2: Collisions: Each collision contains 4 runs. The
table should include the

values for the following quantities:
– m1;
– m2;
he collision;
4
collision;
collision;
collision;
the total kinetic energy of the two cart system after the
collision;

system.
6);
io of masses (eq. 7 b)
for collision 4 only.
Look in the Introduction and Theory section for the useful
equations of momentum and
kinetic energy to enter them in the Excel.
Part 1 – Calibration
How good is your equipment? Let’s test this using a trivial
known result – continuous
motion (no collision). Send a single cart (with no extra
weights) though both gates at
slow speed, first from the left, then repeat from the right.
Repeat this pair, but now at a

moderate speed. Repeat this pair now at fast speed.
Record the value of speed through both gates for each trial in
the prepared data table 1
(don’t forget signs!). For each pass calculate
1
2
v
v
. You can add the column in Excel for
these calculations. The ratio of speeds through the two detectors
should be 1. Compare
your data with this “theory”. Is there any systematic effect of
left vs. right, slow vs. fast,
etc. Pick the speed that had the least systematic error (such as
tilted track, friction, etc) to

be used in the second part of the lab to launch the cart. In data
analysis show the sample
of ratio calculations for the speed picked to use in the second
part of the lab.
In the discussion, explain the physical origin of the systematic
and/or statistical data.
Propose a way to correct the experimental data for this effect.
5
Fig. 1
Part 2. Collisions

Collision 1: Perfectly inelastic collision (carts of about equal
masses stick together after
the collision)
a) Measure the mass of each cart.
b) Set the carts on the track with Velcro ends facing each other.
c) In all collisions: the stationary cart must be positioned
between the gates as
close as possible to the second photogate. The first cart must
pass through
photogate 1 before it collides with the second cart.
d) Make a collision with m1 incident on stationary m2 (v 2i =0)
at chosen speed,
with m1 approaching from the left. Apply linear fit to the
position vs time
graphs to find the velocities of the carts before and after
collision. Because the

track as well as the carts is not exactly frictionless it is
recommended to fit
only a small part of the recorded position closest to the instant
of collision.
(Fig. 1)
e) Complete the row in the prepared data table 2. Repeat the
above steps b), c)
and e) 3 more times.
Collision 2: Perfectly inelastic collision (carts stick together
after the collision), where m1
≠ m2 and v2i=0.
6
a) Add the heavy rectangular block to the second cart, m2= M.
Set the carts

on the track with Velcro ends facing each other. Set up the carts
as
directed in steps b) and c) in the collision 1.
b) Make a collision of m1 on stationary M, with m1 approaching
from the
left.
c) Apply linear fit to the position vs time graphs to find the
velocities of the
carts before and after collision. Because the track as well as the
carts is not
exactly frictionless it is recommended to fit only a small part of
the
recorded position closest to the instant of collision. (Fig. 1).
d) Complete the row in the prepared data table 2. Repeat the
above steps b),
c) and d) 3 more times.
Collision 3: Elastic collision (carts of about equal masses)

Remove additional mass from the cart 2.
a) Set them on the track with magnet bumpers facing each other.
b) Make a collision with m1 incident on m2 at chosen speed,
with m1
approaching from the left.
velocities of the
carts is not
the
above steps b),

Collision 4: Elastic collision (carts stay separate after the
collision), where m1 < m2 and
v2i=0.
a) Add the heavy rectangular block to the second cart, m2= M;
b) Make a collision of m1 on stationary M, with m approaching
from the left.
velocities of the
carts is not
the
above steps b),
In Data Analysis derive equation (6); based on the data

provided in the Excel’s data table
2, show sample calculation of relative percentage change in
momentum
ip
and relative
percentage change in kinetic energy
iKE
for the best run in each collision. For collision
# 3 and #4 show calculation of the relative velocity for one of
the best runs. For run # 4
7
show one sample calculations of the experimental ratio
f

f
v
v
r
2
1
expected value
m
Mm
r ect
2
exp

Report the major results of the lab in the result table.
In the discussion explain your results for the velocity ratios in
part 1. Comment on your
experimental results on the relative velocity ratio compare to
the theoretical value. For
ip
p
iKE
KE
, but why do we
allow the values of

ip
to be less than 10% and
iKE
to be less than 20% to say whether
or not momentum or kinetic energy is conserved?
In the conclusion state if the objective of the lab has been met.
Do the results of the
relative percentage change in momentum and relative
percentage change in kinetic
energy agree with the theory?

Assignment 2 Cloud SolutionsCloud-based computing allows busine.docx

Assignment 2 Cloud SolutionsCloud-based computing allows busine.docx

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