1. PDA APS TEST DETAILED SOLUTIONS:
1. No. of women in the room = (3/5) * 120 = 72
No. of married people = (2/3) * 120 = 80
No. of unmarried people = 40
No. of men in the room = 48
If all the men are supposed to be married, then the number of married women could only be
80 – 48 = 32
Maximum no. of unmarried women = 72 – 32 = 40
2. Let the total number of students be ‘x’
No. of girl students = 2x/3
No .of boy students = x/3
No. of girls who took part in camp = (1/5) * (2x/3) = (2/15)x
No .of boys who took part in camp = (1/8) * (x/3) = (x/24)
Total no. of students who took part in camp = (2/15)x + (x/24) = (7/40) x
3. Cost of Cave = 5 rocks + 2 stones + 3 pebbles
= 35 stones + 14 pebbles + 3 pebbles
= 245 pebbles + 14 pebbles + 3 pebbles
= 262 pebbles
1 rock = 49 pebbles
To use 6 rocks, it requires 294 pebbles.
Change required = 294 -262 = 32 pebbles = 4 stones and 4 pebbles
4. Population ‘n’ years ago = P ans: 68 lakhs
n
( 1 + 0.01 r)
5. 14 out of 200 parts were defective. Hence 7%
6. Time taken to cover first 100 kms = 100/30 = 10/3 hrs
Time taken to cover next 100 kms = 100/40 = 5/2 hrs
Time taken to cover final 100 kms = 100/50 = 2 hrs
Total time taken = 47/6 hrs
avg. speed = total distance/total time = 300 * 6/47 = 38.3 km/hr
7. Income of man:wife = a:b = 5:3
Expenditure of man:wife = c:d = 3:1
Total savings = Rs.4000
Individual savings = S = Rs. 2000
Income of man = a * S * (d – c) = Rs. 5000
(a * d) – (b *c)
Income of woman = b * S * (d – c) = Rs. 3000
(a * d) – (b *c)
8. Share of B= [7/(5+7+13) ] * 1200 = Rs.336
Share of C = [13/(5+7+13)] * 1200 = Rs. 624
Difference of shares of C & B = Rs. 288

2. 9. Let no. of 1 rupee coins = 2K
No. of 50 paise coins = 3K
No. of 25 paise coins = 4K
2K + 0.5 (3K) + 0.25 (4K) = 216
K= 48
No. of 50 paise coins = 144
10. Overall loss= (5 *5)/100 = ¼ % loss
11. A alone can do the work in = 2 * 18 * 24 *36/ [(18*24)+(24*36)-(36*18)] = 48 days
12. Time taken = (L1 + L2)/ (S1 –S2)
L1 & L2 are lengths of the trains 1 & 2
S1 & S2 are speed of the Trains 1 & 2
Time taken = 60 seconds
2 2
13. The required distance = (x – y ) * t / (2*y)
x= 7 km/hr , y = 3 km/hr, t = 6 hours
Required distance = 40kms
14. Son’s age 5 years hence = x years
Father’s age five years hence = 3x years
7 (x-10) = 3x- 10
Father’s age = 40 years
2
15. Cost of article two years hence = 6 ( 1 + {1000 /100}) = 6 * 121 = Rs.726
16. Total no. of odd days= 1600 yrs have 0 odd days + 300 yrs have 1 odd day+ 49 yrs (37 non-
leap,12 leap yrs) have 5 odd days+ 26 days of January have 5 odd days = 0+1+5+5 = 4 odd days
Hence the day was THURSDAY
17. Let Mohan has Rs. y
Let Ram has Rs.x
2(x-30) = y+30 ----- (1)
x+10 = 3 (y-10) --------(2)
solving the linear equations, we get x =62,y=34
18. No. of ways in choosing one white square and one black square is given by:
32 C1 * 32C1 = 32 * 32 = 1024
No. of ways in which square lies in the same row (4 white squars,4 black squars, no. of rows = 8)
= 4C1 * 4C1 * 8 = 128
No. of ways in which square lies on same column = 128
Required no. of ways = 1024 – 128 -128 = 768
19. Let ‘A’ be the event of “getting sum 4”
A = {(1,3) (3,1) (2,2)}
3 = favourable outcomes
36-3 = 33 = unfavourable outcomes
Odds in favour of sum 4 = 3/33 = 1/11
20. nth term = a+ (n-1) d = 4n+1 .This gives d =4
21. Avg. runs of ‘A’ excluding innings where he scored zero = 994/19 = 52.31

3. Avg. runs scored by ‘B’ excluding innings where he scored zero = 751/18 = 41.72
Diff in averages = 10.59
22. avg. runs of C = (414 – 52 )/17 = 21.29
23. Diff. b/w two highest runs = 994 – 772 = 222
Diff. b/w two lowest runs = 653 -414 = 239
Diff. = 17 Lower by 17
24. Ratio of A & D = 141:94 = 3:2
25. Avg. runs of A = 994/20 = 49.70
Avg. runs of B = 751/20 = 37.55
Difference = 12.15
26. Resurrecting ( concerned with redesigning)
27. Sputtering
28. amusing
29. Cause & effect relationship
death causes people to mourn
victory causes people to celebrate
30. buoyancy:prerogative (both are unrelated terms)
31. boorish:rude (antonyms)
32. b) relevance of state origin
33. b) writing views on political science
34. d) Hard to notice the linkage of the theory with that of the practicality
35. a) too general
36. a) Madinah
37. c) Foodles
38. b) Cell phones
39. a) Intel 4004
40. a) R.K.Narayan
41. Compiler Error. In third line, when the function display is encountered, the compiler
doesn't know anything about the function display. It assumes the arguments and return
types to be integers, (which is the default type). When it sees the actual function display, the
arguments and type contradicts with what it has assumed previously. Hence a compile time
error occurs.
42. Here unary minus (or negation) operator is used twice. Same maths rules applies, i.e.
minus * minus= plus. However you cannot give like --2. Because -- operator can only be
applied to variables as a decrement operator (e.g., i--). 2 is a constant and not a variable.
43. sizeof(i)=1.Since the #define replaces the string int by the macro char
44. In the expression !i>14 , NOT (!) operator has more precedence than ‘ >’ symbol. ! is
a unary logical operator. !i (!10) is 0 (not of true is false). 0>14 is false (zero).

4. 45. p is pointing to character 'n'. str1 is pointing to character 'a' ++*p. "p is pointing to
'n' and that is incremented by one." the ASCII value of 'n' is 10, which is then
incremented to 11. The value of ++*p is 11. ++*str1, str1 is pointing to 'a' that is
incremented by 1 and it becomes 'b'. ASCII value of 'b' is 98.
Now performing (11 + 98 – 32), we get 77("M");
So we get the output 77 :: "M" (Ascii is 77).
46. p=&a [2] [2] [2] you declare only two 2D arrays, but you are trying to access the
third 2D (which you are not declared) it will print garbage values. *q=***a starting
address of a is assigned integer pointer. Now q is pointing to starting address of a. If you
print *q, it will print first element of 3D array.
47. Compiler Error. You should not initialize variables in declaration
48. The structure yy is nested within structure xx. Hence, the elements are of yy are to
be accessed through the instance of structure xx, which needs an instance of yy to be
known. If the instance is created after defining the structure the compiler will not know
about the instance relative to xx. Hence for nested structure yy you have to declare
member.
49. n - newline
b - backspace
r - linefeed
50. The arguments in a function call are pushed into the stack from left to right. The
evaluation is by popping out from the stack. and the evaluation is from right to left,
hence the result.