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KINEMATICS OF
1February 5, 2015 Kinematics of Machinery - Unit - I
MECHINERY
Example for Mechanism
2February 5, 2015 Kinematics of Machinery - Unit - I
Example for Mechanism
3February 5, 2015 Kinematics of Machinery - Unit - I
MACHINE
4February 5, 2015 Kinematics of Machinery - Unit - I
A machine is a mechanism or collection of
mechanisms, which transmit force from the
source of power to the resistance to be
overcome.
Though all machines are mechanisms, all
mechanisms are not machines
5February 5, 2015 Kinematics of Machinery - Unit - I
DYNAMIC/INERTIALOAD
Inertia load require acceleration
6February 5, 2015 Kinematics of Machinery - Unit - I
7February 5, 2015 Kinematics of Machinery - Unit - I
8February 5, 2015 Kinematics of Machinery - Unit - I
9February 5, 2015 Kinematics of Machinery - Unit - I
LINK OR ELEMENT
Any body (normally rigid) which has motion
relative to another
 Binary link
 Ternary link
 Quaternary link
Kinematics of Machinery - Unit - I 10February 5, 2015
KINEMATIC PAIRS
Kinematics of Machinery - Unit - I 11February 5, 2015
 A mechanism has been defined as a combination so
connected that each moves with respect to each other.
A clue to the behavior lies in in the nature of
connections, known as kinetic pairs. The degree of
freedom of a kinetic pair is given by the number
independent coordinates required to completely
specify the relative movement.
TYPES OF KINEMATIC PAIRS
Kinematics of Machinery - Unit - I 12February 5, 2015
Based on nature of contact
between elements
 (i) Lower pair : The joint
by which two members are
connected has surface
contact. A pair is said to bea
lower pair
connection between
when the
two
elements are through the
area of contact. Its 6 types
are
Revolute(Or)TurningPair
Prismatic(Or)SlidingPair
Screw(Or)HelicalPair
CylindricalPair
Spherical(Or)GlobularPair
Flat(or)PlanarPair
(ii) Higher pair: The contact between the
pairing elements takes place at a point or along
a line.
Kinematics of Machinery - Unit - I 13February 5, 2015
Based on relative motion between pairing elements
(a)Siding pair [DOF = 1]
(b)Turning pair (revolute pair)
[DOF = 1]
Kinematics of Machinery - Unit - I 14February 5, 2015
Based on relative motion between pairing
elements
(c) Cylindrical pair [DOF = 2]
(d) Rolling pair
[DOF = 1]
Kinematics of Machinery - Unit - I 15February 5, 2015
Based on relative motion between pairing
elements
(e) Spherical pair [DOF = 3]
(f) Helical pair or screw pair [DOF = 1]
Kinematics of Machinery - Unit - I 16February 5, 2015
Based on the nature of mechanical constraint
(a) Closed pair
(b) Unclosed or force closed pair
Kinematics of Machinery - Unit - I 17February 5, 2015
CONSTRAINED MOTION
Kinematics of Machinery - Unit - I 18February 5, 2015
one element has got only one definite motion
relative to the other
(a) Completely constrained motion
Kinematics of Machinery - Unit - I 19February 5, 2015
(b) Successfully constrained motion
February 5, 2015 Kinematics of Machinery - Unit - I 20
(c) Incompletely constrained motion
February 5, 2015 Kinematics of Machinery - Unit - I 21
KINEMATIC CHAIN
February 5, 2015 Kinematics of Machinery - Unit - I 22
Group of links either joined together or
arranged in a manner that permits them to
move relative to one another.
Kinematic Chain
Relation between Links, Pairs and Joints
L=2P-4
J=(3/2) L – 2
L => No of Links
P => No of Pairs
J => No of Joints
L.H.S > R.H.S => Locked chain
L.H.S = R.H.S => Constrained Kinematic Chain
L.H.S < R.H.S => Unconstrained Kinematic
Chain
February 5, 2015 Kinematics of Machinery - Unit - I 23
LOCKED CHAIN (Or) STRUCTURE
Links connected in such a way that no relative
motion is possible.
L=3, J=3, P=3 L.H.S>R.H.S
February 5, 2015 Kinematics of Machinery - Unit - I 24
Kinematic Chain Mechanism
Slider crank and four bar mechanisms
L=4, J=4, P=4
L.H.S=R.H.S
February 5, 2015 Kinematics of Machinery - Unit - I 25
Working of slider crank mechanism
February 5, 2015 Kinematics of Machinery - Unit - I 26
Unconstrained kinematic chain
L=5,P=5,J=5
L.H.S < R.H.S
February 5, 2015 Kinematics of Machinery - Unit - I 27
DEGREES OF FREEDOM (DOF):
It is the number of independent coordinates required to
describe the position of a body.
February 5, 2015 Kinematics of Machinery - Unit - I 28
Degrees of freedom/mobility of a
mechanism
February 5, 2015 Kinematics of Machinery - Unit - I 29
It is the number of inputs (number of
independent coordinates) required to describe
the configuration or position of all the links of
the mechanism, with respect to the fixed link
at any given instant.
GRUBLER’S CRITERION
February 5, 2015 Kinematics of Machinery - Unit - I 30
Number of degrees of freedom of a mechanism is given by
F = 3(n-1)-2l-h. Where,




F = Degrees of freedom
n = Number of links in the mechanism.
l = Number of lower pairs, which is obtained by counting the
number of joints. If more than two links are joined together at any
point, then, one additional lower pair is to be considered for every
additional link.
h = Number of higher pairs
Examples - DOF




F = 3(n-1)-2l-h
Here, n = 4, l = 4 & h = 0.
F = 3(4-1)-2(4) = 1
I.e., one input to any one link
will result in definite motion
of all the links.
February 5, 2015 Kinematics of Machinery - Unit - I 31
Examples - DOF




F = 3(n-1)-2l-h
Here, n = 5, l = 5 and h = 0.
F = 3(5-1)-2(5) = 2
I.e., two inputs to any two links are
required to yield definite motions in
all the links.
February 5, 2015 Kinematics of Machinery - Unit - I 32
Examples - DOF




F = 3(n-1)-2l-h
Here, n = 6, l = 7 and h = 0.
F = 3(6-1)-2(7) = 1
I.e., one input to any one link will result in
definite motion of all the links.
February 5, 2015 Kinematics of Machinery - Unit - I 33
Examples - DOF



F = 3(n-1)-2l-h
Here, n = 6, l = 7 (at the intersection of
2, 3 and 4, two lower pairs are to be
considered) and h = 0.
F = 3(6-1)-2(7) = 1
February 5, 2015 Kinematics of Machinery - Unit - I 34
Examples - DOF


F = 3(n-1)-2l-h
Here, n = 11, l = 15 (two lower
pairs at the intersection of 3, 4,
6; 2, 4, 5; 5, 7, 8; 8, 10, 11) and

h = 0.
F = 3(11-1)-2(15) = 0
February 5, 2015 Kinematics of Machinery - Unit - I 35
Examples - DOF
(a)
F = 3(n-1)-2l-h
Here, n = 4, l = 5 and h = 0.
F = 3(4-1)-2(5) = -1
I.e., it is a structure
(b)
F = 3(n-1)-2l-h
Here, n = 3, l = 2 and h = 1.
F = 3(3-1)-2(2)-1 = 1
(c)
F = 3(n-1)-2l-h
Here, n = 3, l = 2 and h = 1.
F = 3(3-1)-2(2)-1 = 1
February 5, 2015 Kinematics of Machinery - Unit - I 36
Grashoff Law
 The sum of the shortest
and longest link length
should not exceed the
sum of the other two
link lengths.
s+l < p+q
(e.x) (1+2) < (3+4)
February 5, 2015 Kinematics of Machinery - Unit - I 37
INVERSIONS OF MECHANISM
February 5, 2015 Kinematics of Machinery - Unit - I 38
A mechanism is one in which one of the links of a kinematic
chain is fixed. Different mechanisms can be obtained by fixing
different links of the same kinematic chain. These are called as
inversions of the mechanism.
INVERSIONS OF MECHANISM
 1.Four Bar Chain
 2.Single Slider Crank
 3.Double Slider Crank
February 5, 2015 Kinematics of Machinery - Unit - I 39
1.Four Bar Chain - Inversions
February 5, 2015 Kinematics of Machinery - Unit - I 40
Beam Engine (crank &Lever)
February 5, 2015 Kinematics of Machinery - Unit - I 41
February 5, 2015 Kinematics of Machinery - Unit - I 42
Double Crank Msm
February 5, 2015 Kinematics of Machinery - Unit - I 43
Double Lever
February 5, 2015 Kinematics of Machinery - Unit - I 44
2.Single Slider Crank _
Inversions
February 5, 2015 Kinematics of Machinery - Unit - I 45
Single Slider Crank _ Inversions
1.PENDULUM PUMP
February 5, 2015 Kinematics of Machinery - Unit - I 46
February 5, 2015 Kinematics of Machinery - Unit - I 47
February 5, 2015 Kinematics of Machinery - Unit - I 48
2.OSCILLATING CYLINDER
February 5, 2015 Kinematics of Machinery - Unit - I 49
February 5, 2015 Kinematics of Machinery - Unit - I 50
February 5, 2015 Kinematics of Machinery - Unit - I 51
3.ROTARY IC ENGINE
February 5, 2015 Kinematics of Machinery - Unit - I 52
February 5, 2015 Kinematics of Machinery - Unit - I 53
February 5, 2015 Kinematics of Machinery - Unit - I 54
4.Crank and Slotted Lever Mechanism
(Quick-Return Motion Mechanism)
February 5, 2015 Kinematics of Machinery - Unit - I 55
Basic Quick-Return
February 5, 2015 Kinematics of Machinery - Unit - I 56
Quick-Return IN SHAPER M/C
February 5, 2015 Kinematics of Machinery - Unit - I 57
February 5, 2015 Kinematics of Machinery - Unit - I 58
WHIT WORTH QUICK-
RETURN
February 5, 2015 Kinematics of Machinery - Unit - I 59
February 5, 2015 Kinematics of Machinery - Unit - I 60
3.Double Slider Crank
INVERSIONS
February 5, 2015 Kinematics of Machinery - Unit - I 61
ELLIPTICAL TRAMMEL
February 5, 2015 Kinematics of Machinery - Unit - I 62
February 5, 2015 Kinematics of Machinery - Unit - I 63
OLD HAMS COUPLING
February 5, 2015 Kinematics of Machinery - Unit - I 64
February 5, 2015 Kinematics of Machinery - Unit - I 65
February 5, 2015 Kinematics of Machinery - Unit - I 66
February 5, 2015 Kinematics of Machinery - Unit - I 67
February 5, 2015 Kinematics of Machinery - Unit - I 68
1. FOUR BAR CHAIN




(link 1) frame
(link 2) crank
(link 3) coupler
(link 4) rocker
February 5, 2015 Kinematics of Machinery - Unit - I 69
INVERSIONS OF FOUR BAR CHAIN
Fix link 1& 3. Crank-rocker
or Crank-Lever
mechanism
Fix link 2. Drag link
or Double Crank
mechanism
Fix link 4. Double rocker
mechanism
Pantograph
Kinematics of Machinery - Unit - IFebruary 5, 2015 70
APPLICATION
link-1 fixed-
CRANK-ROCKER MECHANISM
OSCILLATORY MOTION
Kinematics of Machinery - Unit - IFebruary 5, 2015 71
CRANK-ROCKER
MECHANISM
Kinematics of Machinery - Unit - IFebruary 5, 2015 72
Link 2 Fixed- DRAG LINK
MECHANISM
Kinematics of Machinery - Unit - IFebruary 5, 2015 73
Locomotive Wheel - DOUBLE
CRANK MECHANISM
Kinematics of Machinery - Unit - IFebruary 5, 2015 74
2.SLIDER CRANK CHAIN
Link1=Ground
Link2=Crank
Link3=ConnectingRod
Link4=Slider
Kinematics of Machinery - Unit - IFebruary 5, 2015 75
lnversions of slider crank chain
(a) crank fixed
Link 2 fixed
(b) connecting rod fixed
Link 3 fixed
(c) slider fixed
Link 4 fixed
Kinematics of Machinery - Unit - IFebruary 5, 2015 76
Application
Inversion II – Link 2 Crank fixed
Whitworth quick return motion mechanism
Timeforforwardstroke

Boˆ2B 

1
Timeforreturnstroke B oˆ2B 2
Kinematics of Machinery - Unit - IFebruary 5, 2015 77
Quick return motion mechanisms
Drag link mechanism
B2 AˆB1
Kinematics of Machinery - Unit - IFebruary 5, 2015 78
Timeforreturnstroke
Timeforforwardstroke

B1AˆB2
of slider crankRotary engine– II inversion
mechanism. (crank fixed)
Kinematics of Machinery - Unit - IFebruary 5, 2015 79
Application
Inversion III -Link 3 Connecting rod fixed
Crank and slotted lever quick return mechanism
Timeforforwardstroke

Boˆ2B 

1
Timeforreturnstroke B oˆ2B 2
Kinematics of Machinery - Unit - IFebruary 5, 2015 80
Crank and slotted lever quick return
motion mechanism
Kinematics of Machinery - Unit - IFebruary 5, 2015 81
Crank and slotted lever quick return motion
mechanism
Kinematics of Machinery - Unit - IFebruary 5, 2015 82
Application of Crank and slotted lever quick
return motion mechanism
Kinematics of Machinery - Unit - IFebruary 5, 2015 83
Oscillating cylinder engine–III inversion of
slider crank mechanism (connecting rod fixed)
Kinematics of Machinery - Unit - IFebruary 5, 2015 84
Application
Inversion IV – Link 4 Slider fixed
Pendulum pump or bull engine
Kinematics of Machinery - Unit - IFebruary 5, 2015 85
3. DOUBLE SLIDER CRANK
CHAIN
Kinematics of Machinery - Unit - IFebruary 5, 2015 86
It is a kinematic chain consisting of two
turning pairs and two sliding pairs.
Link 1 Frame
Link 2 Slider -I
Link 3 Coupler
Link 4 Slider - II
Inversion I – Frame Fixed
Double slider crank mechanism
   cos2
  sin 2
 1
 y 
2
 
 q   p 
 x 
2
 x 
2
 y 
2
      cos2
  sin 2
  1
 q   p 
Elliptical trammel
AC = p and BC = q, then,
x = q.cosθ and y = p.sinθ.
Rearranging,
Kinematics of Machinery - Unit - IFebruary 5, 2015 87
Inversion II – Slider - I Fixed
SCOTCH –YOKE MECHANISM
Turning pairs –1&2, 2&3; Sliding pairs – 3&4,
4&1
Kinematics of Machinery - Unit - IFebruary 5, 2015 88
Inversion III – Coupler Fixed
OLDHAM COUPLING
Kinematics of Machinery - Unit - IFebruary 5, 2015 89
Other Mechanisms
1.Straight line motion mechanisms
Condition for perfect steering
Locus of pt.C will be a
straight line, ┴ to AE if,
AB AC
AC AE
 AE 
AB  AC
AD
butAD  const.
 AE  const.,ifAB  AC  const.
Kinematics of Machinery - Unit - IFebruary 5, 2015 90
is constant.
Proof:
AEC  ABD

AD

AB
1.a) Peaucellier mechanism
Kinematics of Machinery - Unit - IFebruary 5, 2015 91
1.b) Robert’s mechanism
Kinematics of Machinery - Unit - IFebruary 5, 2015 92
1.c) Pantograph
Kinematics of Machinery - Unit - IFebruary 5, 2015 93
2.Indexing Mechanism
Geneva wheel mechanism
Kinematics of Machinery - Unit - IFebruary 5, 2015 94
3.Ratchets and Escapements
Ratchet and pawl mechanism
Kinematics of Machinery - Unit - IFebruary 5, 2015 95
Application of Ratchet Pawl mechanism
Kinematics of Machinery - Unit - IFebruary 5, 2015 96
4. Toggle mechanism
Considering the
condition ofequilibrium
slider 6,
F
Kinematics of Machinery - Unit - IFebruary 5, 2015 97
P
 F  2P tan
For small angles of α, F is
much smaller than P.
tan  2
5.Hooke’s joint
Kinematics of Machinery - Unit - IFebruary 5, 2015 98
Hooke’s joint
Kinematics of Machinery - Unit - IFebruary 5, 2015 99
6.Steering gear mechanism
Condition for perfect steering
Kinematics of Machinery - Unit - I 100February 5, 2015
Ackermann steering gear mechanism
Kinematics of Machinery - Unit - I 101February 5, 2015
Mechanical
Advantage
 Mechanical Advantage
of the Mechanism at
angle a2 = 00or 1800
 Extreme position of the
linkage is known as
toggle positions.
Kinematics of Machinery - Unit - I 102February 5, 2015
Transmission
Angle
θ = a1=Crank Angle
γ = a2 =Angle between
crank and Coupler
μ = a3 =Transmission angle
Cosine Law
a2+ d2-2ad cos θ =
b2+ c2-2 bc cos μ
Where a=AD, b=CD,
c=BC, d=AB
Determine μ.
Kinematics of Machinery - Unit - I 103February 5, 2015
Design of
Mechanism
 1.Slider – Crank Mechanism
Link Lengths, Stroke Length,
Crank Angle specified.


2.Offset Quick Return
Mechanism
Link Lengths, Stroke Length,
Crank Angle, Time Ratio
specified.
3.Four Bar Mechanism –
Crank Rocker Mechanism
Link Lengths and Rocker
angle Specified.
Kinematics of Machinery - Unit - I 104February 5, 2015
ALL THE BEST
Kinematics of Machinery - Unit - I 105February 5, 2015

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Kom ppt unit1

  • 1. KINEMATICS OF 1February 5, 2015 Kinematics of Machinery - Unit - I MECHINERY
  • 2. Example for Mechanism 2February 5, 2015 Kinematics of Machinery - Unit - I
  • 3. Example for Mechanism 3February 5, 2015 Kinematics of Machinery - Unit - I
  • 4. MACHINE 4February 5, 2015 Kinematics of Machinery - Unit - I A machine is a mechanism or collection of mechanisms, which transmit force from the source of power to the resistance to be overcome.
  • 5. Though all machines are mechanisms, all mechanisms are not machines 5February 5, 2015 Kinematics of Machinery - Unit - I
  • 6. DYNAMIC/INERTIALOAD Inertia load require acceleration 6February 5, 2015 Kinematics of Machinery - Unit - I
  • 7. 7February 5, 2015 Kinematics of Machinery - Unit - I
  • 8. 8February 5, 2015 Kinematics of Machinery - Unit - I
  • 9. 9February 5, 2015 Kinematics of Machinery - Unit - I
  • 10. LINK OR ELEMENT Any body (normally rigid) which has motion relative to another  Binary link  Ternary link  Quaternary link Kinematics of Machinery - Unit - I 10February 5, 2015
  • 11. KINEMATIC PAIRS Kinematics of Machinery - Unit - I 11February 5, 2015  A mechanism has been defined as a combination so connected that each moves with respect to each other. A clue to the behavior lies in in the nature of connections, known as kinetic pairs. The degree of freedom of a kinetic pair is given by the number independent coordinates required to completely specify the relative movement.
  • 12. TYPES OF KINEMATIC PAIRS Kinematics of Machinery - Unit - I 12February 5, 2015 Based on nature of contact between elements  (i) Lower pair : The joint by which two members are connected has surface contact. A pair is said to bea lower pair connection between when the two elements are through the area of contact. Its 6 types are Revolute(Or)TurningPair Prismatic(Or)SlidingPair Screw(Or)HelicalPair CylindricalPair Spherical(Or)GlobularPair Flat(or)PlanarPair
  • 13. (ii) Higher pair: The contact between the pairing elements takes place at a point or along a line. Kinematics of Machinery - Unit - I 13February 5, 2015
  • 14. Based on relative motion between pairing elements (a)Siding pair [DOF = 1] (b)Turning pair (revolute pair) [DOF = 1] Kinematics of Machinery - Unit - I 14February 5, 2015
  • 15. Based on relative motion between pairing elements (c) Cylindrical pair [DOF = 2] (d) Rolling pair [DOF = 1] Kinematics of Machinery - Unit - I 15February 5, 2015
  • 16. Based on relative motion between pairing elements (e) Spherical pair [DOF = 3] (f) Helical pair or screw pair [DOF = 1] Kinematics of Machinery - Unit - I 16February 5, 2015
  • 17. Based on the nature of mechanical constraint (a) Closed pair (b) Unclosed or force closed pair Kinematics of Machinery - Unit - I 17February 5, 2015
  • 18. CONSTRAINED MOTION Kinematics of Machinery - Unit - I 18February 5, 2015 one element has got only one definite motion relative to the other
  • 19. (a) Completely constrained motion Kinematics of Machinery - Unit - I 19February 5, 2015
  • 20. (b) Successfully constrained motion February 5, 2015 Kinematics of Machinery - Unit - I 20
  • 21. (c) Incompletely constrained motion February 5, 2015 Kinematics of Machinery - Unit - I 21
  • 22. KINEMATIC CHAIN February 5, 2015 Kinematics of Machinery - Unit - I 22 Group of links either joined together or arranged in a manner that permits them to move relative to one another.
  • 23. Kinematic Chain Relation between Links, Pairs and Joints L=2P-4 J=(3/2) L – 2 L => No of Links P => No of Pairs J => No of Joints L.H.S > R.H.S => Locked chain L.H.S = R.H.S => Constrained Kinematic Chain L.H.S < R.H.S => Unconstrained Kinematic Chain February 5, 2015 Kinematics of Machinery - Unit - I 23
  • 24. LOCKED CHAIN (Or) STRUCTURE Links connected in such a way that no relative motion is possible. L=3, J=3, P=3 L.H.S>R.H.S February 5, 2015 Kinematics of Machinery - Unit - I 24
  • 25. Kinematic Chain Mechanism Slider crank and four bar mechanisms L=4, J=4, P=4 L.H.S=R.H.S February 5, 2015 Kinematics of Machinery - Unit - I 25
  • 26. Working of slider crank mechanism February 5, 2015 Kinematics of Machinery - Unit - I 26
  • 27. Unconstrained kinematic chain L=5,P=5,J=5 L.H.S < R.H.S February 5, 2015 Kinematics of Machinery - Unit - I 27
  • 28. DEGREES OF FREEDOM (DOF): It is the number of independent coordinates required to describe the position of a body. February 5, 2015 Kinematics of Machinery - Unit - I 28
  • 29. Degrees of freedom/mobility of a mechanism February 5, 2015 Kinematics of Machinery - Unit - I 29 It is the number of inputs (number of independent coordinates) required to describe the configuration or position of all the links of the mechanism, with respect to the fixed link at any given instant.
  • 30. GRUBLER’S CRITERION February 5, 2015 Kinematics of Machinery - Unit - I 30 Number of degrees of freedom of a mechanism is given by F = 3(n-1)-2l-h. Where,     F = Degrees of freedom n = Number of links in the mechanism. l = Number of lower pairs, which is obtained by counting the number of joints. If more than two links are joined together at any point, then, one additional lower pair is to be considered for every additional link. h = Number of higher pairs
  • 31. Examples - DOF     F = 3(n-1)-2l-h Here, n = 4, l = 4 & h = 0. F = 3(4-1)-2(4) = 1 I.e., one input to any one link will result in definite motion of all the links. February 5, 2015 Kinematics of Machinery - Unit - I 31
  • 32. Examples - DOF     F = 3(n-1)-2l-h Here, n = 5, l = 5 and h = 0. F = 3(5-1)-2(5) = 2 I.e., two inputs to any two links are required to yield definite motions in all the links. February 5, 2015 Kinematics of Machinery - Unit - I 32
  • 33. Examples - DOF     F = 3(n-1)-2l-h Here, n = 6, l = 7 and h = 0. F = 3(6-1)-2(7) = 1 I.e., one input to any one link will result in definite motion of all the links. February 5, 2015 Kinematics of Machinery - Unit - I 33
  • 34. Examples - DOF    F = 3(n-1)-2l-h Here, n = 6, l = 7 (at the intersection of 2, 3 and 4, two lower pairs are to be considered) and h = 0. F = 3(6-1)-2(7) = 1 February 5, 2015 Kinematics of Machinery - Unit - I 34
  • 35. Examples - DOF   F = 3(n-1)-2l-h Here, n = 11, l = 15 (two lower pairs at the intersection of 3, 4, 6; 2, 4, 5; 5, 7, 8; 8, 10, 11) and  h = 0. F = 3(11-1)-2(15) = 0 February 5, 2015 Kinematics of Machinery - Unit - I 35
  • 36. Examples - DOF (a) F = 3(n-1)-2l-h Here, n = 4, l = 5 and h = 0. F = 3(4-1)-2(5) = -1 I.e., it is a structure (b) F = 3(n-1)-2l-h Here, n = 3, l = 2 and h = 1. F = 3(3-1)-2(2)-1 = 1 (c) F = 3(n-1)-2l-h Here, n = 3, l = 2 and h = 1. F = 3(3-1)-2(2)-1 = 1 February 5, 2015 Kinematics of Machinery - Unit - I 36
  • 37. Grashoff Law  The sum of the shortest and longest link length should not exceed the sum of the other two link lengths. s+l < p+q (e.x) (1+2) < (3+4) February 5, 2015 Kinematics of Machinery - Unit - I 37
  • 38. INVERSIONS OF MECHANISM February 5, 2015 Kinematics of Machinery - Unit - I 38 A mechanism is one in which one of the links of a kinematic chain is fixed. Different mechanisms can be obtained by fixing different links of the same kinematic chain. These are called as inversions of the mechanism.
  • 39. INVERSIONS OF MECHANISM  1.Four Bar Chain  2.Single Slider Crank  3.Double Slider Crank February 5, 2015 Kinematics of Machinery - Unit - I 39
  • 40. 1.Four Bar Chain - Inversions February 5, 2015 Kinematics of Machinery - Unit - I 40
  • 41. Beam Engine (crank &Lever) February 5, 2015 Kinematics of Machinery - Unit - I 41
  • 42. February 5, 2015 Kinematics of Machinery - Unit - I 42
  • 43. Double Crank Msm February 5, 2015 Kinematics of Machinery - Unit - I 43
  • 44. Double Lever February 5, 2015 Kinematics of Machinery - Unit - I 44
  • 45. 2.Single Slider Crank _ Inversions February 5, 2015 Kinematics of Machinery - Unit - I 45
  • 46. Single Slider Crank _ Inversions 1.PENDULUM PUMP February 5, 2015 Kinematics of Machinery - Unit - I 46
  • 47. February 5, 2015 Kinematics of Machinery - Unit - I 47
  • 48. February 5, 2015 Kinematics of Machinery - Unit - I 48
  • 49. 2.OSCILLATING CYLINDER February 5, 2015 Kinematics of Machinery - Unit - I 49
  • 50. February 5, 2015 Kinematics of Machinery - Unit - I 50
  • 51. February 5, 2015 Kinematics of Machinery - Unit - I 51
  • 52. 3.ROTARY IC ENGINE February 5, 2015 Kinematics of Machinery - Unit - I 52
  • 53. February 5, 2015 Kinematics of Machinery - Unit - I 53
  • 54. February 5, 2015 Kinematics of Machinery - Unit - I 54
  • 55. 4.Crank and Slotted Lever Mechanism (Quick-Return Motion Mechanism) February 5, 2015 Kinematics of Machinery - Unit - I 55
  • 56. Basic Quick-Return February 5, 2015 Kinematics of Machinery - Unit - I 56
  • 57. Quick-Return IN SHAPER M/C February 5, 2015 Kinematics of Machinery - Unit - I 57
  • 58. February 5, 2015 Kinematics of Machinery - Unit - I 58
  • 59. WHIT WORTH QUICK- RETURN February 5, 2015 Kinematics of Machinery - Unit - I 59
  • 60. February 5, 2015 Kinematics of Machinery - Unit - I 60
  • 61. 3.Double Slider Crank INVERSIONS February 5, 2015 Kinematics of Machinery - Unit - I 61
  • 62. ELLIPTICAL TRAMMEL February 5, 2015 Kinematics of Machinery - Unit - I 62
  • 63. February 5, 2015 Kinematics of Machinery - Unit - I 63
  • 64. OLD HAMS COUPLING February 5, 2015 Kinematics of Machinery - Unit - I 64
  • 65. February 5, 2015 Kinematics of Machinery - Unit - I 65
  • 66. February 5, 2015 Kinematics of Machinery - Unit - I 66
  • 67. February 5, 2015 Kinematics of Machinery - Unit - I 67
  • 68. February 5, 2015 Kinematics of Machinery - Unit - I 68
  • 69. 1. FOUR BAR CHAIN     (link 1) frame (link 2) crank (link 3) coupler (link 4) rocker February 5, 2015 Kinematics of Machinery - Unit - I 69
  • 70. INVERSIONS OF FOUR BAR CHAIN Fix link 1& 3. Crank-rocker or Crank-Lever mechanism Fix link 2. Drag link or Double Crank mechanism Fix link 4. Double rocker mechanism Pantograph Kinematics of Machinery - Unit - IFebruary 5, 2015 70
  • 71. APPLICATION link-1 fixed- CRANK-ROCKER MECHANISM OSCILLATORY MOTION Kinematics of Machinery - Unit - IFebruary 5, 2015 71
  • 72. CRANK-ROCKER MECHANISM Kinematics of Machinery - Unit - IFebruary 5, 2015 72
  • 73. Link 2 Fixed- DRAG LINK MECHANISM Kinematics of Machinery - Unit - IFebruary 5, 2015 73
  • 74. Locomotive Wheel - DOUBLE CRANK MECHANISM Kinematics of Machinery - Unit - IFebruary 5, 2015 74
  • 76. lnversions of slider crank chain (a) crank fixed Link 2 fixed (b) connecting rod fixed Link 3 fixed (c) slider fixed Link 4 fixed Kinematics of Machinery - Unit - IFebruary 5, 2015 76
  • 77. Application Inversion II – Link 2 Crank fixed Whitworth quick return motion mechanism Timeforforwardstroke  Boˆ2B   1 Timeforreturnstroke B oˆ2B 2 Kinematics of Machinery - Unit - IFebruary 5, 2015 77
  • 78. Quick return motion mechanisms Drag link mechanism B2 AˆB1 Kinematics of Machinery - Unit - IFebruary 5, 2015 78 Timeforreturnstroke Timeforforwardstroke  B1AˆB2
  • 79. of slider crankRotary engine– II inversion mechanism. (crank fixed) Kinematics of Machinery - Unit - IFebruary 5, 2015 79
  • 80. Application Inversion III -Link 3 Connecting rod fixed Crank and slotted lever quick return mechanism Timeforforwardstroke  Boˆ2B   1 Timeforreturnstroke B oˆ2B 2 Kinematics of Machinery - Unit - IFebruary 5, 2015 80
  • 81. Crank and slotted lever quick return motion mechanism Kinematics of Machinery - Unit - IFebruary 5, 2015 81
  • 82. Crank and slotted lever quick return motion mechanism Kinematics of Machinery - Unit - IFebruary 5, 2015 82
  • 83. Application of Crank and slotted lever quick return motion mechanism Kinematics of Machinery - Unit - IFebruary 5, 2015 83
  • 84. Oscillating cylinder engine–III inversion of slider crank mechanism (connecting rod fixed) Kinematics of Machinery - Unit - IFebruary 5, 2015 84
  • 85. Application Inversion IV – Link 4 Slider fixed Pendulum pump or bull engine Kinematics of Machinery - Unit - IFebruary 5, 2015 85
  • 86. 3. DOUBLE SLIDER CRANK CHAIN Kinematics of Machinery - Unit - IFebruary 5, 2015 86 It is a kinematic chain consisting of two turning pairs and two sliding pairs. Link 1 Frame Link 2 Slider -I Link 3 Coupler Link 4 Slider - II
  • 87. Inversion I – Frame Fixed Double slider crank mechanism    cos2   sin 2  1  y  2    q   p   x  2  x  2  y  2       cos2   sin 2   1  q   p  Elliptical trammel AC = p and BC = q, then, x = q.cosθ and y = p.sinθ. Rearranging, Kinematics of Machinery - Unit - IFebruary 5, 2015 87
  • 88. Inversion II – Slider - I Fixed SCOTCH –YOKE MECHANISM Turning pairs –1&2, 2&3; Sliding pairs – 3&4, 4&1 Kinematics of Machinery - Unit - IFebruary 5, 2015 88
  • 89. Inversion III – Coupler Fixed OLDHAM COUPLING Kinematics of Machinery - Unit - IFebruary 5, 2015 89
  • 90. Other Mechanisms 1.Straight line motion mechanisms Condition for perfect steering Locus of pt.C will be a straight line, ┴ to AE if, AB AC AC AE  AE  AB  AC AD butAD  const.  AE  const.,ifAB  AC  const. Kinematics of Machinery - Unit - IFebruary 5, 2015 90 is constant. Proof: AEC  ABD  AD  AB
  • 91. 1.a) Peaucellier mechanism Kinematics of Machinery - Unit - IFebruary 5, 2015 91
  • 92. 1.b) Robert’s mechanism Kinematics of Machinery - Unit - IFebruary 5, 2015 92
  • 93. 1.c) Pantograph Kinematics of Machinery - Unit - IFebruary 5, 2015 93
  • 94. 2.Indexing Mechanism Geneva wheel mechanism Kinematics of Machinery - Unit - IFebruary 5, 2015 94
  • 95. 3.Ratchets and Escapements Ratchet and pawl mechanism Kinematics of Machinery - Unit - IFebruary 5, 2015 95
  • 96. Application of Ratchet Pawl mechanism Kinematics of Machinery - Unit - IFebruary 5, 2015 96
  • 97. 4. Toggle mechanism Considering the condition ofequilibrium slider 6, F Kinematics of Machinery - Unit - IFebruary 5, 2015 97 P  F  2P tan For small angles of α, F is much smaller than P. tan  2
  • 98. 5.Hooke’s joint Kinematics of Machinery - Unit - IFebruary 5, 2015 98
  • 99. Hooke’s joint Kinematics of Machinery - Unit - IFebruary 5, 2015 99
  • 100. 6.Steering gear mechanism Condition for perfect steering Kinematics of Machinery - Unit - I 100February 5, 2015
  • 101. Ackermann steering gear mechanism Kinematics of Machinery - Unit - I 101February 5, 2015
  • 102. Mechanical Advantage  Mechanical Advantage of the Mechanism at angle a2 = 00or 1800  Extreme position of the linkage is known as toggle positions. Kinematics of Machinery - Unit - I 102February 5, 2015
  • 103. Transmission Angle θ = a1=Crank Angle γ = a2 =Angle between crank and Coupler μ = a3 =Transmission angle Cosine Law a2+ d2-2ad cos θ = b2+ c2-2 bc cos μ Where a=AD, b=CD, c=BC, d=AB Determine μ. Kinematics of Machinery - Unit - I 103February 5, 2015
  • 104. Design of Mechanism  1.Slider – Crank Mechanism Link Lengths, Stroke Length, Crank Angle specified.   2.Offset Quick Return Mechanism Link Lengths, Stroke Length, Crank Angle, Time Ratio specified. 3.Four Bar Mechanism – Crank Rocker Mechanism Link Lengths and Rocker angle Specified. Kinematics of Machinery - Unit - I 104February 5, 2015
  • 105. ALL THE BEST Kinematics of Machinery - Unit - I 105February 5, 2015