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Suez University 
Faculty of Petroleum & Mining Engineering 
Porosity and Permeability 
Student 
Belal Farouk El-saied Ibrahim 
Class / III 
Section / Engineering Geology and Geophysics 
Presented to 
Prof. Dr. / Ali Abbas
Porosity and Permeability 
Both are important properties that are related to fluids in sediment and 
sedimentary rocks. 
Fluids can include: water, hydrocarbons, spilled contaminants. 
Most aquifers are in sediment or sedimentary rocks. 
Virtually all hydrocarbons are contained in sedimentary rocks. 
Porosity: the volume of void space (available to contain fluid or air) in a 
sediment or sedimentary rock. 
Permeability: related to how easily a fluid will pass through any 
granular material.
I. Porosity (P) 
The proportion of any material that is void space, expressed as a 
percentage of the total volume of material. 
V 
100 P 
T 
P 
  
V 
Where VP is the total volume of pore space 
and VT is the total volume of rock or 
sediment. 
In practice, porosity is commonly based on measurement of the total 
grain volume of a granular material: 
V  
V 
100 T G 
  
T 
P 
V 
Where VG is the total volume of 
grains within the total volume of 
rock or sediment. 
VP VT VG
Porosity varies from 0% to 70% in natural sediments but exceeds 70% 
for freshly deposited mud. 
Several factors control porosity. 
a) Packing Density 
Packing density: the arrangement of the particles in the deposit. 
The more densely packed the particles the lower the porosity. 
e.g., perfect spheres of uniform size. 
Porosity can vary 
from 48% to 26%.
Shape has an important effect on packing. 
Tabular rectangular particles can vary from 0% to just under 50%: 
Natural particles such as shells can have very high porosity:
In general, the greater the angularity of the particles the more open the 
framework (more open fabric) and the greater the possible porosity. 
b) Grain Size 
On its own, grain size has no influence on porosity! 
Consider a cube of sediment of 
perfect spheres with cubic 
packing. 
V  
V 
100 T G 
  
T 
P 
V 
d = sphere diameter; n = number of grains along a side (5 in this example).
V  
V 
100 T G 
  
T 
P 
V 
Length of a side of the cube = d  n = dn 
Volume of the cube (VT): 
Total number of grains: n  n  n = n3 
 
 
Volume of a single grain: 3 
V d 
6 
Total volume of grains (VG): 
  
3 3 3 3 
V  n  d  
n d 
G 6 6 3 3 
VT  dn dn dn  d n
V  
V 
 
 33 
  3 3 
100 T G 
T 
P 
V 
6 G V n d 
TV d n  Where: and 
 
3 3 3 3 
d n n d 
6 100 
 
Therefore:   
3 3 
P 
d n 
   
   
3 3 
1 
6 
Rearranging:     
3 3 
100 
d n 
P 
d n 
Therefore: 1 100 48% 
6 
P 
   
     
  
d (grain size) does not affect the porosity so that porosity is independent 
of grains size. 
No matter how large or small the spherical grains in cubic packing have 
a porosity is 48%.
There are some indirect relationships between size and porosity. 
i) Large grains have higher settling velocities than small grains. 
When grains settle through a fluid the large grains will impact the 
substrate with larger momentum, possibly jostling the grains into tighter 
packing (therefore with lower porosity). 
Unconsolidated sands tend to 
decrease in porosity with 
increasing grain size. 
Consolidated sands tend to 
increase in porosity with 
increasing grain size. 
ii) A shape effect.
Generally, unconsolidated sands undergo little burial and less 
compaction than consolidated sands. 
Fine sand has slightly higher porosity. 
Fine sand tends to be more angular than coarse sand. 
Therefore fine sand will support a more open framework (higher 
porosity) than better rounded, more spherical, coarse sand.
Consolidated sand (deep burial, well compacted) has undergone 
exposure to the pressure of burial (experiences the weight of overlying 
sediment). 
Fine sand is angular, with sharp edges, and the edges will break under 
the load pressure and become more compacted (more tightly packed 
with lower porosity). 
Coarse sand is better rounded and less prone to breakage under load; 
therefore the porosity is higher than that of fine sand.
c) Sorting 
In general, the better sorted the sediment the greater the porosity. 
In well sorted sands fine grains are not available to fill the pore spaces. 
This figure shows the relationship between sorting and porosity for 
clay-free sands.
Overall porosity decreases with increasing sorting coefficient (poorer 
sorting). 
For clay-free sands the reduction in porosity with increasing sorting 
coefficient is greater for coarse sand than for fine sand. 
The difference is unlikely if clay was also available to fill the pores.
For clay-free sands the silt and fine sand particles are available to fill 
the pore space between large grains and reduce porosity.
Because clay is absent less 
relatively fine material is not 
available to fill the pores of fine 
sand. 
Therefore the pores of fine sand 
will be less well-filled (and have 
porosity higher).
d) Post burial changes in porosity. 
Includes processes that reduce and increase porosity. 
Porosity that develops at the time of deposition is termed primary 
porosity. 
Porosity that develops after deposition is termed secondary porosity. 
Overall, with increasing 
burial depth the porosity of 
sediment decreases. 
50% reduction in porosity 
with burial to 6 km depth due 
to a variety of processes.
i) Compaction 
Particles are forced into closer packing by the weight of overlying 
deposits, reducing porosity. 
May include breakage of grains. 
Most effective if clay minerals are present (e.g., shale). 
Freshly deposited mud may have 70% porosity but burial under a 
kilometre of sediment reduces porosity to 5 or 10%. 
http://www.engr.usask.ca/~mjr347/prog/geoe118/geoe118.022.html
ii) Cementation 
Precipitation of new minerals from pore waters causes cementation of 
the grains and acts to fill the pore spaces, reducing porosity. 
Most common cements are calcite and quartz. 
Here’s a movie of 
cementation at Paul 
Heller’s web site.
iii) Clay formation 
Clays may form by the chemical alteration of pre-existing minerals after 
burial. 
Feldspars are particularly common clay-forming minerals. 
Clay minerals are very fine-grained and may accumulate in the pore 
spaces, reducing porosity. 
Eocene Whitemud 
Formation, Saskatchewan
iv) Solution 
If pore waters are undersaturated with respect to the minerals making up 
a sediment then some volume of mineral material is lost to solution. 
Calcite, that makes up limestone, is relatively soluble and void spaces 
that are produced by solution range from the size of individual grains to 
caverns. 
Quartz is relatively soluble when pore waters have a low Ph. 
Solution of grains reduces VG, increasing porosity. 
Solution is the most effective means of creating secondary porosity. 
v) Pressure solution 
The solubility of mineral grains increases under an applied stress (such 
as burial load) and the process of solution under stress is termed 
Pressure Solution. 
The solution takes place at the grain contacts where the applied stress is 
greatest.
Pressure solution results in a reduction in porosity in two different ways: 
1. It shortens the pore spaces as the grains are dissolved. 
2. Insoluble material within the grains accumulates in the pore spaces as 
the grains are dissolve.
v) Fracturing 
Fracturing of existing rocks creates a small increase in porosity. 
Fracturing is particularly important in producing porosity in rocks with 
low primary porosity.
POROSITY DETERMINATION 
FROM LOGS 
Most slides in this section are modified primarily from NExT PERF Short Course Notes, 1999. 
However, many of the NExT slides appears to have been obtained from other primary 
sources that are not cited. Some slides have a notes section.
OPENHOLE LOG EVALUATION 
Well Log 
SP Resistivity
POROSITY DETERMINATION BY LOGGING 
Oil sand 
Gamma 
ray 
Resisitivity Porosity 
Increasing 
radioactivity 
Increasing 
resistivity 
Increasing 
porosity 
Shale 
Shale
POROSITY LOG TYPES 
3 Main Log Types 
• Bulk density 
• Sonic (acoustic) 
• Compensated neutron 
These logs do not measures porosity directly. To 
accurately calculate porosity, the analyst must 
know: 
•Formation lithology 
• Fluid in pores of sampled reservoir volume
DENSITY LOGS 
• Uses radioactive source to generate 
gamma rays 
• Gamma ray collides with electrons in 
formation, losing energy 
• Detector measures intensity of back-scattered 
gamma rays, which is related 
to electron density of the formation 
• Electron density is a measure of bulk 
density
DENSITY LOGS 
• Bulk density, b, is dependent upon: 
– Lithology 
– Porosity 
– Density and saturation of fluids in pores 
• Saturation is fraction of pore volume 
occupied by a particular fluid (intensive)
DENSITY LOG 
GR 
0 API 200 
CALIX 
6 IN 16 
CALIY 
6 IN 16 
RHOB 
2 G/C3 3 
DRHO 
-0.25 G/C3 0.25 
4100 
Gamma ray Density 
4200 
Caliper 
Density 
correction
Formation (b) 
Long spacing 
detector 
Short spacing 
detector 
Mud cake 
(mc + hmc) 
Source
BULK DENSITY 
b  ma 1   f  
Matrix Fluids in 
flushed zone 
•Measures electron density of a formation 
•Strong function of formation bulk density 
•Matrix bulk density varies with lithology 
–Sandstone 2.65 g/cc 
–Limestone 2.71 g/cc 
–Dolomite 2.87 g/cc
POROSITY FROM DENSITY LOG 
Porosity equation 
   
ma b 
   
ma f 
  
Fluid density equation 
f  mf Sxo  h 1 Sxo 
We usually assume the fluid density (f) is between 1.0 and 1.1. If gas is present, the 
actual f will be < 1.0 and the calculated porosity will be too high. 
mf is the mud filtrate density, g/cc 
h is the hydrocarbon density, g/cc 
Sxo is the saturation of the flush/zone, decimal
DENSITY LOGS 
Working equation (hydrocarbon zone) 
  
S 1 S 
        
b xo mf xo hc 
sh sh  sh  ma 
V 1 V 
       
b = Recorded parameter (bulk volume) 
 Sxo mf = Mud filtrate component 
 (1 - Sxo) hc = Hydrocarbon component 
Vsh sh = Shale component 
1 -  - Vsh = Matrix component
DENSITY LOGS 
• If minimal shale, Vsh  0 
• If hc  mf  f, then 
• b =  f - (1 - ) ma 
   
ma b 
ma f 
d 
   
    
d = Porosity from density log, fraction 
ma = Density of formation matrix, g/cm3 
b = Bulk density from log measurement, g/cm3 
f = Density of fluid in rock pores, g/cm3 
hc = Density of hydrocarbons in rock pores, g/cm3 
mf = Density of mud filtrate, g/cm3 
sh = Density of shale, g/cm3 
Vsh = Volume of shale, fraction 
Sxo = Mud filtrate saturation in zone invaded by mud filtrate, fraction
GRC 
0 150 
SPC 
-160 MV 40 
ACAL 
6 16 
ILDC 
0.2 200 
SNC 
0.2 200 
MLLCF 
0.2 200 
RHOC 
1.95 2.95 
CNLLC 
0.45 -0.15 
DT 
150 us/f 50 
001) BONANZA 1 
10700 
10800 
10900 
BULK DENSITY LOG 
Bulk Density 
Log 
RHOC 
1.95 2.95
NEUTRON LOG 
• Logging tool emits high energy 
neutrons into formation 
• Neutrons collide with nuclei of 
formation’s atoms 
• Neutrons lose energy (velocity) with 
each collision
NEUTRON LOG 
• The most energy is lost when colliding 
with a hydrogen atom nucleus 
• Neutrons are slowed sufficiently to be 
captured by nuclei 
• Capturing nuclei become excited and 
emit gamma rays
NEUTRON LOG 
• Depending on type of logging tool either gamma 
rays or non-captured neutrons are recorded 
• Log records porosity based on neutrons 
captured by formation 
• If hydrogen is in pore space, porosity is related 
to the ratio of neutrons emitted to those counted 
as captured 
• Neutron log reports porosity, calibrated 
assuming calcite matrix and fresh water in pores, 
if these assumptions are invalid we must correct 
the neutron porosity value
NEUTRON LOG 
Theoretical equation 
  
S 1 S 
        
N xo Nmf xo Nhc 
sh sh  sh  Nma 
V 1 V 
       
N = Recorded parameter 
 Sxo Nmf = Mud filtrate portion 
 (1 - Sxo) Nhc = Hydrocarbon portion 
Vsh Nsh = Shale portion 
(1 -  - Vsh) Nhc = Matrix portion where  = True 
porosity of rock 
N = Porosity from neutron log measurement, fraction 
Nma = Porosity of matrix fraction 
Nhc = Porosity of formation saturated with 
hydrocarbon fluid, fraction 
Nmf = Porosity saturated with mud filtrate, fraction 
Vsh = Volume of shale, fraction 
Sxo = Mud filtrate saturation in zone invaded 
by mud filtrate, fraction
GRC 
0 150 
SPC 
-160 MV 40 
ACAL 
6 16 
ILDC 
0.2 200 
SNC 
0.2 200 
MLLCF 
0.2 200 
RHOC 
1.95 2.95 
CNLLC 
0.45 -0.15 
DT 
150 us/f 50 
001) BONANZA 1 
10700 
10800 
10900 
POROSITY FROM NEUTRON LOG 
Neutron 
Log 
CNLLC 
0.45 -0.15
ACOUSTIC (SONIC) LOG 
Upper 
transmitter 
Lower 
transmitter 
R1 
R2 
R3 
R4 
• Tool usually consists of 
one sound transmitter 
(above) and two receivers 
(below) 
• Sound is generated, 
travels through formation 
• Elapsed time between 
sound wave at receiver 1 
vs receiver 2 is dependent 
upon density of medium 
through which the sound 
traveled
50 
sec 
T0 
E2 
E1 
E3 
Mud waves 
Rayleigh 
waves 
Compressional 
waves
COMMON LITHOLOGY MATRIX 
TRAVEL TIMES USED 
Lithology Typical Matrix Travel 
Time, tma, sec/ft 
Sandstone 55.5 
Limestone 47.5 
Dolomite 43.5 
Anydridte 50.0 
Salt 66.7
ACOUSTIC (SONIC) LOG 
Working equation 
  
t S t 1 S t 
        
L xo mf xo hc 
sh sh  sh  ma 
V t 1 V t 
       
tL = Recorded parameter, travel time read from log 
 Sxo tmf = Mud filtrate portion 
 (1 - Sxo) thc = Hydrocarbon portion 
Vsh tsh = Shale portion 
(1 -  - Vsh) tma = Matrix portion
ACOUSTIC (SONIC) LOG 
• If Vsh = 0 and if hydrocarbon is liquid 
(i.e. tmf  tf), then 
• tL =  tf + (1 - ) tma 
or 
t t 
   
   
L ma 
s t t 
f ma 
    
s = Porosity calculated from sonic log reading, fraction 
tL = Travel time reading from log, microseconds/ft 
tma = Travel time in matrix, microseconds/ft 
tf = Travel time in fluid, microseconds/ ft
ACOUSTIC (SONIC) LOG 
DT 
140 USFT 40 
SPHI 
30 % 10 
4100 
4200 
GR 
0 API 200 
CALIX 
6 IN 16 
Sonic travel time 
Sonic 
porosity 
Caliper 
Gamma 
Ray
SONIC LOG 
The response can be written as follows: 
tlog  tma 1   tf  
ma 
t t 
 
  log 
t t 
 
f ma 
tlog = log reading, sec/ft 
tma = the matrix travel time, sec/ft 
tf = the fluid travel time, sec/ft 
 = porosity
GRC 
0 150 
SPC 
-160 MV 40 
ACAL 
6 16 
ILDC 
0.2 200 
SNC 
0.2 200 
MLLCF 
0.2 200 
RHOC 
1.95 2.95 
CNLLC 
0.45 -0.15 
DT 
150 us/f 50 
001) BONANZA 1 
10700 
10800 
10900 
SONIC LOG 
Sonic 
Log 
DT 
150 us/f 50
EXAMPLE 
Calculating Rock Porosity 
Using an Acoustic Log 
Calculate the porosity for the following intervals. The measured travel times from the 
log are summarized in the following table. 
At depth of 10,820’, accoustic log reads travel time of 65 s/ft. 
Calculate porosity. Does this value agree with density and neutron 
logs? 
Assume a matrix travel time, tm = 51.6 sec/ft. In addition, assume the formation is 
saturated with water having a tf = 189.0 sec/ft.
EXAMPLE SOLUTION SONIC LOG 
GRC 
0 150 
SPC 
-160 MV 40 
ACAL 
6 16 
ILDC 
0.2 200 
SNC 
0.2 200 
MLLCF 
0.2 200 
RHOC 
1.95 2.95 
CNLLC 
0.45 -0.15 
DT 
150 us/f 50 
001) BONANZA 1 
10700 
10800 
10900 
SPHI 
45 ss -15 
SPHI
FACTORS AFFECTING SONIC 
LOG RESPONSE 
• Unconsolidated formations 
• Naturally fractured formations 
• Hydrocarbons (especially gas) 
• Rugose salt sections
RESPONSES OF POROSITY LOGS 
The three porosity logs: 
– Respond differently to different matrix 
compositions 
– Respond differently to presence of gas or 
light oils 
Combinations of logs can: 
– Imply composition of matrix 
– Indicate the type of hydrocarbon in pores
GAS EFFECT 
• Density -  is too high 
• Neutron -  is too low 
• Sonic -  is not significantly 
affected by gas
ESTIMATING POROSITY FROM 
WELL LOGS 
Openhole logging tools are the most common method 
of determining porosity: 
• Less expensive than coring and may be less 
risk of sticking the tool in the hole 
• Coring may not be practical in unconsolidated 
formations or in formations with high secondary 
porosity such as vugs or natural fractures. 
If porosity measurements are very important, both 
coring and logging programs may be conducted so 
the log-based porosity calculations can be used to 
calibrated to the core-based porosity measurements.
Influence Of Clay-Mineral Distribution 
On Effective Porosity 
Dispersed Clay 
• Pore-filling 
• Pore-lining 
• Pore-bridging 
Clay Lamination 
Structural Clay 
(Rock Fragments, 
Rip-Up Clasts, 
Clay-Replaced Grains) 
Detrital Quartz 
Grains 
e 
e 
e 
Clay 
Minerals 
e  
e
GEOLOGICAL AND PETROPHYSICAL 
DATA USED TO DEFINE FLOW UNITS 
Flow 
Units 
Gamma Ray 
Log 
Petrophysical 
Data 
Pore 
Types 
Core Lithofacies 
5 
4 
3 
2 
1 
Core 
Plugs 
Capillary 
Pressure 
 vs k
Schematic Reservoir Layering Profile 
in a Carbonate Reservoir 
Baffles/barriers 
3150 
SA -97A 
Flow unit 
SA -251 
SA -356 SA -71 SA -344 
SA -371 
SA -348 
SA -346 
SA -37 
3200 
3250 
3300 
3350 
3100 
3150 
3250 
3300 
3250 
3150 
3200 
3100 
3150 
3200 
3250 
3200 
3250 
3250 
3300 
3350 
3150 
3200 
3250 
3300 
3100 
3200 
3250 
3150 
3200 
3250 
3300 
3350 
From Bastian and others
Why is porosity important? 
Especially because it allows us to make estimations of the amount of 
fluid that can be contained in a rock (water, oil, spilled contaminants, 
etc.). 
Example from oil and gas exploration:
Why is porosity important? 
Especially because it allows us to make estimations of the amount of 
fluid that can be contained in a rock (water, oil, spilled contaminants, 
etc.). 
Example from oil and gas exploration:
Why is porosity important? 
Especially because it allows us to make estimations of the amount of 
fluid that can be contained in a rock (water, oil, spilled contaminants, 
etc.). 
Example from oil and gas exploration:
Why is porosity important? 
Especially because it allows us to make estimations of the amount of 
fluid that can be contained in a rock (water, oil, spilled contaminants, 
etc.). 
Example from oil and gas exploration:
Why is porosity important? 
Especially because it allows us to make estimations of the amount of 
fluid that can be contained in a rock (water, oil, spilled contaminants, 
etc.). 
Example from oil and gas exploration: 
How much oil is contained in the discovered unit? 
In this case, assume that the pore 
spaces of the sediment in the oil-bearing 
unit are full of oil. 
Therefore, the total volume of oil is 
the total volume of pore space (VP) 
in the oil-bearing unit.
V 
100 P 
T 
P 
  Total volume of oil = VP, therefore solve for VP. 
V 
T 
100 
P 
P V 
V 
 
 
VT  800m 200m1m 160,000m3 
10% P  
Therefore: 
10  
160,000 
V 
 
P 100 3 16,000m of oil
II. Permeability (Hydraulic Conductivity; k) 
Stated qualitatively: permeability is a measure of how easily a fluid will 
flow through any granular material. 
More precisely, permeability (k) is 
an empirically-derived parameter 
in D’Arcy’s Law, a Law that 
predicts the discharge of fluid 
through a granular material.
Those are all properties that are independent of the granular material. 
There are also controls on permeability that are exerted by the granular 
material and are accounted for in the term (k) for permeability: 
k is proportional to all sediment properties that influence the flow of fluid 
through any granular material (note that the dimensions of k are cm2). 
Two major factors: 
1. The diameter of the pathways through which the fluid moves. 
2. The tortuosity of the pathways (how complex they are).
1. The diameter of the pathways. 
Along the walls of the pathway the velocity is zero (a no slip boundary) 
and increases away from the boundaries, reaching a maximum towards 
the middle to the pathway. 
Narrow pathway: the region where the velocity is low is a relatively 
large proportion of the total cross-sectional area and average velocity is 
low. 
Large pathway: the region where 
the velocity is low is proportionally 
small and the average velocity is 
greater. 
It’s easier to push fluid through a large 
Pathway than a small one.
2. The tortuosity of the pathways. 
Tortuosity is a measure of how 
much a pathway deviates from a 
straight line.
2. The tortuosity of the pathways. 
Tortuosity is a measure of how 
much a pathway deviates from a 
straight line. 
The path that fluid takes through a 
granular material is governed by 
how individual pore spaces are 
connected. 
The greater the tortuosity the 
lower the permeability because 
viscous resistance is cumulative 
along the length of the pathway.
Pathway diameter and tortuosity are controlled by the properties of the 
sediment and determine the sediment’s permeability. 
The units of permeability are Darcies (d): 
1 darcy is the permeability that allows a fluid with 1 centipoise 
viscosity to flow at a rate of 1 cm/s under a pressure gradient of 1 
atm/cm. 
1 
1000 
d 
Permeability is often very small and expressed in millidarcies ( )
a) Sediment controls on permeability 
i) Packing density 
Tightly packed sediment has smaller 
pathways than loosely packed 
sediment (all other factors being 
equal). 
Smaller pathways reduce porosity and the size of the pathways so the 
more tightly packed the sediment the lower the permeability.
ii) Porosity 
In general, permeability increases with primary porosity. 
The larger and more abundant the pore spaces the greater the 
permeability. 
Pore spaces must be well connected 
to enhance permeability.
Shale, chalk and vuggy rocks (rocks with large solution holes) may have 
very high porosity but the pores are not well linked. 
The discontinuous pathways result in low permeability. 
Fractures can greatly enhance permeability but do not increase porosity 
significantly. 
A 0.25 mm fracture will pass fluid 
at the rate that would be passed 
by13.5 metres of rock with 100 md 
permeability.
iii) Grain Size 
Unlike porosity, permeability increases with grain size. 
The larger the grain size the larger the pore area. 
For spherical grains in cubic packing: 
Pore area = 0.74d2
A ten-fold increase in grain size yields a hundred-fold increase in 
permeability. 
iv) Sorting 
The better sorted a sediment is the 
greater its permeability. 
In very well sorted sands the pore 
spaces are open. 
In poorly sorted sands fine grains 
occupy the pore spaces between 
coarser grains.
v) Post-burial processes 
Like porosity, permeability is changed following burial of a sediment. 
In this example permeability 
is reduced by two orders of 
magnitude with 3 km of 
burial. 
Cementation 
Clay formation 
Compaction 
Pressure solution 
All act to reduce permeability
b) Directional permeability 
Permeability is not necessarily isotropic (equal in all directions) 
Fractures are commonly aligned in the same direction, greatly 
enhancing permeability in the direction that is parallel to the 
fractures.
Variation in grain size and geological structure can create directional 
permeability. 
E.g., Graded bedding: grain 
size becomes finer upwards in 
a bed. 
Fluid that is introduced at the surface will follow a path that is towards the 
direction of dip of the beds.
Fabric (preferred orientation of the grains in a sediment) can cause 
directional permeability. 
E.g., A sandstone unit of prolate particles. 
The direction along the long axes of grains will have larger pathways 
and therefore greater permeability than the direction that is parallel to 
the long axes.

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Pablo

  • 1. Suez University Faculty of Petroleum & Mining Engineering Porosity and Permeability Student Belal Farouk El-saied Ibrahim Class / III Section / Engineering Geology and Geophysics Presented to Prof. Dr. / Ali Abbas
  • 2. Porosity and Permeability Both are important properties that are related to fluids in sediment and sedimentary rocks. Fluids can include: water, hydrocarbons, spilled contaminants. Most aquifers are in sediment or sedimentary rocks. Virtually all hydrocarbons are contained in sedimentary rocks. Porosity: the volume of void space (available to contain fluid or air) in a sediment or sedimentary rock. Permeability: related to how easily a fluid will pass through any granular material.
  • 3. I. Porosity (P) The proportion of any material that is void space, expressed as a percentage of the total volume of material. V 100 P T P   V Where VP is the total volume of pore space and VT is the total volume of rock or sediment. In practice, porosity is commonly based on measurement of the total grain volume of a granular material: V  V 100 T G   T P V Where VG is the total volume of grains within the total volume of rock or sediment. VP VT VG
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  • 26. Porosity varies from 0% to 70% in natural sediments but exceeds 70% for freshly deposited mud. Several factors control porosity. a) Packing Density Packing density: the arrangement of the particles in the deposit. The more densely packed the particles the lower the porosity. e.g., perfect spheres of uniform size. Porosity can vary from 48% to 26%.
  • 27. Shape has an important effect on packing. Tabular rectangular particles can vary from 0% to just under 50%: Natural particles such as shells can have very high porosity:
  • 28. In general, the greater the angularity of the particles the more open the framework (more open fabric) and the greater the possible porosity. b) Grain Size On its own, grain size has no influence on porosity! Consider a cube of sediment of perfect spheres with cubic packing. V  V 100 T G   T P V d = sphere diameter; n = number of grains along a side (5 in this example).
  • 29. V  V 100 T G   T P V Length of a side of the cube = d  n = dn Volume of the cube (VT): Total number of grains: n  n  n = n3   Volume of a single grain: 3 V d 6 Total volume of grains (VG):   3 3 3 3 V  n  d  n d G 6 6 3 3 VT  dn dn dn  d n
  • 30. V  V   33   3 3 100 T G T P V 6 G V n d TV d n  Where: and  3 3 3 3 d n n d 6 100  Therefore:   3 3 P d n       3 3 1 6 Rearranging:     3 3 100 d n P d n Therefore: 1 100 48% 6 P           d (grain size) does not affect the porosity so that porosity is independent of grains size. No matter how large or small the spherical grains in cubic packing have a porosity is 48%.
  • 31. There are some indirect relationships between size and porosity. i) Large grains have higher settling velocities than small grains. When grains settle through a fluid the large grains will impact the substrate with larger momentum, possibly jostling the grains into tighter packing (therefore with lower porosity). Unconsolidated sands tend to decrease in porosity with increasing grain size. Consolidated sands tend to increase in porosity with increasing grain size. ii) A shape effect.
  • 32. Generally, unconsolidated sands undergo little burial and less compaction than consolidated sands. Fine sand has slightly higher porosity. Fine sand tends to be more angular than coarse sand. Therefore fine sand will support a more open framework (higher porosity) than better rounded, more spherical, coarse sand.
  • 33. Consolidated sand (deep burial, well compacted) has undergone exposure to the pressure of burial (experiences the weight of overlying sediment). Fine sand is angular, with sharp edges, and the edges will break under the load pressure and become more compacted (more tightly packed with lower porosity). Coarse sand is better rounded and less prone to breakage under load; therefore the porosity is higher than that of fine sand.
  • 34. c) Sorting In general, the better sorted the sediment the greater the porosity. In well sorted sands fine grains are not available to fill the pore spaces. This figure shows the relationship between sorting and porosity for clay-free sands.
  • 35. Overall porosity decreases with increasing sorting coefficient (poorer sorting). For clay-free sands the reduction in porosity with increasing sorting coefficient is greater for coarse sand than for fine sand. The difference is unlikely if clay was also available to fill the pores.
  • 36. For clay-free sands the silt and fine sand particles are available to fill the pore space between large grains and reduce porosity.
  • 37. Because clay is absent less relatively fine material is not available to fill the pores of fine sand. Therefore the pores of fine sand will be less well-filled (and have porosity higher).
  • 38. d) Post burial changes in porosity. Includes processes that reduce and increase porosity. Porosity that develops at the time of deposition is termed primary porosity. Porosity that develops after deposition is termed secondary porosity. Overall, with increasing burial depth the porosity of sediment decreases. 50% reduction in porosity with burial to 6 km depth due to a variety of processes.
  • 39. i) Compaction Particles are forced into closer packing by the weight of overlying deposits, reducing porosity. May include breakage of grains. Most effective if clay minerals are present (e.g., shale). Freshly deposited mud may have 70% porosity but burial under a kilometre of sediment reduces porosity to 5 or 10%. http://www.engr.usask.ca/~mjr347/prog/geoe118/geoe118.022.html
  • 40. ii) Cementation Precipitation of new minerals from pore waters causes cementation of the grains and acts to fill the pore spaces, reducing porosity. Most common cements are calcite and quartz. Here’s a movie of cementation at Paul Heller’s web site.
  • 41. iii) Clay formation Clays may form by the chemical alteration of pre-existing minerals after burial. Feldspars are particularly common clay-forming minerals. Clay minerals are very fine-grained and may accumulate in the pore spaces, reducing porosity. Eocene Whitemud Formation, Saskatchewan
  • 42. iv) Solution If pore waters are undersaturated with respect to the minerals making up a sediment then some volume of mineral material is lost to solution. Calcite, that makes up limestone, is relatively soluble and void spaces that are produced by solution range from the size of individual grains to caverns. Quartz is relatively soluble when pore waters have a low Ph. Solution of grains reduces VG, increasing porosity. Solution is the most effective means of creating secondary porosity. v) Pressure solution The solubility of mineral grains increases under an applied stress (such as burial load) and the process of solution under stress is termed Pressure Solution. The solution takes place at the grain contacts where the applied stress is greatest.
  • 43. Pressure solution results in a reduction in porosity in two different ways: 1. It shortens the pore spaces as the grains are dissolved. 2. Insoluble material within the grains accumulates in the pore spaces as the grains are dissolve.
  • 44. v) Fracturing Fracturing of existing rocks creates a small increase in porosity. Fracturing is particularly important in producing porosity in rocks with low primary porosity.
  • 45.
  • 46. POROSITY DETERMINATION FROM LOGS Most slides in this section are modified primarily from NExT PERF Short Course Notes, 1999. However, many of the NExT slides appears to have been obtained from other primary sources that are not cited. Some slides have a notes section.
  • 47. OPENHOLE LOG EVALUATION Well Log SP Resistivity
  • 48. POROSITY DETERMINATION BY LOGGING Oil sand Gamma ray Resisitivity Porosity Increasing radioactivity Increasing resistivity Increasing porosity Shale Shale
  • 49. POROSITY LOG TYPES 3 Main Log Types • Bulk density • Sonic (acoustic) • Compensated neutron These logs do not measures porosity directly. To accurately calculate porosity, the analyst must know: •Formation lithology • Fluid in pores of sampled reservoir volume
  • 50. DENSITY LOGS • Uses radioactive source to generate gamma rays • Gamma ray collides with electrons in formation, losing energy • Detector measures intensity of back-scattered gamma rays, which is related to electron density of the formation • Electron density is a measure of bulk density
  • 51. DENSITY LOGS • Bulk density, b, is dependent upon: – Lithology – Porosity – Density and saturation of fluids in pores • Saturation is fraction of pore volume occupied by a particular fluid (intensive)
  • 52. DENSITY LOG GR 0 API 200 CALIX 6 IN 16 CALIY 6 IN 16 RHOB 2 G/C3 3 DRHO -0.25 G/C3 0.25 4100 Gamma ray Density 4200 Caliper Density correction
  • 53. Formation (b) Long spacing detector Short spacing detector Mud cake (mc + hmc) Source
  • 54. BULK DENSITY b  ma 1   f  Matrix Fluids in flushed zone •Measures electron density of a formation •Strong function of formation bulk density •Matrix bulk density varies with lithology –Sandstone 2.65 g/cc –Limestone 2.71 g/cc –Dolomite 2.87 g/cc
  • 55. POROSITY FROM DENSITY LOG Porosity equation    ma b    ma f   Fluid density equation f  mf Sxo  h 1 Sxo We usually assume the fluid density (f) is between 1.0 and 1.1. If gas is present, the actual f will be < 1.0 and the calculated porosity will be too high. mf is the mud filtrate density, g/cc h is the hydrocarbon density, g/cc Sxo is the saturation of the flush/zone, decimal
  • 56. DENSITY LOGS Working equation (hydrocarbon zone)   S 1 S         b xo mf xo hc sh sh  sh  ma V 1 V        b = Recorded parameter (bulk volume)  Sxo mf = Mud filtrate component  (1 - Sxo) hc = Hydrocarbon component Vsh sh = Shale component 1 -  - Vsh = Matrix component
  • 57. DENSITY LOGS • If minimal shale, Vsh  0 • If hc  mf  f, then • b =  f - (1 - ) ma    ma b ma f d        d = Porosity from density log, fraction ma = Density of formation matrix, g/cm3 b = Bulk density from log measurement, g/cm3 f = Density of fluid in rock pores, g/cm3 hc = Density of hydrocarbons in rock pores, g/cm3 mf = Density of mud filtrate, g/cm3 sh = Density of shale, g/cm3 Vsh = Volume of shale, fraction Sxo = Mud filtrate saturation in zone invaded by mud filtrate, fraction
  • 58. GRC 0 150 SPC -160 MV 40 ACAL 6 16 ILDC 0.2 200 SNC 0.2 200 MLLCF 0.2 200 RHOC 1.95 2.95 CNLLC 0.45 -0.15 DT 150 us/f 50 001) BONANZA 1 10700 10800 10900 BULK DENSITY LOG Bulk Density Log RHOC 1.95 2.95
  • 59. NEUTRON LOG • Logging tool emits high energy neutrons into formation • Neutrons collide with nuclei of formation’s atoms • Neutrons lose energy (velocity) with each collision
  • 60. NEUTRON LOG • The most energy is lost when colliding with a hydrogen atom nucleus • Neutrons are slowed sufficiently to be captured by nuclei • Capturing nuclei become excited and emit gamma rays
  • 61. NEUTRON LOG • Depending on type of logging tool either gamma rays or non-captured neutrons are recorded • Log records porosity based on neutrons captured by formation • If hydrogen is in pore space, porosity is related to the ratio of neutrons emitted to those counted as captured • Neutron log reports porosity, calibrated assuming calcite matrix and fresh water in pores, if these assumptions are invalid we must correct the neutron porosity value
  • 62. NEUTRON LOG Theoretical equation   S 1 S         N xo Nmf xo Nhc sh sh  sh  Nma V 1 V        N = Recorded parameter  Sxo Nmf = Mud filtrate portion  (1 - Sxo) Nhc = Hydrocarbon portion Vsh Nsh = Shale portion (1 -  - Vsh) Nhc = Matrix portion where  = True porosity of rock N = Porosity from neutron log measurement, fraction Nma = Porosity of matrix fraction Nhc = Porosity of formation saturated with hydrocarbon fluid, fraction Nmf = Porosity saturated with mud filtrate, fraction Vsh = Volume of shale, fraction Sxo = Mud filtrate saturation in zone invaded by mud filtrate, fraction
  • 63. GRC 0 150 SPC -160 MV 40 ACAL 6 16 ILDC 0.2 200 SNC 0.2 200 MLLCF 0.2 200 RHOC 1.95 2.95 CNLLC 0.45 -0.15 DT 150 us/f 50 001) BONANZA 1 10700 10800 10900 POROSITY FROM NEUTRON LOG Neutron Log CNLLC 0.45 -0.15
  • 64. ACOUSTIC (SONIC) LOG Upper transmitter Lower transmitter R1 R2 R3 R4 • Tool usually consists of one sound transmitter (above) and two receivers (below) • Sound is generated, travels through formation • Elapsed time between sound wave at receiver 1 vs receiver 2 is dependent upon density of medium through which the sound traveled
  • 65. 50 sec T0 E2 E1 E3 Mud waves Rayleigh waves Compressional waves
  • 66. COMMON LITHOLOGY MATRIX TRAVEL TIMES USED Lithology Typical Matrix Travel Time, tma, sec/ft Sandstone 55.5 Limestone 47.5 Dolomite 43.5 Anydridte 50.0 Salt 66.7
  • 67. ACOUSTIC (SONIC) LOG Working equation   t S t 1 S t         L xo mf xo hc sh sh  sh  ma V t 1 V t        tL = Recorded parameter, travel time read from log  Sxo tmf = Mud filtrate portion  (1 - Sxo) thc = Hydrocarbon portion Vsh tsh = Shale portion (1 -  - Vsh) tma = Matrix portion
  • 68. ACOUSTIC (SONIC) LOG • If Vsh = 0 and if hydrocarbon is liquid (i.e. tmf  tf), then • tL =  tf + (1 - ) tma or t t       L ma s t t f ma     s = Porosity calculated from sonic log reading, fraction tL = Travel time reading from log, microseconds/ft tma = Travel time in matrix, microseconds/ft tf = Travel time in fluid, microseconds/ ft
  • 69. ACOUSTIC (SONIC) LOG DT 140 USFT 40 SPHI 30 % 10 4100 4200 GR 0 API 200 CALIX 6 IN 16 Sonic travel time Sonic porosity Caliper Gamma Ray
  • 70. SONIC LOG The response can be written as follows: tlog  tma 1   tf  ma t t    log t t  f ma tlog = log reading, sec/ft tma = the matrix travel time, sec/ft tf = the fluid travel time, sec/ft  = porosity
  • 71. GRC 0 150 SPC -160 MV 40 ACAL 6 16 ILDC 0.2 200 SNC 0.2 200 MLLCF 0.2 200 RHOC 1.95 2.95 CNLLC 0.45 -0.15 DT 150 us/f 50 001) BONANZA 1 10700 10800 10900 SONIC LOG Sonic Log DT 150 us/f 50
  • 72. EXAMPLE Calculating Rock Porosity Using an Acoustic Log Calculate the porosity for the following intervals. The measured travel times from the log are summarized in the following table. At depth of 10,820’, accoustic log reads travel time of 65 s/ft. Calculate porosity. Does this value agree with density and neutron logs? Assume a matrix travel time, tm = 51.6 sec/ft. In addition, assume the formation is saturated with water having a tf = 189.0 sec/ft.
  • 73. EXAMPLE SOLUTION SONIC LOG GRC 0 150 SPC -160 MV 40 ACAL 6 16 ILDC 0.2 200 SNC 0.2 200 MLLCF 0.2 200 RHOC 1.95 2.95 CNLLC 0.45 -0.15 DT 150 us/f 50 001) BONANZA 1 10700 10800 10900 SPHI 45 ss -15 SPHI
  • 74. FACTORS AFFECTING SONIC LOG RESPONSE • Unconsolidated formations • Naturally fractured formations • Hydrocarbons (especially gas) • Rugose salt sections
  • 75. RESPONSES OF POROSITY LOGS The three porosity logs: – Respond differently to different matrix compositions – Respond differently to presence of gas or light oils Combinations of logs can: – Imply composition of matrix – Indicate the type of hydrocarbon in pores
  • 76. GAS EFFECT • Density -  is too high • Neutron -  is too low • Sonic -  is not significantly affected by gas
  • 77. ESTIMATING POROSITY FROM WELL LOGS Openhole logging tools are the most common method of determining porosity: • Less expensive than coring and may be less risk of sticking the tool in the hole • Coring may not be practical in unconsolidated formations or in formations with high secondary porosity such as vugs or natural fractures. If porosity measurements are very important, both coring and logging programs may be conducted so the log-based porosity calculations can be used to calibrated to the core-based porosity measurements.
  • 78. Influence Of Clay-Mineral Distribution On Effective Porosity Dispersed Clay • Pore-filling • Pore-lining • Pore-bridging Clay Lamination Structural Clay (Rock Fragments, Rip-Up Clasts, Clay-Replaced Grains) Detrital Quartz Grains e e e Clay Minerals e  e
  • 79. GEOLOGICAL AND PETROPHYSICAL DATA USED TO DEFINE FLOW UNITS Flow Units Gamma Ray Log Petrophysical Data Pore Types Core Lithofacies 5 4 3 2 1 Core Plugs Capillary Pressure  vs k
  • 80. Schematic Reservoir Layering Profile in a Carbonate Reservoir Baffles/barriers 3150 SA -97A Flow unit SA -251 SA -356 SA -71 SA -344 SA -371 SA -348 SA -346 SA -37 3200 3250 3300 3350 3100 3150 3250 3300 3250 3150 3200 3100 3150 3200 3250 3200 3250 3250 3300 3350 3150 3200 3250 3300 3100 3200 3250 3150 3200 3250 3300 3350 From Bastian and others
  • 81. Why is porosity important? Especially because it allows us to make estimations of the amount of fluid that can be contained in a rock (water, oil, spilled contaminants, etc.). Example from oil and gas exploration:
  • 82. Why is porosity important? Especially because it allows us to make estimations of the amount of fluid that can be contained in a rock (water, oil, spilled contaminants, etc.). Example from oil and gas exploration:
  • 83. Why is porosity important? Especially because it allows us to make estimations of the amount of fluid that can be contained in a rock (water, oil, spilled contaminants, etc.). Example from oil and gas exploration:
  • 84. Why is porosity important? Especially because it allows us to make estimations of the amount of fluid that can be contained in a rock (water, oil, spilled contaminants, etc.). Example from oil and gas exploration:
  • 85. Why is porosity important? Especially because it allows us to make estimations of the amount of fluid that can be contained in a rock (water, oil, spilled contaminants, etc.). Example from oil and gas exploration: How much oil is contained in the discovered unit? In this case, assume that the pore spaces of the sediment in the oil-bearing unit are full of oil. Therefore, the total volume of oil is the total volume of pore space (VP) in the oil-bearing unit.
  • 86. V 100 P T P   Total volume of oil = VP, therefore solve for VP. V T 100 P P V V   VT  800m 200m1m 160,000m3 10% P  Therefore: 10  160,000 V  P 100 3 16,000m of oil
  • 87. II. Permeability (Hydraulic Conductivity; k) Stated qualitatively: permeability is a measure of how easily a fluid will flow through any granular material. More precisely, permeability (k) is an empirically-derived parameter in D’Arcy’s Law, a Law that predicts the discharge of fluid through a granular material.
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  • 100. Those are all properties that are independent of the granular material. There are also controls on permeability that are exerted by the granular material and are accounted for in the term (k) for permeability: k is proportional to all sediment properties that influence the flow of fluid through any granular material (note that the dimensions of k are cm2). Two major factors: 1. The diameter of the pathways through which the fluid moves. 2. The tortuosity of the pathways (how complex they are).
  • 101. 1. The diameter of the pathways. Along the walls of the pathway the velocity is zero (a no slip boundary) and increases away from the boundaries, reaching a maximum towards the middle to the pathway. Narrow pathway: the region where the velocity is low is a relatively large proportion of the total cross-sectional area and average velocity is low. Large pathway: the region where the velocity is low is proportionally small and the average velocity is greater. It’s easier to push fluid through a large Pathway than a small one.
  • 102. 2. The tortuosity of the pathways. Tortuosity is a measure of how much a pathway deviates from a straight line.
  • 103.
  • 104. 2. The tortuosity of the pathways. Tortuosity is a measure of how much a pathway deviates from a straight line. The path that fluid takes through a granular material is governed by how individual pore spaces are connected. The greater the tortuosity the lower the permeability because viscous resistance is cumulative along the length of the pathway.
  • 105. Pathway diameter and tortuosity are controlled by the properties of the sediment and determine the sediment’s permeability. The units of permeability are Darcies (d): 1 darcy is the permeability that allows a fluid with 1 centipoise viscosity to flow at a rate of 1 cm/s under a pressure gradient of 1 atm/cm. 1 1000 d Permeability is often very small and expressed in millidarcies ( )
  • 106. a) Sediment controls on permeability i) Packing density Tightly packed sediment has smaller pathways than loosely packed sediment (all other factors being equal). Smaller pathways reduce porosity and the size of the pathways so the more tightly packed the sediment the lower the permeability.
  • 107. ii) Porosity In general, permeability increases with primary porosity. The larger and more abundant the pore spaces the greater the permeability. Pore spaces must be well connected to enhance permeability.
  • 108. Shale, chalk and vuggy rocks (rocks with large solution holes) may have very high porosity but the pores are not well linked. The discontinuous pathways result in low permeability. Fractures can greatly enhance permeability but do not increase porosity significantly. A 0.25 mm fracture will pass fluid at the rate that would be passed by13.5 metres of rock with 100 md permeability.
  • 109. iii) Grain Size Unlike porosity, permeability increases with grain size. The larger the grain size the larger the pore area. For spherical grains in cubic packing: Pore area = 0.74d2
  • 110. A ten-fold increase in grain size yields a hundred-fold increase in permeability. iv) Sorting The better sorted a sediment is the greater its permeability. In very well sorted sands the pore spaces are open. In poorly sorted sands fine grains occupy the pore spaces between coarser grains.
  • 111. v) Post-burial processes Like porosity, permeability is changed following burial of a sediment. In this example permeability is reduced by two orders of magnitude with 3 km of burial. Cementation Clay formation Compaction Pressure solution All act to reduce permeability
  • 112. b) Directional permeability Permeability is not necessarily isotropic (equal in all directions) Fractures are commonly aligned in the same direction, greatly enhancing permeability in the direction that is parallel to the fractures.
  • 113. Variation in grain size and geological structure can create directional permeability. E.g., Graded bedding: grain size becomes finer upwards in a bed. Fluid that is introduced at the surface will follow a path that is towards the direction of dip of the beds.
  • 114. Fabric (preferred orientation of the grains in a sediment) can cause directional permeability. E.g., A sandstone unit of prolate particles. The direction along the long axes of grains will have larger pathways and therefore greater permeability than the direction that is parallel to the long axes.